Which of the following are dipole-dipole interactions that occur only between molecules containing N-H, O-H or F-H bonds?

Ion-dipole forces
Hydrogen bonding
Dipole-dipole forces
London dispersion forces

Answer:

[tex]\boxed{\text{ 93 \%}}[/tex]

Explanation:

[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]

Data:

[tex]\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}[/tex]

Calculation:

[tex]\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}[/tex]

Answer:

False

Explanation:

All Arrhenius acids and bases are also Bronsted-Lowry acids and bases.

An Arrhenius base is a compound that dissociates to form hydroxide ions in water.

NaOH(s) → Na^+(aq) +OH^-(aq)

A Bronsted-Lowry base is a proton acceptor.

NaOH is a Bronsted-Lowry base because the hydroxide on can accept a proton from HCl to form water.

Thus, all Arrhenius bases are Bronsted-Lowry bases.

Answer:

Approximately 0.074 grams.

Explanation:

How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].

[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)

Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,

For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to

[tex]Q = I \cdot t[/tex].

In case

[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)

For this electrochemical cell,

[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].

The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.

[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].

[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].

Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.

[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].

[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,

[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].

The Relative atomic mass of copper is [tex]63.546[/tex].

[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].

Final answer:

The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.

Explanation:

To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.

Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.

Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.

Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.

Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.

Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.

Moles are the number of particles in a given weight. So unless you state the amount of water, aluminum, salt, and baking soda no one can not consider which contain the most moles.

Answer:

a triangle

Explanation:

the name "triangular prism" has triangle in it, just like "rectangular prism" which has a rectangle as a base

Answer:

It’s actually DFG

Explanation:

DFBA

Answer:

10 electrons 8 protons

Explanation:

p +8 - e10- equals -2

Answer:

green

Explanation:

Answer:

The answer is Green

Explanation:

I've just answered this on usatestprep.

Answer:

B

Explanation:

If the concentration is increased, there are more particles to collide with each other, increasing the rate of the reaction.

The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.

The reaction rate refers to how quickly the concentration of such a particular reactant as well as product changes during a chemical reaction.

The abundance of an ingredient divided by the volume of a combination is called concentration. Mass concentration, molar concentration, number concentration, as well as volume concentration are all examples of mathematical descriptions.

The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.

Therefore, the correct answer will be option B

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Answer:

The ideal gas equation

Explanation:

The ideal gas equation is derived from the combination of three gas laws:

The ideal gas law is expressed mathematically as: PV=nRT where:

P is pressure

V is volume

n is the number of moles

R is the ideal gas law

T is temperature.

To obtain the combined gas law, we assume that n=1 and this gives:

                       [tex]\frac{PV}{T}[/tex] = R

Therefore:

[tex]\frac{P_{1} V_{1} }{T_{1} }[/tex] = [tex]\frac{P_{2} V_{2} }{T_{2} }[/tex]

Answer:

8856joules

Explanation:

Energy= MC. ©

energy = 123.00*1*(97-25)

energy =8856joules//

Answer: The amount of energy required will be 8856 Joules.

Explanation:

To calculate the amount of heat absorbed, we use the equation:

[tex]Q=mc\Delta T[/tex]

where,

Q = heat absorbed or released

m = Mass of the substance = 123 kg

c = specific heat capacity of water = [tex]1J/kg.K[/tex]

[tex]\Delta T[/tex] = change in temperature = [tex](97-25)^oC=72^oC=72K[/tex]  (change remains the same)

Putting values in above equation, we get:

[tex]Q=123kg\times 1J/kg.K\times 72K\\\\Q=8856J[/tex]

Hence, the amount of energy required will be 8856 Joules.

A. Two electrodes separated by an electrolyte that can generate an electrical current.

Answer:

Two electrodes separated by an electrolyte that can generate an electrical current.

Explanation:

Answer via Educere/ Founder's Education

Answer:

Explanation:

Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.

The heat capacity on the other hand, expresses the heat required to raise the temperature of  asubstance by 1kelvin.

When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.

Answer:

Reactivity

Explanation:

The scenario shows that baking soda is reactive enough to produce bubbles with vinegar but not enough to do so in pure water.

Flammability, color change, and boiling point are all wrong.  The scenario says nothing about these properties.

Answer:

Reactivity (Znk Elite Answerer is right)

Explanation:

I just took a test and I got it right. Even if the question says select all that apply there is only 1 answer and it is reactivity

First we look at the chemical reaction:

2 Na + Br₂ → 2 NaBr

number of moles = mass / molecular weight

mass = number of moles × molecular weight

number of moles of Na = 1000 / 23 = 43.48 moles

number of moles of Br₂ = 3000 / 160 = 18.75 moles

from the reaction:

if        2 moles of Na are reacting with 1 mole of Br₂

then   X moles of Na are reacting with 18.75 moles of Br₂

X = (18.75 × 2) / 1 = 37.5 moles of Na

The limiting reactant is bromine Br₂.

After the reaction is complete you remain with Na as excess reagent.

moles of Na = 43.48 - 37.5 = 5.98 moles

mass of Na =  5.98 × 23 = 137.54 g

if        reacting 1 mole of Br₂  produces 2 moles of NaBr

then  reacting 18.75 moles of Br₂  produces Y moles of NaBr

Y  = (18.75 × 2) / 1 = 37.5 moles of NaBr

mass of NaBr = 37.5 × 103 = 3862.5 g

Answer:

Explanation:

Given parameters:

Mass of Na = 1kg = 1000g

Mass of Br = 3kg = 3000g

Unkown:

Limiting reagent =?

Amount of excess reagent = ?

Quantity of NaBr formed = ?

Solution

The reaction equation can be expressed as:

                 2Na + Br₂ → 2NaBr

To find the limiting reagent

The limiting reagent is the reagent that is in short supply and it determines the amount of products that can be formed in the reaction.

To find the limiting the reagent, we establish a mole relationship between the reactants. We then check their stoichoimetric expression to see the one in excess and the limiting reagent.

Number of moles of Na = [tex]\frac{mass of Na}{molar mass of Na}[/tex]

   molar mass is expressed as g/mol and the Na should also be in grams

Number of moles = [tex]\frac{1000}{23}[/tex] = 43.48mol

Number of moles of Br₂ =  [tex]\frac{mass}{molar mass}[/tex]

    Number of moles = [tex]\frac{3000}{2x80}[/tex] = 18.75mol

From the balanced reaction equation:

     2 mole of Na combines with 1 mole of Br₂

     43.48mole of Na would require 43.48/2 mole = 21.74mole of Br₂ to react with.

But the given amount of Br we have is 18.75mole.

Therefore, the reagent in short supply is Bromine. It is the limiting reagent

Quantity of NaBr formed

To find the quantity of NaBr formed, we use the known reagent which is the limiting one to determine its number of moles and eventually the mass. The limiting reagent determines the extent of the reaction.

 From the stoichiometric equation:

          1 mole of Br₂ will produce 2 mole of NaBr

  19.23 mole Br₂ would now yield  (18.75 x2)= 37.5mole  of NaBr

Mass of NaBr = number of moles of NaBr x molar mass of NaBr

Molar mass of NaBr = 23 + 80 = 103g/mol

      Mass of NaBr = 37.5 x 103 = 3862.5g = 3.86Kg

Amount of excess reagent remaining after the complete reaction:

The amount of excess reagent would be derived from the reagent that occurs in excess which is Na:

1 mole of Br₂ reacts with 2 moles of Na

18.75mole of Br₂  will require 2x 18.75 = 37.5mole of Na

Excess mole of Na = (43.48 - 37.5)mole = 5.98mole

Mass of excess Na = number of moles of excess Na x molar mass of Na

Mass of excess Na = 5.98 x 23

Mass of excess Na = 137.54g or 0.14g

Answer:

A. Deposition Occurs

Explanation:

When a gas becomes ionized, deposition occurs.

Answer: Option (D) is the correct answer.

Explanation:

A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.

Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.

Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.

Thus, we can conclude that when a gas becomes ionized then a plasma is formed.

Answer:

2SO2 + 02 ====>2SO3

Explanation:

SO2 + O2 ===> SO3

The only thing you can do is balance the oxygens that are on the sulfurs. When you do that the oxygen (O2) can make the difference.

SO2 + O2 ===> 2SO3

Bring the oxygen on the right up to 6. When you do that, the sulfurs are out of balance. So balance the sulfurs.

2SO2 + 02 ====>2SO3

Your equation is now balanced. The trick is not to leave the number of oxygens on the right as an odd number. When you fix that problem, the equation will balance easily.

Species           S                 O

Left                  2                  2+4=6

Right                2                  2*3 =6

Balanced.

The temperature 12.17º C rounded to three significant figures is 12.2º C, taking into account the fourth figure which is a 7. This causes an upward rounding due to the rule of significant figures.

To round off the temperature of 12.17º C to three significant figures, we look at the fourth figure which is a 7. Since 7 is greater than 5, we round the third significant figure up, which results in a rounded temperature of 12.2º C.

In the context of rounding based on significant figures, the temperature value is often dependent on the least precise measurement in a data set or calculation. As an example, if we had another measurement of 13.7 kg, which is to the 0.1 decimal place, any resultant calculation would need to be rounded to the tenths place for consistency, giving us a hypothetical final answer of 15.2 kg, to match the precision of 13.7 kg.

Sulfur hexafluoride or SF6 is an inorganic, greenhouse gas. It is non-flammable, odorless, and colorless, and is an excellent insulator. It is a hypervalent octahedral molecule that has been an interesting topic of conversation among chemistry enthusiasts.

Hope this helps:)

SF₆ has six covalent bonds created by sp³ d² hybridization of the sulfur atom, forming a symmetrical octahedral structure with low reactivity.

The type of bond in SF₆ (sulfur hexafluoride) is a covalent bond. Specifically, the sulfur atom undergoes sp³ d² hybridization, allowing it to form six equivalent bonding pairs with the fluorine atoms. These bonds exhibit both sigma (σ) and pi (π) characteristics, as the S-F bond length is short, which is consistent with π-bonding in addition to σ-bonding.

This indicates that there are no lone pairs of electrons on the sulfur atom. The geometry displayed by SF₆ is highly symmetrical, forming an octahedron where all bond lengths and angles are identical, making it a nonpolar molecule with high symmetry and low reactivity. SF₆ is resistant to chemical attack and exhibits inert characteristics, which makes it useful in applications such as a spark suppressor.

Answer:

0.0057034 or 5.7034 * 10^-3

Answer:

The correct answer is Cirrocumulus.

Explanation:

Cirrocumulus : Clouds forming broken layer of small fleecy clouds at higher altitudes.

Cumulonimbus  : Clouds forming a towering mass with flat base with flat base at lower altitude

Cumulus  : Cloud forming rounded masses heaped or stacked on each other above a flat base , fairly at lower altitudes.

Stratus : Clouds forming continuous horizontal gray sheet, usually during rain or snow.

The given image corresponds to description given as Cirrocumulus.

Answer: A

Explanation:

Answer:

Explanation:

Heat = m*c * deltat

m = 20 grams

c = 4.19 J/g*C

deltaT = 30 - 10 = 20

Heat = 20 * 4.19 * 20

Heat = 1676 joules or 1.7 kJ depending on what you need.

Answer:

The correct answer for plato/edmentum is C). 1700 joules

Answer:

molecules

Explanation:

molecules because the summer like atoms and Sciences sciency to be honest

Answer:

Polar

Explanation:

water is a polar solvent since they can ionize into positive (H+) and negative ions (OH-). they can dissociate into negatively and positively charged poles

Answer:

-65.897°C.

Explanation:

where, ΔTf is the depression in freezing point of chloroform solution.

Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.

Answer:

-65.9 and 100.9

Explanation:

Hope this helps

Answer:

False

Explanation:

Compounds are chemically combined

lemonade is not

If the squeezed lemonade is made by squeezing lemons to extract the juice and mixing it with water and sugar, it would be a homogenous mixture.

If it contains a pulp than it would be heterogeneous

Explanation:

The total mass is:

100 g + 200 g

= 300 g

The mass of salt is:

0.20 (100 g) + 0.10 (200 g)

= 20 g + 20 g

= 40 g

So the concentration is:

40 g / 300 g

≈ 13.33%

Round as needed.

Answer:

D

Explanation:

Most if not all fields of research will post their results for others to test and find data to make sure their experiment is theoretically correct.

Scientific journals are the first repost of new scientific discoveries published. Hence, option D is correct.

Scientific papers are also called journal articles, A scientific journal is the best medium for disseminating and popularizing scientific information in the form of accomplishments, discoveries, and research findings.

In order to publish this kind of work, they are typically published in a periodical called a journal.

Thus, option D is correct.

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Answer:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Explanation:

2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction

Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.

In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.  

So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.  

As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.  

And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.  

Answer:

2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction

Answer:

B. High temp and low pressure

Explanation:

I got an A on my chem final :) Got this right.

Answer:

A gas is most likely to exist at B) High temperatures and low pressures

Explanation:

Ideal gas behaviour is likely to be at high temperature and low pressure .

The causes of deviations from ideal behaviour may be due to the following two assumptions of kinetic theory of gases.  

The volume occupied by gas molecules is negligibly small as compared to the volume occupied by the gas.

The forces of attraction between gas molecules are negligible.

Deviation occur for real gases with a minor difference from that of an Ideal gas.

When real gases are at low pressures and high temperatures they behave close enough to ideal gases