Answer:
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What is the greatest common factor of 14c^3, 70c^4, and 28c^2
Answer:
14c^2
Step-by-step explanation:
The greatest common factor is the factor between the 3 expressions that once divided by each expression, 1 becomes the only number common to all 3. Considering all the expressions as follows (broken into all the factors that make up each expression)
14c^3 = 2 × 7 × c × c
70c^4 = 2 × 5 × 7 × c × c × c × c
28c^2 = 2 × 7 × c × c
From the above, the common factors are 2, 7, c and c,the product of these
= 2 × 7 × c × c
= 14c^2
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Sebuah prisma dengan alas berbentuk belah ketupat mempunyai panjang diagonal 24 cm dan 10 cm. jika tinggi prisma 8 cm , maka luas permukaan prisma adalah
A blueprint was using a scale of 3 cm=4.5m. find the actual length if it is 5 cm on the drawing. show work
The science club raised money to clean the beach the spent $29 on trashbags and $74 on waterproof boots I still have $47 left how much did they raise
What are the asymptotes of the graph of f(x) ?
helpppppppppppppppppppppppppppppppppppppp
Answer:
Option D is correct.
value of x is 48
Step-by-step explanation:
Solve: [tex]\frac{x}{64}=\frac{3}{4}[/tex]
Cross multiply in the given equation we get;
[tex]x \cdot 4 = 3 \cdot 64[/tex]
Simplify:
[tex]4x = 192[/tex]
Divide both sides by 4 we get;
[tex]\frac{4x}{4}=\frac{192}{4}[/tex]
Simplify:
[tex]x = 48[/tex]
Therefore, the value of x is 48
find the lateral area of the given prism
Match the reasons to the statements in the proof.
1. m∠1 + m∠5 = 180° and m∠1 + m∠4=180°
Subtraction property of equality
2. m∠1 + m∠5 = m∠1 + m∠4
Substitution
3. m∠5 = m∠4
If alternate interior angles equal, then lines are ||.
4. Ray YZ is parallel to Ray UV
Given
Answer:
1. [tex]m\angle 1+m\angle 5=180^{\circ}[/tex] and [tex]m\angle 1+m\angle 4=180^{\circ}[/tex]; given
2. [tex]m\angle 1+m\angle5=m\angle 1+m\angle4[/tex]; substitution
3.[tex]m\angle5=m\angle4[/tex]; subtraction property of equality
4. Ray YZ is parallel to ray UV; if alternate interior angles equal , then lines are parallel.
Step-by-step explanation:
Given
[tex]m\angle1+m\angle5=180^{\circ}[/tex]
[tex]m\angle 1+m\angle4=180^{\circ}[/tex]
To prove that YZ is parallel to UV.
Proof:
1.Statement: [tex]m\angle 1+m\angle5=180^{\circ}[/tex] and [tex]m\angle1+m\angle4=180^{\circ}[/tex]
Reason; Given
2. Statement: [tex]m\angle1+m\angle5=m\angle 1+m\angle4[/tex]
Reason: By using substitution property
3.Statement: [tex]m\angle5=m\angle4[/tex]
Reason: Subtraction property of equality.
4.Statement: Ray YZ is parallel to Ray UV
Reason: If alternate interior angles equal, then lines are parallel.
Write an inequality to represent a number decreased by 15 is at least 4
The inequality that represents the number decreased by 15 is at least 4 will be equal to x - 15 ≥ 4.
What is inequality?Inequalities are mathematical expressions where neither side is equal. In inequality, as opposed to equations, we compare the two values.
Less than (or less than and equal to), larger than (or greater or equal to), or not similar to signs are used in place of the equal sign in between.
As per the given data in the question,
Let the number be x.
Number is decreased by 15 which is at least equal to 4.
Then, the inequality will be,
x - 15 ≥ 4
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Which of the following is equal to the rational expression when x 2 or -4? 5(x-2)/(x-2)(x+4)
Answer: 5/x+4
Step-by-step explanation: a pex
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Express the sequence given below as a recursively-defined function.
3, 11, 27, 59, 123
*u(0) = 3
u(n + 1) = u(n) + 8
for n = 0, 1, 2, ...
*u(0) = 3
u(n + 1) = 2u(n) + 5
for n = 0, 1, 2, ...
*u(0) = 3
u(n + 1) = 3u(n) + 2
for n = 0, 1, 2, ...
*u(0) = 3
u(n + 1) = 8u(n) + 1
for n = 0, 1, 2, ...
Diana invested $3000 in a savings account for 3 years. She earned $450 in interest over that time period. What interest rate did she earn? Use the formula I=Prt to find your answer, where I is interest, P is principal, r is rate and t is time. Enter your solution in decimal form rounded to the nearest hundredth. For example, if your solution is 12%, you would enter 0.12.
The non-congruent angle in an isosceles triangle is called the
The non-congruent angle in an isosceles triangle is called the vertex angle.
What is an isosceles triangle?
An isosceles triangle is a triangle that has at least two sides of equal length.
Sometimes it is specified as having exactly two sides of equal length, and sometimes as having at least two sides of equal length, the latter version thus including the equilateral triangle as a special case.
The two angles opposite to the equal sides are congruent with each other. That means it has two congruent base angles and this is called an isosceles triangle base angle theorem.
The angle which is not congruent to the two congruent base angles is called an apex angle.
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Choose the correct simplification of the expression a to the 7th power times b to the 8th power all over a to the 4th power times b to the 4th power
Find the slope of (2,3) and (6,7)
East Ascension High School is creating a rectangular parking lot behind the school. The width of the parking lot is 8 more yards than the length. The total area of the parking lot is 65 yds2. What are the length and the width of the parking lot?
A Not enough information
B length = 13 yards width = 21 yards
C length = 5 yards width = 13 yards
D length = 10 yards width = 6 yards
Which statement is true about the parts of this expression?
7.5y-z/9+50+2y
he constant is 7.5.
The coefficients are 7.5 and -9
The variables are x and y.
the like terms are 7.5y and 2y
Answer:
The answer is, the like terms are 7.5y and 2y.
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Which set of points correctly demonstrates a pre-image that has been is reflected over x = -1? A(0,-1) and A'(4,-1) A(0,-5) and A'(0,3) A(-5,0) and A'(3,0) A(0,-4) and A'(0,4)
The correct set of points that demonstrate a pre-image that has been reflected over x = -1 is A(0,-1) and A'(−2,−1).
What are coordinates?A pair of numbers called coordinates are used to locate a point or a form in a two-dimensional plane. The x-coordinate and the y-coordinate are two numbers that define a point's location on a 2D plane.
To reflect a point over the line x = -1, we simply need to flip the x-coordinate of the point across the line. In other words, if a point has coordinates (x,y), its image after reflection over x = -1 will have coordinates (-x,y).
Using this rule, we can check each of the given options:
A(0,-1) and A'(4,-1): The reflection of A(0,-1) over x = -1 should have an x-coordinate of -0, which means it should be the same as the original point. A'(4,-1) does not fit this requirement, so this is not the correct set of points.A(0,-5) and A'(0,3): The reflection of A(0,-5) over x = -1 should have an x-coordinate of -0, which means it should be the same as the original point. A'(0,3) does not fit this requirement, so this is not the correct set of points.A(-5,0) and A'(3,0): The reflection of A(-5,0) over x = -1 should have an x-coordinate of 5, which means it should be (-5,0). A'(3,0) does not fit this requirement, so this is not the correct set of points.A(0,-4) and A'(0,4): The reflection of A(0,-4) over x = -1 should have an x-coordinate of -0, which means it should be the same as the original point. A'(0,4) does not fit this requirement, so this is not the correct set of points.Therefore, the correct set of points is A(0,-1) and A'(−2,−1).
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17+4h+2=1−5h solve for h
The value of h for the expression will be -2.
What is an expression?Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
The given expression is 17+4h+2=1−5h. The value of "h" will be calculated as below:-
17+4h+2 = 1-5h
4h+5h = 1-2-17
9h = -18
h = -2
Therefore, the value of h for the expression will be -2.
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A recipe calls for 2/3 cup of water. You have a 1/6 cup measuring cup.
Which statements are true? Check all that apply.
The cup cannot be used to measure the amount of water needed.
2/3 can be rewritten as sixths.
Four full measuring cups are needed.
The numerator and denominator of 2/3 can be multiplied by 2 to get 4/6.
1/6 is equivalent to 2/3.
A circle has a radius of 6 in.
What is the exact length of an arc formed by a central angle measuring 45°?
Express your answer using π
A bakery packages cookies in two sizes of boxes, one with 18 cookies and the other with 24 cookies. A small number of cookies are to be wrapped in cellophane before they are placed in a box. To save money, the bakery will use the same size cellophane packages for each box. How many cookies should the bakery place in each cellophane package to maximize the number of cookies in each package?
Final answer:
The bakery should place 6 cookies in each cellophane package to maximize the number of cookies per package and fit them evenly in both sizes of boxes. This is found by calculating the greatest common divisor (GCD) of the box sizes, which in this case is 6.
Explanation:
To solve the problem of how many cookies the bakery should place in each cellophane package to maximize the number of cookies in each package, we need to find the greatest common divisor (GCD) of the two box sizes, which are 18 cookies and 24 cookies. The GCD represents the largest number of cookies that can be evenly distributed in both box sizes without any leftovers.
Step-by-step Solution:
List the divisors of 18: 1, 2, 3, 6, 9, 18.List the divisors of 24: 1, 2, 3, 4, 6, 8, 12, 24.Find the largest number that appears on both lists, which is 6.Thus, the bakery should use cellophane packages that contain 6 cookies each to maximize the number of cookies per package and ensure that they fit evenly in both the 18-cookie box and the 24-cookie box.This way, both the smaller and the larger box sizes can be filled with equal-sized packages of cookies, and there will be no leftover cookies.
The width of Maya’s poster is 2 inches shorter than the length. The graph models the possible area (y) of Maya’s poster determined by its length (x). Which describes what the point (2, 0) represents? The area is 2 if the length is 0. The area is 0 if the length is 2. The length is 2 if the width is 0. The width is 0 if the length is 2.
The 8 foot diameter circular table has a 4 foot wide extension. What is the total area with the extension? How does the area compare to the area of the 10 foot diameter table? Show your work.
If two figures have the same perimeter, they are congruent. True or false?
What is the sum of the first eight terms of the series?
(−600)+(−300)+(−150)+(−75)+(−37.5)+...
Round the answer to two decimal places.
−1200.50
−1195.31
−1190.63
−1181.25
The given sequence is a geometric series.
Common ratio can be found as :
(-300/-600) = 0.5
(-150/-300) =0.5
So common ratio is 0.5
First term is -600
The attachment shows the required calculations.
Answer: Sum of eight terms is (-1195.31).
Assume x = 5, y = 6, and z = 8. what is the value of the expression?
Rewrite this inequality so that one side is 0.
x2 − 2x + 1 < x − 1
To rewrite the inequality so that one side is 0, simply subtract x and add 1 to both sides, resulting in the inequality x² - 3x + 2 < 0.
To rewrite the inequality x² - 2x + 1 < x - 1 so that one side is 0, we follow these steps:
Bring all terms to one side of the inequality by subtracting x and adding 1 to both sides, resulting in x² - 3x + 2 < 0.
Now, the inequality is set up with one side equal to 0, and we can analyze or solve the inequality from here.
Write the expression as a product of polynomials:
a(p–q)+q–p
p^2q+r^2–pqr–pr
PLZ ANSWER ASAP
1. a(p–q)+q–p
We take out common factor
To change q - p as p - q we pull out -1
So q - p becomes -1(p - q)
a(p–q)+q–p
a(p–q) -1(p - q)
p -q is in common so we factor out p-q
(p - q) (a - 1)
2. p^2q+r^2–pqr–pr
WE change the order of terms
[tex] p^2q-pqr+r^2-pr [/tex]
We group first two terms and last two terms
[tex] (p^2q-pqr)+(r^2-pr) [/tex]
Now we factor out pq from first group and -r from second group
[tex] pq(p-r) - r(p - r) [/tex]
[tex] (p - r) (pq - r) [/tex]
To write the answer as a product of polynomials we try to factor the polynomial
a(p–q)+q–p
we can write this expression as
a(p-q)+(q-p)
from second parenthesis we can factor out -1 , so we get
a(p-q) -1(p-q)
Now it has two terms a(p-q) and -1(p-q) , from these two terms we can factor out (p-q)
So we get it
(p-q)(a-1)
So we get the polynomial as a product of two polynomials.
Second
[tex] p^2q+r^2- pqr-pr [/tex]
we can rewrite the expression as
[tex] (p^2q- pqr)+(r^2-pr) [/tex]
Now try to factor the groups
factor out "pq" as GCF from first group and "-r" as GCF from second group
[tex] pq(p- r)-r(p-r) [/tex]
Now we can factor it out for final step
[tex] (p- r)(pq-r) [/tex]