A 0.025m radius toy top is spinning at a rate of 150rpm, what is the angular velocity? What is the linear velocity of the paint on the outside edge?
a doghouse has a mass of 98 kg, and the coefficient of friction between it and the ground is 0.95. what is the maximum force of friction between the doghouse and the ground?
Answer:
Maximum force of friction, F = 912.38 N
Explanation:
It is given that,
Mass of doghouse, m = 98 kg
Coefficient of friction between doghouse and the ground, μ = 0.95
We have to find the maximum force of friction between the doghouse and the ground. It is given by :
F = μ N
N = normal force = mg
F = μmg
F = 0.95 × 98 kg × 9.8 m/s²
F = 912.38 N
Hence, this is the required solution.
find the mass of a flying discus that has a net force of 1.05 newtons and accelerates at 3.5 m/s^2
Does a physicist studies cells and life cycles?
Final answer:
Physicists may delve into biological concepts through biophysics, but the study of cells and life cycles is principally a field within biology, focused on by cell biologists.
Explanation:
No, A physicist primarily studies the fundamental principles governing the universe, such as energy, force, and matter. While physics does impact biological systems by explaining behaviors of molecules in cells or assisting in the creation of medical technology, the study of cells and life cycles specifically falls within the realm of biology.
Cell biology is a branch of biology focusing on the study of cellular structures and functions and is fundamentally concerned with the life cycle of cells. Physicists may contribute to this field through biophysics or biomedical applications, such as using physics principles to describe properties of cell membranes or developing diagnostic tools like MRI machines. However, the everyday work of studying cells and their life cycles is typically performed by biologists rather than physicists.
What does the index of refraction directly measure? the angle between the incident ray and the normal line the angle between the refracted ray and the normal line the bending of light in a medium the reflection of light in a medium
Answer:
The answer is The bending of light in a medium.
Explanation:
The refractive index is the dimensionless number that expresses the relationship between the speed of light in the air and the speed of light in the densest medium, that is, the refractive index directly measures the ratio of the velocity of the light in a vacuum and the speed of light in a medium. This phenomenon occurs because the light rays follow a rectilinear path, but when they pass from one means of transport to another, it is refracted, because the light has a velocity distance according to the density of the material it passes through. The refractive index has variables that affect the measurement, which are temperature, wavelength and pressure.
A weightlifter raises a 200-kg barbell through a height of 2 m in 2.2 s. the average power he develops during the lift is
Answer:
Power, P = 1781.81 watts
Explanation:
It is given that,
Mass of the barbell, m = 200 kg
It is lifted to a height of, h = 2 m
Time taken, t = 2.2 s
We need to find the develops during the lift. We know that the pwer developed by an object is equal to the rate of doing work. Mathematically, it is given by :
[tex]P=\dfrac{W}{t}[/tex]
[tex]P=\dfrac{mgh}{t}[/tex]
[tex]P=\dfrac{200\times 9.8\times 2}{2.2}[/tex]
P = 1781.81 watts
So, the average power developed during the lift is 1781.81 watts. Hence, this is the required solution.
You are given two carts, a and
b. they look identical and you are told that they are made of the same material. you place a at rest on an air track and give b a constant velocity directed to the right so that it collides elastically with
a. after the collision, both carts move to the right, the velocity of b being smaller than what it was before the collision. what do you conclude?
In the described collision, the momentum of cart B is partially transferred to cart A due to the conservation of momentum principle. Hence, cart A starts moving and cart B slows down but continues to move to the right.
Explanation:The scenario you described relates to the physics principle of conservation of momentum. In the collision of the carts, the total momentum before the collision equals the total momentum after the collision. This is because in an elastic collision, both kinetic energy and momentum are conserved. Initially, only cart B had momentum (since it was moving), and cart A was at rest. After the collision, both carts moved to the right, indicating that some of cart B's momentum was transferred to cart A. The fact that cart B moved slower after the collision indicates that it transferred some of its initial momentum to cart A. Hence, we can conclude that cart A gained momentum while cart B lost some but kept enough to continue moving to the right.
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Why can an object still be seen when it is at absolute zero?
A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. the radius of this circle is 0.95 m. what is the minimum speed that the pail must have at the top of its circular motion if the water is not to spill out of the upside-down pail
Lena would like to be able to know her exact location on a map as she travels across the country. Which technology would best help Lena?
an example of a Destructive force is the formation of mountains True or False?
Give an example to explain that motion is relative in nature
A 92-kg astronaut and a 2000-kg satellite are at rest relative to a space station. the astronaut pushes on the satellite, giving it a speed of 0.14 m/s directly away from the station. seven and a half seconds later the astronaut comes into contact with the station. part a what was the initial distance from the station to the astronaut?
Answer:
22.8 s
Explanation:
First we calculate the change in momentum of the satellite.
ΔP = 2000 kg (0.14 m/s 0 m/s) = 280 kg·m/s
The change in momentum of the satellite is equal to the change in momentum of the astronaut as a result of Newton's Third law. Therefore:
280 kg·m/s = 92kg * v
v = 3.04 m/s
d = speed * time = 3.04 m/s * 7.5 s = 22.8 m
Which ions are most abundant in an acid?
The hydrogen ion is the most abundant in an acid for it is a bare proton that associates with any water in the molecule, solution or reaction so the H+ ions produced by an acid exist as H3O+ ions.
Moreover, in the Arrhenius theory, an acid is a substance that dissociates to produce H+ ions in solution and a base as a substance that dissociates to produce OH- ions in solution. Meanwhile, in the Bronsted-Lowery theory, an acid is considered as a proton donor.
If an object 70 millimeters high is placed 40 millimeters from a converging lens and the image is formed 120 millimeters in front of the lens on the same side as the object, what’s the height of the image?
on Earth, how many grams of mass does it take to produce a force of 1 newton?
HELP!! Physical or chemical property? For the questions..
A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?
The work input = _____. Fi × di Fi ÷ di Fo × do Fo ÷ do
explain the role that the ant and the acacia tree play in their symbiotic relationships
2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?
3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?
As per the first question we have to calculate the height at which the boulder is present.
we have been given the mass of the boulder [m] as 200 kg.
The gravitational potential energy is given as 39,000 Joule.
The gravitational potential energy at a height ' h' from the surface earth is given as P.E= mass×height×acceleration due to gravity
The value of g=9.8 m/s^2
Hence height [h][tex]=\frac{P.E}{mg}[/tex]
=[tex]\frac{39000}{200*9.8} metre[/tex]
=19.8979 metre
As per the second question we have to calculate the sped and height of the model airplane.
the mass of model airplane is 1 kg
The kinetic energy [K.E] of the airplane is 12.5 joule
we have K.E[tex]=\frac{1}{2} mass*speed^2[/tex]
K.E[tex]=\frac{1}{2}mv^2[/tex]
[tex]v^2=\frac{2K.E }{m}[/tex]
[tex]v^2=\frac{2*12.5}{1}[/tex]
[tex]v=\sqrt{25}[/tex]
v=5 m/s
Again we have to calculate the height [h]
The potential energy is given as 98 Joule.
we know that P.E= mgh
tex]h=\frac{P.E}{mg}[/tex]
=[tex]\frac{98}{1*9.8} metre[/tex]
=10 metre
A uniform bridge 20.0m long and weighing 4.00 x 10^5 N is supported by two pillars located 3.00m from each end. If a 1.96 x 10 ^4N car is parked 8.00m from one end of the bridge. How much force does each pillar exert?
The left support exerts a force of 2.0392 x 10⁵ N and the right support exerts a force of 2.1568 x 10⁵ N on the bridge. This is calculated by considering the total weight supported by the bridge and the location of the car.
Explanation:The problem you are asking about relates to static equilibrium, a concept in Physics. To find the force exerted by each pillar, we must first find the total weight supported by the bridge. The total weight is the sum of the weight of the bridge itself (4.00 x 10⁵ N) and the weight of the car (1.96 x 10^4 N), which gives us a total of 4.196 x 10⁵ N.
The location of the car changes the balance of these forces. The first pillar is 8m from the car and the second pillar is 12m from the car. To find the force on each pillar, we apply the principle that the sum of the moments about any point in a system in equilibrium is zero. Using the left pillar as the point, the moments of the bridge's weight and the car's weight are counterbalanced by the force of the right pillar:
Force_right_pillar = (Bridge_weight * Bridge_mid_point + Car_weight * Distance_from_left_pillar) / Total_bridge_length = ((4.00 x 10⁵ N * 10m) + (1.96 x 10⁴ N * 8m)) / 20m = 2.1568 x 10⁵ N.
The force exerted by the left pillar is then the total weight minus the force on the right pillar: Force_left_pillar = Total_weight - Force_right_pillar = 4.196 x 10⁵ N - 2.1568 x 10⁵ N = 2.0392 x 10⁵ N. So, the left support exerts a force of 2.0392 x 10⁵ N, and the right one exerts a force of 2.1568 x 10⁵ N.
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The forces exerted by the pillars supporting a 20.0m long and [tex]4.00 * 10^5 N[/tex] bridge with a [tex]1.96 * 10^4 N[/tex] car parked 8.00m from one end are approximately [tex]2.13 * 10^5 N[/tex] and [tex]2.07 * 10^5 N[/tex].
To find the forces exerted by each pillar on the uniform bridge, we need to consider the torque (moment of force) and the equilibrium conditions of the bridge.
Here is the step-by-step solution:
Given Data:
Length of the bridge (L) = 20.0 mWeight of the bridge [tex](W_{bridge}) = 4.00 * 10^5 N[/tex]Weight of the car [tex](W_{car}) = 1.96 * 10^4 N[/tex]Distance of each pillar from the end = 3.00 mPosition of the car from one end = 8.00 mThe two pillars provide upward forces labeled as [tex]F_L[/tex] and [tex]F_R[/tex].
1. Identify the distances to center of mass:
Center of mass of bridge from left end = 10.0 mPosition of car from left end = 8.0 m2. Set up equilibrium equations:
Since the bridge is in static equilibrium, the sum of the forces and the sum of the torques must be zero.
Sum of Vertical Forces:
[tex]F_L + F_R - W_{bridge} - W_{car} = 0\\F_L + F_R = 4.00 * 10^5 N + 1.96 * 10^4 N\\F_L + F_R = 4.196 * 10^5 N[/tex]
Sum of Torques about the left pillar (taking counterclockwise as positive):
[tex]-(W_{bridge} * 7.0 m) - (W_{car} * 5.0 m) + (F_R * 14.0 m) = 0\\-(4.00 * 10^5 N * 7.0 m) - (1.96 * 10^4 N * 5.0 m) + (F_R * 14.0 m) = 0\\-2.8 * 10^6 Nm - 9.8 * 10^4 Nm + 14 F_Rm = 0\\14 F_R = 2.898 **10^6 Nm\\F_R = 2.898 * 10^6 Nm / 14 m\\F_R = 2.07 * 10^5 N\\[/tex]
Substitute F_R back into the sum of the forces equation:
[tex]F_L + 2.07 * 10^5 N = 4.196 * 10^5 N\\F_L = 4.196 * 10^5 N - 2.07 * 10^5 N\\F_L = 2.126 * 10^5 N\\[/tex]
Result:
The forces exerted by the pillars are approximately:
[tex]F_L = 2.13 * 10^5 N\\F_R = 2.07 * 10^5 N[/tex]
How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?
If you shook the end of a rope up and down 5 times each second, what would be the period of the waves set up in the rope?
Final answer:
Shaking the rope at 5 times per second sets up waves with a frequency of 5 Hz. The period of these waves, which is the inverse of frequency, would be 0.2 seconds.
Explanation:
When you shake the end of a rope up and down 5 times each second, you are creating waves with a certain frequency. The frequency is the number of complete waves that pass a given point in one second, and it is measured in hertz (Hz). Since you're shaking the rope 5 times per second, the frequency of the waves set up in the rope is 5 Hz.
The period of a wave is the time it takes for one complete wave cycle to pass a point. It is the inverse of the frequency. To calculate the period (T), you would use the formula:
T = 1 / f, where 'f' is the frequency.
So in this case:
T = 1 / 5 Hz = 0.2 seconds.
Therefore, the period of the waves set up in the rope is 0.2 seconds.
Match the terms
Term Definition
Chromosphere A) Layer of the sun where energy is transferred by thermal conduction.
Photosphere B) Contains the sun's outer shell from which light energy is radiated.
Radiative zone C) Layer of the sun that is known for its red color and can only be seen during eclipses
Corona D) The plasma that surrounds the sun
Explanation :
(1) Chromosphere: It is a layer above the photosphere. The temperature in chromosphere increases from [tex]6000^0\ C[/tex] to [tex]20,000^0\ C[/tex]. This layer is known for its red color and can only be seen during eclipses.
(2) Photosphere: It is the outer layer of the star which contains sun's outer shell from which light energy is radiated.
(3) Radiative zone: it is a layer of sun where energy is transmitted towards via radiative diffusion or conduction.
(4) Corona: It is a plasma that surrounds the sun and the other stars.
Hence, this is the required definitions.
Answer:bdca
Explanation:
Planet B has a tilt of 45 degrees. What seasonal changes would be expected on this planet?
A. Extreme temperature changes between seasons
B. Little to no change in temperatures between seasons
C. Seasonal changes along the equator only
D. Seasonal changes at the poles only
Answer:
Extreme temperature changes between seasons
Explanation:
If our Earth is at a rotational degree of 23 degrees, then the planet is going to experience bigger changes between how hot and how cold it is going to be.
One’s behavior cannot be affected by one’s subconscious
That statement is false
Our subconscious tend to give a strong influence to our behaviours even if we are not feeling it directly.
For example, let's say that there is a boy that hurt by cats and it's ingrained in his head that cats possess high level of danger to him. Even after that boy grow up, his subsconcious would most likely cause a certain level of paranoia that make him either scared of cats or simply annoyed by seeing them.
Answer:
False is the correct answer
Explanation:
Peace and Love
Which of the following refers to a combination of substances in which the components are evenly mixed?
A. Heterogeneous mixture
B. Ion
C. Compound
D. Homogeneous mixture
Calculate the kinetic energy of an 86-kg scooter moving at 16 m/s
The kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem, we have to calculate the kinetic energy of an 86 - kilogram scooter moving at 16 m / s ,
The mass of the scooter = 86 kilogram
The velocity fo the scooter = 16 meters per second
The kinetic energy of the scooter = 0.5 × m × v²
= 0.5 × 86 × 16²
= 11008 Joules
Thus , the kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules .
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The kinetic energy of an 86-kg scooter moving at 16 m/s is calculated using the formula KE = ½ mv², resulting in 10,976 Joules or 10.976 kJ of kinetic energy.
To calculate the kinetic energy of an 86-kg scooter moving at 16 m/s, you can use the kinetic energy formula KE = ½ mv², where m is mass and v is velocity. Substituting the given values, we get KE = ½ (86 kg) (16 m/s)². After performing the calculation, the kinetic energy of the scooter is found to be 10,976 Joules or 10.976 kJ.
Which are examples of projectile motion? Check all that apply. a kicker punting a football a car traveling along a highway a free throw in basketball a ball rolling downhill a person throwing darts
A kicker punting a football, a free throw in basketball and a person throwing darts are some examples of projectile motion.
What is a projectile motion?It is the movement of any item or material when it is launched from the planet's surface and takes any curving course while being affected by the pull of gravity of the planet.
This movement style The only force affecting our objects is gravity. Different projectile kinds are available.
A football is thrown upward, being kicked and imparting speed at an angle from the horizontal, or just being dropped and allowed to fall independently are all examples of the initial velocity.
Thus, a kicker punting a football, a free throw in basketball and a person throwing darts are some examples of projectile motion.
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