Which of the following elements is not contained in a carbohydrate?
Carbon
Hydrogen
Nitrogen
Oxygen

Answer:

Organic

Explanation:

Glucose is an organic compound, as its structure contains atoms of carbon, which are the main constituents of organic molecules. Glucose is specifically a monosaccharide that belongs to the group of carbohydrates, one of the four types of organic molecules.

C6H12O6 is an organic compound because it contains carbon in its structure.

Organic compounds are carbon-based molecules, essential to life and diverse in structure. They include hydrocarbons like methane, functional groups like alcohols, and complex biomolecules such as proteins and DNA. Organic chemistry studies their synthesis, structure, and properties, playing a crucial role in pharmaceuticals, agriculture, and materials science

In the given case C6H12O6 is an organic compound as organic compounds are defined as covalently bonded compounds containing carbon, excluding carbonates and oxides. C6H12O6 is composed of carbon (C), hydrogen (H), and oxygen (O) atoms, making it an organic compound.

Answer:

42.5 g

Explanation:

Calculate the mass of the soft drink given the density and volume:

355 mL × 1.04 g/mL = 369.2 g

Now calculate the mass of sucrose given the percentage:

0.115 × 369.2 g = 42.46 g

Rounded to 3 significant figures, the mass is 42.5 g.

Answer:

42.458 g of sucrose is contained in 355 mL (12 oz) of the soft drink

Explanation:

Volume of the soft drink = 355mL

Density = 1.04 g/mL

We know

Density = Mass / Volume

Rearranging the formula  

Mass of soft drink = Density × volume

[tex]=1.04 g/mL \times 355mL=369.2 g[/tex]

[tex]Mass = \frac {(mass of solute)}{(mass of solution )} \times 100%[/tex]

[tex]11.5  = \frac {(mass of solute (sucrose))}{(mass of solution(soft drink) )} \times 100%[/tex]

[tex]11.5  = \frac {(mass of solute (sucrose))}{(369.2 g)} \times 100%[/tex]

So

Mass of sucrose

[tex]=\frac {(11.5 \times 369.2g)}{(100)}[/tex]

= 42.458 g  is the Answer

Answer:

n = 9

Explanation:

Given parameters:

Molar mass of Na₂SO₄.nH₂O = 304.04gmol⁻¹

Solution

To find the hydration number n, we simply express atomic masses of the atoms in the compound as equal to the given molar mass.

Atomic mass of Na = 23g

                           S = 32g

                           O = 16g

                            H = 1g

       Molar mass of the compound is evaluated as:

       2(23) + 32 + 4(16) + n[2(1) + 16] = 304.04

       46 + 32 + 64 + 18n = 304.04

          142 + 18n = 304.04

              18n = 304.04 - 142

              18n = 162.04

                n = 9

Answer:

=C₄H₄O₂

Explanation:

Given the empirical formula of a molecule, the he the quotient of the molecular mas and and the empirical mass=constant.

84.0 g/mol/mass of(C₂H₂O)=constant

=84/(12×2+1×2×16)

=84/42

=2

Therefore, the molecular formula is (C₂H₂O)₂=C₄H₄O₂

Answer:

[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula

Explanation:

Empirical formula is the simplest form of a Molecular formula.

For example  

Molecular formula of glucose is [tex]C_6 H_{12} O_6[/tex]

Its empirical formula is [tex]C_1 H_2 O_1[/tex]

The subscript numbers of the molecular formula is divided by a common number n=6 here.

Another example:

Molecular formula of Octane is [tex]C_8 H_{18}[/tex] and Its empirical formula will be [tex]C_4 H_9[/tex]  

Subscripts divided by n=2.

To find n we make use of the formula  

[tex]\frac {(molecular mass )}{(empirical formula mass)}=n[/tex]

[tex]= \frac {84.0g}{(C_2H_2O mass)}\\\\=\frac {84.0g}{(24+2+16)g}=\frac {84.0g}{42g}=2[/tex]

So, we see n=2 here

Empirical formula × n = molecular formula

[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula

(Answer)

Please note:

Molar mass is the mass of 1 mole of the substance and its unit is g/mol .

n is the number of moles by which the empirical formula is multiplied to get the molecular formula of the compound.

Answer:

Approximately 3318 disintegrations per minute.

Explanation:

The activity [tex]A[/tex] of a radioactive decay at time [tex]t[/tex] can be found with the following equation:

[tex]\displaystyle A(t) = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}[/tex].

In this equation,

The decay constant here can be found using the activity after 10 days. As long as both times are in the same unit (days in this case,) conversion will not be necessary.

[tex]A(10) = A_0\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}= (\mathrm{8540\; min^{-1}})\cdot \mathrm{e}^{\rm -\lambda \times 10\;day}[/tex].

[tex]A(10) = \rm 6690\; min^{-1}[/tex].

[tex]\displaystyle \frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}} = \mathrm{e}^{\rm -\lambda \times 10\;day}[/tex]

Apply the natural logarithm to both sides of this equation.

[tex]\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)} = \ln{\left(\mathrm{e}^{\rm -\lambda \times 10\;day}\right)}[/tex].

[tex]\displaystyle \rm -\lambda \cdot (10\;day) = \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}[/tex].

[tex]\displaystyle \rm \lambda= \rm \frac{\displaystyle \ln{\left(\frac{\rm 6690\; min^{-1}}{\mathrm{8540\; min^{-1}}}\right)}}{-10 \; day} \approx 0.0200280\; day^{-1}[/tex].

Note that the unit of the decay constant [tex]\lambda[/tex] is [tex]\rm day^{-1}[/tex] (the reciprocal of days.) The exponent [tex]-\lambda \cdot t[/tex] should be dimensionless. In other words, the unit of [tex]t[/tex] should also be days. This observation confirms that there's no need for unit conversion as long as the two times are in the same unit.

Apply the equation for decay activity at time [tex]t[/tex] to find the decay activity after 47.2 days.

[tex]\displaystyle \begin{aligned}A(t)& = A_0 \cdot \mathrm{e}^{-\lambda\cdot t}\\&\approx \rm \left(8540\; min^{-1}\right)\cdot \mathrm{e}^{-0.0200280\; day^{-1}\times 47.2\;day}\\&\approx \rm 3318\; min^{-1}\end{aligned}[/tex].

By dimensional analysis, the unit of activity here should also be disintegrations per minute. The activity after 47.2 days will be approximately 3318 disintegrations per minute.

Answer:

236588 cm3

Explanation:

If a large recipe calls for 250 quarts of milk, there are 236588 cm3.

Multiply the volume value by 946.353

Answer:

From n=1 to n=2

Explanation:

Electrons in n=1 are strongly attracted to the nucleus and therefore will require great force to overcome the electrostatic force of attraction to displace them from the energy level to another.

The electrostatic force reduces as you progress to the outer energy levels.

Answer:

C. from n = 1 to n = 2

Explanation:

A.

[tex]\Delta E=E_{final}-E_{initial}[/tex]

[tex]\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(4^2 )}-\frac {1}{(3^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(16 )}-\frac {1}{(9)}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[0.0625-0.111]KJ mol^{-1}[/tex]

[tex]\Delta E=64 KJ mol^{-1}[/tex]

B.

[tex]\Delta E=E_{final}-E_{initial}[/tex]

[tex]\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(3^2 )}-\frac {1}{(2^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(9 )}-\frac {1}{(4)}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[0.111-0.25]KJ mol^{-1}[/tex]

[tex]\Delta E=182 KJ mol^{-1}[/tex]

C.

[tex]\Delta E=E_{final}-E_{initial}[/tex]

[tex]\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(2^2 )}-\frac {1}{(1^2 )}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[\frac{1}{(4)}-\frac {1}{(1)}]KJ mol^{-1}[/tex]

[tex]\Delta E=-1312[0.25-1]KJ mol^{-1}[/tex]

[tex]\Delta E=984 KJ mol^{-1}[/tex]

Answer:

D) constructive

Explanation:

Deposition is a constructive force since it involves dumping sediment in a particular location.

Constructive is the correct answer. A deposition is a constructive force when it involves dumping into sediment a particular location. I hope this will help you. Have a wonderful day!

Answer:

1-3 2-2 3-1

Explanation:

Explanation:

First conversion factor: moles of SO₄ per mole of Al₂(SO₄)₃.

3 mol SO₄ / mol Al₂(SO₄)₃

Second conversion factor: moles of S per mole of SO₄.

1 mol S / mol SO₄

Altogether:

(3 mol SO₄ / mol Al₂(SO₄)₃) × (1 mol S / mol SO₄) = 3 mol S / mol Al₂(SO₄)₃

To relate moles of S to moles of Al2(SO4)3, we use the compound's 2:3 ratio to establish that 1 mole of Al2(SO4)3 has 3 moles of S. Conversion factors are 1 mole Al2(SO4)3/3 moles S and 3 moles S/1 mole Al2(SO4)3. These allow for conversions between the moles of the two substances.

To construct a pair of conversion factors that relate moles of S to moles of Al2(SO4)3, we need to look at the chemical compound's formula. The compound aluminum sulfate, Al2(SO4)3, shows there are three sulfate (SO42-) ions for every two aluminum (Al3+) ions.

This indicates a 2:3 ratio between Al and SO4 in the compound. Each sulfate ion contains one atom of sulfur (S), so for every mole of Al2(SO4)3, there are three moles of sulfur atoms (S). Thereby, the conversion factors are:

These factors can be used to convert moles of sulfur to moles of aluminum sulfate and vice versa.

Answer:

14.3 g SO₃

Explanation:

2S + 3O₂ → 2SO₃

First, find the limiting reactant.  To do that, calculate the mass of oxygen needed to react with all the sulfur.

5.71 g S × (1 mol S / 32 g S) = 0.178 mol S

0.178 mol S × (3 mol O₂ / 2 mol S) = 0.268 mol O₂

0.268 mol O₂ × (32 g O₂ / mol O₂) = 8.57 g O₂

There are 10.0 g of O₂, so there's enough oxygen.  The limiting reactant is therefore sulfur.

Use the mass of sulfur to calculate the mass of sulfur trioxide.

5.71 g S × (1 mol S / 32 g S) = 0.178 mol S

0.178 mol S × (2 mol SO₃ / 2 mol S) = 0.178 mol SO₃

0.178 mol SO₃ × (80 g SO₃ / mol SO₃) = 14.3 g SO₃

Answer:

oxidation

Explanation:

oxidation number are based on the distribution of electrons in a molecule

Answer:

Water

Explanation:

Water molecules are known to have a melting point of 0°C and a boiling point of 100°C.

The melting and boiling points are as a result of the intermolecular force of attraction between the molecules of water. The predominant bond type that dictates the property of the melting and boiling point is the hydrogen bonding. This bond is a strong force of attraction and it impacts on the physical properties of water.

Answer:

Water

Explanation:

The substance that has a melting point at 0 and a boiling point at 100 is water.  Water is the only substance that fits into this category.  According to van.physics.illinois.edu, it states the following "For pure water, the boiling point is 100 degrees Celsius (212 Fahrenheit) at one atmosphere of pressure, and the melting point is 0 degrees Celsius (32 degrees Fahrenheit) at one atmosphere of pressure."

Answer:  Water

Answer: The benzoic acid is a weak acid.

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

The chemical equation for the reaction of potassium benzoate with water follows:

[tex]C_6H_5COOK+H_2O\rightarrow C_6H_5COOH+KOH[/tex]

Here, benzoate anion is accepting a proton from water and is acting as conjugate base. Water is acting as conjugate acid.

The solution formed is basic solution because of the formation of potassium hydroxide.

When a strong base and weak acid reacts, it leads to the formation of basic solution.

Hence, the benzoic acid is a weak acid.

A conjugate base differs from the forming acid in that it has one additional negative charge and one fewer H atom. It is a material that remains after an acid loses its hydrogen ion. Here benzoic acid is a weak acid. The correct option is C.

Benzoic acid is a weak acid because it is an organic acid. The acid is more potent at higher proton-leaving rates. Because of its resonance structure, benzoic acid has a reduced ability to leave protons, which restricts its proton-leaving potential.

The chemical equation for the reaction of potassium benzoate with water follows:

C₆H₅COOK + H₂O → C₆H₅COOH + KOH

Here, the benzoate anion is accepting a proton from water and is acting as a conjugate base. Water is acting as conjugate acid. When a strong base and weak acid react, it leads to the formation of a basic solution.

Thus the correct option is C.

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Answer:

B. Chemicals can keep bread fresher longer.

Explanation:

I checked the label of my bread  :)) and I found one ingredient which keep the freshness:  

ascorbic acoid (vitamin C) - it has antioxidant properties

Answer:

Chemicals can keep bread fresher longer.

Answer: 0.4

Explanation: The easiest way to do this is to get a denominator of 10. To do this, multiply each number in 2/5 by 2. You will get the fraction 4/10. With the denominator of 10, the answer would be 0.4 by putting the decimal in front of the number.

Answer:

1+2i

Explanation:

Answer:

1+2i

Explanation:

Let the two complex numbers in the question to be as shown below,

a + bi = 4 − 3i and s + ti = -2 + 7i.

Apply the Midpoint Formula for the 2 complex numbers which are a + bi and s + ti is:

[tex]Midpoint=\frac {a+s}{2}+ \frac {b+t}{2}i[/tex]

Applying values as:

[tex]Midpoint=\frac {4-2}{2}+ \frac {-3+7}{2}i[/tex]

Hence, the midpoint is 1+2i

Answer:

C,D

Explanation:

Answer:

C D

Explanation:

Answer:

A double covalent bond.

Explanation:

A double covalent bond forms between two oxygen atoms.

A double covalent bond is when two pairs of electrons are shared between the atom. Usually, there is only one pair, rather than two pairs.

The electrostatic attractive interaction between the same or different elements is called bonds. A nonpolar covalent is formed between two oxygen atoms. Thus, option a is correct.

A chemical bond that involves the mutual sharing of electrons between the outer valence shell of the elemental atom is called a covalent bond. The covalent bonds are of two types namely polar and non-polar.

The polar covalent bond is the unequal sharing of the electrons in the outer shell due to differences in electronegativities. The non-polar covalent bond is formed between the same or different elements in a compound.

In a non-polar covalent bond like two oxygen atoms, the valence electrons are shared equally and have negligible electronegativity differences.

Therefore, option a. two oxygen atoms form a nonpolar covalent.

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Answer:

0.22 atm

Explanation:

The total pressure is the sum of the partial pressures.

P = P₁ + P₂ + P₃

1.25 atm = 0.68 atm + 0.35 atm + P

P = 0.22 atm

Answer:

0.22 atm

Explanation:

First, you need to add up each of the values of the known gases

0.68+0.35

Then you need to subtract that value from the total pressure to find the partial pressure of the third value

1.25-(0.68+0.35)

By doing that you get the answer of 0.22 atm

Answer:

Explanation:

Oxidation state of Cr in CrPO₄

As a general rule, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

The compound above is in its neutral state and we sum all the oxidation numbers and equate to zero:

The oxidation number of P is -2

                                           O is -2

Let the oxidation number of Cr be x:

                              x + (-2) + 4(-2) = 0

                              x -2-8 = 0

                               x -10 = 0

                                x = +10

For Cr in Cr₃(PO₄)₂

         Using the same rule:

        2(x) + 2[-2 + 4(-2)] = 0

           2x + 2(-2-8) = 0

            2x -20 = 0

                x = +10

Answer:

[tex]CrPO_4: Cr +3\\Cr_3(PO_4)_2: Cr+2[/tex]

Explanation:

[tex]CrPO_4[/tex] and [tex]Cr_3(PO_4)_2[/tex] are compounds known as ternary salts

This means that they are formed by a metal or a non-metal and an anion

 Its formula is [tex]M_x(X_yO_z)_w[/tex], that is, the cation is written first and then the anion and the simplified charges are exchanged if possible.

The anion [tex]PO_4[/tex] has a load of -3: [tex]PO_{4}^{-3}[/tex]

Let's look at the first compound [tex]CrPO_4[/tex] we observe that when exchanging the charges 3 of the[tex]PO_4[/tex] does not appear therefore the charges are simplified as the charges are completely simplified, it means that the chromium has the same valence (numerically but with opposite sign) that the anion

Therefore the oxidation state of Cr in [tex]CrPO_4[/tex] is +3

Let's look at the second compound [tex]Cr_3(PO_4)_2[/tex], it is observed that when exchanging the valences, the 3 of the [tex]PO_4[/tex] is with the chromium, and with the anion is  2

As valencia are not multiples, they cannot be simplified.

When exchanging the valences, the[tex]PO_4[/tex] has the valence corresponding to the chromium which in this case is + 2

Answer:

Its not bar graph

Explanation:

Answer:

C- Line Graph

Explanation:

Answer:

D) forms hydronium ions in water

Explanation:

Texture and conductivity are physical properties which makes answer A and B wrong. Answer C does not refer to a chemical reaction.

Answer:

Total of all numbers added with the correct rounding and number of significant figures

Explanation:

1. Add up all the numbers

8.32+8.00+8.30+8.3

2. Determine how many significant figures should be in your final answer. When it comes to addition, it will be the fewest number of decimal places. since 8.3 has one decimal place, your final answer should only have one decimal place.

3. Round your final answer to the nearest tenths

Give the numbers that we have to add up.

Answer:

Among the three major types of rock, fossils are most commonly found in sedimentary rock. Unlike most igneous and metamorphic rocks, sedimentary rocks form at temperatures and pressures that do not destroy fossil remnants. Often these fossils may only be visible under magnification.

Explanation:

Answer:

(C) 503 g

Explanation:

Balanced reaction:

2NH₃ + 2O₂ → N₂O + 3H₂O

Stoichiometry:

317 g NH₃ × (1 mol NH₃ / 17.03 g NH₃) = 18.61 mol NH₃

18.61 mol NH₃ × (3 mol H₂O / 2 mol NH₃) = 27.92 mol H₂O

27.92 mol H₂O × (18.02 g H₂O / mol H₂O) = 503 g H₂O

Answer:

(C) 503 g of water, H2O, are produced from 317 grams of ammonia and excess oxygen

Explanation:

[tex]2 NH_3+2 O_2>N_2 O+3 H_2 O[/tex]

Molar mass of

[tex]H_2 O=(2\times1.008)+15.999=18.02 g/mol[/tex]

Molar mass of

[tex]NH_3=14.01+(3\times1.008)=17.03 g/mol[/tex]

The conversions are

Step 1:

Mass [tex]NH_3[/tex] to moles [tex]NH_3[/tex] by dividing with molar mass [tex]NH_3[/tex]

Step 2:

Moles [tex]NH_3[/tex] to moles [tex]H_2 O[/tex] by using mole ratio of [tex]NH_3:H_2 O[/tex] i.e., 2 : 3

Step 3:

Moles [tex]H_2 O[/tex] to mass [tex]H_2 O[/tex] by multiplying with molar mass [tex]H_2 O[/tex]

[tex]317gNH_3  \times \frac {(1mol NH_3)}{(17.03gNH_3 )} \times \frac {(3mol H_2 O)}{(2mol NH_3 )} \times \frac {(18.02g H_2 O)}{(1mol H_2 O)}[/tex]

[tex]= 503g H_2 O[/tex] is formed.

(Answer)

Please note :

To convert moles to mass, we multiply by molar mass  

To convert mass to moles, we divide by molar mass

Molar mass is the mass of 1 mole of the substance

For example molar mass of [tex]CO_2[/tex] is

[tex](12.0+2\times16)=44 g/mol[/tex]

(we just add the atomic mass of the atoms to get the molar mass of the substance).

Answer:

A double bond between carbon atoms

Explanation:

The suffix -ene is used for alkenes, which tells you that the molecule has a carbon-carbon double bond.

Answer:

Weathering is the breakdown of rocks into smaller particles called sediment (not sediments)

Mechanical weathering is when rocks are physically broken into smaller pieces, but the minerals in the rock remain the same

When a rock is broken down in a way that changes the mineral composition, it is called Chemical Weathering.

The blanks about Weathering in the question are filled as follows;

According to the question;

For Statement 1:

For Statement 2;

For Statement 3:

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Answer:

Dr. Patel, a cardiologist, presents her findings on heart disease

Explanation: