D
Nuclear reaction involves the nuclei of atoms. The nucleus can either split (as is the case with fission) of fuse as is the case with nuclear fusion. Remember the main particles in the nucleus are protons and neutrons.
Explanation:
In nuclear fission, atomic nuclei split into lighter atoms through loss of protons and neutrons (such as through loos of a beta particles - 2 protons and 2 neutrons). In the case of fusion, two atomic nuclei fuse under pressure (hence adding neutrons and protons) to create heavier atoms (2 hydrogens can fuse to form a helium). Electrons are not involved in nuclear reactions. Electrons are mainly involved in chemical reactions.
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Which substance is a mixture?
table salt
gasoline
aluminum
carbon dioxide
Answer:
Gasoline
Explanation:
Pure Substance: are those having same type of atoms or molecules.
Compound: one or more atoms of the element combine to form a compound.
Mixture: is combination of one or more substances mix together.
Homogeneous Mixture: are those which are not distinguish by naked eye but can be separated into its components by physical means
Heterogeneous mixture: are those which can be distinguishing by naked eye and can be separated into its components by physical means.
So keeping in mind the above definitions
Table salt:
The chemical formula of table salt is NaCl and it a pure compound not mixture.
Gasoline:
Gasoline is mixture of hydrocarbon, It contains small hydrocarbons ranging from 4 Carbon to 12 Carbon per molecule. it is a homogeneous mixture.
Aluminum:
Aluminum is a pure substance that is made up of same kind of atoms. so it is an element and not mixture. Its symbol is Al
Carbon dioxide:
Carbon dioxide is a pure compound and its chemical formula is CO₂ and not a mixture.
So, the write option is Gasoline.
Answer:
gasoline
Explanation:
Two types of heterogeneous mixtures are suspensions and colloids.
true or false
Explanation:
Heterogeneous mixture is a mixture with non-uniform composition.
The properties of the mixture like concentration may change for different parts of the mixture.
Colloids contain solute particles of size [tex]2nm-500nm[/tex].The presence of these particles makes the mixture heterogeneous.
Suspensions contain solute particles of size [tex]500nm-1000nm[/tex].These particles settle to the bottom of the mixture which makes the composition of the bottom different from the top.
So,colloids and suspensions are two types of heterogeneous mixtures.
Final answer:
Yes, the statement is true; suspensions and colloids are both types of heterogeneous mixtures, differentiated by the size of their particles and their tendency to settle.
Explanation:
The statement is true: suspensions and colloids are indeed two types of heterogeneous mixtures. A suspension is a heterogeneous mixture where large particles are dispersed throughout a liquid or gas and can settle over time, examples include paint and mud. On the other hand, a colloid is also a heterogeneous mixture, but it consists of much finer particles that don't settle upon standing, such as fog, milk, and butter.
Colloids can be found in various states like sols (solid particles in a liquid), gels (solids absorbing liquids), aerosols (solid or liquid particles in a gas), or emulsions (liquids dispersed in other liquids). They exhibit the Tyndall effect, where light is scattered by the particles, distinguishing them from solutions, which are homogenous and clear. Suspensions, with their larger particle size, do not maintain their dispersion upon standing and are often cloudy.
It's important to note that while suspensions and colloids are heterogeneous due to the presence of dispersed particles, these particles differ significantly in size between the two types, which influences the stability and appearance of the mixture.
A beam of light has a wavelength of 24.0 μm ( μm = 10 -6m). What is its frequency?
Choices:
a. 1.25 x 1013 Hz
b. 8.00 x 10-8 Hz
c. 1.25 x 107 Hz
d. 8.00 x 10-11 Hz
Answer:
Frequency = 1.25 ×10¹³ Hz
Explanation:
Given data:
Wavelength of light = 24.0 μm (2.4 ×10⁻⁵ m)
Frequency = ?
Solution:
Formula:
Speed of light = wavelength × frequency
Speed of light /wavelength = frequency
Frequency = 3×10⁸ m /s /2.4 ×10⁻⁵m
Frequency = 1.25 ×10¹³ s⁻¹
s⁻¹ = Hz
Frequency = 1.25 ×10¹³ Hz
if 115 G of a substance reacts with 84 grams of another substance what will be the mass of the products after the reaction
Answer:
199 g
Explanation:
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In given reaction there are two reactant one with a mass of 115 g and other with the mass of 84 g thus the resultant product must have a mass of 199 g.
Chemical equation:
A + B → AB
115 g + 84 g = 199 g
119 g = 199 g
Final answer:
The mass of the products after the reaction between 115 grams and 84 grams of two substances, according to the Law of Conservation of Mass, will be 199 grams, assuming no material is lost during the reaction.
Explanation:
If 115 grams of a substance reacts with 84 grams of another substance, according to the Law of Conservation of Mass, the mass of the products after the reaction will be the sum of the masses of the reactants. This is because in a chemical reaction, matter is neither created nor destroyed, so the total mass of the reactants must equal the total mass of the products.
In this case, adding the masses of the reactants gives us:
115 g + 84 g = 199 g
Therefore, the mass of the products after the reaction will be 199 grams. However, this assumes a perfectly efficient reaction with no losses to factors such as gas escaping the reaction vessel or side reactions. In a practical setting, a slight discrepancy might be observed due to such factors.
How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
Answer:
[tex]\large \boxed{\text{77.4 mL}}[/tex]
Explanation:
Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O
V/mL: 249
c/mol·L⁻¹: 0.0443 0.285
1. Calculate the moles of Ba(OH)₂
[tex]\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}[/tex]
2. Calculate the moles of HCl
The molar ratio is 2 mol HCl:1 mol Ba(OH)₂
[tex]\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}[/tex]
3. Calculate the volume of HCl
[tex]V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}[/tex]
For each of the following balanced chemical equations, calculate how many moles of product(s) would be produced if 0.500 mole of the first reactant were to react completely.
A) CO29(g) + 4h2(g) = CH4 (g) + 2H2O(l)
B) BaCl2 (aq) + 2AgANO3 (aq) = 2AgCl (s) + Ba(NO3)2 (aq)
c) C3H8 (g) + 5O2 (g) = 4H2O (l) + 3CO2(g)
d) 3H2SO4 (aq) + 2Fe (s) = Fe2(SO4)3 (aq) + 3H2 (g)
Answer:
A) 1.5 moles B) 1.5 moles C) 3.5 moles D) 2/3 moles
Explanation:
A) 1 mole of CO₂ gives 1 mole of CH₄ and 2 moles of H₂O, i.e, 3 moles of products. So 0.5 moles of CO₂ gives 3 x 0.5 = 1.5 moles of products.
B) 1 mole of BaCl₂ gives 2 moles of AgCl and 1 mole of Ba(NO₃)₂, i.e, 3 moles of products. So 0.5 moles of BaCl₂ gives 3 x 0.5 = 1.5 moles of products.
C) 1 mole of C₃H₈ gives 4 moles of H₂O and 3 moles of CO₂, i.e, 7 moles of products. So 0.5 moles of C₃H₈ gives 7 x 0.5 = 3.5 moles of products.
D) 3 moles of H₂SO₄ gives 1 mole of Fe₂(SO₄)₃ and 3 moles of H₂, i.e, 4 moles of products. So 0.5 moles of H₂SO₄ gives 4/3 x 0.5 = 2/3 moles of products.
To calculate the number of moles of product produced when a given amount of reactant is completely reacted, use the stoichiometric coefficients of the balanced chemical equation.
Explanation:To calculate the number of moles of product produced when a given amount of reactant is completely reacted, we need to use the stoichiometric coefficients of the balanced chemical equation. Each coefficient represents the ratio of moles between reactants and products.
For example, in the first equation, CO2 (g) + 4H2 (g) → CH4 (g) + 2H2O (l), the coefficient of CO2 is 1 and the coefficient of CH4 is also 1. This means that for every 1 mole of CO2 that reacts, 1 mole of CH4 is produced.
Therefore, if 0.500 mole of CO2 were to react completely, 0.500 mole of CH4 would be produced.
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Jason has five equally massed lead fishing weights, each weighing 250 grams. What is the total mass of the five leaf fishing weights
Answer:
Total mass of 5 lead fishing weights= 1250 grams
Explanation:
Given:
Mass of a lead fishing weight =250 grams
To find total mass of 5 such fishing weights
We can apply unitary method to find total mass of 5 fishing weights.
If mass of 1 lead fishing weight = 250 grams
∴ Total mass of 5 lead fishing weights = [tex]250\times 5 =1250\ grams[/tex]
Which of the following is true of gas?
A gas is not compressed because of the low intermolecular forces.
a gas does not easily mix with other gases becasye of the high density of substances as gases.
gas particles have high intermolecular forces, leading to the ability to flow easily. gas particles spread out to fill a container, leading to a low density of gas
Answer:
Gases mix easily because of their high kinetic energy and low inter-molecular forces.
Explanation:
Answer:
Gases mix easily because of their high kinetic energy and low inter-molecular forces.
Explanation:
How can general properties influence element location on a periodic table?
Answer:
The elements in the periodic table are arranged in order of increasing atomic number.
Explanation:
The elements are arranged based on their atomic numbers in a periodic table, not based on their atomic masses.
• The chemical elements in the periodic table are demonstrated in order of their atomic number.
• In the modern periodic table, the arrangement of elements is done based on their atomic number, not their relative atomic masses.
• In the periodic table, the horizontal rows, known as periods, show the arrangement of elements in order of increasing atomic number.
Thus, based on atomic numbers, elements are arranged in a periodic table.
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How many decigrams are in 4.6 decagrams?
0.0046 decigrams
0.046 decigrams
460 decigrams
4,600 decigrams
Answer:
[tex]\large \boxed{\text{460 dg}}[/tex]
Explanation:
1. Convert decagrams to grams
[tex]\text{Mass} = \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}[/tex]
2. Convert grams to decigrams
\[tex]\text{Mass} = \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}[/tex]
The procedure for an experiment is _____.
A. the variable that you will change
B. a set of safety rules that you need to follow in the lab
C. what you're going to do and how you're going to do it
D. research you've done about the topic you're investigating
Answer:
the correct answer would be c.
Answer: The correct answer is: C. what you're going to do and how you're going to do it
Explanation: A good experiment should follow a design with a few logical steps. An experiment must be carried out methodically in order to perform valid and reliable measurements. Experimenting is a procedure to check one or several hypotheses about a specific topic.
Write the equations for the esterification process between ethanoic acid and 2-
propanol with sulphuric acid as catalyst.
Answer: CH3COOH + CH3CHOHCH3 -> CH3COOCH(CH3)CH3 + H2O
Explanation: Estherification is the reaction between alkanoic acids and alkanols to porduce esters and what. ethanoic acid will react with 2-propanol to produce an ester and water.
Ethanoic acid reacts with 2-propanol to form an ester and water in the presence of sulfuric acid.
[tex]\bold {CH_3COOH + CH_3CHOHCH_3 \rightarrow CH_3COOCH(CH_3)CH_3 + H_2O}[/tex]
What is Esterification?It is a type of reaction in which typically acid and alcohol react to form an ester product.The ester is derived from acid when the hydroxyl group is replaced by an alkyl group.Ethanoic acid reacts with 2-propanol to form an ester and water in the presence of sulfuric acid.[tex]\bold {CH_3COOH + CH_3CHOHCH_3 \rightarrow CH_3COOCH(CH_3)CH_3 + H_2O}[/tex]
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Which are examples of physical weathering? Check all that apply.
grinding away of rock surface
top layers flaking off due to release of pressure
water dissolving soft rock
rust forming due to oxidation
temperature changes from hot to cold
animals digging burrows to make homes
water freezing, expanding and thawing repeatedly
acid rain weathering a statue
tree roots growing in the cracks of rock
Final answer:
Physical weathering refers to the process of breaking down rocks without changing their chemical composition. Examples include grinding away of rock, flaking due to pressure release, and water freezing and thawing.
Explanation:
Physical weathering refers to the process of breaking down rocks into smaller pieces without changing their chemical composition. Examples of physical weathering include the grinding away of a rock surface, the top layers of rock flaking off due to the release of pressure, and the freezing and thawing of water, which causes it to expand and contract and break the rock apart.
Other examples include tree roots growing in the cracks of rocks and animals digging burrows. On the other hand, rust forming due to oxidation and acid rain weathering a statue are examples of chemical weathering.
Final answer:
Physical weathering includes processes like abrasion, exfoliation, temperature fluctuations, freeze-thaw cycles, animal activities, and root wedging, all of which disintegrate rock mechanically.
Explanation:
The examples of physical weathering are those processes that result in the breakdown of rock without altering its chemical composition. Here are the examples that correctly apply to the concepts of physical weathering:
Grinding away of rock surface due to abrasionTop layers flaking off due to release of pressure (exfoliation)Temperature changes from hot to cold causing expansion and contractionWater freezing, expanding, and thawing repeatedly in cracks (freeze-thaw weathering)Animals digging burrows to make homes (biomechanical weathering)Tree roots growing in the cracks of rock (root wedging)On the other hand, the following are not examples of physical weathering because they involve chemical changes to the rock: water dissolving soft rock, rust forming due to oxidation, and acid rain weathering a statue.
How many moles are there in 8.50 X 10^24 molecules of sodium sulfate, Na2SO3?
(Molecules to Moles)
A.) 51.2 moles
B.) 5.12x10^48 moles
C.)14.1 moles
D.)1.40 Moles
Answer:
C) 14.1 moles
Explanation:
1 mole = 6.02 *10^ 23
8.50 * 10^24 molecules *(1 mole/6.02*10^23 molecules) ≈ 14.1 moles
The number of moles there are in 8.50 X [tex]10^{24}[/tex] molecules of sodium sulfate is 14.1 moles (option C).
How to calculate number of moles?The number of moles in a molecule of a substance can be calculated by dividing the number of molecules by Avogadro's number as follows:
no of moles = no of molecules ÷ 6.02 × [tex]10^{23}[/tex] molecules
According to this question, there are in 8.50 X [tex]10^{24}[/tex] molecules of sodium sulfate in a substance. The number of moles in this substance can be calculated as follows:
no of moles = 8.50 X [tex]10^{24}[/tex] ÷ 6.02 × [tex]10^{23}[/tex]
no of moles = 14.1 moles
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Please help would really appreciate it! Thank you so much! ❤️ Have a wonderful day!
Answer:
option b : O₉S₁₀
Explanation:
There are some points to name a covalent compound, according to that
number of atoms numbered as
**mono for one, di - for two tri for three and so on.
the name of the atom as
**carbon as carbide, sulfur as sulfide, oxygen as oxide, foulrine as flouro etc.
So,
Formula of Nonoxide decasulfide
Now Naming of the Chemical compound
Following are the explanations of terms
Prefix nono is used for number ''9'' denoting to the number of atomOxide used for oxygendeca is use for number ''10'' denoting to the number of atomSulfide is used for Sulfur in a compoundSo keeping the above points in mind
The right answer is
Option b : O₉S₁₀
Draw Lewis structures for each of the following.
1. nitrogen trifluoride, NF3
2. hydrogen sulfide, H2S
3. fluorine, F2
4. carbon monoxide, CO
5. sulfur dioxide, SO2
6. oxygen, O2
7. sulfur difluoride, SF2
8. boron trihydride, BHz
9. chloroform, CHCl3
10. carbon disulfide, CS2
11. beryllium chloride, BeCl2
12. hydrogen cyanide, HCN
13. acetylene, C2H2
14. silicon dioxide, SiO2
15. hydrogen peroxide, H2O2
16. sulfate, SO2-
17. methanol, CH3OH
18. nitrate, NO3
19. chlorite, CIO,
20. formic acid, CH2O
Answer:
Structures Attached
Explanation:
1. Total Number of e⁻ in NF₃
Number of e in Nitrogen = 5
Number of e in Flourine = 7
Total Number of e⁻ in NF₃ = 5 + 7(3)
Total Number of e⁻ in NF₃ = 5 + 21
Total Number of e⁻ in NF₃ = 26
2. Total Number of e⁻ in H₂S
Number of e in Hydrogen = 1
Number of e in sulphur = 6
Total Number of e⁻ in H₂S = 1(2) + 6
Total Number of e⁻ in H₂S = 2 + 6
Total Number of e⁻ in H₂S = 8
3. Total Number of e⁻ in F₂
Number of e in Flourine = 7
Total Number of e⁻ in F₂ = 7(2)
Total Number of e⁻ in F₂ = 14
4. Total Number of e⁻ in CO
Number of e in carbon = 4
Number of e in oxygen = 6
Total Number of e⁻ in CO = 4 + 6
Total Number of e⁻ in CO = 10
5. Total Number of e⁻ in SO₂
Number of e in Sulphur = 6
Number of e in oxygen = 6
Total Number of e⁻ in SO₂ = 6 + 6(2)
Total Number of e⁻ in SO₂ = 6 + 12
Total Number of e⁻ in SO₂ = 18
6. Total Number of e⁻ in O₂
Number of e in Oxygen = 6
Total Number of e⁻ in O₂ = 6(2)
Total Number of e⁻ in O₂ = 12
7. Total Number of e⁻ in SF₂
Number of e in Sulphur = 6
Number of e in Flourine = 7
Total Number of e⁻ in SF₂ = 6 + 7(2)
Total Number of e⁻ in SF₂ = 6 + 14
Total Number of e⁻ in SF₂ = 20
8. Total Number of e⁻ in BH₃
Number of e in Boron = 3
Number of e in Hydrogen = 1
Total Number of e⁻ in BH₃ = 3 + 1(3)
Total Number of e⁻ in BH₃ = 3 + 3
Total Number of e⁻ in BH₃ = 6
9. Total Number of e⁻ in CHCl₃
Number of e in Carbon = 4
Number of e in Hydrogen = 1
Number of e in chlorine = 7
Total Number of e⁻ in CHCl₃ = 4 + 1+ 7(3)
Total Number of e⁻ in CHCl₃ = 4 + 1 + 21
Total Number of e⁻ in CHCl₃ = 26
10. Total Number of e⁻ in CS₂
Number of e in Carbon = 4
Number of e in Sulphur = 6
Total Number of e⁻ in CS₂ = 4 + 6(2)
Total Number of e⁻ in CS₂ = 4 + 12
Total Number of e⁻ in CS₂ = 16
11. Total Number of e⁻ in BeCl₂
Number of e in Beryllium = 2
Number of e in Chlorine = 7
Total Number of e⁻ in BeCl₂ = 2 + 7(2)
Total Number of e⁻ in BeCl₂ = 2 + 14
Total Number of e⁻ in BeCl₂ = 16
12. Total Number of e⁻ in HCN
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Carbon = 4
Number of e⁻ in Nitrogen = 5
Total Number of e⁻ in HCN = 1 + 4 + 5
Total Number of e⁻ in HCN = 10
13. Total Number of e⁻ in C₂H₂
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Total Number of e⁻ in C₂H₂ = 4(2) + 1(2)
Total Number of e⁻ in C₂H₂ = 8 + 2
Total Number of e⁻ in C₂H₂ = 10
14. Total Number of e⁻ in SiO₂
Number of e⁻ in Silicon = 4
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in SiO₂ = 4 + 6(2)
Total Number of e⁻ in SiO₂ = 4 + 12
Total Number of e⁻ in SiO₂ = 16
15. Total Number of e⁻ in H₂O₂
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in H₂O₂ = 1(2) + 6(2)
Total Number of e⁻ in H₂O₂ = 2 + 12
Total Number of e⁻ in H₂O₂ = 14
16. Total Number of e⁻ in SO₂⁻
Number of e in Sulphur = 6
Number of e in Oxygen = 6
Total Number of e⁻ in SO₂⁻ = 6 + 6(2)
Total Number of e⁻ in SO₂⁻ = 6 + 12
Total Number of e⁻ in SO₂⁻ = 18
17. Total Number of e⁻ in CH₃OH
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in CH₃OH = 4 + 1(3) + 6 + 1
Total Number of e⁻ in CH₃OH = 4 + 3 + 6 + 1
Total Number of e⁻ in CH₃OH = 14
18. Total Number of e⁻ in NO₃
Number of e⁻ in Nitrogen = 5
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in NO₃ = 5 + 6(3)
Total Number of e⁻ in NO₃ = 5 + 18
Total Number of e⁻ in NO₃ = 23
19. Total Number of e⁻ in ClO
Number of e⁻ in Chlorine = 7
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in ClO = 7 + 6
Total Number of e⁻ in ClO = 7 + 6
Total Number of e⁻ in ClO = 13
20. Total Number of e⁻ in CH₂O
Number of e⁻ in Carbon = 4
Number of e⁻ in Hydrogen = 1
Number of e⁻ in Oxygen = 6
Total Number of e⁻ in CH₂O = 4 + 1(2) + 6
Total Number of e⁻ in CH₂O = 4 + 2 + 6
Total Number of e⁻ in CH₂O = 12
Lewis structures for different molecules are provided, including nitrogen trifluoride, hydrogen sulfide, fluorine, carbon monoxide, sulfur dioxide, oxygen, sulfur difluoride, boron trihydride, chloroform, carbon disulfide, beryllium chloride, hydrogen cyanide, acetylene, silicon dioxide, hydrogen peroxide, sulfate, methanol, nitrate, chlorite, and formic acid.
Explanation:Nitrogen trifluoride, NF3: Nitrogen (N) is the central atom and it forms single bonds with three fluorine (F) atoms. Each fluorine atom has a lone pair of electrons.Hydrogen sulfide, H2S: Hydrogen (H) is the central atom and it forms single bonds with two sulfur (S) atoms. Each sulfur atom has a lone pair of electrons.Fluorine, F2: Fluorine (F) forms a single bond with another fluorine atom.Carbon monoxide, CO: Carbon (C) is the central atom and it forms a triple bond with oxygen (O).Sulfur dioxide, SO2: Sulfur (S) is the central atom and it forms a double bond with one oxygen (O) atom and a single bond with another oxygen atom. The oxygen atom with the double bond has two lone pairs of electrons.Oxygen, O2: Oxygen (O) forms a double bond with another oxygen atom.Sulfur difluoride, SF2: Sulfur (S) is the central atom and it forms a single bond with two fluorine (F) atoms. The sulfur atom has two lone pairs of electrons.Boron trihydride, BH3: Boron (B) is the central atom and it forms three single bonds with hydrogen (H) atoms.Chloroform, CHCl3: Carbon (C) is the central atom and it forms a single bond with three hydrogen (H) atoms and a single bond with chlorine (Cl) atom. The chlorine atom has three lone pairs of electrons.Carbon disulfide, CS2: Carbon (C) is the central atom and it forms double bonds with two sulfur (S) atoms.Beryllium chloride, BeCl2: Beryllium (Be) is the central atom and it forms two single bonds with chlorine (Cl) atoms.Hydrogen cyanide, HCN: Carbon (C) is the central atom and it forms a triple bond with nitrogen (N). The nitrogen atom has a lone pair of electrons.Acetylene, C2H2: Carbon (C) is the central atom and it forms triple bonds with another carbon atom. Each carbon atom forms single bonds with two hydrogen (H) atoms.Silicon dioxide, SiO2: Silicon (Si) is the central atom and it forms a double bond with one oxygen (O) atom and a single bond with another oxygen atom. The oxygen atom with the double bond has two lone pairs of electrons.Hydrogen peroxide, H2O2: Oxygen (O) is the central atom and it forms single bonds with two hydrogen (H) atoms. Each oxygen atom has two lone pairs of electrons.Sulfate, SO2-: Sulfur (S) is the central atom and it forms a double bond with one oxygen (O) atom and two single bonds with other oxygen atoms. The oxygen atoms with single bonds have a lone pair of electrons.Methanol, CH3OH: Carbon (C) is the central atom and it forms single bonds with three hydrogen (H) atoms, a single bond with oxygen (O) atom, and also has a lone pair of electrons. The oxygen atom has two lone pairs of electrons.Nitrate, NO3-: Nitrogen (N) is the central atom and it forms a double bond with one oxygen (O) atom and two single bonds with other oxygen atoms. The oxygen atoms with single bonds have a lone pair of electrons.Chlorite, CIO-: Chlorine (Cl) is the central atom and it forms a single bond with oxygen (O) atom and has two lone pairs of electrons. The oxygen atom has two lone pairs of electrons.Formic acid, CH2O: Carbon (C) is the central atom and it forms single bonds with two hydrogen (H) atoms, a single bond with oxygen (O) atom, and also has a lone pair of electrons. The oxygen atom has two lone pairs of electrons.Learn more about Lewis structures here:https://brainly.com/question/34631490
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how many moles are in 75.02 grams of strontium
Answer:
1 grams Strontium Fluoride to mol = 0.00796 mol
10 grams Strontium Fluoride to mol = 0.07961 mol
50 grams Strontium Fluoride to mol = 0.39804 mol
100 grams Strontium Fluoride to mol = 0.79607 mol
200 grams Strontium Fluoride to mol = 1.59214 mol
500 grams Strontium Fluoride to mol = 3.98036 mol
1000 grams Strontium Fluoride to mol = 7.96072 mol
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Which chemical equation represents a precipitation reaction?
Answer:
See the answer below, please.
Explanation:
A precipitation reaction is defined as one that yields an insoluble compound (precipitate) as a product by mixing two different solutions. An example:
NaCl + AgN03 -> Agcl (precipitate) + NaN03
Answer:
K2CO3 + PbCl2 → 2KCl + PbCO3
Explanation:
This is correct because a percipitant solution is one that has an insoluble compound in it and PbCO3 is insoluble since the Pb is not amonium or an alkaline metal. The compound PbCO3 is unsoluable and 2KCl is soluable.
SOLUBILITY RULES:
1.) Hydroxides (OH−), carbonates (CO32−), and phosphates (PO43−) are insoluble, except for compounds containing group 1 alkali metals and ammonium (NH4+).
2.) Chlorides (Cl−), bromides (Br−), and iodides (I−) are soluble, except for compounds containing silver (Ag+), mercury(I) (Hg22+), and lead (Pb2+).
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Answer:
All of these
option a to f are molecule
Explanation:
Molecule:
Molecule is formed when two or more than two atoms of an element combine chemically.
N₂O₄ is a molecule where Nitrogen combine with oxygen through covalent bond.
The name of this compound is Dinitrogen tetraoxide.
Na₂CO₃ is a Compound where sodium carbon and oxygen combined to form a Compound.
Its name is sodium carbonate.
CClF3 is a Compound: It is a polar Compound
It named as Chlorofloromethan.
OBr₂ is polar Molecule. This molecule consist of oxygen and Bromine atoms and a covalent compound.
It named as oxygen dibromide.
FeSO₄ is a compound . it consists of iron Oxygen and sulfate atoms.
It named as Iron Sulfate.
LiBr is molecule. it is ionic in nature and Known as molecular compound
It named as Lithium bromide.
All molecule can not be compound as some molecule have same type of atom such as ozone or hydrogen molecule., but all compounds are molecule, so with this concept all of these are molecule.
4. 450g of chromium (III) sulfate reacts with excess potassium phosphate. How many grams of
potassium sulfate will be produced? (ANS: 6.0x10ʻg K2SO4)
Answer:
[tex]1.6\times 103[/tex]g of K₂SO₄ will be produced
Explanation:
Given [tex]K_3PO_4[/tex] is available in excess
Reaction:
Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄
From the above reaction, it is clear that the moles of (Cr₂(SO₄)₃), [tex]K_3PO_4[/tex] and K₂SO₄ are 1, 2 and 3 respectively
We can say that 1 mole of chromium(iii) sulfate (Cr₂(SO₄)₃) react with 2 mole of potassium phosphate (K₃PO₄) to produce 3 mole of K₂SO₄
molar mass of Cr₂(SO₄)₃ = 147 g/mol
molar mass of K₃PO₄ = 212 g/mol
molar mass of K₂SO₄ = 174 g/mol
We can write as;
Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄
1 mol (147 g/mol) 2 mol (212 g/mol) 3 mol (174g/mol)
Therefore, we have
Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄
147 g 424 g 522 g
So, we can see that 147 g of Cr₂(SO₄)₃ reacts with 424 g of 2K₃PO₄ to produce 522 g of K₂SO₄
147 g of Cr₂(SO₄)₃ = 522 g of K₂SO₄
So, 450 g of Cr₂(SO₄)₃ = [tex]\frac{(522\times 450)}{147}[/tex]g of K₂SO₄ = 1597.959 g = [tex]1.59\times 103[/tex] g = [tex]1.6\times 103[/tex] g
So,[tex]1.6\times 103[/tex]g of K₂SO₄ will be produced
1. Ir a mixture contains 0.639 g NaCl, 0.350 g NHACI, & 0.851 g of SiO2, with due regar
Signiricant figures, what is the mass percent of NaCl in the mixture?
34.73%
Explanation:We are given;
A mixture that contains;
NaCl = 0.639 g NH₄Cl = 0.350 g SiO₂ = 0.851 gWe are required to determine mass percent of NaCl in the mixture;
Step 1: Determine the total mass of the mixture;Mass of the mixture = Mass of NaCl + Mass of NH₄Cl + Mass of SiO₂
= 0.639 g + 0.350 g + 0.851 g
= 1.84 g
Step 2: Calculate the mass percent of NaCl in the mixtureThe mass % of NaCl = (Mass of NaCl ÷ Mass of the mixture) 100
= (0.639 g ÷ 1.84 g) × 100
= 34.73%
Therefore, the mass % of NaCl in the mixture is 34.73%
KAYLA BURNED A CANDLE IN A CLOSED SYSTEM WHERE MATTER CANNOT ENTER OR ESCAPE. GIVEN THIS SITUATION, WHAT SHOULD EQUAL THE MASS OF THE ORIGINAL CANDLE
Answer:same
Explanation:
Condensation will most likely occur in a given volume
of air when the air is
A) saturated and contains no condensation nuclei
B) saturated and contains condensation nuclei
C) unsaturated and contains no condensation nuclei
D) unsaturated and contains condensation nuclei
Condensation is most likely to occur when air is saturated and contains condensation nuclei, as the saturation represents the maximum capacity for water vapor and the nuclei act as a base for the water vapor to condense into droplets.
Explanation:Condensation can most likely occur in a given volume of air when the air is saturated and contains condensation nuclei. The saturation of air refers to its maximum capacity to hold water vapor. After reaching its saturation point, air cannot dissolve more water vapor, and any further addition of water vapor will lead to condensation. On the other hand, condensation nuclei are tiny particles that water vapor latches onto to form water droplets, facilitating the process of condensation. Therefore, air that is not only saturated with water vapor but also contains condensation nuclei has the strongest propensity for condensation to occur.
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Please help will give 40 points and brainiest
Examine the following reactions.
Reaction 1
PCl3(g) + Cl2(g) → PCl5(g)
Reaction 2
PCl5(g) → PCl3(g) + Cl2(g)
Which options correctly explain the relationship between the two reactions?
Select all that apply.
Both reactions contain entirely gaseous substances, making them both decomposition reactions.
Both reactions contain all the same substances, making them both synthesis reactions.
Reaction 1 is the opposite of Reaction 2.
The reactant in Reaction 2 breaks apart, making it a decomposition reaction.
The reactants in Reaction 1 combine instead of breaking apart, making it a synthesis reaction.
Reaction 1 is the same as Reaction 2.
The relationship between the two reactions is correctly explained as chemical equation 1 is the opposite of Reaction 2.The reactant in Reaction 2 breaks apart, making it a decomposition reaction.
What is chemical equation?
Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.
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Cathode rays are composed of_____.
a. protons
b. electrons
c. neutrons
Answer:
negatively-charged particles.(ELECTRON) B
Explanation:
Electrons are the negatively charged particles of atom. Together, all of the electrons of an atom create a negative charge that balances the positive charge of the protons in the atomic nucleus
Which methods could be used to dilute a solution of sodium chloride (NaCl)?
Answer: Add more water to the solution and remove a small amount of the solution and mix it with water.
How could soil and a mouse interact in an ecosystem?
Answer:
Explanation:
It could make burrows and homes in the dirt. It could hide food and itself in the soil. The Soil will grow food.
In an ecosystem , a mouse would make burrows in soil and soil would provide nutrients to the mouse.
What is an ecosystem?Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.
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Vhat is the molarity of an Nal solution that contains 7.0 g of Nal in 23.0 mL of solution?
Answer:
Molarity = 5.22 M
Explanation:
Given data:
Mass of sodium chloride = 7.0 g
Volume of solution = 23.0 mL ( 23.0/1000 = 0.023 L)
Molarity = ?
Solution;
Number of moles of NaCl = 7.0 g/ 58.4 g/mol
Number of moles of NaCl = 0.12 mol
Molarity = moles of solute / volume in litter
Molarity = 0.12 mol / 0.023 L
Molarity = 5.22 M
can someone please please explain how to write the formula for a compound containing a polyatomic ion. If you could include examples that would be great too!
Answer:
Explanation:
Polyatomic ions are ions which consist of more than one atom. For example, nitrate ion, NO3-, contains one nitrogen atom and three oxygen atoms. The atoms in a polyatomic ion are usually covalently bonded to one another, and therefore stay together as a single, charged unit.
To write the formula for a compound with a polyatomic ion, consider that the compound should be electrically neutral. Balance the charges from different ions, treating polyatomic ions as discrete units. For instance, calcium phosphate (Ca3(PO4)2) illustrates this with three calcium ions and two phosphate ions.
Explanation:When writing the formula for a compound containing a polyatomic ion, you must consider that the compound has to be electrically neutral overall. This often involves balancing the number of positive and negative charges coming from different ions. The polyatomic ions are usually treated as discrete units in the formula.
For example, consider calcium phosphate, which has the formula Ca3(PO4)2. Here, there are three calcium ions (Ca²+), and two phosphate groups (PO4³-). Each PO4³- group comprises one phosphorus atom and four oxygen atoms. The overall compound is electrically neutral because the positive charges from the three calcium ions balance out the negative charges from the two phosphate ions.
Another example can be seen in the ionic compound sodium oxalate, which has the formula Na₂C₂O₄. Here, the polyatomic ion is C₂O₄²-, and the compound has two sodium ions (Na⁺) for each oxalate ion. The formula of this compound is not empirical because it represents the number of atoms in the discrete unit of the oxalate ion.
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What's C2H6O2 in empirical formula?
The empirical formula for [tex]C_2H_6O_2[/tex] is [tex]CH_3O[/tex], obtained by finding the simplest whole-number ratio of the elements after dividing the number of atoms in the molecular formula by the greatest common divisor.
To determine the empirical formula of [tex]C_2H_6O_2[/tex], we need to find the simplest whole-number ratio of the atoms of each element in the compound. We can start by noting that the number of carbon (C), hydrogen (H), and oxygen (O) atoms as represented in the molecular formula [tex]C_2H_6O_2[/tex].
Looking at the subscripts of the elements, we can divide each by the greatest common divisor of the subscripts, which is 2. Doing this, we get:
Carbon: 2 / 2 = 1
Hydrogen: 6 / 2 = 3
Oxygen: 2 / 2 = 1
Therefore, the empirical formula is [tex]CH_3O[/tex]. To clarify, this is the simplest form of a formula representing the chemical composition.
As a check, if we consider the molecular formula of a very different compound, glucose, which is [tex]C_6H_{12}O_6[/tex], the empirical formula is [tex]CH_2O[/tex], because it is the simplest whole-number ratio, which in glucose's case is 1:2:1 for carbon, hydrogen, and oxygen atoms, respectively.