Which shows how the distributive property can be used to evaluate 7×84/5?

Answers

Answer 1
Well you have nothing here, so I'll take a guess.
84/5 gives 16 4/5. I don't know how much saving in work there is in doing this but you could do this.

7 ( 16 + 4/5)
You still have to do something with 28/5 when you get done, but it is one way to do it.

Related Questions

Find r for the geometric series with s5 = 484, a1 = 4, a5 = 324

Answers

a5 / a1 =  r^4  = 324/4 

So r^4 = 81

r = +/- 3

If  r = 3 :-

S5  = 4 *  (3^5-1) / (3-1)  = 484

so r = 3 Answer

A purse contains 5-cent coins and 10-cent coins worth a total of $1.05. If the 5-cent coins were replaced with 10-cent coins and the 10-cent coins were replaced with 5-cent coins, the coins would be worth a total of $2.15. How many coins are in the purse? HELP PLEASE WITH WORK

Answers

Let f and t represent the numbers of 5- and 10-cent coins in the purse. (We expect these numbers to be positive integers.)
.. 5f +10t = 105 . . . . . . current value
.. 10f +5t = 215 . . . . . . value if numbers are swapped

Multiply the first equation by -2 and add to the second.
.. -2(5f +10t) +(10f +5t) = -2(105) +215
.. -15t = 5
.. t = -1/3

No such coin arrangement is possible.

_____
If you simply add the two original equations, you get
.. 15(t + f) = 320
.. t + f = 21 1/3 . . . . . There are 21 1/3 coins in the purse.

Taking that at face value, we find the average coin value is 
.. 1.05/21.3333... = 4.921875¢ . . . . less than the value of a nickel

There is no combination of nickels and dimes that will make the average value of a single coin be less than 5¢. (The average value must be between 5¢ and 10¢.)

Answer:

The other person should be correct

Step-by-step explanation:

Please help me with this!

Answers

m(BAC)=35 degrees.
m(CAD)=2* m(BAC) =2*35=70 degrees.

m(BAD)=m(BAC)+m(CAD)
              = 70 + 35
              = 105 degrees.

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Answers

Note that if [tex]{x_2}'=x_1[/tex], then [tex]{x_2}''={x_1}'[/tex], and so we can collapse the system of ODEs into a linear ODE:

[tex]{x_2}''=3{x_2}'-x_2+e^t[/tex]
[tex]{x_2}''-3{x_2}'+x_2=e^t[/tex]

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

[tex]r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0[/tex]

so that the characteristic solution is

[tex]{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}[/tex]

Now let's suppose the particular solution is [tex]{x_2}_p=ae^t[/tex]. Then

[tex]{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t[/tex]

and so

[tex]ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1[/tex]

Thus the general solution for [tex]x_2[/tex] is

[tex]x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t[/tex]

and you can find the solution [tex]x_1[/tex] by simply differentiating [tex]x_2[/tex].

Final answer:

To find the general solution of the given system of differential equations, first, solve the second equation for x1 in terms of x2. Then substitute x1 into the first equation and simplify to isolate x'2. Next, solve the second equation for x2 in terms of x1 and substitute x2 into the first equation. Simplify and rearrange to isolate x'1. Finally, solve the resulting differential equations to find the general solution.

Explanation:

To find the general solution of the given system of differential equations:
x'1 = 3x1 - x2 + et, x'2 = x1

Step 1: Solve the second equation for x1 in terms of x2:
x1 = x'2

Step 2: Substitute x1 into the first equation:
x'1 = 3(x'2) - x2 + et

Step 3: Simplify and rearrange the equation to isolate x'2:
x'2 = (x'1 + x2 - et)/3

Step 4: Solve the second equation for x2 in terms of x1:
x2 = x'1 - 3x'2 + et

Step 5: Substitute x2 into the first equation:
x'1 = 3x1 - (x'1 - 3x'2 + et) + et

Step 6: Simplify and rearrange the equation to isolate x'1:
x'1 = (3x'2 + x'1 - 2et)/3

Now we have two differential equations for x'1 and x'2 in terms of each other. These can be solved using standard methods to find the general solution.

Find a generating function for the number of integer solutions of 2x+3y+7z=r

Answers

2x+3y+7z=r
r=2x+3y+7z
r=2x+3y+7z

Mindy is training to run a marathon. She runs 4 miles each day. Write an equation that would represent the number of miles m, she runs on a given day, d.

Answers

You know that she runs 4 miles every day, so we can set up the equation:

[tex]\sf m=4d[/tex]

For any given day you just plug that number in for 'd' and it will give you the total number of miles.

A couple has 12 children, what is the probability that child number 11 is female?

Answers

The probability is 1/12.

What is probability?

Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e. how likely they are to happen, using it.

Given:

Total children = 12

There is possibility of girl number 11.

So, the probability that child number 11 is female

=1/12.

Hence, the probability is 1/12.

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Final answer:

The probability that the 11th child is female is 50%, assuming an equal chance for the birth of either sex and that the gender of the previous children does not affect this outcome.

Explanation:

The question at hand is a basic probability question in the realm of mathematics. It attempts to find the likelihood of an event that is purely random and independent of previous outcomes. The event in question is the sex of a newborn child, which can either be male or female, generally with equal likelihood.

To determine the probability that child number 11 is female, we assume a 50% chance for either sex, since the likelihood of having a boy or girl is typically equal. The sex of the previous children has no influence on the gender of the next child. Therefore, the probability of child number 11 being female is simply 1/2 or 50%.

It is important to understand that each child's sex is determined independently of their siblings. This is akin to flipping a fair coin where each flip is independent of the previous flips.

Help Please..

On a regional map, one inch represents 68 miles. How many miles apart are two cities that are three inches apart on the map?

Answers

the formula you should use for this question is 1:68.  1 being inches and 68 being miles.  So if the cities are 3 inches apart, then all you need to do is times 68 by 3.

A scatter plot is shown below:

Which two ordered pairs can be joined to draw most accurately the line of best fit on this scatter plot?

(4, 9.5) and (10, 5.5)
(5, 0) and (10, 10)
(0, 6) and (5, 0)
(0, 9.5) and (10, 1.5)

Answers

(0, 9.5) and (10, 1.5)

Answer:

(0, 9.5) and (10, 1.5)

Step-by-step explanation:

as we can see the closest points that assimilate the scatter plot, these is the answer.

1 2 3 4 5 6 7 8 9 10 The two conditional relative frequency tables below show the results of a survey asking students whether they are taking a foreign language or not. Table B: Frequency of Foreign-Language Studies by Row Which table could be used to answer the question "Assuming a student is taking a foreign language, what is the probability the student is also in high school?” Table A, because the given condition is that the student is in high school. Table A, because the given condition is that the student is taking a foreign language. Table B, because the given condition is that the student is in high school. Table B, because the given condition is that the student is taking a foreign language.

Answers

B (:  


cuz i saw it on this other website and i am like 50% sure its correct 










Answer:

B. Table A, because the given condition is that the student is taking a foreign language.

Step-by-step explanation:

ED 2020

Determine whether the lines l1 and l2 are parallel, coincident, skew, or intersecting. if they intersect, find the point of intersection: ℓ1:x1(t)=1−6t,y1(t)=2+9t,z1(t)=−3t ℓ2:x2(u)=2+2u,y2(u)=3−3u,z2(u)=u

Answers

Rewrite the lines as:
L1:(1,2,0)+t(-6,9,-3)
L2:(2,3,0)+u(2,-3,1)

The direction vector of L1 is <-6,9,-3>=-3<2,-3,1>
while that of L2 is <2,-3,1>
we see that both direction vectors are parallel, that is, L1 and L2 are parallel.

To check if the two lines are coincident, we need to find at least one common point.

Assuming the x-coordinates coincide, we have
1-6t=2+2u  => 6t+2u=-1 ................(1)
Assuming the y-cordinates coincide, we have
2+9t=3-3u => 9t+3u=1..................(2)
3(1)-2(3) :  18t+6u - (18t+6u) = -2-3 => 0=-5  ..... therefore no solution.

If we cannot find one common point between the two lines, they are not coincident.

Another way to check this is to match the x-coordinates of the lines, and see if the other coordinates match
Here, we try to match the x-coordinate = 1, for the point (1,2,0) on L1.
For L2, we set u=-1/2
L2: (2,3,0)-(2,-3,1)/2 = (2-1, 3+1.5, 0-0.5) = (1, 4.5, -0.5) 
which does not match (1,2,0) on L1.  So the two lines are not coincident.

Answer: the two lines L1 and L2 are parallel  (i.e. not coincident)
Final answer:

To determine whether the lines are parallel, coincident, skew, or intersecting, we first analyze the direction vectors of both lines obtained from the parametric equations. The lines are not parallel or coincident as they're not proportional. They could be intersecting or skew, which we can confirm by finding a potential point of intersection.

Explanation:

To determine the relationship between lines ℓ1 and ℓ2, we should analyze the direction vectors of both lines. The coefficients of t or u in the parametric equations for the lines refer to the direction vectors. For ℓ1, the direction vector is (-6, 9, -3). For ℓ2, it's (2, -3, 1).

Lines are parallel if their direction vectors are proportional, and intersect if they pass through a common point and their direction vectors are not proportional. Lines are coincedent if all corresponding points are identical, while skew lines are nonintersecting, nonparallel lines.

Given the direction vectors, we can see they are not proportional. Hence, ℓ1 and ℓ2 are neither parallel nor coincident. They might be intersecting or skew. To distinguish between these two, we need to try to find a point of intersection by equating ℓ1 and ℓ2 and solving for t and u. If a solution exists, the lines intersect at that specific point; if no solution exists, the lines are skew.

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What number goes in the missing space?

Answers

I would say that the answer is 20.

Good luck!

The summation expression in the following series has an absolute value in it. Expand and evaluate the summation notation. What is the sum of the series?

Answers

[tex]|3i-10|=\begin{cases}3i-10&\text{for }3i-10\ge0\\-(3i-10)&\text{for }3i-10<0\end{cases}=\begin{cases}3i-10&\text{for }i\ge\dfrac{10}3\\\\10-3i&\text{for }i<\dfrac{10}3\end{cases}[/tex]

We have that [tex]3<\dfrac{10}3<4[/tex], which means [tex]|3i-10|[/tex] reduces to [tex]3i-10[/tex] when [tex]i\ge4[/tex], or reduces to [tex]10-3i[/tex] when [tex]i\le3[/tex].

So we can expand the summation as

[tex]\displaystyle\sum_{i=1}^6|3i-10|=\sum_{i=1}^3(10-3i)+\sum_{i=4}^6(3i-10)[/tex]

Notice that the 10 contributes a total of 30 from the first sum, and -30 from the second sum, so those terms cancel, leaving us with

[tex]\displaystyle3\left(\sum_{i=4}^6i-\sum_{i=1}^3i\right)=3((4+5+6)-(1+2+3))=3(15-6)=3(9)=27[/tex]
Final answer:

To expand and evaluate the summation notation with an absolute value, we can use the binomial theorem. The expanded form of the series will depend on whether the sum inside the absolute value is positive or negative. Substituting the given values and simplifying the expression will give the sum of the series.

Explanation:

A binomial expansion is a way of expressing an algebraic quantity as a sum of an infinite series of terms. In this case, we have an absolute value in the summation expression.

To expand and evaluate the summation notation, we can use the binomial theorem.

The binomial theorem states that (a + b)^n = C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + ... + C(n,n)b^n, where C(n,k) represents the binomial coefficient.

In the given case, we have an expression of the form |a + b|.

To expand this, we can consider two cases: a + b ≥ 0 and a + b < 0. If a + b ≥ 0, then |a + b| = a + b. If a + b < 0, then |a + b| = -(a + b).

Thus, the expanded form of the series will be a + b when a + b ≥ 0, and -(a + b) when a + b < 0.

To evaluate the series, substitute the given values for a and b into the expanded form and simplify the expression.

A grain distributor can process 14.6 tons of grain an hour.How much can the distributor process in 8.75 hours?

Answers

Hi there! For this question, all you have to do is multiply the two numbers. 14.6 tons are processed every hour. With this rate, we can find the amount processed in 8.75 hours. Multiply decimals like you do regular numbers. 14.6 * 8.75 is 127.75. There. The grain distributor can process 127.75 tons of grain in 8.75 hours.
Final answer:

The grain distributor can process 127.75 tons of grain in 8.75 hours.

Explanation:

To find out how much the distributor can process in 8.75 hours, you can multiply the amount of grain it can process in one hour by the number of hours. The distributor can process 14.6 tons of grain in an hour, so to find out how much it can process in 8.75 hours, you would multiply 14.6 by 8.75.

14.6 x 8.75 = 127.75

Therefore, the distributor can process 127.75 tons of grain in 8.75 hours.

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Miguel ordered a rectangular print for his bedroom. The print is 78 feet wide and 135 feet long.



What is the area of the print?

Answers

the area of the print is 10,530
To find the area of the print you must multiply 78ft(width) by 135ft(length). So your answer is 10,530.

Edit: To find the area of print you must multiply [tex] \frac{7}{8} [/tex] by [tex]1 \frac{3}{5} [/tex]. So your answer is [tex]1 \frac{2}{5} [/tex].

An elephant can run mile in 36 seconds. Which of the following correctly shows this rate as miles per hour? = 25 miles per hour = 144 miles per hour = 25 miles per hour = 144 miles per hour

Answers

None of the above.

36 seconds = (36 seconds)/(3600 seconds/hour) = 1/100 hour

(1 mile)/(1/100 hour) = 100 mile/hour

Select all the expressions that have the following quotient

Answers

answer 2 is the right one for your equation
Answer:

The expression that have the following quotient is:

         [tex]\dfrac{-4x^2+20x-25}{-2x+5}[/tex]          [tex]\dfrac{-14x^2+35x}{-7x}[/tex]          [tex]\dfrac{12x^2-58x+70}{6x-14}[/tex]Step-by-step explanation:

1)

[tex]\dfrac{-4x^2+20x-25}{-2x+5}[/tex]

It could also be written as:

[tex]\dfrac{-(5-2x)^2}{5-2x}\\\\\\=-(5-2x)\\\\\\=2x-5[/tex]

Hence, we get the quotient:

    [tex]2x-5[/tex]

Option: (1) is correct.

2)

[tex]\dfrac{-14x^2+35x}{-7x}[/tex]

which is simplified as follows:

[tex]\dfrac{-7x(2x-5)}{-7x}\\\\\\=2x-5[/tex]

Option: (2) is correct.

3)

[tex]\dfrac{12x^2-58x+70}{6x-14}[/tex]

which is simplified as follows:

[tex]=\dfrac{2(2x-5)(3x-7)}{2(3x-7)}\\\\\\=2x-5[/tex]

Hence, option: (3) is correct.

4)

[tex]\dfrac{6x^2-10x-4}{3x+1}[/tex]

On simplifying:

[tex]\dfrac{2(3x+1)(x-2)}{3x+1}\\\\\\=2(x-2)\\\\\\=2x-4[/tex]

Hence, option: (4) is incorrect.

5)

[tex]\dfrac{18x-45}{9x}[/tex]

on simplifying:

[tex]\dfrac{9(2x-5)}{9x}\\\\\\=\dfrac{2x-5}{x}[/tex]

Hence, option: (4) is incorrect.

Find a quadratic function associated with vertex (h, k) = (2, 1) and point (x, y) = (6, 7) that the parabola passes through.

Answers

To find the quadratic function with vertex (2, 1) that passes through (6, 7), use the vertex form of a quadratic equation and solve for 'a' using the given point. The resulting function is y = ([tex]\frac{3 }{ 8}[/tex])(x - 2)² + 1.

To find a quadratic function associated with the vertex (h, k) = (2, 1) and a point (x, y) = (6, 7) that the parabola passes through, we need to use the vertex form of a quadratic equation:

y = a(x - h)² + k

Since we know the vertex (h, k), we can substitute h=2 and k=1 into the equation, which gives us:

y = a(x - 2)² + 1

We also know that the parabola passes through the point (6,7), so we can substitute x=6 and y=7 into the equation to find the value of 'a':

7 = a(6 - 2)² + 1

7 = a(4)² + 1

6 = 16a

[tex]a = \frac{6 }{ 16} = \frac{3 }{ 8}[/tex]

Now, substituting the value of 'a' into the vertex form, we get the quadratic function:

y = ([tex]\frac{3 }{ 8}[/tex])(x - 2)² + 1

At what rate must $287.50 be compounded annually for it to grow to $572.86 in 8 years?

Answers

Using the compound interest formula,
572.86=287,50(1+i)^8
(1+i)^8=572.86/287.50=1.992557
1+i=(1.992557)^(1/8)=1.0899996
=> 
i=1.0899996-1=9%

Note: This problem can also be solved in the head using the rule of 72.
Since after 8 years, the amount is roughly doubled, we can say that the interest rate is approximately 72/8=9%

If p(a) = 0.50, p(b) = 0.60, and p(a intersection
b.= 0.30, what is the p(a union b)? enter your answer as a decimal rounded to two places.

Answers

Use the identity P(A &cup; B) = P(A)+P(B)-P(A &cap; B)

P(A)=0.50
P(B)=0.60
P(A &cup; B) = 0.30
=>
P(A &cup; B) = P(A)+P(B)-P(A &cap; B)
=(0.50+0.60)-0.30
=0.80

The probability is 0.80.

To find the probability of the union of two events, calculate the sum of their individual probabilities and subtract the probability of their intersection.

The probability of the union of events A and B (P(A ∪ B)) can be calculated using the formula:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Given P(A) = 0.50, P(B) = 0.60, and P(A ∩ B) = 0.30, substitute these values into the formula to find P(A ∪ B) = 0.50 + 0.60 - 0.30 = 0.80

David was looking at his limousine bill and saw that the total number of miles he has ridden in the car was tracked, as shown below: Month Miles 5 580 6 695 7 810 8 925 The function representing David's miles per month is f(m) = 115m + 5. What does the 115 represent?

Answers

Increasing miles in the month ( proportional of miles which he rides in the month

The number of additional miles each month.

In the decimal value 4256, the weight of the numeral 2 is ________.

Answers

The weight of the numeral 2 is hundreds.

Answer: 200

Explanation:

Numeral system is a system for expressing numbers; that is, a mathematical notation for representing numbers of a given set, using digits or other symbols in a consistent manner. The same sequence of symbols may represent different numbers in different numeral systems.

For example:

2356:-

We start from left

6 = 6*10⁰ = 6*1 = 6

5 = 5*10¹ = 5*10 = 50

3 = 3*10² = 3*100 = 300

2 = 2*10³ = 2*1000 = 2000

Similarly,

Given number is 4256

6 = 6*10⁰ = 6*1 = 6

5 = 5*10¹ = 5*10 = 50

2 = 2*10² = 2*100 = 200

I think that the answer is c can somebody help me out ?

Answers

Answer:
tan F = 40/9 which is the third option

Explanation:
Triangle DEF is a right-angled triangle. This means that we can apply the special trigonometric function.
This means that:
tan θ = opposite / adjacent
In the given:
θ = F
opposite is DE = 40
adjacent is DF = 9
Substitute in the above equation:tan F = 40/9

Hope this helps :)

what expression must the center cell of the table below contain so that the sums of each row, each column, and each diagonal are equivalent?

  x       8x      -3x
-2x      ?        6x
7x      -4x       3x

Answers

Oh, I adore magic squares!

We need all rows to be equivalent, so try adding up the bottom (complete) row to get 7x-4x+3x=10x-4x=6x.

To solve the middle number, we have -2x+X+6x=6x, so X=2x.
To solve the top number, we have X+8x-3x=6x, so X=6x-8x+3x=x

Now check first column, 
x-2x+7x=6x   ok
Second column
8x+2x-4x=6x  ok
Top-right to bottom-right diagonal: x+2x+3x=6x, ok   
Bottom-left to top right diagonal: 7x+2x-3x=6x

So everything is ok!

The missing value in the center cell (y) should be 2x to achieve equivalent sums in each row, column, and diagonal.

To achieve equivalent sums in each row, column, and diagonal, we need to determine the missing value in the center cell. Let's denote the missing value as "y."

The table is as follows:

x 8x -3x

-2x y 6x

7x -4x 3x

Now, let's consider the sum along each row, column, and diagonal:

Rows:

x + 8x - 3x = 6x (1st row)

-2x + y + 6x = 4x + y (2nd row)

7x - 4x + 3x = 6x (3rd row)

Columns:

x - 2x + 7x = 6x (1st column)

8x + y - 4x = 4x + y (2nd column)

-3x + 6x + 3x = 6x (3rd column)

Diagonals:

x + y + 3x = 4x + y (from top-left to bottom-right)

-3x + y + 7x = 4x + y (from top-right to bottom-left)

To ensure equivalent sums, the expression for "y" in the center cell should be such that 4x + y = 6x. Solving for "y," we find y = 2x.

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How do i solve a Real world problem that involves finding the product of a fraction and a mixed number?

Answers

You solve it the same way you solve a textbook or classroom problem.

a) convert the mixed number to an improper fraction, then multiply the fractions in the usual way, then convert the result to a mixed number.

or

b) multiply the fraction by the integer part of the mixed number, multiply the fraction by the fractional part of the mixed number, and add the result. Sometimes, this is easier to do when you're doing it in your head.

or

c) divide the mixed number into an integer and another mixed number and do it in a fashion similar to b).

Example:
.. I have a recipe that calls for 5 1/3 cups of flour. I want to make 1/4 of the recipe. How much flour do I need?

a) (1/4)*(5 1/3)
.. = (1/4)*(16/3)
.. = (1*16)/(4*3)
.. = (4*4)/(4*3)
.. = 4/3
.. = 1 1/3 . . . . cups of flour

b) (1/4)*(5 1/3)
.. = (1/4)*5 +(1/4)*(1/3)
.. = 5/4 +1/12
.. = 64/48 . . . or . . . (1 1/4) +1/12
.. = 4*16/(3*16) . . . or . . . 1 +(3/12 +1/12)
.. = 4/3 . . . or . . . 1 +4/12
.. = 1 1/3 . . . . cups of flour

c) (1/4)*(5 1/3)
.. = (1/4)*(4 + 4/3)
.. = (1/4)*4 +(1/4)*(4/3)
.. = 1 1/3 . . . . cups of flour

Combine the like terms to create an equivalent expression. 12p + p

Answers

Answer: The equivalent expression of the given terms is 13 p

Step-by-step explanation:

Like terms are defined as the terms which have same variable. Mathematical operation are applied on these terms.

Unlike terms are defined as the terms which do not have same variable. Mathematical operation are not applied on these terms.

For Example:  [tex]x^2+2x+5x^2+7[/tex]

In the above expression, [tex]x^2\text{ and }5x^2[/tex] are the like terms because they have same variable which is '[tex]x^2[/tex]'

In the given expression:  12 p + p

Both the terms are like terms, and thus the operation can be applied.

Hence, the equivalent expression of the given terms is 13 p

We have enough material to build a fence around a station that has a perimeter of 180 feet. The width of the rectangular space must be 30 1/4 feet. What must the length be?

Answers

To solve this problem you must use the formula of the perimeter (P) of a rectangle and clear the length (L). The perimeter of a rectangle, is:

 P=2L+2W

 "P" is the perimeter of the rectangle (P=180 feet).
 "L" is the lenght of the rectangle.
 "W" is the widht of the rectangle (W=30 1/4 feet=30.25 feet).

 As you can see, you already have the value of the perimeter (P) and the value of the widht (W). Now, you can clear the lenght (L):

 P=2L+2W
 2L=P-2W
 L=(P-2W)/2

 When you substitute the values, you obtain:

 L=(P-2W)/2
 L=(180 feet-2x30.25 feet)/2
 L=(119.5 feet)/2
 L=59.75 feet

 What must the length be?

 The answer is: 59.75 feet


 



An urn contains eight blue balls and seven yellow balls. if six balls are selected randomly without being​ replaced, what is the probability that of the balls​ selected, two of them will be blue and four of them will be​ yellow

Answers


to be sure that 2 of them will be blue i have to select 7+2=9 balls
7+8=15 balls in the urn
P=9/15

to be sure that 4 of them will be yellow i have to select 8+4=12 balls
P=12/15


Here is the sample space for three tosses of a coin.
{HHH, HHT, HTH, HTT, THH, THT, TTH, THT}
Calculate the probability that this compound event will yield a result of 2 heads and 1 tail (in any order)
A. 0.125
B. 0.25
C. 0.333
D. 0.375

Answers

Assuming the coin is fair, the probability of the coin toss resulting in H is [tex]p=\dfrac12[/tex]. So the probability of getting two Hs, in any order, is

[tex]\dbinom32p^2(1-p)=\dfrac38=0.375[/tex]

The probability that the compound event of tossing a coin 3 times will yield a result of 2 heads and 1 tail (in any order) is option D. 0.375.

Given that:

A coin is tossed three times.

The sample space is given as:

{HHH, HHT, HTH, HTT, THH, THT, TTH, THT}

Now, it is required to find the probability of getting 2 heads and 1 tail in any order.

Total number of outcomes = number of elements in the sample space

                                             = 8

Outcomes that yield two heads and one tail = {HHT, HTH, THH}

Number of outcomes that yield two heads and one tail = 3

So, the probability is

[tex]P(\text{2 heads and 1 tail})=\frac{3}{8}\\[/tex]

So, P = 0.375

Hence, the correct option is D.

Learn more about Probability here :

https://brainly.com/question/4455723

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I have no idea how to do this equation, please help

Answers

Put in the given numbers and you have two equations in two unknowns.
.. 10Ta +25Tb = 220
.. Ta +Tb = 10

It is convenient to solve this by substitution. Use the second equation to write an expression for Tb.
.. Tb = 10 -Ta
Now use this in the first equation.
.. 10Ta +25(10 -Ta) = 220
.. -15Ta +250 = 220 . . . . . . . collect terms
.. -15Ta = -30 . . . . . . . . . . . . . subtract 250
.. Ta = 2 . . . . . . . . . . . . . . . . . divide by the coefficient of Ta
.. Tb = 10 -2 = 8

Selection C is appropriate.
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