Which of the following do the objects in the four categories of small objects in the solar system all have in common?
A.
They all orbit the sun.

B.
They can all be found in the Oort cloud.

C.
They all contain a nucleus.

D. They all are made of gas and ice.

No, the mechanical energy does not change if it is ideal.

We define mechanical energy as the sum of kinetic energy and potential energy

ME = PE + KE

When the pendulum swings, potential energy is converted to kinetic energy and vise versa. But the sum of both remains constant, which is the mechanical energy.

Weight of the object on surface of any planet is given as the gravitational pull on the object due to planet

This gravitational pull is defined as formula below

[tex]F = mg[/tex]

m = mass of object

g = acceleration due to gravity of the planet

now here it is given that weight on the planet is 370 N which is defined as the force due to planet

Also the mass is given as 100 kg

now using the formula above

[tex]370 = 100 * g[/tex]

[tex]g = \frac{370}{100}[/tex]

[tex]g = 3.7 m/s^2[/tex]

so the gravitational strength of the mars will be 3.7 m/s^2

Answer:

The gravitational strength of the mars will be 3.7 m/s^2

Explanation:

Potential energy is given as

[tex]U = 4y^3[/tex]

now as we know that force is related by potential energy by the formula

[tex]F = - \frac{dU}{dy}[/tex]

So it is gradient of energy with position in Y

[tex]F = - \fracd(4y^3}{dy}[/tex]

[tex]F = -12y^2 \hat j[/tex]

Now at y = 0

[tex]F = 0 N[/tex]

at y = 1

[tex]F = - 12*1^2 [/tex]

[tex]F = - 12 N[/tex]

at y = 2

[tex]F = - 12*2^2[/tex]

[tex]F = - 48 N[/tex]

so above is the forces at given positions

The force on the particle at

[tex]y=0\;\text{is} \;0\;\text{N}\\\\y=1\;\text{is} \;12\;\text{N}\\\\y=2\;\text{is} \;48\;\text{N}\\[/tex]

Explanation:

Given information:

The potential energy: [tex]U=4y^3[/tex]

Now, as we know that force:

[tex]F=-\frac{dU}{dy}[/tex]

So, the gradient of energy with position y

[tex]F=-4y^3dy\\F=-12y^2j[/tex]

At, y=0

[tex]F=0\;N[/tex].

At, y=1

[tex]F=-12+1\\F=-12 \;N[/tex]

At, y=2

[tex]F=-12\times 4\\F=-48\;\text{N}[/tex]

Hence , The force on the particle at

[tex]y=0\;\text{is} \;0\;\text{N}\\\\y=1\;\text{is} \;12\;\text{N}\\\\y=2\;\text{is} \;48\;\text{N}\\[/tex]

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a) The change in momentum of the ball is given by:

[tex]\Delta p = m \Delta v[/tex]

where m=140 g=0.14 kg is the mass of the ball, and [tex]\Delta v =30 m/s[/tex] is the change in velocity. Substituting, we find

[tex]\Delta p=(0.14 kg)(30 m/s)=4.2 kg m/s[/tex]

The ball stops in t=1.5 ms=0.0015 s; the magnitude of the force that stops the baseball is given by the ratio between the change in momentum and the time taken:

[tex]F=\frac{\Delta p}{t}=\frac{4.2 kg m/s}{0.0015 s}=2800 N=2.8 kN[/tex]

b) The force we found at point a) is the force that the head exerts on the ball to stop it. However, Newton's third law states that when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. If we apply this law to this case, we understand that the force exerted by the baseball on the head is equal to the force exerted by the head on the ball: therefore, the answer is still 2.8 kN.

c) The forehead is not in danger of a fracture, since it can withstand a maximum force of 6.0 kN, while the ball exerts a force of 2.8 kN. Instead, the cheek is in danger of fracture, because it can withstand only a maximum force of 1.3 kN.

There are 4 ways in which electrons are emitted from the conductor.

i. Thermionic emission

ii. Electric field electron emission

iii. Photoelectric emission

iv. Secondary emission

In thermionic emission large amount of external energy in the form of heat is supplied to release free electrons from the metal.

In electric field electron emission, electrons are emitted from the metal surface when the metals are placed in a very strong electric field.

During photoelectric emission, light is absorbed by the metals and this provides energy to the valence electrons which break their bond with the parent atom and which are then released from the atom.

Valence electrons do have some kinetic energy, but they don't have enough energy to escape from the atom. During secondary emission, a high-speed electron is bombarded with an atom, which provides the energy for the valence electrons to break their bonds with their parent atom which are then released from the atom.

Answer:

Conditions that result in the emission of electrons from a conductor:

Heating the conductor to a suitable temperature

Exposing the conductor to a strong light

Subjecting the conductor to a very high applied voltage

Subjecting the conductor to high-speed electrons from another source

Explanation:

For both NPN and PNP this is true:

The base is between the collector and the emitter.

In the transistors, the base is between the collector and emitter.

Option C is the correct answer.

The Transistor has two types, they are NPN transistor and PNP transistor.

     Both NPN and PNP transistor are bipolar transistor. In the NPN transistor, base will be the P-type semiconductor, emitter and collector will be the N- type semiconductor where as in the PNP transistor, base will be the N- type semiconductor, emitter and collector will be the P -type semiconductor. The circuit diagram of both the transistor will be attached as a image. The current flow in both the transistor will be collector to emitter and emitter to collector.

So that, the base is between the collector and emitter is the true statement in the given options.

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Cellular respiration is of two types namely aerobic and anaerobic respiration.

During aerobic respiration,the food(glucose) is broken down in the mitochondria to produce ATP,water and CO2.This is carried out in 3 steps glycolysis followed by Tricarboxylic acid cycle and electron transport chain.

During anaerobic respiration, glucose is broken down in the absence of oxygen to produce ethanol,CO2 and water. Anaerobic respiration occurs in the cytoplasm.

Answer:

Option C is the correct answer.

Explanation:

  We have velocity of a body = Change in position/ Time.

  Considering first portion of graph,

  Change in position = 30 - 0 = 30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = 30/2700 = 0.011 m/s

  Considering second portion of graph,

  Change in position = 30 - 30 = 0 m

  Time = 0.5 hours = 30 minutes = 1800 seconds

   Velocity = 0/1800 = 0 m/s

 Considering third portion of graph,

  Change in position = 0 - 30 = -30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = -30/2700 = -0.011 m/s

So firstly they walked in one direction(positive direction), then they were still(velocity is zero), then they walked in the opposite direction( velocity is negative).

Option C is the correct answer.

Answer:

I had this same question the answer is C 100% sure

Explanation:

when two vectors are inclined at some angle to each other then the magnitude of resultant of two vectors is given as

[tex]R = \sqrt{A^2 + B^2 + 2AB cos\theta}[/tex]

here A and B are the magnitude of two vectors and theta is the angle between them

now here we know that two vectors are of magnitude 0.25 m/s^2 each and they are inclined at angle of 45 degree

now we will plug in all data above

A = B = 0.25

[tex]\theta = 45[/tex]

[tex]a_{net} = \sqrt{0.25^2 + 0.25^2 + 2*(0.25)(0.25)cos45}[/tex]

[tex]a_{net} = 0.46 m/s^2[/tex]

So the magnitude of resultant acceleration will be 0.46 m/s^2

The magnitude of the resultant is 0.354 m/s^2.

The magnitude of the resultant can be found using the Pythagorean theorem. Since the balloon experiences an upward acceleration of 0.25 m/s^2 and a rightward acceleration of 0.25 m/s^2 at 45 degrees, we can find the magnitude of the resultant using:

R = sqrt((0.25)^2 + (0.25)^2) = 0.354 m/s^2.

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Final answer:

Conservation of energy dictates that the speed of the ball at the top of the circular path decreases as its kinetic energy is converted to potential energy. The final speed can be calculated using the formula v = √(2gh).

Explanation:

Conservation of energy states that the total energy of a system remains constant. In the case of the ball on a string winding around a post, as the ball reaches the top, its kinetic energy will be converted to potential energy, resulting in a decreased speed.

To find the speed of the ball at the top of the circular path, we can set the initial kinetic energy equal to the final potential energy. This can be expressed as:

[tex]1/2 mv^2 = mgh[/tex], where 'v' is the final speed, 'm' is the mass of the ball, 'h' is the height above the peg, and 'g' is the acceleration due to gravity.

Therefore, the speed of the ball at the top of the circular path is v = √(2gh), where 'g' is the acceleration due to gravity and 'h' is the height of the circular path above the peg.

The weight will be 1/6 time less on the moon than earth.

The varies the size of the object the effects the of gravitational pull will vary. As the moon is smaller than the size of the earth, then it has less gravitational pull. The value of gravity is [tex]9.8 ms^{-2}[/tex]on the earth but in the moon, it will reduce 1/6 times and will be [tex]1.62ms^{-2}[/tex]. The weight change by change the planet but mass remain same. In the given question the weight is 150g. So,

[tex]W = m * g[/tex]

at earth[tex]g = 9.8ms^{-2}[/tex]

by rearranging

[tex]m= W/g[/tex]

[tex]m = 150/9.8[/tex]

[tex]m = 15.3 g[/tex]

On moon [tex]g = 1.62 ms{^-2}[/tex]

[tex]m = 150/1.62[/tex]

[tex]m = 92.6 g[/tex]

The change in mass was because of gravitational pull

When Sam applies the brakes on his bike, the friction between the brake pads and the tires converts the kinetic energy of the moving bike into heat energy, causing the tires to become warmer.

When Sam applies the brakes on his bike, it creates friction between the brake pads and the tires. This friction converts the kinetic energy of the moving bike into heat energy, causing the tires to become warmer. This is similar to how car brakes work - they use friction to reduce speed and convert motion energy into heat energy, which is why the brakes can become hot after stopping.

Motion is detected when an object changes its position with respect to a reference point. Coordinate system is basically used to represent motion. A coordinate system uses numbers or coordinates which represent position of the reference points on a two-dimensional or three-dimensional space. The trajectory of a point or line can be studied on a coordinate system which describes various aspects of motion like velocity, acceleration, distance, displacement etc. Coordinate system is important because it helps to choose a starting point and the direction (which will be positive).

In the question there are three values of densities.

We are asked to arrange these values in descending order.

In order to solve this problem first we have to convert each values into same unit.Let the unit chosen to be gram per cubic centimeter.

The first value is 1000 kg per cubic metre.

we know that 1 kg=1000 kg and and 1 m=100 cm

Hence the value in CGS system will be-

                                                  [tex]1 kg/m^3 =\frac{10^3 gram}{[10^2cm]^3}[/tex]

                                                                  [tex]=10^-3\ g/cm^3[/tex]

 The second value is 1 gram per cubic centimetre.

Third value is 1 kg per cubic millimeter.

we know that

                      [tex]1 mm =10^-1 cm[/tex]

Hence 1 kg per cubic millimeter i.e

                                                     [tex]1 kg/mm^3[/tex]

                                                       [tex]=\frac{10^3 gram}{[10^-1cm]^3}[/tex]

                                                       [tex]=10^6 g/cm^3[/tex]

Hence the perfect order will be-

                      [tex]10^6 g/cm^3[/tex] >[tex]1 g/cm^3[/tex]  > [tex]10^-3\ g/cm^3[/tex]  

                      [tex]i.e\ 1 kg/mm^3>1\ g/cm^3>1 kg/m^3[/tex]

Answer:

1 kg/mm³, 1 kg/m³, 1 g/m³

Explanation:

We have 3 objects of different densities, 1 kg/m³, 1 g/m³, and 1 kg/mm³.

In order to compare their densities, we will express all of them in the same units, for instance, kg/m³.

First object

It has a density of 1 kg/m³.

Second object

We know that 1 kg = 10³ g. Then,

1 g/m³ × (1 kg/10³ g) = 10⁻³ kg/m³

Third object

We know that 1 m = 10³ mm. Then,

1 kg/mm³ × (10³ mm/1 m)³ = 10⁹ kg/mm³

The densities, from most to least dense are:

1 kg/mm³, 1 kg/m³, 1 g/m³

With the air bag deployed, the driver has 5 times longer to decelerate and lessen her/his impact and risk of injury.

Final answer:

The presence of heat, steam, and condensation, as well as feeling or hearing the engine cooling down, can indicate if a parked car had been running recently.

Explanation:

When walking close to a parked car, you can tell if it has been recently running by paying attention to energy flows. If the engine was running recently, you may be able to feel the heat radiating from the hood or hear the engine cooling down. Another clue is the presence of steam or condensation from the exhaust pipe, indicating that the engine has been producing heat and burning fuel. These signs indicate that the car was using stored chemical energy in the form of gasoline, converting it into mechanical energy to power the engine and produce heat.

IT's cell membrane because it maintains homeostasis by controlling what enters the cell and what exits it.

Future NASA research projects include using probes to collect data, collecting samples on an asteroid, and conducting unmanned space missions.

The future NASA research projects that apply to the given options in the question are:

Answer: At the top of its flight.

At the top of the flight,the height from the ground is maximum. Owing to this position the potential energy attained here is the maximum.

Also potential energy = mgh

Where m is the mass of the object.

g is the acceleration due to gravity

h is the height of object.

From this equation we can conclude that at the top,the maximum height would be attained and hence it would possess maximum potential energy.

Also at the top the object will possess zero velocity.

Kinetic energy = 1/2 (mv^2).

Where m is the mass of the object

v is the velocity of the object.

Hence at the top, since the velocity of the object is zero,the kinetic energy would be zero as explained in the below equation.

Kinetic energy= 1/2(m x 0)

Kinetic energy = 0.

Thus at the top of the flight,the ball possess only potential energy and minimum (0) kinetic energy.

Because this allows us to describe the direction of the motion.

In fact, when studying a motion, we need to specify the velocity of the object, which consists of a magnitude (the speed) and also a direction. Without a coordinate system, it would be impossible to describe in which direction is the object moving.

Budgets help consumers control their expenses and reach financial goals by providing a system to track and manage incoming and outgoing funds, allowing for informed financial decisions.(Option B)

The question relates to how budgeting assists consumers in reaching their financial goals. Among the given options, B) Budgets allow consumers to control how much money they have going out for expenses is the best explanation. A budget is an invaluable tool that enables individuals to track incoming and outgoing funds, ensuring that expenses do not exceed income. It helps in identifying non-essential expenditures and allows for adjustments to meet financial goals.

While budgeting isn't always easy—often because it requires making trade-offs and giving up certain pleasures—it is essential in a world of economic scarcity where desires outstrip realities. By creating and adhering to a budget constraint, individuals can navigate their financial resources effectively and make informed decisions about their consumption.

Answer is B- 200 m

Given:

m (mass of the car) = 2000 Kg

F = -2000 N

u(initial velocity)= 20 m/s.

v(final velocity)= 0.

Now we know that

F= ma

Where F is the force exerted on the object

m is the mass of the object

a is the acceleration of the object

Substituting the given values

-2000 = 2000 × a

a = -1 m/s∧2

Consider the equation

v=u +at

where v is the initial velocity

u is the initial velocity

a is the acceleration

t is the time

0= 20 -t

t=20 secs

s = ut +1/2(at∧2)

where s is the displacement of the object

u is the initial velocity

t is the time

v is the final velocity

a is the acceleration

s= 20 ×20 +(-1×20×20)/2

s= 200 m

Answer:

Stopping distance, s = 200 meters

Explanation:

Mass of the car, m = 2000 kg

Force acting in the car, F = -2000 N

Initial speed of car, u = 20 m/s

Finally, it stops, v = 0          

Using second equation of motion as :      

[tex]F=ma[/tex]

[tex]a=\dfrac{F}{m}[/tex]

[tex]a=\dfrac{-2000}{2000}[/tex]

[tex]a=-1\ m/s^2[/tex]

Let s is the stopping distance. Now using third equation of motion as :

[tex]s=\dfrac{v^2-u^2}{2a}[/tex]

[tex]s=\dfrac{0-(20)^2}{2\times -1}[/tex]

s = 200 meters

So, the stopping distance of the car is 200 meters. Hence, this is the required solution.

Answer:

 Height of ramp = 17.49 m

Explanation:

  We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Considering horizontal motion of skier

      Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.

    [tex]63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds[/tex]

The vertical distance traveled in 1.909 seconds is the height of  ramp

      Initial velocity = 0 m/s, acceleration = acceleration due to gravity =  9.8 [tex]m/s^2[/tex], time = 1.909 s and we need to find displacement.

      [tex]s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m[/tex]

    So height of ramp = 17.49 m

Answer:

B on edge

Explanation:

Hold up raw egg and say “CAUSE” as you crack the egg on the side of the bowl.

2. Say “EFFECT” as you break open the egg into the bowl.

3. Hold up the hardboiled egg and say “CAUSE” as you go through exaggerated motions of tossing the egg to a student.

4. As they either catch it or drop it, say “EFFECT”.

It is a physical change. One is physically change the wheat from one form to the other.

a) Let's call x the direction parallel to the river and y the direction perpendicular to the river.

Dave's velocity of 4.0 m/s corresponds to the velocity along y (across the river), while 6.0 m/s corresponds to the velocity of the boat along x. Therefore, the drection of Dave's boat is given by:

[tex]\theta= arctan(\frac{v_y}{v_x})=arctan(\frac{4.0 m/s}{6.0 m/s})=arctan(0.67)=33.7^{\circ}[/tex]

relative to the direction of the river.

b) The distance Dave has to travel it S=360 m, along the y direction. Since the velocity along y is constant (4.0 m/s), this is a uniform motion, so the time taken to cross the river is given by

[tex]t=\frac{S_y}{v_y}=\frac{360 m}{4.0 m/s}=90 s[/tex]

c) The boat takes 90 s in total to cross the river. The displacement along the y-direction, during this time, is 360 m. The displacement along the x-direction is

[tex]S_x = v_x t =(6.0 m/s)(90 s)=540 m[/tex]

so, Dave's landing point is 540 m downstream.

d) If there were no current, Dave would still take 90 seconds to cross the river, because its velocity on the y-axis (4.0 m/s) does not change, so the problem would be solved exactly as done at point b).