Answer:
a
Explanation:
While scuba diving with some friends, Deshawn notices that the air bubbles exhaled by his friends increase in size as they get closer to the surface of the water.
Why does this occur and which gas law explains it?
Answer:As the air bubbles rise to the surface, the pressure on them decreases. This decrease in pressure allows the air to expand and each bubble increases in size. Boyle’s law explains why this occurs.
Explanation:
What can iron filings sprinkled on a piece of paper demonstrate?
A the clockwise motion of the magnetic field
B the counter clock wise motion of the magnetic fields
c the pattern of the magnetic fields lines
d the distortion of the magnetic field by paper,
The iron filings sprinkled on a piece of paper demonstrate is "the pattern of the magnetic fields lines".
What is magnetic fields?A magnetic field would be a vector field which thus explains the magnetic influence affecting electric charges, electric currents, as well as magnetic materials.
What is iron?The chemical element iron has the atomic number 26 and also the symbol Fe. It is just a metal that would be found in group 8 of such periodic table and the very first transition series.
Therefore, the iron filings sprinkled on a piece of paper demonstrate is "the pattern of the magnetic fields lines".
To know more about magnetic fields and iron
https://brainly.com/question/14848188
#SPJ2
What is the specific heat of the solid phase?
If you could just explain to me how I get it, it'd be great
Which actions most likely cause the domains in a ferromagnetic material to align?
Check all that apply.
- heating the material
- rubbing the material against a magnet
- passing electricity around the material
- placing the material in a magnetic field of opposite polarity
- placing the material near a strong magnet
- hitting the material
Answer:
A ferromagnetic material is a temporary magnet. The domains in a ferromagnetic material are randomly arranged. Under certain actions, the domains align in a particular direction and the material acts as a magnet. The actions that can cause alignment of domains in a ferromagnetic material are:
rubbing the material against a magnet would cause the alignment of domains in the same direction as of the magnet. passing electricity around the material would generate magnetic field which would cause domains to align along the direction of the field. placing the material near a strong magnet would cause the alignment of domains in the direction of the field generated by the strong magnet.Other actions like heating the material, placing the material in a magnetic field of opposite polarity and hitting the material would lead to demagnetization of the magnetic material.
Answer:
2,3, and 5
Explanation:
Edg 2022
Physics Review Questions. Please help quickly!!
Will give medal to best answer!
A pitcher exerts 100.0 N of force on a ball with a velocity of 45 m/s. What is the pitcher's power?
A 50.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45 degrees with the mast. How much work did he do?
An inclined plane is 5.00 m long and 2.00 m high. What is the ideal mechanical advantage of this machine?
A sailboat moves north for a distance of 10.00 km when blown by a wind 30 degrees east of south with a force of 5.00 x 10^4 N. How much work was done by the wind?
Lucas plugs a lamp into the wall. The light bulb in the lamp turns on. What kind of energy transformation is this
Answer:
Electric energy from the outlet transforms to radiant energy and thermal energy in the lightbulb.
Explanation:
Motion of a light source, like stars in distant galaxies, causes the spectral lines to shift positions as well. An object's motion causes a wavelength shift Δλ = λnew - λres. The amount of shift in the spectral lines can tell astronomers how galaxies are moving relative to our position on Earth. The wavelength shift depends on
the speed and direction the object is moving.
The Answer is A)
ON USAtestprep
MEDAL AND FAN FOR FIRST ANSWER!!!!
Which of the following materials is a conductor of electric current?
A.a plastic game piece
B.a wooden spoon
C.a copper penny (I think its this one)
D.a glass window
A car is traveling at 52.0 mi/h on a horizontal highway. (a) if the coefficient of static friction between road and tires on a rainy day is 0.102, what is the minimum distance in which the car will stop? m (b) what is the stopping distance when the surface is dry and µs = 0.603? m
Final answer:
To find the minimum stopping distance, we use the formula d = v² / (2 · μ_s · g), considering the speed and the coefficient of static friction. For wet conditions (μ_s = 0.102), the stop distance is 27.8 meters, and for dry conditions (μ_s = 0.603), it is 4.6 meters.
Explanation:
To calculate the minimum stopping distance of a car traveling at 52.0 mi/h (which converts to approximately 23.2 m/s) on a horizontal highway, we can use the formula for stopping distance based on the coefficient of static friction ( μ_s ) and the deceleration rate:
d = v² / (2 · μ_s · g), where v is the initial speed in m/s, μ_s is the coefficient of static friction, and g is the acceleration due to gravity (9.8 m/s²).
(a) On wet concrete, where μ_s = 0.102, the minimum stopping distance is:
d = (23.2²) / (2 · 0.102 · 9.8) = 27.8 meters
(b) On dry concrete, where μ_s = 0.603, the minimum stopping distance is:
d = (23.2²) / (2 · 0.603 · 9.8) = 4.6 meters
These calculations provide an understanding of the significance of road conditions on stopping distances, emphasizing the increased risk associated with wet roads.
A mass m1 = 3.5 kg rests on a frictionless table and connected by a massless string over a massless pulley to another mass m2 = 4.8 kg which hangs freely from the string. When released, the hanging mass falls a distance d = 0.71 m.
1) How much work is done by gravity on the two block system?
34 J (All of my answers are correct up to the last question, which I need help on)
2) 2) How much work is done by the normal force on m1?
0 J
3) What is the final speed of the two blocks?
2.84 m/s
4) How much work is done by tension on m1?
14.1 J
5) What is the tension in the string as the block falls?
19.9 N
7) What is the NET work done on m2?
**** This is the question I need help on. I gave the answers to the previous questions because something in there might be needed for solving this part of the problem.
In this exercise we have to use the block knowledge in a system, thus we find that:
1) 33.4 J
2) 0J
3) 2.84 m/s
4) 14.1 J
5) 19.9 N
6) 19.3 J
So with the knowledge of force and energy we can calculate what is required, like this:
1) We have to calculate the value of work in the system which will be:
[tex]W=FS\\W=0.71 m * 9.8 m/s^2 * 4.8kg\\ = 33.3984 kg*m^2/s^2 \\= 33.3984 J \\=33.4 J[/tex]
2) As we are dealing with the work of the normal force, we will have to be zero, since the force will not have a distance, so:
[tex]W=FS\\W=35*0\\W=0J[/tex]
3) We want to calculate the final speed of the system as a whole, so:
[tex]E = 0.5MV^2 \\E = 33.3984 J\\ 33.3984 = 0.5*(3.5 + 4.8 )V^2\\ 33.3984 = 0.5*8.3 *V^2\\ 33.3984 = 4.15*V^2\\ 8.047807229 = V^2\\V= 2.83686574 m/s\\V=2.84 m/s[/tex]
4) We want to find the work of the voltage in this way we have:
[tex]E = 0.5MV^2\\ E = 0.5*3.5kg* (2.84 m/s)^2\\ E = 0.5*3.5kg* 8.0656 m^2/s^2\\ E = 14.1148 kg*m^2/s^2\\ E = 14.1 J[/tex]
5) Now calculating the value of the string tension, we have:
[tex]T= 14.1 J / 0.71 m \\= 19.88 J/m\\= 19.88 kg*m/s^2\\ = 19.88 N[/tex]
6) Calculating the value of work on top of block 2 we have:
[tex]E = 0.5MV^2\\ E = 0.5*4.8 kg * (2.84 m/s)^2\\ E = 0.5*4.8 kg * 8.0656 m^2/s^2\\ E = 19.35744 kg*m^2/s^2\\ E = 19.4 J[/tex]
See more about work at brainly.com/question/756198
A 5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
What is the distance of the image from the lens? Round your answer to three significant figures.
cm
What is the height of the image? Round your answer to three significant figures.
cm
The image distance from the lens is 22.5 cm, and the height of the image is -6.25 cm indicating it is inverted.
To determine the distance of the image from the lens and the height of the image, we use the lens formula and magnification formula.
Lens formula:
[tex]1/f = 1/d_o + 1/d_i[/tex]
Given:
Object distance ([tex]d_o[/tex]) = 18.0 cmFocal length (f) = 10.0 cmSubstitute the values:
[tex]1/10 = 1/18 + 1/d_i[/tex]
[tex]1/d_i = 1/10 - 1/18 = 0.1 - 0.0556 = 0.0444[/tex]
[tex]d_i = 22.5 cm[/tex]
So, the image distance from the lens is 22.5 cm.
Next, we calculate the height of the image using the magnification formula:
Magnification (m) = [tex]-d_i/d_o = h_i/h_o[/tex]
Given:
Object height ([tex]h_o[/tex]) = 5 cmImage distance ([tex]d_i[/tex]) = 22.5 cm[tex]h_i = h_o * (-d_i/d_o)[/tex]
Substitute the values:
[tex]h_i[/tex] = 5 * (-22.5/18)
[tex]h_i[/tex] = -6.25 cm
Therefore, the height of the image is -6.25 cm which indicates the image is inverted.
What is the transfer of heat through a solid as a result of molecular action called? radiation convection conduction magnetism?
The radius of each wheel on a bicycle is 0.400 m. the bicycle travels a distance of 3.0 km. assuming that the wheels do not slip, how many revolutions does each wheel make?
Final answer:
To find the number of revolutions a bicycle wheel makes over 3.0 km, we calculate the wheel's circumference, convert total distance to meters, and then divide the distance by the circumference. The result is approximately 1194 revolutions.
Explanation:
The student is asking about the number of revolutions each wheel of a bicycle makes when it travels a certain distance. Given that the radius of each wheel is 0.400 meters and the bicycle travels a distance of 3.0 kilometers, we can use the relationship between the circumference of the wheel and the total distance traveled to calculate the number of revolutions.
To find the number of revolutions, we first calculate the circumference of the wheel using the formula C = 2πr, where r is the radius of the wheel. Then, we convert the total distance traveled from kilometers to meters. Finally, we divide the total distance traveled by the circumference of the wheel to get the number of revolutions.
Step-by-step calculation:
Calculate the circumference of the wheel: C = 2π(0.400 m) = 2.513 m
Convert the distance traveled to meters: 3.0 km = 3000 m
Calculate the number of revolutions: (3000 m) / (2.513 m/revolution) ≈ 1194 revolutions
Each wheel makes approximately 1194 revolutions as the bicycle travels 3.0 kilometers.
A sample of Bismuth-212 has a mass of 2.64 grams (g) after 121 seconds (s). What was the initial mass of the sample if Bismuth-212 has a half-life of 60.5 s?
The initial mass of the Bismuth-212 sample is 10.56 grams.
Explanation:To find the initial mass of the Bismuth-212 sample, we can use the concept of half-life. The half-life of Bismuth-212 is given as 60.5 seconds. Since the sample has a mass of 2.64 grams after 121 seconds, we can calculate the number of half-lives that have passed.
The number of half-lives is given by the formula: Number of Half-lives = Total Time / Half-life
So, the number of half-lives = 121 s / 60.5 s = 2 half-lives.
Since each half-life results in half the initial mass remaining, after 2 half-lives, the remaining mass would be (1/2)(1/2) = 1/4 of the initial mass.
If we let the initial mass be x grams, then after 2 half-lives, the remaining mass is (1/4)x grams.
Given that the remaining mass is 2.64 grams, we can solve for the initial mass:
(1/4)x = 2.64 grams
Simplifying, x = 2.64 grams * 4 = 10.56 grams.
Therefore, the initial mass of the sample of Bismuth-212 is 10.56 grams.
Learn more about Calculating initial mass using half-life here:https://brainly.com/question/29970608
#SPJ11
Find the conductivity of a conduit with a cross-sectional area of 0.40 cm2 and a length of 20.0 cm if its conductance G is 0.080 units.
Answer:
4.0
Explanation:
Adults should also do muscle-strengthening activities that involve all major muscle groups, performed on _____ or more days per week.
A 7
B 2
C 5
D 4
Final answer:
Adults should perform muscle-strengthening activities that work all major muscle groups at moderate to high intensity at least 2 days per week for additional health benefits.
Explanation:
Adults should engage in muscle-strengthening activities that involve all major muscle groups, performed on 2 or more days per week. These activities, such as push-ups, sit-ups, squats, and lifting weights, should be done at moderate or greater intensity to provide additional health benefits. Over time, the frequency and intensity of these workouts can be increased to further enhance muscle strength and endurance.
Which of the following is most appropriate to follow motion in one dimension?
linear scale
x- y- z coordinates
solid coordinates
graph with x- and y-axes.,
There is a 120 V circuit in a house that is a dedicated line for the dishwasher, meaning the dishwasher is the only resistor on that circuit line. If the dishwasher draws 18 A of electricity, what would the resistance of the dishwasher be? Round the answer to the nearest hundredth of an ohm.
Answer : Resistance of the dishwasher is 6.67 ohms.
Explanation :
It is given that,
Total voltage flowing in a house, V = 120 V
Current flowing, I = 18 A
According to Ohm's law :
V = I R ...........(1)
R is the resistance of the circuit.
Putting all values in (1) we get :
[tex]R=\dfrac{V}{I}[/tex]
[tex]R=\dfrac{120\ V}{18\ A}[/tex]
[tex]R=6.666\ \Omega[/tex]
or
[tex]R=6.67\ \Omega[/tex]
So, the resistance of the dishwasher is [tex]R=6.67\ \Omega[/tex].
How many workers are injured in scaffold falls each year
Acceleration involves a change in speed or...
Answer:
Direction
Explanation:
If an endothermic reaction is in Equilibrium, What will happen when you increase the temp? (1 point)
a. More reactants form
b. more products form
c. no change in the amounts of products and reactants occur
d. the system does not reach equilibrium again
During each heartbeat, about 80 g of blood is pumped into the aorta in approximately 0.2 s. during this time, the blood is accelerated from rest to about 1 m/s. what is the average force on the blood during this time?
The average force acting on the blood as it is pumped into the aorta is [tex]\boxed{0.4\text{ N}}[/tex].
Explanation:
As the blood enters the aorta, the speed of the blood increases from zero to [tex]1\text{ m/s}[/tex] in a time of [tex]0.2\text{ s}[/tex]. It means that the blood moves under the acceleration as it passes through the aorta.
The acceleration produced in a body is due to the force experienced by the particular amount of blood as it enters the aorta.
Write the expression for the acceleration of the blood as its speed increases.
[tex]\boxed{a=\dfrac{v_{f}-v_{i}}{t}}[/tex] ...... (1)
Here, [tex]v_{f}[/tex] is the final velocity of blood, [tex]v_{i}[/tex] is the initial velocity and [tex]t[/tex] is the time taken to accelerate.
Substitute the values of the velocities and the time taken by the blood in equation (1).
[tex]a&=\dfrac{1-0}{0.2}\text{ m}\text{/s}^2}\\&=\dfrac{1}{0.2}\text{ m}\text{/s}^2}\\&=5\text{ m}\text{/s}^2}[/tex]
The net force acting on the blood is given by:
[tex]F=m\times{a}[/tex] ...... (2)
Substitute the values of mass and acceleration in the above expression.
[tex]\begin{aligned}F&=80\text{ g}\left(\dfrac{1 \text{ kg}}{1000\text{ g}}\right)\times\left(5\text{ m/s}^2\right)\\&=0.08\times5\text{ N}\\&=0.4\text{ N}\end{aligned}[/tex]
Therefore, the average force acting on the blood as it is pumped into the aorta is [tex]\boxed{0.4\text{ N}}[/tex].
Learn More:
1. what type of mirror do dentist use https://brainly.com/question/997618
2. forces of attraction limit the motion of particles most in https://brainly.com/question/947434
3. how long to walk 2000 miles https://brainly.com/question/3785992
Answer Details:
Grade: High School
Subject: Physics
Chapter: Force and acceleration
Keywords:
heartbeat, average force, aorta, blood, rest, speed up, acceleration, initial speed, final speed, time, accelerated, 80 g, blood is pumped.
Final answer:
The average force on the blood during this time is 0.4 Newtons.
Explanation:
The average force on the blood can be calculated using the equation:
F = m * a
where F is the force, m is the mass, and a is the acceleration.
In this case, the mass of the blood is given as 80 g (or 0.08 kg) and the acceleration is the change in velocity divided by the time taken.
Given that the blood is accelerated from rest to 1 m/s in 0.2 s, the acceleration is calculated as:
a = (v-u)/t
Substituting the given values:
a = (1-0)/0.2 = 5 m/s²
Plugging the values back in the original equation:
F = 0.08 kg * 5 m/s² = 0.4 N
So, the average force on the blood during this time is 0.4 Newtons.
A 35-cm-tall, 5.0-cm-diameter cylindrical beaker is filled to its brim with water. what is the downward force of the water on the bottom of the beaker?
The downward force of the water on the beaker's bottom is its weight, calculated using the beaker's volume, the density of water, and acceleration due to gravity.
Explanation:The question is asking about the downward force exerted by water on the bottom of a cylindrical beaker. This situation relates to principles in physics around fluid dynamics and specifically Pascal's principle. According to Pascal's principle and the equation for fluid pressure, the downward force exerted by the water (F) is its weight, which can be calculated as the product of the volume of the water, the density of the water, and the acceleration due to gravity (g).
Since the beaker is filled to the brim, the volume (V) of the water is equal to the volume of the cylinder, which can be calculated by the formula V = π(r^2)h, where r is the radius and h is the height of the beaker. The radius can be obtained from the given diameter. If we have the density (ρ) of water and the value for g, we can substitute these in the mentioned equation to get the force F = ρVg.
Finally, using the calculated volume, the known density of water (approximately 1000 kg/m³ for standard conditions), and the standard gravity (approximately 9.8 m/s²), we can find F, which is the downward force from the water on the beaker's bottom.
Learn more about Fluid Dynamics here:https://brainly.com/question/30578986
#SPJ12
Angular velocity and linear velocity have the same dimensions. This statement is:
a. true
b. false
c. sometimes true sometimes false. it varies
Part 1: The following questions refer to the motion of a baseball. Call towards home plate positive and towards the outfield negative. While being thrown, a net force of 125 N acts on a baseball (mass = 141 g) for a period of 0.04 sec. What is the magnitude of the change in momentum of the ball?
Part 2: If the initial speed of the baseball is v = 0.0 m/s, what will its speed be when it leaves the pitcher's hand?
Part 3: When the batter hits the ball, a net force of 1165 N, opposite to the direction of the ball's initial motion, acts on the ball for 0.005 s during the hit. What is the final velocity of the ball?
How do particles move differently in transverse waves and in surface water waves?
In transverse waves, particles move perpendicularly to the wave's direction, while in surface water waves, they follow circular orbits due to a combination of longitudinal and transverse motions. The size of these orbits decreases with depth, and a slight horizontal movement called Stokes drift occurs after each wave crest passes.
Particle Movement in Different Waves
In transverse waves, particles move in a direction perpendicular to the propagation of the wave. Examples of transverse waves include vibrations in a stretched string or ripples on the surface of water when viewed from the side. However, the surface water waves present a more complex motion. Particles in these waves move in circular orbits, which is a combination of longitudinal (back and forth) and transverse (up and down) motions.
Water waves are created when wind transfers energy to the water surface, leading to the oscillatory motion of water particles. The size of these circular orbits decreases as the depth increases. In deep water, particles move in closed circular paths, whereas in shallow water, their motion is elliptical due to the compression of the wave's energy.
Moreover, water waves display a phenomenon called Stokes drift, where particles are slightly displaced horizontally after the passage of each wave crest. This accounts for the small forward movement observed alongside the predominant up and down movement of the particles in the wave.
Imagine a book Is resting on table. This book weighs 45N. Are the forces in balance? Why or why not?
Awanita is placing items on a shelf that is 200 cm above the ground. She exerts a force of 20 N to lift a box from the floor to the shelf. She does this in 5 s. What is Awanita’s power output? (Power: P = W/t)
Answer:
Awanita's power output is 8watts
Explanation:
First we find workdone= Force × distance
Given: F=20N , d= 200cm converting to meter: (200/100)m=2m
W= 20×2=40Joules
Power,P= workdone/ time
Given: time=5seconds
P= 40/5= 8 watts
The frequency of the middle d note on a piano is 293.66 hz. what is the wavelength of this note in centimeters? the speed of sound in air is 343.06 m/s.
The wavelength of the middle D note, with a frequency of 293.66 Hz and a speed of sound of 343.06 m/s, is approximately 116.8 cm. The calculation involves dividing the speed of sound by the frequency and converting the result from meters to centimeters.
To find the wavelength of the middle D note on a piano with a frequency of 293.66 Hz in air, where the speed of sound is 343.06 m/s, we can use the formula:
Wavelength (λ) = Speed of Sound (v) / Frequency (f)
First, let's perform the calculation:
Identify the given values:
Frequency (f) = 293.66 Hz
Speed of Sound (v) = 343.06 m/s
Calculate the wavelength:
[tex]\lambda = \frac{v}{f} = \frac{343.06 \, \text{m/s}}{293.66 \, \text{Hz}}[/tex]
≈ 1.168 m
Convert the wavelength from meters to centimeters:
1 meter = 100 centimeters
1.168 meters = 1.168 * 100 = 116.8 centimeters
Therefore, the wavelength of the middle D note is approximately 116.8 cm.
Two straight roads diverge at an angle of 45°. two cars leave the intersection at 2:00 p.m., one traveling at 36 mi/h and the other at 52 mi/h. how far apart are the cars at 2:30 p.m.?