Answer:
A. both have critical mass
D. both use chain reactions
Apex.
Answer:
A & D
Explanation:
What factor reduces the accuracy of radiocarbon dating? Atmospheric carbon-14 levels change over time. Bones and objects absorb carbon dioxide. Bones and fossilized plants absorb carbon over time.
Explanation:
Carbon-14 is a radioactive isotope of carbon and has a half-life of 5730 years. Due to its presence in all organic materials, this radioisotope is used in the dating of organic specimens.
However, this test is only useful for samples of thousands of years, for samples with ages of millions of years is not useful because the half-life of carbon-14 is lower.
In addition, there is a factor that negatively influences the accuracy of the test, the fact that the concentration of carbon-14 in the terrestrial atmosphere has not remained constant over time. This is due to changes in the flow of cosmic radiation and solar activity, changes in the intensity of the earth's magnetic field and the artificial production of this radiosotope between the 1950s and 1960s with the nuclear tests carried out.
Answer:
the answer is a
Explanation:
A 10 kg box resting on a horizontal, frictionless surface is attached to a 6 kg
weight by a thin, light wire that passes over a pulley . The pulley has the shape of a uniform solid disc of mass 2.5 kg and diameter 0.650 m. After the system is released, calculate
(i) the tension in the wire on both sides of the pulley.
(ii) the angular acceleration of the pulley.
Answer:
T₁ = 34.1 N
T₂ = 38.4 N
α = 10.5 rad/s²
Explanation:
Sum of the forces on the box in the x direction:
∑F = ma
T₁ = m₁ a
Sum of the torques on the pulley:
∑τ = Iα
T₂ r − T₁ r = (½ mr²) α
T₂ r − T₁ r = (½ mr²) (a / r)
T₂ − T₁ = ½ ma
Sum of the forces on the weight in the y direction:
∑F = ma
T₂ − m₂ g = m₂ (-a)
T₂ = m₂ g − m₂ a
Substitute:
(m₂ g − m₂ a) − (m₁ a) = ½ ma
m₂ g = (m₁ + m₂ + ½ m) a
a = m₂ g / (m₁ + m₂ + ½ m)
Given m₁ = 10 kg, m₂ = 6 kg, and m = 2.5 kg:
a = (6) (9.81) / (10 + 6 + ½ (2.5))
a = 3.41 m/s²
Therefore:
T₁ = m₁ a
T₁ = (10) (3.41)
T₁ = 34.1 N
T₂ = m₂ g − m₂ a
T₂ = (6)(9.81) − (6)(3.41)
T₂ = 38.4 N
α = a / r
α = 3.41 / 0.325
α = 10.5 rad/s²
A construction worker is carrying a load of 40 kilograms over his head and is walking at a constant velocity. If he travels a distance of 50 meters, how
much work is being done?
Answer: 2000
Explanation:
Answer:
0 J
Explanation:
Work is force times distance in the direction of the force (the dot product of the force and distance vectors).
W = F · d
Another way to write it is force times distance times the cosine of the angle between the force and distance vectors:
W = Fd cos θ
The force the worker is applying is vertical (there's no horizontal force because he is moving at constant velocity). The direction he moves in is horizontal. The two vectors are perpendicular, so there is no force component in the direction of motion, so there is no work being done.
find the weight density 1.00 qt. of liquid weighing 4.00 lb.
Answer:
p = 1.91722 g/cm3
Explanation:
Density is p=m/V, where density (p) is equal to mass (m) divided by volume (V).
Answer/Explanation:
I've worked out that p = 1.91722 g/cm3
Density is p=m/V, where density (p) is equal to mass (m) divided by volume (V).
a meteor is falling towards the earth. If the mass and radius of the earth are 6×10^24 kg and 6.4×10^6 m respectively. Find the hieght of the meteor where its acceleration due to gravity is 4m/s^2
Answer:
3.6×10⁶ m
Explanation:
Newton's law of universal gravitation states that the force between two masses is:
F = GMm / r²
where G is the universal constant of gravitation (6.67×10⁻¹¹ m³/kg/s²),
M is the mass of one object
m is the mass of the other object,
and r is the distance between the center of masses of the objects.
The force acting on the meteor is:
∑F = ma
GMm / r² = ma
GM / r² = a
Given M = 6×10²⁴ kg and a = 4 m/s²:
(6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / r² = 4 m/s²
r = 10⁷ m
The distance from the meteor to the center of the Earth is 10⁷ m. We want to know what the height of the meteor is (distance to the surface of the Earth). So we need to subtract the Earth's radius.
h = 10⁷ m − 6.4×10⁶ m
h = 3.6×10⁶ m
2 Points
An athlete jumps with a speed of 4 m/s at an angle of 23º. How long does the
athlete stay in the air?
O
A. 0.32 s
B. 0.92 s
C. 0.55 s
D. 0.75 s
SUBMIT
Calculate the vertical component of the athlete's speed:
Vy = Vsin(θ)
Vy is the vertical component of the speed, V is the speed, and θ is the angle the athlete jumps off the ground at.
Given values:
V = 4m/s
θ = 23°
Plug in these values and solve for Vy:
Vy = 4sin(23°) = 1.563m/s
Let us use this kinematics equation for the athlete's vertical motion:
H = Vt + 0.5At²
H is the height, t is time, V is the initial vertical velocity, and A is acceleration.
Given values:
V = 1.563m/s
A = -9.81m/s² (acceleration due to gravity)
Plug in these values:
H = 1.563t - 4.905t²
We want to know the athlete's airtime, or when they reach the ground, ie calculate a time t when H = 0m. So let us substitute H = 0 and solve for t:
1.563t - 4.905t² = 0
t = 0.3187, 0
Reject t = 0s
t = 0.3187s
Choice A
17. What are the two factors that can cause the volume of water in the ocean to change? A. Temperature and pressure B. Gravity and temperature C. Pressure and salinity level D. Salinity level and temperature
Explanation:
The density [tex]D[/tex] of the water is given by a relation between its mass [tex]m[/tex] and its volume [tex]V[/tex]:
[tex]D=\frac{m}{V}[/tex]
Isolating the volume:
[tex]V=\frac{m}{D}[/tex]
This means the volume of the water will depend on its mass and its density.
In this sense, the two factors that affect the volume of seawater are salinity level and temperature.
This is because the salinity (amount of salt in water) changes the its mass and its density, therefore its volume. The higher the salinity, the greater the volume.
In the case of temperature, when it increases, the volume of water also increases and when the temperature decreases, the volume also decreases.
Answer:
D. Salinity level and temperature
Explanation:I took the test
Matthew drops a ball and watches it bounce back up from the ground he draws a force diagram that shows the forces when the ball collides with the grand Which diagram correctly shows the forces involved
Answer: i think that the third option is correct
the force of the ball goes to the floor making it go down and up reflecting a little lower force back to the ball and sending the ball back up
hope this helps
brainliest if possible
Answer:
Option (c)
Explanation:
In this question it is given that, Matthew drops a ball and watches it bounce back up from the ground. The force diagram is given which shows when the ball collides with the ground.
The force acting on the ball are gravitational force and drag force. According to Newton's third law of motion, the force acting on the ball are equal in magnitude but the direction is opposite.
So, diagram (c) shows the correct scenario as per third law of motion. Hence, the correct option is (c).
What is the volume of 282 g of metal with a density of 11.7 g/cm32
Answer:
24.1025641
Explanation:
Density = Mass ÷ Volume
We need to work out volume so the equation is going to be ⇒
Mass ÷ Density
Mass = 282 g
Density = 11.7
282 ÷ 11.7 = 24.1025641
Suppose a rock is dropped off a cliff with an initial speed of 0 m/s. What is
the rock's speed after 3 seconds, in m/s, if it encounters no air resistance?
Answer:
29.4 m/s
Explanation:
v = at + v₀
v = (9.8 m/s²) (3 s) + 0 m/s
v = 29.4 m/s
Answer:29.4 is correct
Explanation:
A rod of length r and mass m is pivoted at its center, and given an angular velocity, ω1. What would be the angular velocity of a second rod, which has the same angular momentum as the first, but whose length is 3r and whose mass is 2m?
Answer:
ω₁ / 18
Explanation:
Angular momentum is the moment of inertia times the angular velocity.
L = Iω
For a rod pivoted at its center, the moment of inertia is:
I = mr² / 12
where m is the mass and r is the length.
For the first rod:
L = (mr² / 12) ω₁
For the second rod:
L = ((2m) (3r)² / 12) ω₂
L = (18mr² / 12) ω₂
They have the same angular momentum, so:
(mr² / 12) ω₁ = (18mr² / 12) ω₂
mr² ω₁ = 18mr² ω₂
ω₁ = 18 ω₂
ω₂ = ω₁ / 18
The angular velocity of a second rod is ω₁ / 18.
What is angular momentum?Angular momentum is the moment of inertia times the angular velocity.
L = Iω
For a rod pivoted at its center, the moment of inertia is I = mr² / 12
where m is the mass and r is the length.
A rod of length r and mass m is pivoted at its center, and given an angular velocity, ω1. the second rod has the same angular momentum as the first, but whose length is 3r and whose mass is 2m.
For the first rod, angular momentum is
L = (mr² / 12) ω₁
For the second rod, angular momentum is
L = ((2m) (3r)² / 12) ω₂
L = (18mr² / 12) ω₂
They have the same angular momentum,
(mr² / 12) ω₁ = (18mr² / 12) ω₂
mr² ω₁ = 18mr² ω₂
ω₁ = 18 ω₂
ω₂ = ω₁ / 18
Thus, the angular velocity of a second rod is ω₁ / 18.
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positional and non positional different between
Explanation:
In positional number system,
1. each symbol represents different value depending on the position they occupy in a number.
2. In positional number system, each system has a value that relates to the number directly next to it. The total value of a positional number is the total of the resultant value of all positions.
3. Example: 12 can be 1 x 10 + 2 x 1, 10 + 2= 12
whereas in Non-Positional number
1. In non-positional number system, each symbol represents the same value regardless of its position
2. In non-positional number system each symbol represents a number with its own place value.
3. Example: Roman number system where I for 1, II for 2 etc.
~~
A hollow glass sphere has a density of 1.30g/cm cubic at 20°C.Glycerine has a density of 1.26g/cm cubic at 20°C.At what temperature would the sphere begin to float in glycerine?
Given coefficient of volume expansion of glycerine is 53 × 10^-5/ °C.
The glass sphere will begin to float in glycerine when the glycerine's density decreases below that of the sphere's density of 1.30 g/cm³ upon heating. Using the coefficient of volume expansion, we can calculate the temperature at which this occurs.
Explanation:To determine at what temperature the hollow glass sphere would begin to float in glycerine, we need to consider the density changes of glycerine with temperature. Since the sphere's density is 1.30 g/cm³ and the density of glycerine is 1.26 g/cm³ at 20°C, we look for the temperature at which the glycerine's density drops below that of the sphere. Using the formula ΔV = βV₀ΔT (where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion of glycerine, and ΔT is the change in temperature), we can calculate the new density of glycerine at different temperatures and find the point where it is equal to the sphere's density.
Since density is mass over volume, as volume increases due to temperature rise, density decreases. As glycerine warms up and expands, its density will decrease: Density_glycerine(T) = Density_glycerine(20°C) / (1 + βΔT). We set this equal to the sphere's density to solve for the temperature increase. When glycerine's density is just less than that of the glass sphere, the sphere will begin to float.
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A natural resource that is in limited supply is known as a _________________.
Answer:
Limited Resources
Answer:I’m sure it lime red resources
Explanation:
Write differences between tornado and typhoon
The difference lies in their size, wind velocity, rate of travel, and duration. A tornado reaches rotating speeds up to 300 miles per hour, travels between 25 and 40 miles per hour, and generally lasts for a few minutes (although it can exist for hours). A typhoon (the term used in the Pacific for a hurricane) has winds that vary from 75 to 200 miles per hour, moves between 10 and 20 miles per hour, has a diameter up to 600 miles, and exists from days up to a week. A tornado generally forms several thousand feet above Earth’s surface, usually during warm, humid weather. A typhoon breeds in low-altitude belts over the ocean, generally from 5 to 15 degrees latitude north or south.
what is the kinetic energy of a 60 kg person jogging at 2 m/s
Ek = 1/2 m v^2
Ek = 1/2 × 60 × 2^2
Ek = 1/2 × 60 × 4
Ek = 120 J
the kinectic energy is 120 J
which of the following is the best definition of ethics?
A) guidelines for good behavior
B) laws that require scientists to research certain things
C) the needs of society
Answer:
B) laws that require scientists to research certain things
The best definition of ethics is A) guidelines for good behavior.
What are Ethics?Ethics are a set of principles that guide our behavior and help us to make decisions about what is right and wrong. Ethics are based on our beliefs about what is good and bad, and they help us to live our lives in a way that is morally acceptable.
Laws are also important for good behavior, but they are not the same as ethics. Laws are rules that are enforced by the government, while ethics are guidelines that we follow voluntarily. Ethics are often more general than laws, and they can be applied to a wider range of situations.
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9. At the amusement park, a blue bumper car crashes into a red bumper car. Which of the
following statements about their momentum is accurate?
A. There is less overall momentum after the collision.
B. The momentum of the red car is destroyed as it is hit.
C. There is greater overall momentum after the collision.
D. The overall momentum stavs the same before and after the collision
Answer:A)
Explanation:
Well It makes the Most sense. The momentum of the Cars were lessened due to the hit.
B is wrong because not only did the red car crash but so did the blue so the real answer should be both.
C makes no sense at all.
D The momentum is lost after collision so it is not the same, so this is false also.
HOPE THIS HELPS! :)
if an atom has 34 protons and 40 neutrons, what is the mass number?
If an atom has 34 protons and 40 neutrons, the mass number is 74.
Explanation:
Mass number is related to the protons and neutrons. It is the product of the above two subatomic particles. Hence the mass number and the atomic number are dependent upon the subatomic particles of an atom. From the given data in the question, mass number of the atom is calculated as, 34 + 40 = 74.
When the ionic compound NaBr dissolves in water, Br– ions are pulled into solution by the attraction between what two particles?
Answer:
The attraction of Br⁻ to H⁺ and Na⁺ to OH⁻
Explanation:
NaBr is an ionic compound and would easily be dissociated by water in solutions.
Water is a polar covalent molecule and with a partial dipole on it. The hydrogen ions have a positive charge and the hydroxyl ions are negatively charged.
In solutions with water, NaBr dissolves. This releases the sodium and bromide ion into the solution. The Bromide ion becomes hydrated and surrounded by the water molecules. The negatively charged end of the water molecule bonds with the Na ion and the positive end bonds with the negative part of the water molecule. This bonding provides the NaBr an ease of movement in its lattice structure.
This procedure leads to the solubility of NaBr in water.
A helicopter is hovering at an altitude of 200m above the surface of the lake. A speaker on the helicopter is sending out sound waves which are reflected from both the surface of the water and bottom of the lake. If the differences in arrival times of the two echoes is measured to be 0.24s, what is the depth of the lake? (The atmospheric temperature is 20°C)
Explanation:
The first echo travels from the helicopter to the surface and back. The second echo travels from the helicopter to the surface to the bottom of the lake and then back.
We know the difference in time is 0.24 s, so the time it takes the sound wave to travel through only the water is 0.24 s. Since the sound wave covers the distance twice (first from the surface to the bottom, then the bottom to the surface), we only want half the time, 0.12 s.
The speed of sound in water at 20°C is 1481 m/s. Therefore:
d = 1481 m/s × 0.12 s
d = 178 m
The depth of the lake is 178 meters (round as needed).
To calculate the depth of the lake, use the speed of sound at 20°C (343 m/s) and multiply it by the time difference (0.24s) between the echoes. This product gives the total distance sound traveled, which is twice the depth of the lake. The depth is found by dividing this distance by two, resulting in 41.16 meters.
Explanation:The student is asking about determining the depth of a lake using sound waves from a hovering helicopter that are reflected from the surface of the water and the bottom of the lake. The time difference between the arrivals of the two echoes is given, and the speed of sound at 20°C needs to be used in the calculations. Since the speed of sound at this temperature is approximately 343 m/s, the total distance traveled by the sound waves is the speed of sound multiplied by the time difference between the echoes. This total distance is twice the depth of the lake, because the sound travels to the lake bottom and back up. Dividing this total distance by two gives the depth of the lake.
The formula to calculate the total distance traveled by the sound is:
Total distance = Speed of sound × Time difference
To find the depth, we divide the total distance by two:
Depth = (Speed of sound × Time difference) / 2
Depth calculation:
Speed of sound at 20°C = 343 m/sTime difference = 0.24 sTotal distance = 343 m/s × 0.24 s = 82.32 m
Depth = 82.32 m / 2 = 41.16 m
The depth of the lake is therefore 41.16 meters.
A particle moves in horizontal circle of radius 15 cm inside an inverted smooth hollow
hemisphere as shown in FIGURE 6.6.
calculate speed of particle
The speed of the particle moving in a horizontal circle within a hemisphere can't be calculated without knowing the mass of the particle or the centripetal force. The force necessary for such motion is given by the equation F = mv^2/r, where F denotes force, m is mass, v is speed and r is radius.
Explanation:The question asks for the speed of the particle moving in a circular path inside a hollow hemisphere. This is a classical mechanics problem in
Physics
, specifically dealing with centripetal force. According to Physics, for an object moving in a circle of radius r at a speed v, the centripetal force necessary to keep the object moving in this path is mv^2/r, where m is the mass of the object. However, the exact speed can't be calculated without knowing either the mass of the particle or the centripetal force involved.
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3- (a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a radius of 40,075 km at its equator, what is the linear velocity at Earth’s surface?
Explanation:
a) The Earth makes 1 rotation in 24 hours. In seconds:
24 hr × (3600 s / hr) = 86400 s
b) 1 rotation is 2π radians. So the angular velocity is:
2π rad / 86400 s = 7.27×10⁻⁵ rad/s
c) The earth's linear velocity is the angular velocity times the radius:
40075 km × 7.27×10⁻⁵ rad/s = 2.91 km/s
(a)The period of rotation of Earth in seconds will be 86400 second.
(b) The angular velocity of Earth will be 7.27 ×10⁻⁵ sec.
(c)The linear velocity at Earth’s surface will be 2.91 km/sec.
What is angular velocity?The rate of change of angular displacement is defined as angular velocity.
It is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The period of rotation of Earth in seconds is found as;
As we know, the complete rotation of the earth took 24 hours.
The total rotational time is converted into the second;
1 hour = 3600 sec
24 hour=24×3600
T= 86400 second
The angular velocity of Earth is;
[tex]\rm \omega= \frac{2\pi}{T} \\\\\ \omega = \frac{2\times 3.14}{86400}\\\\ \omega = 7.27 \times 10^{-5} \ rad/sec[/tex]
The linear velocity at Earth’s surface is found as;
v=r ×ω
v=40075 ×7.27 ×10 ⁻⁵
v=2.91 km/sec
Hence, period of rotation, angular velocity of earth and linear velocity at Earth’s surface 86400 second,7.27 ×10⁻⁵ sec and 2.91 km/sec respectively.
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How are the fossils of the Precambrian eon different from the Phanerozoic eon
Answer:by carbon and oder element
Explanation:
The Precambrian eon is different from the Phanerozoic eon due to the fact that the fossil present from the Precambrian eon was of mostly microorganisms which are single cellular organisms.
Explanation:
The Phanerozoic eon was marked with eon which had the multi cellular organism that is the level of cellularity was enhanced by this eon due to the evolutionary course taken for the organisms. Phanerozoic eon and Precambrian eon had a vast difference of cellular level of organization found in the fossil remains of both times.
Precambrian eon had many primitive algae which existed mostly till the earliest Cambrian era only. Due to single cellularity of the organisms, the fossil of Precambrian eon was not much in abundance whereas the Phanerozoic eon had much abundant fossil remains.
The age of the universe in seconds
Answer:
4.351968e+17 seconds
Explanation:
So I googled age of the universe and it says 13.8 billion years.
you'll have to do some conversions:
in one year, there are 365 days. in one day, there are 24 hours. in one hour, there are 3600 seconds.
[tex]\frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}[/tex]
so you have to add in the current age of the universe to that equation:
[tex]\frac{x seconds}{13.8 bil years} x \frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}[/tex]
arranged so that the proper "units" will read as "x seconds" at the end of the equation.
then you do the math to find x:
13.8 billion x 365 x 24 x 3600 = 4.351968e+17 seconds.
which would be 435,196,800,000,000,000 seconds
Hope this helps :)
Final answer:
The age of the universe is approximately 13.8 billion years, estimated using the Hubble constant. For a Hubble constant of 70 kilometers/second per million parsecs, the age of the universe is about 13.8 billion years. The age of the universe is approximately 13.799 billion years. Converting this into seconds, we get around 4.358 × 10^17 seconds with a margin of error due to uncertainty.
Explanation:
The student has asked for the age of the universe in seconds. To determine this, we use the currently accepted estimate for the age of the universe, which is approximately 13.799 billion years. To convert this age into seconds, we follow these steps:
First, convert the age in years to seconds by multiplying by the number of seconds in a year (31,536,000). Since there are ± 0.038 billion years of uncertainty, calculate the margin of error in seconds by multiplying 0.038 billion years by the number of seconds in a year. Performing the calculations, we find that the age of the universe in seconds is approximately 4.358 × 10^17 seconds, with an uncertainty of about 1.2 × 10^15 seconds. This answer provides an estimation based on the current understanding of astrophysics and cosmology.
If the mass of an object is 6 kg and its momentum is 72 kgm/s, what is its velocity?
A. 18 m/s
B. 12 m/s
C. 9 m/s
D. 72 m/s
Answer:
B. 12 m/s
Explanation:
Momentum is mass times velocity
p = mv
Given p = 72 kgm/s and m = 6 kg:
72 kgm/s = (6 kg) v
v = 12 m/s
Final answer:
The correct answer is B. 12 m/s.
Explanation:
The question provided is asking about finding the velocity of an object when its mass and momentum are known. The formula for momentum (p) is the product of mass (m) and velocity (v), which is expressed as p = m × v. Given that the momentum (p) is 72 kg·m/s and the mass (m) is 6 kg, we can solve for velocity (v) by rearranging the formula: v = p / m.
Plugging in the values, we get v = 72 kg·m/s divided by 6 kg, which simplifies to 12 m/s. Therefore, the correct answer is B. 12 m/s.
A ball rolls horizontally off a table and a height of 1.4 m with a speed of 4 m/s. How long does it take the ball to reach the ground
For vertical motion, use the following kinematics equation:
H(t) = X + Vt + 0.5At²
H(t) is the height of the ball at any point in time t for t ≥ 0s
X is the initial height
V is the initial vertical velocity
A is the constant vertical acceleration
Given values:
X = 1.4m
V = 0m/s (starting from free fall)
A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)
Plug in these values to get H(t):
H(t) = 1.4 + 0t - 4.905t²
H(t) = 1.4 - 4.905t²
We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:
1.4 - 4.905t² = 0
4.905t² = 1.4
t² = 0.2854
t = ±0.5342s
Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))
t = 0.53s
Final answer:
In the Physics topic of projectile motion, it takes approximately 0.5345 seconds for a ball to reach the ground after rolling off a 1.4-meter high table horizontally at a speed of 4 m/s. This calculation is based on the free fall motion equation considering a gravitational acceleration of 9.8 m/s².
Explanation:
The subject of this question is Physics, particularly the topic of projectile motion. To determine how long it takes for a ball to reach the ground when it is rolled off a table, we need to use the equations of motion for objects in free fall. Since the horizontal motion and vertical motion are independent of each other, we only need to consider the vertical motion to answer this question.
Step-by-Step Calculation:
Identify the known variables: the height of the table (h) is 1.4 meters, and the acceleration due to gravity (g) is 9.8 m/s² (assuming earth's gravity).
The initial vertical velocity (vi) is 0 m/s since the ball is rolling off horizontally.
Use the equation for the vertical motion in free fall: h = vi * t + (1/2) * g * t², where t is the time in seconds.
Plugging in the known values, we get 1.4 = 0 * t + (1/2) * 9.8 * t².
Simplifying, we have 1.4 = 4.9 * t², which gives us t² = 1.4 / 4.9.
Calculating t², we find it equals approximately 0.2857.
Take the square root of both sides to find the time (t), which is roughly 0.5345 seconds.
Therefore, the ball takes approximately 0.5345 seconds to reach the ground after rolling off the table.
what are the 12 colors of the spectrum called?
Answer: The correct answer is : Hues
Explanation: The spectrum is made up of three primary light colors that are red, green and blue. For three secondary colors that are yellow, cyan and magenta. For six tertiary colors that are orange, lemon green, turquoise, light blue, violet and teal. The spectrum does not contain all the colors that human eyes and the brain can distinguish, for example magenta, pink and coffee are not in the visible spectrum because the mixing of several wavelengths, mainly dark reds, is required .
The visible spectrum includes the colors red, orange, yellow, green, blue, indigo, and violet, with specific wavelengths assigned to each. These colors are often observed in a rainbow. While indigo is sometimes included, the main colors are typically red, orange, yellow, green, blue, and violet.
The visible spectrum of light consists of colors that are produced by visible light of specific wavelengths. The primary colors that we see in a rainbow and that can be produced by narrow bands of wavelengths include:
Red (620 to 750 nm), Orange (590 to 620 nm), Yellow (570 to 590 nm), Green (495 to 570 nm), Blue (450 to 495 nm), Indigo (approx. 445 to 450 nm), Violet (380 to 445 nm). In total, these are the main colors of the visible light spectrum.
The flywheel of a steam engine runs with a constant angular velocity of 150 rev/min. When steam is shut off, the friction of the bearings and of the air stops the wheel in 2.2 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 50 cm from the axis of rotation? (d)What is the magnitude of the net linear acceleration of the particle in (c)?
Answer:
a) -1.14 rev/min²
b) 9900 rev
c) -9.92×10⁻⁴ m/s²
d) 30.8 m/s²
Explanation:
First, convert hours to minutes:
2.2 h × 60 min/h = 132 min
a) Angular acceleration is change in angular velocity over change in time.
α = (ω − ω₀) / t
α = (0 rev/min − 150 rev/min) / 132 min
α = -1.14 rev/min²
b) θ = θ₀ + ω₀ t + ½ αt²
θ = 0 rev + (150 rev/min) (132 min) + ½ (-1.14 rev/min²) (132 min)²
θ = 9900 rev
c) The tangential component of linear acceleration is:
a_t = αr
First, convert α from rev/min² to rad/s²:
-1.14 rev/min² × (2π rad/rev) × (1 min / 60 s)² = -1.98×10⁻³ rad/s²
Therefore:
a_t = (-1.98×10⁻³ rad/s²) (0.50 m)
a_t = -9.92×10⁻⁴ m/s²
d) The magnitude of the net linear acceleration can be found from the tangential component and the radial component:
a² = (a_t)² + (a_r)²
The radial component is the centripetal acceleration:
a_r = v² / r
a_r = ω² r
First, convert 75 rev/min to rad/s:
75 rev/min × (2π rad/rev) × (1 min / 60 s) = 7.85 rad/s
Find the radial component:
a_r = (7.85 rad/s)² (0.50 m)
a_r = 30.8 m/s²
Now find the net linear acceleration:
a² = (-9.92×10⁻⁴ m/s²² + (30.8 m/s²)²
a = 30.8 m/s²
The angular acceleration of the flywheel is -1.14 rev/min². It makes 9,900 revolutions before stopping. The tangential component of the linear acceleration at 75 rev/min is 3.927 m/s² and the net linear acceleration is 31.08 m/s².
Explanation:The following are the solutions to those physics problems (assuming no slip, only the deceleration is involved) :
Angular acceleration can be calculated by the formula = final angular speed - initial angular speed/time. Here, the final angular speed is 0 (since it stops) and the initial speed is 150 rev/min. The time here should be converted to minutes, which is 2.2 x 60 = 132 min. So, Angular acceleration = (0 - 150) / 132 = -1.14 rev/min².The total number of revolutions the flywheel makes before stopping can be calculated by the equation = initial speed x time + 0.5 x angular acceleration x time² = 150 x 132 + 0.5 x -1.14 x (132)² = 9,900 revolutions.The tangential component of the linear acceleration when the flywheel is turning at 75 rev/min can be calculated by angular speed (in rad/sec) x radius. Angular speed should be converted to rad/sec from rev/min. So, Angular Speed = 75 x 2π / 60 = 7.854 rad/sec. Therefore, Tangential acceleration = angular speed x radius = 7.854 x 0.5 = 3.927 m/s².The net linear acceleration is the vector sum of the tangential acceleration and radial (centripetal) acceleration. Centripetal acceleration can be calculated by (angular velocity)² x radius (for this, angular velocity should be in rad/sec). Hence, Centripetal acceleration = (7.854)² x 0.5 = 30.796 m/s². Therefore, Net linear acceleration = sqrt(tangential acceleration² + centripetal acceleration²) = sqrt((3.927)² + (30.796)²) = 31.08 m/s².Learn more about Physics here:https://brainly.com/question/32123193
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Black holes have three major parts that include:
A) The event horizon, singularity, and the chute located between the two.
B) Stars, planets, and the event horizon
C) The event horizon, singularity, and moons
D) The event horizon, a large planet, and the chute located between the two.
Answer:
A) The event horizon, singularity, and the chute located between the two.
Answer:
Black holes have three major parts that include A) The event horizon, singularity, and the chute located between the two.
Explanation:
A black hole is a celestial object that has an extremely important mass in a very small volume. They are cold remains of very old stars that contain a lot of matter in a compact space. Because of this, they have a great force of gravity.
Black holes are only formed by very massive stars. When they collapse on themselves forming a well in space: a black hole. If they are not so massive, the matter they are made of can stop the collapse and form a dying star that barely shines: a white dwarf or a neutron star.
Black holes have three main parts that include:
The event horizon: In the center of each black hole there is such a concentration of matter that it exerts a gravitational attraction so strong that not even light, the fastest phenomenon in nature, can escape. Then the event or event horizon is the point at a distance from the center of that rotating celestial object where matter or energy, when crossed, cannot escape gravity. The singularity: a singularity is a theoretical point with zero volume and infinite density. It is a place where the density of matter and the curvature of space become infinite. They are inside the horizon of a black hole. The ramp located between the two (the even horizon and singularity).