Reaction of option c produces precipitate.
Rhodium on reacting with potassium phosphate produces rhodium phosphate which remain in solution due to low lattice energy for rhodium phosphate.
Niobium on reacting with lithium carbonate produces niobium carbonate and it will remain in aqueous form.
Cobalt on reacting with zinc nitrate produces cobalt nitrate. This, Co(NO3 )2 is insoluble precipitate and settles at bottom whereas zinc ion will remain in solution as follows:
[tex]Co^2^+ + Zn(NO¬_3 )¬_2 Co(NO¬_3 )¬_2 + Zn^2^+[/tex]
Potassium ion on reacting with sodium sulfide produces potassium sulfide which remain in solution
Final answer:
Among the given options, mixing a) Rh³⁺(aq) with K₃PO₄(aq) will produce a precipitate, RhPO₄, since most phosphates are insoluble except those of alkali metals and ammonium.
Explanation:
The question asks which of the following mixtures will produce a precipitate. To determine this, we need to apply knowledge of solubility rules. Precipitates form when products of a chemical reaction are insoluble in water.
a) Rh³⁺(aq) with K₃PO₄(aq): This combination will produce a precipitate of RhPO₄, as phosphates, except those of alkali metals (like sodium and potassium) and ammonium, are generally insoluble.
b) Nb³⁺(aq) + Li₂CO₃ (aq): Niobates are not common, but considering that most carbonates are insoluble except those of alkali metals which Li is, no precipitate is expected here.
c) Co₂⁺(aq) + Zn(NO₃)₂ (aq): Neither of these will produce a precipitate as all nitrates are soluble, and no insoluble compound is formed.
d) K⁺(aq) + Na₂S (aq): This will not produce a precipitate because sulfides of alkali metals are soluble in water.
Therefore, the correct answer is a) Rh³⁺(aq) + K₃PO₄(aq), which will lead to the formation of a precipitate, RhPO₄.
Choose all the answers that apply
If the earth were
Larger the weight of the atmosphere would be crushing
Closer to the sun all the water on earth would evaporate
Farther away from the sun all it’s water would freeze
Smaller the atmosphere would float away
the first and second answers i hope this helps :3
What do elements in thr first two columns of the periodic table have in common?
Picking up a hot coal is an example of what type of heat transfer?
Conduction
Convection
Radiation
Transmission
conduction: Conduction is how heat transfers through direct contact with objects that are touching.
A chemistry student combines 32 grams of one chemical and an unknown amount of another chemical in a closed system. A chemical reaction occurs and the mass of the products is 114 grams. How much of the unknown chemical was used in the reaction?
The reaction used 82 g of the unknown chemical.
The word equation is
Chemical 1 + Chemical 2 → Products
32 g + x g → 114 g
The Law of Conservation of Mass tells us the total mass of the reactants must equal the mass of the products. Then
32 g + x g = 114 g
x = 114 – 32 = 82
The mass of Chemical 2 was 82 g.
2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)
In the equation, if 14 L of ethane (C2H6) and 14 L of oxygen (O2) combined and burned to completion, which gas will be leftover after the reaction, and what is the volume of that gas remaining
In the given chemical reaction, if equal volumes of ethane ([tex]C_{2} H_{6}[/tex]) and oxygen ([tex]O_{2}[/tex]) are combined, ethane will be the gas left over after the reaction due to its larger required volume of oxygen for complete combustion. The exact volume of ethane remaining can be calculated using stoichiometry and the proportions of the balanced equation.
Explanation:The balanced chemical reaction is
[tex]\[2C_2H_6(g) + 7O_2(g) \rightarrow 4CO_2(g) + 6H_2O(g)\][/tex]This implies that 2 moles of ethane [tex]C_{2} H_{6}[/tex] react with 7 moles of oxygen([tex]O_{2}[/tex]) to produce carbon dioxide ([tex]CO_{2}[/tex]) and water ([tex]H_{2} O[/tex]) by the process of combustion. As per Avogardo's law, the volume of gases is directly proportional to the number of moles, when the conditions (pressure, temperature) are kept constant.
Since you are starting with equal volumes of ethane and oxygen (14 L), and since ethane requires more oxygen to react (3.5 volumes of oxygen for each volume of ethane), there will not be enough oxygen present to react with all of ethane. Thus, it will be ethane ([tex]C_{2} H_{6}[/tex]) gas that is leftover after the reaction. The volume of that gas remaining can be calculated using stoichiometry and the proportions of the balanced equation.
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An object will _____ if the weight of the liquid displaced is less than the weight of the object.
I am not exactly sure the answer that you are looking for, but I will guess on what you might be looking for. If the weight of an object is greater than the weight of the liquid it's being put into, the object will sink. Although, it isn't necessarily just based upon weight, it is more dependent on density to decide if it'll float or sink.
Answer:
It will sink
Explanation:
Hi, this is the result of the Archimedes principle, that states that the push force an object receives from the liquid it is submerged in, is proportional to the volume it displace.
As can be seen in the figure, there are two opposite forces interacting, the weight of the object (P) and the push force (E).
If P is higher than E the object will sinkIf P is lower than E the object will floatIf they are equal the object will be in submerged in equilibrium.In equations:
[tex]P=m*g[/tex] where g is gravity
[tex]E=\rho_{liq}*V_{liq}*g[/tex]
Also [tex]\rho_{liq}*V_{liq}=m_{liq}[/tex]
So: [tex]\frac{P}{E}=\frac{m*g}{m_{liq}*g}[/tex]
[tex]\frac{P}{E}=\frac{m}{m_{liq}}[/tex]
If m is higher than m_liq, it means that P is higher than E and the object will sink.
A sample of NaNO3 was fully decomposed into its elements, and the resulting gas was collected over water at 34°C. If the total pressure of the collected gas was 760 torr, and the vapor pressure of water at 34°C is 40.0 torr, what was the partial pressure of N2 gas in the flask?
The partial pressure of N2 gas in the flask, after subtracting the vapor pressure of water from the total pressure, is 720 torr.
To determine the partial pressure of N2 gas collected over water, we must subtract the vapor pressure of water from the total pressure of the collected gas according to Dalton's law of partial pressures. Given that the total pressure is 760 torr and the vapor pressure of water at 34°C is 40.0 torr, we can perform the following calculation:
Total pressure = Partial pressure of N2 + Vapor pressure of water .
Therefore, Partial pressure of N2 = Total pressure - Vapor pressure of water
Partial pressure of N2 = 760 torr - 40.0 torr
Partial pressure of N2 = 720 torr
The partial pressure of N2 gas in the flask is 720 torr.
The partial pressure of N2 gas in the flask is 720 torr.
To find the partial pressure of N2 gas, we need to subtract the vapor pressure of water from the total pressure of the collected gas. The total pressure is given as 760 torr, and the vapor pressure of water at 34°C is 40.0 torr.
The partial pressure of a gas in a mixture is calculated using Dalton's Law of Partial Pressures, which states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas. Mathematically, this can be expressed as:
[tex]\[ P_{\text{total}} = P_{\text{gas 1}} + P_{\text{gas 2}} + \ldots + P_{\text{gas }n} \][/tex]
where [tex]\( P_{\text{total}} \)[/tex] is the total pressure and [tex]\( P_{\text{gas }i} \)[/tex] is the partial pressure of the i-th gas.
In this case, the total pressure [tex]\( P_{\text{total}} \)[/tex] is 760 torr, and it is composed of the partial pressure of N2 gas [tex]\( P_{\text{N2}} \)[/tex] and the vapor pressure of water [tex]\( P_{\text{H2O}} \)[/tex]:
[tex]\[ P_{\text{total}} = P_{\text{N2}} + P_{\text{H2O}} \][/tex]
We can rearrange this equation to solve for [tex]\( P_{\text{N2}} \)[/tex]:
[tex]\[ P_{\text{N2}} = P_{\text{total}} - P_{\text{H2O}} \][/tex]
Substituting the given values:
[tex]\[ P_{\text{N2}} = 760 \text{ torr} - 40.0 \text{ torr} \] \[ P_{\text{N2}} = 720 \text{ torr} \][/tex]
Therefore, the partial pressure of N2 gas in the flask is 720 torr.
Which are examples of equilibrium? Check all that apply. Water drips out of a faucet and down a drain. A person's income and expenses are equal every month. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere. The temperature of a metal increases as heat is added to it.
The equilibrium means that amount that are coming equals the amount that are going.
So the correct answers are
2. A person's income and expenses are equal every month.
3. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.
-Hiadamcom/From Agarvated
Answer:
A person's income and expenses are equal every month.
The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.
Explanation:
In equilibrium there is balance always.
Option A is incorrect. Equilibrium would be maintained if the water that falls out of the faucet is re-entered into the faucet.
Option B is correct. As the income and expense of the person is equal, so what the person spends is equal to what he earns. So the person neither spends more than his income goes to debt nor does the person has some money left after his spending to save or invest.
Option C is correct. As the pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere, the balloon does not burst. The air pressure is balanced on either side of the balloon.
Option D is incorrect. Equilibrium would be maintained if the heat gained is equal to the heat lost.
Mass number is equal to the _____.
A. Average atomic mass
B. Number of protons + number of electrons
C. Number of protons + number of neutrons
D. Number of neutrons + number of electrons
Please answer, Will give BRAINIEST
Answer:
Number of protons + neutrons
ANSWER C
Draw the optically active stereoisomer(s) of 1,3-cyclopentanediol.
The three possible stereoisomers of 1,3-cyclopentanediol are as follow,
i) (1S,3R)-1,3-Cyclopentanediol
ii) (1R,3R)-1,3-Cyclopentanediol
iii) (1S,3S)-1,3-Cyclopentanediol
Structures of all three compounds are attached below.
Explanation:Stereoisomers: Also known as spatial isomers are those isomers which have same molecular formula and structural formula but the groups about the chiral center occupy different orientation in space.
Enantiomers: These are stereoisomers of each other which are non-identical mirror-images of each other.
Diastereomers: These are stereoisomers which are not mirror images of each other.
Meso Compounds: These are those isomers which are superimposible on its mirror image.
Given the following data:
N2(g)2NO(g)++O2(g)O2(g)2N2O(g)→→→2NO(g),2NO2(g),2N2(g)+O2(g),ΔH=+180.7kJΔH=−113.1kJΔH=−163.2kJ
use Hess's law to calculate ΔH for the following reaction:
N2O(g)+NO2(g)→3NO(g)
Answer is: enthalpy is 155.65 kJ.
Reaction 1: N₂(g) + O₂(g) → 2NO(g); ΔrH₁ = 180.7 kJ.
Reaction 2: 2NO(g) + O₂(g) → 2NO₂(g); ΔrH₂ = -113.1 kJ.
Reaction 3: 2N₂O → 2N₂(g) + O₂(g); ∆rH₃ = -163.2 kJ.
Reaction 4: N₂O(g) + NO₂(g) → 3NO(g); ΔrH₄ = ?.
Using Hess's law reaction number 4 is sum of reaction number 1 and half of reaction number 3 minus half of the reaction number 2.
ΔrH₄ = ΔrH₁ + 1/2ΔrH₃ - 1/2ΔrH₂.
ΔrH₄ = 180.7 kJ + 1/2 · (-163.2 kJ) - 1/2 · (-113.1 kJ).
ΔrH₄ = 155.65 kJ.
Hess's law states that the enthalpy change in the chemical reaction is same, whether the reaction takes place in one or several steps. For the given equation, the enthalpy change of overall reaction is 155. 65 kJ.
[tex]\begin{aligned}\text{N}_2(\text{g})2\text{NO}(\text{g})+\text{O}_2(\text{g})\text{O}_2(\text{g})2\text{N}_2\text{O}(\text{g})\rightarrow2\text{NO}(\text{g}),2\text{NO}_2(\text{g}),2\text{N}_2(\text{g})+\text{O}_2(\text{g})\end{aligned}[/tex]
Given that,
1. The enthalpy change for the reaction between nitrogen and oxygen to form nitrogen oxide is:
[tex]\begin{aligned}\text{N}_2(\text{g})+\text{O}_2(\text{g})\rightarrow2\text{NO}(\text{g});\Delta\text{rH}_1&=180.7\text{kJ}\end{aligned}[/tex]2. The enthalpy change in the reaction between nitrogen oxide and oxygen to form nitrogen dioxide will be:
[tex]\begin{aligned}2\text{NO}(\text{g})+\text{O}_2(\text{g})\rightarrow2\text{NO}_2(\text{g});\Delta\text{rH}_2&=-113.1\text{kJ}\end{aligned}[/tex]3. The enthalpy change in breakdown of nitrous oxide to form nitrogen and oxygen:
[tex]\begin{aligned}2\text{N}_2\text{O}\rightarrow2\text{N}_2(\text{g})+\text{O}_2(\text{g});\Delta\text{rH}_3&=-163.2\text{kJ}\end{aligned}[/tex]4. The reaction between nitrous oxide and nitrogen dioxide will from nitrogen oxide as:
[tex]\begin{aligned}\text{N}_2\text{O}(\text{g})+\text{NO}_2(\text{g})\rightarrow3\text{NO}(\text{g});\Delta\text{rH}_4&=?\end{aligned}[/tex]Using Hess's law on the fourth reaction, we get sum of first reaction and halved the enthalpy change of second and third reaction.
[tex]\begin{aligned}\Delta\text{rH}_4&=\Delta\text{rH}_1+\frac{1}{2}\Delta\text{rH}_3-\frac{1}{2}\Delta\text{rH}_2\\&=180.7\text{kJ}+\frac{1}{2}\times(-163.2\text{kJ})-\frac{1}{2}\times(-113.1\text{kJ})\\&=155.65\text{kJ}\end{aligned}[/tex]
Therefore, the enthalpy change for the equation will be 155.65 kJ.
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A plane travel for about 2.5 hours at a velocity of 1200 km/hr east. What distance did it travel?
We multiply the two numbers 2.5 and 1200 because thats the distance you went every hour and it equals 3000km
The study of numbers is called mathematics.
The correct answer is 3000km.
What is the formula used?The formula used to solve the question is of distance that is distance = speed * timeAll the data is given in the question, the data is as follows:-
Time - 2.5 hoursspeed- 1200kmPlaced all the values in the formula. the solution is as follows:-
[tex]D =S*T\\= 1200*2.5\\=3000km[/tex]
Hence, the correct answer is 3000km.
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What is the frequency, in hertz, of an electromagnetic wave with a wavelength of 625 nm?
Answer:- Frequency is [tex]4.80*10^1^4Hz[/tex] .
Solution:- The wavelength of electromagnetic radiation is given as 625 nm and we are asked to calculate the frequency. Frequency is inversely proportional to the wavelength and the formula used to calculate frequency when wavelength is given is:
[tex]\nu =\frac{c}{\lambda }[/tex]
where, [tex]\nu [/tex] is frequency, c is speed of light and [tex]\lambda [/tex] is the wavelength.
Value of speed of light is [tex]\frac{3.0*10^8m}{s}[/tex] . We need to convert the given wavelength from nm to m.
[tex]1nm=10^-^9m[/tex]
So, [tex]625nm(\frac{10^-^9m}{1nm})[/tex]
= [tex]6.25*10^-^7m[/tex]
Let's plug in the values in the formula and calculate the frequency:
[tex]\nu =\frac{3.0*10^8m.s^-^1}{6.25*10^-^7m}[/tex]
= [tex]4.80*10^1^4s^-^1[/tex] or Hz.
So, the frequency of the electromagnetic wave is [tex]4.80*10^1^4Hz[/tex] .
The frequency of an electromagnetic wave with a wavelength of 625 nm is [tex]\boxed{4.8 \times 10^{14} \text{ Hz}}.[/tex]
To find the frequency of an electromagnetic wave, one can use the relationship between the speed of light (c), the frequency (f), and the wavelength (\lambda), which is given by the equation:
[tex]\[ c = f \lambda \][/tex]
The speed of light in a vacuum is approximately [tex]\( 3 \times 10^8 \)[/tex]meters per second (m/s). Since the wavelength is given in nanometers (nm), we need to convert it to meters to match the units of the speed of light. There are [tex]\( 10^9 \)[/tex] nanometers in a meter, so a wavelength of 625 nm is:
[tex]\[ \lambda = 625 \text{ nm} \times \frac{1 \text{ m}}{10^9 \text{ nm}} = 625 \times 10^{-9} \text{ m} \][/tex]
Now we can rearrange the equation [tex]\( c = f \lambda \)[/tex] to solve for the frequency (f):
[tex]\[ f = \frac{c}{\lambda} \][/tex]
Substituting the values for c and \lambda:
[tex]\[ f = \frac{3 \times 10^8 \text{ m/s}}{625 \times 10^{-9} \text{ m}} \][/tex]
[tex]\[ f = \frac{3}{625} \times 10^{14} \text{ Hz} \][/tex]
[tex]\[ f = 4.8 \times 10^{14} \text{ Hz} \][/tex]
Therefore, the frequency of the electromagnetic wave is[tex]( 4.8 \times 10^{14} \) hertz.[/tex]
The half life of a certain radioactive element is 800 years. How old is an object if only 12.5% of the radioactive atoms in it remains?
Given, half life of a certain radioactive element = 800 years.
Amount of substance remaining at time t = 12.5%
Lets consider the initial amount of the radioactive substance = 100%
Using the half life equation:
A = A₀(1/2)^t/t₁/₂
where A₀ is the amount of radioactive substance at time zero and A is the amount of radioactive substance at time t, and t₁/₂ is the half-life of the radioactive substance.
Plugging the given data into the half life equation we have,
12.5 = 100 . (1/2)^t/800
12.5/100 = (1/2)^t/800
0.125 = (0.5)^t/800
(0.5)^3 = (0.5)^t/800
3 = t/800
t = 2400 years
Thus the object is 2400 years old.
The age of the object can be calculated using the given half-life and the percentage of remaining atoms which is 2888.8 years
Explanation:The half-life of a radioactive element is the time it takes for half of its radioactive atoms to decay, transforming into a stable form. It's a fundamental concept in nuclear physics and radiometric dating, used to estimate the age of rocks and archaeological artifacts. The half-life of a radioactive element is the time it takes for half of its nuclei to decay. If only 12.5% of the radioactive atoms remain, it means that 87.5% of the atoms have decayed. Using the given half-life of 800 years, we can calculate the age of the object by finding the number of half-lives it would take for 87.5% decay:
Age of half-lives = log2(87.5%) ≈ 3.61
Age of the object = 3.61 x 800 years = 2888.8 years
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Copper is a metal that is used for many purposes. It is mined from the earth using various methods. Though the amount of copper in the Earth's crust is very large, if the mining of copper continues, it will eventually run out.
Jim thinks that conserving copper is important, and says that the best way to do this would be to stop all copper mining at once. Is there a problem with this solution?
A. no, it is a good solution as any.
B. yes, there is no need to conserve copper.
C. no, we must conserve copper no matter what.
D. yes, the need to conserve copper must be balanced with use
Answer:
the answer is d
Explanation:
Answer: Option (D) is the correct answer.
Explanation:
When we use an object or substance in excess then it is likely that the substance will run out with time. But at the same time, if we use that substance according to its requirement and try to conserve it as much as we can then we can preserve the substance.
Hence, it is good to avoid wastage of a substance and balance its use according to the need.
Therefore, we can conclude that in the given situation yes, there is a problem with the solution as the need to conserve copper must be balanced with use.
Which is a better conductor of heat: air or a copper wire? Why?
Copper wire
Metal is one of best conductors for heat
Balanced Chemical Equation: 2H2(g)+O2(g)——> 2H2O(g)
How many grams of O2 are needed to produce 118 g of H2O if the reaction has a 78.2 % yield?
You must use 134 g O₂ to produce 118 g H₂O.
[tex]\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \%[/tex]
[tex]\text{Theoretical yield} = \text{Actual yield}\times \frac{100\%}{\%\text{ yield}} = \text{118 g }\times \frac{100 \%}{78.2 \%} = \text{150.9 g}[/tex]
M_r: 32.00 18.02
2H₂ + O₂ ⟶ 2H₂O
Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O
Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂
Mass of O₂ = 4.1877 mol O₂ × (32.00 g O₂/1 mol O₂) = 134 g O₂
Condors are related to vultures and feed on carrion, or dead animals.
A condor’s role in the food web is as a _____.
It's "Scavenger."
What is the equation you use to determine the momentum of an object
The terms of a equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity
determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
[tex]n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}[/tex]
where [tex]N_A = 6.02 \times 10^{23}\; \text{mol}^{-1}[/tex] the Avogadro's constant that relates the number of particles to their number, in the unit moles [tex]\text{mol}[/tex].
The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.
[tex]M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}[/tex]
[tex]8.6 \times 10^{-3} \; \text{mol}[/tex] of propanol molecules would thus have a mass of [tex]8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}[/tex]
How can the concept of density be used to differentiate between a genuine diamond and an imitation diamond
Explanation: Genuine diamonds and imitation diamonds are different in terms of their strengths.
Strength is directly related to the density of the molecule.
High density means the molecule is hard as there will be no voids and the particles are closer to each other.
Lower density means that the molecule is soft because there will be voids present and the particles will be away from each other.
Genuine diamonds are hard in nature and hence they have high density while imitation diamonds can be broken down easily and hence they have has lower density.
What is the strongest intermolecular force that occurs between molecules in CO2?
a. Dipole-dipole
b. Induced dipoles
c. Ionic bonding
d. London dispersion
Answer:- d. London dispersion
Explanations:- Carbon dioxide structure is given below:
O=C=O
It has two polar C=O bonds but even then it is non polar molecule as it's linear and the dipole moment of one C=O bond is canceled by it's opposite C=O bond.
being non polar, the only attraction forces present in it are London dispersion forces.
Answer:
d. London dispersion
Carbon dioxide is derived from the reaction between Carbon and Oxygen and the structure is as shown below:
O=C=O
The only intermolecular force found in carbon dioxide is the London dispersion forces and they are forces which are caused by electron movement which forms dipoles.
Carbondioxide has two polar C=O bonds in which the dipoles are cancelled out thereby making it a non polar compound. This non-polarity is what makes the only force present to be the London dispersion forces and can also be regarded as the strongest intermoelcular bond found in the compound (CO₂)
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While visiting the Grand Canyon, you observe the exposed layers of rock on the valley. What natural process most likely caused the valley to form? Deposition Chemical weathering Oxidation Erosion
Erosion caused the grand canyon to form
This would be either chemical weathering or erosion.
See, the rock was broken down and cracked by any sort of weathering or erosion. It could've been caused by either one of those, honestly.
Have a great day :)
a rough guide to fluid requirements based on body weight is 100mL/kg for the first 10kg of body weight, 50mL/kg for the next 10kg, and 20mL/kg for weight over 20kg. What volume of fluid per day is needed by a 55kg woman? give answer to 2 significant figures
Given, weight of the woman = 55 kg
For the first 10 kg, fluid required is 100 mL/kg
So for the first 10 kg volume of fluid required is 100 ml/kg x 10 kg = 1000 ml = 1 L
For the second 10 kg, fluid required is 50 mL/kg
So for the second 10 kg volume of fluid required is 50 ml/kg x 10 kg = 500 ml = 0.5 L
For the remaining (55 kg - 20 kg ) or 35 kg, fluid required is 20mL/kg
Now for the the remaining 35 kg volume of fluid required is 20 ml/kg x 35 kg = 700 ml = 0.7 L
The total volume of fluid per day required by a 55 kg woman = 1L + 0.5L + 0.7L = 2.2 L
The volume of fluid per day needed by a 55kg woman, based on the given guide to fluid requirements, is 1000mL for the first 10kg, 500mL for the next 10kg, and 700mL for the remaining weight, totaling 2200mL or 2.2 liters per day when rounded to two significant figures.
To calculate the volume of fluid per day needed by a 55kg woman based on the rough guide to fluid requirements, we use the following method:
For the first 10kg of body weight: 100mL/kg.
For the next 10kg of body weight: 50mL/kg.
For the remaining weight over 20kg: 20mL/kg.
So for a 55kg woman:
For the first 10kg: 10kg x 100mL/kg = 1000mL
For the next 10kg: 10kg x 50mL/kg = 500mL
For the remaining 35kg: 35kg x 20mL/kg = 700mL
Therefore, the total fluid requirement is 1000mL + 500mL + 700mL = 2200mL, which rounded to two significant figures is 2200mL or 2.2 liters per day.
Why is the collision theory considered to be well-established and highly reliable?
Collision theory is reliable because it gives a repeatable measure for predicting necessary conditions for reactions, is supported by extensive experimental data, and aligns with scientific principles, only offering limitations when relativistic speeds are involved.
Collision theory is considered well-established and highly reliable because it provides a repeatable measure for predicting the conditions necessary for chemical reactions. These conditions typically include the energy threshold that reacting particles must overcome known as activation energy, and the proper orientation during collisions. This theory is supported by numerous experiments, and no experiment has so far contradicted its postulates. As with the transition from hypothesis to theory in scientific disciplines, collision theory's predictions have been consistently validated by experimental data, making it reliable in the study of reaction rates and mechanisms. It should be noted that the application of collision theory is restricted to non-relativistic speeds, as at relativistic velocities encountered in particle physics, relativistic mechanics would be necessary for correct analysis.
Furthermore, the theory's ability to generalize across various types of collisions, provided we stay in one dimension and minimize external influences such as friction, adds to its dependability. However, in practical applications, especially regarding high-energy collisions between particles like in particle accelerators, adjustments are made to account for the relativistic speeds.
What will happen to density of urine when a diabetic excretes too much sugar ?
The density of urine decreases when a diabetic secretes too much sugar.
When there is excess sugar in the blood, the kidneys release extra water.
The result is a more dilute and therefore less dense urine.
The urine from a non-diabetic person usually has a density of 1.010 g/mL to 1.025 g/mL.
The urine from a diabetic person often has a density less than 1.008 g/mL.
How many Valence electrons does Li have?
It has a single valence electron.
3pro & 3ele - it is the single electron in shell 2.
Li has 1 valence electron
The process by which hot and cold air are transferred in the atmosphere is
Convection: the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.
hope that helps :)
(6.022*10^23)*2.58=
what’s the answer
Answer:
The answer is 1.55 × 1024 on edg.
Explanation:
number with fewer significant figures.
what has 20 electrons in 44 Mass
It would be Calcium: Ca
We can tell which atom has 20 electrons by looking on the periodic table. If we look at number 20 (the atomic number shows how many electrons and protons an atom has) it is Calcium (symbol Ca).