Which structures are common to both prokaryotic and eukaryotic cells? Check all that apply.
vacuole
cell membrane
Golgi body
ribosome
cytoplasm
endoplasmic reticulum

Answer:

A.

Once it rains the pesticide goes down the runoff and pollute the water

Answer:

change temperature at different rates

The specific heat is used to explain why different substances change the temperature at different rates.

Specific Heat:

It is the amount of heat that is required to increase the temperature of 1 kg of a substance by 1^oc. It is measured in the [tex]\bold {J/g/^oC }[/tex].

Therefore, the specific heat is used to explain why different substances change the temperature at different rates.

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Answer:

A)  acetic acid ten times greater than acetate pH = 3.74

B)  acetate ten times greater than acetic acid pH = 5.74

C) For solution 3: acetate=acetic acid pH = 4.74

Mass NH4Cl = 40.30 grams

Explanation:

Step 1: Data given

Ka is: 1.8 * 10^-5

Solution 1: acetic acid ten times greater than acetate

Solution 2: acetate ten times greater than acetic acid

Solution 3: acetate=acetic acid

Step 2: The pH formula

pH = pKa + log[CH3COO-]/[CH3COOH]

For solution 1:  acetic acid ten times greater than acetate this means ) [[CH3COO-]/[CH3COOH]) has a value of 1/10

pH = pKa + log[CH3COO-]/[CH3COOH]

pH = -log(1.8*10^-5) + log(1/10)

pH = 4.74 -1

pH = 3.74

For solution 2: acetate ten times greater than acetic acid

pH = pKa + log[CH3COO-]/[CH3COOH]

pH = -log(1.8*10^-5) + log(10)

pH = 4.74 + 1

pH = 5.74

For solution 3: acetate=acetic acid

pH = pKa + log[CH3COO-]/[CH3COOH]

pH = -log(1.8*10^-5) + log(1)

pH = 4.74 + 0

pH = 4.74

Part B: Calculate molarity

pOH = pKb + log [H

5.29= -log (1.8*10^-5)  + log [BH+]/[0.600 M]

5.29 = 4.744 + log [BH+]/[0.600 M]

0.546 = [BH+]/0.600

[BH+] = 0.3276 M

Moles NH4+ = 0.3276  M * 2.30 L

Moles NH4+ = 0.75348 moles

Moles NH4Cl = 0.75348 moles

Mass NH4Cl = 0.75348 moles * 53.49 g/mol

Mass NH4Cl = 40.30 grams

Answer: [tex]2CH_4+4H_2O\rightarrow 2CO_2+4H_2O[/tex] is not a combination reaction.

Explanation:

Synthesis reaction or combination reaction is defined as the reaction where two or more substances combine to form a single product.

[tex]2N_2+3H_2\rightarrow 2NH_3[/tex]

[tex]2Mg+O_2\rightarrow 2MgO[/tex]

[tex]CaO+H_2O\rightarrow Ca(OH)_2[/tex]

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

[tex]2CH_4+4H_2O\rightarrow 2CO_2+4H_2O[/tex]

Among the provided reactions, the reaction 2CH4 + 4O2 → 2CO2 + 4H2O is not a combination reaction, but rather a combustion reaction.

In the given reactions, the reaction 2CH4 + 4O2 → 2CO2 + 4H2O is not a combination reaction. In a combination reaction, two or more substances (either elements or compounds) combine to form a single compound. However, the mentioned reaction is actually an example of a combustion reaction where methane (CH4) undergoes combustion in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O).

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Answer:

Two important quantum-mechanical concepts associated with the Bohr model of the atom are (1) that electrons are particles moving in discrete orbitals, and (2) electron energy is quantized into shells. (b) Two important refinements resulting from the wave-mechanical atomic model are (1) that electron position is described in terms of a probability distribution, and (2) electron energy is quantized into both shells and subshells--each electron is characterized by four quantum numbers.

Explanation:

Part A:

The two important quantum-mechanical concepts associated with the Bohr model of the atom are:

(1) Electrons are particles moving in discrete orbitals.

(2) Electron energy is quantized into shells.

Part B:

The two important refinements resulting from the wave-mechanical atomic model are:

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Answer:E is an acidic

Explanation:

Soo he should avoid the drink E and in pH measurement the more acidic is below 7 and the the more alkali is above 7 and the neutral drink is B and it may a water ...

Final answer:

There are 4 dozens in 48 doughnuts, as a dozen is a group of 12 objects. This quantity would require four boxes with a volume of 324 cubic inches each to hold all the doughnuts.

Explanation:

To find out how many dozens of doughnuts are in 48 doughnuts, we can simply divide the total number of doughnuts by the number in a dozen. Since a dozen refers to 12 objects, we divide 48 by 12.

48 ÷ 12 = 4

Therefore, there are 4 dozens in 48 doughnuts. When buying items like doughnuts, it is common to acquire them in groups, like a dozen, because it is more convenient and efficient.

Let's consider the dimensional aspect for a moment. If you have a 9x9x4 inch box for a dozen doughnuts, this box would have a volume of 324 cubic inches. For 48 doughnuts, which we have established are 4 dozens, we would need four of these boxes, equating to 4 × 324 in3 or 1296 in3 in total to hold all of them.

Answer : The amount of heat required is, 2160 cal.

Explanation :

The process involved in this problem are :

[tex](1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(3):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)[/tex]

The expression used will be:

[tex]Q=[m\times \Delta H_{fusion}]+[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{vap}][/tex]

where,

[tex]Q[/tex] = heat required for the reaction = ?

m = mass of ice = 3 g

[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]1cal/g^oC[/tex]

[tex]\Delta H_{fusion}[/tex] = enthalpy change for fusion = [tex]80cal/g[/tex]

[tex]\Delta H_{vap}[/tex] = enthalpy change for vaporization = [tex]540cal/g[/tex]

Now put all the given values in the above expression, we get:

[tex]Q=[3g\times 80cal/g]+[3g\times 1cal/g^oC\times (100-0)^oC]+[3g\times 540cal/g][/tex]

[tex]Q=2160cal[/tex]

Therefore, the amount of heat required is, 2160 cal.

To vaporize a 3 g ice cube initially at 0°C, a total heat of 2160 cal is required. This includes the heat required to melt the ice, heat the melted ice to water's boiling point, and vaporize the water.

The process to vaporize a 3 g ice cube at 0°C consists of three steps. First, the ice cube needs to melt. This requires an amount of heat given by Q = mass x latent heat of fusion. i.e., Q = 3 g x 80 cal/g = 240 cal.`

Then, the water obtained from melted ice at 0°C needs to be heated up to 100°C. The required heat is Q = mass x specific heat x ΔT, i.e., Q = 3 g x 1 cal/g°C x (100°C-0°C) = 300 cal.

Finally, the 100°C water needs to be vaporized. This requires an amount of heat given by Q = mass x latent heat of vaporization. i.e., Q = 3 g x 540 cal/g = 1620 cal.

So, the total heat required to vaporize a 3 g ice cube initially at 0°C is 240 cal + 300 cal + 1620 cal = 2160 cal.

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Final answer:

When the system is at equilibrium with specific initial pressures and the volume of the container is reduced by half, the pressure of each gas changes accordingly.The pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.

Explanation:

When the system is at equilibrium, it contains NO₂at a pressure of 0.817 atm, and N₂O₄ at a pressure of 0.0667 atm. If the volume of the container is reduced to half its original volume, the pressure of each gas will change.

According to the ideal gas law, the pressure of each gas will double when the volume is reduced by half. So, after re-establishing equilibrium, the pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.

Question:

The question is incomplete. What is required to calculate was not added.The equilibrium data was not also added. Below is the additional questions and the answers.

1. Calculate the minimum solvent that can be used.

2.Using a solvent rate of 1.5 times the minimum, calculate the number of

theoretical stages.

Answer:

1. Minimum solvent = 411.047

2. N = 5

Explanation:

See the attached files for explanations.

An aqueous feed solution.

The aqua solution is a solvent on water that has a chemical equation of aq. The example includes the solution of the salt table and NaCl. Having positive and negative ions. The solution feed id of 1000 KG/hand consists of 23.5 wt% acetone and has a 76.5 wt% of water by volume which is being used.

Thus the answer is minimum solvent = 411.047 and the N equals 5.

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Answer: 1 dissociation. 2. Hydration. 3. Dissolving.

Explanation:

Answer:

0.17 mole of glucose is formed.

Explanation:

Step 1:

The equation for the reaction. This is given below:

CO2 + H2O —> C6H12O6 + O2

Step 2:

Balancing the equation.

The equation can be balanced as follow:

CO2 + H2O —> C6H12O6 + O2

There are 6 atoms of C on the right side and 1 atom on the left side. It can be balance by putting 6 in front of CO2 as shown below:

6CO2 + H2O —> C6H12O6 + O2

Therefore are 12 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 6 in front of H2O as shown below:

6CO2 + 6H2O —> C6H12O6 + O2

There are a total of 8 atoms of O the right side and a total of 18 atoms on the left. It can be balance by putting 6 in front of O2 as shown below:

6CO2 + 6H2O —> C6H12O6 + 6O2

Now the equation is balanced.

Step 3:

Determination of the number of mole of glucose (C6H12O6) produced by 1 mole of water.

This is illustrated below:

6CO2 + 6H2O —> C6H12O6 + 6O2

From the balanced equation above,

6 moles of H2O produced 1 mole of C6H12O6.

Therefore, 1 mole of H2O will produce = 1/6 = 0.17 mole of C6H12O6.

Answer:

IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced

Explanation:

Step 1: Data given

Number of moles of water = 1.0 moles

Carbon dioxide is in excess

Step 2: The balanced equation

6CO2 + 6H2O → C6H12O6 + 6O2

Step 3: Calculate moles of glucose

For 6 moles CO2 we need 6 moles H2O to produce 1 mol glucose and 6 moles O2

For 1.0 moles of water we'll have 1.00 / 6 = 0.167 moles of glucose

IF 1.0 mol of water is available, 0.167 moles of glucose (C6H12O6) will be produced

Answer:

The question is incomplete, no worries I got you.

Here is the complete question;

__________ reactions are used to detect antibodies for relatively large pathogens, such as bacteria. For these tests, the antigen is mixed with the test sample at various dilutions. Reaction mixes are then monitored for the formation of visible aggregates.

Explanation:

AGGLUTINATION is the reaction used.

Agglutination is the reaction in which there is the clumping of particles. A agglutination reaction is the visible clumping of the bacterial cells as an antigen reacts with its corresponding antibody. This type is often used as an initial confirmation of specific pathogens. Agglutination tests is is used to detect antibody or antigen and it involves the  agglutination of bacteria, red cells, or antigen- or antibody-coated latex particles. It is therefor used for large pathogens like bacteria. In this reaction, antigens are introduced into various dilutions of antibodies in test tubes or surfaces of glass slides, visible clumping is observed which depends on the size of the antibodies, amount and acidity of the antibody molecule, time of incubation and as well as the environment of the reaction which includes optimum pH, protein concentration among others.  

Answer:

Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V

Explanation:

A close look at all the options shows that the most feasible first reaction is the reduction of tin II ion to ordinary metallic tin.

Given the two half cells, nickel is oxidized in one half cell to Ni II while in the second half cell, tin II ion is reduced to metallic tin. The platinum electrodes simply act as electron conduits in the cell.

Answer:

32.232 L

Explanation:

-Given the volume at 1.58atm is 20.4 L

-At standard pressure, the pressure is 1.00atm

-We apply Charle's Law to find the volume at STP:

[tex]P_1V_1=P_2V_2\\\\\\1.58\ atm\times 20.4\ L=1.00\ atm\times V_2\\\\V_2=\frac{1.58\times 20.4}{1.00}\\\\\\\\=32.232\ L[/tex]

Hence, the volume of the gas at STP is 32.232 L

The answer is Y < X < Z

Final answer:

The order of increasing strength of intermolecular forces for substance X (liquid), Y (gas), and Z (solid) is: Y < X < Z, with the gas having the weakest and the solid having the strongest intermolecular forces.

Explanation:

If we consider substances X, Y, and Z, which are a liquid, a gas, and a solid respectively, and they are all at the same temperature and pressure, the order of increasing strength of their intermolecular forces can be determined based on their states of matter. Given that substances with stronger intermolecular forces are more likely to be a solid at room temperature and will have a higher boiling point, it follows that the solid will have the strongest forces, followed by the liquid, and then the gas. Consequently, substance Z (the solid) would have the strongest intermolecular forces, substance X (the liquid) would have intermediate forces, and substance Y (the gas) would have the weakest forces.

Answer:

Evaporation

Explanation:

Evaporation is when liquid becomes a gas which is how the river dried up

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = [tex]\frac{PV}{RT}[/tex]

putting the values in the equation:

n = [tex]\frac{1X2}{0.08201 X 273}[/tex]

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

Final answer:

To find how many moles are in 2.0 L of N2 at standard temperature and pressure, we use the fact that 1 mole of any gas occupies 22.4 L at STP. By dividing 2.0 L by 22.4 L, we find that there are approximately 0.089 moles of N2.

Explanation:

The question asks, How many moles are contained in 2.0 L of N2 at standard temperature and pressure? To answer this, it's essential to know that at standard temperature and pressure (STP), which is defined as 0°C (273K) and 1 atmosphere (atm) of pressure, 1 mole of any ideal gas occupies 22.4 liters of volume. This is a key concept in understanding gas laws and mol calculations in chemistry.

Given that we have 2.0 liters of N2 gas at STP, we can use the proportionality given by the molar volume at STP to find the number of moles. Since 22.4 liters is equivalent to 1 mole of a gas, we can set up a simple calculation to find the moles of N2 in 2.0 liters:

Moles of N2 = Volume of N2 (L) / Volume of 1 mole of gas at STP (L)

= 2.0 L / 22.4 L

= 0.089 moles of N2

This calculation demonstrates the direct application of molar volume at STP to determine the number of moles in a given volume of gas.

Answer:

the first and last

Explanation:

the enthalpy Change is positive.

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Answer:

One (2H2O → 2H2 + O2, ΔH = 484 kJ )

Four (2NH3 → N2 + 3H2, ΔH = 92 kJ)

Explanation:

An endothermic process is any process with an increase in the enthalpy H of the system. So if it has a positive result then the heat is going up which means it is endothermic .

Answer:

a. All of the below

Explanation:

Column chromatography in chemistry is a chromatography method used to isolate a single chemical compound from a mixture.

TLC can be used to analyze a chemical reaction to determine if the reactants have been consumed and a new product has formed. Running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot, when you view the TLC plate under a UV light, you will notice that acetylferrocene product is on the right-most lane, this shows that the reaction appears to be a success: the higher spot of ferrocene has been consumed), and a new product spot is present. From these we can observe that the we can use this to identify the number of products of the reaction, determine if the starting material is still present in the reaction and the elution in a chromatography column of the starting material and products. Therefore, all the choices are correct.

Answer:

The answer to your question is butanal

Explanation:

To name this compound we must consider:

1.- Identify the functional group. The functional group of this molecule is the first carbon to the right and its oxygen.

When carbon is attached to oxygen is a border, this functional group is called Aldehyde.

2.- Count the total number of carbons starting from the right. This molecule has 4 carbons.

3.- Name the compound

    An organic molecule with 4 carbons is called butane but change the ending for al, then the name will be butanal

Explanation:

Given

mass (m) = 44 kg

velocity (v) = 31 m/s

Now

Kinetic energy

= 1/2 mv²

= 1/2 * 44 * 31²

= 0.5 * 44 * 961

= 21142 joule

Hope it will help you :)

Answer:

B. The amount of oxygen will decreases

Explanation:

According to Le Châtelier’s Principle, when the condition of the system changes the equilibrium will shift to compensate for the changes. When temperature decrease, the pressure will also decrease and this will shift the equilibrium to the side with exothermic reaction or less molecule count.

The question is not giving the equilibrium reaction of oxygen, so I assume its

O2 + Hb = HbO2

Since the number of molecules in the right side is lower, then the number of oxygen will decrease since the reaction will shift to the right.

Answer:

P1V1 = P2V2

(1.5 atm)(5.6 L) = (x)(4.8 L) x = 1.8 atm

If we have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, the new pressure inside the piston will be 175 kPa.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

Here temperature doesn't change, hence-

(P1 × V1) = (P2 × V2)

P1 = 150 kPa

V1 = 5.6 litres

P2 = ?

V2 = 4.8 litres

P2 = 175 kPa

Therefore, If we have 5.6 liters of gas in a piston at a pressure of 150 kPa and compress the gas until its volume is 4.8 L, the new pressure inside the piston will be 175 kPa.

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Answer:

0.0812 grams of nitrate ions are there in the final solution.

Explanation:

Mass of cobalt (II) nitrate = 3.00 g

Moles of cobalt(II) nitrate = [tex]\frac{3.00 g}{183 g/mol}=0.0164 mol[/tex]

Volume of the solution = 100 mL = 0.100 L

1 mL = 0.001 L

[tex]Molarity=\frac{Moles}{Volume(L)}[/tex]

Molarity of the solution = [tex]\frac{0.0164 mol}{0.100 L}=0.164 M[/tex]

Cobalt (II) nitrate in its aqueous solution gives 1 mole of cobalt(II) ion and 2 moles of nitrate ions.

[tex][NO_3^{-}]=2\times [Co(NO_3)_2]=2\times 0.164 M=0.328 M[/tex]

Molarity of the nitrate ion before solution = [tex]M_1=0.328 M[/tex]

Volume of the  nitrate ion  before solution = [tex]V_1=4.00 mL[/tex]

Molarity of the  nitrate ion after solution = [tex]M_2=?[/tex]

Volume of the  nitrate ion after solution = [tex]V_2=275 mL[/tex]

[tex]M_1V_1=M_2V_2[/tex] ( Dilution)

[tex]M_2=\frac{0.328 M\times 4.00 mL}{275 mL}=0.00477 M[/tex]

Moles of nitrate ions in 275 ml = n

Molarity of the  nitrate ion after solution =0.00477 M

volume of the final solution = 275 mL = 0.275 L

[tex]n=0.00477 M\times 0.275 L=0.00131 mol[/tex]

Mass of 0.00131 moles of nitrate ions:

0.00131 mol × 62 g/mol = 0.0812 g

0.0812 grams of nitrate ions are there in the final solution.

Answer:

The amount of ion that carries 1 mole of electrical charge

Explanation:

One equivalent: In reaction stoichiometry, the amount of one substance that reacts with one mole of another substance. This will often (but not always) be a 1:1 mole ratio.

An equivalent is  the amount of ion that carries 1 mole of electrical charge.

An equivalent is the amount of a substance that reacts with one mole of another substance in a given chemical reaction.

It is a unit of measurement in Stoichiometry that helps to describe the amount of ion that carries 1 mole of electrical charge.

Examples include:

Thus, we can conclude that  an equivalent is  the amount of ion that carries 1 mole of electrical charge.

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Answer: The mass of solution the student should use is 256 g

Explanation:

Given : 29.3 % w/w which means that 29.3 g of solute is present in 100 g of solution

Thus 100 g of solution contains = 29.3 g of solute

0.50 kg or 500 g of solution contains = [tex]\frac{29.3}{100}\times 500=146.5[/tex] g of solute   (1kg=1000g)

146.5 g of solute is available in = 500 g of solution

Thus 75 g of solute is available in = [tex]\frac{500}{146.5}\times 75 g=256g[/tex] of solution

Thus the mass of solution the student should use is 256 g

Answer:

44 mL of Na2SO4

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

Step 2:

Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:

Molarity of Ba(NO3)2 = 0.5 M

Volume of solution = 20 mL = 20/1000 = 0.02 L

Mole of solute (Ba(NO3)2) =?

Molarity = mole /Volume

0.5 = Mole of Ba(NO3)2 / 0.02

Cross multiply to express in linear form

Mole of Ba(NO3)2 = 0.5 x 0.02

Mole of Ba(NO3)2 = 0.01 mole

Step 3:

Determination of the number of mole of Na2SO4 that reacted.

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

From the balanced equation above,

1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.

Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.

Step 4:

Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:

Mole of Na2SO4 = 0.01 mole

Molarity of Na2SO4 = 0.225M

Volume =?

Molarity = mole /Volume

0.225 = 0.01 / volume

Cross multiply to express in linear form

0.225 x Volume = 0.01

Divide both side by 0.225

Volume = 0.01/0.225

Volume of Na2SO4 = 0.044 L

Converting 0.044 L to mL, we have

Volume of Na2SO4 = 0.044 x 1000

Volume of Na2SO4 = 44 mL

Therefore, 44 mL of Na2SO4 is needed for the reaction

Answer:

She has to add 44.44 mL of Na2SO4

Explanation:

Step 1: Data given

Volume of barium nitrate = 20.00 mL = 0.020 L

Molarity of barium nitrate = 0.500 M

Molarity of sodium sulfate = 0.225 M

Step 2: The balanced equation

Ba(NO3)2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2 NaNO3 (aq)

Step 3: Calculate volume of the sodium sulfate solution needed

For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol basO4 and 2 moles NaNO3

C1*V1 = C2*V2

⇒with C1 = the molarity of Ba(NO3)2 = 0.500 M

⇒with V1 = the volume of Ba(NO3)2 = 0.020 L

⇒with C2 = the molarity of Na2SO4 =0.225 M

⇒with V2 = the volume of Na2SO4 = TO BE DETERMINED

0.500 M * 0.020 L = 0.225 M * V2

V2 = (0.500 M * 0.020 L) / 0.225 M

V2 = 0.04444 L = 44.44 mL

She has to add 44.44 mL of Na2SO4

Answer: The only force that acts between particles of helium gas is Vanderwaal forces.

Explanation:

When molecules are uncharged in nature but still combined together due to the dipole moment of elements then this force holding the molecules together is known as Vanderwaal forces.

This force is weak in nature.

For example, particles of helium gas has Vanderwaal force between its atoms.

Thus, we can conclude that the only force that acts between particles of helium gas is Vanderwaal forces.

Answer:

Acid-base equilibrium.

Explanation:

At low temperatures the amines react with carboxylic acids as bases and not as nucleophiles. This acid-base reaction is disadvantageous on heating, with the nucleophilic attack that will form the amide prevailing under these conditions.