Which of the following statements are true?

All square matrices are diagonal matrices.

All diagonal matrices are square matrices.

The size of any square matrix is m x m, where m is a positive integer.

All coefficient matrices are square matrices.

If each item Kathy puts in the box weighs 2 kg, then the weight of p items will be 2p kilograms. Since the box weighs 1 kg, the total weight in kilograms will be ...

... 2p + 1

Kathy wants that value to be less than or equal to 10 kg, so her inequality will be

... 2p + 1 ≤ 10 . . . . . corresponds to selection D

The left end of the box is at 32; the right end is at 37. The box part of the plot contains all the values ...

... between 32 and 37.

Answer:

The correct option is 3.

Step-by-step explanation:

From the given box plot it is clear that

1. The left end point of the line is 27. So, the minimum value of the data is 27.

2. The left end of the box is 32. It means the first quartile of the data is 32.

3. The line inside the box represents the median. So the median of the data is 36.

4. The right end of the box is 37. It means the third quartile of the data is 37.

5. The right end point of the line is 40. So, the maximum value of the data is 40.

It means the box part of the box plot contains all the values between 32 and 37.

Therefore the correct option is 3.

To find the area of the given traingle we have to draw perpendicular from point 'J' which meets the x axis at point (2,0) and let us named it 'P'.

As we know that area of triangle is

[tex] = \frac{1}{2}\times b \times h [\tex]

Here base 'b' will be LK and height 'h' will be JP

Here,

LK= 4 units JP=4 units

Area ={1}{2} *(4)*(4)

On solving the equation we get,

Area=8 Sq units

The interest is computed from

... I = Prt

where P is the principal amount ($569), r is the rate (0.045) and t is the time in years (250/360).

... I = $569×0.045×250/360 ≈ $17.78

Please note that time is not rounded. Rather, the exact value (25/36) is used in the calculation. The only rounding of any number is done at the end, where the amount is rounded to the nearest cent. (Your text authors should know this.)

_____

If you follow the problem instructions (which Valerie's lender will not do), the interest is calculated as ...

... t = 250/360 = 0.6944444... ≈ 0.69 . . . . years

... I = $569×0.045×0.69 ≈ $17.67

_____

Note the rounding of intermediate numbers (time) introduces an error of about $0.11 in the answer.

Answer:$17.41 (A+)

Step-by-step explanation:

Answer:

The answers would be

1. C

2. B

3. A

Step-by-step explanation:

The term product refers to multiplication. So in question 1, when we see the term quotient, we are looking to multiply.

The term quotient refers to division. So in questions 2 and 3, when we see this term, we look to divide.

Answer:

C. [tex]6n[/tex]

B. [tex]\frac{6}{(x+y)}[/tex]

A. [tex]\frac{Z}{3}[/tex]

Step-by-step explanation:

1. This expression refers to the product operation between real numbers, therefore the correct algebraic form is [tex]6n[/tex]

2. This expression refers to the operation division between real numbers, therefore the correct algebraic form is [tex]\frac{6}{(x+y)}[/tex]

3. This expression refers to the operation division between real numbers, therefore the correct algebraic form is [tex]\frac{Z}{3}[/tex]

2c. We assume that the equations for ballistic motion in a vacuum apply, and the rate of downward acceleration is 32 ft/s². Then it will take ...

... (288 ft/s)/(32 ft/s²) = 9 s

for the rocket to reach its maximum height (its vertical velocity to decrease to zero).

2d. The trip down takes the same amount of time as the trip up, so the round trip time is ...

... (9 s)×2 = 18

_____

The acceleration due to gravity decreases the vertical velocity by the same amount (32 ft/s) each second. An equation for that might be ...

... v = 288 -32t

When the vertical velocity is zero, the rocket is no longer going up. It has reached its maximum height. Then the equation for that looks like ...

... 0 = 288 -32t

... 32t = 288

... t = 288/32 = 9 . . . . . compare to the solution above

After 9 seconds, the rocket reaches its maximum height.

___

Simplifying the description of free-fall is a little harder. In physics terms, the potential energy the rocket has at its maximum height all gets converted to kinetic energy on the way down. At impact with the ground, the kinetic energy is the same as it was when the rocket was launched. That is, its velocity is 288 ft/s earthward at impact. The above equation for velocity still applies, but now we're solving for v = -288.

... -288 = 288 -32t

... -576 = -32t

... 576/32 = t = 18 . . . . . twice the time it took to reach maximum height.

The round trip takes 18 seconds.

A 81.2 is the answer

Hello!

Answer:⇒⇒⇒⇒⇒⇒⇒⇒A. 81.2

Step-by-step explanation:

[tex]6(2.6+12.1)[/tex]

Add the numbers.

[tex]2.6+12.1=14.7[/tex]

[tex]6*14.7[/tex]

Multiply the numbers.

[tex]6*14.7=88.2[/tex]

[tex]=88.2[/tex]

[tex]88.2-7[/tex]

Subtract the numbers.

[tex]88.2-7=81.2[/tex]

[tex]=81.2[/tex]

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

Answer:By multiplying with (1+0.01x) where x is the percentage of increase, monthly pay rate of 21$ after marked up 78.7% and 10% profit will be $41.28.

Step-by-step explanation:

Given that pay rate is 21$ and it is marked up by 78.7% and made a 10% profit.

If any value marked up or made a profit of x% then we have to multiply with (1+0.01x) to find the new value.

New pay after 78.7% marked up using above formula is [tex]21X(1+0.01X78.7)=21X1.787=37.527[/tex]

Now we have to use above formula again for 10% profit.

Hence new value [tex]=37.527(1+0.01X10)=37.527X1.1=41.2797[/tex]≈$41.28

6

24% = [tex]\frac{24}{100}[/tex]

multiply 25 by this fraction

25 × [tex]\frac{24}{100}[/tex] = [tex]\frac{25(24)}{100}[/tex] = 6

Angles 1 and 2 involve lines a, b, and d. If d is the transversal, then the only pair left out of those three lines is a and b.

_____

Angles 1 and 2 are between lines a and b (interior), and either side of line d (alternate), so meet the requirements to be called alternate interior angles.

Answer:

ITS A AND B

Step-by-step explanation:

Answer: First option. x-intercept is -5; y-intercept is -7/4

Solution:

1) To find the x-intercept we replace y by 0, and solve for x:

-(7/5)x-4y=7

-(7/5)x-4(0)=7

-(7/5)x-0=7

-(7/5)x=7

Multiplying both sides of the equation by -(5/7)

-( 5/7)[-(7/5)]x=-(5/7)(7)

x=-(5*7)/7

x=-35/7

x=-5

The x-intercept is -5

2) To find the y-intercept we replace x by 0, and solve for y:

-(7/5)x-4y=7

-(7/5)(0)-4y=7

-0-4y=7

-4y=7

Dividing both sides of the equation by -4:

-4y/(-4)=7/(-4)

y=-(7/4)

The y-intercept is -(7/4)

Answer: 6280 cm

Step-by-step explanation:

Given: The diameter of hamster wheel = 20 cm

The circumference of hamster wheel is given by :-

[tex]C=\pi d[/tex], where d is the diameter of the hamster wheel.

[tex]\Rightarrow C=(3.14)(20)=62.8\text{ cm}[/tex]

During one race, the number of rotations of the wheel = 100

Therefore, the distance run by chubby is given by :-

[tex]D=100\times C\\\\\Rightarrow D=100\times62.8\\\\\Rightarrow D=6280\text{ cm}[/tex]

Answer:

6283 cm.

Step-by-step explanation:

We have been given that Avi's pet hamster Chubby completed 100 rotations of the wheel. The diameter of the hamster wheel is 20 cm.

Since wheel is a circle, so the distance covered by Chubby in one rotation will be equal to the circumference of wheel.

[tex]\text{Circumference of circle}=2\pi r=\pi D[/tex], where,

r = Radius of circle,

D = Diameter of circle.

Now we will find the circumference of wheel by substituting [tex]D=20[/tex] in above formula.

[tex]\text{Circumference of wheel}=\pi*20[/tex]

[tex]\text{Circumference of wheel}=62.83185307[/tex]

Since Chubby covers a distance of 62.83185307 cm in one rotation, so in 100 rotations distance covered by Chubby would be:

[tex]\text{Distance covered in 100 rotations}=100\times 62.83185307[/tex]

[tex]\text{Distance covered in 100 rotations}=6283.185307\approx 6283[/tex]

Therefore, Chubby ran a distance of 6283 centimeters.

(1) it is (C) the commutative property of multiplication: a*b = b*a, so 2*(-6/7) = (-6/7)*2

(2) it is (D) the commutative property of addition: a+b=b+a, so 5*4+3=3+5*4

commutate = "swap around"

D. John Felton kills the Duke of Beckingham

Here is some proof: https://en.wikipedia.org/wiki/John_Felton_(assassin)

Answer:

d

Step-by-step explanation:

Let x represent the number of half-gallons purchased by the store. Then x-13 is the number sold, and 2.80x is the store's cost. The revenue is 4.06(x-13) and the difference between that and cost is the profit.

... 4.06(x -13) -2.80x = 63.14

... 1.26x - 52.78 = 63.14 . .  . . eliminate parentheses, collect terms

... 1.26x = 115.92 . . . . . . . . . . add 52.78

... x = 115.92/1.26 = 92 . . . . . divide by the coefficient of x

The store purchased 92 half-gallons of milk.

Answer

d = 2

Step-by-step explanation:

d divided by 12 is the same as d/12?

d/12 = 1/6

cross multiply and get 12 = 6d.

6(2) = 12.

Divide 12 by 2 and you get 2/12 which simplifies to 1/6.

Hope I helped. ^-^

d = 2

given [tex]\frac{d}{12}[/tex] = [tex]\frac{1}{6}[/tex]

multiply both sides by 12

d = 12 × [tex]\frac{1}{6}[/tex] = 2

Differentiating both sides of PV = C with respect to t gives us ...

... P'V +PV' = 0

Filling in the given numbers gives us ...

... (40 kPa/min)(900 cm³) + V'(150 kPa) = 0

Solving for V' gives ...

... V' = -(40 kPa/min)(900 cm³)/(150 kPa)

.. V' = -240 cm³/min

The volume is decreasing at the rate of 240 cm³/min.

Final answer:

In Physics, Boyle's Law relates the pressure and volume of a gas at constant temperature. To find the rate at which volume is decreasing as pressure increases, we differentiate the equation PV = C with respect to time and solve for [tex]\frac{dV}{dt}[/tex] , given the pressure, volume, and rate of change of pressure which comes out to be 240 cm³/min.

Explanation:

The subject of this question is Physics, specifically relating to Boyle's Law, which is part of gas laws studied in chemistry and physics. The level of this question is appropriate for High School students. We know from Boyle's Law that for a given amount of gas at constant temperature, the pressure P is inversely proportional to the volume V, meaning that PV = C or k, where C is a constant.

To solve the problem stated, we differentiate both sides of PV = C with respect to time t. This will give us P[tex]\frac{dV}{dt}[/tex] + V[tex]\frac{dP}{dt}[/tex] = 0. With the known values of P, V, and[tex]\frac{dP}{dt}[/tex] , we can solve for [tex]\frac{dV}{dt}[/tex], which will give us the rate at which the volume is decreasing as the pressure increases.

By substituting the given values into the differentiated equation: 150 kPa x   [tex]\frac{dV}{dt}[/tex]+ 900 cm³ x 40 kPa/min = 0, we solve for [tex]\frac{dV}{dt}[/tex]  to find the rate at which the volume is changing.

[tex]\frac{dV}{dt}[/tex] = - [tex]\frac{900}{150}[/tex] x  40

[tex]\frac{dV}{dt}[/tex] = -6 x 40

[tex]\frac{dV}{dt}[/tex] = -240 cm³/min

Following this method, we find that the volume is decreasing at a rate of 240 cm³/min.

| u + v | = 2

u + v = - 4i + 1j + 4i + 1j = 2j

the magnitude of a vector ai + bj is

| ai + bj | = √(a² + b² )

for u + v = 0 + 2j

| u + v | = √(0² + 2² ) = √4 = 2

Answer:

the answer is D and A hope this helps

B and D

under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (y, - x )

A(5, 4 ) → A'(4, - 5 )

B(6, 9 ) → B'(9, - 6 )

C(2, 8 ) → C'(8, - 2 )

These points correspond to the coordinates in the diagram → B

under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x )

A(- 1, 2 ) → A'(- 2, - 1 )

B(-1, 5 ) → B'(- 5, - 1 )

C(- 3, 5 ) → C'(- 5, - 3 )

D(- 3, 2 ) → D'(- 2, - 3 )

These points correspond to the coordinates in the diagram → D

2*53/25 = 4.24

4 is not enough to maintain the required ratio, so there must be 5 chaperones, minimum.

_____

Presumably, the guidelines contain additional information regarding whether the number of chaperones can be odd. Sometimes, two are required so that one can be taking care of a student while the other handles the remaining students (or calls for emergency aid). In that case, the minimum for 53 students may be 6 chaperones.

Alright, so i'm looking at the graphs and i'm seeing B as an answer, Probably not A. C and D are confusing,

In the end, i'd say B and D.

If i'm wrong, please tell me.

The correct answers are (B), (C), and (D).

(C) is pretty straight forward. The graph resembles the graph of a quadratic function that us concave upwards. A quadratic function, and functions with an even degree like [tex]x^4, x^6[/tex] will be concave upwards if the leading term is positive.

For function with an odd degree such as [tex]x^3, x^5[/tex] will be mostly negative on the side of the negative x axis and positive on the side of the positive x-axis if the leading coefficient is positive.  A cubic function with a positive leading term will be negative on the side of the negative x-axis  for large negative numbers and positive on the side of the positive x-axis for large positive numbers.  From this explaination we can gather that (B) and (D) are also correct .

The correct options are (B),(C) and (D).

Yes. You can solve in the usual way.

Take the square root:

... x-7 = ±√0 = 0

Add 7:

... x = 7

_____

There is one distinct real solution (with multiplicity 2).

y = -x² + 9

the x-intercepts are x = - 3 and x = 3 hence the factors are

(x + 3 ) and (x - 3 )

polynomial is the product of its factors

y = a(x - 3 )(x + 3) ← ( a is a multiplier )

from the end behaviour the parabola opens down and is a maximum and so the value of a is negative

y = -(x - 3)(x+3) = - (x² - 9 ) = - x² + 9

The polynomial function with the given features is f(x) = -(x + 3)(x - 3), which is a quadratic function with the required y-intercept, x-intercepts, and end behavior.

The question involves finding a polynomial function given certain characteristics: a y-intercept of (0, 9), x-intercepts at (-3, 0) and (3, 0), a degree of 2, and specific end behavior.

Since the degree is 2, we are dealing with a quadratic function.

The x-intercepts tell us that the factors of the polynomial are (x + 3) and (x - 3).

The y-intercept indicates that when x is 0, the function equals 9.

The end behavior suggests that the leading coefficient is -1 because as x goes to infinity or negative infinity, f(x) goes to negative infinity.

Considering all the information, the function can be expressed as:

f(x) = -(x + 3)(x - 3)

To verify, expanding the factors gives:

f(x) = -(x^2 - 9)

f(x) = -x^2 + 9

This function has the required y-intercept of 9, x-intercepts of -3 and 3, and the correct end behavior.

Answer:

m=-3/8, n=12

Step-by-step explanation:

Answer: m=-3/8, n=12

Step-by-step explanation: Got it right on TTM

Multiply these as you would any binomial expressions, then replace i² with -1.

(4 -5i)·(2 +3i) = 4·2 +4·3i -5i·2 -5i·3i

... = 8 +12i -10i -15i²

... = 8+15 +2i

... = 23 +2i

_____

Your calculator may be able to do this problem for you.

(b)

using the 'laws of exponents '

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex]

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex]

2² × [tex]\frac{2}{2^{4} }[/tex] = [tex]\frac{2^{3} }{2^{4} }[/tex] = [tex]2^{(3-4)}[/tex] = [tex]2^{-1}[/tex]

Answer:

The price over three days fell linearly

Step-by-step explanation:

s = stock

s = -4x

s = -4(3)

s = -12

The stock decreased by 12 dollars over 3 days.

Answer: -12

Step-by-step explanation:Hello!I hope you are having a good day or evening and I hope this helps :) !!

C) p ≤ 78

I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.  

Answer:

C) p ≤ 78

Step-by-step explanation:

so we know the plane has a maximum capacity of 118

and 40 have already been loaded.

118-40= 78

we know it cannot have greater than 78 but it can equal 78

there fore passengers are less than or equal to 78

also shown like this p ≤ 78 or option C