what are the advantages of adulteration
The advantages of food adulteration includes a better appearance in the food and may increase the selling price, but these advantages only affect the producer of the product. Disadvantages include the increased risk of illness and allergic reactions due to the inedible products that are addedExplanation:
In which of the following situations is heat transferred from the source to popcorn kernels by the method of conduction?
An air popper is used
Popcorn bag is exposed to the sun
Bag of corn is placed in a microwave
Kernels are placed in a pan on a stove
Answer:
Kernels are placed in a pan on a stove
Explanation:
Heat transfer by conduction involves the actual movement between particles of the medium. For conduction to occur, the particles must be in contact with the heating medium or the body at a higher temperatures.
For the popcorn kernels to conduct heat using the conduction heat transfer process, the kernels are placed in contact with the heat source using the frying pan. The stove is the heat source.
When put a knife in contact with fire, it is heat transfer by conduction.
Answer:kernels are placed in a pan on a stove
Explanation:
Balance these equations
N2 + O2 > NO
Answer:
N2 + O2 ---> 2NO
Explanation:
There has to be the same amount of elements on both sides of the equation and it's the rules of chemistry that you cannot add subscripts to the elements because that just changes the whole compound so you must always add coefficients. (The 2 distributes to both elements)
Final answer:
The balanced equation for the reaction between molecular nitrogen (N2) and oxygen (O2) to form nitrogen monoxide (NO) is N2(g) + O2(g) → 2 NO(g). Adding more O2 to a system at equilibrium will shift it to form more NO.
Explanation:
To balance the given equation N2 + O2 → NO, one must ensure that there are equal numbers of each type of atom on both sides of the equation. Starting with nitrogen, we have one N2 molecule, which contains 2 N atoms. On the right side, there is one NO molecule, which contains only 1 N atom, so we can place a coefficient of 2 in front of NO to balance nitrogen. Now we have 2 atoms of nitrogen on both sides. Initially, we have one O2 molecule with 2 O atoms and only one O atom in each NO molecule. After balancing nitrogen, we have two NO molecules, bringing the number of O atoms to two, which balances the oxygen atoms as well. So the balanced equation is N2(g) + O2(g) = 2 NO(g).
If more O2 is added to this system at equilibrium, according to Le Chatelier's Principle, the system would adjust to counteract this change by forming more NO, thus consuming some of the added O2 and potentially shifting the equilibrium position.
Read the second section, "Tsunamis Usually Happen In The Pacific Ocean."
Read the final section, "Warning Systems And Evacuation Plans Have Saved Lives."
How does the second section relate to the final section?
A
Both sections provide specific examples of the effects of tsunamis.
B
Both sections compare and contrast different causes of tsunamis.
C
The second section describes problems with studying tsunamis. The final section describes how scientists discovered a solution to the problems.
D
The second section describes scientists' predictions about tsunamis. The final section provides information about whether they were correct.
The second section explains why tsunamis are a significant risk in the Pacific Ocean, providing context for the development of warning systems and evacuation plans discussed in the final section.
The second section, which deals with the fact that tsunamis usually happen in the Pacific Ocean, is related to the final section about warning systems and evacuation plans in that it sets the context for the need for such systems. Because tsunamis are most prevalent in the Pacific, the presence of warning systems and evacuation plans in that area is crucial for saving lives. The mitigation efforts mentioned in the second section, such as the Pacific Tsunami Warning Center established after a tsunami in Hawaii, exemplify the types of responses that have been created to address the clear and present danger that tsunamis pose to coastal communities.
1.1 Outline a method for separating the chalk from potassium chloride,
Answer:
Explanation:
To separate the a mixture of chalk and potassium chloride, we must not that chalk is calcium carbonate compound, CaCO₃.
Calcium carbonate has low solubility in water. KCl is readily soluble in water and it is also an ionic compound.
To separate a mixture of compounds with various solubility, we can carryout dissolution, filtration and evaporation.
We first pour pure water into the mixture. Water will dissolve the potassium chloride readily.
Then using a filter paper we filter out the suspended chalk particles. Leave the filtrate to then dry and collect it.
The solution filtered should be evaporated to dryness. This will leave the KCl behind from the solution.
Determine the energy in joules or a photon with frequency of 5.78 x 10^17 Hz
Answer:
E= 3.829 x 10-16 J
Explanation:
Data Given
Frequency= 5.78 x 10^17 Hz
Energy in joules = ?
Solution:
Formula used to calculate Energy
E= hv…………….. (1)
Where E is Energy
h is Planks Constant = 6.626 x 10–34 J s
v is frequency
The given frequency is in Hz (Hertz)
Hz is equal to s-1 (per second)
1 hertz = 1 /second
Putting the values in Equation 1
E= (6.626 x 10–34 J s) (5.78 x 1017 s-1)
E= 3.829 x 10-16 J
Mole conversions.
Find the number of moles of argon in 607g of argon?
Answer:
24249.65 mol
Explanation:
n=MM × m
n= 39.95 ×607
n=24249.65
an 1.04-L sample of gas at 759 mm Hg pressure
expanded until its volume is 2.24 L. What
the pressure in the expanded gas sample
at constant temperature)?
PV = nRT
where P is the pressure,
V is the volume,
n is the moles of gas,
R is the gas constant,
and T is the temperature.
We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:
P1V1 = P2V2
where P1 is the initial pressure,
V1 is the initial volume,
P2 is the final pressure,
and V2 is the final volume.
Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.
P1V1 = P2V2
(759 mm Hg)(1.04 L) = P2(2.24 L)
P2 = 352 mm Hg (rounded to three significant figures)
To find the pressure in the expanded gas sample, you can use Boyle's Law: P1V1 = P2V2. Plugging in the values, the pressure in the expanded gas sample is 353.03 mm Hg.
Explanation:To find the pressure in the expanded gas sample, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. This means that as the volume increases, the pressure decreases, and vice versa.
Using the formula P1V1 = P2V2 (where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume), we can solve for P2:
P2 = P1V1/V2
Plugging in the given values, P1 = 759 mm Hg, V1 = 1.04 L, and V2 = 2.24 L:
P2 = (759 mm Hg)(1.04 L)/(2.24 L) = 353.03 mm Hg
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Please Help!!!1
Which member of each pair has the greater negative electron affinity?
a) Se or Br
b) Si or Al
c) Na or Cl
9. Which member of each pair has the larger radius?
a) Ca or Mg
b) Al or P
c) F-1 or F
10. Which member of each pair has the higher ionization energy?
a) He or Ne
b) Na or Mg
c) Ca or Ca +2
Answer:
the red one in each pair
Explanation:
see the picture2
Answer:
Here's what I find.
Explanation:
8. Electron affinity
The atom that is closer to having a complete valence shell (is further to the right in the Periodic Table) will have the greater electron density. The correct answers are:
(a) Br
(b) Si
(c) Cl
9. Atomic radius
(a) Ca. Ca is one period closer to the bottom of the Periodic Table. It has one more electron shell than Mg, so its valence electrons are further from the nucleus.
(b) Al. P is two atoms to the right of Al, so it has two more protons in the nucleus. Its valence electrons are held more tightly, so it is the smaller atom.
(c) F⁻. An anion is always larger than its neutral atom the added electron increases electron repulsions. The electrons move further out so they can reduce these repulsions.
10. Ionization energy
(a) He. He is a smaller atom, so its electrons are closer to the nucleus and more difficult to remove.
(b) Mg. Mg is to the right of Na and has a filled 3s subshell. Both factors make it more difficult to remove an electron.
(c) Ca²⁺. Once you have removed the two valence electrons from an atom of Ca, you have exposed its argon-like inner core. It takes more energy to remove an electron from a completed shell.
2. Why do atoms combine to form chemical bonds?
Atoms combine because they are all working toward getting 8 valence electrons, except for noble gases. It is in their nature.
If you need a better explanation just ask in the comments.
Happy to help! Please mark as BRAINLIEST! Thanks
3.50 g of an unknown base is dissolved in 289 mL of water and has a concentration of 0.219 M. What is the the identification of the unknown base.
Answer:
The unknown base should be KOH whose molar mass is 56 g per mol (Answer)
Explanation:
Molarity = moles /(Volume in liters)
So,
Moles = Molarity [tex]\times[/tex] Volume
[tex]\\$=0.219 M \times 289 m L$\\\\$=0.219 \frac{m o l}{L} \times 0.289 L$\\\\$=0.063291 \mathrm{mol}$[/tex]
Molar mass = mass/moles
[tex]\\\\$=\frac{3.50 \mathrm{g}}{0.063291 \mathrm{mol}}=55.3 \mathrm{g}$ per mole[/tex]
The unknown base should be KOH whose molar mass is 56 g per mol (Answer)
Scientists must be curious, honest, creative open minded skeptical , ethical and aware of bias. list 3 ways thinking like a scientist can help u in everyday life when doing things like shopping for a new bike,baking a cake, or reading a magazine??
Answer:
Explanation:
Thinking like a scientist can help me make daily rational decisions between my wants. In that the way I see want would be ultimately to satisfy the most pressing of needs. This is where the open minded nature of scientist will come in. A scientist would rather chose to buy a new bike than going on expensive dates in order to cut and save travel time.
Thinking like a scientist can help me save cost on actually going out there to buy a cake or making one myself. This is the creative aspect of being a scientist. Why have the ingredient and the skill and I will still choose to go out there buy a cake?
A scientist reads a magazine with all mind seeking to establish the bias that might be laden in an edition. This will help him to rationale between different information presented on the pages of the paper. He/she would question the information source and not believe the story completely.
Suppose your bedroom is 21 ft long, 17 ft wide, and the distance from floor to ceiling is 7 ft, 6 in. You need to know the volume of the room in metric units for some scientific calculations. What is the room’s volume in cubic meters.
1. ______ m^3 (cubic meters)
2.______ L (Liters)
Answer:
1. 75.82 m^3 (cubic meters)
2. 75820 L (Liters)
Explanation:
Given data
L = 21 FT
W = 17 ft
h = 7 ft 6 in
Calculation
Formula to calculate volume is:
V= L×W×h
put the values in formula
V = 21 ft × 17 ft × 7 ft 6 in
V = 2677.5 ft
Now we will convert Cubic ft to cubic meters, as we know that 1 cubic meter is equal to 35.3147 cubic feet
V (m^3) = 2677.5 ÷ 35.3147
V (m^3) = 75.82 m^3
Now we will calculate liters
as we know that 1 cubic meter is equal to 1000 liters
so multiply the ans. with 1000
L = 75.82 × 1000
L = 75820 l
highlighted answer is wrong just need someone to explain it if you can!❤️
Answer:
2.7 x 10^-1
Explanation:
The places you move to the left are added to the 10 in negative exponential
In a paper chromatography chamber, which example could be the stationary phase?
air
plastic plate
paper
Answer:
Paper
Explanation:
Paper chromatography is a method of separating mixtures of coloured substances into their components.
It uses a stationary phase and a mobile phase.
A tiny drop of a solution of the mixture is applied to the paper, which is suspended in a solvent.
The solvent flows through the paper and carries the components of the mixture with it.
Different components travel at different rates, so the mixture separates into different coloured spots as the solvent front moves up the paper.
The solvent moves up the paper, so it is the mobile phase.
The paper does not move, so it is the stationary phase.
Calculate the empirical formula for each compound.
2.677 g Ba, 3.115 g Br
To determine the empirical formula for the compound with given masses of Ba and Br, convert the masses to moles and find the ratio of the moles. In this case, the empirical formula is BaBr2.
Explanation:To calculate the empirical formula for each compound, we need to determine the ratio of the elements in the compound using their masses.
Given the masses of Ba and Br, we can convert them to moles using their respective molar masses.
The molar mass of Ba is 137.33 g/mol, and the molar mass of Br is 79.90 g/mol.
Using these values, we find that there are 0.0195 moles of Ba and 0.0390 moles of Br in the given sample.
To find the empirical formula, we need to divide the moles of each element by the smallest number of moles obtained. In this case, the smallest number of moles is 0.0195.
Dividing the moles of Ba and Br by 0.0195 gives us approximately 1 mole of Ba and 2 moles of Br.
Therefore, the empirical formula for the compound is BaBr2.
Match the formula for the following compound: acetic acid HC 2H 3O 2 C 2H 3O 2 H 2C 2H 3O 2 HA
Final answer:
The formula for acetic acid is C2H4O2, also written as CH3COOH. Its empirical formula, derived by simplifying the molecular formula to the lowest whole number ratio, is CH2O.
Explanation:
The formula for acetic acid is C2H4O2, which can also be written as CH3COOH. In calculating its empirical formula, you would note the number of Carbon (C), Oxygen (O), and Hydrogen (H) atoms. You mentioned a given molecular formula of acetic acid as C2H4O2. This indicates a ratio of 2 Carbon atoms to 4 Hydrogen atoms to 2 Oxygen atoms. Dividing by the lowest common denominator, which is 2, yields a simplest whole-number ratio of atoms of 1:2:1, thus the empirical formula for acetic acid is CH2O.
How many atoms are there in 1.60 moles of selenium
The number of atoms in 1.60 moles of selenium is approximately 9.64 x 10^23 atoms.
In order to determine the number of atoms in 1.60 moles of selenium, we need to use Avogadro's number. Avogadro's number is 6.022 x 10^23 atoms per mole.
So, for 1.60 moles of selenium, we can calculate the number of atoms as:
Number of atoms = 1.60 moles x 6.022 x 10^23 atoms/mole
Number of atoms = 9.6352 x 10^23 atoms
Therefore, there are approximately 9.64 x 10^23 atoms in 1.60 moles of selenium.
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1. If a person's mass is 56 kg, what is this weight in pounds?
56kg
Answer:
123lb
Explanation:
lb= 2.2046 kg
56×2.2046= 123lb
A person with a mass of 56 kg weighs approximately 123.46 pounds.
The conversion uses the factor that 1 kilogram is approximately 2.20462 pounds. Mass is the amount of matter, while weight is the gravitational force on that matter.
To convert a person's mass from kilograms to pounds, you can use the conversion factor that 1 kilogram is approximately equivalent to 2.20462 pounds.
Conversion Calculation:
Given a mass of 56 kg, you can calculate the weight in pounds as follows:
Weight in pounds = Mass in kilograms × Conversion factor
Weight in pounds = 56 kg × 2.20462 lbs/kg
Weight in pounds ≈ 123.46 lbs
So, a person with a mass of 56 kg weighs approximately 123.46 pounds.
Understanding Mass and Weight:
Note that mass is a measure of the amount of matter in an object, while weight is the force exerted by gravity on that mass. In the US customary units, weight can be expressed in pounds, where 1 lb is equivalent to a mass of 0.4536 kg.
List three criteria used to identify a cold front.
Answer:
Explanation:
A cold front is a transition zone from warm air masses to cold air masses. We use weather elements to identify cold fronts.
Temperature: Since air moves from warm masses to cold masses, the air in a cold front is at different temperatures. The air behind a cold front is warm while the one ahead is cold. This implies that within a cold front is at different temperatures. Precipitation: Prior to the passing of cold front, precipitation is usually rife with low showers. A coldfront in itself is usually accompanied by heavy rainfall full of thunderstorms and lightening. After a coldfront, the showers steadies and decreases. Pressure changes: before a coldfront, the atmospheric pressure decreases steadily. When the front arrives, the pressure further lowers with a sharp increase thereafter. After the front, the pressure can continue to increase.Where are the electrons found in Bohr's atomic model?
Answer:
The answer to your question is letter D.
Explanation:
Bohr tells us that the electrons which have a negative charge clicle the orbits in specific nucleus, so the right answer is letter D.
Letter C is not possible because the electrons are in orbits circling the nucleus where the protons are.
Letter B is not correct because electrons are distributed in orbits but the amount of electrons in one orbit is different to the other one.
The electrons found around the nucleus in specific orbit in Bohr's atomic model.
So, option D is correct one.
What is Bohr's atomic model?This model explained about position of electron and their energy levels.
According to Bohr's atomic model the electron revolve around the nucleus in particular orbit or shell.
Rutherford's model described about nucleus which is surrounded by the electrons which is negatively charged.
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An element has two naturally occurring isotopes, X-85 with a mass of 84.9118 amu and a natural abundance of 72.17%, and X-87 with a mass of 86.9092 amu and a natural abundance of 27.83%. Calculate the atomic mass of this element.
Final answer:
To calculate the average atomic mass of an element with three naturally occurring isotopes, multiply the mass of each isotope by its natural abundance in decimal form, and then sum the results.
Explanation:
To calculate the average atomic mass of an element with three naturally occurring isotopes, we need to multiply the mass of each isotope by its natural abundance in decimal form, and then sum the results. Let's use an example to illustrate this calculation. Suppose an element has three isotopes: X-1 with a mass of 1.000 amu and a natural abundance of 40%, X-2 with a mass of 2.000 amu and a natural abundance of 50%, and X-3 with a mass of 3.000 amu and a natural abundance of 10%. We can calculate the average atomic mass as follows:
(1.000 amu * 0.40) + (2.000 amu * 0.50) + (3.000 amu * 0.10) = 0.400 amu + 1.000 amu + 0.300 amu = 1.700 amu
Round the number 0.005758 to 3 sig figs
Answer:
0.00576
Explanation:
To round 0.005758 to three significant figures, we get 0.00576. We only consider the first non-zero digit and the two digits to its right for this purpose.
Explanation:To round the number 0.005758 to three significant figures, we first locate the first non-zero digit from the left, which is 5. We then count two more digits to its right, thus including 7 and 5. We denote these as the significant figures. The next digit after these is 8, since it is more than 5, it rounds the prior digit (5) up by one. Therefore, the number 0.005758 rounded to three significant figures is 0.00576.
Leading zeros are not considered as significant figures. The significant figures in a number are digits that carry meaning contributing to its precision. This includes all non-zero numbers, zeros between significant figures, and any trailing zeros if the number is a decimal.
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An atom has 27 protons and 22 neutrons. What is the chemical symbol for the atom?
Consult the periodic table.
O Co
О Cs
O Cr
O Ca
The attraction between particles give solids a definite
Answer:Shape and volume
Explanation:
Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 3.11 kg
Answer:
The volume is 3.96 dL
Explanation:
Step 1: Convert ml to dl
1Liter = 1000ml = 10³ ml
1Liter = 10 dl
⇒ 1 Liter has 1000ml or 10 dl
⇒ The ratio can be written as : 10dl/ 1000ml = 1 dl / 100ml
Step 2: Convert cm³ =
⇒ 1cm³ is equal to 1 ml.
Step 3: Calculate volume
⇒ We use the formule of density here, which is : Density (p) = mass (g) / volume( cm³)
⇒ 7.86 g/ cm³ = 3110 grams / Volume ( cm³)
⇒Volume = 3110 grams / 7.86g/cm³ = 395.67 cm³
395.67 cm³ = 395.67 ml = 0.39567 L = 3.96 dL
3.96 dL is reported to three significant digits due to the precision reported for the density.
What volume of a product is required to make half liter of 0.25% of the product solution?
Answer:
0.00125 liters of product
Explanation:
So the question it tell you that 0.25 % from 0.5 liters is pure product.
So we calculate the volume of pure product:
volume = (0.25 / 100) × 0.5 = 0.00125 liters
Now to produce the solution over 0.00125 liters of pure product you add (most likely) water until you reach a volume of 0.5 liters.
Convert 234 kJ to kcal. Only include the numerical value in your answer. Respond with the correct number of significant figures in scientific notation.
Answer:
234 KJ ≡ 55.887 Kcal
Explanation:
∴ J ≡ Kg/m².s² ≡ N.m = 0.2389 cal
∴ cal = 4.187 J
⇒ 234 KJ * ( 1000 J / KJ ) * ( cal / 4.187 J ) * ( Kcal / 1000 cal ) = 55.887 Kcal
Answer : The correct number of significant figures in scientific notation is [tex]9.791\times 10^2\text{ kilocalorie}[/tex]
Explanation :
The conversion used from kilojoules (kJ) to kilocalories (kcal) is:
1 Joule = 4.184 Calorie
or,
1 kilojoule = 4.184 kilocalorie
As we are given that the energy 234 kJ. Now we have to convert it into kcal.
As, [tex]1\text{ kilojoule}=4.184\text{ kilocalorie}[/tex]
So, [tex]234\text{ kilojoule}=\frac{234\text{ kilojoule}}{1\text{ kilojoule}}\times 4.184\text{ kilocalorie}=9.791\times 10^2\text{ kilocalorie}[/tex]
Therefore, the correct number of significant figures in scientific notation is [tex]9.791\times 10^2\text{ kilocalorie}[/tex]
The density of liquid Z is 0.9237 g/mL. A student masses a cup
with a sample of liquid Z in it and finds the mass to be 50.7 g.
The mass of the cup alone is 15.92 g. What is the volume of
liquid Z in the cup? (Volume = mass - density)
If the mass of the cup alone is 15.92 g, the volume of liquid Z in the cup will be 39.11 mL.
How to calculate the volume of liquid Z?Volume is a measure of the amount of space that matter occupies. Matter is defined as a physical substance that occupies space and has a mass.
Volume of liquid Z = (Total mass - Cup mass) / Density of liquid Z
= (50.7 g - 15.92 g) / 0.9237 g/mL
= 34.78 g / 0.9237 g/mL
= 39.11 mL.
Therefore, if the mass of the cup alone is 15.92 g, the volume of liquid Z in the cup will be 39.11 mL.
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Magnesium has 3 naturally occurring isotopes: 24 Mg (23.985 amu) with 78.99% abundance,
25 Mg (24.986 amu) with 10.00% abundance, and a third with 11.01% abundance.
Look up the atomic weight of magnesium, and then calculate the mass of the third isotope.
Answer:
The mass of third isotope is 25.98 amu.
Explanation:
Mass of Mg²⁴ = 23.985 amu
Mass of Mg²⁵ = 24.986 amu
Abundance of Mg²⁴ = 78.99 %
Abundance of Mg²⁵ = 10%
Abundance of third isotope = 11.01%
Atomic weight of magnesium = 24.305
Solution:
Atomic mass = ( % age of first isotope × its atomic mass) + (% age abundance of second isotope × its atomic mass) + ( % age of third isotope × its atomic mass ) / 100
Now we will put the values in formula.
24.305 = (78.99 × 23.985 ) + (10 ×24.986 ) + ( 11.01 × X) / 100
24.305 = 1894.56 + 249.9 +( 11.01 × X ) / 100
24.305 × 100 = 2144.46 + ( 11.01 × X)
2430.5 - 2144.46 = (11.01 × X)
286.04 / 11.01 = X
25.98 = X
The mass of third isotope is 25.98 amu.
The mass of the third isotope of magnesium, 26Mg, can be calculated using the atomic weight of magnesium and the known abundances and masses of the other two isotopes, 24Mg and 25Mg. The atomic weight is a weighted average of all isotopes, allowing for the determination of the unknown mass.
Explanation:The mass of the third isotope of magnesium can be calculated using the atomic weight of magnesium and the known abundances and masses of the other two isotopes. The atomic weight of magnesium is a weighted average of the masses of all naturally occurring isotopes, calculated based on their relative abundances. Since we have the relative abundances and masses for two of the isotopes (24Mg and 25Mg), we can use the given atomic weight of magnesium to find the mass of the third isotope, 26Mg.
Let's say the atomic weight of magnesium is X amu (this value can be found on the periodic table). To find the mass of 26Mg, we can set up the equation based on the equation for average atomic mass:
(0.7899)(23.985 amu) + (0.1000)(24.986 amu) + (0.1101)(M3 amu) = X amu
Where M3 is the mass of the third isotope that we are trying to find. We can solve for M3 to get the mass of the 26Mg isotope.