which scale facor would produce an expansion under a dilation of the original image

Answers

Answer 1
I think a scale factor greater than 1

Related Questions

If r = 1, s = 2, and t = 3, what value do you expect y will have?

Answers

um the y=8???????????

a rectangular fish pond is 21 ft squared in area. if the owner can surround the pond with a 20 ft fence what are the dimensions of the pond

Answers

the dimensions are 41 ft

THE ANSWER IS 41 FEET

Which of the following graphs matches the circle defined by this equation ? (X+2)^2+(y-4)^2=9

Answers

Center (2,4)
Radius :3

This equation represents the circle having a radius of 3 units and a center situated at (-2, 4). Hence, graph D is correct.

Use the concept of a circle defined as:

A circle is a particular type of ellipse in mathematics or geometry where the eccentricity is zero and the two foci are congruent.

A circle is also known as the location of points that are evenly spaced apart from the center.

The radius of a circle is measured from the center to the edge.

The given equation of a circle is:

(X+2)²+(y-4)²= 9

Since we know that,

The general equation of the circle is,

(x-a)²+(y-b)²= r²

Where (a, b) is the center of the circle

r is the radius of the circle.

Now compare with the given equation we have,

(a, b) = (-2, 4)

And radius r² = 9

Then r = 3

Then this circle has a radius of 3 units and a center situated at (-2, 4).

Hence,

Graph D is correct.

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The complete question is:

Which of the following graphs matches the circle defined by this equation? (x-a)²+(y-b)²= r²

Find the equation of the line that has these features: slope, m=-6/5 passes through the point (-5,10)

Answers

we know that

the equation of the line is 
y-y1=m(x-x1)
then
m=-6/5 passes through the point (-5,10)
y-10=(-6/5)*(x+5)-------> y-10=(-6x/5)-6------------> y=(-6x/5)+4---------> y=-1.2x+4

see the attached figure

the answer is
y=-1.2x+4

Quadrilateral ABCD ​ is inscribed in this circle. What is the measure of angle C? Enter your answer in the box
https://static.k12.com/nextgen_media/assets/8120449-SUM_CR_GMT_SemB_06_UC_DP100_864_003.jpg

Answers

1. The sum of the opposite angles of the quadrilateral ABCD that is inscribed in the circle, is 180°. Therefore, the sum of all the angles is 360°.

 2. As you can see, m∠B=(2x-1)° and m∠D=(3x-59)° are opposite angles, then:

 m∠B+m∠D=180°

 3. When you substitute the values of m∠B and m∠D into m∠B+m∠D=180°, you obtain:

 m∠B+m∠D=180°
 (2x-1)+(3x-59)=180°

 4. You must clear the "x", as below:

 (2x-1)+(3x-59)=180°
 5x-60=180
 x=48°

 5. Now, you can find the value of m∠A, m∠B and m∠D:

 m∠A=2x+4
 m∠A=2(48)+4
 m∠A=100°

 m∠B=2x-1
 m∠B=2(48)-1
 m∠B=95°

 m∠D=3x-59
 m∠D=3(48)-59
 m∠D=85°

 6. Therefore, the value of m∠C is:

 m∠A+m∠B+m∠C+m∠D=360°
 m∠C=360-m∠A-m∠B-m∠D
 m∠C=360°-100°-95°-85°
 m∠C=80°

 What is the measure of angle C?

 The answer is: 80°

Rami sold concessions during a concert. He sold bottled water for $3.50 each and bags of trail mix for $4 each. By the end of the evening, Rami sold 400 items for a total of $1,475. How many bottles of water and how many bags of trail mix did Rami sell?

Answers

price of bottled water - $3.50 each 
price of bag of trail mix - $4 each 
number of bottles of water sold - x
number of bags of trail mix sold - y
cost spent for bottles - 3.5x
cost spent for bags - 4y
total cost;
3.5x + 4y = 1475 ----> 1)
total number of items
x + y = 400---2)
multiply 2nd equation by 4
4x + 4y = 1600 ---> 3)
Subtract third equation from the 1st 
0.5x = 125
x = 250
when x = 250
x + y = 400
250 + y = 400
y = 150
number of bottles - 250
number of bags - 150

Rami sold 250 bottles of water and 150 bags of trail mix at the concert, totaling $1,475 in sales.

To solve the problem of how many bottles of water and bags of trail mix Rami sold, we need to set up and solve a system of linear equations based on the given information.

Let's define the variables:

- [tex]\( x \)[/tex] = the number of bottles of water sold

- [tex]\( y \)[/tex] = the number of bags of trail mix sold

From the problem, we have two pieces of information that we can turn into equations:

1. The total number of items sold is 400.

2. The total revenue from the items sold is $1,475.

We can write these two statements as equations:

1. [tex]\( x + y = 400 \)[/tex]

2. [tex]\( 3.50x + 4y = 1475 \)[/tex]

We now have a system of linear equations:

[tex]\[\begin{cases}x + y = 400 \\3.50x + 4y = 1475\end{cases}\][/tex]

Step 1: Solve the first equation for [tex]\( y \)[/tex]

[tex]\[y = 400 - x\][/tex]

Step 2: Substitute [tex]\( y \)[/tex] in the second equation

Replace [tex]\( y \)[/tex] in the second equation with [tex]\( 400 - x \)[/tex]:

[tex]\[3.50x + 4(400 - x) = 1475\][/tex]

Step 3: Simplify and solve for [tex]\( x \)[/tex]

Expand and simplify the equation:

[tex]\[3.50x + 1600 - 4x = 1475\][/tex]

Combine like terms:

[tex]\[3.50x - 4x + 1600 = 1475\][/tex]

[tex]\[-0.50x + 1600 = 1475\][/tex]

Subtract 1600 from both sides:

[tex]\[-0.50x = 1475 - 1600\][/tex]

[tex]\[-0.50x = -125\][/tex]

Divide both sides by -0.50:

[tex]\[x = \frac{-125}{-0.50} = 250\][/tex]

So, Rami sold 250 bottles of water.

Step 4: Find [tex]\( y \)[/tex] using the value of [tex]\( x \)[/tex]

Substitute [tex]\( x = 250 \)[/tex] back into the first equation:

[tex]\[y = 400 - 250 = 150\][/tex]

So, Rami sold 150 bags of trail mix.

Conclusion

Rami sold:

- 250 bottles of water

- 150 bags of trail mix

To verify, we check the total revenue:

[tex]\[3.50 \times 250 + 4 \times 150 = 875 + 600 = 1475\][/tex]

The numbers match the given total revenue, confirming our solution is correct.

a small bunch of flowers costs $5 and a large bunch costs $20. what fraction of the cost of the large bunch is the small bunch

Answers

The cost of large bunch is 1/4th of the small bunch......

Hope it's helpful.....

The enrollment in college A may be modeled by y = 0.046x + 0.570, and the enrollment in college B may be modeled by y = –0.036x + 2.702, where x is the number of years since 1990 and y is the enrollment in thousands. When will the two colleges have the same enrollment and what is that enrollment?  
 In 1974, both colleges had an enrollment of 1,766 students.
   In 2016, both colleges will have an enrollment of 1,766 students.
   In 2012, both colleges will have an enrollment of 1,122 students.
   In 1992, both colleges had an enrollment of 1,600 students.

Answers

You want to know when both colleges have the same enrollment. "When" is a time thing so you are going to be solving for x. The number of students is the same and that means you will be solving for y.

Since both ys are equal, you can equate the right side of each equation to each other.

0.046 x + 0.570 = - 0.036x + 2.702 There are a number of ways to go on. The easiest is to dig out your calculator. Add 0.036x to both sides.
0.046x + 0.036x + 0.570 = 2.702
0.082x + 0.570 = 2.702    Now subtract 0.570 from both sides.
0.082x = 2.702 - 0.570
0.082x = 2.132 Divide by 0.084
x = 2.132 / 0.082
x = 26 which means you add 26 onto 1990. The year this took place was 2016 
x = 2016 (That's the year there was equality in enrollment). The second one is the only year that gives 2016 as an answer. So you don't have to find y. But we'll do it anyway. 

Now you have to solve for y
y = 0.046x +0.57 put 26 in for x
y = 0.046 * 26 + 0.570
y = 1.196 + 0.570
y = 1.766 enrollment numbers were equal, but this is in thousands.
y = 1766 enrollment in actual numbers of students.


Second choice <<<<<===== answer.

Answer:

In 2016, both colleges will have an enrollment of 1,766 students.

Step-by-step explanation:

gradpoint

Express the confidence interval (0.070, 0.126) in the form of

Answers

Express the confidence interval (0.070, 0.126) in the form of p-E
Solution 1
Let's find E
2E=(0.126-0.070)
E=(0.126-0.070)/2
E=0.056/2
E=0.028
Solution 2
Let's find U
u=(0.126+0.070)/2
u=0.196/2
u=0.098
Then:
CI=(u-E < p < u+E)
Replace the number according to the formula
CI=(0.098-0.028 < p < 0.098+0.028)

The enrollment in college a may be modeled by y = 0.051x + 0.470, and the enrollment in college b may be modeled by y = –0.041x + 1.850, where x is the number of years since 1990 and y is the enrollment in thousands. when will the two colleges have the same enrollment and what is that enrollment?

Answers

The first equation represents the enrollments of college A
The second equation represents the enrollments of college B
if you let two equation equal to each other, you can understand them as the enrollments of college A and college B at "x" year.

0.051x + 0.470 = -0.041x + 1.850
0.051x + 0.041x = 1.850 - 0.470
0.092x = 1.38
x = 1.38/0.092 = 15 years from 1990, 1990 + 15 = 2005 
both equations represents the enrollments, but for specific the year of 2005, they have the same enrollments. You can either plug 2005 in the first or second equation, the answer will come out the same.
y = 0.051(2005) + 0.470 = 102.745 thousands of enrollments. It's awkward to say it this way, you can multiply 102.745 by 1000.
==> 102.725 * 1000 = 102725 enrollements 
===================================================================
The year of 2005 college A and college B both have the same enrollments of 102725.  

In year 2005, both the colleges have same enrollments and the total number of enrollments are 1235 students.

What is Two Variable linear Equation?

An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.

Here, given relation between enrollment year and total number of enrollment

y = 0.051x + 0.470 ..............(i)

y = -0.041x + 1.850 ................(ii)

On comapring eq. (i) and eq. (ii), we get

0.051x + 0.470 = -0.041x + 1.850

0.051x + 0.041x = 1.850 - 0.470

0.092x = 1.380

x = 1.380 / 0.092

x = 15

put the value of x in equation (i), we get

y = 1235

Thus, In year 2005, both the colleges have same enrollments and the total number of enrollments are 1235 students.

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A full bag of dog food weighs 5 1 2 pounds. How much dog food do you have if there are 3 3 4 bags in the cupboard

Answers

now, we know there are 3 and 3/4 bags in the cupboard, and each one of them weights 5 and 1/2 lbs, so the amount in the cupboard is just their product.

now, let's firstly convert the mixed fractions to "improper" and do the product after,

[tex]\bf \stackrel{mixed}{5\frac{1}{2}}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}} \\\\\\ \stackrel{mixed}{3\frac{3}{4}}\implies \cfrac{3\cdot 4+3}{2}\implies \stackrel{improper}{\cfrac{15}{4}}\\\\ -------------------------------\\\\ \cfrac{11}{2}\cdot \cfrac{15}{4}\implies \cfrac{165}{8}\implies \stackrel{lbs}{20\frac{5}{8}}[/tex]

The dog food we have if there are 3 3 4 bags in the cupboard is 20 5/8 pounds

What are proper and improper fractions and how to convert mixed fractions to simple fractions?

A fraction represents a part of a number or any number of equal parts.

There is a fraction, containing a numerator(upper value) and denominator(lower value). When the numerator is less than the denominator, the fraction is called a proper fraction, otherwise, it is called an improper fraction. A proper fraction is also called a fraction that is less than 1. And an improper fraction is ≥ 1. A mixed fraction contains a sum of whole numbers and a proper fraction.

We have been given that a full bag of dog food weighs [tex]5\dfrac{1}{2}[/tex]  pounds.

First, we need to convert mixed fractions into simple fractions;

[tex]5\dfrac{1}{2}[/tex]  = 11/2

Also,  [tex]3\dfrac{3}{4}[/tex] = 15/4

Therefore, we know there are 3 and 3/4 bags in the cupboard, and each one of them weighs 5 and 1/2 lbs, thus the total amount in the cupboard is just their product.

[tex]5\dfrac{1}{2}[/tex]  × [tex]3\dfrac{3}{4}[/tex]

11/2  × 15/4

= [tex]20\dfrac{5}{8}[/tex]

Hence, The dog food we have if there are 3 3 4 bags in the cupboard is 20 5/8 pounds.

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A pentagon has angle measures of 102°, 100°, 115° and 110°. What must the fifth angle measure?

Answers

Pentagon angles add up to 540°. So we subtract all angles above from 540° to find the fifth angle.

540 - 102- 100 - 115 - 110= 113°

ANSWER:
The fifth angle measures 113°.

Hope this helps! :)

A pentagon has angle measures of 102°, 100°, 115°, and 110°. Therefore, The fifth angle measures 113°.

What is the sum of angles in pentagon?

The sum of all the angles of Pentagon angles is 540°.

A pentagon has angle measures of 102°, 100°, 115°, and 110°.

To find the fifth angle so we subtract all angles above from 540°

102 + 100 + 115 + 110 = 540

540 - 102- 100 - 115 - 110 = 113°

Therefore, The fifth angle measures 113°.

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A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches. What is the ratio of the area of the school banner to the area of the sign? $$

Answers

Answer:

   2916/289 = 10 26/289 ≈ 10.09

Step-by-step explanation:

The ratio of areas of similar figures is the square of the scale factor. Here, the scale factor is the ratio of lengths, so is ...

  k = banner/sign = 54/17

The ratio of areas is k² = (54/17)² = 2916/289 = 10 26/289 ≈ 10.09

Final answer:

The ratio of the area of the school banner to the area of the sign is approximately 3.36:1. This was calculated by first finding the areas of both the banner and the sign, and then dividing the area of the banner by the area of the sign.

Explanation:

The subject of this question falls under Mathematics, and it deals with the concept of ratio and similar figures. In this case, the figures are a school banner and a sign, both of which are rectangular in shape. The ratio of their areas can be determined by calculating the areas of both figures and then finding the ratio of the two values.

Firstly, let's calculate the area of the school banner. The area of a rectangle is calculated by multiplying its length by its width. Therefore, the area of the school banner = 54 inches (length) * 36 inches (width) = 1944 square inches.

Next, the sign's width isn't given, but because the two shapes are similar, the ratio of the banner's length to its width is equal to the ratio of the sign's length to its width. So, if we let 'w' be the width of the sign, then 54/36 = 17/w. Solving this for 'w', the width of the sign = [tex](17 * 36) / 54 = 17*2 = 34[/tex] inches. The area of the sign, then, is 17 inches (length) * 34 inches (width) = 578 square inches.

To get the ratio of the school banner's area to the sign's area, divide 1944 by 578, which equals approximately 3.36. Therefore, the ratio of the areas is 3.36:1. Meaning for every square inch of the sign, there are approximately 3.36 square inches of the school banner.

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The angle a vector makes with the x-axis of a coordinate system must be what size in order to make one or more of its components negative? A) Less the 30 degrees B) between 30 and 60 degrees C) between 61 and 90 degrees D) greater then 90 degrees

Answers

D) greater than 90 degrees

_____
An angle greater than 90 degrees will put it in the second quadrant, where the x-component is negative.

Answer:

Greater than 90 degrees.

Step-by-step explanation:

Let a vector R make angle [tex]\theta[/tex] with the x-axis. Then, the component along the x-axis would be

[tex]R cos\theta[/tex]

Component along y-axis would be

[tex]R sin\theta[/tex]

For [tex]0<\theta<90[/tex] both the components will be positive and lie in the first quadrant. If angle of vector is more than 90 degrees, one of the components would be negative. For example, angle between 90 to 180 degrees, x-component would be negative while between 180-270 degrees, both the components would be negative.

Two sides of a triangle are equal in length, and the third side is 5 inches. If the perimeter is 17 inches, how long are the two equal sides?

Answers

You know the length of one side is 5in and are trying to find the length of the other two side (which, conveniently, are equal!). 

Perimeter of a triangle can be found by adding up all three sides of the triangle. That means if you know the length of one side, subtracting that length from the perimeter gives you the length of the other two sides added up. So:
[tex]P = s1 + s2 + s3 [/tex]
[tex]17 = 5 + s2 + s3 [/tex]
[tex]12 = s2 + s3[/tex]

Since you know the two mystery sides are the same length, just divide 12 by 2. 12/2 = 6in. That means each one of the two equal sides is 6in long.

I Need help please cmon

Answers

there are 3 "x" above the 3/4 mark, meaning there are 3 buttons that are 3/4 of an inch, now if she lines them up, what is their length total?

[tex]\bf \cfrac{3}{4}+\cfrac{3}{4}+\cfrac{3}{4}\implies \cfrac{3+3+3}{4}\implies \cfrac{9}{4}\implies 2\frac{1}{4}[/tex]

Read the line of poetry:


And the dish ran away with the spoon.


This line is an example of what term?


A.
alliteration

B.
personification

C.
onomatopoeia

D.
imagery

Please help I AM SO SCARED IF I FAIL THIS...

Answers

I know it is b I had this I had this question before

2, 3, 6, 8, . . . is an example of an infinite alternating series. True False

Answers

Answer: False.

Explanation: An alternating series is on in which the alternate terms are negative & positive.
Example, 1/2 − 1/4 + 1/8 − 1/16 + ⋯  is an alternating series.

but here, in the given series - all numbers are positive . Hence, it is not an infinite alternating series.

Answer:

false

Step-by-step explanation:

took the test

A particle moves along the x-axis in such a way that its velocity at any time t > 0 is given by v(t)=3t^2-4t-4. the particl's position x(t) has a value of 1 when t=1

Answers

what's the question here?

what fraction of the letters in the word MUSHROOM are not vowels? show me how you got the answer please

Answers

5/8 because their is 8 letters and there is 3 that you underlined vowels 5 of them are not a vowel 
There are 8 letters in the word 'mushroom'. Out of these letters, 3 are vowels and the other 5 are consonants (not vowels). Therefore, 5/8 of the letters in the word 'mushroom' are not vowels.

There are 18 students enrolled in Mr. Baker's class. Today 3 of them are absent. What is the ratio of the number of students present in class today to the total number enrolled?

Answers

Answer:

5/6

Step-by-step explanation:18 total -3 absent = 15

15 divided by 3

18 divided by 3=

5/6

The ratio for the given two numbers is 5 : 6.

What is the application ratio and proportion?

A ratio is the relation between two numbers as a / b. A proportion is the equality of two ratios as a / b = c / d.

Ratio and proportion can be applied to solve Mathematical problems dealing with unit values of the quantities.

The total number of students are given as 18.

And, the number of students absent is 3.

Then, the number of present students is given as 18 - 3 = 15.

Now, the ratio as per the given case can be obtained as follows,

Number of students present ÷ Number of enrolled students

⇒ 15 ÷ 18

⇒ 15/18

⇒ 5 : 6

Hence, the required ratio for the two numbers is 5 : 6.

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ABCD and JKLM are similar rectangles. What is the perimeter of JKLM?

21 m

22 m

24 m

28 m

Answers

SCale factor is ML/DC = 6/4 = 3/2

So multiply AD by 3/2 to find the length of JM . The length would be 3*3/2=9/2

Next find the perimeter of JKML. It would be 2(9/2+6)=21

Answer:

Step-by-step explanation:

21

A random variable x that assumes the values x1, x2, . . . , xk is called a discrete uniform random variable if its probability mass function is f(x) = 1 k for all of x1, x2, . . . , xk and 0 otherwise. find the mean and variance of x.

Answers

Recall that for a random variable [tex]X[/tex] following a discrete distribution, the expectation of [tex]X[/tex] is given by

[tex]\mathbb E[X]=\displaystyle\sum_x x\,f_X(x)[/tex]

where [tex]f_X(x)=\mathbb P(X=x)[/tex] is the PMF of [tex]X[/tex]. We have

[tex]f_X(x)=\begin{cases}\dfrac1k&\text{for }x\in\{x_1,\ldots,x_k\}\\\\0&\text{otherwise}\end{cases}[/tex]

So the expectation (mean) of the given uniformly distributed [tex]X[/tex] is

[tex]\mathbb E[X]=\displaystyle\sum_x x\,f_X(x)=\sum_{i=1}^k x_i\,f_X(x_i)=\frac1k\sum_{i=1}^k x_i[/tex]

Without any more specific information, this is all we can say about the mean.

The variance of [tex]X[/tex] is defined by

[tex]\mathbb V[X]=\mathbb E[(X-\mathbb E[X])^2]=\mathbb E[X^2]-\mathbb E[X]^2[/tex]

In computing the second moment [tex](\mathbb E[X^2])[/tex] we run into the same issue as before - we can't find a "complete" result - but we do get

[tex]\mathbb E[X^2]=\displaystyle\sum_x x^2\,f_X(x)=\frac1k\sum_{i=1}^k{x_i}^2[/tex]

and so

[tex]\mathbb V[X]=\displaystyle\frac1k\sum_{i=1}^k{x_i}^2-\left(\frac1k\sum_{i=1}^kx_i\right)^2[/tex]

We can expand [tex]\mathbb E[X]^2[/tex] a bit. Denoting the set [tex]K=\{1,2,\ldots,k\}[/tex], we can write

[tex]\displaystyle\left(\frac1k\sum_{i=1}^kx_i\right)^2=\frac1{k^2}\left(\sum_{i=1}^k{x_i}^2+\sum_{i,j\in K,\,i\neq j}x_ix_j\right)[/tex]

and so

[tex]\mathbb V[X]=\displaystyle\left(\frac1k-\frac1{k^2}\right)\sum_{i=1}^k{x_i}^2-\frac1{k^2}\sum_{i,j\in K,\,i\neq j}x_ix_j[/tex]
[tex]\mathbb V[X]=\displaystyle\frac{k-1}{k^2}\sum_{i=1}^k{x_i}^2-\frac1{k^2}\sum_{i,j\in K,\,i\neq j}x_ix_j[/tex]

but again, that's as much as we can say without any more specific information.
Final answer:

A discrete uniform random variable has values which are equally likely to occur. The mean can be calculated by summing all the values of the variable and dividing by the number of values, represented as μ = Σx/k. The variance, a measure of dispersion, can be calculated using the formula σ² = Σ(x − μ)²/k.

Explanation:

In the context of a discrete uniform random variable, the mean (μ) and variance (σ²) can be calculated using specific formulas. This is related to the nature of a discrete uniform distribution, where x assumes the values x1, x2, ..., xk, and the probability of each outcome is equally likely.

Firstly, to find the mean

you simply need to add up all the values of x and divide by the number of values (k). This could be represented as μ = Σx/k.

Secondly, the variance can be calculated using the formula σ² = Σ(x − μ)²/k. In this equation, x represents the values of the random variable, μ is the mean (which we calculated earlier), and k represents the total number of values.

The concept here is essentially determining the central tendency (mean) and dispersion (variance) of a discrete uniform random variable. This is a fundamental topic in the field of probability and statistics.

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Why is partitioning a directed line segment with a ratio of 1:2 not the same as finding half the length of the directed line segment

Answers

The ratio would need to be 1:1 in order to split the line in half. Think of it like having two cookies. If you split those cookies between you and your friend, then you get 1 and s/he gets the other. So the ratio of your cookie count to your friend's count is 1:1

With the ratio 1:2, you would have 1 cookie while your friend has 2 cookies. This is no longer a fair split. Things are not 50/50 anymore. You have 1/3 of the cookies while your friend has 2/3 of the cookies. Your friend would have twice as much.

So that applies to the segment lengths as well. The line segment would be split up into two parts A and B. Part A is the smaller segment that is half as long as part B. Or put another way, part B is twice as long as part A

Answer:

Sample response: A ratio of 1:2 means that there are 3 parts in total. One part will be before the desired point, and 2 parts will be after the desired point. This is the same as finding the point that is 1/3 the length. Half the length of the segment would mean there would only be two pieces, each of equal size.

Step-by-step explanation:

A box contains 13 ​transistors, 5 of which are defective. if 5 are selected at​ random, find the probability that
a. all are defective.
b. none are defective.

Answers

Answer:

A. 1/1287

B. 56/1287

Step-by-step explanation:

Probability of getting all are defective transistors is 5/12.

Given that, a box contains 13 ​transistors, 5 of which are defective.

What is the probability?

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

We know that, probability of an event = Number of favorable outcomes/Total number of outcomes

a) Probability of getting all are defective

Number of favorable outcomes = 5

Total number of outcomes = 12

Probability of getting all are defective = 5/12

b) Probability of getting none are defective

Number of favorable outcomes = 7

Total number of outcomes = 12

Probability of getting none are defective = 7/12

Therefore, probability of getting all are defective transistors is 5/12.

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The table below shows the total cost for purchasing a certain number of equally-priced concert tickets. Total cost (in dollars) Number of concert tickets. the total costs in dollars are 110 275 440. the number in concert tickets are 2, 5, 8 Write an equation to describe the relationship between the total cost in dollars (c), and the number of tickets purchased (t),

Answers

Answer:

c = 55t

Step-by-step explanation:

Since there are no handling fees and the price of tickets is constant, we know the cost will be proportional to the number of tickets purchased. The generic form of an equation expressing a proportional relationship between cost (c) and number of tickets (t) is ...

c = kt

where k is the constant of proportionality (the cost per ticket). We can find k by using any of the data points given in the table. Using the first point, we have ...

110 = k·2

110/2 = k = 55 . . . . . divide by 2

Then using this value for k, the desired equation can be written ...

c = 55t

PLZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPP!

Using similarity solve for x. Show all work.

Answers

we know that
see the attached figure with letters 

applying the Pythagorean theorem

in the triangle ABE
BE²=x²-9²------------> equation 1

in the triangle ABD
BD²=(16+9)²-x²--------> BD²=25²-x²-----------> equation 2

in the triangle BED
BD²=(BE)²+16²--------------> equation 3

I substitute 1 and 2 in 3
25²-x²=x²-9²+16²------> 25²+9²-16²=2x²-------> 2x²=450--------> x²=225
x=√225--------> x=15 cm

the answer is x=15 cm


is this correct....help me with the 2 questions

Answers

Yes I believe that these are correct

someone help me on this question please

Answers

The proportion
  peanuts : raisins : chocolate chips = 4 : 6 : 2
tells you that peanuts make up
  4/(4+6+2) = 1/3
of the total quantity of the mix.

The quantity of peanuts required is (1/3)*(48 ounces) = 16 ounces (or 1 pound).

_____
In the 48 ounces of mix, 1 part = 4 ounces.

Zach has 53 flowers to plant. he wants to plant them in groups of 10s and 1s. zach can plant 10 flowers in each flower box. He can plant 1 flower in each pot. Zach only wants to plant a group of ten flowers in each box. Is there any way that zach could plant all 53 flowers using boxes only? Explain your answer.

Answers

No, he can not use boxes only

Solution:

we are given that

Zach has 53 flowers to plant.

He wants to plant them in groups of 10s and 1s.

zach can plant 10 flowers in each flower box.

Zach only wants to plant a group of ten flowers in each box.

We have been asked to find  Is there any way that zach could plant all 53 flowers using boxes only?

since zach can plant 10 flowers in each flower box. so in 5 boxes he can plant

50 flowers.

Now we have 3 left. These 3 can be planted in pot.

But he wants to use boxes only with 10 flowers in each box.

So its not possible to plant all 53 flowers using boxes only.


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