Which of the following theorems verifies that ABC=SPR?
LOOK AT PICTURE

Answer:

A (-1,4,1.5)

Step-by-step explanation:

Solve by graphing, the lines intersect near this point.

Answer:

20 feet wide, 24 feet long

Step-by-step explanation:

Let x - width, y - length.

The perimeter is given by the formula:

P = 2*(width + length) or using x, y

P = 2*(x + y) = 88

x + y = 44

And we know that the ratio between the sides is 5/6:

x/y = 5/6. x is on top because the length is bigger than the width

x = 5y/6

Plug this in the first expression:

y + 5y/6 = 44. Muliply by 6

6y + 5y = 264

11y = 264

y = 264/11 = 24.

So x = 5(24)/6  = 20

Answer:

-10, -33, -125, -493, -1965

Step-by-step explanation:

a_1 = -10

a_n = 4a_(n - 1) + 7

The first five terms of the sequence are

a_1 =                                             -10

a_2 = 4(-10) + 7     =   -40 + 7 =    -33

a_3 = 4(-33) + 7    =  -132 + 7 =   -125

a_4 = 4(-125) + 7  = -500 + 7 =   -493

a_5 = 4(-473) + 7 = -1972 + 7 = -1965

Answer:

x=35

Step-by-step explanation:

We have the two angles (6x -82)  and (3x + 23) that are equal. To find 'x' we need to solve the system of equations:

6x -82 = 3x + 23

Solving for 'x':

3x = 105

x = 35

[tex]6x-82=3x+23\\3x=105\\x=35[/tex]

Answer: 1) (x - 7)(x - 8)

               2) 2x(2x-7)(x + 2)

               3) (4x + 7)²

               4) (9ab² - c³)(9ab² + c³)

Step-by-step explanation:

1) x² - 15x + 56  → use standard form for factoring

                    ∧

                -7 + -8 = -15

  (x - 7) (x - 8)

************************************

2) 4x³ - 6x² - 28x      → factor out the GCF (2x)

2x(2x² - 3x - 14)         → factor using grouping

2x[2x² + 4x    - 7x - 14]    

2x[ 2x(x + 2)   -7(x + 2)]

2x(2x - 7)(x + 2)

*************************************

3) 16x² + 56x + 49     → this is the sum of squares

√(16x²) = 4x      √(49) = 7

              (4x + 7)²

******************************************************

4) 81a²b⁴ - c⁶          → this is the difference of squares

√(81a²b⁴) = 9ab²       √(c⁶) = c³

       (9ab² - c³)(9ab² + c³)

Answer:

[tex]\boxed{\vphantom{\dfrac{\sqrt{2}}{2}}\quad \cos(x+y)\quad }\longleftrightarrow \boxed{\quad \dfrac{-(\sqrt{6}+\sqrt{2})}{4}\quad }[/tex]

[tex]\boxed{\vphantom{\dfrac{\sqrt{2}}{2}}\quad \sin(x+y)\quad }\longleftrightarrow \boxed{\quad\dfrac{\sqrt{6}-\sqrt{2}}{4}\quad }[/tex]

[tex]\boxed{\quad \tan(x+y)\quad }\longleftrightarrow \boxed{\quad\sqrt{3} -2\quad }[/tex]

[tex]\boxed{\vphantom{\sqrt{3}}\quad \tan(x-y)\quad }\longleftrightarrow \boxed{\quad-(2+\sqrt{3})\quad }[/tex]

Step-by-step explanation:

To find the values of the given trigonometric identities, we first need to find the values of cos x and sin y using the Pythagorean identity, sin²x + cos²x ≡ 1.

Given values:

[tex]\sin x = \dfrac{\sqrt{2}}{2}\qquad \textsf{Angle $x$ is in Quadrant I}\\\\\\\cos y=-\dfrac{1}{2}\qquad \textsf{Angle $y$ is in Quadrant II}[/tex]

Find cos(x):

[tex]\sin^2 x+\cos^2 x=1\\\\\\\left(\dfrac{\sqrt{2}}{2}\right)^2+\cos^2 x=1\\\\\\\dfrac{1}{2}+\cos^2 x=1\\\\\\\cos^2 x=1-\dfrac{1}{2}\\\\\\\cos^2 x=\dfrac{1}{2}\\\\\\\cos x=\pm \sqrt{\dfrac{1}{2}}\\\\\\\cos x=\pm \dfrac{\sqrt{2}}{2}[/tex]

As the cosine of an angle is positive in quadrant I, we take the positive square root:

[tex]\cos x=\dfrac{\sqrt{2}}{2}[/tex]

Find sin(y):

[tex]\sin^2 y + \cos^2 y = 1 \\\\\\ \sin^2 y + \left(-\dfrac{1}{2}\right)^2 = 1 \\\\\\ \sin^2 y + \dfrac{1}{4} = 1 \\\\\\ \sin^2 y = 1-\dfrac{1}{4} \\\\\\ \sin^2 y = \dfrac{3}{4} \\\\\\ \sin y =\pm \sqrt{ \dfrac{3}{4}} \\\\\\ \sin y = \pm \dfrac{\sqrt{3}}{2}[/tex]

As the sine of an angle is positive in quadrant II, we take the positive square root:

[tex]\sin y = \dfrac{\sqrt{3}}{2}[/tex]

The tangent of an angle is the ratio of the sine and cosine of that angle. Therefore:

[tex]\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}=1[/tex]

[tex]\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}}=-\sqrt{3}[/tex]

Now, we can use find the sum or difference of two angles by substituting the values of sin(x), cos(x), sin(y), cos(y), tan(x) and tan(y) into the corresponding formulas.

[tex]\dotfill[/tex]

[tex]\cos(x+y)=\cos x \cos y - \sin x \sin y \\\\\\ \cos(x+y)=\left(\dfrac{\sqrt{2}}{2}\right) \left(-\dfrac{1}{2}\right) - \left(\dfrac{\sqrt{2}}{2}\right) \left(\dfrac{\sqrt{3}}{2}\right) \\\\\\ \cos(x+y)=-\dfrac{\sqrt{2}}{4} - \dfrac{\sqrt{6}}{4} \\\\\\ \cos(x+y)=\dfrac{-\sqrt{2}-\sqrt{6}}{4} \\\\\\ \cos(x+y)=\dfrac{-(\sqrt{2}+\sqrt{6})}{4} \\\\\\ \cos(x+y)=\dfrac{-(\sqrt{6}+\sqrt{2})}{4}[/tex]

[tex]\dotfill[/tex]

[tex]\sin(x+y)=\sin x \cos y + \cos x \sin y \\\\\\\sin(x+y)=\left(\dfrac{\sqrt{2}}{2}\right) \left(-\dfrac{1}{2}\right) + \left(\dfrac{\sqrt{2}}{2}\right) \left(\dfrac{\sqrt{3}}{2}\right) \\\\\\\sin(x+y)=-\dfrac{\sqrt{2}}{4} + \dfrac{\sqrt{6}}{4} \\\\\\ \sin(x+y)=\dfrac{-\sqrt{2}+\sqrt{6}}{4} \\\\\\ \sin(x+y)=\dfrac{\sqrt{6}-\sqrt{2}}{4}[/tex]

[tex]\dotfill[/tex]

[tex]\tan(x+y)=\dfrac{\tan x + \tan y}{1-\tan x \tan y} \\\\\\ \tan(x+y)=\dfrac{1 + (-\sqrt{3})}{1-(1) (-\sqrt{3})} \\\\\\ \tan(x+y)=\dfrac{1 -\sqrt{3}}{1+\sqrt{3}} \\\\\\ \tan(x+y)=\dfrac{(1 -\sqrt{3})(1 -\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})} \\\\\\ \tan(x+y)=\dfrac{1-2\sqrt{3}+3}{1-\sqrt{3}+\sqrt{3}-3} \\\\\\ \tan(x+y)=\dfrac{4-2\sqrt{3}}{-2} \\\\\\ \tan(x+y)=-2+\sqsrt{3} \\\\\\ \tan(x+y)=\sqrt{3} -2[/tex]

[tex]\dotfill[/tex]

[tex]\tan(x-y)=\dfrac{\tan x - \tan y}{1+\tan x \tan y} \\\\\\\tan(x-y)=\dfrac{1 - (-\sqrt{3})}{1+(1) (-\sqrt{3})} \\\\\\\tan(x-y)=\dfrac{1 +\sqrt{3}}{1-\sqrt{3}} \\\\\\\tan(x-y)=\dfrac{(1 +\sqrt{3})(1 +\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})} \\\\\\ \tan(x-y)=\dfrac{1+2\sqrt{3}+3}{1+\sqrt{3}-\sqrt{3}-3} \\\\\\ \tan(x-y)=\dfrac{4+2\sqrt{3}}{-2} \\\\\\ \tan(x-y)=-2-\sqrt{3}\\\\\\\tan(x-y)=-(2+\sqrt{3})[/tex]

Answer:

[tex]\large\boxed{f(x)=5x}[/tex]

Step-by-step explanation:

[tex]\begin{array}{c|c}x&f(x)\\1&5\\2&10\\3&15\end{array}\\\\\\f(1)=5(1)=5\\f(2)=5(2)=10\\f(3)=5(3)=15\\\Downarrow\\f(x)=5x[/tex]

Answer:

The correct answer is option D.  13

Step-by-step explanation:

From the figure we can see two matrices A and B

To find the sum of a₃₂ and b₃₂

From the given attached figure we get

a₃₂ means that the third row second column element in the matrix A

b₃₂ means that the third row second column element in the matrix B

a₃₂ = 4 and b₃₂ = 9

a₃₂ + b₃₂ = 4 + 9

 = 13

The correct answer is option D.  13

[tex]A={\begin{bmatrix}a_{11}&a_{12}&\cdots &a_{1n}\\a_{21}&a_{22}&\cdots &a_{2n}\\\vdots &\vdots &\ddots &\vdots \\a_{m1}&a_{m2}&\cdots &a_{mn}\end{bmatrix}}[/tex]

So

[tex]a_{32}=4\\b_{32}=9\\\\a_{32}+b_{32}=4+9=13[/tex]

Answer: Option A

[tex]x=\frac{3+i}{2}[/tex] or [tex]x=\frac{3-i}{2}[/tex]

Step-by-step explanation:

Use the quadratic formula to find the zeros of the function.

For a function of the form

[tex]ax ^ 2 + bx + c = 0[/tex]

The quadratic formula is:

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

In this case the function is:

[tex]2x^2-6x+5=0[/tex]

So

[tex]a=2\\b=-6\\c=5[/tex]

Then using the quadratic formula we have that:

[tex]x=\frac{-(-6)\±\sqrt{(-6)^2-4(2)(5)}}{2(2)}[/tex]

[tex]x=\frac{6\±\sqrt{36-40}}{4}[/tex]

[tex]x=\frac{6\±\sqrt{-4}}{4}[/tex]

Remember that [tex]\sqrt{-1}=i[/tex]

[tex]x=\frac{6\±\sqrt{4}*\sqrt{-1}}{4}[/tex]

[tex]x=\frac{6\±\sqrt{4}i}{4}[/tex]

[tex]x=\frac{6\±2i}{4}[/tex]

[tex]x=\frac{3\±i}{2}[/tex]

[tex]x=\frac{3+i}{2}[/tex] or [tex]x=\frac{3-i}{2}[/tex]

Answer:

Step-by-step explanation:

Divide 4378 by 15

From 4378 lets take the first two digits for division:

43/ 15

We know that 43 does not come in table of 15

So we will take 15 *2 = 30

43-30 = 13

The quotient is 3 and the remainder is 13

Now take one more number which is 7 with 13

137/15.

Now 137 does not come in table of 15

15*9 = 135

135-137 = 2

It means quotient is 9 and remainder is 2

Now take one more number which is 8 with 2

28/15

28 does not come in table of 15

15*1 = 15

28-15 = 13/15

Now the quotient is 1 and remainder is 13

Hence, the quotient of 4,378 is 291 and remainder is 13 ....

The given quadratic equation x² - 4x = -7 is rearranged into standard form and then solved using the quadratic formula -b ± √(b² - 4ac) / (2a). The roots of the equation are realized from solving this formula.

The subject of this problem is a quadratic equation in the form of ax²+bx+c = 0. The given equation is x² - 4x = -7, which can be rearranged into standard form as x² - 4x + 7 = 0. Thus, in this case, a=1, b=-4, and c=7.

The solutions or roots for this quadratic equation can be calculated using the quadratic formula, which is -b ± √(b² - 4ac) / (2a). Substituting the values of a, b, and c into the formula will give the roots of the given equation.

Doing that, we get: x = [4 ± √((-4)² - 4*1*7)] / (2*1)

The values that solve the equation are the roots of the quadratic equation.

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To solve the equation x^2 - 4x = -7 using the Quadratic Formula, we follow the steps of plugging the values of a, b, and c into the formula, evaluating the square root and simplifying to find the solutions.

To solve the equation x2 - 4x = -7 using the Quadratic Formula, we first need to make sure the equation is in standard form, which is ax2 + bx + c = 0. In this case, a = 1, b = -4, and c = 7. Plugging these values into the Quadratic Formula, we get:

x = (-(-4) ± √((-4)2 - 4(1)(-7))) / (2(1))

x = (4 ± √(16 + 28))/2

x = (4 ± √44)/2

x = (4 ± 2√11)/2

x = 2 ± √11

So the solutions to the equation x2 - 4x = -7 are x = 2 + √11 and x = 2 - √11.

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Final answer:

Isabel's ride rotates 60° every two seconds. It takes 6 intervals (360° divided by 60°) to make a full rotation. Multiplying 6 intervals by 2 seconds gives us 12 seconds for Isabel to return to the starting position.

Explanation:

To determine how many seconds will pass before Isabel returns to her starting position on the ride, we need to establish the total degrees of rotation that equate to a full circle, which is 360°. Since the ride rotates 60° every two seconds, we can calculate the number of two-second intervals required to complete a full 360° rotation.

Firstly, divide 360° by 60° to find the number of intervals:

360° / 60° = 6 intervals

Since each interval takes 2 seconds, multiply the number of intervals by 2 to find the total time:

6 intervals × 2 seconds/interval = 12 seconds.

Therefore, it will take Isabel 12 seconds to return to her starting position on the amusement park ride.

Answer:

Part A) Annual [tex]\$66,480.95[/tex]  

Part B) Semiannual [tex]\$66,862.38[/tex]  

Part C) Monthly [tex]\$67,195.44[/tex]  

Part D) Daily [tex]\$67,261.54[/tex]  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

Part A)

Annual

in this problem we have  

[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=1[/tex]  

substitute in the formula above  

[tex]A=47,400(1+\frac{0.07}{1})^{1*5}[/tex]  

[tex]A=47,400(1.07)^{5}[/tex]  

[tex]A=\$66,480.95[/tex]  

Part B)

Semiannual

in this problem we have  

[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=2[/tex]  

substitute in the formula above  

[tex]A=47,400(1+\frac{0.07}{2})^{2*5}[/tex]  

[tex]A=47,400(1.035)^{10}[/tex]  

[tex]A=\$66,862.38[/tex]  

Part C)

Monthly

in this problem we have  

[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=12[/tex]  

substitute in the formula above  

[tex]A=47,400(1+\frac{0.07}{12})^{12*5}[/tex]  

[tex]A=47,400(1.0058)^{60}[/tex]  

[tex]A=\$67,195.44[/tex]  

Part D)

Daily

in this problem we have  

[tex]t=5\ years\\ P=\$47,400\\ r=0.07\\n=365[/tex]  

substitute in the formula above  

[tex]A=47,400(1+\frac{0.07}{365})^{365*5}[/tex]  

[tex]A=47,400(1.0002)^{1,825}[/tex]  

[tex]A=\$67,261.54[/tex]  

The value of an investment of $47,400 at an interest rate of 7% per year was calculated at the end of 5 years for different compounding methods, reaching slightly different amounts, with the highest value obtained through daily compounding.

The value of the investment at the end of 5 years for different compounding methods would be:

Answer:

y - 21 = 3(x - 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 3 and (a, b) = (5, 21), hence

y - 21 = 3(x - 5) ← in point- slope form

The point slope form of an equation is y - y1 = m(x - x1). Substituting the given point (5,21) and slope 3 into the equation, we get y - 21 = 3(x - 5). To remove the parenthesis on the y side, we simplify the equation to be y = 3x + 6.

The question asks for the writing of a point-slope equation of a line with a given slope of 3 that passes through a point (5,21). The point-slope form of an equation is generally denoted as:

y - y1 = m(x - x1)

Here, (x1, y1) = (5,21) and m (slope) = 3. Hence, substituting these values yields the equation:

y - 21 = 3(x - 5)

The asked equation without parenthesis on the y side would be:

y = 3x - 15 + 21

So, the final equation is:

y = 3x + 6

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Answer:

y=-(x-3)^2+2

Step-by-step explanation:

since the curve is convex up so the coefficient of x^2 is negative

and by substituting by the point 3 so y = 2

Answer:

B

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (3, 2), hence

y = a(x - 3)² + 2

If a > 0 then vertex is a minimum

If a < 0 then vertex os a maximum

From the graph the vertex is a maximum hence a < 0

let a = - 1, then

y = - (x - 3)² + 2 → B

Answer:

3(2x+3)=-3(-30+4)

6x+9=90+12

6x+9=102

6x=93

x=15.5

-please mark as brainliest-

Answer:

11½ = x

Step-by-step explanation:

6x + 9 = 78

- 9 - 9

-------------

6x = 69 [Divide by 6]

x = 11½ [3⁄6 = ½]

I hope this helps you out, and as always, I am joyous to assist anyone at any time.

Answer:

A

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile, that is

interquartile range = [tex]Q_{3}[/tex] - [tex]Q_{1}[/tex]

The interquartile range (IQR) represents the spread of the middle 50 percent of a data set and is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). It also helps in identifying potential outliers in the data.

The interquartile range (IQR) is a measure of statistical dispersion, which is the spread of the middle 50 percent of a data set. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). To elaborate:

If, for example, Q1 is 2 and Q3 is 9, the IQR is calculated as 9 minus 2, resulting in an IQR of 7.

In addition to providing insight into the spread of the central portion of the data set, the IQR can also be used to identify potential outliers. These are values that fall more than 1.5 times the IQR above Q3 or below Q1.

Answer: (1.5, -5)

Step-by-step explanation: a p e x

Answer: B

Step-by-step explanation:

Division of components are consistent  - the same

Answer:

B. -3, 3, -3, 3...

Step-by-step explanation:

There's two types of sequences, arithmetic and geometric.

Arithmetic equations are sequences that increase or decrease by adding or subtracting the previous number.

For example, take a look at the following sequence:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20...

Here, the numbers are increasing by +2. [adding]

So, this the sequence is arithmetic, since its adding.

Geometric sequences are sequences that increase or decrease by multiplying or dividing the previous number.

For example, take a look at the following sequence:

2, 4, 16, 32, 64, 128, 256, 512...

Here, the numbers are icnreasing by x2. [multiplying]

So, the sequence is geometric since its multiplying.

Based on this information, the correct answer is "B. -3, 3, -3, 3..." since its being multiplyed by -1.

Answer:

5

Step-by-step explanation:

16+24

--------------

30-22

Complete the items on the top of the fraction bar

40

----------

30-22

Then the items under the fraction bar

40

------------

8

Then divide

5

Step-by-step explanation:

First of all, solve the numerator.

16+24=40

Secondly, solve the denominator:

30-22 = 8

So now the fraction appear like this :

[tex] \frac{40}{8} [/tex]

40/8 = 5

Answer:

Hey, You have chosen the correct answer.

the correct answer is C.

Answer:

f(x)=-3x+4

(can't see some of your choices)

Step-by-step explanation:

We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.

So we need to solve for y.

9x+3y=12

Subtract 9x on both sides

     3y=-9x+12

Divide both sides by 3:

     y=-3x+4

Replace y with f(x).

    f(x)=-3x+4

Answer:

[tex]1,207.6\ m[/tex]

Step-by-step explanation:

step 1

Find the perimeter of one lap

we know that

The perimeter of one lap is equal to the circumference of a complete circle (two half circles is equal to one circle) plus two times the length of 96 meters

so

[tex]P=\pi D+2(96)[/tex]

we have

[tex]D=35\ m[/tex]

[tex]\pi =3.14[/tex]

substitute

[tex]P=(3.14)(35)+2(96)[/tex]

[tex]P=301.9\ m[/tex]

step 2

Find the total meters of four laps

Multiply the perimeter of one lap by four

[tex]P=301.9(4)=1,207.6\ m[/tex]

Answer:

1207.6

Step-by-step explanation:

step 1

i got it right on the test

step 2

you get it right on the test

Answer:

[tex] D.~ 34.2~cm^2 [/tex]

Step-by-step explanation:

An arc measure of 20 degrees corresponds to a central angle of 20 degrees.

Area of sector of circle

[tex] area = \dfrac{n}{360^\circ}\pi r^2 [/tex]

where n = central angle of circle, and r = radius

[tex] area = \dfrac{20^\circ}{360^\circ}\pi (14~cm)^2 [/tex]

[tex] area = \dfrac{1}{18}(3.14159)(196~cm^2) [/tex]

[tex] area = 34.2~cm^2 [/tex]

Answer:

5/9

Step-by-step explanation:

y = 15 • 3^x

Let x = -3

y = 15 • 3^(-3)

The negative means the exponent goes to the denominator

y = 15 * 1/3^3

  = 15 * 1/27

  =15/27

Divide the top and bottom by 3

 =5/9

Answer:

OPTION B.

OPTION C.

Step-by-step explanation:

In order to know which numbers are less than [tex]\frac{9}{4}[/tex], you can convert this fraction into a decimal number. To do this, you need to divide the numerator 9 by the denominator 4. Then:

 [tex]\frac{9}{4}=2.25[/tex]

 Now you need convert the fractions provided in the Options A and B into decimal numbers by applying the same procedure. This are:

Option A→ [tex]\frac{11}{4}=2.75[/tex] (It is not less than 2.25)

Option B→ [tex]\frac{15}{8}=1.875[/tex] (It is less than 2.25)

The number shown in Option C is already expressed in decimal form:

Option C→ [tex]2.201[/tex] (It is less than 2.25)

Answer:

9

Step-by-step explanation:

From the diagram:

So, correct option is 9 cases.

Answer:

The correct option is 4. For value 9 both p ∧ r true and q false.

Step-by-step explanation:

The diagram represents three statements: p, q, and r.

We need to find the value for which p ∧ r is true and q false.

p ∧ r true mean the intersection of statement p and r. It other words p ∧ r true means p is true and r is also true.

From the given venn diagram it is clear that the intersection of p and r is

[tex]p\cap r=9+2=11[/tex]

p ∧ r true and q false means intersection of p and r but q is not included.

From the given figure it is clear that for value 2 all three statements are true. So, the value for which both p ∧ r true and q false is

[tex]11-2=9[/tex]

Therefore the correct option is 4.

Answer:

V = 3053.63

Step-by-step explanation:

The volume of a sphere that has a radius of 9 is 3053.63.

V=4

3πr3=4

3·π·93≈3053.62806

Answer is provided in the image attached.

Answer:

7t^2 + 21t

Step-by-step explanation:

You have 7 tiles of each t by t+3.

One tile has an area of

t * (t+3) = t^2 + 3t

So in total the area is

7* (t^2 + 3t)

7t^2 + 21t

Answer:

The coordinates are  (4 , -2) , (0 , -5) , (-2 , -2) , (2 , 1)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) rotated about the origin by angle 180°

 ∴ Its image is (-x , -y)

- If the point (x , y) translated horizontally to the right by h units

 ∴ Its image is (x + h , y)

- If the point (x , y) translated horizontally to the left by h units

 ∴ Its image is (x - h , y)

- If the point (x , y) translated vertically up by k units

 ∴ Its image is (x , y + k)

- If the point (x , y) translated vertically down by k units

 ∴ Its image is (x , y - k)

* Now lets solve the problem

∵ ABCD is a parallelogram

∵ Its vertices are A (1 , 1) , B (5 , 4) , C (7 , 1) , D (3 , -2)

∵ The parallelogram rotates about the origin by 180°

∵ The image of the point (x , y) after rotation 180° about the origin

   is (-x , -y)

∴ The images of the vertices of the parallelograms are

  (-1 , -1) , (-5 , -4) , (-7 , -1) , (-3 , 2)

∵ The parallelogram translate after the rotation 5 units to the right

   and 1 unit down

∴ We will add each x-coordinates by 5 and subtract each

   y-coordinates by 1

∴ A' = (-1 + 5 , -1 - 1) = (4 , -2)

∴ B' = (-5 + 5 , -4 - 1) = (0 , -5)

∴ C' = (-7 + 5 , -1 - 1) = (-2 , -2)

∴ D' = (-3 + 5 , 2 - 1) = (2 , 1)

* The coordinates of the parallelograms A'B'C'D' are:

  (4 , -2) , (0 , -5) , (-2 , -2) , (2 , 1)