Which of these is a product of photosynthesis and a requirement
for cellular respiration?
Select one:
sunlight
carbon dioxide
glucose
water

Answer:

3.91g

Explanation:

1. Use the equation mol = mass/Mr (Molecular Formula)

2. Use the information you have and put it into the formula 2.9/23 = 0.1260869565

3. Multiply 0.1260869565 by 62 (molecular formula of Na2O) - Formula rearranged to mass = mol × Molecular formula = 7.817391303

4. Divide by two to get two moles, as shown in the chemical equation

5. 3.9086956515

6. 3.91g to three significant figures

The solution which could be with 0.1 M NaOH is solution "C"

Explanation:

Answer:

Because of oxygen toxicity.

Explanation:

Oxygen toxicity.

Oxygen has been known to cause central nervous system (CNS) toxicity when the pressure gets higher. This toxicity can cause convulsions, and this can cause the diver to drown.

The current standard maximum safe oxygen working pressure is 1.4 atm ppO2. This is equal to 56.5m/185′ when breathing air (21% O2 / 79% N). Below that depth the fraction of oxygen in a breathing gas must be reduced, and in order to maintain this maximum pressure of 1.4 ppO2, Helium must be added.

Answer:

b

Explanation:

Answer:

HNO3 is nitric acid. NH3 is ammonia, NaCl is common salt. O is an atom of oxygen. No idea about remaining.

Answer:

HI and HNO3 are acids

Explanation:

Answer:

I'm not sure that is the full question can you show a picture or something?

the string of a bow and arrow is pulled tight with Elastic

The correct option is (c).

When the string of a bow and arrow is pulled tight, the energy stored in the string is primarily due to its deformation, which is a characteristic of elastic potential energy.

c. Elastic potential energy arises from the deformation of an object, such as stretching a spring or pulling a rubber band. When the string of the bow and arrow is pulled tight, it undergoes deformation, storing potential energy in the form of elastic potential energy. This energy is then released when the string is released, propelling the arrow forward.

a. Gravitational potential energy refers to the energy associated with an object's position in a gravitational field. While gravity does play a role in the bow and arrow system (as it affects the trajectory of the arrow), the energy stored in the string itself is not primarily gravitational potential energy.

b. Chemical potential energy refers to the energy stored in chemical bonds, which is released during a chemical reaction. The action of pulling the string tight does not involve any chemical reactions, so it is not chemical potential energy.

d. Electric potential energy refers to the energy stored in an electric field due to the position of charged particles. The energy stored in the string of a bow and arrow is not related to electric potential energy.

complete question given below:

The string of a bow and arrow is pulled tight with?

a.Gravitational

b.Chemical

c.Elastic

d.Electric

Answer:

Coal mining can compromised a lot of our resources one of it is the soil. It is because it eliminates the nutrients of the soil that can affect the vegetation, it destroys the wildlife and habitat. Also, it changes permanently the topography of the area mined.

Explanation:

edge 2020 just did it

One resource that is often compromised due to mining is water, as mining have significant effect on quality and quantity of water.

Resources are anything that can be used to satisfy a need or want. Resources can be natural, such as land, water, minerals, and wildlife, or they can be human made, such as tools, machines, buildings, and infrastructure.

Mining activities can have significant impacts on water quality and quantity, especially in areas with limited water resources or sensitive ecosystems.

Water can become contaminated by chemicals and heavy metals used in mining, such as cyanide, sulfuric acid, and mercury, which can have harmful effects on aquatic life and human health. Mining can also consume large amounts of water for processing and dust suppression, which can exacerbate water scarcity and competition with other users, such as agriculture and urban areas.

Therefore, mining can have significant impacts on water resources, which are essential for human health, ecosystem functioning, and economic development.

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Answer:

B pancreas, since the pancreas secretes insulin

Explanation:

Answer:

pancreas

Explanation:

Answer:

a is the correct answer

Explanation:

i just did this question and it said a was right

The number of moles of aluminum sulfate produced from the 5.8 moles of aluminum hydroxide and excess sulfuric acid is 2.9 moles.

The balanced chemical equation can be given as:

2 Al(OH)₃ + 3 H₂SO₄ [tex]\rightarrow[/tex] Al₂(SO₄)₃ + 6 H₂O

In the above reaction, the stoichiometry of the amounts of each compound participating in the reaction is:

Al(OH)₃ - 2 moles

H₂SO₄ -  3 moles

Al₂(SO₄)₃ - 1 mole

H₂O - 6 moles

From the above observation, it can be assumed that for every 2 moles of aluminum hydroxide produce 1 mole of aluminum sulfate.

Then, the number of moles produced by 5.8 moles of aluminum hydroxide is x.

[tex]\text{moles of Al}_{2} (\text{SO}_{4} ){3} =\dfrac{\text{5.8moles of Al(OH)}_{3} \times \text {1 mole of Al}_{2} (\text {SO}_{4} ){3}}{\text {2moles of Al(OH)}_{3}}[/tex]

Thus, 2.9 moles of aluminum hydroxide will be produced from the 5.8 moles of aluminum hydroxide.

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265

Explanation:

660 divided by 2.5 equals 265. The frequency is 265.

Answer:

132Hz

Explanation:

the explanation is in the picture

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Electrons have a negative charge and orbit around the nucleus, while protons have a positive charge and are found in the nucleus. Neutrons have no charge and are also found in the nucleus with protons.

I hope this helps! If you have any doubts, feel free to ask.

your answer is  C and D

Answer: 0.0250

Explanation: 10 X 0.0750 = .75

.75 / 30 = 0.0250 M

The concentration of KOH(aq) solution is 0.025 M.

In this titration, the volume and concentration of HCl(aq) are given as 10.0 ml and 0.0750 M, respectively. The volume of KOH(aq) is given as 30.0 ml. To find the concentration of KOH(aq) solution, we can use the concept of stoichiometry and the balanced equation for the reaction:

HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)

From the balanced equation, we can see that the ratio of moles of HCl to KOH is 1:1. Therefore, the moles of KOH can be calculated as:

moles of KOH = moles of HCl = volume of HCl × concentration of HCl

Substituting the values:

moles of KOH = 10.0 ml × 0.0750 M = 0.750 mol

The concentration of KOH(aq) solution can be calculated using the moles of KOH and the volume of KOH(aq) solution:

concentration of KOH = moles of KOH / volume of KOH(aq)

Substituting the values:

concentration of KOH = 0.750 mol / 30.0 ml = 0.025 M

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Answer:

they slow down and get close together

Explanation:

low temperature lowers kinetic energy in particles hence they slow down and get close together thereby causing shrinking of the particles

Answer:

They slow down and get closer together

Explanation:

Answer:

Because both of them are Diatomic molecules.

Explanation:

Final answer:

To find the number of moles of CO₂ produced from 79.0 g of C₃H₈, convert the mass of C₃H₈ to moles and then use the mole ratio from the balanced combustion equation to find the moles of CO₂produced, which is approximately 5.37 moles.

Explanation:

To calculate the number of moles of CO₂ produced from 79.0 g of C₃H₈ (propane), you need the balanced chemical equation for the combustion of propane, which is:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

According to this equation, one mole of propane produces three moles of CO₂. First, we need to determine the number of moles of C₃H₈ present in 79.0 g. The molar mass of propane (C₃H₈) is 44.1 g/mol.

To find the moles of propane, we use the formula:

moles of propane = mass (g) / molar mass (g/mol)

moles of propane = 79.0 g / 44.1 g/mol ≈ 1.79 mol

Now, to find the moles of CO₂ produced from the combustion of 1.79 mol of propane:

moles of CO₂ = moles of C3H8 x (3 moles CO₂ / 1 mole C₃H₈)

moles of CO₂= 1.79 mol x 3 ≈ 5.37 mol

Therefore, the combustion of 79.0 g of C₃H₈ will produce approximately 5.37 moles of CO₂.

Answer:

T initial =  19.55°C

Explanation:

Given data:

Mass of Al = 35 g

Energy produces = 781.2 J

Final temperature = 44.3°C

Initial temperature = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of Al is 0.902 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

Q = m.c. ΔT

781.2 J = 35 g×0.902 J/g.°C× (T final - T initial)

781.2 J = 35 g×0.902 J/g.°C× (44.3°C -T initial )

781.2 J = 31.57 j/°C× (44.3°C -T initial )

781.2 J/ 31.57 j/°C = (44.3°C -T initial )

24.75°C = (44.3°C -T initial )

24.75° - 44.3°C = -T initial

T initial =  19.55°C

Answer:

Radioactive decay is the spontaneous breakdown of a nucleus into smaller parts

Explanation:

Answer:

Bronsted-Lowry

Explanation:

brainliest please ?

Answer:

1.) phenolphthalein

2.) neutral and acidic

3.) basic

Explanation:

Answer: Phenolphthalein was used as an indicator because it is colorless in neutral and acidic solutions and pink in basic solutions.

Explanation:

Recall that in the lab we added enough of the base NaOH so that the indicator turned pink. Prior to the solution turning pink, the solution was acidic (HCl) → neutral. Furthermore, phenolphthalein is used as an indicator of basic solutions.

The equivalence/equilibrium point occurs at ph 7.

Phenolphthalein causes solutions to become pink around pH 8.2 (a basic pH). Therefore, we added slightly more NaOH than actually needed to neutralize the acid.

13.5 is the new concentration of this solution if it is boiled down to a

volume of 1.0 L.

Explanation:

Data given:

Initial volume of the solution of sea water = 2.5 litre

Molarity of NaCl solution M1 = 5.4 M

fInal volume = 1 litre

final molarity = ?

Assuming that no loss of NaCl from sea water took place when the sea water was boiled.

applying the formula for change in concentration as:

Minitial V initial = Mfinal X Vfinal

M final = [tex]\frac{M initial X V initial}{V final}[/tex]

Putting the values in the equation:

Mfinal = [tex]\frac{5.4 X 2.5}{1}[/tex]

M final = 13.5 M

thus it can be concluded that molarity will increase drastically when volume gets reduced from 2.5 litre to 1 litre. The solution becomes highly concentrated as water volume decreases due to evaporation.

The new concentration of a seawater solution initially at 5.4 M and 2.5 L volume, after boiling down to 1.0 L, is calculated to be 13.5 M using the principle of conservation of mass and the formula M1V1 = M2V2.

The question involves calculating the new concentration of a solution when its volume changes due to boiling. A 2.5 L sample of seawater with NaCl concentration of 5.4 M is reduced to 1.0 L after boiling. To find the new concentration, we use the principle of conservation of mass, which implies that the amount of solute (NaCl) remains constant even as the volume changes. Using the formula M1V1 = M2V2, where M1 and V1 are the initial concentration and volume, and M2 and V2 are the final concentration and volume, we can calculate the new concentration after boiling down to 1.0 L.

Initial information: M1 = 5.4 M, V1 = 2.5 L, V2 = 1.0 L.

Calculation: To find M2, rearrange the formula to M2 = (M1V1) / V2. Therefore, M2 = (5.4 M * 2.5 L) / 1.0 L = 13.5 M.

The new concentration of the NaCl solution after being boiled down to 1.0 L is 13.5 M. This demonstrates how the concentration of a solution increases as the volume decreases, provided no solute is added or removed.

Answer:

Q17. D

Explanation:

A single line between 2 atoms represent a single covalent bond between a pair of electrons. There are 17 lines in the diagram hence there are 17 bonding pairs of electrons in the molecule.

Do count the double bond as 2 bonding pairs of electrons.

Answer: increasing atomic number

Explanation: Elements are arranged left to right, top to bottom, from smallest to largest, of increasing atomic number.

Answer:

I think adding a catalyst

Explanation:

From what I found, any of the first 4 don't work, reducing the concentrations of reactant molecules just decreases the chances of it reacting, decreasing the temperature does more or less the same, as it takes away energy, decreasing the surface area of the particles does more or less nothing in this situation, but for a reaction to occur, you need to add energy, which only the catalyst does. good luck!

Answer:

B) water displacement

Explanation:

C and D are incorrect because they are formulas to find volume for specific shapes.  That wouldn't work here since you have an irregularly shaped solid object.

A is incorrect because a triple beam balance is used to find mass.

Final answer:

To determine the volume of an irregular shaped solid object, the correct method is water displacement, which measures the volume of water the object displaces when submerged.

Explanation:

The proper way to find the volume of an irregular shaped solid object is B) water displacement. Unlike regular solids, which can be calculated geometrically using formulas such as Length x Width x Height for rectangular prisms, or πr²h for cylinders, irregularly shaped objects do not conform to simple mathematical formulas. The water displacement method involves submerging the object in water and measuring the volume of water displaced, which equals the volume of the object. This technique is based on Archimedes' principle, which states that the volume of the fluid displaced by an object is equal to the volume of the object itself.

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  [tex]\frac{actual yield}{theoretical yield}[/tex] x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112[tex]H_{2}[/tex] x   [tex]\frac{1 mol H_{2} }{2.016 g of H{2} }[/tex]    x    [tex]\frac{4 mol H_{2}O }{4 mol H_{2} }[/tex]    x  [tex]\frac{18.02 g H_{2}O }{1 mol H_{2}O}[/tex]   = 1.001 g [tex]H_{2}O[/tex]

Now Step 2

% yield   =  [tex]\frac{actual yield}{theoretical yield}[/tex] x 100% =   [tex]\frac{0.745g}{1.001g}[/tex] = 74.5%

Final answer:

To calculate the percent yield, compare the actual yield of H2O (0.745 grams) to the theoretical yield determined by stoichiometry and molar masses of reactants and products.

Explanation:

The student is asking how to calculate the percent yield of a chemical reaction. In this chemical reaction, 0.112 grams of hydrogen (H2) produces 0.745 grams of water (H2O). To find the percent yield, first we need to calculate the theoretical yield based on the stoichiometry of the reaction; then we compare the actual yield (0.745 grams) to the theoretical yield. The theoretical yield is calculated using the molar mass of H2 and H2O, converting grams of H2 to moles, and then using the stoichiometry given by the balanced equation to find the moles of H2O produced. These moles are then converted back to grams. The percent yield is the (actual yield / theoretical yield) x 100%. The stoichiometry of 4H2O to 4H2 implies a 1:1 mole ratio. Using the molar mass of H2 (approximately 2.02 g/mol) and H2O (approximately 18.015 g/mol), we can calculate the theoretical yield and then the percent yield.

Answer:

A) sulfur - 32

Explanation:

In periodic table you can see that S has average atomic mass = 32.06

It is closest to 32, that means that most of the atoms are isotopes sulfur-32.

The most common isotope of sulfur is sulfur-32 (32S), as it has the highest natural abundance among sulfur isotopes at 95.02% and aligns with the atomic mass listed on the periodic table.

Using a periodic table, the most common isotope of sulfur can be determined to be sulfur-32 (32S). This is because the weighted average of sulfur's atomic mass on the periodic table closely aligns with the mass number of sulfur-32, indicating its high natural abundance. To confirm, the major isotopes of sulfur are 32S with a 95.02% abundance, 33S with a 0.75% abundance, 34S with a 4.21% abundance, and 36S with a 0.02% abundance. Therefore, the most common isotope of sulfur is sulfur-32 (32S), which coincides with option A in the question provided.