Which sequence is modeled by the graph below?

coordinate plane showing the points 2, 9; 3, 3; and 4, 1
A) an = one third(27)n − 1
B) an = 27(one third)n − 1
C) an = 1(−3)n − 1
D) an = 3(one half)n − 1

Answers

Answer 1

Answer:

an=27(one third) - 1

thanks

Answer 2
Answer:

The correct answer is:

                Option: B

   [tex]B.\ a_n=27(\dfrac{1}{3})^{n-1}[/tex]

Step-by-step explanation:

We are given that the graph passes through (2,9) , (3,3) and (4,1)

Now, the function which models the graph is given by:

[tex]a_n=27(\dfrac{1}{3})^{n-1}[/tex]

when n=2 we have:

[tex]a_2=27(\dfrac{1}{3})^{2-1}\\\\i.e.\\\\a_2=27(\dfrac{1}{3})^1\\\\i.e.\\\\a_2=9[/tex]

when n=3 we have:

[tex]a_3=27(\dfrac{1}{3})^{3-1}\\\\i.e.\\\\a_3=27(\dfrac{1}{3})^2\\\\i.e.\\\\a_3=3[/tex]

when n=4 we have:

[tex]a_3=27(\dfrac{1}{3})^{4-1}\\\\i.e.\\\\a_3=27(\dfrac{1}{3})^3\\\\i.e.\\\\a_4=1[/tex]


Related Questions

The yearly profit or loss for a clothing store is shown for a period of three years. Use a calculator to determine the clothing strore’s overall profit or loss in the three years.

Answers

Answer:

  loss of $12,481.38

Step-by-step explanation:

It is usually a good idea to follow directions. (See attached.)

The sum of the three profit values is -$12,481.38, indicating a loss in the 3-year period.

Use point slope formula to find the equation perpendicular to y=-2x+9 passing through the points (0,7)

Answers

Answer:

y-7 = 1/2x point slope form

y = 1/2x+7  slope intercept form

Step-by-step explanation:

y=-2x+9

This equation is in the form y= mx +b so the slope is -2

We want a line perpendicular

Take the negative reciprocal

m perpendicular is - (-1/2)

m perpendicular = 1/2

We have a slope of 1/2 and a point.  We can use point slope form

y-y1 = m(x-x1)

y-7 = 1/2(x-0)  point slope form

y-7 = 1/2x

Adding 7 to each side

y-7+7 =1/2x +7

y = 1/2x+7  slope intercept form

HELPPPP
How would you write the following expression as a sum or difference?

Answers

Answer:

  see below

Step-by-step explanation:

The applicable rules of logarithms are ...

  log(a^b) = b·log(a)

  log(a/b) = log(a) -log(b)

___

The expression can be rewritten as ...

[tex]\log{\dfrac{\sqrt[3]{2-x}}{3x}}=\log{\sqrt[3]{2-x}}-\log{3x}=\dfrac{1}{3}\log{(2-x)}-\log{(3x)}[/tex]

The expression can be written as a sum or difference as:

[tex]$$\boxed{\frac{1}{3} \log(2-x) - \log(3x)}$$[/tex]

How would you write the following expression as a sum or difference?

To write the expression [tex]$\log(\frac{\sqrt[3]{2-x}}{3x})$[/tex] as a sum or difference, we can use the following logarithmic identities:

[tex]$\log(a/b) = \log(a) - \log(b)$[/tex]

[tex]$\log(a^n) = n \log(a)$[/tex]

First, we can use the first identity to split the logarithm of the fraction into two logarithms:

[tex]$$\log(\frac{\sqrt[3]{2-x}}{3x}) = \log(\sqrt[3]{2-x}) - \log(3x)$$[/tex]

Next, we can use the second identity to expand the logarithm of the cube root:

[tex]$$\log(\sqrt[3]{2-x}) = \log((2-x)^{1/3}) = \frac{1}{3} \log(2-x)$$[/tex]

Substituting this back into the first expression, we get:

[tex]$$\log(\frac{\sqrt[3]{2-x}}{3x}) = \frac{1}{3} \log(2-x) - \log(3x)$$[/tex]

Therefore, the expression can be written as a sum or difference as:

[tex]$$\boxed{\frac{1}{3} \log(2-x) - \log(3x)}$$[/tex]

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find all solutions of each equation on the interval 0 ≤ x < 2 pi.
tan^2 x sec^2 x +2 sec^2 x - tan^2 x=2
SOMEONE PLEASE HELPPP!!

Answers

Answer:

[tex]x = 0 , \pi , 2\pi[/tex]

Step-by-step explanation:

The given equation is:l

[tex] \tan^{2} (x) \sec^{2} x + 2 \sec^{2} x - \tan^{2} x = 2[/tex]

Add -2 to both sides of the equation to get:

[tex] \tan^{2} (x) \sec^{2} x + 2 \sec^{2} x - \tan^{2} x - 2 = 0[/tex]

We factor the LHS by grouping.

[tex]\sec^{2} x(\tan^{2} (x) + 2 ) - 1( \tan^{2} x + 2) = 0[/tex]

[tex](\sec^{2} x - 1)(\tan^{2} (x) + 2)= 0[/tex]

We now apply the zero product property to get:

[tex](\sec^{2} x - 1) = 0 \: \: or \: \: (\tan^{2} (x) + 2)= 0[/tex]

This implies that:

[tex]\sec^{2} x = 1 \: \: or \: \: \tan^{2} (x) = - 2[/tex]

[tex] \tan^{2} (x) = - 2 \implies \tan(x) = \pm \sqrt{ - 2} [/tex]

This factor is never equal to zero and has no real solution.

[tex]\sec^{2} x = 1[/tex]

This implies that:

[tex]\sec \: x= \pm\sqrt{1} [/tex]

[tex] \sec(x) = \pm - 1[/tex]

Recall that

[tex] \frac{1}{ \sec(x) } = \cos(x) [/tex]

We reciprocate both sides to get:

[tex] \cos(x) = \pm1[/tex]

[tex]\cos x = 1 \: or \: \cos x = - 1[/tex]

[tex]\cos x = 1 \implies \: x = 0 \: or \: 2\pi[/tex]

[tex]\cos x = - 1 \implies \: x = \pi[/tex]

Therefore on the interval

[tex]0 \leqslant x \leqslant 2\pi[/tex]

[tex]x = 0 , \pi , 2\pi[/tex]

Drag the tiles to the correct boxes to complete the pairs.
Match the subtraction expressions to their correct answers.

Answers

Answer:

Each part is solved and working is shown  

Step-by-step explanation:

1)

[tex]-6\displaystyle\frac{4}{9}-3\displaystyle\frac{2}{9}-8\displaystyle\frac{2}{9}\\\\= -\displaystyle\frac{58}{9}-\displaystyle\frac{29}{9}-\displaystyle\frac{74}{9}\\\\= -\displaystyle\frac{161}{9}\\=-17\displaystyle\frac{8}{9}[/tex]

2)

[tex]-12.48-(-2.99) -5.62\\=-12.48 + 2.99 -5.62 \\=-15.11[/tex]

3)

[tex]-19\displaystyle\frac{2}{9}-4\displaystyle\frac{1}{9}+3\displaystyle\frac{4}{9}\\\\= -\displaystyle\frac{173}{9}-\displaystyle\frac{37}{9}+\displaystyle\frac{31}{9}\\\\= -\displaystyle\frac{179}{9}\\=-19\displaystyle\frac{8}{9}[/tex]

4)

[tex]-353.92 - (-283.56) - 131.29\\= -353.92 + 283.56 - 131.29\\= -201.65[/tex]

5)

[tex]83\displaystyle\frac{1}{5}-108\displaystyle\frac{2}{5} + 99\displaystyle\frac{1}{5}\\\\= \displaystyle\frac{416}{5}-\displaystyle\frac{542}{5}+\displaystyle\frac{496}{5}\\\\= -\displaystyle\frac{370}{5}\\= 74[/tex]

Answer:

Step-by-step explanation:

All rhombus have all sides that are equal in length but which one are rhombus or not. Need help on this. ​

Answers

Answer:

I think that the first one is not a rhombus but the last two are.

Find the cosine of angle Z

Answers

Answer:

[tex]cosZ=\frac{3}{5}[/tex]

Step-by-step explanation:

Cos of an angle by definition of its ratio is side adjacent/hypotenuse.  The side adjacent to angle Z cannot be the hypotenuse, so it has to be 6.  The hypotenuse is 10.  Therefore,

[tex]cosZ=\frac{6}{10}=\frac{3}{5}[/tex]

Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.

A.) 3
B.) 1/3
C.) -1/3
D.) -3

Answers

Answer:

-3 is the value of k in g(x)=kf(x)

Step-by-step explanation:

Both functions cross nicely at x=-3 so I'm going to plug in -3 for x:

g(x)=kf(x)

g(-3)=kf(-3)

To solve this for k we will need to find the values for both g(-3) and f(-3).

g(-3) means we want the y that corresponds to x=-3 on the curve/line of g.

g(-3)=-3

f(-3) means we want the y that corresponds to x=-3 on the curve/line of f.

f(-3)=1

So our equation becomes:

g(-3)=kf(-3)

-3=k(1)

-3=k

So k=-3.

This is about interpretation of graphs.

Option C is correct.

From the graph, we can see the 2 lines representing function f(x) and function g(x).

Now for us to find the value of x in g(x) = k⋅f(x), we need get a mutual x-coordinate where we can easily read their respective y-coordinate values.

We see that the best point for that is where x = -3.

For f(x), when x = -3, y = 1For g(x), when x = -3, y = -3

we can rewrite them as;

x = -3, f(-3) = 1 and x = -3, g(-3) = -3

Let us plug in the relevant values into g(x) = k⋅f(x) to get;

-3 = k(1)

Thus; k = -1/3

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In the diagram, transversal t cuts parallel lines a and b. Which equation is necessarily true?

A.
m∠1 = m∠7

B.
m∠3 = m∠6

C.
m∠5 + m∠8 = 90°

D.
m∠6 + m∠7 = 180°

Answers

B is the correct answer

Answer:

The correct answer is option B.  

m<3 = m<6

Step-by-step explanation:

From the figure we an see that, a and b are parallel lines and line t is the traversal on the lines.

To find the correct option

From the given figure we get

Corresponding angles are,

<1 & <5,  <2&<6, <2&<7 and <4 &<8

Alternate interior angles are,

<3 & <6  and <4 &<5

Alternate interior angles are equal.

m<3 = m<6

Therefore the correct answer is optionB

Only the function represented by graph has an inverse function.

Answers

Answer:

  2

Step-by-step explanation:

Only graph 2 shows a function that passes the horizontal line test. The other graphs will cross a horizontal line multiple times, meaning the function does not have an inverse.

Answer:

Graph 2: the linear function.

Step-by-step explanation:

A function is invertible if its bijective: injective and surjective at the same time. But, graphically exist the horizontal line test to know if the function is injective,  i.e., one to one: one element of the domain has a unique element in the image set.

So, in this case, the only function that can be cut once by a imaginary horizontal line is graph number 2. If we draw a horizontal line in other options, it will cut them in more than one point, meaning that they are not injective, therefore, not invertible.

The mean number of births per minute in a country in a recent year was about three. Find the probability that the number of births in any given minute is​ (a) exactly four​, ​(b) at least four​, and​ (c) more than four.

Answers

Final answer:

To find the probability, we use the Poisson probability formula with a mean of three. The probability of exactly four births is 0.168, the probability of at least four births is 0.361, and the probability of more than four births is 0.193.

Explanation:

To find the probability in each case, we will use the Poisson probability formula since the number of births per minute in a country follows a Poisson distribution with a mean of three.

(a) Exactly four births in a minute:

The probability of exactly four births in a minute can be calculated using the Poisson probability formula:

P(X = 4) = (e⁻³* 3⁴) / 4! = 0.168

(b) At least four births in a minute:

The probability of at least four births in a minute is the complement of the probability of having three or fewer births in a minute:

P(X ≥ 4) = 1 - P(X ≤ 3) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)) = 1 - (0.049 + 0.147 + 0.221 + 0.222) = 0.361

(c) More than four births in a minute:

The probability of more than four births in a minute is the complement of the probability of having four or fewer births in a minute:

P(X > 4) = 1 - P(X ≤ 4) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)) = 1 - (0.049 + 0.147 + 0.221 + 0.222 + 0.168) = 0.193

NEED HELP!!!
see picture*****

Answers

Answer:

1. -10

2. [tex]x=1\pm\sqrt{2}i[/tex]

3. -1+2i

4. -3-7i

5. 13

6. rectangular coordinates are (-4.3,-2.5)

7. rectangular coordinates are (-2.5,4.3)

8. x^2 + y^2 = 8y

9. Polar coordinates of point (-3,0) are  (3,180°)

10. Polar coordinates of point (1,1) are  (√2,45°)

Step-by-step explanation:

1) Simplify (2+3i)^2 + (2-3i)^2

Using formula (a+b)^2 = a^2+2ab+b^2

=((2)^2+2(2)(3i)+(3i)^2)+((2)^2-2(2)(3i)+(3i)^2)

=(4+12i+9i^2)+(4-12i+9i^2)

We know that i^2=-1

=(4+12i+9(-1))+(4-12i+9(-1))

=(4+12i-9)+(4-12i-9)

=(-5+12i)+(-5-12i)

=5+12i-5-12i

=-10

2. Solve x^2-2x+3 = 0

Using quadratic formula to find value of x

a=1, b=-2 and c=3

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(3)}}{2(1)}\\x=\frac{2\pm\sqrt{4-12}}{2}\\x=\frac{2\pm\sqrt{-8}}{2}\\x=\frac{2\pm2\sqrt{-2}}{2}\\x=\frac{2\pm2\sqrt{2}i}{2}\\x=2(\frac{1\pm\sqrt{2}i}{2})\\x=1\pm\sqrt{2}i[/tex]

3. If u =1+3i and v =-2-i what is u+v

u+v = (1+3i)+(-2-i)

u+v = 1+3i-2-i

u+v = 1-2+3i-i

u+v = -1+2i

4. if u = 3-4i and v = 3i+6 what is u-v

u-v = (3-4i)-(3i+6)

u-v = 3-4i-3i-6

u-v = 3-6-4i-3i

u-v = -3-7i

5. if u=(3+2i) and v=(3-2i) what is uv?

uv = (3+2i)(3-2i)

uv = 3(3-2i)+2i(3-2i)

uv = 9-6i+6i-4i^2

uv = 9-4i^2

i^2=-1

uv = 9-4(-1)

uv = 9+4

uv = 13

6. Convert (5, 7π/6)  to rectangular form

To convert polar coordinate into rectangular coordinate we use formula:

x = r cos Ф

y = r sin Ф

r = 5, Ф= 7π/6

x = r cos Ф

x = 5 cos (7π/6)

x = -4.3

y = r sin Ф

y = 5 sin (7π/6)

y = -2.5

So rectangular coordinates are (-4.3,-2.5)

7. Convert (5, 2π/3)  to rectangular form

To convert polar coordinate into rectangular coordinate we use formula:

x = r cos Ф

y = r sin Ф

r = 5, Ф= 2π/3

x = r cos Ф

x = 5 cos (2π/3)

x = -2.5

y = r sin Ф

y = 5 sin (2π/3)

y = 4.33

So rectangular coordinates are (-2.5,4.33)

8. Convert r=8cosФ to rectangular form

r.r = (8 cos Ф)r

r^2 = 8 (cosФ)(r)

Let (cosФ)(r) = y and we know that r^2 = x^2+y^2

x^2 + y^2 = 8y

9. Convert(-3,0) to polar form

We need to find (r,Ф)

r = √x^2+y^2

r = √(-3)^2+(0)^2

r =√9

r = 3

and tan Ф = y/x

tan Ф = 0/-3

tan Ф = 0

Ф = tan^-1(0)

Ф = 0°

As Coordinates are in 2nd quadrant, so add 180° in the given angle

0+180 = 180°

So,Polar coordinates of point (-3,0) are  (3,180°)

10) Convert (1,1) to polar form

We need to find (r,Ф)

r = √x^2+y^2

r = √(1)^2+(1)^2

r =√2

and tan Ф = y/x

tan Ф = 1/1

tan Ф = 1

Ф = tan^-1(1)

Ф = 45°

As Coordinates are in 1st quadrant, so Ф will be as found

So,Polar coordinates of point (1,1) are  (√2,45°)

Pizza delivery times at Pizza Time are normally distributed with a mean time of 27 minutes and a standard deviation of 3 minutes. Using the empirical rule, approximately what percent of pizzas are delivered between 24 and 30 minutes?

32%
68%
95%
99.7%

Answers

Answer: Second Option

68%

Step-by-step explanation:

First we calculate the Z-scores

We know the mean and the standard deviation.

The mean is:

[tex]\mu=27[/tex]

The standard deviation is:

[tex]\sigma=3[/tex]

The z-score formula is:

[tex]Z = \frac{x-\mu}{\sigma}[/tex]

For x=24 the Z-score is:

[tex]Z_{24}=\frac{24-27}{3}=-1[/tex]

For x=30 the Z-score is:

[tex]Z_{30}=\frac{30-27}{3}=1[/tex]

Then we look for the percentage of the data that is between [tex]-1 <Z <1[/tex] deviations from the mean.

According to the empirical rule 68% of the data is less than 1 standard deviations of the mean.  This means that 68% of pizzas are delivered between 24 and 30 minutes

The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how long is the diagonal in meters? Round your answers to the nearest tenth.​

Answers

I hate rounding.

Let's call the diagonal x.  It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

[tex]x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})[/tex]

Only the positive value makes any sense for this problem, so we conclude

[tex]x = \frac 1 2(9 \pm \sqrt{329})[/tex]

That's the exact answer.  Did I mention I hate rounding?  That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent.  By the Pythagorean Theorem the diagonal satisfies

[tex]x^2 = (x-4)^2 + (x-5)^2[/tex]

which works out to

[tex]x=9 \pm 2\sqrt{10}[/tex]

That's not consistent with the first answer; this problem really has no solution.  Tell your teacher to get better material.

Final answer:

To find the length of the diagonal, we can use the formula for the area of a rectangle and quadratic equation. By substituting the given values and solving for D, we can find the length of the diagonal.

Explanation:

To solve this problem, we can use the formula for the area of a rectangle: length * width = area. Let's represent the length of the rectangle as L, the width as W, and the diagonal as D. According to the problem, L = D - 4 and W = D - 5, and the area is given as 82 m2. We can substitute these values into the formula and solve for D.

L * W = area

(D - 4) * (D - 5) = 82

Expanding and rearranging the equation, we get:

 

D2 - 9D - 82 = 0

Next, we can solve this quadratic equation either by factoring or by using the quadratic formula. After finding the value of D, we can round it to the nearest tenth to obtain the length of the diagonal.

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The simple interest formula is l=prt where l represents simple interest on an amount p for t years at a rate of r where r is expressed as a decimal. What is the amount of money p that will generate $40 in interest at a 10% interest rate over 5 years

Answers

Answer: $80

Step-by-step explanation:

Given : Interest amount : [tex]T=\$40[/tex]

The rate of interest : [tex]r=10\%=0.1[/tex]

Time period : [tex]t=5[/tex] years

The simple interest formula is

[tex]l=prt[/tex], where l represents simple interest on an amount p for t years at a rate of r where r is expressed as a decimal.

Substitute all the values in the  formula , we get

[tex]40=p(0.1)(5)\\\\\Rightarrow\ p=\dfrac{40}{0.1\times5}=80[/tex]

Hence, the amount of money p that will generate $40 in interest at a 10% interest rate over 5 years= $80

The amount of money (p) required to generate $40 in interest at a 10% interest rate over 5 years is $80.

What is the principal needed?

Given the parameters:

Simple interest l = $40

Interest rate r = 10% = 10/100 = 0.10

Time t = 5 years

To determine the amount of money (p) that will generate $40 in interest at a 10% interest rate over 5 years, we use the simple interest formula:

I = P × r × t

Solve for p:
P = I / rt

Plug in the values

P = $40 / ( 0.10 × 5 )

P = $40 / 0.5

P = $80

Therefore, the value of the principal is $80.

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I need some help with graphing again.

Answers

To find the x intercepts, we need to put the standard form equation into factored form.

Which two numbers multiply to -8 and add to -2?

[tex]-4*2=-8[/tex]

[tex]-4+2=-2[/tex]

So the factored form is

[tex](x-4)(x+2)[/tex]

That means the x intercepts are at [tex]x=4,-2[/tex]

So now we have the x intercepts.

To find the vertex, we need to convert the standard form equation into vertex form.

The formula of vertex form is [tex]y=a(x-h)^2+k[/tex]

Since the a value in the standard form equation is 1, the a value in vertex form is also one.

The h value can be found using the formula [tex]h=\frac{-b}{2a}[/tex]

Which comes out to [tex]\frac{2}{2}[/tex] or 1.

To find the k value, we can just plug in what we got for h back into the equation.

[tex](1)^2-2(1)-8=-9[/tex]

So the vertex is [tex](1,-9)[/tex].

This also means the axis of symmetry is [tex]x=-1[/tex]

Finally, to find the y intercept, we plug in 0 for x and solve.

[tex](0)^2-2(0)-8=-8[/tex]

So the y intercept is [tex](0,-8)[/tex].

Noam chose 3 songs from a pile of 20 songs to play at a piano recital. What is the probability that she chose The Entertainer, Something Doing, and The Ragtime Dance?

Answers

[tex]|\Omega|={_{20}C_3}=\dfrac{20!}{3!17!}=\dfrac{18\cdot19\cdot20}{2\cdot3}=1140\\|A|=1\\\\P(A)=\dfrac{1}{1140}\approx0.09\%[/tex]

Answer:

0.014%

Step-by-step explanation:

To calculate the probability that she chooses that exact songs for the piano recital, you just first calculate the probability of her choosing one of them:

[tex]Probability of 1=\frac{1}{20}=.05[/tex]

This is 5%, now you multipy this with the probability of the second song after this one, since there is one less song, the total number of outcomes should be reduced to 19:

[tex]Probability of 2nd=(.05)(\frac{1}{19}[/tex]

[tex]Probability of 2nd=(0.05)(0.052}[/tex]

[tex]Probability of 2nd=0.002[/tex]

This would be .26%

To calculate the probability of the third song being chosen after the first two, we have 2 less outcomes possibles, so the total number of possibilities now is reduced to 18.

[tex]Probability of 3rd=(.0026)(\frac{1}{18}[/tex]

[tex]Probability of 3rd=(.0026)(0.055)[/tex]

[tex]Probability of 3rd=0.00014[/tex]

The probability of Noam choosing the three songs would be: 0.014%

The city of Odessa, Texas is building a wheelchair ramp to make their courthouse accessible for persons in a wheel chair. The Americans with Disabilities Act (ADA) requires that a wheelchair ramp have an angle of elevation of 4.8°. The ADA guidelines also allow a maximum run of 30 feet of ramp before installing a rest platform. At the Odessa courthouse, the ramp must rise 2.5 feet to reach the top of the steps. Will they have to install a rest platform on their ramp?

Answers

Answer:

No they will not have to install a rest platform.

The ramp will be 29.88 feet long so they will not have to install a rest platform.

Step-by-step explanation:

Write an equation in standard form for each ellipse with center (0, 0) and co-vertex at (5, 0); focus at (0, 3).

Answers

Answer:

The required standard form of  ellipse is [tex]\frac{x^2}{25}+\frac{y^2}{34}=1[/tex].

Step-by-step explanation:

The standard form of an ellipse is

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

Where, (h,k) is center of the ellipse.

It is given that the center of the circle is (0,0), so the standard form of the ellipse is

[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]             .... (1)

If a>b, then coordinates of vertices are (±a,0), coordinates of co-vertices are (0,±b) and focus (±c,0).

[tex]c^2=a^2-b^2[/tex]            .... (2)

If a<b, then coordinates of vertices are (0,±b), coordinates of co-vertices are (±a,0) and focus (0,±c).

[tex]c^2=b^2-a^2[/tex]            .... (3)

It is given that co-vertex of the ellipse at (5, 0); focus at (0, 3). So, a<b we get

[tex]a=5,c=3[/tex]

Substitute a=5 and c=3 these values in equation (3).

[tex]3^2=b^2-(5)^2[/tex]

[tex]9=b^2-25[/tex]

[tex]34=b^2[/tex]

[tex]\sqrt{34}=b[/tex]

Substitute a=5 and [tex]b=\sqrt{34}[/tex] in equation (1), to find the required equation.

[tex]\frac{x^2}{5^2}+\frac{y^2}{(\sqrt{34})^2}=1[/tex]

[tex]\frac{x^2}{25}+\frac{y^2}{34}=1[/tex]

Therefore the required standard form of  ellipse is [tex]\frac{x^2}{25}+\frac{y^2}{34}=1[/tex].

AC, DF, and GI are parallel. Use the figure to complete the proportion. (7)

Answers

Answer:

The answer is

C.) BE

AD/AG=BE/BH

Answer:

Option C

Step-by-step explanation:

We have to find the value in the blank space

We are given that AC,DF and GI are parallel

We know that by middle splitting theorem

We have

[tex]\frac{JD}{AD}=\frac{JE}{BE}[/tex]

Because AC is parallel to DF and A and B are the mid points of JD and JE

[tex]\frac{JD}{GD}=\frac{JE}{EH}[/tex]

Because DF is parallel to GI

Divide  equation one by equation second then we get

[tex]\frac{GD}{AD}=\frac{EH}{BE}[/tex]

Adding one on both sides then we get

[tex]\frac{GD}{AD}+1=\frac{BE}{EH}+1[/tex]

[tex]\frac{GD+AD}{AD}=\frac{BE+EH}{BE}[/tex]

[tex]\frac{AG}{AD}=\frac{BH}{BE}[/tex]

Because BE+EH=BH and AD+GD=AG

Reciprocal on both sides then we get

[tex]\frac{AD}{AG}=\frac{BE}{BH}[/tex]

Hence, option C is true.

I need help with this problem.

Answers

Answer: y = -1/4x - 4

Step-by-step explanation:

y = (-1/4)x + 2 (This is the first linear function.)

(4,3) has slope of (-1/4)x  or (1/-4)x

4(y2) - 4(y1= the new y  -1(x2) -3(x1) = new x which leads to (0,-4) so y-intercept = -4

so all in all, y = (-1/4)x -4 is the answer

Hopefully, you're able to understand this. It's difficult to explain through typed words rather than visually and through a written example.

Same y intercept as x+4y=8 through (4,3)

Y intercept is when x=0, so 4y=8, so y=2 and the y intercept is (0,2)

Answer for y intercept:  (0,2)

So we need the line through (0,2) and (4,3).  Point-point form says the line through (a,b) and (c,d) is

(c-a)(y-b) = (d-b)(x-a)

(4 - 0)(y - 2) = (3 - 2)(x - 0)

4y - 8 = x

Answer for the line:  x - 4y = -8

Check:

(0,2) is on the line: 0-4(2)  = -8 check

(4,3) is on the line 4 - 4(3) = -8 check

Geometry
The picture below shows the question and answer choices for the questions.

Answers

Look at the table for the people that used Lithium.

There are 18 relapses, 6 No relapses with a total of 24 people.

The relative frequency for relapse, would be dividing the number of relapses by the total number of people.

This would be D. 18 / 24 = 75%

If two planes are perpendicular to the same line, then
A. they are perpendicular to each other
B. not enough information
C. they form a straight line
D. they are parallel​

Answers

Answer:

  D.  they are parallel​

Step-by-step explanation:

A plane can be defined by a point and a direction vector that is perpendicular to the plane. If two planes have the same direction vector (perpendicular line), then they are either the same plane or they are parallel.

If two planes are perpendicular to the same line, then they must also be parallel to each other.

If two planes are perpendicular to the same line, then they are also parallel to each other. This is because any line that intersects two parallel planes will be perpendicular to both planes.

To illustrate this, imagine two planes, A and B, that are perpendicular to the same line, L. If we draw a line, M, that intersects both planes, then M will be perpendicular to both planes A and B. This is because lines A and B are parallel to each other, and any line that intersects two parallel lines will be perpendicular to both lines.

Therefore, if two planes are perpendicular to the same line, then they must also be parallel to each other. The answer is D. they are parallel.

For such more question on perpendicular

https://brainly.com/question/1202004

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1. Write 3,876,943,000 using scientific notation.

Use the 1x10^6 style format for entering your answer. No spaces between characters.

2. Write 0.0007317 using scientific notation.

Use the 1x10^-6 style format for entering your answer. No spaces between characters.

Answers

Answer:

3.876943x10^9

7.317x10^-4

Step-by-step explanation:

3,876,943,000

Put the decimal at the end

3,876,943,000.

Move it so only 1 number is before the decimal

3.876943000

We moved it 9 places, so that is the exponent

We moved it to the left, so the exponent is positive

The three zeros at the end can be dropped because they are the last numbers to the right of the decimal

3.876943x10^9

0.0007317

Move it so only 1 number is before the decimal

00007.317

We moved it 4 places, so that is the exponent

We moved it to the right, so the exponent is negative

The four zeros at the left can be dropped because they are the last numbers to the left of the whole number

7.317x10^-4

I need help with these. They are hard.

Answers

Answer:

Find the explicit from for the sequence [tex]t_n=t_{n-1}+4,t=6[/tex]:

[tex]a_n=4n+2[/tex]

This next question I edited a bit.  Your question just says find the four terms.  I'm assuming they meant the first four. I also changed the c to an [tex]a[/tex].

Find the first four terms of the sequence given by: [tex]a_n=n a_{n-1}-3,a_1=2[/tex]:

a) 2,1,0.-3

You might want to read that second question again because there is errors in the question or things that don't really make sense.  I made my own interpretation of the problem based on my own mathematical experience.

Step-by-step explanation:

So your first question actually says that you can find a term by taking that term's previous term and adding 4.

So more terms of the sequence starting at first term 6 is:

6,10,14,18,....

This is an arithmetic sequence.  When thinking of arithmetic sequences you should just really by thinking about equations of lines.

Let's say we have this table for (x,y):

x  |   y

----------

1      6

2    10

3     14

4     18

So we already know the slope which is the common difference of an arithmetic sequence.

We also know point slope form of a line is [tex]y-y_1=m(x-x_1)[/tex] where m is the slope and [tex](x_1,y_1)[/tex] is a point on the line.  You can use any point on the line. I'm going to use the first point (1,6) with my slope=4.

[tex]y-6=4(x-1)[/tex]

[tex]y=6+4(x-1)[/tex]    :I added 6 on both sides here.

[tex]y=6+4x-4[/tex]     :I distribute here.

[tex]y=4x+2[/tex]        :This is what I get after combining like terms.

So [tex]a_n=y[/tex] and [tex]x=n[/tex] so you have:

[tex]a_n=4n+2[/tex]

---------------------------------------------------------------------------------------

The first four terms of this sequence will be given by:

[tex]a_1,a_2,a_3,a_4[/tex]

[tex]a_1=2[/tex] so it is between choice a, c, and d.

[tex]a_n=na_{n-1}-3[/tex]

To find [tex]a_2[/tex] replace n with 2:

[tex]a_2=2a_{1}-3[/tex]

[tex]a_2=2(2)-3[/tex]

[tex]a_2=4-3[/tex]

[tex]a_2=1[/tex]

So we have to go another further the only one that has first two terms 2,1 is choice a.

A metallurgist has an alloy with 16​% titanium and an alloy with 30​% titanium. He needs 100 grams of an alloy with 23​% titanium. How much of each alloy should be mixed to attain the 100 grams of alloy with 23​% ​titanium?
nothing grams of the alloy with 16​% of titanium are needed.

Answers

Let x = amount of 16% alloy, and y = amount of 30% alloy he should use.

Mixing the alloys will result in a compound weighing x + y = 100 grams.

For each gram of the 16% alloy used, 0.16 gram of titanium is contributed; similarly, for each gram of the 30% alloy used, there's a contribution of 0.3 gram. He wants to end up with an alloy of 23% titanium, or 23 grams (23% of 100), so that 0.16x + 0.3y = 23.

Solve the system:

[tex]x+y=100\implies y=100-x[/tex]

[tex]0.16x+0.3y=23\implies 0.16x+0.3(100-x)=23\implies7=0.14x[/tex]

[tex]\implies\boxed{x=50}\implies\boxed{y=50}[/tex]

What is the simplified form of the quantity x over 3 plus y over 4 all over the quantity x over 4 minus y over 3? the quantity 4x plus 3y all over the quantity 3x minus 4y the quantity 4x minus 3y all over the quantity 3x plus 4y the quantity 3x plus 4y all over the quantity 4x minus 3y the quantity 3x minus 4y all over the quantity 4x plus 3y

Answers

Answer:

Option A) [tex]\frac{4x+3y}{3x-4y}[/tex]

Step-by-step explanation:

The given expression is:

[tex]\frac{\frac{x}{3}+\frac{y}{4}}{\frac{x}{4}-\frac{y}{3}}[/tex]

Taking LCM in upper and lower fractions, we get:

[tex]\frac{\frac{x}{3}+\frac{y}{4}}{\frac{x}{4}-\frac{y}{3}}\\\\ =\frac{\frac{4x+3y}{12}}{\frac{3x-4y}{12}}\\\\\text{Cancelling out the common factor 12, we get:}\\\\ =\frac{4x+3y}{3x-4y}[/tex]

Therefore, the option A gives the correct answer.

A circle has a radius of 10.9 cm. If the area is multiplied by 6, what happens to the radius? HELP ASAP!!

The radius is multiplied by √6
The radius is multiplied by 6.
The radius is multiplied by 36.

Answers

Answer:

root 6

Step-by-step explanation:

pi*r^2 = A

6*pi*r^2 = 6A

6*r^2 = new radius squared

root 6 * r = new radius

The correct answer is option 1) The radius is multiplied by [tex]\sqrt{6}[/tex]

[tex]A = \pi r^2[/tex]
where A is the area and r is the radius.
If the area is multiplied by 6, we can represent this with the following equation:
A' = 6A
where A' is the new area and let r' be its radius.
[tex]A' = \pi (r')^2[/tex]
Substituting this into the equation for the new area gives us:
[tex]\pi (r')^2 = 6*(\pi r^2)[/tex]
To solve for r', we can divide both sides of the equation by [tex]\pi[/tex]:
[tex](r')^2 = 6r^2[/tex]
Next, take the square root of both sides to solve for r':
[tex]r' = \sqrt{6}r[/tex]
Therefore, the new radius r' is the original radius r multiplied by [tex]\sqrt{6}[/tex].

Please assist me with this problem.

Answers

Answer:

4

(We didn't even need to use (9,6) )

Step-by-step explanation:

The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.

We are given the line we are looking for has the same y-intercept as x+2y=8.

So if we put x+2y=8 into y=mx+b form we can actually easily determine the value for b.

So we are solving x+2y=8 for y:

x+2y=8

Subtract x on both sides:

  2y=-x+8

Divide both sides by 2:

   y=(-x+8)/2

Separate the fraction:

  y=(-x/2)+(8/2)

Reduce the fractions (if there are any to reduce):

y=(-x/2)+4

Comparing this to y=mx+b we see that b is 4.

So the y-intercept is 4.

Again since we know that the line we are looking for has the same y-intercept, then the answer is 4 since the question is what is the y-intercept.

4

A rectangular dartboard has an area of 648 square centimeters. The triangular part of the dartboard has an area of 162 square centimeters. A dart is randomly thrown at the dartboard. Assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle? To the nearest whole percent, the probability is

Answers

162 divide by 648 is equal to 1/4, or 25%

Answer: 25%

Step-by-step explanation:

Given : A rectangular dartboard has an area of 648 square centimeters.

The triangular part of the dartboard has an area of 162 square centimeters.

If we assume that the dart lands in the rectangle, then the probability that it lands inside the triangle will be :-

[tex]\dfrac{\text{Area of triangular part}}{\text{Area of rectangular dart board}}\\\\=\dfrac{162}{648}=0.25[/tex]

In percent, [tex]0.25\times100=25\%[/tex]

Hence, the required probability = 25%

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