Which of these are minerals? Select all that apply

A) mica

B) quartz

C) steam

D) copper

changing electric field gives a changing magnetc field ... can calculate energy using Poynting vector

Answer:

[tex]25L[/tex]

Explanation:

The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:

[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]

Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.

We want to know the initial volume, this is:

[tex]V_{1}=\frac{P_{2}V_{2}}{P_{1}}[/tex]

we also know from the problem that

[tex]P_{1}=4atm\\P_{2}=0.2atm\\V_{2}=500L[/tex]

Thus, the initial volume V1 is:

[tex]V_{1}=\frac{0.2atm*500L}{4atm}[/tex]

[tex]V_{1}=25L[/tex]

Answer:

Downstream, the current is helping the swimmer go faster relative to the land.

Explanation:

As shown in the figure the resultant vector is the addition of velocity of water and velocity of swimmer.

This shows that the swimmer is in the direction along the flow of the current. Thus, answer is downwards, the current is helping the swimmer go faster relative to the land.

The appropriate unit of measurement for pitch is mel.

There are several definitions of 'pitch', but I think you mean how 'high' or 'low' a sound sounds to our ear.  

If that's it, then you're talking about the frequency of the sound, and the unit is 'vibrations per second' or 'Hertz' (Hz) .

When an object is having variable velocity then we can use the definition of acceleration to find it that rate of change in velocity is known as acceleration.

We can define it as

[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]

here

[tex]v_f[/tex] = final velocity

[tex]v_i[/tex] = initial velocity

[tex]\Delta t[/tex] = time interval

now it is given here that final velocity is less than initial velocity after some time which means

[tex]v_f < v_i[/tex]

so here we can say acceleration will have negative value which shows it is opposite to the direction of velocity.

So this is the case of decreasing velocity which is known as deceleration.

So correct answer is

deceleration

Answer: the lattice contains 1 magnesium ion for every 2 fluoride ions.

[tex]MgF_2[/tex]  is an ionic compound. It contains positive ions of Magnesium and  and negative ions of Fluorine. To balance the +2 positive charge of one magnesium ion, two (-1) negatively charged Fluorine ions are present. Hence, The correct interpretation of [tex]MgF_2[/tex]  is that the lattice contains 1 Magnesium ion for every 2 Fluoride ions.

The person is exerting an equal force of 150 N against the crate, as per Newton's Third Law of Motion, meaning the force exerted by the person is equal to the normal force of 150 N.

To determine how much force a person is currently exerting to lift a crate with a mass of 30 kg, given the normal force supplied by the floor is 150 N, we need to consider the equal and opposite force applied by the person. According to Newton's Third Law of Motion, if the normal force acting upward from the floor is 150 N, then the person must be exerting an equal amount of force in the opposite direction, which would also be 150 N in order to maintain static equilibrium (assuming no other vertical forces are acting on the system, such as acceleration or additional weights).

Answer:

It must be moving at a constant speed

Explanation:

When an object move in a circular path, its motion is called uniform circular motion. The object moves with constant speed but the direction always changes. We know that the rate of change of velocity is called acceleration of the object.

In circular motion, the centripetal acceleration act towards the center of circle. The force acting on the object is called centripetal force. It is given by :

[tex]F_c=\dfrac{mv^2}{r}[/tex]

Hence, the statement that is true about an object to be in uniform circular motion is (C) " It must be moving at a constant speed".

The following must be true about an object for it to be in uniform circular motion C. It must be moving at a constant speed.

In uniform circular motion, an object travels in a circular path at a constant speed, but its velocity is not constant because the direction of the velocity is constantly changing.

The centripetal acceleration is directed toward the center of the circle and is responsible for keeping the object in its circular path, but the object's speed remains unchanged.

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car starts from rest

[tex]v_i = 0[/tex]

final speed attained by the car is

[tex]v_f = 5 m/s[/tex]

acceleration of the car will be

[tex]a = 3.6 m/s^2[/tex]

now the time to reach this final speed will be

[tex]t = \frac{v_f - v_i}{a}[/tex]

[tex]t = \frac{5 - 0}{3.6}[/tex]

[tex]t = 1.39 s[/tex]

so it required 1.39 s to reach this final speed

To calculate the time to reach 5 m/s from rest with an acceleration of 3.6 [tex]m/s^2[/tex], the kinematic equation v = u + at is used, where u is zero. Solving for t gives 1.39 seconds.

The question asks about the time it takes for a car to reach a certain speed given a constant acceleration, which falls under the subject of Physics.

To find the time required for the car to attain a speed of 5 m/s from rest with an acceleration of 3.6 [tex]m/s^2[/tex], you use the kinematic equation:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the car starts from rest, the initial velocity u is 0, and we can rearrange the formula to solve for time:

t = (v - u) / a

Plugging in the given values:

t = (5 m/s - 0 m/s) / 3.6 [tex]m/s^2[/tex] t = 5 / 3.6 t = 1.39 seconds

Thus, the car needs approximately 1.39 seconds to accelerate to 5 m/s.

D, all notebooks would hit the floor at the same time. The time it takes to hit the floor is independent of their weight, but rather dependent on the acceleration of gravity. Since gravity is constant, they will all hit the floor at the same time.

the correct answer would be D because they all have the same gravitational pull

A

the unit used for measuring both work and energy is the joule

✿━━━━@♥ℳg━━━━✿

[tex]\boxed{Explained\:Answer}[/tex]

______________________________

✿━━━━@♥ℳg━━━━✿

What is the unit used for measuring both work and energy?

A) joule✔✔

B) Newton

C) Pascal

D) meter

The mower will go approximately 1.163 meters before stopping.

To determine the distance the mower will go before stopping, we need to calculate the deceleration first. We can use Newton's second law of motion: F = ma. The net external force (F) is the force exerted by the person minus the frictional force, which is 51 N - 24 N = 27 N. The mass of the mower (m) is 22 kg. Rearranging the formula, we get: a = F/m = 27 N / 22 kg = 1.227 m/s².

Then, using the equation v² = u² + 2as, where v is the final velocity (0 m/s when the mower stops), u is the initial velocity (1.5 m/s), a is the deceleration (-1.227 m/s²), and s is the distance we're trying to find. Rearranging the equation, we get: s = (v² - u²) / (2a) = (0 - (1.5)²) / (2 * (-1.227)) = 1.163 m.

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The lawn mower will travel approximately 0.955 meters before stopping.

To find out how far the lawn mower will travel before stopping, we need to use the principles of physics, specifically the concepts of friction and linear motion. Here’s the step-by-step method:

Therefore, the lawn mower will travel approximately 0.955 meters before coming to a stop.

Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is

[tex]v_1 =548 mph[/tex] along the x-direction

[tex]v_2 = 343 mph[/tex] in a direction [tex]67^{\circ}[/tex] north of east.

To find the resultant, we must resolve both vectors on the x- and y- axis:

[tex]v_{1x}= 548 mph[/tex]

[tex]v_{1y}=0[/tex]

[tex]v_{2x} = (343 mph)( cos 67^{\circ})=134.0 mph[/tex]

[tex]v_{2y} = (343 mph)( sin 67^{\circ})=315.7 mph[/tex]

So, the components of the resultant velocity in the two directions are

[tex]v_{x}=548 mph+134 mph=682 mph[/tex]

[tex]v_{y}=0 mph+315.7 mph=315.7 mph[/tex]

So the new speed of the aircraft is:

[tex]v=\sqrt{v_x^2+v_y^2}=\sqrt{(682 mph)^2+(315.7 mph)^2}=751.5 mph[/tex]

The new speed of the aircraft with respect to the ground, taking into account the wind speed and direction, is approximately 744.91 mph.

To solve this problem, you should first break the wind's velocity into its eastward (x-component) and northward (y-component) using trigonometry. The eastward component is 343 mph x cos(67) = 134.87 mph, and the northward component is 343 mph x  sin(67) = 313.37 mph.

Now, you can add the eastward component of the wind speed to the initial speed of the jet airliner (548 mph + 134.87 mph = 682.87 mph). The northward component of the wind's speed remains the same (313.37 mph) since the plane was initially moving only eastwards with no northwards component.

The new speed of the aircraft with respect to the ground (or resultant velocity) can be found using Pythagoras' theorem: √[(682.87)^2 + (313.37)^2] = 744.91 mph.

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A great, helpful, useful definition of acceleration is

A = (change in speed) / (time for the change) .   <== you should memorize this

This simple tool will directly solve all 3 problems.

The REASON for assigning these problems for homework is NOT to find the answers.  It's to help YOU find out whether you know this definition, to let you go back and review it if you don't, and to give you a chance to practice using it if you do.  Noticed that if you get the answers from somebody else, you lose all of these benefits.

The only wrinkle anywhere here is in #3, because when you use this definition,      the unit of time has to be the same in both the numerator and the denominator.  

So for #3, you have to EITHER  change the km/hr to km/sec, OR change the 4sec to a fraction of an hour, before you plug anything into the definition.

It has to be D because the arrow will drop as it moves, if it were a gun, you'd lead the target so fire below it, but due to it being an arrow, you aim high not low. Also, they didnt specify how fast anything is, so you'd probably miss if you actually did it.

Answer:

C. directly at the initial position of the object

Explanation:

As we know that archer wants to hit the target at a given position but at the same time when archer shot the arrow the the target is also dropped under gravity

So here the arrow will move simultaneously in two directions

a) horizontal motion with uniform speed

b) motion under gravity

so here the arrow will move under gravity and drops the same distance in same time as that the target will drop due to gravity

so here the motion of arrow will hit the target if the archer initial shot at the initial position of the target

odour = gas suggesting molecular rearrangement ... chem change

A change in odor can indicate a chemical change has occurred. Examples include the oxidation of iron in myoglobin when cooking red meat and a banana turning brown.

A change in odor can indicate a chemical change has occurred. Examples of reactions that result in a change in odor include the oxidation of iron in myoglobin when cooking red meat, which causes a red-to-brown color change and change in smell. Another example is a banana turning brown, where new, darker substances form and the odor changes. These changes in odor are indicators that chemical reactions have taken place.

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i believe it would be the same because time doesn't matter when calculating total work done.

Work=FxD

F=force

D=distance

Final answer:

The scenario that requires more work is when the force applied is greater.

Explanation:

Work is defined as the product of force and displacement.

The work done on an object is given by the formula: work = force × distance × cosine(θ), where θ is the angle between the force and displacement vectors.

In this case, both objects are lifted through the same distance. Therefore, the work done on each object is equal to the force applied to lift the object multiplied by the distance lifted.

The time taken to lift the object does not affect the work done.

So, the scenario that requires more work is when the force applied is greater.

From among the choices provided, the better choice is the upper-case letter 'T '.  That symbol can conveniently be used to represent the words "true" or "truth", which is exactly the reason that it is the better choice for a response, since the complicated statement at the beginning of the question is completely true in its every detail, nuance, jot and tittle.  

Answer:

it is true my child

Explanation:

Answer: Earth

Explanation:

Answer:

the correct answer on E2020 is A.) a field pointing in two directions.

Electric field lines can never cross. The crossed electric field lines indicate a field pointing in two directions. The correct option is A.

The field developed around a charge. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of another charge.

Electric field lines originate from positive end and terminate to the negative end of the magnet.

So, the crossed electric field lines indicate a field pointing in two directions.

Thus, the correct option is A.

Learn more about electric field.

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A hypothesis is a guess based off of previous dater or simply reasoning for the most logical outcome.

A theory is a statement that has evidence and facts supporting it but still has room for change or error.

A law is a proven statement that works in every possible case without exception and will never be disproved (unless it was wrongly named a law in the first place).

Gravitation, gravity won't work, it has to be gravitation

the answer is gravitation  :D

D. As the internal energy increases a substance would go from solid to a liquid.

hope this helps :)

Answer: Option (D) is the correct answer.

Explanation:

Internal energy is defined as the minimum amount of energy present within the molecules of a substance.

More is the internal energy within the molecules of a substance more will be the number of collisions between them.

As a results, the particles will move away from each other and this leads to change in state of matter from solid to liquid and liquid to gaseous state.

Thus, we can conclude that the relationship between the internal energy of a substance and its state of matter is that as the internal energy increases a substance would go from solid to a liquid.

my hypothesis is that If you drop a piece of buttered toast, it will land butter side down.

I tested it by dropping 10 pieces of buttered toast off the table and noted on which side it landed

It could be falsified cause I just made all of this up. In essence, it's like flipping a coin, 50/50 chance so I could say that 5 landed butter up and 5 landed butter down.

A scientific hypothesis, such as 'Plant growth is positively affected by the presence of light', must be testable and falsifiable. It is tested and potentially falsified through controlled experiments, where one group is exposed to the variable under question while the other is not. Science advances by testing and potentially disproving such hypotheses, never claiming absolute proof.

Example of a Scientific Hypothesis and Testing

A scientific hypothesis is a proposed explanation for a phenomenon that is testable and falsifiable. An example of a hypothesis could be: 'Plant growth is positively affected by the presence of light'. To test this hypothesis, you could conduct an experiment with two groups of plants: one group, the experimental group, would be exposed to light, while the control group would not. Plant growth can be measured over a period to determine the effect of light. The hypothesis would be falsified if the plants in darkness grew as well or better than the plants exposed to light.

Falsifiability

Falsifiability is a core principle in science, ensuring that hypotheses can be disproven. A non-falsifiable hypothesis, such as 'Red is a better color than blue', cannot be tested or disproven, and thus is not scientific. Falsifiable hypotheses contribute to the scientific method by ensuring that they can be subject to empirical testing. If ongoing tests and experiments consistently fail to disprove a hypothesis, it gains support as a valid explanation until potentially falsified by future research.

Since the Van de Graaff generator is given to behave like a point charge, we can use the equation for Electric Field, given as

[tex]E = \frac{kQ}{r^{2} }[/tex]

where, [tex]k = \frac{1}{4\pi ε₀}[/tex] = [tex]8.99 X 10^{9} \frac{Nm^{2} }{C^{2} }[/tex]

r is the distance between the generator and the test charge = 0.75 m

E is the magnitude of the Electric Field Strength = [tex]4.5 X 10^{5} N/C[/tex]

Rearranging the equation, making Q the subject of the formula, we have

[tex]Q = \frac{E.r^{2} }{k}[/tex]

Plugging in the numerical values and simplifying them gets us

[tex]Q = 0.2815 X 10^{-4} \\[/tex]

Thus, the charge on the Van de Graaff generator is 28.16 μC.

Answer:

Answer is 2.8 × 10-7 coulombs.

Night vision equipment detects infrared radiation.  Where it detects some, it paints the corresponding place on a screen with visible rays.

Let us list out what we know from the question.

Initial Velocity [tex]V_{i}  = 0[/tex] since the piton is 'dropped'.

Vertical Displacement of the piton D = 215 m

Acceleration due to gravity [tex]a = 9.8 m/s^{2}[/tex]

Final Velocity [tex]V_{f} = ?[/tex]

Using the equation, [tex]V^{2} _{f} = V^{2} _{i}  + 2aD[/tex] and plugging in the known values, we get

[tex]V^{2} _{f}  = 0^{2}  + 2(9.8)(215)[/tex]

Simplifying by taking square-root on both sides gives us [tex]V_{f} =  64.915 m/s[/tex]

Thus, the speed of the piton just before striking the ground is 65 m/s.

The speed of the piton just before striking the ground would be approximately 64.94 meters per second.

To determine the speed of the piton just before it strikes the ground, we can use the kinematic equation for an object in free fall under the influence of gravity, ignoring air resistance. The equation is:

[tex]\[ v = \sqrt{2gh} \][/tex]

Given:

- The mass of the piton (m) is [tex]\( 77.5 \, g \)[/tex] or [tex]\( 0.0775 \, kg \)[/tex] (since [tex]\( 1 \, g = 0.001 \, kg \))[/tex],

- The height (h) is 215 m.

We can plug these values into the equation:

[tex]\[ v = \sqrt{2 \times 9.81 \, m/s^2 \times 215 \, m} \] \[ v = \sqrt{2 \times 9.81 \times 215} \] \[ v = \sqrt{4217.7} \] \[ v \approx 64.94 \, m/s \][/tex]

mass of iron block given as

[tex]m_1 = 1.90 kg[/tex]

density of iron block is

[tex]\rho = 7860 kg/m^3[/tex]

now the volume of the iron piece is given as

[tex]V = \frac{m}{\rho}[/tex]

[tex]V = \frac{1.90}{7860} = 2.42* 10^{-4} m^3[/tex]

Now when this iron block is complete submerged in oil inside the beaker the buoyancy force on the iron block will be given as

[tex]F_b = \rho_L V g[/tex]

here we know that

[tex]\rho_L[/tex] = density of liquid = 916 kg/m^3

[tex]F_b = 916* 2.42 * 10^{-4} * 9.8[/tex]

[tex]F_b = 2.17 N[/tex]

Now for the reading of spring balance we can say the spring force and buoyancy force on the block will counter balance the weight of the block at equilibrium

[tex]F_s + F_b = mg[/tex]

[tex]F_s + 2.17 = 1.90* 9.8[/tex]

[tex]F_s = 16.45 N[/tex]

So reading of spring balance will be 16.45 N

Now for other scale which will read the normal force of the surface we can write that normal force on the container will balance weight of liquid + container and buoyancy force on block

[tex]F_n = F_g + F_b[/tex]

[tex]F_n = (1 + 2.50)*9.8 + 2.17[/tex]

[tex]F_n = 34.3 + 2.17 = 36.47 N[/tex]

So the other scale will read 36.47 N

To find the equilibrium readings of the beaker and spring scale, use Archimedes' principle and the concept of buoyancy.

In this question, we are given a beaker containing oil and a block of iron that is submerged in the oil. We need to find the equilibrium readings of both the beaker and the spring scale. To solve this problem, we can use Archimedes' principle and the concept of buoyancy.

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Because it's maybe the only color they see.

D. Weathering

The six steps of the rock cycle includes Weathering and Erosion, Transportation, Deposition, Compaction and Cementation. Metamorphism, Rock Melting.

Deposition is the process where rock particles sink at the rivers and become sediment.

Weathering is the process by which wind and water breaks down igneous, sedimentary, and metamorphic rocks. The process refers to large rocks broken down into smaller pieces and the broken off particles stay in the area.