Which of the following statements are true ? Check all that apply

Answer:

[tex]\frac{1215}{32}[/tex]

Step-by-step explanation:

The n th term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex], hence

[tex]a_{6}[/tex] = 5 × [tex](\frac{3}{2 )} ^{5}[/tex] = 5 × [tex]\frac{243}{32}[/tex] = [tex]\frac{1215}{32}[/tex]

The sixth term of the geometric sequence is 1215/32 given that the first term a₁=5 and common ratio r=3/2. This can be obtained by using formula for nth term of the geometric sequence.

Sequence is s collection of objects in a particular order and repetitions are allowed.

   Geometric Sequence:

a, ar, ar¹, ..., arⁿ⁻¹ is a geometric sequence, where a is the first term, r is the common ratio and arⁿ⁻¹ is the nth term.

From the definition, nth term of a geometric sequence is arⁿ⁻¹.

Given that, a₁=5 and r=3/2​

To find sixth term, put n=6 ⇒ arⁿ⁻¹=(5)(3/2)⁶⁻¹

                                                       =(5)(3/2)⁵

                                                       =5(3⁵/2⁵)

                                                       =5×(243/32)

                                                       =1215/32

Hence the sixth term of the geometric sequence is 1215/32 given that the first term a₁=5 and common ratio r=3/2.

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Answer:

D) 1/27

Step-by-step explanation:

The question is: 3^(-3).

Note that there is a negative sign in the number at the power place. This means that you must flip the number, and in this case, put it over 1. The rest is solved as usual:

3^-3 = 1/(3^3) = 1/(3 * 3 * 3) = 1/27

1/27, or D) is your answer.

~

Answer:

43.60

Step-by-step explanation:

12.36+31.24

Answer:

$384.00

Step-by-step explanation:

Since $8..0 is 1 hour, just multiply 48 x 8! Hope this helps!

Answer:

320

Step-by-step explanation:

The reason that you  48* 8 is because the 48 has overtime included in it so you would only 40*8.

Answer:

9a^2 +  3ab  - 6b^2

Step-by-step explanation:

(3a-2b)(3a+3b)

First term of each grouping is 3a and 3a.

Multiply those you get 9a^2.

Outer term of each grouping is 3a and 3b.

Multiply those you get 9ab.

Inner term of each grouping is -2b and 3a.

Multiply those you get -6ab.

Last term of each grouping is -2b and 3b.

Multiply those you get -6b^2.

Add up all your products from above.

9a^2+9ab+-6ab+-6b^2

There are like terms here.  The 9ab+-6ab which is 3ab.

So you can write your expression now as:

9a^2 + 3ab  +-6b^2

9a^2 +  3ab  - 6b^2

Step-by-step explanation:

[tex]\text{Use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd:\\\\(3a-2b)(3a+3b)\\\\=(3a)(3a)+(3a)(3b)+(-2b)(3a)+(-2b)(3b)\\\\=9a^2+9ab-6ab-6b^2\qquad\text{combine like terms}\\\\=9a^2+3ab-6b^2[/tex]

Ella can make 21 complete envelopes with her available red, white, and blue pages, since the number of complete sets is limited by the blue pages.

Ella has 48 red pages, 25 white pages, and 84 blue pages. She needs to put 2 red pages, 1 white page, and 4 blue pages in every envelope. To find out how many complete envelopes she can make, we need to calculate the number of complete sets of pages she can create based on the quantity of each color she has and the number she needs for each envelope.

For the red pages: 48 red pages / 2 pages per envelope = 24 envelopes

For the white pages: 25 white pages / 1 page per envelope = 25 envelopes

For the blue pages: 84 blue pages / 4 pages per envelope = 21 envelopes

Since the number of envelopes is limited by the color with the least amount of complete sets, Ella can make 21 complete envelopes because she will run out of blue pages after the 21st envelope.

Answer:

X is parallel to Z

X || Z

Step-by-step explanation:

This is called the transitive property.

It says something like:

If f is related to g and g is related to h, then f is related to h.

The parallel relationship is transitive.

That is,

if X is parallel to Y and Y is parallel to Z, then X is parallel to Z.

4x + 3y = -6

Step-by-step explanation:

Answer:

3x yrs old

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

Co terminal angles are angle ± 2π, that is

[tex]\frac{11\pi }{8}[/tex] + 2π

= [tex]\frac{11\pi }{8}[/tex] + [tex]\frac{16\pi }{8}[/tex] = [tex]\frac{27\pi }{8}[/tex]

and

[tex]\frac{11\pi }{8}[/tex] - 2π

= [tex]\frac{11\pi }{8}[/tex] - [tex]\frac{16\pi }{8}[/tex] = - [tex]\frac{5\pi }{8}[/tex]

An outside angle is equal to the sum of the two opposite inside angles.

The triangle has an outside angle of 98, it's two opposite inside angles are given as 32 and X.

To find X, subtract 32 from 98.

X = 98 - 32 = 66

The answer is B.

Answer:

B

Step-by-step explanation:

The angle on the circumference is half the angle subtended at the centre by the arc CB, that is

∠CAB = 0.5 × ∠COB = 0.5 × 96° = 48° → B

m∠CAB is 48° given that point O is the center of the circle and ∠COB is 96°. This can be obtained by using the circle theorem.

Given that, ∠COB = 96°

By applying Circle theorem, we can say that

                                 ∠COB = 2∠CAB

                                      96° = 2∠CAB

                                 ∠CAB = 96°/2 = 48°

                                 ∠CAB = 48°

Hence m∠CAB is 48° given that point O is the center of the circle and ∠COB is 96°.

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Answer:

128 units^3

Step-by-step explanation:

[tex]v = \frac{b \times b \times h}{3} = \\ = \frac{8 \times 8 \times 6}{3} = \\ = 128 \: {units}^{3} [/tex]

Step-by-step explanation:

base areas x height / 3

a^2 . h / 3

8^2 . 6 / 3

= 128 units^3

iyi ödevler

have a good lesson

Answer:

[tex]x^{4}[/tex]

Step-by-step explanation:

[tex]\frac{x^{5}y^{2}  }{xy^{2} }[/tex]

= [tex]x^{4}[/tex]

Question 1:

For this case we have the following expression:

[tex]\frac {x ^ 5y ^ 2} {xy ^ 2}[/tex]

We eliminate similar terms in the numerator and denominator:

[tex]\frac {x ^ 5} {x}[/tex]

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

[tex]\frac {x ^ 5} {x} = x ^ {5-1} = x ^ 4[/tex]

ANswer:

Option D

Question 2:

For this case we must indicate which expression is not equal to 125.

We tested option A:

[tex]5 (\frac {5 ^ 3} {\frac {2} {5}}) ^ 2 =[/tex]

Simplifying we have:

[tex]5 (\frac {5 ^ 3 * 5} {2}) ^ 2 =\\5 (\frac {5 ^ 8} {4}) =\\\frac {5 ^ 9} {4}[/tex]

The expression is not equal to 125.

Answer:

option A

Answer:

(5,-3) if the system is

y=x-8

2x+3y=1

Step-by-step explanation:

I think the system is to read:

y=x-8

2x+3y=1.

Please correct me if I'm wrong.

I'm going to plug 1st equation into 2nd equation giving me:

2x+3(x-8)=1      ->I replaced y with (x-8).

Distribute:

2x+3x-24=1

Combine like terms:

5x-24=1

Add 24 on both sides:

5x=25

Divide both sides by 5:

x=5

If y=x-8 and x=5, then y=5-8=-3.

The solution is (5,-3).

(5, −3) is the solution of given system of equations.

"It is a mathematical statement which consists of equal symbol between two algebraic expressions."

"It is set of equations for which we find a common solution."

"It is a method of solving system of equation we substitute the value of a variable found by one equation in the second equation."

For given question,

We have been given a system of equations.

y = x - 8                ..............(i)

2x + 3y = 1                 ...............(ii)

We use substitution method to solve given system of equations.

Substitute the value of y from (i) to equation (ii).

⇒ x + 3(x - 8) = 1

⇒ 2x + 3x - 24 = 1

⇒ 5x = 1 + 24

⇒ 5x = 25

⇒ x = 5

Substitute above value of x in an equation (i)

⇒ y = 5 - 8

⇒ y = -3

So, the solution of given system of equations is x = 5 and y = -3

Therefore (5, -3) is the solution of given system of equations.

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Answer:

[tex]\large\boxed{\dfrac{(2x^3y)^3}{(4xy^2)^2(xy^3)}=\dfrac{x^6}{2y^4}}[/tex]

Step-by-step explanation:

[tex]\dfrac{(2x^3y)^3}{(4xy^2)^2(xy^3)}\qquad\text{use}\ (ab)^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{2^3(x^3)^3y^3}{4^2x^2(y^2)^2xy^3}\qquad\text{cancel}\ y^3\\\\=\dfrac{8x^{(3)(3)}y^3\!\!\!\!\!\diagup}{16x^2y^{(2)(2)}xy^3\!\!\!\!\!\diagup}\\\\=\dfrac{8\!\!\!\!\diagup^1x^9}{16\!\!\!\!\!\diagup_2x^2y^4x}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=\dfrac{x^9}{2x^{2+1}y^4}\\\\=\dfrac{x^9}{2x^3y^4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\dfrac{x^{9-3}}{2y^4}\\\\=\dfrac{x^6}{2y^4}[/tex]

Answer:

The product is 25

Step-by-step explanation:

we know that

The complex number z1 is equal to

z1=(-4-3i)

we know that

To find the complex conjugate of (-4 - 3i) we change the sign of the imaginary part

so

The conjugate is equal to (-4+3i)

therefore

[tex](-4-3i)(-4+3i)=16-9(-1)=25[/tex]

Answer:

[tex](-4-3i) (- 4 + 3i) = 25[/tex]

Step-by-step explanation:

Notice in the graph that z1 has a real component of -4 and an imaginary component of -3.

Then we know that:

[tex]z_1 = -4-3i[/tex]

By definition for an imaginary number of the form [tex]a-bi[/tex] its conjugate will always be the number [tex]a + bi[/tex]

So the conjugate of [tex]z_1[/tex] is:

[tex]-4 + 3i[/tex]

The product of both numbers is:

[tex](-4-3i) (- 4 + 3i) = 16-12i + 12i-9i ^ 2\\\\(-4-3i) (- 4 + 3i) = 16-9 (-1)\\\\(-4-3i) (- 4 + 3i) = 16 + 9\\\\(-4-3i) (- 4 + 3i) = 25[/tex]

Step-by-step explanation and answer:

The given equations P=2T=3Q can be split up into

P=2T..................(1)

P=3Q................(2)

since they are all equal.

Rewrite the given equation

3Q + 4T = 26  .............(3)

as

3Q + 2(2T) = 26  ...........(4)

and substitute (1) and (2) into (4)

P + 2(P) = 26 .................(5)

Multiply (5) by two to get

6P = 2*26 = 52   ..............(6)

as given.

Answer:

see explanation

Step-by-step explanation:

Given P = 2T = 3Q, then

3Q + 4T = 26 can be expressed as

P + 2P = 26

3P = 26 ( multiply both sides by 2 )

6P = 52 ← as required

Answer:

309

Step-by-step explanation:

(2x-)^5

step 1

1 5 10 10 5 1

step 2

1(2x¹-3^0) 5(2x²-3^5) 10(2x³-3^4)

10(2x^4-3³) 5(2x^5-3²)

1(2x^0-3¹)

step 3

(2x) (10x²-243) (20x³-81) (20x^4-27)

(10x^5-9) (2-3)

step 4

2 -243-61-7 +1 -1=309

The coefficient of [tex]x^3[/tex] in the expansion of [tex](2x-3)^5[/tex] is 720

The correct answer is an option (E)

"It refers to a number or quantity placed with a variable."

"The alphabetic character that expresses a numerical value."

"It is a mathematical expression which consists of numbers, variables and mathematical operations."

" [tex](a-b)^3=a^3-3a^2b+3ab^2- b^3[/tex] "

" [tex](a-b)^2=a^2-2ab+b^2[/tex] "

For given question,

We have been given an expression [tex](2x-3)^5[/tex]

We need to expand given expression.

[tex](2x-3)^5\\\\= (2x-3)^3\times (2x-3)^2\\\\=[(2x)^3-3(2x)^23+3(2x)(3)^2- 3^3]\times ((2x)^2-2(2x)(3)+3^2)\\\\=[8x^3-36x^2+54x-27]\times [4x^2-12x+9]\\\\=-243+810x-1080x^2 +720x^3-240x^4+32x^5\\\\=32x^5-240x^4+720x^3-1080x^2+810x-243[/tex]

Therefore, the coefficient of [tex]x^3[/tex] in the expansion of [tex](2x-3)^5[/tex] is 720

The correct answer is an option (E)

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(10х — 4х2) - (7х + ?) = 3х – 6х2

10x - 7x = 3x which is given,

Now you have -4x^2 - ? needs to equal -6x^2

write it as an equation:

-4x^2 - ? = -6x^2

To solve for ? add 4x^2 to each side:

-? = -2x^2

Multiply each side by -1:

? = 2x^2

Answer:

12

Step-by-step explanation:

[tex]\frac{Parts of Water}{Parts of Concentrate} =3[/tex]

3/1=3

9/3=3

36/12=3

Answer:

4

Step-by-step explanation:

6/7 divided by 3/14​ is 4.

Find common denominators.

6/7 would be changed into 12/14.

3/14 would stay the same because its denominator is already 14.

12/3 = 4

Therefore, 6/7 divided by 3/14​ is 4.

Answer:

The answer is 4

Step number one use the butterfly method:

6 14

-- ×---- =84/21

7 3

Step 2: Divide since it's improper

84÷21=4

4 21

-- × --- =4

1 21

Answer:

x^4+100x^2-5x^2-500=0

x^2(x^2+100)-5(x^2+100)=0

(x^2+100)(x^2-5)=0

from first expression

x^2+100=0

x^2=-100

x= root under -100

Therefore x=-10

from next expression

x^2-5=0

x^2=5

Or x=2.23

Step-by-step explanation:

Answer:

x = ± sqrt(5)

x = ±10i

Step-by-step explanation:

x^4+ 95x^2-500=0

What two numbers multiply to -500 and add to 95

-5 * 100 = -500

-5 +100 = 95

(x^2 - 5) (x^2 + 100) = 0

Using the zero product property

x^2 -5 =0          x^2 +100 =0

x^2 -5+5 =0      x^2 +100-100 = 0-100

x^2 =5               x^2 = -100

Take the square root of each side

x = ± sqrt(5)       x = imaginary numbers

                           x = ±10i

Answer:

[tex]y=\frac{1}{2}x-6[/tex]

Step-by-step explanation:

The general equation of a line: [tex]y = ax+b[/tex]

In our case a is given

[tex]a=\frac{1}{2}[/tex]

Now we plug in for a and we get:

[tex]y=\frac{1}{2}*x+b[/tex]

Now we plug in our coordinates into this equation and we solve for b

[tex]-3=\frac{1}{2}*6+b\\b = -6[/tex]

So the equation of the line is [tex]y=\frac{1}{2}x-6[/tex]

Answer:

[tex]y=\frac{1}{2}x-6[/tex]

Step-by-step explanation:

Since the Inclination of the line was already given to us. Let us use Inclination of line formula:

[tex]m=\frac{y-y_0}{x-x_0}[/tex]

Plugging it in those values then we have the equation of the line:

[tex]\frac{1}{2}=\frac{y+3}{x-6}[/tex]

Rewriting, multiplying both sides

2y+6=x-6

2y=x-12 Rearranging

[tex]y=\frac{1}{2}x-6[/tex]

For this case we have the following function:

[tex]y = 5-x[/tex]

We look for the points of intersection with the x axis, doing y = 0

[tex]0 = 5-x\\x = 5[/tex]

We look for the points of intersection with the y axis, doing x = 0

[tex]y = 5-0\\y = 5[/tex]

We can also observe that the slope is -1.

[tex]y = mx + b\\y = -x + 5[/tex]

Answer:

See attached image

Answer:

[tex]f(g(x)) =\sqrt{6x^2-1}[/tex]

Step-by-step explanation:

Given

f(x) = √2x-5

and

g(x) = 3x^2+2

We have to find the composition of both function

f(g(x)) means that we have to put function g in place of x in function f.

[tex]f(g(x))= \sqrt{2*g(x)-5}\\ =\sqrt{2(3x^2+2)-5}\\=\sqrt{6x^2+4-5}\\=\sqrt{6x^2-1}[/tex]

..

The composite function f(g(x)) is given by f(g(x)) = √(6x^2 - 1).

To find the composite function f(g(x)), you need to substitute the expression for g(x) into the function f(x). Here's how you can do it step by step:

Start with the function g(x):

g(x) = 3x^2 + 2

Now, substitute this expression into the function f(x):

f(g(x)) = √(2(3x^2 + 2) - 5)

Simplify the expression inside the square root:

f(g(x)) = √(6x^2 + 4 - 5)

Further simplify the expression inside the square root:

f(g(x)) = √(6x^2 - 1)

So, the composite function f(g(x)) is given by:

f(g(x)) = √(6x^2 - 1)

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Find the ratio of the known sides and calculate X.

1. The smaller triangle is half the size of the lager one:

6/12 = 1/2

10/12 = 1/2

This means x is half the length of 16

x = 16/2 = 8

2.  18/30  = 3/5

     9/15 = 3/5

This means x is 3/5 of 25

x = 25 * 3/5 = 15

3. 32/24 = 1 1/3

   16 /12 = 1 1/3

X is 1 1/3 times the length of 21

x = 21 x 1 1/3

x = 28

4.  12/15 = 4/5

    20/25 = 4/5

x is 4/5 the length of 40

x = 40 * 4/5

x = 32

Answer:

20.6

Step-by-step explanation:

28.6×20.6=589.16

Answer:

20.6

Step-by-step explanation:

Area of a rectangle = base times height

A = bh

Substitute in what we know

589.16 = 28.6 * h

Divide each side by 28.6

589.16/28.6 = 28.6h/28.6

20.6=h

Answer:

the answer is D

Step-by-step explanation:

a is not it has a negative

a b is not it has an equation in it

so that leaves it to see and d c does not work

because it has to have two variables per one number

Answer:

(4,0)

Step-by-step explanation:

So we have the system:

-x+5y=-4

4x+4y=16

--------------

We are asked to solve this for elimination.

We aren't totally setup for elimination though.

Both equations are in the same form, the form being ax+by=c form, so we are good there.

Now the other requirement is one the columns that contain variables need to be opposites (you will add) or same (you will subtract).

I'm going to multiply the first equation by 4.  The reason I'm going to do this is because the first column will contain -4x and 4x.  Those are opposites.  When you add opposites, you get 0 (they cancel).

So applying the multiplication of 4 to first equation gives:

-4x+20y=-16

4x+   4y=16

----------------- Add the equations now.

0x+24y=0    Again this is called elimination, because we made it to where a                         variable is canceled when combining the equations.

0x+24y=0

0+ 24y=0

     24y=0

Divide both sides by 24:

         y=0

So using one of the equations (you only need one of them) along with the y=0, let's find x.

I'm going to go with -x+5y=-4 with y=0.

Plugging in the 0 for y gives us:

-x+5y  =-4

-x+5(0)=-4

-x+  0  =-4

-x        =-4

Multiply both sides by -1:

x        =4

The solution is (x,y)=(4,0).

ANSWER

The ordered pair is

(4,0)

EXPLANATION

To solve a simultaneous equation using the elimination method means making the coefficient of one of the variables the same. We then add or subtract to eliminate that variable.

The given system has equations:

[tex] - x + 5y = - 4...(1)[/tex]

[tex]4x + 4y = 16...(2)[/tex]

Divide the second equation by 4

[tex]x + y = 4...(3)[/tex]

Add equation (1) and (3) to eliminate x.

[tex] \implies \: 5y + y = - 4 + 4[/tex]

[tex] \implies \: 6y = 0[/tex]

[tex] \implies \: y = \frac{0}{6} = 0[/tex]

Put

[tex]y = 0[/tex]

into the first equation to get:

[tex] - x + 5 \times 0 = - 4[/tex]

[tex] - x = - 4[/tex]

[tex] \therefore \: x = 4[/tex]

The ordered pair is

(4,0)