Which of the following are opposite rays?
A. TV and TS
B. TX and TL
C. TS and TX
D. TL and TV

Which Of The Following Are Opposite Rays?A. TV And TS B. TX And TL C. TS And TX D. TL And TV

Answers

Answer 1
B) TX and TL is correct.
Answer 2

The correct answer is:

B. TX and TL  

Explanation:

Opposite rays are rays that have the same endpoint and extend in opposite directions.  The ones in the diagram that fit this description are TX and TL.


Related Questions

A grid map marks the plot of Harold’s garden in meters. The coordinates of the quadrilateral-shaped property are G(–8, 3), A(4, 8), R(10, 0), and D(–2, –5). He wants to build a short fence around the garden. The perimeter of his garden is meters.

Answers

Answer:

46, i did the assignment on edge   hope this helps!   :)

Step-by-step explanation:

On a coordinate plane, quadrilateral D G A R is shown. Point G is at (negative 8, 3), point A is (4, 8), point R is at (10, 0), and point (negative 2, negative 5).

A grid map marks the plot of Harold’s garden in meters. The coordinates of the quadrilateral-shaped property are G(–8, 3), A(4, 8), R(10, 0), and D(–2, –5). He wants to build a short fence around the garden.

The perimeter of his garden is  meters. 46

The Perimeter of garden as shown in the quadrilateral 46 units

Distance

The distance between two points is the amount of space between the points. From the quadrilateral:

[tex]AG=\sqrt{(8-3)^2+(4-(-8))^2}=13 \ units\\\\AR=\sqrt{(8-0)^2+(4-10)^2}=10 \ units\\\\GD=\sqrt{(-5-3)^2+(-2-(-8))^2}=10 \ units\\\\RD=\sqrt{(-5-0)^2+(-2-10)^2}=13 \ units\\[/tex]

Perimeter of garden = AG + AR + GD + RD = 13 + 10 + 13 + 10 = 46 units

The Perimeter of garden as shown in the quadrilateral 46 units

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A scale drawing of an automobile has a scale of 1 in.
The actual width of the car is 8 ft. What is the width on the scale drawing?

Answers

the correct question in the attached figure

we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for  actual width of the car  8 ft
[scale drawing]=[2 in/ft]*[8 ft]=16 in

the answer is 16 in

❤️ Kinda fuzzy but can anyone help?

Answers

The answer would be B.

Answer:

thats to hard

Step-by-step explanation:

get a calculater

What is the solution to the equation g(x) = 3?

x = 3

3 < x < 5

3 ≤ x ≤ 4

3 ≤ x < 5

Answers

The correct answer is:  [A]:  " x = 3 " .
__________________________________________________

helpppppppppppppppppppppppp

Answers

Remember that
 you must do in this case is composition of both functions: 
 a (x) = 3x + 1 
 b (x) = root (x-4) 
 Making the composition we have: 
 b (a (x)) = root ((3x + 1) -4) 
 Rewriting: 
 b (a (x)) = root (3x-3) 
 b (a (x)) = root (3 (x-1)) 
 Answer: 
 The domain of the function is: x> = 1 
 Equivalently we have [1, inf)

If a piece of licorice is to be cut into 10 equal-side pieces. If the length of the piece of licorice is 2/3 yard, how long will each piece of licorice be?

Answers

This is the term used to describe economic systems in which the basic economic questions are answered based on a socially, pre-established way.

PLEASE HELP
7.01

1. Find the first six terms of the sequence.
a1 = 4, an = an-1 + 8


A) 0, 8, 16, 24, 32, 40
B) 12, 20, 28, 36, 44, 52
C) 4, 12, 20, 28, 36, 44
D) 4, 8, 16, 24, 32, 40

2. Find the first six terms of the sequence.
a1 = -8, an = 5 an-1

A) -8, -40, -200, -1000, -5000, -25,000
B) -8, -40, -35, -30, -25, -20
C) 0, 5, -40, -35, -30, -25
D) -40, -200, -1000, -5000, -25,000, -125,000

3. Find an equation for the nth term of the arithmetic sequence.
8, 6, 4, 2, ...


A) an = 8 + -2(n)
B) an = 8 - 2
C) an = 8 + -2(n + 1)
D) an = 8 + -2(n - 1)

4. Find an equation for the nth term of the arithmetic sequence.
-17, -12, -7, -2, ...


A) an = -17 + 5(n + 2)
B) an = -17 + 5(n + 1)
C) an = -17 + 5(n - 1)
D) an = -17 x 5(n - 1)

5. Find an equation for the nth term of the arithmetic sequence.
a19 = -58, a21 = -164

A) an = 896 - 53(n - 2)
B) an = 896 - 53(n - 1)
C) an = 896 + 53(n + 1)
D) an = 896 - 53(n + 1)

6. A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 200 centimeters tall.

Answers

1. Find the first six terms of the sequence.a1 = 4, an = an-1 + 8
 For this case, the first thing you should do is replace the values ​​given one by one.
 We have then:
 a1 = 4
 a2 = a1 + 8 = 4 + 8 = 12
 a3 = a2 + 8 = 12 + 8 = 20
 a4 = a3 + 8 = 20 + 8 = 28
 a5 = a4 + 8 = 28 + 8 = 36
 a6 = a5 + 8 = 36 + 8 = 44
 Answer:
 C) 4, 12, 20, 28, 36, 44


 2. Find the first six terms of the sequence.
a1 = -8, an = 5 an-1
 
 For this case, the first thing you should do is replace the values ​​given one by one.
 We have then:
 a1 = -8,
 a2 = 5 ^ (- 8) = -40
 a3 = 5 ^ (- 40) = -200
 a4 = 5 ^ (- 200) = -1000
 a5 = 5 ^ (- 1000) = -5000
 a6 = 5 ^ (- 5000) = -25000
 answer:
 A) -8, -40, -200, -1000, -5000, -25,000

 3. Find an equation for the nth term of the arithmetic sequence.
8, 6, 4, 2, ...
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 8, 6, 4, 2,
 The sequence is:
 an = 8 + -2 (n - 1)
 a1 = 8 + -2 (1 - 1) = 8
 a2 = 8 + -2 (2 - 1) = 6
 Answer:
 An equation for the nth term of the arithmetic sequence is
 D) an = 8 + -2 (n - 1)

 4. Find an equation for the nth term of the arithmetic sequence.
-17, -12, -7, -2, ...
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 -17, -12, -7, -2,
 The sequence is:
 an = -17 + 5 (n - 1)
 a1 = -17 + 5 (1 - 1) = - 17
 a2 = -17 + 5 (2 - 1) = - 12
 Answer:
 Answer:
 An equation for the nth term of the arithmetic sequence is
 C) an = -17 + 5 (n - 1)



 5. Find an equation for the nth term of the arithmetic sequence.
a19 = -58, a21 = -164
 What you must do for this case is to verify which sequence is best suited to the problem.
 For this case we have:
 a19 = -58, a21 = -164
 The sequence is:
 an = 896 - 53 (n - 1)
 a19 = 896 - 53 (19 - 1) = - 58
 a21 = 896 - 53 (21 - 1) = - 164
 Answer:
 An equation for the nth term of the arithmetic sequence is
 B) an = 896 - 53 (n - 1)

 6. A certain species of tree grows an average of 0.5 cm per week. Write an equation for the sequence that represents the weekly height of this tree in centimeters if the measurements begin when the tree is 200 centimeters tall.

 For this case, what you should do is to write the equation step by step to find the correct result.
 We have then:
 the measurements begin when the tree is 200 centimeters tall
 200
 tree grows an average of 0.5 cm per week
 200 + 0.5n
 Where
 n: number of weeks.
 answer:
 An equation for the sequence that represents the weekly height of this tree in centimeters is
 an = 200 + 0.5n
Final answer:

The answers identified are: (C) for the first sequence question, (A) for the second sequence question, (D) for the arithmetic sequence with a start of 8 and difference -2, (C) for the arithmetic sequence starting from -17, (B) for the arithmetic sequence question with given a19 and a21, and finally an = 200 + 0.5n for the tree growth question.

Explanation:

The correct answers are as follows:

For the first question, you start with 4 (a1 = 4) and each subsequent term is the previous term plus 8 (an = an-1 + 8). This gives the sequence 4, 12, 20, 28, 36, 44, which matches option (C).For the second question, starting at -8 (a1 = -8) and then multiplying the previous term by 5 gives you -8, -40, -200, -1000, -5000, -25,000, which matches option (A).For the third question, the common difference between consecutive terms is -2 and the first term is 8, which gives an = 8 - 2(n - 1) (option D)For the fourth question, the common difference is +5 and the first term is -17, so the equation for the nth term is an = -17 + 5(n - 1) (option C). For the fifth question, the common difference can be calculated from the problem as 53. Hence the equation for the nth term is an = 896 - 53(n - 1) (option B).For the last question, if the tree grows at a rate of 0.5 cm per week and the initial height is 200 cm, the height of the tree each week is represented by an = 200 + 0.5n.

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Write the equation of a circle with a center at (15, –35) and a diameter of 100.

(x – 15)2 + (y + 35)2 = 250

(x – 15)2 + (y + 35)2 = 50

(x – 15)2 + (y + 35)2 = 2500

(x – 15)2 + (y + 35)2 = 100

Answers

(x-15)2+ (y+35)2=2500. for sure without a doubt.

∆ABC has side lengths of 10 units, 20 units, and 24 units. ∆XYZ is similar to ∆ABC, and the length of its longest side is 60 units. The perimeter of ∆XYZ is units. If the height of ∆ABC, with respect to its longest side being the base, is 8 units, the area of ∆XYZ is square units. NextReset

Answers

To find the perimeter of triangle XYZ, you will need to find out how many groups of 24 it takes to get 60(both are the longest sides). The answer is 2.5 (You divide to get this). You then multiply the other 2 sides (20 and 10) by 2.5. The other two sides would be 50 and 25. Add 60+50+25 to get a perimeter of 135 units. To find the area, you will use the same factor (2.5) to find the height of triangle XYZ. So, 8 x 2.5= 20 for the height of triangle XYZ. Please see the picture to help further understand this relationship and see the work for finding the area of triangle XYZ.

Final answer:

The perimeter of ΔXYZ is 25 units and the area of ΔXYZ is 40 square units.

Explanation:

In this problem, we are given that ΔABC has side lengths of 10 units, 20 units, and 24 units, and ΔXYZ is similar to ΔABC. We are also given the length of the longest side of ΔXYZ as 60 units. To find the perimeter of ΔXYZ, we need to add up the lengths of all its sides. Since the longest side of ΔABC is 24 units, and the longest side of ΔXYZ is 60 units, we can set up the following proportion:

24/10 = 60/x

Cross-multiplying gives us:

24x = 600

x = 600/24 = 25 units

Therefore, the perimeter of ΔXYZ is 25 units.

Now, to find the area of ΔXYZ, we can use the proportional relationship between the areas of similar triangles. Since the ratio of the longest sides is 60/24 = 5/2, the ratio of the areas will be (5/2)^2 = 25/4. Since the area of ΔABC is 1/2 times the base times the height, we can use the same formula for ΔXYZ with the corresponding measurements:

Area of ΔXYZ = (1/2) * 10 * 8 = 40 square units

Which table of ordered pairs represents a proportional relationship

Answers

Your answer is (B.) because 2 times 5 is 10. 4 times 5 is 20. and 6 times 5 is 30, these make proportional relationships.

Answer:

The second table.

Step-by-step explanation:

In this case, "a proportional relationship" refers to the presence of a constant of variation between variables, that is, variables must variate at the same rate, where such rate is call the constant of proportionality.

Notice that the second table fulfils this definion, because x-variable variates 2 units, while y-variable variates ten units. To find the constant of proportionality, we just need to divide

[tex]k=\frac{10}{2}=5[/tex]

Which means that y-variable represents five times x-variable, let's evalute to prove this

[tex]2 \times 5=10\\4 \times 5 = 20\\6 \times = 30[/tex]

Notice that we got all y-values.

Therefore, the right table is the second one, it presents a proportional relationship.

The newspapers cover page is 3/8 text and photographs filled the rest if 2/5 of the text is an article about endangered species, what fraction of the cover page is the article about endangered species

Answers

The fraction of text -3/8 of the cover page
From this fraction of text only 2/5 of the text is about endangered species
We are asked to find out what the fraction of the cover page is that covers endangered species
In this 2/5 of 3/8 is about endangered species
Therefore to obtain the answer we need to multiply the two fractions
2/5 * 3/8
Fraction of the cover page about endangered species is therefore = 2/5 * 3/8
= 0.15

The article about endangered species is  ³/₂₀ of the cover page

Further explanation

Order of Operations in Mathematics follow this following rule :

ParenthesesExponentsMultiplication and DivisionAddition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem !

Given:

Total Area of Cover Page = X

Text Section is 3/8 the newspapers cover page

[tex]\texttt{Text Section Area} = \frac{3}{8} \times \texttt{Total Area of Cover Page}[/tex]

[tex]\texttt{Text Section Area} = \boxed {\frac{3}{8}X}[/tex]

The rest of cover page is Photographs Section

[tex]\texttt{Photographs Section Area} = (1 - \frac{3}{8}) \times \texttt{Total Area of Cover Page}[/tex]

[tex]\texttt{Photographs Section Area} = \boxed {\frac{5}{8}X}[/tex]

2/5 of the text is an article about endangered species.

[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \texttt{Text Section Area}[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{2}{5} \times \frac{3}{8}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{2 \times 3}{5 \times 8}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{6}{40}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \frac{6 \div 2}{40 \div 2}X[/tex]

[tex]\texttt{Endangered Species Article Section Area} = \boxed {\frac{3}{20}X}[/tex]

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Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

An airplane has a maximum capacity of 118 passengers. The flight attendant has loaded 40 passengers. Which inequality represents the solution set that shows the number of passengers, p, that can still load the plane? A) p ≥ 68 B) p ≤ 68 C) p ≤ 78 D) p ≥ 78

Answers

Answer:

Its C

Step-by-step explanation:

It is C because you can only load 78 more passengers

Answer:

c

Step-by-step explanation:

If p = the number of passengers that can still load the plane, then p + 40 ≤ 118.

Therefore,

p + 40 ≤ 118

p + 40 − 40 ≤ 118 − 40

p ≤ 78

whats the value of x??im really confused i thought it was 7 but that doesnt make sense can someone please help me!!!

Answers

10x-20 + 6x+8 = 180

16x -12 = 180
16x = 192
x = 192/16
x = 12
These angles are supplementary
meaning they both add up to 180 because they are on a straight line
To solve:
(10x - 20) + (6x + 8) = 180
combine like terms
(10x + 6x ) + (-20 + 8) = 180
16x - 12 = 180
add 12 to both sides
16x = 192
divide both sides by 16
x = 12

To solve for the angles, you would just take x and plug it into the angle and solve XD

Hope this helps

Given this proportion, what ratio completes the equivilent proportion a/8?
[tex] \frac{a}{b}= \frac{8}{15} [/tex]
Please show your work so that I know how to do this.

Answers

To solve this problem you must follow the steps below:

 You have a/b=8/15, Then:

 1. You must divide in both side of the given proportion by 8:

 a/bx8=8/15x8

 2. When you simplify, you obtain:

 a/8b=1/15

 3. Now, you must multiply both sides by "b", as below:

 axb/8b=1xb/15

 4. Finally, when you simplify, you have:

 a/8=b/15
 


Which equation is quadratic in form 2(x+5)^2+8x+5+6=0, x^6+6x^4+8=0, 7x^6+36x^3+5=0, 4x^9+20x^3+25=0?

Answers

Equation 2(x+5)² + 8x + 5 + 6 = 0 or 2x² + 28x + 61 = 0 is the equation in quadratic form.

What is a quadratic equation?

A quadratic equation is an equation of second order. Quad implies the square power, it is also called equation of degree 2.

The standard form of a quadratic equation is ax² + bx + c = 0.

Where a, b and c are constants.

In the given equation,

2(x+5)² + 8x + 5 + 6 = 0

2 (x² + 25 + 10x) + 8x + 11 = 0

2x² + 50 + 20x + 8x + 11 = 0

2x² + 28x + 61 = 0

This is the quadratic equation.

Rest of the equation are in the higher degree power, only equation 2x² + 28x + 61 = 0 is second power equation.

Hence, 2x² + 28x + 61 = 0 is a quadratic equation.

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Which of the following is equal to the expression below?

(160 * 243)^1/5

A. [tex] 6 \sqrt[5]{5} [/tex]
B.96
C.80
D.5[tex] 5 \sqrt[5]{5}
[/tex]

Answers

(160 * 243)^1/5

To simplify the above expression first step is to factor the numbers. Therefore,

[tex] (160*243)^{\frac{1}{5}} = ((2*2*2*2*2*5)*)(3*3*3*3*3)^{\frac{1}{5}} [/tex]

=[tex] (2^5*5*3^5)^{\frac{1}{5}} [/tex]

= [tex] (2^5)^{\frac{1}{5}} *(5)^{\frac{1}{5}} *(3^5)^{\frac{1}{5}} [/tex]

=[tex] 2 * (5)^{\frac{1}{5}} *3 [/tex]

= [tex] 6*(5)^{\frac{1}{5}} [/tex]

= [tex] 6\sqrt[5]{5} [/tex]

So, correct choice is A.

In 2008 Melvin thought that he was making a sound investment by buying $100,000 worth of Alpha Biotechnology stock. Unfortunately, his investment has depreciated, losing 13% of its current value each year.

Answers

The current value of an invested of $100, 000 that has lost a value of 13% will be:
current value in percent=100-13=87%
The value of $100,000 investment will be:
87/100*100000
=$87,000

helpppppppppppppppppppppppp

Answers

We make the composition of both functions:
 f (x) = x ^ 2-1
 g (x) = 2x-3
 Then:
 f (g (x)) = (2x-3) ^ 2-1
 Rewriting:
 f (g (x)) = 4x ^ 2-12x + 8
 The domain of this function is all real numbers.
 Equivalently
 x: (-inf, inf)
 answer:
 x: (-inf, inf)
 option 1.

The ratio of the measures of the sides of a triangle is 9:15:5. If the perimeter of the triangle is 130 feet, find the measures of the sides.

Answers

5x + 9x +15x = 130
29x = 130
x = 4.4827586207
So the triangle sides =
22.4137931034
40.3448275862
67.2413793103


In the diagram, KL ≅ NR and JL ≅ MR. What additional information is needed to show ΔJKL ≅ ΔMNR by SAS?
A. ∠J ≅ ∠M
B. ∠L ≅ ∠R
C. ∠K ≅ ∠N
D.∠R ≅ ∠K

Answers

B. Angle L=angle R. To prove congruence of triangles by SAS, we need two pairs of sides to be equal, and the included angle equal. We are given KL=NR and JL=MR (the two pairs of sides), then we only need that the angle between KL and JL equals to the angle between NR=MR, so L=R.

Answer:

B. <L=<R  

Step-by-step explanation:

^^^Just too test got 100%

Given the geometric sequence where a_1 = 3 and r = √2 find a_9
A.] 48
B.] 48√2
C.] 64
D.] 64√2

Answers

To find n-therm of a geometric sequence, we are going to use the formula [tex]a_{n} =a _{1} r^{n-1} [/tex]
where:
[tex]a_{n} [/tex] is the term we are looking for
[tex]a _{1} [/tex] is the first term 
[tex]r[/tex] is the ratio 
[tex]n[/tex] is the position of the number in the sequence 

From the question we now that [tex]a _{1} =3[/tex], [tex]r= \sqrt{2} [/tex], and [tex]n=9[/tex]. Lets replace those values into our formula to get:
[tex]a _{9} =3( \sqrt{2} )^{9-1} [/tex]
[tex]a_{9} =3 \sqrt{2} ^{8} [/tex]
[tex]a_{9} =48[/tex]

We can conclude that in our geometric sequence [tex]a_{9} =48[/tex]; therefore, the answer is A.

If you have 240 homies and the Crips rolls up on your block poppin 128 of yo homies, how many homies do ya got left?

Answers

you will only have 112 homies left.

Answer:

You'll have 112 blood homies left

240b-128b=112b

112

Substitute

-3x-8y=4
-2x+7y=15

Answers

-2x=15-7y
x=-7.5+3.5y

-3x-8y=4
-3(7.5+3.5y)-8y=4
-22.5-10.5y-8y=4
-22.5-18.5y=4
-18.5y=4+22.5
-18.5y=26.5
y=-53/35

the fraction might not be in lowest terms.

A scout troop planned to take a bus for an overnight trip to a campground in a nearby state. The bus will cost $360 to rent. The bus company told them that if they could get 3 more troop members to join in the trip each person could pay $6 less to go on the trip. If the troop was able to find the 3 additional people to join the trip, which answer is the most reasonable for the number of members that went on the trip?

Answers

Let x represent the number originally signed up.
.. 360/x -6 = 360/(x +3)
.. 360*(x +3) -6x(x +3) = 360x . . . . . multiply by the product of denominators
.. 360x +1080 -6x^2 -18x = 360x
.. x^2 +3x -180 = 0
.. (x +15)(x -12) = 0
Solutions are x = {-15, 12}

12 members went on the trip.
_____
The problem wording does not make clear whether the original number (12) or the number suggested by the bus company (15) went on the trip. It would be most reasonable for 15 to go, if the troop had people who were willing.

Joaquim is baking giant cookies for the school bake sale. They will be sold for $20 for one large cookie or $20 for three small cookies. Which offer is the better buy? Explain your reasoning.

Answers

Small i believe
Because sure the large is bigger but you get more with the small cookies

Three small cookies for $20 is a better buy than one large cookie for $20 because the cost per small cookie is cheaper ($6.67 per small cookie). You get more cookies for the same price.

To determine which offer is the better buy, let's compare the cost in terms of cookies:

One large cookie: $20 for 1 large cookie.Three small cookies: $20 for 3 small cookies.

Next, let's find the cost per small cookie:

For the large cookie: $20 / 1 large cookie = $20 per large cookie.For the small cookies: $20 / 3 small cookies = $6.67 per small cookie (approximately).

Therefore, since $6.67 per small cookie is less than $20 for 1 large cookie, the offer of three small cookies for $20 is the better buy. This way, you get three cookies for the same price as one large cookie.

SIMPLIFY the radical expression: square root of 75 + square root of 3

Answers

I believe the answer would be 10.39, since the square root of 75 is 8.66 and the square root of 3 is 1.73. Adding them both would give you 10.39. Hope this helped!

The product of x and 8 is less than or equal to 19

Answers

The answer to this is 8x ≤ 19.

jami can now mow 1/6 acre in 8 minutes. if her rate is constant, can jami mow 1 and 1/2 acres in one hour? explain ur reasoning.

Answers

we have that
 1 1/2 acres-------------> 1.5 acres
one hour----------------> 60 minutes

Step 1
I proceed to make a rule of three
if Jami can now mow 1/6 acre -----------------------> in 8 minutes
1.5 acres----------------------------------------------> X
X=1.5*8/(1/6)=72 minutes

72 minutes > 60 minutes

therefore
Jami can not mow 1 1/2 acres in an hour
The time required by jami to mow 1 1/2 acres is 72 minutes

559 tickets were sold 59 more student tickets were sold than adult tickets how many adult tickets were sold

Answers

Let s = number of student tickets and a = number of adult tichets;
We have the equation: s + a = 559 and s = 59 + a;
Then, we solve the equation: 59 + a + a = 559;
59 + 2a = 559;
2a = 500;
a = 500/2;
a = 250;
s = 59 + 250;
s = 309;

The number of adult tickets sold will be 250.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Suppose the number of student tickets is S while adult tickets are A.

As per the given,

59 more student tickets were sold than adult tickets.

S = A + 59

S - A = 59

Total tickets S + A = 559

Add both equations as

S - A + S + A = 559 + 59

2S = 618

S = 309

A = 309 - 59 = 250

Hence "The number of adult tickets sold will be 250".

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The main arena hall has dimensions 200 m by 85 m. On a large diagram on the office wall the scale is 1:40. What are the dimensions of the floor space on the diagram?

Answers

Answer:

500 cm by 212.5 cm

Step-by-step explanation:

Using the scale 1:40 on the 200 m dimension, we have 200/40 = 5 m.  Each meter is 100 cm; this makes this 5(100) = 500 cm.

Using the scale on the 85 m dimension, we have 85/40 = 2.125 m.  Each meter is 100 cm; this makes this 2.125(100) = 212.5 cm.

Answer:

500 cm by 212.5 cm

Step-by-step explanation:

Given :

The main arena hall has dimensions 200 m by 85 m.

On a large diagram on the office wall the scale is 1:40.

To Find: What are the dimensions of the floor space

Solution :

Length of arena hall = 200 m

Scale is 1:40

So, the length of the floor = [tex]\frac{200\times 1}{40}[/tex]

                                           =  [tex]5m[/tex]

Since 1 m = 100 cm

So, 5 m = 100*5 = 500 cm

Width of arena hall  = 85 m

So, width of floor = [tex]\frac{85\times 1}{40}[/tex]

                             =  [tex]2.125m[/tex]

Now 1 m = 100 cm

So, 2.125 m = 212.5 cm

Thus the dimensions of floor is 500 cm by 212.5 cm

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