Answer: "The car that finishes last has the lowest power."
Graph the velocity of a car accelerating at a uniform rate from 7.0 m/s to 12.0 m/s in 2.0 s. Calculate the accerleration
Final answer:
Velocity vs. time graph for uniform acceleration is a straight line, acceleration calculated using the formula a = (Vf - Vi) / t. The acceleration during the first 8 seconds is 1 m/s², and during the last 6 seconds it is -1 m/s².
Explanation:
To graph the velocity of a car accelerating at a uniform rate from 7.0 m/s to 12.0 m/s in 2.0 s, plot a velocity vs. time graph where the time axis (x-axis) spans at least 2 seconds and the velocity axis (y-axis) spans from 7.0 m/s to 12.0 m/s. The graph will be a straight line starting at the point (0, 7.0) and ending at the point (2.0, 12.0) since the acceleration is uniform.
To calculate the acceleration (a), use the formula a = (Vf - Vi) / t, where Vf is the final velocity, Vi is the initial velocity, and t is the time taken for the change in velocity. Substituting the given values, we get a = (12.0 m/s - 7.0 m/s) / 2.0 s = 2.5 m/s².
The acceleration of the car during the first 8 seconds (from 2 m/s to 10 m/s) is calculated by a = (Vf - Vi) / t = (10 m/s - 2 m/s) / 8 s = 1 m/s². During the last 6 seconds, when the car slows down from 10 m/s to 4 m/s, the acceleration is a = (4 m/s - 10 m/s) / 6 s = -1 m/s². Note the negative acceleration indicates a deceleration or slowing down.
On its own, a certain tow-truck has a maximum acceleration of 3.0 m/s2. what would be the maximum acceleration when this truck was towing a bus of twice its own mass?
The maximum acceleration would be 1.0 m/s² when this truck was towing a bus of twice its own mass
[tex]\texttt{ }[/tex]
Further explanationNewton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial acceleration = a₁ = 3.0 m/s²
mass of tow-truck = m₁ = m
mass of bus = m₂ = 2m
Asked:
final acceleration = a₂ = ?
Solution:
[tex]\texttt{Initial Force of Tow-Truck = Final Force of Tow-Truck }[/tex]
[tex]F_1 = F_2[/tex]
[tex]m_1 a_1 = m_2 a_2[/tex]
[tex]m (3.0) = (m + 2m) a_2[/tex]
[tex]3m = 3m (a_2)[/tex]
[tex]a_2 = 3m \div 3m[/tex]
[tex]\boxed{a_2 = 1.0 ~ \mathtt{ m/s^2}}[/tex]
[tex]\texttt{ }[/tex]
Conclusion :The maximum acceleration would be 1.0 m/s²
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Dynamics
After watching an advertisement for hand sanitizer on television, Ben decided to see just how effective the advertised hand sanitizer really was. Ben used warm water as his control. He compared the advertised sanitizer with two brands of hand soap. In all four trials he rubbed his hands together for two minutes. After using the three products and the control, he cultured the bacteria on his hands. He recorded the number of bacterial cultures that appeared on each culture plate. Ben's results can be seen in the data table. Ben concluded that both brands of soap were more effective in killing bacteria than the advertised hand sanitizer. What term BEST describes Ben's results for all four trials? A) biased B) inconclusive C) qualitative D) quantitative ASAPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Here Ben checked the quality of three sanitizer
He took all three and checked how much effective each soap is to kill the bacteria
He analyzed and find out that both brands of soap were more effective in killing bacteria than the advertised hand sanitizer
He took his decision on the basis of quality so this is qualitative analysis
option C is correct
Answer:
It is C
Explanation:
Which of these best explains the ability of small insects to walk on the surface of still water?
The ability of small insects to walk on water is due to surface tension, which results from cohesive forces among water molecules. This tension creates a thin 'skin' at the water's surface that can support the weight of light objects, such as insects.
The ability of small insects to walk on the surface of still water can be best explained by the phenomenon of surface tension. Surface tension is created due to the cohesive forces between water molecules at the liquid-air interface. This cohesion results in a thin 'skin' forming at the surface, which can support the weight of small insects like water striders. These insects distribute their weight over their long legs, ensuring that the force they exert is less than the surface tension holding the water molecules together, allowing them to effectively 'walk' on water.
An example of this can be seen when a paper clip or a thin razor blade is carefully placed on the surface of water without sinking, demonstrating the strength of surface tension.
Latent heat of fusion refers to which changes of state?
Answer:
Explanation:
The amount of energy required to change the state of matter at constant temperature is called latent heat.
There are two types of latent heat.
1. Latent heat of fusion: The amount of heat required to convert 1 kg of ice at 0 degree Celsius into 1 kg water at 0 degree Celsius is called latent heat of fusion.
2. Latent heat of vaporization: The amount of heat required to convert 1 kg of water at 100 degree Celsius into 1 kg steam at 100 degree Celsius is called latent heat of vaporization.
If the above two waveforms were sound waves, we would hear the ___________ wave louder. If the above two waveforms were light waves, we would see the ________ wave dimmer.
Answer:
the answer is green, red
One mole of ideal gas is slowly compressed to one-third of its original volume. in this compression, the work done on the gas has magnitude 672 j . for the gas, cp=7r/2.
when you squeeze the rubber bulb of a perfume atomizer how do you change the air pressure at the top of the tube
the record for a ski jump is 180 m set in 1989. Assume the jumper comes off the end of the ski jump horizontally and falls 90 m vertically before contacting the ground . what was the initial horizontal speed of the jumper?
A wave travels through water at a speed of 3 m/s and has a frequency of 10 Hz. What is the wavelength of the wave?
V=wavelength*frequency
3 m/s=wavelength*10 Hz
3m/s=10 Hz
wavelength= .3
Answer:
Wavelength of the wave, λ = 0.3 m
Explanation:
It is given that,
The speed of the wave, v = 3 m/s
The frequency of the wave, f = 10 Hz
We know the relationship between the frequency, wavelength and the speed of the wave. Mathematically, it can be written as :
[tex]speed=frequency\times lambda[/tex]
or
[tex]v=f\times \lambda[/tex]
[tex]\lambda=\dfrac{v}{f}[/tex]
[tex]\lambda=\dfrac{3\ m/s}{10\ Hz}[/tex]
[tex]\lambda=0.3\ m[/tex]
Hence, the wavelength of the wave is 0.3 m
A Geiger counter is like an electroscope that discharges whenever ions formed by a radioactive particle produce a conducting path. A typical Geiger counter consists of a thin conducting wire of radius 0.002 cm stretched along the axis of a conducting cylinder of radius 2.0 cm. The wire and the cylinder carry equal and opposites charges of 8.0 x 10-10 C all along their length of 10.0 cm. What is the magnitude of the electric field at the surface of the wire
The magnitude of the electric field at the surface of the wire in the Geiger counter can be found using the charge per unit length and the formula E = (1/(2πε0)) * (λ/r). Substituting the given values into the formula will yield the electric field at the wire's surface.
The student asked about calculating the magnitude of the electric field at the surface of the wire in a Geiger counter. To solve this, we will employ the formula for the electric field (E) generated by an infinitely long charged wire, which is given by E = (1/(2πε0)) * (λ/r), where λ is the charge per unit length and r is the radial distance from the wire. In this case, the charge per unit length λ is the total charge divided by the length of the wire, and r is the radius of the wire.
Given: Charge (Q) = 8.0 x 10-10 C, Length (L) = 10.0 cm = 0.1 m, and Wire radius (a) = 0.002 cm = 0.00002 m.
First, calculate the charge per unit length: λ = Q/L = (8.0 x 10-10 C) / (0.1 m) = 8.0 x 10-9 C/m.
Next, calculate the electric field using the radius of the wire (a) as radial distance (r): E = (1/(2πε0)) * (λ/a).
Using the value for the vacuum permittivity ε0 (approximately 8.854 x 10-12 C2/N·m2), the electric field on the surface of the wire is computed to be:
E = (1/(2π(8.854 x 10-12))) * (8.0 x 10-9 / 0.00002) N/C.
Simplifying this expression gives us the electric field at the surface of the wire.
Using the given values, the magnitude of the electric field at the surface of the wire (r = 0.002 cm or 0.00002 m) and L = 10 cm or 0.1 m is calculated as follows:
Convert the radius to meters: r = 0.002 cm = 0.00002 m.
Plugging in the values: E = (8.0 x 10-10 C) / (2π * 8.854 x 10-12 C2/Nm2 * 0.00002 m * 0.1 m).
Calculate the electric field: E = 2.87 x 106 N/C.
The magnitude of the electric field at the surface of the wire in the Geiger counter is therefore 2.87 x 106 Newtons per Coulomb (N/C).
The magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].
The magnitude of the electric field at the surface of the wire is given by the formula:
[tex]\[ E = \frac{\sigma}{\varepsilon_0} \][/tex]
where [tex]\( \sigma \)[/tex] is the surface charge density of the wire, and [tex]\( \varepsilon_0 \)[/tex]is the vacuum permittivity [tex](\( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \)).[/tex]
The surface charge density [tex]\( \sigma \)[/tex] can be calculated by dividing the total charge [tex]\( Q \)[/tex] by the surface area [tex]\( A \)[/tex] of the wire. The surface area of a cylinder is given by [tex]\( A = 2\pi r h \)[/tex], where [tex]\( r \)[/tex] is the radius and [tex]\( h \)[/tex] is the height (or length in this case) of the cylinder.
Given:
- Radius of the wire, [tex]\( r = 0.002 \, \text{cm} = 2 \times 10^{-5} \, \text{m} \) (since 1 cm = 0.01 m)[/tex]
- Length of the wire, [tex]\( h = 10.0 \, \text{cm} = 0.1 \, \text{m} \)[/tex]
- Total charge on the wire, [tex]\( Q = 8.0 \times 10^{-10} \, \text{C} \)[/tex]
First, we convert the radius from centimeters to meters for consistency in units:
[tex]\[ r = 0.002 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} = 2 \times 10^{-5} \, \text{m} \][/tex]
Now, we calculate the surface area of the wire:
[tex]\[ A = 2\pi r h = 2\pi (2 \times 10^{-5} \, \text{m})(0.1 \, \text{m}) \][/tex]
[tex]\[ A = 4\pi \times 10^{-6} \, \text{m}^2 \][/tex]
Next, we calculate the surface charge density [tex]\( \sigma \)[/tex]:
[tex]\[ \sigma = \frac{Q}{A} = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \][/tex]
[tex]\[ \sigma = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \approx \frac{8.0 \times 10^{-10}}{12.56637 \times 10^{-6} \, \text{m}^2} \][/tex]
[tex]\[ \sigma \approx 6.3662 \times 10^{-5} \, \text{C/m}^2 \][/tex]
Finally, we calculate the magnitude of the electric field at the surface of the wire:
[tex]\[ E = \frac{\sigma}{\varepsilon_0} = \frac{6.3662 \times 10^{-5} \, \text{C/m}^2}{8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2} \][/tex]
[tex]\[ E \approx 7.19 \times 10^{6} \, \text{N/C} \][/tex]
Therefore, the magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].
A water balloon weighing 19.6 N rests on a table. The balloon has an area of 0.015 m^2 in contact with the table. What pressure does the balloon exert on the table?
If you were creating an electrical circuit and ran out of wire what materials would you use
A:yarn
B:licorice strings
C:plastic knitting needle
D:tin foil
A 0.55-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1.3 m on a frictionless horizontal surface. if the cord will break when the tension in it exceeds 75 n, what is the maximum speed the ball can have?
The force act on the body tries to attract the body inward towards the circle when the body is executing circular motion. The maximum value of speed will be 13.3 m/sec.
What is centripetal force?The force operating on an object in curvilinear motion directed toward the axis of rotation or center of curvature is known as centripetal force.
Newton is the unit of centripetal force.
The centripetal force is always perpendicular to the direction of displacement of the item. The centripetal force of an item traveling on a circular route always works towards the center of the circle.
Due to rotation, the tension is act in the chord which is equal to the centripetal force act the ball.
[tex]\rm T = F_c= \frac{mv^2}{r}[/tex]
Tension in the cord = T= 75 N
Centripetal force = [tex]F_c[/tex]
Mass of the ball= m= 0.55 Kg
Linear speed =v= ?
The radius of the circle.= r = 1.3 m
T is the maximum tension before the cord breaks. So according to the condition the obtained velocity will be ;
[tex]\rm v = \sqrt{\frac{Tr}{m} } \\\\ \rm v = \sqrt{\frac{75\times1.3}{0.55} }\\\\ \rm v = 13.3 \;m/sec[/tex]
Hence the maximum value of speed will be 13.3 m/sec.
To learn more about the centripetal force refer to the link;
https://brainly.com/question/10596517
If you mix equal amounts of cyan pigments and magenta pigments on a sheet of white paper, what color will you see on the paper?
A. Red
B. Blue
C. Black
D. Yellow
E. Cyan
F. Magenta
A box is initially sliding across a frictionless floor toward a spring which is attached to a wall. the box hits the end of the spring and compresses it, eventually coming to rest for an instant before bouncing back the way it came. the work done by the spring on the box as the spring compresses is:
What happens to light when it changes speed?
A)It reflects
B)It polarizes
C)It refracts.
Answer:
The correct answer is C) Refracts
A bag of sports equipment has a mass of 10.0 kilograms and a weight of
The weight of the bag of sports equipment is 98N
From the question,
We are to determine the weight of a bag of sports equipment that has a mass of 10.0 kg
The weight of an object with a given mass can be determined by using the formula
W = mg
Where
W is the weight
m is the mass
and g is the acceleration due to gravity (g = 9.8 m/s²)
From the given information,
m = 10.0 kg
∴ Weight of the bag of sports equipment,
W = 10.0 × 9.8
W = 98 N
Hence, the weight of the bag of sports equipment is 98N
Learn more here: https://brainly.com/question/20898566
While parachuting, a 66.0-kg person experiences a downward acceleration of 2.60 m/s2. 1) what is the downward force on the parachute from the person? (express your answer to three significant figures?
Final answer:
The downward force on the parachute from the 66.0 kg person experiencing a downward acceleration of 2.60 m/s2 is 171.6 newtons, calculated using Newton's second law of motion (F = ma).
Explanation:
The question asks for the downward force on the parachute from a person with a mass of 66.0 kg experiencing a downward acceleration of 2.60 m/s2. To find this force, we use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a), or F = ma.
To calculate the force, we multiply the person's mass (66.0 kg) by the given acceleration (2.60 m/s2):
F = 66.0 kg × 2.60 m/s2
= 171.6 N
The downward force exerted on the parachute by the person is therefore 171.6 newtons, expressed to three significant figures.
HURRY The compressed spring of a dart gun has potential energy of 50 J. If the spring constant is 200 N/m, what is the displacement of the spring?
A. 0.5 m
B. 0.2 m
C. 0.7 m
D. 0.4 m
Answer: its C on edge 2023. =0.7
Explanation: He's right just putting it in a quicker format.
A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J/(kg * K) B. 383 J/(kg*K) C. 130 J/(kg * K) D. 897 J/(kg*K)
Why is it important to know the direction of the force applied to a moving object and the direction in which the object is moving when determining the work done on the object?
A. Only the component of the force perpendicular to the motion is used to calculate the work.
B. If the force acts in the same direction as the motion, then no work is done.
C. When there is an angle between the two directions, the cosine of the angle must be considered.
D. A force at a right angle to the motion requires the use of the sine of the angle.
Answer:
C. When there is an angle between the two directions, the cosine of the angle must be considered.
Explanation:
I can confirm answer is C.
The charge per unit length on a long, straight filament is -94.5 µc/m. (a) find the electric field 10.0 cm from the filament, where distances are measured perpendicular to the length of the filament. (take radially inward toward the filament as the positive direction.)
The electric field at 10.0 cm from a long, straight filament with a charge per unit length of -94.5 µC/m can be calculated using the formula E = λ / (2πε₀r), producing a value directed radially inward.
Explanation:Finding the Electric Field from a Charged Filament
The problem is asking us to calculate the electric field generated by a long, straight filament with a given charge per unit length. By using Gauss's law, we can find the electric field at a distance from the filament. Since the electric field of a uniformly charged infinite line is symmetrical, it only depends on the distance from the line, and it is directed radially.
We can use the formula for the electric field created by an infinitely long straight filament, which is:
E = λ / (2πε0r)
Where:
ε0 is the permittivity of free space (approximately 8.85 x 10-12 C2/N·m2).
r is the distance from the filament, which is 10.0 cm (or 0.10 meters).
By substituting the known values into the equation:
E = (-94.5 x 10-6 C/m) / (2π x 8.85 x 10-12 C2/N·m2 x 0.10 m)
We perform the calculation to find the magnitude and direction of the electric field. The negative sign of λ indicates that the electric field is directed radially inward, towards the filament.
A bolt is dropped from a bridge under construction, falling 80 m to the valley below the bridge. (a) how much time does it take to pass through the last 17 % of its fall? what is its speed (b) when it begins that last 17 % of its fall and (c) just before it reaches the ground?
It takes Harry 34 s to walk from x1 = -11 m to x2 = -54 m .
Referring to the map of the temperature field in the room, where was the warmest field found?
The warmest field on a temperature map is indicated by warmer colors such as red or orange. On maps like those from the WMAP spacecraft, red represents higher temperatures. In thermographic maps of buildings, warmer areas show where heat transfer is most severe.
Explanation:The warmest field on a map showing temperature variations can typically be found in regions marked with a warmer color, such as red or orange, indicating higher temperatures. In the context of the map used by the WMAP spacecraft to show fluctuations in the cosmic microwave background, red represents areas of higher temperature and higher density. Similarly, thermographic maps of buildings, like Figure 1.32, use color to indicate variations in temperature, with warmer areas potentially signifying regions where heat transfer is most severe, such as through windows.
It's important to carefully analyze the colors and legends provided on the map to determine the precise locations of the warmest fields. When maps show global temperature changes, such as Figure 24.9.5, the land areas and the Arctic are noted for having experienced the greatest increases in temperature relative to mid-20th-century baseline values.
how did the world form
Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?
List at least 3 physical properties that the professor describes of his newly discovered flubber
Answer:
Flubber is a combination of two words Fluid+ Rubber. It means flubber has physical properties of both fluid and rubber(solid).
Physical properties of Flubber are as follows
1. It has elasticity like rubber
2. It can take the shape of the container in which it is filled. It does not have any particular shape like fluid.
3.It has viscoplastic nature
4. It is gelatinous
5. It flows under low pressure and can break when high pressure is applied on it.
Manuel is holding a 5kg box. How much force is the box exerting on him?In what direction
The box that Manuel is holding would exert a force of 49 N, directed downwards due to gravity. This calculation is done using the mass of the box and the acceleration due to gravity. According to Newton's third law, the force exerted by the box on Manuel would be in the opposite direction to which he lifts it.
Explanation:The box that Manuel is holding exerts a force equal to its weight due to gravity. The weight can be calculated using the formula F = mg, where F is the force, m is the mass of the object, and g is the acceleration due to gravity. In this case, the mass of the box is 5 kg and assuming the acceleration due to gravity to be approximately 9.8 m/s², we can calculate the force as F = (5 kg) * (9.8 m/s²) = 49 N.
As for the direction, the direction of the force is always directed downwards or towards the center of the Earth because gravity is the force involved in this situation. To be more specific, the force that the box exerts on Manuel is in the opposite direction to which he lifts it, according to Newton's third law of motion which states that for every action, there is an equal and opposite reaction. Therefore, the box exerts a downward force of 49 Newtons on Manuel.
Learn more about Force and Gravity here:https://brainly.com/question/13634821
#SPJ3