Which statement correctly describes the current in a circuit that is made up of any two resistors connected in series with a battery
A. The current in the battery is less than the current in either resistor.
B. The current in the battery equals the product of the currents in the resistors.
C. The current in the battery equals the sum of the currents in the resistors.
D. The current in the battery and in each resistor is the samattery?

Answers

Answer 1
The answer is D. The current in the battery and in each resistor is the same. 

If we have two or more components in series, the current that flows through each of them is the same.

In this case, the battery generates the current, and since there must be conservation of electric charge, no current can be lost through the resistors.
Answer 2

for those on ~ a p e x ~ note that this question asks when the resistors are connected in SERIES

if you have the question for in PARALLEL the answer is:

> The current the battery equals to the sum of the currents in the resistors

wink wonk


Related Questions

Why does light refract when it encounters the glass in a lens?
A) because it speeds up, which causes it to bend
B) because it slows down, which causes it to bend
C) because it hits a dense medium, which causes it to bounce off
D) because it gets absorbed, which causes it to lessen in intensity

Answers

Hey there Donnell!

The reason to why light refract when it encounters the glass in a lens would be because it slows down, which causes it to bend, this would be the reason why  light refract when it encounters the glass in a lens.

I hope this helps you!

Answer:

B) because it slows down, which causes it to bend

Explanation:Light hits the glass in a lens because it slows down, which causes it to bend. The material of a lens is more optically dense than the air it is traveling from.

When a clock reads 5.0 seconds a cart's velocity in the negative x direction is 3.0 m/s. when the clock reads 6.0 seconds, the cart's velocity in the positive x direction is 4.0 m/s. what is the magnitude (in m/s2) of the average acceleration of the cart?

Answers

Impulse is the change of momentum before and after the collision:
I = mv₁ - mv₂ = m (v₁-v₂)
m mass
v velocity

Impuls also is defined as the average force during a short period of time:
I = F * t = m * a * t
F average force
t time difference
m mass
a average acceleration

Combined:
m(v₁- v₂) = m * a * t
a = (v₁- v₂) / t
= (4m/s - (-3m/s)) / 6s - 5s
= 7m/s / 1s
= 7 m/s²


The kinematic we find the average acceleration of the body is 7 m/s²

Given parameters

The velocity at two instant of time t₁ = 5.0 s, v₁ = -3.0 m / s

           t₂= 6.0 s,  v₂ = 4.0 m / s

To find

The average acceleration of the body

Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.

Average acceleration is defined as the change in velocity in a given time interval

             a_ {avg} = [tex]\frac{\Delta v}{\Delta t}[/tex]

Let's apply this expression to our case

let's set a reference frame where the positive direction of the x axis is positive, so v₁ is negative

         

             a_ {avg} = [tex]\frac{v_2 -v_1}{t_2 -t_1}[/tex]

             a_ {avg} = [tex]\frac{4- (-3)}{6-5}[/tex]

             a_ {avg} = 7 m / s²

In conclusion using kinematics we find the average acceleration of the body is 7 m / s²

learn more about average acceleration here:

https://brainly.com/question/17355747

What resistance is needed in this rc circuit if the flash is to charge to 90% of its full charge in 22 s ?

Answers

Missing part in the text of the problem:
"a flash unit for a camera has a capacitance of1200μF."

Solution:
In a RC circuit, the charge of the capacitor at time t follows the relationship:
[tex]Q(t) = Q_0 (1-e^{- \frac{t}{\tau} })[/tex]
where [tex]Q_0 [/tex] is the full charge, and [tex]\tau = RC[/tex] is the time constant of the circuit. 

We can isolate [tex]\tau[/tex] from the previous equation:
[tex] \frac{Q(t)}{Q_0} = 1-e^{ \frac{t}{\tau} } [/tex]
[tex] \frac{t}{\tau} = -ln(1- \frac{Q(t)}{Q_0}) [/tex]
[tex]\tau = - \frac{t}{ln(1- \frac{Q(t)}{Q_0} )} [/tex]

We can now using the data of the problem. We know that after a time t=22.0s, the capacitor is at 90% of tis charge, therefore [tex] \frac{Q(t)}{Q_0} = 0.9[/tex]. So we find
[tex]\tau = - \frac{22}{ln(1-0.9)}=9.55 s [/tex]

And from this value we can find the value of the resistance R, since we know that [tex]\tau = RC[/tex]. Given [tex]C=1200 \mu F = 1200 \cdot 10^{-6} F[/tex], we have
[tex]R= \frac{\tau}{C}= \frac{9.55s}{1200 \cdot 10^{-6}F}=7958 \Omega = 7.96 k \Omega [/tex]

A raft is made of a plastic block with a density of 650 kg/m 3 , and its dimensions are 2.00 m à 3.00 m à 5.00 m. 1. what is the volume of the raft? _________________________________________________________________ 2. what is its mass? _________________________________________________________________ 3. what is its weight? _________________________________________________________________ 4. what is the raft's ap parent weight in water? (hint: density of water = 1.00 à 10 3 kg/m 3 ) _________________________________________________________________ 5. what is the buoyant force on the raft in water? _________________________________________________________________ 6. what is the mass of the displaced water? _________________________________________________________________ 7. what is the volume of the displaced water? _________________________________________________________________ 8. how much of the raft's volume is below water? how much is above? _________________________________________________________________ 9. answer items 5 â 8 using ethanol (density = 0.806 à 10 3 kg/m 3 ) instead of water.

Answers

1) The volume of the raft is the product between the lenghts of its three dimensions:
[tex]V = (2.00 m)(3.00m)(5.00m)=30 m^3[/tex]

2) The mass of the raft is the product between its density, d, and its volume, V:
[tex]m=dV=(650 kg/m^3)(30 m^3)=19500 kg[/tex]

3) The weight of the raft is the product between its mass m and the gravitational acceleration, [tex]g=9.81 m/s^2[/tex]:
[tex]W=mg=(19500 kg)(9.81 m/s^2)=1.91 \cdot 10^5 N[/tex]

4) The apparent weight is equal to the difference between the weight of the raft and the buoyancy (the weight of the displaced fluid):
[tex]W_a = W- \rho_W V_{disp} g[/tex]
where [tex]\rho _W = 1000 kg/m^3[/tex] is the water density and [tex]V_{disp}[/tex] is the volume of displaced fluid.
The density of the raft ([tex]650 kg/m^3[/tex]) is smaller than the water density ([tex]1000 kg/m^3[/tex]), this means that initially the buoyancy (which has upward direction) is larger than the weight (downward direction) and so the raft is pushed upward, until it reaches a condition of equilibrium and it floats. At equilibrium, the weight and the buoyancy are equal and opposite in sign:
[tex]W=B=\rho _W V_{disp} g[/tex]
and therefore, the apparent weight will be zero:
[tex]W_a = W-B=W-W=0[/tex]

5) The buoyant force B is the weight of the displaced fluid, as said in step 4):
[tex]B=\rho_W V_{disp} g[/tex]
When the raft is completely immersed in the water, the volume of fluid displaced [tex]V_{disp}[/tex] is equal to the volume of the raft, [tex]V_{disp}=V[/tex]. Therefore the buoyancy in this situation is
[tex]B= \rho_W V g = (1000 kg/m^3)(30 m^3)(9.81 m/s^2)=2.94 \cdot 10^5 N[/tex]
However, as we said in point 4), the raft is pushed upward until it reaches equilibrium and it floats. At equilibrium, the buoyancy will be equal to the weight of the raft (because the raft is in equilibrium), so:
[tex]B=W=1.91 \cdot 10^5 N[/tex]

6) At equilibrium, the mass of the displaced water is equal to the mass of the object. In fact, at equilibrium we have W=B, and this can be rewritten as
[tex]mg = m_{disp} g[/tex]
where [tex]m_{disp}= \rho_W V_{disp}[/tex] is the mass of the displaced water. From the previous equation, we obtain that [tex]m_{disp}=m=19500 kg[/tex].

7) Since we know that the mass of displaced water is equal to the mass of the raft, using the relationship [tex]m=dV[/tex] we can rewrite [tex]m=m_{disp}[/tex] as:
[tex]d V =d_W V_{disp}[/tex]
and so
[tex]V_{disp}= \frac{d V}{d_W}= \frac{(650 kg/m^3)(30m^3)}{1000kg/m^3}= 19.5 m^3 [/tex]

8) The volume of water displaced is (point 7) [tex]19.5 m^3[/tex]. This volume is now "filled" with part of the volume of the raft, therefore [tex]19.5 m^3[/tex] is also the volume of the raft below the water level. We can calculate the fraction of raft's volume below water level, with respect to the total volume of the raft, [tex]30 m^3[/tex]:
[tex] \frac{19.5 m^3}{30 m^3}\cdot 100= 65 \% [/tex]
Viceversa, the volume of raft above the water level is [tex]30 m^3-19.5 m^3 = 10.5 m^3[/tex]. Therefore, the fraction of volume of the raft above water level is
[tex] \frac{10.5 m^3}{30 m^3}\cdot 100 = 35 \% [/tex]

9) Let's repeat steps 5-8 replacing [tex]\rho _W[/tex], the water density, with [tex]\rho_E=806 kg/m^3[/tex], the ethanol density.

9-5) The buoyant force is given by:
[tex]B=\rho _E V_{disp} g = (806 kg/m^3)(30 m^3)(9.81 m/s^2)=2.37 \cdot 10^5 N[/tex]
when the raft is completely submerged. Then it goes upward until it reaches equilibrium and it floats: in this condition, B=W, so the buoyancy is equal to the weight of the raft.

9-6) Similarly as in point 6), the mass of the displaced ethanol is equal to the mass of the raft: 
[tex]m_E = m = 19500 kg[/tex]

9-7) Using the relationship [tex]d= \frac{m}{V} [/tex], we can find the volume of displaced ethanol:
[tex]V_E = \frac{m}{d_E} = \frac{19500 kg}{806 kg/m^3}=24.2 m^3 [/tex]

9-8) The volume of raft below the ethanol level is equal to the volume of ethanol displaced: [tex]24.2 m^3[/tex]. Therefore, the fraction of raft's volume below the ethanol level is 
[tex] \frac{24.2 m^3}{30 m^3}\cdot 100 = 81 \% [/tex]
Consequently, the raft's volume above the ethanol level is 
[tex]30 m^3 - 24.2 m^3 = 5.8 m^3[/tex]
and the fraction of volume above the ethanol level is
[tex] \frac{5.8 m^3}{30 m^3}\cdot 100 = 19 \% [/tex]

In a thermostat, what property of the bimetallic coil allows it to contract and expand? The two metals absorb different amounts of thermal energy. The two metals are placed perpendicular to each other. The two metals burn at different temperatures. The two metals turn into liquids when absorbing energy.

Answers

Hello!

In a thermostat, the property of the bimetallic coil that allows it to contract and expand is that The two metals absorb different amounts of thermal energy. 

This bimetallic coil is used to transform thermal energy into mechanical movement. Two metals with different thermal expansivity are joined together parallelly and the changes of temperature cause bending in different directions depending on if the temperature is rising or descending. 

The differences in the thermal energy absorption of the two metals are the basis for the mechanism of this device. 

Answer:

The two metals absorb different amounts of thermal energy.

Explanation:

Temperature controlling device in an electric equipment like a heater, is called a thermostat.

A bimetallic strip contains two different metals. Each metal has its own characteristic property of expansion or cooling. Coefficient of thermal expansion has a different value for different metals.

The metal that has a higher expansion coefficients will expand more when  heated, compared to the metal that has a lower coefficient of expansion.

In a thermostat used in a heating circuit, the electric contact is cut off due to the bending of the bimetallic strip, when the desired temperature is reached.

What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.
1.1 × 10–17 J 
1.1 × 10–16 J
8.3 × 10–16 J
8.3 × 10–15 J

Answers

The energy carried by a single photon is given by
[tex]E=hf[/tex]
where h is the Planck's constant and f is the frequency of the photon.

The photon of our exercise has a frequency of [tex]f=1.7 \cdot 10^{17} Hz[/tex], therefore its energy is
[tex]E=hf=(6.63 \cdot 10^{-34}Js)(1.7 \cdot 10^{17} Hz)=1.1 \cdot 10^{-16} J[/tex]

Answer:

The correct answer is B.

Explanation:

Got a 100% on the Exam

A proton is fired from far away toward the nucleus of a mercury atom. mercury is element number 80, and the diameter of the nucleus is 14.0 fm. part a if the proton is fired at a speed of 3.4×107 m/s , what is its closest approach to the surface of the nucleus? assume the nucleus remains at rest. express your answer to two significant figures and include the appropriate units.

Answers

The initial kinetic energy of the proton is given by:
[tex]K= \frac{1}{2} mv^2[/tex]
where [tex]m=1.67\cdot 10^{-27}kg[/tex] is the proton mass and [tex]v=3.4\cdot 10^7 m/s[/tex] is the initial speed.

As the proton approaches the nucleus, it decelerates because of the repulsive electric field and its kinetic energy converts into electric potential energy. The proton will stop at a distance r from the center of the nucleus, and its potential energy at this distance will be:
[tex]U=k_e \frac{(80e)(e)}{r} [/tex]
where [tex]k_e = 8.99\cdot 10^9 N m^2 C^{-2}[/tex], 80e is the charge of the nucleus of mercury (which contains 80 protons), and [tex]e=1.6\cdot 10^{-19}C[/tex] is the proton charge.

For the conservation of energy,
[tex]K=U[/tex]
Rewriting it, we find
[tex]r=2k_e \frac{(80e)(e)}{mv^2}=3.4 \cdot 10^{-15} m =34 fm [/tex]

This is not the final answer, however, because this is the distance reached by the proton with respect to the center of the nucleus. So, to find the distance from the surface, we should subtract the radius of the nucleus, which is half the diameter: 14/2=7 fm. So
[tex]d=r-r_0=34 fm-7 fm=27 fm =2.7 \cdot 10^{-15 } m[/tex]

Answer:

[tex]27fm[/tex]

Explanation:

Kinetic Energy of proton

[tex]Kinetic Energy (K)=\frac{1}{2}mV^{2}[/tex]

[tex]m=Mass of proton[/tex]

[tex]V=Velocity of proton[/tex]

[tex]m=1.67\times 10^{-27} kg[/tex]

[tex]V=3.4\times 10^{7}ms^{-1}[/tex]

[tex]K=\frac{1}{2}\times 1.67\times 10^{-27}kg\times \left (3.4\times 10^{7}ms^{-1}  \right )^2[/tex]

[tex]K=\frac{19.305}{2}\times 10^{-13}J[/tex]

[tex]K=9.65\times 10^{-13}J[/tex]

For conservation of energy;

[tex]Kinetic Energy=Potential energy[/tex]

[tex]K= U[/tex]

So,

[tex]U= 9.65\times 10^{-13}J[/tex]

Here,

[tex]U=Potential Energy[/tex]

[tex]U=k_{e}\frac{q_{1}q_{2}}{r}[/tex]

Here,

[tex]k_{e}=Coulomb's law constant[/tex]

[tex]k_{e}=8.99\times 10^{9}Nm^{2}C^{-2}[/tex]

[tex]q_{1}=80e[/tex]

[tex]q_{2}=e[/tex]

[tex]e=1.602\times 10^{-19}C[/tex]

[tex]r=The distance that proton will stop from the center of the nucleus[/tex]

[tex]U=k_{e}\frac{80e\times e}{r}[/tex]

[tex]9.65\times 10^{-13}J=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{r}[/tex]

[tex]r=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{9.65\times 10^{-13}J}[/tex]

[tex]34fm[/tex]

[tex]r_{0}=Radius of the atom[/tex]

[tex]Radius\left ( r_{0} \right )=\frac{diameter\left ( d \right )}{2}[/tex]

[tex]Diameter of the nucleus of mercury atom=14fm[/tex]

[tex]Radius of atom =\frac{14fm}{2}[/tex]

[tex]r=7fm[/tex]

[tex]d=r-r_{0}[/tex]

[tex]d=34fm-7fm[/tex]

[tex]d=27fm[/tex]

Further Explanation:

When a proton approaches a nucleus, it decelerates. Because the repulsive electric field and its kinetic energy converts into electric potential energy.  

Then due to this, the proton will stop at a distance “r” from the center of the nucleus.  

To find the distance from the surface where the proton hits, we have to subtract the radius of the nucleus.  

Learn more:

1. Kinetic energy https://brainly.com/question/1621817 (answer by skyp)

2. Potential energy https://brainly.com/question/12489105 (answer by nitrotype2000)

3. Conservation of energy https://brainly.com/question/11911812 (answer by hrishisup)

Keywords:

Kinetic energy, potential energy, conservation of energy.  

You see a marble sign. Its letters are too worn to read. What caused this?

Answers

The worn letters on a marble sign are the result of weathering and erosion from natural elements, human activities, and pollution, which cause the marble to deteriorate over time.

If you see a marble sign with letters too worn to read, it's likely that the sign has been subjected to various forms of weathering and erosion. Over time, natural elements like rain, wind, temperature changes, and possibly even the growth of lichens or moss can cause the marble to wear down. This process can gradually erase the inscriptions on the sign.

Additionally, human activities such as touching or rubbing the sign can accelerate the erosion of marble, further contributing to the letters becoming unreadable. Moreover, pollution can also have a corrosive effect on marble, causing the inscriptions to fade more quickly.

Overall, the combined effects of natural weathering, human interference, and environmental pollutants are responsible for the deterioration of marble signs and their inscriptions.

Tai ran from his home to a position 300 m south of his home in 100 seconds. What was his velocity? A.0.33 m/s south B.0.33 m/s north C.3 m/s north D.3 m/s south

Answers

[tex]velocity = distance / time = 300m/100s = 3m/s [/tex]

When photons with a wavelength of 310 nm strike a magnesium plate the maximum velocity of the ejected electrons is 3.45*10^5 m/s. calculate the binding?

Answers

Given that the work function for sodium metal is 1.82 eV, what is the threshold frequency? 0. 1. 1. 0. 1. 1. 34. • When photons with a wavelength of 310 nm strike a magnesium plate, the maximum velocity of the ejected electrons is 3.45x10. 5 m/s. Calculate the binding energy of electrons to the magnesiumsurface. 1. 2. 2 +. 1.

13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coasting. B) a driver's foot off the accelerator and on the break pedal. C) a driver's foot on the accelerator pressed down to maintain speed. D) a driver's foot on the accelerator and pressed down gradually more and more.

Answers

a driver's foot off the accelerator and on the break pedal. C

Its D: A driver's foot on the accelerator and pressed down gradually more and more.

What properties of titanium make it attractive for use in race-car and jet-engine components?

Answers

Titanium's high quality to weight proportion and corrosion protection at room and hoisted temperature makes it appealing for use in elite applications. High cost of titanium is the key purpose behind not utilizing it in traveler autos. The cost of large scale manufacturing of the parts would drive the last items cost fundamentally.

At what separation will two charges, each of magnitude 6.0fYC,exert a force of 1.4N on each other?

a.0.48m

b.2.0m

c.5.1*10^6m

d.0.23m

e.40m

Answers

I assume that "fYC" is just a writing mistake and the two charges have magnitude [tex]q=6 \mu C=6 \cdot 10^{-6}C[/tex].
The electrostatic force between the two charges is
[tex]F=k_e \frac{q^2}{d^2} [/tex]
where [tex]k_e = 8.99 \cdot 10^9 Nm^2C^{-2}[/tex] is the Coulomb's constant, q is the magnitude of the two charges, and d is the separation between them.

We know the value of the force, F=0.14 N, so re-arranging the formula and using these data we can solve to find the value of d:
[tex]d= \sqrt{ \frac{k_e q^2}{F} } =0.48 m[/tex]

So, the separation between the two charges is 0.48 m.

This question involves the concept of Colomb's Law and electrostatic force.

The separation between charges will be "a. 0.48 m".

COLOMB'S LAW

According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

where,

F = electrostatic force = 1.4 Nk = Colomb's constant = 9 x 10⁹ N.m²/C²q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ Cq₂ = magnitude of second charge = 6 μC = 6 x 10⁻⁶ Cr = distance between charges = ?

Therefore,

[tex]1.4 N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{r^2}\\\\r=\sqrt{\frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{1.4\ N}}[/tex]

r = 0.48 m

Learn more about Colomb's Law here:

brainly.com/question/9774180

14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?

Answers

The relationship between resistance R and resistivity [tex]\rho[/tex] is
[tex]R= \frac{\rho L}{A} [/tex]
where L is the length of the wire and A its cross section.

The radius of the wire is half the diameter:
[tex]r= \frac{d}{2}= \frac{1.6 mm}{2}=0.8 mm=8\cdot 10^{-4} m [/tex]
and the cross section is
[tex]A=\pi r^2 = \pi (8\cdot 10^{-4} m)^2=2.01\cdot 10^{-6} m^2[/tex]

From the first equation, we can then find the length of the wire when [tex]R=4.8 \Omega[/tex] (copper resistivity: [tex]\rho = 1.724 \cdot 10^{-8} \Omega m[/tex])
[tex]L= \frac{AR}{\rho}= \frac{(2.01\cdot 10^{-6} m^2)(1.724 \cdot 10^{-8} \Omega m)}{4.8 \Omega}=7.21 \cdot 10^{-15} m [/tex]

If an object that enters the Earth’s atmosphere does not completely disintegrate, its remains can impact the Earth true or flase

Answers

true, when entering earths atmosphere there are stages. also known as the Thermosphere. stage 3. Where tempatures are hotter then any other stage. but do not burn all the way. mainly like a "shooting star".

Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.

Answers

When the Skydiver jump out a plane, his Potential Energy is being converted or transform into Kinetic energy due to gravity. Hope this helps

Answer:

Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.

Explanation:

Thats the answer

Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of 50 kilograms. What can Paul do to increase the bike’s kinetic energy?

A. He can let Ivan off at the next stop.
B. He can pedal harder to increase the rate to 10 meters/second.
C. He can reduce the speed to 3 meters/second.
D. He can pick up a third rider.

Answers

The formula is Ke = 1/2 m v^2
The two of them together have a Ke of mv^2. So you either increase m or v. That's what makes the problem difficult. He can do D or B. We have to choose.

A is no solution. The Ke goes down because Paul loses Ivan's mass.
C is out of the question 3 meters/sec is a big reduction from 5 m/s. So now what do we do about B and D?

The question is what does the third person add. The tandoms I've peddled only allow for 1 or 2 people to add to the motion. So the third person only adds mass. He does not have a v that he is contributing to. To say that he is going 5m/s is true, but he's not contributing anything to that motion.

I pick B, but it is one of those questions that the correctness of it is in the head of the proposer. Be prepared to get it wrong. Argue the point politely if you agree with me, but back off as soon as you have presented your case.

B <<<<====== answer. 

Answer: The correct answer is option C.

Explanation:

Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:

[tex]K.E.=\frac{1}{2}mass\times (velocity)^2[/tex]

Kinetic energy depends upon the mass and velocity of the an object.

So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.

Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion

Consider a ball rolling down the decreasing slope inside a semicircular bowl (the slope is steep at the top rim, gets less steep toward the bottom, and is zero (no slope) at the bottom). As the ball rolls from the rim downward toward the bottom, its rate of gaining speed

Answers

The answer would be:
It's rate of gaining speed decreases.
The rate at which speed changes is called acceleration, 
You can think of this problem as an inclined plane. But the angle of an inclined plane is constantly decreasing.
We know that on a frictionless inclined plane acceleration of an object is:
[tex]a=gsin(\theta)[/tex]
Where g is the gravitational acceleration of the Earth and [tex] \theta[/tex] is the angle of an inclined plane. 
Using our analogy, the ball would start on an inclined plane with a 90-degree angle and that angle would continue to decrease to zero. 
The sine function is 1 at 90 degrees and is equal to zero at 0 degrees. Since our acceleration is proportional to the sine, and sine function is decreasing with the angle, our acceleration is also decreasing.

Tom and his little sister are enjoying an afternoon at the ice rink. they playfully place their hands together and push against each other. tom's mass is 61 kg and his little sister's mass is 15 kg. if the sister's acceleration is 2.1 m/s2 in magnitude, what is the magnitude of tom's acceleration?

Answers

Newton's third law says:
"For every action, there is an equal and opposite reaction. ".

So, the force that Tom does on the sister is equal to force the sister applies on Tom:
[tex]F_t = F_s[/tex]
where the label "t" means "on Tom", while the label "s" means "on the sister".

From Newton's second law, we also know
[tex]F=ma[/tex]
where m is the mass and a the acceleration. so we can rewrite the first equation as
[tex]m_t a_t = m_s a_s[/tex]
And find Tom's acceleration:
[tex]a_t = \frac{m_s}{m_t} a_s = \frac{15 kg}{61 kg} (2.1 m/s^2) =0.52 m/s^2[/tex]
Final answer:

Under the principle of conservation of momentum, Tom and his sister exert equal and opposite forces on each other when they push, leading to equal and opposite accelerations. Tom's acceleration is given by the force his sister exerts (her mass times her acceleration) divided by his mass. Thus, his acceleration is calculated to be 0.516 m/s².

Explanation:

This problem involves the principle of conservation of momentum in physics. When Tom and his sister push against each other, they exert equal and opposite forces, leading to equal and opposite accelerations because acceleration = force/mass. The sister's acceleration (2.1 m/s²), as given in the problem, is directed away from Tom. To find Tom's acceleration, we need to use the equation: force = mass * acceleration (from Newton's 2nd law), solve this equation for Tom assuming that the force exerted by Tom and his sister on each other is the same.

Assuming that his sister's mass (15 kg) times her acceleration (2.1 m/s²) gives the force they exert on each other, we get 15 kg * 2.1 m/s² = 31.5 N. Then we divide this force by Tom's mass (61 kg) to get his acceleration: 31.5 N / 61 kg = 0.516 m/s². Therefore, Tom's acceleration is 0.516 m/s² away from his sister.

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5. Amy and Josh are coasting on their bicycles down a 10° slope at 15 m/s through still air. The mass of Amy and her bicycle is 60 kg. The mass of Josh and his bicycle is 90 kg. The cross-sectional area of Amy and her bicycle is 0.45, while the cross-sectional area of Josh and his bicycle is 0.60. The drag coefficient for both cyclists is 0.70. Other than gravity and air resistance, the external forces acting on the two bicycle and rider systems are the same. Which cyclist is more affected by air resistance? The Answer is Amy but what is the math invovled, Please Show Work and Help!

Answers

Forces in the x-direction:

[tex]ma = mg*sin \theta - cA v^{2} [/tex]

The acceleration:
[tex]a = g*sin \theta - \frac{cA}{m} v^2[/tex]

The first term is independent of mass, only the second term depends on mass m:
[tex]\frac{cA}{m} v^2 [/tex]
Amy:
[tex]\frac{0.45 * 0.7}{60} v^2 = 0.00525v^2[/tex]
Josh:
[tex] \frac{0.6 * 0.7}{90} v^2 = 0.00467v^2[/tex]

The negative impact on Amy is larger than on Josh.
Final answer:

Amy experiences less air resistance due to her smaller cross-sectional area compared to Josh, but as she has a lower mass, the air resistance has a more significant effect on her, making her more affected by air resistance.

Explanation:

To determine which cyclist, Amy or Josh, is more affected by air resistance, we can examine the force due to air resistance, which can be calculated using the formula:

Fd = (1/2)ρCdAv2

where Fd is the force of drag (air resistance), ρ is the air density (which we'll assume to be constant for both cyclists), Cd is the drag coefficient, A is the cross-sectional area, and v is the velocity.

Given that both cyclists have the same drag coefficient (Cd = 0.70) and are traveling at the same velocity (v = 15 m/s), the only variables that differ between the two are their cross-sectional areas. Since Amy has a smaller mass and a smaller cross-sectional area (A = 0.45 m2), the force of air resistance will be smaller in magnitude compared to Josh's due to his larger cross-sectional area (A = 0.60 m2).

However, air resistance's impact on an object is also related to the object's mass. A smaller force applied to a smaller mass can have a more significant effect than the same force applied to a larger mass. Therefore, even if the force of air resistance is absolutely higher for Josh, Amy, with her lower mass, would be more affected by it, as it would constitute a more substantial proportion of her total mass.

The earth's radius is about 4000 miles. kampala, the capital of uganda, and singapore are both nearly on the equator. the distance between them is 5000 miles as measured along the earth's surface. part a the flight from kampala to singapore takes 8.3 hours. what is the plane's angular velocity relative to the earth's surface? give your answer in â/h.

Answers

Plane's angular velocity relative to the earth's surface = 0.15 rad/hr

Explanation:

Radius of earth, r = 4000 miles

Angular velocity is the ratio of linear velocity and radius.

         [tex]\omega =\frac{v}{r}[/tex]

Linear distance from Kampala to Singapore = 5000 miles

Time taken = 8.3 hours

         Distance = Time x Velocity

         5000 = 8.3 x Velocity

         Velocity, v = 602.41 mph

Substituting in angular velocity equation

        [tex]\omega =\frac{v}{r}=\frac{602.41}{4000}=0.15rad/hr[/tex]

Plane's angular velocity relative to the earth's surface = 0.15 rad/hr

Final answer:

The plane's angular velocity in hours can be calculated using the angle in radians covered in one hour's flight and the Earth's radius, applying the formula for angular velocity.

Explanation:

To find the plane's angular velocity relative to the Earth's surface, we need to calculate how many radians the plane covers in an hour and then convert this to angular velocity in degrees per hour. The formula for angular velocity (ω) is ω = θ / t, where θ is the angle in radians and t is the time in seconds. Given that the Earth's circumference is approximately 24,900 miles, we can determine the angle by using the proportion θ / (2π) = distance / Earth's circumference. With the plane's distance being 5000 miles and the Earth's radius being 4000 miles, we use the arc length formula s = rθ, where s is the arc length (5000 miles), r is the radius of the Earth (4000 miles), and θ is the angle in radians. Solving this for θ gives us θ = s / r.

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Why aren’t organisms on the sea floor crushed by water pressure

Answers

Their internal pressure is balanced out with the external pressure of the water.
For exactly the same reason that you don't get crushed by air pressure.
Your body is built with exactly enough pressure inside, pushing out.

a 50kg box is being pushed along a horizontal surface. the coefficient of kinetic friction between the box and the ground is 0.35.what horizontal force must be exerted on the box for it to accelerate at 1.20m/s^2

Answers

For Newton's second law, the resultant of the forces acting on the box is equal to the product between the mass of the box m and its acceleration a:
[tex]\sum F = ma[/tex] 
We are interested only in what happens on the x-axis (horizontal direction). Only two forces act on the box in this direction: the force F, pushing the box along the surface, and the frictional force [tex]F_f = \mu m g[/tex] which has opposite direction of F (because it points against the direction of the motion). Therefore we can rewrite the previous equation as
[tex]F-F_f = ma[/tex]
and solve to find F:
[tex]F=ma+F_f =m(a+\mu g)=(50 kg)(1.2 m/s^2+(0.35)(9.81 m/s^2))=[/tex]
[tex]=232 N[/tex]

Answer:

Net horizontal force, [tex]F_{net}=231.5\ N[/tex]

Explanation:

It is given that,

Mass of the box, m = 50 kg

The coefficient of kinetic friction between the box and the ground is 0.35, [tex]\mu=0.35[/tex]

Acceleration of the box, [tex]a=1.2\ m/s^2[/tex]

We know that the frictional force acts in opposite direction to the direction of motion. The net force acting on it is given by :

[tex]F_{net}=f+ma[/tex]

[tex]F_{net}=\mu mg+ma[/tex]

[tex]F_{net}=m(\mu g+a)[/tex]

[tex]F_{net}=50\times (0.35\times 9.8+1.2)[/tex]

[tex]F_{net}=231.5\ N[/tex]

So, the net force acting on the box is 231.5 N. hence, this is the required solution.

A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.

What is the value of F?
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm

Answers

In order to solve the problem, we must require the equilibrium of all the torques acting on the rod. The fixed point is in X, so we have:
- The weight of the rod (mg) acting at the center of the rod (so, at a distance L/2 from X, where L is the length of the rod). So, the torque is 
[tex]T_W = mg \frac{L}{2} [/tex]
- The vertical component of F (so, [tex]F \sin 30^{\circ}[/tex]) applied in Y, so at a distance L from X. Its torque is
[tex]F \sin 30^{\circ} L[/tex]

The weight points downwards (so, the torque is clockwise), while the torque of F points anti-clockwise, so the equilibrium of torques is
[tex]F \sin 30^{\circ} L = mg \frac{L}{2} [/tex]
and since the weight is mg=10 N, re-arranging the equation we find
[tex]F = \frac{10 N}{2 sin 30^{\circ}} = 10 N[/tex]

The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:

Given data:

The weight of rod is, W = 10.0 N.

The angle made by force with respect to horizontal is, [tex]\theta = 30^\circ[/tex].

To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.

Therefore,

[tex](Fsin\theta) \times L = W \times \dfrac{L}{2} \\\\(F \times sin30^{\circ}) = \dfrac{10}{2} \\F = 10 \;\rm N[/tex]

Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.

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Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.

Answers

Let's call [tex]C_{eq}[/tex] the equivalent capacitance of the circuit. The relationship between the  capacitance, the charge Q in the circuit and the potential difference V applied on the capacitor is
[tex]C_{eq}= \frac{Q}{V} [/tex]
Using [tex]Q=3.5 \cdot 10^{-4}C[/tex] and [tex]V=5.55 V[/tex], we find
[tex]C_{eq}= \frac{3.5 \cdot 10^{-4}C}{5.5 V} =6.4 \cdot 10^{-5}F[/tex]

In reality, the circuit consists of 3 capacitors in parallel, each one having same capacitance C. When 3 capacitors are connected in parallel, their equivalent capacitance is:
[tex]C_{eq}=C+C+C=3C[/tex]
We know [tex]C_{eq}[/tex], so we can find C:
[tex]C= \frac{C_{eq}}{3}= \frac{6.4 \cdot 10^{-5}F}{3} =2.1 \cdot 10^{-5}F [/tex]

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

The capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

What is equivalent capacitance of parallel series?

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

It can be given as,

[tex]C_{eq}=\dfrac{Q}{V}[/tex]

Here, [tex]Q[/tex] is the charge and [tex]V[/tex] is the voltage.

Given information-

The voltage of the battery is 5.55 V.

The value of charge is [tex]3.45\times10^{-4}[/tex] C.

Put the values in the above formula as,

[tex]C_{eq}=\dfrac{3.45\times10^{-4}}{5.55}\\C_{eq}=6.4\times10^{-4}\rm F[/tex]

Given that the three uncharged capacitors with equal capacitance are combined in parallel.

For the parallel connection of the capacitance the equivalent capacitance can be given as,

[tex]C_{eq}=C+C+C[/tex]

Here, [tex]C[/tex] is the capacitance of each capacitors. Put the values,

[tex]6.4\times10^{-4}\rm =3C\\C=2.1\times10^{-5}\rm F[/tex]

Hence the capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

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The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. What is the equilibrium concentration of Cl2 in a 1.00 liter vessel containing 0.235 mole of PCl5 and 0.174 mole of PCl3? Remember to use the correct number of significant digits. Cl2 = Are the products or reactants favored?

Answers

To find the equilibrium concentration of Cl2 in the decomposition of PCl5, we start with initial concentrations, assume x is the change at equilibrium, and apply the equilibrium expression using Keq = 2.24 x 10^-2. Solving this for x yields the equilibrium concentration of Cl2, showing whether reactants or products are favored.

To determine the equilibrium concentration of Cl2 when PCl5 decomposes into Cl2 and PCl3, we can start with the provided concentrations and use the equilibrium constant (Keq).

The equilibrium equation for this decomposition is:
PCl5(g) \<=> Cl2(g) + PCl3(g)
and the given Keq is 2.24 x 10-2 at 327°C.

Let's assume x is the amount of PCl5 that decomposes to form x moles of Cl2 and x moles of PCl3 at equilibrium:

Initial moles of PCl5 = 0.235 molInitial moles of PCl3 = 0.174 molChange for PCl5 = -xChange for Cl2 = +xChange for PCl3 = +x

At equilibrium, we will have:

[PCl5] = (0.235 - x) mol / 1.00 L[Cl2] = x mol / 1.00 L[PCl3] = (0.174 + x) mol / 1.00 L

The Keq expression is:

Keq = [PCl3][Cl2] / [PCl5]

Plugging in the equilibrium concentrations:

2.24 x 10-2 = ((0.174 + x) × x) / (0.235 - x)

This equation can be solved for x to find the equilibrium concentration of Cl2. With the calculated value of x, it is possible to determine the favorability of the reaction. A small Keq value (< 1) typically indicates that reactants are favored, which suggests in this case, PCl5 would be favored at equilibrium.

A book rests on a table, exerting a downward force on the table. the reaction to this force is:

Answers

The upward force the table exerts on the ground!
Equal and opposite forces.

rapid energy transfer between ____ and ____ energy make roller coasters thrilling

Answers

Hello there!

The answer is the following:

Rapid energy transfer between Potential and Kinetic energy makes roller coasters thrilling. 

Potential Energy is the energy related to the vertical position of the roller coaster cart. When it is at the highest point, the Potential Energy is at a maximum. 

Kinetic Energy is the energy related to the speed of the roller coaster cart. When the cart is at the highest point, the kinetic energy is at a minimum, but as it begins to go down, the Potential Energy is transformed into Kinetic Energy, making the cart to increase its speed and making it a thrilling experience. 

Which of the following is the main evidence of life in the early universe?
A.) Dinosaur fossils
B.) Rock layering
C.) Plant remains
D.) Cyanobacteria

Answers

A) Dinosaur fossils because they were proven that there was life before us. we also found out that our old skulls had dinosaur teeth in the heads. that showed us that we were on the food chain. but now we aren't because we now have protected cities.

Answer:

Cyanobacteria.

Explanation:

The oldest forms of life would be considered the cyanobacteria from the options, this bacteria are called extremists because they can survive in environments with littlo to zero oxygen andis thought that they have been present from the early begining of the universe because they are the only living organisms known to mankind that are able to survive under those conditions.

This back-and-forth movement of electrons is called . In contrast, the movement of electrons in one direction in a battery circuit is called .

Answers

the back-and-forth movement of electrons is called alternating current. Electrons go back and forth, the direction of their path alternates from one direction to another.

the movement of electrons in one direction is called direct current. The electrons move in a direct, single path without changing directions.

Final answer:

The back-and-forth movement of electrons is called alternating current (AC), and the unidirectional flow in a battery circuit is known as direct current (DC). DC moves from the negative to the positive terminal of a battery, driven by the terminal voltage. The concept of conventional current assumes the flow of positive charges from positive to negative terminal.

Explanation:

The back-and-forth movement of electrons is called alternating current (AC). In contrast, the movement of electrons in one direction in a battery circuit is called direct current (DC).

When electrons move from a low-potential terminal (negative end) through a conductor, such as a wire, and enter a high-potential terminal (positive end) of a battery, this consistent unidirectional flow forms a DC. This is differ from AC, where the movement of electric charge periodically reverses direction. Electricity produced by batteries is a form of DC, and this is why it has definite positive and negative terminals.

The terminal voltage or electromotive force (emf) of a battery drives the flow of electrons, producing electric current. In metal wires, conventional current is carried by the flow of electrons which are negatively charged. However, conventional current is treated as if positive charges move from the positive to the negative terminal, reflecting historical conventions established before the discovery of the electron.

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