Answer:
Commutator.
Explanation:
It is electrical switch and consist of cylinder. Split rings are two halves of a ring that act as a Commutator. When current in the coil is Zero and is about to change the direction.
When convection currents flow in the mantle they also move the
Answer:
Crust
Explanation:
When the convection currents flow in the mantle they also move the crust. This is best explained as that the crust gets a free ride with the convection currents in the mantle; just as a conveyor belt in a factory moves boxes.
__________ is a type of molding in which thermoplastics are heated above melting temperature and, using an extruder, are forced into a closed die to produce a molding.
a. Injection molding
b. Blow molding
c. Thermoforming
d. Extrusion
Answer: The correct and is
D. Extrusion
Explanation:
What is extrusion?
Extrusion is a manufacturing process used to make basically pipes and hoses.
The pvc granules are melt into a liquid which is forced through a die, forming a long 'tube like' shape. The shape of the die determines the shape of the tube.
The extrusion is then cooled and forms a solid shape
Extrusion moulding is used to create products with a consistent cross-section.
Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.
The resistance means resist, means to resist the current, so we are here given that, three resistors are connected in series, so as we know that, if n resistors are connected in series combination, then the total resistance is the individual sum of all n Resistors, so if we apply the same formula here, we will be having :
[tex]{:\implies \quad \sf R_{Total}=3+4+5}[/tex]
[tex]{:\implies \quad \boxed{\bf{R_{Total}=12\Omega}}}[/tex]
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https://brainly.com/question/27101567A zone reconnaissance involves a directed effort to obtain detailed information on all routes, obstacles, terrain, enemy forces, or specific civil considerations within a zone defined by boundaries to include obstacles (existing and reinforcing) as well as areas of CBRN contamination. True or false?
Answer:
It is True
Explanation:.
A commander assigns a zone reconnaissance mission when he seeks additional information on a zone before committing other forces in the zone. It is appropriate when the enemy situation is vague, existing knowledge of the terrain is limited, or combat operations have altered the terrain. A zone reconnaissance could include several route or area reconnaissance missions assigned to subordinate units.
A block of unknown mass is attached to a spring of spring constant 6.1 N/m and undergoes simple harmonic motion with an amplitude of 10.3 cm. When the mass is halfway between its equilibrium position and the endpoint, its speed is measured to be 31.3 cm/s. Calculate the mass of the block. Answer in units of kg
Answer:
Explanation:
Given that, .
Spring constant.
K = 6.1 N/m
Amplitude of oscillation
A = 10.3cm = 0.103m
Half wave, it speed is
V = 31.3cm/s = 0.313m/s
Mass of block
M =?
The is half of the distance between the equilibrium position and endpoint
Then,
x = A/2
Where,
A is the amplitude
x is the position of the block
x = A / 2 = 0.103/2
x = 0.0515m
The velocity if the block at any given position is given as
v = ω√(A²—x²)
Then,
ω = v / √(A²—x²)
Where
ω is angular frequency
v Is the velocity of the block
The force constant is given as
k = mω²
Where,
K is spring constant
ω is angular frequency
Substitute ω into k
Then,
k = m (v / √(A²—x²))²
k = mv² / (A²—x²)
Make m subject of formula since we want to find m
m = k(A²—x²) / v²
m = 6.1 (0.103²—0.0515²) / 0.313²
m = 6.1 × 7.96 × 10^-3 / 0.313²
m = 0.495 kg
The mass of the block is approximately 0.5kg
Answer:
The mass of the block is 496 g
Explanation:
Here we have by the principle of conservation of energy;
Energy in spring, E = 0.5·k·A²
Where:
k = Spring constant = 6.1 N/m
A = Amplitude of motion = 10.3 cm = 0.103 m
E = 0.5×6.1×0.103² = 0.03235745 J= 3.24 × 10⁻² J
At half way, we have
[tex]E = \frac{1}{2} k(\frac{A}{2} )^{2} + \frac{1}{2} mv^{2} = \frac{E}{4} + \frac{1}{2} mv^{2}[/tex]
Where:
m = Mass of the block
v = Velocity of block at the instant (Halfway between its equilibrium position and the endpoint)
Therefore,
[tex]\frac{3}{4}E = \frac{1}{2} mv^{2}[/tex] or
m = [tex]\frac{3}{2v^2}E[/tex] = [tex]\frac{3}{2\times 0.313^2} \times 3.24 \times 10^{-2}[/tex]= 0.496 kg = 496 g.
The diagrams below each show the motion of a distant star relative to Earth (not to scale). The red arrows indicate the speed and direction of the star’s motion: Longer arrows mean faster speed. Rank the stars based on the Doppler shift that we would detect on Earth, from largest blueshift, through no shift, to largest redshift.Note:a picture in resemble to solar system is shown in the figure
Answer:
The ranking of the stars are 5 → 2 → 4 → 3 → 1
Explanation:
To solve the question, we note that an approaching star has a blue-shift, a regressing star has a red-shift and a crossing star will have no shift.
The magnitude of the blue-shift or red-shift is dependent on the speed of the stars.
Therefore we have the rank of the stars based on the Doppler shift that would be detected on earth from largest blue-shift to largest red-shift given as
5 → 2 → 4 → 3 → 1.
The Doppler shift affects the wavelengths of light emitted or reflected by objects in motion. Larger blueshifts indicate faster speeds towards us, while larger redshifts indicate faster speeds away from us. Stars with no shift do not have a detected Doppler shift.
The Doppler shift is a phenomenon that occurs when an object's motion causes a change in the wavelengths of light that it emits or reflects. In the case of stars, if a star is moving away from us, its light will be redshifted, meaning the wavelengths of the light will be longer. On the other hand, if a star is moving towards us, its light will be blueshifted, meaning the wavelengths of the light will be shorter.
To rank the stars based on the Doppler shift that we would detect on Earth, we need to understand that larger blueshifts indicate faster speeds towards us, and larger redshifts indicate faster speeds away from us. So, the star with the largest blueshift will have the highest ranking for blueshift, while the star with the largest redshift will have the highest ranking for redshift. Stars with no shift will have no Doppler shift detected.
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A passenger compartment of a rotating amusement park ride contains a bench on which a book of mass
mb is
placed, as indicated by the dot in the left figure above. The compartment moves with a constant angular speed
about the center of the ride along a circular path of radius R. The bench remains horizontal throughout the
compartment’s motion. The right figure above shows a magnified view of the compartment.
The graph below shows the horizontal ( ) x component of the book’s position as a function of time, where the
+x-direction is to the right.
(a)
i. Determine the period of revolution of the book.
ii. Calculate the tangential speed vb (not the angular speed) of the book.
a) 120 s
b) v = 0.052R [m/s]
Explanation:
a)
The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).
The graph of the problem is missing, find it in attachment.
To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.
The first point we take is t = 0, when the position of the book is x = 0.
Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.
Therefore, the period is
T = 120 s - 0 s = 120 s
b)
The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.
The perimeter of the wheel is:
[tex]L=2\pi R[/tex]
where R is the radius of the wheel.
The period of revolution is:
[tex]T=120 s[/tex]
Therefore, the tangential speed of the book is:
[tex]v=\frac{L}{T}=\frac{2\pi R}{120}=0.052R[/tex]
When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain constant force acts upon an object with mass , the acceleration of the object is 26m/s^2 . If the same force acts upon another object whose mass is 13 , what is this object's acceleration
If the same force acts upon another object whose mass is 13 kg the acceleration is [tex]4m/s^2[/tex].
Force is a fundamental concept in physics that describes the interaction between objects that can cause a change in their motion or shape. It's a vector quantity, meaning it has both magnitude and direction. In simpler terms, force is what can make things move, stop, change direction, or deform.
Given:
Masses, [tex]m_1 = 2\ kg[/tex] and [tex]m_2 = 13\ kg[/tex]
Acceleration, [tex]a = 26\ m/s^2[/tex]
The force is computed as:
[tex]F = m_1a\\F = 2\times26\\F = 52\ N[/tex]
The acceleration for mass 52 kilograms is:
[tex]F = m_2a\\a = F/m_2\\a = 52/ 13\\a = 4\ m/s^2[/tex]
Hence, if the same force acts upon another object whose mass is 13 kg the acceleration is [tex]4m/s^2[/tex].
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Applying Newton's second law of motion, the acceleration of an object is directly proportional to the force acting on it, but inversely proportional to its mass. The acceleration of a 13kg object, when acted upon by the same force that gives a 2kg object an acceleration of 26m/s^2, would be 4 m/s^2.
Explanation:The question basically asks us to apply Newton's second law of motion, which states that the acceleration of a system is directly proportional to the net external force acting on the system, but inversely proportional to its mass. In equation form, this can be written as F=ma, where F is the force, m is the mass, and a is the acceleration. This is also referred to as the principle of constant acceleration, in which the force applied to an object will either accelerate or decelerate it at a constant rate, provided the mass of the object remains unchanged.
In this case, we know that a 2kg object accelerates at 26m/s^2 under the influence of a constant force. Therefore, the force (F) acting on it can be computed as F = m * a = 2kg * 26m/s^2 = 52N. Now, if the same force acts on another object with a mass of 13kg, the acceleration (a) of this object can be computed by rearranging the equation as a = F/m = 52N / 13kg = 4m/s^2. So, the acceleration of the second object, under the same force, would be 4 m/s^2.
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At the top of the hill, the
ball has 100 J of potential energy. Explain what happens
to Mechanical Energy, Kinetic Energy and Potential
Energy as the ball rolls down and reaches the bottom.
Answer:
The answer to your question is below
Explanation:
To explain what happens with the ball we must remember the Law of Conservation of Energy.
This law states that the energy can be neither created nor destroyed only converted from one form of energy to another.
Then,
At the top of the hill, the potential energy is maximum and the kinetic energy equals to zero.
When the ball starts to roll down the potential energy will be lower and the kinetic energy will have a low value.
At the middle of the hill, both energies have the same values.
At the end of the hill, the potential energy will be equal to zero and the kinetic energy will be maximum.
According to this law, energy cannot be generated or annihilated; it can only be transformed from one type of energy to another.
The gravitational potential is highest at the summit of the slope, whereas the kinetic energy is negative.The potential energy of the ball will be reduced when it begins to roll down, and the velocity will be low.Both energy have had the same value at the center of the slope.The gravitational potential will be minimal and the velocity will be highest at the top of the slope.Learn more:https://brainly.com/question/17858145?referrer=searchResults
During which phase of the moon may a lunar eclipse occur?
Answer: New moon
Explanation: A solar eclipse is only possible during a new moon phase
In physics how much energy is required to raise the temp of 9.78kg of water from 40.82c to 52.07c? The specific heat of water in this state is 4186j/kg-c.
Answer:
469.6KJ
Explanation:
Heat energy required can be calculated using the formula
H = mc∆t where
m is the mass of the water
c is the specific heat capacity of the water
∆t is the change in temperature of the water
Given m = 9.78kg
c = 4186j/kg-c.
∆t = 52.07°C - 40.82°C
∆t = 11.25°C
H = 9.78 × 4186 × 11.25
H = 460,564.65Joules
= 460.6KJ
Answer:
the amount of energy required to raise the temperature of the water is 460564.65 J
Explanation:
The energy required to raise the temperature of water can be calculated as follows;
Q = mcΔθ
where;
Q is the quantity of heat or energy required to raise the temperature of water
m is mass of water
c is specific heat capacity of water
Δθ is change in temperature = T₂ - T₁
Given;
m = 9.78kg
c = 4186j/kg-c
Δθ = T₂ - T₁ = 52.07°C - 40.82°C = 11.25°C
Q = mcΔθ
Q = (9.78)(4186)(11.25)
Q = 460564.65 J
Therefore, the amount of energy required to raise the temperature of the water is 460564.65 J
Air pollution from a power plant is being monitored for levels of nitrogen dioxide and ground-level ozone. The levels are measured daily at the same time. What is the impact of a dark and cloudy day on the readings for the levels of air pollutants measured?
An increase in the level of nitrogen dioxide and a decrease in the level of ground-level ozone occurs.
Explanation:
Ozone gas is normally found in stratosphere, it protects us from solar radiation. Under certain circumstances, it can be formed on the ground level.
Conditions that have to be met in order for this to happen are existing of nitrogen oxides and volatile organic compounds and their reaction catalyzed by heat and light.
During dark, cold and cloudy days, due to the lack of heat and light from the Sun, formation of ozone will be decreased.
Also, this will enable building up of nitrogen dioxide, due to the same reason, leading to increased concentration.
A stone is dropped at t = 0. A second stone, with 3 times the mass of the first, is dropped from the same point at t = 55 ms. (a) How far below the release point is the center of mass of the two stones at t = 470 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time?
Answer:
Part(a): At [tex]\bf{t = 470~ms}[/tex] the center of mass will travel [tex]\bf{0.903~m}[/tex].
Part(b): The velocity of the first stone is [tex]\bf{4.606~m.s^{-1}}[/tex] and the velocity of the second stone is [tex]\bf{4.067~m.s^{-1}}[/tex].
Explanation:
Given:
The first stone is dropped at [tex]t_{1}=0~s[/tex].
The second stone is dropped at, [tex]t_{2}=55~ms=0.055~s[/tex]
The mass of the second stone is 3 times the mass of the first.
Both the stones are dropped from the same point.
Consider the mass of the first stone be [tex]m[/tex]. So the mass of the second stone is [tex]3m[/tex].
(a)
The formula to calculate the distance traveled by each stone is given by
[tex]y = \dfrac{1}{2}gt^{2}~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)[/tex]
where [tex]g[/tex] is the acceleration due to gravity and [tex]t[/tex] is the time taken by each stone.
Substituting [tex]9.8~m.s^{-2}[/tex] for [tex]g[/tex], [tex]y_{1}[/tex] for [tex]y[/tex] and [tex]470~ms[/tex] or [tex]0.47~s[/tex] for first stone in equation (1), we have
[tex]y_{1}&=& \dfrac{1}{2}(9.8~m.s^{-2})(0.47~s)^{2}\\~~~~&=& 1.08~m[/tex]
where [tex]y_{1}[/tex] is the distance traveled by the first stone.
Substituting [tex]9.8~m.s^{-2}[/tex] for [tex]g[/tex], [tex]y_{2}[/tex] for [tex]y[/tex] and [tex](470-55)~ms = 415~ms[/tex] or [tex]0.415~s[/tex] for second stone in equation (1), we have
[tex]y_{2}&=& \dfrac{1}{2}(9.8~m.s^{-2})(0.415~s)^{2}\\~~~~&=& 0.844~m[/tex]
The formula to calculate the distance traveled by the center of mass is given by
[tex]y_{c} &=& \dfrac{my_{1}+3my_{2}}{m+3m} \\~~~~&=& \dfrac{1.08m + 0.844(3m)}{4m}\\~~~~&=& 0.903~m[/tex]
(b)
The formula to calculate the velocity of each stone is given by
[tex]v=gt~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)[/tex]
Substituting [tex]v_{1}[/tex] for [tex]v[/tex], [tex]9.8~m.s^{-2}[/tex] for [tex]g[/tex] and [tex]0.47~s[/tex] for [tex]t[/tex] in equation (2), we have
[tex]v_{1} &=& (9.8~m.s^{-2})(0.47~s)\\~~~~&=& 4.606~m.s^{-1}[/tex]
where [tex]v_{1}[/tex] is the velocity of the first stone after [tex]470~ms[/tex].
Substituting [tex]v_{2}[/tex] for [tex]v[/tex], [tex]9.8~m.s^{-2}[/tex] for [tex]g[/tex] and [tex]0.415~s[/tex] for [tex]t[/tex] in equation (2), we have
[tex]v_{2} &=& (9.8~m.s^{-2})(0.415~s)\\~~~~&=& 4.067~m.s^{-1}[/tex]
where [tex]v_{2}[/tex] is the velocity of the second stone after [tex]470~ms[/tex].
A form of charge designated as negative positive or neutral is called
Answer:
Electrical charge
Explanation:
Electrical Charge is a form of charge, designated negative, positive, or neutral (without charge) that is found on the subatomic particles that make up all atoms
An ideal transformer has 50 turns in its primary and 250 turns in its secondary. 12 Vac is connected to the primary. Find: (a) volts ac available at the second- ary; (b) current in a 1O-ohm device connected to the secondary; and (c) power supplied to the primary.
Answer:
a. 60 V b. 6 A c. 360 W
Explanation:
a. Voltage in secondary
For an ideal transformer,
N₁/N₂ = I₂/I₁ = V₁/V₂ where N₁ = turns in primary = 50 turns, N₂ = turns in secondary = 250 turns, V₁ = voltage in primary = 12 V, V₂ = voltage in secondary = ? V
N₁/N₂ = V₁/V₂
V₂ = V₁N₂/N₁ = 250 × 12/50 = 60 V
b. Since V₂ = I₂R,
I₂ = V₂/R R = 10 Ω
I₂ = 60 V/10 Ω
I₂ = 6 A
c. We first calculate the current in the primary from
N₁/N₂ = I₂/I₁ where I₁ = primary current
I₁ = N₂I₂/N₁ = 250 × 6 A/50 = 30 A
The power supplied to the primary is thus
P = I₁V₁ = 30 A × 12 V = 360 W
(a) The voltage supply at the secondary coil is of 60 V.
(b) The current flow through the 10- ohm device is 6 A.
(c) The power supply to the primary coil is 360 W.
Given Data:
Number of turns of primary coil is, n1 = 50.
Number of turns of secondary coil is, n2 = 250.
The voltage supply to primary coil is, V1 = 12 V.
The resistance of device is, R = 10 ohm.
(a)
The first part of the given problem is based on the Transformer equation relating the number of turns of coils at primary and secondary and voltage supply at each coils.
Therefore,
n1 / n2 = V1 / V2
Here,
V2 is the voltage supply to the secondary coil.
Solving as,
50 / 250 = 12 / V2
V2 = 250 / 50 × 12
V2 = 60 V.
Thus, we can conclude that the voltage supply at the secondary coil is of 60 V.
(b)
Now in order to find the current flow through the 10 - ohm device, we can use the Ohm's law as,
V2 = I' × R
Solving as,
60 = I' × 10
I ' = 60 / 10
I' = 6 A
Thus, we can conclude that the current flow through the 10- ohm device is 6 A.
(c)
Now, we first calculate the current in the primary from
n1 / n2 = I' / I
here,
I is the primary current
Solving as,
I = n2 × I' / n1
I = 250 × 6 /50
I = 30 A
The power supplied to the primary is thus
P1 = I × V1
P1 = 30 × 12
P1 = 360 W
Thus, we can conclude that the power supply to the primary coil is 360 W.
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Which statement best describes pseudoscience? Pseudoscience is
A) not a branch of science and involves beliefs and opinions
B) a method that scientists use to study the living world
C) a trustworthy branch of science that involves theories and laws
D) a way of testing a hypothesis to prove or disprove your theory
(FLVS Physical Science 03.09)
Answer:
Pseudoscience is not science - it involves beliefs and opinions.
Explanation:
i got it right on the test
Answer:
Pseudoscience is not science - it involves beliefs and opinions.
Explanation:
A technician is checking refrigerant system pressures. Both high- and low-side service ports are located on the A/C compressor. When the compressor is engaged, the high-side pressure instantly goes over 375 psig. What is the most likely cause of this condition
Answer:
Two major causes are outline bellow
1. The presence of air in the system
2. Clogged condenser
Explanation:
1. The presence of air in the system
One of the causes that have been established in relation to high compressor discharge pressure is the presence of air in the system. When this takes place, your best solution is to recharge the system.
2. Clogged condenser
Another is a clogged condenser in which case you will need to clean the condenser so that it will function properly. When you happen to spot that the discharge valve is closed and it is causing high discharge pressure on the compressor, you can solve that easily by opening the valve
The most likely cause of a refrigerant system's high-side pressure exceeding 375 psig is a blockage, overcharging, or a malfunctioning expansion valve. These issues prevent proper refrigerant flow and pressure regulation within the vapor compression system.
If a technician observes that the high-side pressure of a refrigerant system instantly exceeds 375 psig once the compressor is engaged, the most likely cause for this condition could be a blockage in the condenser or the liquid line, overcharging of the refrigerant, or a malfunctioning expansion valve that is not allowing the liquefied refrigerant to flow properly into the evaporator. The blockage could result in an excessively high pressure build-up because the refrigerant cannot circulate properly. Overcharging of the system adds too much refrigerant, which also leads to high pressure. Additionally, if the expansion valve is stuck closed or not functioning correctly, it would prevent the refrigerant from moving into the evaporator, causing the pressure to build up on the high side.
In a typical vapor compression system, as the electrically driven compressor introduces work (W), it raises the temperature and pressure of the refrigerant, forcing it into the condenser coils. Here, heat transfer occurs as the gas inside the coils is higher in temperature than the room, leading to condensation of the gas back into a liquid. The cooled pressurized liquid passes through the expansion, or pressure-reducing valve, and goes to the evaporator coils located outdoors where it is further cooled by expansion.
A 0.100-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wall and rebounds with 70.0% of its initial kinetic energy. What is the magnitude of the change in momentum of the stone
Answer:
Change in momentum of the stone is 3.673 kg.m/s.
Explanation:
Given:
Mass of the ball on the horizontal the surface, m = 0.10 kg
Velocity of the ball with which it hits the stone, v = 20 m/s
According to the question it rebounds with 70% of the initial kinetic energy.
We have to find the change in momentum i.e Δp
Before that:
We have to calculate the rebound velocity with which the object rebounds.
Lets say that the rebound velocity be "v1" and KE remaining after the object rebounds be "KE1".
⇒ [tex]KE_1=0.7\times \frac{mv^2}{2}[/tex]
⇒ [tex]KE_1=0.7\times \frac{0.10\times (20)^2}{2}[/tex]
⇒ [tex]KE_1=0.7\times \frac{0.10\times 400}{2}[/tex]
⇒ [tex]KE_1=14[/tex] Joules (J).
Rebound velocity "v1".
⇒ [tex]KE_1=\frac{m(v_1)^2}{2}[/tex]
⇒ [tex]v_1 = \sqrt{\frac{2KE_1}{m} }[/tex]
⇒ [tex]v_1 = \sqrt{\frac{2\times 14}{0.10} }[/tex]
⇒ [tex]v_1=16.73[/tex]
⇒ [tex]v_1=-16.73[/tex] m/s ...as it rebounds.
Change in momentum Δp.
⇒ [tex]\triangle p= m\triangle v[/tex]
⇒ [tex]\triangle p= 0.10\times (20-(-16.73)[/tex]
⇒ [tex]\triangle p= 0.10\times (20+16.73)[/tex]
⇒ [tex]\triangle p= 0.10\times (36.73)[/tex]
⇒ [tex]\triangle p = 3.673[/tex] Kg.m/s
The magnitude of the change in momentum of the stone is 3.673 kg.m/s.
A bat locates insects by emitting 25.3 kHz ultrasonic chirps and then listening for echoes from insects flying around it. Humans can hear sounds with frequencies up to 20 kHz. How fast would a bat have to fly and in which direction (positive away from and negative towards a stationary human listener) in order for a person to hear these chirps
Answer:
Speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.
Explanation:
Given:
Frequency of the bat that is source here, [tex]f_S[/tex] = 25.3 kHz = 25.3 * 10^3 Hz
Frequency of the listener (human), [tex]f_L[/tex] = 20 kHz = 20*10^3 Hz
We have to identify how fast the bat have to fly in order for a person to hear these chirps .
Let the velocity of bat that is source is "Vs" and "Vs" = "Vbat".
Doppler effects formulae :
When the source is receding (moving away) [tex]f_L=(\frac{V+V_L}{V+V_S}) f_S[/tex] When the source is approaching [tex]f_L=(\frac{V+V_L}{V-V_S}) f_S[/tex] Speed of sound in [tex]V_S =433.895-343[/tex]the air (medium), [tex]V = 343\ ms^-^1[/tex]Using the above formula and considering that the bat is moving away so that the human can listen the chirps also [tex]V_L=0[/tex] as listener is stationary.
⇒ [tex]f_L=(\frac{V+V_L}{V+V_S}) f_S[/tex] ⇒ [tex]f_L=(\frac{V+0}{V+V_S}) f_S[/tex]
Re-arranging in terms of Vs.
⇒ [tex]V+V_S =\frac{V\times f_S}{f_L}[/tex]
⇒ [tex]V_S =\frac{V\times f_S}{f_L}-V[/tex]
⇒ [tex]V_S =\frac{343\times 25.3\times 10^3}{20\times 10^3}-343[/tex]
⇒ [tex]V_S=90.895[/tex] m/s
The speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.
Your little sister is building a radio from scratch. Plans call for a 500 μH inductor wound on a cardboard tube. She brings you the tube from a toilet-paper roll (12 cm long, 4.0 cm diameter), and asks how many turns she should wind on the full length of the tube.
Answer:
N = 195 turns
Explanation:
The inductance of the inductor, L = 500 μH = 500 * 10⁻⁶H
The length of the tube, l = 12 cm = 0.12 m
The diameter of the tube, d = 4 cm = 0.04 m
Radius, r = 0.04/2 = 0.02 m
Area of the tube, A = πr² = 0.02²π = 0.0004π m²
[tex]\mu_{0} = 4\pi * 10^{-7}[/tex]
The inductance of a solenoid is given by:
[tex]L = \frac{\mu_{0}N^{2} A }{l}[/tex]
[tex]500 * 10^{-6} = \frac{4\pi *10^{-7} N^{2} *4\pi *10^{-4} }{0.12}\\500 * 10^{-6} = 0.00000001316N^{2} \\N^{2} = \frac{500 * 10^{-6}}{0.00000001316}\\N^{2} = 37995.44\\N = \sqrt{37995.44} \\N = 194.92 turns[/tex]
How might a nitrogen-oxygen atmosphere on the moon affect the range of temperatures on the moon?
A) An atmosphere might hold in heat, making the moon very hot
B) An atmosphere might block heat radiating from the sun, making the moon very cold
C) An atmosphere might moderate temperatures, making more or even, as on Earth
D) An atmosphere would have no effect on the range of temperatures on the moon
Answer:
C) An atmosphere might moderate temperatures, making more or even, as on Earth
Explanation:
Atmosphere has moderating effect on a planet . It not only protects the planet from getting heated excessively during day time but it also protects it from getting too much cooled during night . In day time , it filters excessive heat out and during night it traps the heat coming out . Both ways , it tries to keep the temperature of the planet evenly balanced in day and night.
The Answer Is C) An atmosphere might moderate temperatures, making more or even, as on Earth
Which statement describes Newton's law of universal gravitation?
Mass has hittle effect on gravity between objects.
Gravity pushes objects away from Earth's center,
Gravity does not act between Earth and the moon.
Every object in the universe attracts every other object
Final answer:
Newton's law of universal gravitation states that all objects in the universe attract each other with a force proportional to the product of their masses and inversely proportional to the square of the distance between them.
Explanation:
Newton's Law of Universal Gravitation:
Sir Isaac Newton's law of universal gravitation states that every object in the universe attracts every other object with a force. This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The gravitational force is universally attractive and only depends on mass and distance, following the equation F = G × (m1 × m2) / r², where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the centers of the two masses.
A fisherman fishing from a pier observes that the float on his line bobs up and down, taking 2.4 s to move from its highest to its lowest point. He also estimates that the distance between adjacent wave crests is 48 m. What is the speed of the waves going past the pier?
(A) 20 m/s
(B) 1.0 m/s
(C) 10 m/s
(D) 5.0 m/s
(E) 115 m/s
Answer:
(c) 10m/s
Explanation:
to find the speed of the waves you can use the following formula:
[tex]v=\frac{\lambda}{T}[/tex]
λ: wavelength of the wave
T: period
the wavelength is the distance between crests = 48m
the period is the time of a complete oscillation of the wave. In this case you have that the float takes 2.4 s to go from its highest to the lowest point. The period will be twice that time:
T = 2(2.4s)=4.8s
by replacing you obtain:
[tex]v=\frac{48m}{4.8s}=10\frac{m}{s}[/tex]
the answer is (c) 10m/s
Luis is trying to push a box of new soccer balls across the floor. In the illustration, the arrow on the box is a vector representing the force that Luis exerts . If the box is not moving, which of the filling must be true
Answer:
Complete question
Luis is trying to push a box of new soccer balls across the floor.
If the box is not moving, which of the following must be true?
A. The box is exerting a larger force on Luis than he is exerting on the box
B. There is another force acting on the box that balances Luis's force.
C. Luis is applying a force that acts at a distance.
D. There is no force of friction acting on the box.
Explanation:
Using newton second law of motion
ΣF = ma
Now, for a body not to move when a force is acting on it means that the body is in equilibrium and acceleration a = 0
Therefore,
Fnet = 0
So, if he is applying a force F to push the box and the box is not moving then, there is an external force that is pushing the force back opposite the direction he his pushing and this force counterbalance is own force.
F—F' = 0
F' = F
So, F' is the counter balance force and it is equal to the force applied by Luis
Or it might be frictional force, because if the static friction is not overcome, then, the body will not leave it's state of rest. So if the fictional force is very high, then the box will not leave it rest position and we also know that frictional force opposes motion,
F—Fr=0
F = Fr
So using this explanation,.
The answer is B
B. There is another force acting on the box that balances Luis's force.
How many significant figures are present in the number 50,670?
the difference between an electric motor and an electric generator is that a motor converts _____ energy into ______ energy, while a generator converts _______ energy into ________ energy
Answer:electrical,kinetic,kinetic,electrical
Explanation:
Answer:
Electrical, kinetic, kinetic, electrical
Explanation:
Just did it
Determine whether each of the following is exothermic or endothermic and indicate the sign of δh. A. Natural gas burning on a stove b. Isopropyl alcohol evaporating from skin c. Water condensing from steam
Natural gas burning on a stove is exothermic (δh < 0), isopropyl alcohol evaporating from the skin is endothermic (δh > 0), and water condensing from steam is exothermic (δh < 0).
Explanation:(a) Natural gas burning on a stove: This is an exothermic process. The combustion of natural gas on a stove releases a huge amount of heat which cooks the food. The sign of δh (enthalpy change) in this process is negative (δh < 0) as heat is released.
(b) Isopropyl alcohol evaporating from the skin: This is an endothermic process. When isopropyl alcohol evaporates from our skin, it absorbs heat from our body which causes a cooling effect. Hence, the sign of δh is positive (δh > 0) as heat is absorbed.
(c) Water condensing from steam: This is an exothermic process. The condensation process releases heat and hence, the sign of δh is negative (δh < 0).
Learn more about Exothermic and Endothermic reactions here:https://brainly.com/question/9799465
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All of the following are functions of the skeletal system EXCEPT:
A.
producing red blood cells
B.
providing support for the body
C.
producing white blood cells
D.
producing ligaments and tendons
Answer:
D. Producing ligaments and tendons.
just to the quiz on edge
The skeletal system provides structure, assists in movement, protects internal organs, and produces both red and white blood cells. However, it does not produce ligaments and tendons, which are part of the muscular system and connective tissues. Thus, the correct option is D.
Explanation:The skeletal system has multiple functions within the body. These include providing structure, facilitating movement, protecting internal organs, producing red blood cells, and producing white blood cells. These cells are crucial as they are responsible for oxygen transport around the body and defense against disease. However, producing ligaments and tendons is not a function of the skeletal system. Ligaments and tendons are part of the muscular system and connective tissues. Ligaments connect bones to each other, and tendons connect muscle to bone.
Therefore, the correct answer would be D. producing ligaments and tendons.
Learn more about skeletal system here:https://brainly.com/question/31883942
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A 6.4 kg block with a speed of 5.4 m/s collides with a 12.8 kg block that has a speed of 3.6 m/s in the same direction. After the collision, the 12.8 kg block is observed to be traveling in the original direction with a speed of 4.5 m/s. (a) What is the velocity of the 6.4 kg block immediately after the collision
Answer:
The velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.
Explanation:
Given;
mass of first block, m₁ = 6.4 kg
initial speed of first block, u₁ = 5.4 m/s
mass of second block, m₂ = 12.8 kg
initial speed of second block, u₂ = 3.6 m/s
final speed of second block, v₂ = 4.5 m/s
To determine the final speed of 6.4 kg block immediately after the collision, we apply principle of conservation linear momentum;
Total momentum before collision = Total momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
v₁ is the final speed of 6.4 kg block
v₂ is the final speed of 12.8 kg block
Substitute the given values of m₁, u₁, m₂, u₂ , v₂ and calculate v₁
6.4 x 5.4 + 12.8 x 3.6 = 6.4v₁ + 12.8 x 4.5
34.56 + 46.08 = 6.4v₁ + 57.6
80.64 = 6.4v₁ + 57.6
80.64 - 57.6 = 6.4v₁
23.04 = 6.4v₁
v₁ = 23.04 / 6.4
v₁ = 3.6 m/s
Therefore, the velocity of the 6.4 kg block immediately after the collision is 3.6 m/s in the original direction.
A uniform horizontal beam 4.0 m long and weighing 200 N is attached to the wall by a pin connection that allows the beam to rotate. It is supported by a cable that makes an Angle of 53 degrees with the horizontal. If the person of weight 350 N stands 1.50 m from the wall. Find the magnitude of the tension T in the cable. (Show your workout instead of giving the final answer).
The magnitude of the tension T in the cable is approximately 468.164 N.
To find the tension T in the cable supporting the beam, we can analyze the forces acting on the beam in equilibrium.
First, let's consider the forces acting on the beam:
1. The weight of the beam, acting downward at its center (2.0 m from the wall).
2. The tension T in the cable, acting upward and at an angle of 53 degrees with the horizontal.
3. The reaction force at the pin connection, acting horizontally to the left.
4. The vertical force exerted by the person standing on the beam, which contributes to the vertical component of the tension in the cable.
The beam is in equilibrium, so the sum of the torques about any point must be zero. Let's take moments about the pin connection at the wall.
Clockwise torques:
- Weight of the beam: [tex]\(200 \, \text{N} \times 2.0 \, \text{m}\)[/tex]
- Vertical component of the tension: [tex]\(T \times \cos(53^\circ) \times 1.5 \, \text{m}\)[/tex]
Counterclockwise torques:
- Tension in the cable: [tex]\(T \times \sin(53^\circ) \times 1.5 \, \text{m}\)[/tex]
- Vertical force exerted by the person: [tex]\(350 \, \text{N} \times 1.5 \, \text{m}\)[/tex]
Since the beam is in equilibrium, these torques must balance:
[tex]\[ 200 \, \text{N} \times 2.0 \, \text{m} + T \times \cos(53^\circ) \times 1.5 \, \text{m} = T \times \sin(53^\circ) \times 1.5 \, \text{m} + 350 \, \text{N} \times 1.5 \, \text{m} \][/tex]
Now, we can solve for T:
[tex]\[ 400 \, \text{N} + T \times \cos(53^\circ) \times 1.5 \, \text{m} = T \times \sin(53^\circ) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ 400 \, \text{N} = T \times \sin(53^\circ) \times 1.5 \, \text{m} - T \times \cos(53^\circ) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ 400 \, \text{N} = T \times (\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ T \times (\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m} = 125 \, \text{N} \][/tex]
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
Now, we can calculate T:
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{(0.7986 - 0.6206) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{0.178 \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{0.267 \, \text{m}} \][/tex]
[tex]\[ T \approx 468.164 \, \text{N} \][/tex]
So, the magnitude of the tension T in the cable is approximately 468.164 N.