Which substance found in fossil fuels can form a harmful acid when the fuel is burned?

Answers

Answer 1
fossil fuels are mainly organic compounds.Combustion of fossil fuels also produces other air pollutants, such as nitrogen oxides, sulfur dioxide, volatile organic compounds and heavy metals.so,substances which contain sulphur cause to form harmful acids like sulphuric and sulphurus acids
Answer 2

Answer is: sulfur.

Fossil fuel combustion increases the acidity of rain because the sulfur dioxide is produced.  

Because of fuel combustion, sulfur dioxide goes up into the atmosphere as the hot gases rise, than it reacts with water and oxygen in the air and form sulfuric acid:  

Balanced chemical reaction: SO₂(g) + 2O₂(g) + 2H₂O → 2H₂SO₄.  

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

When pH is less than seven (pH<7), solution is acidic.


Related Questions

Imagine a solution of two liquids that are so similar that their interactions together are the same as in the individual liquids. will this solution deviate positively from, deviate negatively from, or ideally follow raoult's law?

Answers

Answer:
ideally follow Raoult's law

Explanation:
Raoult's law states that: "the partial vapor pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture"

It is given that:
1- the two solutions are similar
2- their interactions together are the same as in the individual liquids

This means that the solution formed will be an ideal solution. This means that the vapor pressure formed will be exactly equal to that predicted by Raoult's law.

Hope this helps :)

How many grams of CaCl2 must be used to provide 0.252 moles of chloride ions?

Answers

Calcium chloride dissociates as follows:

CaCl₂(s) ⇄ Ca²⁺(aq) + 2Cl⁻(aq)

According to the dissociation equation, it can be seen that CaCl₂ and Cl⁻ ions have stoichiometric ratio:

n(CaCl₂) : n(Cl⁻) = 1 : 2

n(CaCl₂) = n(Cl⁻)/2

So, it is necessary 2 times more moles of calcium chloride for producing 1 mole of Cl⁻.

n(CaCl₂) = 0.252/2 = 0.126 mole

Finally, we can calculate the necessary mass of calcium chloride:

m(CaCl₂)  = n x M = 0.126 x 110.98 = 13.98 g of CaCl₂





To provide 0.252 moles of chloride ions, one would need 13.98428 grams of [tex]CaCl_2[/tex], using its molar mass of 110.98 g/mol and factoring in that each mole of [tex]CaCl_2[/tex] contains two moles of chloride ions.

To find out how many grams of calcium chloride ([tex]CaCl_2[/tex]) must be used to provide 0.252 moles of chloride ions, consider that each mole of [tex]CaCl_2[/tex] contains two moles of chloride ions. The molar mass of [tex]CaCl_2[/tex] is 110.98 g/mol.

To get the total number of moles of [tex]CaCl_2[/tex] needed, halve the number of chloride ions, which is [tex]\frac{0.252 moles}{2} = 0.126 moles[/tex] [tex]CaCl_2[/tex]. Then, use the molar mass to convert moles to grams:

0.126 moles [tex]CaCl_2[/tex] x 110.98 g/mol = 13.98428 grams of [tex]CaCl_2[/tex]

Therefore, you would need 13.98428 grams of [tex]CaCl_2[/tex] to provide 0.252 moles of chloride ions.

select the one that most likely has the highest rate of effusion Oxygen (O2) or hydrogen (H2):

Answers

The answer is hydrogen (H2) because i just answered this question from Edgenuit.

The identity of a carbonyl-containing compound has been narrowed down to three possibilities: acetamide (ethanamide), acetone (propanone), or 1,1,1-trichloropropanone. 1h nmr and ir spectral data for the compound are given below. determine the structure, and thus the identity, of the compound that gives the observed data.

Answers

I have provided a pair of spectra, NMR and IR for one of the compounds in the question.

The NMR spectrum provides the least information, as there is only a single peak that is a singlet. All three compounds have a methyl group adjacent to a carbonyl that would appear as a singlet. However, the chemical shift is closer to 3 ppm which suggests it is being deshielded further compared to a standard carbonyl which would appear at 2 ppm. This suggests the structure is most likely 1,1,1-trichloropropanone.

Looking at the IR spectrum, we see the carbonyl stretch at approximately 1750 cm⁻¹. We also see the presence of strong stretches at 750 and 850 cm⁻¹ which are very characteristic of a C-Cl stretch. Therefore, there is enough evidence to suggest that these spectra correspond to 1,1,1-trichloropropanone.

Write a chemical equation depicting what happens to the salt in water.

Answers

NaCl(s) + H2O(l) = Na+(aq) + Cl-(aq)
Answer:

[tex]NaCl(s) + H_2O-->Na^{+}(aq)+Cl^{-}(aq)+H_2O[/tex]

Explanation:

1) NaCl is a solid ionic compound.

2) The ions in a crystal of Na Cl are Na(+) and Cl(-).

3) One fundamental property of the ionic compounds is that they dissociate completely in water, which means that the ions separate and are surrounded by molecules of water.

4) That property is what make these compounds electrolytes which means that the solutions conduct electricity (the ions carry the charge and form the flow of current).


Differentiated animal cells and tissues include _____.

cuboidal cells
columnar cells
bone cells
fat cells
neurons
all of the above

Answers

The correct option is ALL OF THE ABOVE.
Differentiation of cell is said to occur when cells changes into another type of cells or cells. The process occurs during cell growth in multi cellular organisms. When a cell is fully differentiated it becomes specialized. All of the cells mentioned in the options above are differentiated cells. 

What does it mean for a solution to be saturated

A. No more solute can be dissolved
B. The Concentration can be increased
C. No more solvent can be dissolved
D. The Solution can dissolve more substances

Answers

Answer:
A. No more solute can be dissolved 

Explanation:
A solute is defined as a substance that is dissolved
A solvent is the substance in which the solute is dissolved

When the maximum concentration of solute is dissolved in a solvent, the solution is said to be saturated.
This means that the any more solute added to the solution will not dissolve.

Hope this helps :)

Complete the sentence to explain when waves interact.

Waves interact with _____ and other _______ .

Answers

The answer is: Waves interact with objects and other waves.

There are many types of waves, with different energy and interactions witt.

In order from highest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

For example, ultraviolet wave is a type of electromagnetic radiation.

Ultraviolet has shorter waves and higher energy than violet, it lies between visible light and X-rays on the electromagnetic spectrum.

Ultraviolet radiation oscillates at rates between about 800 terahertz (THz) and 30000 THz.

To effectively stop both beta particles and gamma waves, scientists use a chamber composed of lead (Pb).

Answer:

objects and waves

Explanation:

If this reaction produced 19.6 g of kcl, how much o2 was produced (in grams)?

Answers

Answer is: mass of oxygen is 12,576 grams.
Missing chemical reaction: 2KClO₃ → 2KCl + 3O₂.
m(KCl) = 19,6 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 19,6 g ÷ 74,55 g/mol.
n(KCl) = 0,262 mol.
From chemical reaction: n(KCl) : n(O₂) = 2 : 3.
n(O₂) = 3 · 0,262 mol ÷ 2.
n(O₂) = 0,393 mol.
m(O₂) = n(O₂) · M(O₂).
m(O₂) = 0,393 mol · 32 g/mol.
m(O₂) = 12,576 g.

What mass of phosphoric acid (h3po4, 98.0 g/mol) is produced from the reaction of 10.0 g of p4o10 (284 g/mol) with excess water?

Answers

when the balanced reaction equation is:
P4O10 + 6H2O→ 4 H3PO4
when we have the mass of P4O10 = 10 g  and the molar mass of P4O10=284 g/mol & we have the molar mass of H3PO4 =98 g/mol so we can get the mass of H3PO4 by substitution by:
mass of H3PO4 = (mass of P4O10)/(molar mass of P4O10) * 4(mol of H3PO4)*molar mass of H3PO4
∴mass of H3PO4 = (10 / 284) * 4 * 98 = 13.8 g

Answer : The mass of phosphoric acid produced is 6.89 grams.

Solution : Given,

Mass of [tex]P_4O_{10}[/tex] = 10.0 g

Molar mass of [tex]P_4O_{10}[/tex] = 284 g/mole

Molar mass of [tex]H_3PO_4[/tex] = 98.0 g/mole

First we have to calculate the moles of [tex]P_4O_{10}[/tex].

[tex]\text{ Moles of }P_4O_{10}=\frac{\text{ Mass of }P_4O_{10}}{\text{ Molar mass of }P_4O_{10}}=\frac{10.0g}{284g/mole}=0.0352moles[/tex]

Now we have to calculate the moles of [tex]MgO[/tex]

The balanced chemical reaction is,

[tex]P_4O_{10}+6H_2O\rightarrow 4H_3PO_4[/tex]

From the reaction, we conclude that

As, 1 mole of [tex]P_4O_{10}[/tex] react to give 2 mole of [tex]H_3PO_4[/tex]

So, 0.0352 moles of [tex]P_4O_{10}[/tex] react to give [tex]0.0352\times 2=0.0704[/tex] moles of [tex]H_3PO_4[/tex]

Now we have to calculate the mass of [tex]H_3PO_4[/tex]

[tex]\text{ Mass of }H_3PO_4=\text{ Moles of }H_3PO_4\times \text{ Molar mass of }H_3PO_4[/tex]

[tex]\text{ Mass of }H_3PO_4=(0.0704moles)\times (98.0g/mole)=6.89g[/tex]

Therefore, the mass of phosphoric acid produced is 6.89 grams.

Choose the solvent below that would show the greatest freezing point lowering when used to make a 0.20 m nonelectrolyte solution.

Answers

Missing question:
a) benzene, Kf = 5.12°C/m.
b) ethanol, Kf = 1.99°C/m.
c) chloroform, Kf = 4.70°C/m.
d) carbon tetrachloride, Kf = 29.9°C/m
e) diethyl ether, Kf = 1.79°C/m.
Answer is: d) carbon tetrachloride, Kf = 29.9°C/m.
b(solution) = 0,2 m.
ΔT = Kf · b(solution).
Because molality (b) is constant, greatest freezing point lowering is solution with highest Kf (the freezing point depression constant).


Because the rock is irregularly shaped, you used the (______) method to measure its volume. A. Addition B. Direct C. Displacement

Answers

Because the rock is irregular in shape, you use the Displacement method to measure its volume.

After getting a cylindur (with measurements), you can it up half way with water.

For example: let say the cylindur is goes up to 10 cm. You will fill it up to 5 cm with water. Then when you put the rock inside, (for example), the water level goes up to 8 cm. You will then know that the rock that you put in displaces 3 cm of water

hope this helps

Answer:

Displacement

Explanation:

I NEED HELP, HELP ME PLZ!!!

Answers

I belevieve the answer is A
Hey there Cakes!

So, when you present a (oral) presentation, this would mean that you would pretty much be giving a speech, because it would be oral. (from your mouth).

Based on my understanding, I believe that the best option would actually be A.)  I think that it would be best if you were not to do this because alot of times, this could get you very nervous and unconcentrated in your speech

The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the reactant, pcl5, at equilibrium?

Answers

we have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula: 
Kc   = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 =  0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

Final answer:

The concentration of the reactant PCl5 at equilibrium can be found using the given equilibrium concentrations of the products and the equilibrium constant by rearranging the equilibrium expression and substituting the known values.

Explanation:

To determine the concentration of the reactant PCl5 at equilibrium, we use the equilibrium constant Ke for the reaction, which is given as 0.0211. Let's set up the equilibrium expression for this decomposition reaction:

PCl5 → PCl3 + Cl2

The equilibrium constant expression is:

Ke = [PCl3][Cl2] / [PCl5]

We can rearrange this equation to solve for [PCl5]:

[PCl5] = [PCl3][Cl2] / Ke

We substitute the given concentrations [PCl3] = 0.180 M and [Cl2] = 0.250 M into the equation:

[PCl5] = (0.180 M)(0.250 M) / 0.0211

By calculating the above equation, we find the concentration of PCl5 at equilibrium.

Match the element or group to the rule assigning its oxidation state.
(1.5 points) A. Oxygen B. Hydrogen C. Lone elements and atoms in gases D. Elements with multiple oxidation states E. Elements in groups 1, 2, and 17 and polyatomic ions
_____ 0
_____ Ionic charge
_____ +1, – 1 if bonded to a diatomic metal
_____ Almost always –2
_____ Determined by other elements in the compound

Answers

C. Lone elements and atoms in gases : 0

Elements in the free elemental have an oxidation number of zero

E. Elements in groups 1, 2, and 17 and polyatomic ions : Ionic charge

Group 1, 2, and 17 ions are formed by the alkali metals, alkaline metals and halogens respectively. Alkali metals, alkaline metals and halogens form +1, +2 and -1  ions respectively. Polyatiomic ions have -1, -2, -3 charges such as OH-, CO32-, PO43- respectively.

B. Hydrogen : +1, – 1 if bonded to a diatomic metal

H has an oxidation number of +1. H in metal hydrides such as NaH (sodium hydride) has an oxidation number of -1

A. Oxygen : Almost always –2  

O has an oxidation number of -2.

D. Elements with multiple oxidation states : Determined by other elements in the compound

V (vanadium) has different oxidation which depends on the compound in which V is found.

look at the thing attached

The ka of benzoic acid is 6.4 x 10–5. what is the approximate ph of a 1.5 m solution of benzoic acid?

Answers

I don't know if you need the answer explain to you but here's the answer 2.00

Answer: 2.01

Explanation:

[tex]C_6H_5COOH\rightleftharpoons C_6H_5COO^-+H^+[/tex]

initial : c         0             0

eqm: [tex]c(1-\alpha)[/tex]     [tex]c\alpha[/tex]      [tex]c\alpha[/tex]  

[tex]K_a=\frac{c\alpha\times c\alpha}{c(1-\alpha)}[/tex]

when [tex]\alpha[/tex] is very very small the, the expression will be,

[tex]k_a=\frac{c^2\alpha^2}{c}=c\alpha^2\\\\\alpha=\sqrt{\frac{k_a}{c}}[/tex]

And,

[tex][H^+]=c\alpha[/tex]

Thus the expression will be,

[tex][H^+]=\sqrt{k_a\times c}[/tex]

Now put all the given values in this expression, we get

[tex][H^+]=\sqrt{(6.4\times 10^{-5})\times 1.5}[/tex]

[tex][H^+]=9.7\times 10^{-3}M[/tex]

[tex]pH=-log[H^+][/tex]

[tex]pH=-log[9.7\times 10^{-3}]=2.01[/tex]

A carbon sink is a location that stores carbon for a long period of time. What are two carbon sinks that remove carbon from the atmosphere?

Answers

The ocean is a carbon sink and the soil is the other one. A third is plants.
Hope that helps!

Plants, the ocean, and soil serve as the primary natural carbon sinks. A portion of the carbon dioxide that plants absorb from the environment to use in photosynthesis is transferred to the soil as plants disintegrate and die.

What is carbon sinks?

Anything—natural or artificial—that gathers and stores a carbon-containing chemical compound over an extended period of time eliminates carbon dioxide from the atmosphere.

The ocean and vegetation are the two most significant carbon sinks on a global scale.

Typically, forests act as carbon sinks, absorbing more carbon than they emit. Through photosynthesis, they remove carbon from the atmosphere on a constant basis.

Another example of a carbon sink is the ocean, which takes in a lot of carbon dioxide from the atmosphere.

Therefore, the ocean, plants, and soil serve as the primary natural carbon sinks.

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Part a draw the major organic product formed when the compound shown below undergoes a reaction with an excess of etoh under acidic conditions.

Answers

Propanal undergoes nucleophilic addition with excess ethanol under acidic conditions, forming ethyl propanoate (ethyl propionate) and water through esterification.

Let's go into more detail about the reaction between propanal [tex](\(CH_3CH_2CHO\))[/tex] and ethanol [tex](\(EtOH\))[/tex] under acidic conditions.

1.  Nucleophilic Addition of Ethanol:

  - In the presence of an acid catalyst, such as sulfuric acid [tex](\(H_2SO_4\))[/tex], the carbonyl group of propanal undergoes nucleophilic addition with ethanol.

  - The oxygen in the carbonyl group acts as a nucleophile attacking the partially positive carbon of the carbonyl carbon.

 [tex]\[ \ce{CH3CH2CHO + EtOH} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3} \][/tex]

2. Formation of Hemiacetal:

  - Initially, a hemiacetal is formed, which involves the addition of one molecule of ethanol to the carbonyl group.

[tex]\[ \ce{CH3CH2CHO + EtOH} \xrightarrow{acid} \ce{CH3CH(OH)CH2COOCH2CH3} \][/tex]

3. Formation of Acetal (Ester):

  - The hemiacetal formed can undergo another nucleophilic addition with a second molecule of ethanol, leading to the formation of the acetal (ester) and regeneration of the acid catalyst.

 [tex]\[ \ce{CH3CH(OH)CH2COOCH2CH3} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3 + H2O} \][/tex]

4. Overall Reaction:

  - The overall reaction involves the addition of two molecules of ethanol to propanal, resulting in the formation of ethyl propanoate (ethyl propionate) and water.

[tex]\[ \ce{CH3CH2CHO + 2 EtOH} \xrightarrow{acid} \ce{CH3CH2COOCH2CH3 + H2O} \][/tex]

The ethyl propanoate formed is an ester, and this reaction is an example of an esterification reaction under acidic conditions. It's important to note that excess ethanol is used to drive the reaction to completion, and the acidic conditions help in the protonation and activation of the carbonyl group for nucleophilic attack by ethanol.

Complete Question

A tank of water contains many billions of water molecules. These molecules move at random speeds and in random directions, often colliding with each other. What form of energy does the water have due to the random motion of its particles?


thermal


radiant


chemical


potential

Answers

I think the answer is A. thermal.Hope this helps!:)

The energy due to the random motion of water molecules in a tank is thermal energy, which is related to the temperature of the water and can be transferred as heat.

The form of energy that water has due to the random motion of its molecules is called thermal energy. This energy arises from the kinetic energy that is present in the random microscopic motions of the water molecules. When these molecules move, collide, and bounce off each other, the average kinetic energy of these motions correlates with the temperature of the water. Furthermore, thermal energy can be transferred between objects or systems through processes like conduction, convection, and radiation, at which point it is commonly referred to as heat energy.

The most stable conformation of 1,2-dibromoethane is:

Answers

I have attached an image that shows the most stable conformation of 1,2-dibromoethane. The top image shows the line drawing of the structure and the bottom image shows the Newman project of the structure. The Newman project shows up the perspective of looking down the C1-C2 bond of the compound. From this perspective, we can see the relationship between the two bromo-substituents.

Since the bromo-substituents are the largest groups substituted on each carbon atom, these groups will want to be as far away from each other in space as possible. The result is this anti- relationship shown, where the two bromo atoms are as far away from each other as possible within the molecule to reduce the amount of steric interactions. Therefore, the anti-conformation is the most stable conformation of 1,2-dibromoethane.

In which range of time do earthquakes occur? A. seconds B. days C. months D. millions of years

Answers

A) Seconds
Earthquakes are very frequent around the world

is the correct.......................

HELP!!!! 15 pts !!! Which chemical equation below does not illustrate the Law of Conservation of Mass? Al4C3 + 3H2O yields CH4 + 4Al(OH)3 2 NaCl + CaO yields Na2O + CaCl2 3 LiOH + Fe(NO3)3 yields 3LiNO3 + Fe(OH)3 Zn + 2HCl yields ZnCl2 + H2

Answers

The last chemical equation doesn't follow the law of conservation because there isn't an equal number of zinc

Write a balanced chemical equation for the reaction of acetone (c3h6o) with oxygen (o2) to form carbon dioxide (co2) and water (h2o). select one:
a. c3h6o + 4 o2 ® 3 co2 + 3 h2o.
b. 3 co2 + 3 h2o ® c3h6o + 4 o2.
c. 6 c3h6o + 8 o2 ® 6 co2 + 6 h2o.
d. c3h6o + o2 ® co2 + h2o.

Answers

the balanced equation for this reaction is  
C3H6O + 4 O4 → 3CO2 + 3H2O
but you should how to balance the original equation:
the original equation was C3H6O + O4 → CO2 + H2O
to be the equation balanced we have to make each number of the atom is equal on each side of the equation.
1) first, we start with C atom in the original equation it was 3 atom in the right side and 1 atom in the left side so we put 3CO2 instead of CO2 in the right side to make the C atoms number is equal in both sides.
the equation becomes C3H6O + O2 → 3CO2 + H2O
2) second, the H atom, it was 6 atom in the left side and only 2 in the right side so we put 3H2O instead of H2O to make it equals each other in both sides.
the equation becomes C3H6O + O2 → 3 CO2 + 3H2O
3) finally, the O atom, it was 4 atom in the right side and 9 atoms in the left side so we put 4 O2 instead of O2 to make it equals each other in both sides

so we get the final balanced equation is
C3H6O + 4O2 → 3CO2 +3H2O


The balanced chemical equation for the reaction of acetone (C3H6O) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is C3H6O + 4 O2 → 3 CO2 + 3 H2O (option a). It preserves mass and element conservation.

The balanced chemical equation for the reaction of acetone (C3H6O) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:

a. C3H6O + 4 O2 → 3 CO2 + 3 H2O.

In this balanced equation, the number of carbon atoms, hydrogen atoms, and oxygen atoms on both sides is the same, ensuring that mass and element conservation are maintained.

Explanation:

- On the left side (reactants), there is one molecule of acetone (C3H6O) and four molecules of oxygen (O2).

- On the right side (products), there are three molecules of carbon dioxide (3 CO2) and three molecules of water (3 H2O).

This equation satisfies the law of conservation of mass and the law of conservation of elements because the number of each type of atom (carbon, hydrogen, and oxygen) remains the same on both sides of the equation. Option (a) is the correct balanced chemical equation for this reaction.

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What type of change does electron have?

Answers

Proton—positive; electron—negative; neutron—no charge. The charge on the proton and electron are the same size but opposite. The same number of protons and electrons exactly cancel one another in a neutral atom.
If you mean charge than that would be negative

how many molecules of h2o are equal to 97.2 g h2o

Answers

m(H₂O) = 97,2 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 97,2 g ÷ 18 g/mol.
n(H₂O) = 5,4 mol.
N(H₂O) = n(H₂O) · Na.
N(H₂O) = 5,4 mol · 6,023·10²³ 1/mol.
N(H₂O) = 3,25·10²⁴ molecules of water.
n - amount of substance.
Na - Avogadro number.

Answer:

3.25*10^24

Explanation:

The wittig reaction involves coupling between a phosphonium ylide and a carbonyl-containing molecule. if a chemist wants to use the wittig reaction to synthesize 2-methyl-2-pentene, which reactants should be used?

Answers

Final answer:

In the Wittig reaction to synthesize 2-methyl-2-pentene, a phosphonium ylide and a carbonyl-containing molecule, such as an aldehyde or a ketone, are needed as reactants.

Explanation:

The reactants needed for the Wittig reaction to synthesize 2-methyl-2-pentene are a phosphonium ylide and a carbonyl-containing molecule. In this case, the carbonyl-containing molecule should be an aldehyde or a ketone. The phosphonium ylide is usually generated from a phosphine and an alkyl halide. For example, one possible combination of reactants could be triphenylphosphine and methyl iodide to form the phosphonium ylide, which can then react with an aldehyde or ketone to produce 2-methyl-2-pentene.

What is the pressure in atmospheres if 1360.0g of N2O gas is compressed in a 25.0L cylinder and is stored in an outdoor shed where the temperature can reach 59.0°C in the summer?

Answers

According to this formula:
PV = nRT
when V = 25 L and n (mol) = 1360 g / 44 (mass weight of N2O)= 30.9 mol
R constant = 0.0821    and T in kelvin =59 + 273 = 332 K
By substitution in the formula:
P* 25 = 30 * 0.0821 * 332 
∴ P = 32.7 atm
  

Final answer:

pressure of 34.19 atmospheres.

Explanation:

To find the pressure in atmospheres of 1360.0g of N2O gas compressed in a 25.0L cylinder at 59.0°C, use the Ideal Gas Law PV = nRT, where:

P is the pressure we want to find, V is the volume of the gas (25.0L),n is the number of moles of N2O,R is the ideal gas constant (0.0821 L·atm/K·mol),T is the temperature in Kelvin (59.0°C + 273.15 = 332.15 K).

First, calculate the moles of N2O:

Molecular mass of N2O = (14.0×2) + 16.0 = 44.0g/mol

Moles of N2O = 1360.0g / 44.0g/mol = 30.91mol

Then, substitute the values into the Ideal Gas Law and solve for P:

P = (nRT)/V = (30.91mol × 0.0821 L·atm/K·mol × 332.15 K) / 25.0L = 34.19 atm

After you preform your experiment, you determine that the kf value for naphthalene is 6.91 °c/m . you are using 10g of naphthalene and added 1.0 g of your unknown. the the freezing point of the solvent decreased by 4.47 °c when the unknown was added. knowing this information, determine the molar mass of the unknown. g/mol

Answers

Answer is: molar mass of compound is 154,58 g/mol.
m(naphthalene) = 10 g = 0,01 kg.
m(unknown compound) = 1,00 g.
ΔT (solution) = 4,47 °C.
Kf(naphthalene) = 6,91°C/m; cryoscopic constant.
M(unknown compound) = Kf(naphthalene)· m(unknown compound) ÷ m(naphthalene) · ΔT(solution).
M(xylene) = 6,91°C/m · 1 g ÷ 0,01 kg · 4,47°C.
M(xylene) = 154,58 g/mol.

Based on the Kf value and mass of the solvent naphthalene, the molar mass of the unknown compound is 154.58 g/mol.

What is the molar mass of a substance?

The molar mass of a substance is the mass of one mole of that substance.

The molar mass of a substance can be calculated from the Kf value and mass of the solvent naphthalene as follows:

mass of naphthalene = 10 g or 0.01 kg.

mass of unknown compound = 1.00 g

ΔT of the solution = 4,47 °C.

Kf value of naphthalene = 6.91°C/m;

Molar mass of unknown compound = Kf(naphthalene) × mass of unknown compound/ mass of naphthalene × ΔT

Molar mass of the unknown compound = 6.91°C/m · 1 g ÷ 0.01 kg × 4,47°C.

Molar mass of the unknown compound = 154.58 g/mol.

Therefore, the molar mass of the unknown compound is 154.58 g/mol.

Learn more about molar mass and Kf at: https://brainly.com/question/10674700


1. At approximately 50°C and 0.5 kPa, what phase of matter is water in? *


A. Solid

B. liquid

C. vapor

D. both liquid and vapor


2. A sample of neon occupies a volume of 375 mL at STP. What will be the volume of the neon if the pressure is reduced to 90.0 kPa? *


A.422 mL

B.422 L

C. 333 mL

D. 333 L


3. A gas at 155 kPa and standard temperature has an initial volume of 1.00 L. The pressure of the gas rises to 500 kPa as the temperature also rises to 135°C. What is the new volume? *


A. 2.16 L

B. 0.463 L

C. 0.207 L

D. 4.82 L


4. What pressure will be exerted by 0.650 mol of a gas at 30.0°C if it is contained in a 0.700 L vessel? *


A. 2340 kPa

B. 2340 atm

C. 231 kPa

D. 231 atm


5. The vapor pressure of water is *


a. high due to very weak intermolecular attractions

b. high due to water's polarity

c. low due to water's high specific heat

d. low due to relatively strong intermolecular attractions


6. Which mixture contains the largest particles? *


a. solution

b. suspension

c. colloid

d. emulsion


7. How does evaporation of a liquid differ from boiling a liquid?


8. Describe the Tyndall Effect and how it could affect my drive home on a foggy night.

Answers

The answer would have to be the letter a for question 1

The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine in this solution?

Answers

The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is X = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
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