which transformations are needed to change the parent some function to the sine function below?
Answers
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.
Solution:
the function y = sin x, which would have range from -1 to 1 and period of 2pi:
So the answer would be:Vertical compression of 1/2 compresses the range from -1/2 to 1/2Phase shift of pi/2 to the leftHorizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4piVertical shift of 1 unit up moves the range to 1/2 to 3/2
Related Questions
What is the cube root of 216x^9y^8
Answers
Please, see the attached file.
Thanks.
(216x^9y^8)^(1/3)
216^(1/3) = 6
9/3 = 3
8/3 = 2 2/3
(216x^9y^8)^(1/3) = 6 x^3 y^2 y^(2/3)
given f(x)=x^2 +3 find h(x) h(x)=f(5x)-f(-2)
Answers
Answer:
h(x) = 25x^2 -4
Step-by-step explanation:
Fill in the given arguments and evaluate:
h(x) = f(5x) -f(-2)
= ((5x)^2 +3) - ((-2)^2 +3)
h(x) = 25x^2 -4
The prices (in dollars) of 50 randomly chosen types of shoes at 4 different stores are shown in the box plots. At which store would a person MOST LIKELY pay $18.75 for a pair of shoes?
A) Store A
B) Store B
C) Store C
D) Store D
Answers
The answer to this question is A.
In a box plot, the values outside box are less likely to occur than the values inside the box. The store a person MOST LIKELY pay $18.75 for a pair of shoes from is given by: Option A: Store A
How does a box-plot shows the data points?A box plot has 5 data description.
The leftmost whisker shows the minimum value in the data.The rightmost whisker shows the maximum value in the data.The leftmost line in the box shows the first quartile.The middle line shows the median, also called second quartile.The last line of the box shows the third quartile.For all the box-plots plotted in the image attached, we can see that only the first box plot is such that the amount $18.75 is falling inside the box's boundaries.
The box is contained with more likely elements than those which are outside of it. It is because, the box contains those elements which are between first and third quartile. Since the selection was done randomly, so mean, median and mode all lie approximately on the same point due to the distribution tending to normal distribution(sample size is large enough (50 > 30, a needed sample size for consideration of that sample belonging from normal distribution)). Now, for the first graph, the median is closest to $18.75, and the more close a value is to center of a normal distribution, the more probable it is.
That's why, the store a person MOST LIKELY pay $18.75 for a pair of shoes from is given by: Option A: Store A
Learn more about box plot here:
https://brainly.com/question/1523909
Kelly ask Tyrese to help her use the vertical line test to determine whether or not the curve that she was given it is a function Tyrese informed Kelly that an order for the given curve to be designated as a function of a vertical line drawn through any x value must intersect the Curve___ time(s)
Answers
General Idea:
Vertical line test is a test used to determine if a relation is a function. As per vertical line test, a relation is a function if there are no vertical lines that intersect the graph at more than one point.
Applying the concept:
Kelly ask Tyrese to help her use the vertical line test to determine whether or not the curve that she was given it is a function Tyrese informed Kelly that an order for the given curve to be designated as a function of a vertical line drawn through any x value must intersect the Curve [tex] ONE [/tex] time.
A six-sided die in which each side is equally likely to appear is repeatedly rolled until the total of all rolls exceed 400
Answers
Approximately 0.2266, or 22.66%, is the probability that rolling the die more than 140 times is needed to exceed a total of 400.
To approximate the probability that rolling the die more than 140 times is needed to exceed a total of 400, we can use a normal approximation to the binomial distribution since the number of rolls is large.
First, let's calculate the mean (μ) and standard deviation (σ) of the number of rolls needed to exceed 400:
[tex]\[ \text{Mean (μ)} = \frac{\text{Total target}}{\text{Expected value per roll}} = \frac{400}{\frac{7}{2}} \][/tex]
[tex]\[ \text{Standard deviation (σ)} = \sqrt{\frac{\text{Total target} \times (\text{Sides}^2 - 1)}{12}} = \sqrt{\frac{400 \times (6^2 - 1)}{12}} \][/tex]
Now, we'll use the normal approximation and the z-score formula to find the probability:
[tex]\[ z = \frac{\text{X} - \text{μ}}{\text{σ}} \][/tex]
[tex]\[ z = \frac{140 - \text{μ}}{\text{σ}} \][/tex]
Then, we look up the z-score in a standard normal distribution table or use a calculator to find the probability associated with that z-score.
Let's calculate these values.
First, let's calculate the mean (μ) and standard deviation (σ):
[tex]\[ \text{Mean (μ)} = \frac{400}{\frac{7}{2}} = \frac{800}{7} \approx 114.29 \][/tex]
[tex]\[ \text{Standard deviation (σ)} = \sqrt{\frac{400 \times (6^2 - 1)}{12}} = \sqrt{\frac{400 \times 35}{12}} \approx \sqrt{\frac{14000}{12}} \approx \sqrt{1166.67} \approx 34.16 \][/tex]
Now, let's find the z-score for rolling the die more than 140 times:
[tex]\[ z = \frac{140 - \text{μ}}{\text{σ}} = \frac{140 - 114.29}{34.16} \approx \frac{25.71}{34.16} \approx 0.75 \][/tex]
Using a standard normal distribution table or calculator, we find the probability associated with a z-score of 0.75, which represents the probability that rolling the die more than 140 times is needed to exceed a total of 400.
The Correct Question is :
A six-sided die, in which each side is equally likely to appear, is repeatedly rolled until the total of all rolls exceeds 400. Approximate the probability that this will require more than 140 rolls.
The approximate probability that it will require more than 140 rolls for the total to exceed 400 is 0.005.
To find the approximate probability that it will require more than 140 rolls for the total to exceed 400, we can relate it to the probability that the sum of the first 140 rolls is less than 400.
Let X be the random variable representing the sum of the rolls. We want to find P(X > 400), which is the probability that it will require more than 140 rolls.
We can calculate this by finding the complement of the event that the sum of the first 140 rolls is less than 400.
Let A be the event that the sum of the first 140 rolls is less than 400. Then, P(A) is the probability that we're interested in.
Now, we calculate P(A):
Since each side of the die is equally likely, the expected value of the roll is [tex]\( \frac{1+6}{2} = 3.5 \)[/tex].
The expected value of the sum of the first 140 rolls is [tex]\( 140 \times 3.5 = 490 \)[/tex].
Therefore, P(A) can be approximated using the normal distribution, since the sum of the rolls follows approximately a normal distribution due to the Central Limit Theorem.
Using the properties of the normal distribution, we can standardize the value:
[tex]\[ Z = \frac{400 - 490}{\sqrt{140 \times \left(\frac{1}{12}\right)}} \][/tex]
Here, [tex]\( \frac{1}{12} \)[/tex] is the variance of a single roll of the die.
Now, we find P(A) using the standardized value of Z:
P(A) = P(X < 400) = P(Z > z)
We can then find the probability from a standard normal distribution table or calculator.
[tex]\[ P(A) \approx P(Z > -2.589) \][/tex]
From a standard normal distribution table, we find that [tex]\( P(Z > -2.589) \approx 0.995 \)[/tex].
So, the approximate probability that it will require more than 140 rolls for the total to exceed 400 is 1 - 0.995 = 0.005.
The probable question may be:
A six-sided die, in which each side is equally likely to appear, is repeatedly rolled until the total of all rolls exceeds 400. What is the approximate probability that this will require more than 140 rolls? (Hint: Relate this to the probability that the sum of the first 140 rolls is less than 400.)
The Fergusons reported making the following payments during the year:
State income taxes of $4,400. Federal tax withholding of $4,000.
Alimony payments to John’s former wife of $10,000.
Child support payments for John’s child with his former wife of $4,100.
$3,200 of real property taxes.
Sandy was reimbursed $600 for employee business expenses she incurred. She was required to provide documentation for her expenses to her employer.
In addition to the $750 of Web design expenses, John attended a conference to improve his skills associated with his Web design work. His trip was for three days and he incurred the following expenses: airfare $370, total taxi fares for trip $180, meals $80, and conference fee of $200.
$3,600 to Kid Care day care center for Samantha’s care while John and Sandy worked.
$14,000 interest on their home mortgage.
$3,000 interest on a $40,000 home-equity loan. They used the loan to pay for a family vacation and new car.
$6,000 cash charitable contributions to qualified charities.
Donation of used furniture to Goodwill. The furniture had a fair market value of $400 and cost $2,000.
a. What is the Fergusons’ 2017 federal income taxes payable or refund, including any self-employment tax and AMT, if applicable? (Use the 2017 AMT exemptions.) (Round your answer to 2 decimal places.)
Answers
Answer:163.46
Step-by-step explanation:
somebody please help so I can pass, please
Rewrite the following equation in the form y = a(x - h)2 + k. Then, determine the x-coordinate of the minimum.
y=2x^2 - 32x + 56
The rewritten equation is y = ____ (x - _____ )2 + ____ .
The x-coordinate of the minimum is _____
Answers
We now from our quadratic that [tex]a=2[/tex] and [tex]b=-32[/tex], so lets use our formula:
[tex]h= \frac{-b}{2a} [/tex]
[tex]h= \frac{-(-32)}{2(2)} [/tex]
[tex]h= \frac{32}{4} [/tex]
[tex]h=8[/tex]
Now we can evaluate our quadratic at 8 to find [tex]k[/tex]:
[tex]k=2(8)^2-32(8)+56[/tex]
[tex]k=2(64)-256+56[/tex]
[tex]k=128-200[/tex]
[tex]k=-72[/tex]
So the vertex of our function is (8,-72)
Next, we are going to use the vertex to rewrite our quadratic equation:
[tex]y=a(x-h)^2+k[/tex]
[tex]y=2(x-8)^2+(-72)[/tex]
[tex]y=2(x-8)^2-72[/tex]
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.
We can conclude that:
The rewritten equation is [tex]y=2(x-8)^2-72[/tex]
The x-coordinate of the minimum is 8
Answer:
y = 2 (x - 8 )2 + (-72)) .
The x-coordinate of the minimum is 8.
Step-by-step explanation:
I just took this test on plato and I got it correct.
For the data set below, calculate the variance to the nearest hundredth decimal place. 27 38 47 42 33 56 37 57 38 52
Answers
Var=Σ(x-μ)²/(n-1)
mean=(27+38+47+42+33+56+37+57+38+52)/10=42.7
Σ(x-μ)²=(27-42.7)²+(38-42.7)²+(47-42.7)²+(42-42.7)²+(33-42.7)²+(56-42.7)²+(37-42.7)²+(57-42.7)²+(38-42.7)²+(52-42.7)²
=904.1
Thus variance will be:
904.1/(10-1)
=100.45555556
~100.5
Suppose you pay $1.00 to roll a fair die with the understanding that you will get back $3.00 for rolling a two or a three. what are the expected winnings?
Answers
G technical mathematics with calculus volume 10 find the derivative of the function y = sqrt(x^2+1) using limits definition
Answers
[tex]\displaystyle\frac{\mathrm dy}{\mathrm dx}=\lim_{h\to0}\frac{y(x+h)-y(x)}h[/tex]
[tex]\displaystyle\frac{\mathrm dy}{\mathrm dx}=\lim_{h\to0}\frac{\sqrt{(x+h)^2+1}-\sqrt{x^2+1}}h=\lim_{h\to0}\frac{\sqrt{x^2+2xh+h^2+1}-\sqrt{x^2+1}}h[/tex]
Multiply the numerator and denominator by the conjugate of the numerator:
[tex]\dfrac{\sqrt{x^2+2xh+h^2+1}-\sqrt{x^2+1}}h\cdot\dfrac{\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}}{\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}}=\dfrac{(x^2+2xh+h^2+1)-(x^2+1)}{h\left(\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}\right)}[/tex]
Now
[tex]\displaystyle\frac{\mathrm dy}{\mathrm dx}=\lim_{h\to0}\frac{(x^2+2xh+h^2+1)-(x^2+1)}{h\left(\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}\right)}[/tex]
[tex]=\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h\left(\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}\right)}[/tex]
[tex]=\displaystyle\lim_{h\to0}\frac{2x+h}{\sqrt{x^2+2xh+h^2+1}+\sqrt{x^2+1}}[/tex]
As [tex]h\to0[/tex], in the numerator we have [tex]2x+h\to2x[/tex]; in the denominator we have [tex]\sqrt{x^2+2xh+h^2+1}\to\sqrt{x^2+1}[/tex]. So the limit is
[tex]\dfrac{2x}{2\sqrt{x^2+1}}=\dfrac x{\sqrt{x^2+1}}[/tex]
What equation results from completing the square and then factoring? x^2-8x=39
Answers
x²-8x=39
Group terms that contain the same variable
(x²-8x)=39
Complete
the square. Remember to balance the equation by adding the same constants
to each side
(x²-8x+16)=39+16
Rewrite as perfect squares
(x-4)²=55-------> (x-4)²-55=0(+/-)]x-4]=√55
(+)]x-4]=√55--------> x=4+√55
(-)]x-4]=√55-------> x=4-√55
the answer is
(x-4)²-55=0
Answer: (x-4)²=55
Step-by-step explanation:
This is apex answer
Q # 13. please help to solve this
Answers
A=2πrh+2πr^2
Where r is the radius and h is the height of the cylinder
You have that r=15.1 inches and h=12.8 inches, then:
A=2πrh+2r^2
A=2π(15.1 in)(12.8 in)+2π(15.1 in)^2
A=2647 in^2
The answer is 2647 in^2
304 students went on a field trip. seven buses were filled and 17 students traveled in cars. how many students were in each bus?
Answers
-
304: total students
17: riding in car
7: number of buses
-
304 - 17 = 287
287 divided by 7 = 41
PLZ HELP NOOWWWWWWW!!!
The diameter of a certain planet is approximately 3x10^7 meters (aka 30000000 meters). The length of a certain city is approximately 5x10^4 meters (aka 50000 meters).
How many times greater is the diameter of the planet compared to the length of the city?
Answers
You divide the diameter of the planet by the length of the city
30000000 / 50000 = 600
The diameter is 600 times greater than the length of the city
The answer is 600
Hope this helps!
hey can you please help me posted picture of question
Answers
Vertical translation is obtained by adding or subtracting a number from the function. Addition of a number brings about upward translation and subtraction of a number brings downward translation.
So, the answer to this question is option A
Explain how you would use equivalent fractions to solve 0.5 + 0.10
Answers
1/2+1/10 which would be 3/5 which that in decimal form is .6
What is the median of the data set: 50, 54,62,48,49,52
Answers
First, sort the data from least to greatest:
48, 49, 50, 52, 54, 62
The median lies between the number 50 and 52
The median is 51
If p(a) = 0.35, p(b) = 0.45, and p(a and
b.= 0.25, then p(a|b) is:
Answers
[tex]\mathbb P(A\mid B)=\dfrac{\mathbb P(A\cap B)}{\mathbb P(B)}[/tex]
Thus
[tex]\mathbb P(A\mid B)=\dfrac{0.25}{0.45}\approx0.56[/tex]
Suppose that a sample of size 44 is drawn from a population with mean 36 and standard deviation 47, find the standard deviation of the distribution of sample means
Answers
Answer:
Standard deviation of the distribution of sample means = 7.0855
Step-by-step explanation:
We are given that a sample of size 44 is drawn from a population with mean 36 and standard deviation 47.
Using Central Limit Theorem, it is stated that;
Standard deviation of the distribution of sample means = [tex]\frac{Population S.D.}{\sqrt{n} }[/tex]
= [tex]\frac{\sigma}{\sqrt{n} }[/tex] = [tex]\frac{47}{\sqrt{44} }[/tex] = 7.0855
A grocer bought 300 pounds of bananas at 30 cents per pound. Experience at this store indicates that, as a result of aging, 30% of the bananas are sold at 80% of cost and another 10% are discarded. At what price per pound must the top-quality bananas be sold so that the total proceeds will result in a 20% markup on selling price? Round up to the nearest penny.
a. $0.51
b. $0.38
c. $0.30
Answers
Let p represent the selling price of the top-quality bananas (per pound). The revenue from the sale of those will be
p*(1 -0.30 -0.10) = 0.60p
The revenue from the sale of aged bananas will be
0.30*(0.80*$0.30) = $0.072
Then the total revenue is
(revenue from top quality bananas) +(revenue from aged bananas)
total revenue = 0.60p +0.072
The cost of the bananas is $0.30 (per pound).
Then the proceeds are
proceeds = (total revenue) - cost
And the problem tells us we want the proceeds to be 20% of the total revenue.
(total revenue) -cost = 0.20*(total revenue)
0.80*(total revenue) = cost
0.80*(0.60p +0.072) = 0.30
0.60p = (0.30/0.80) -0.072
p = 0.303/0.60 = 0.505
The best choice for the selling price of top quality bananas is ...
a. $0.51
i feel like its A but i am dumb
When s is the open hemisphere x 2 + y 2 + z 2 = 1, z ≤ 0 , oriented by the inward normal pointing to the origin, then the boundary orientation on ∂s is clockwise. true or false?
Answers
Therefore, the answer above False
what is the median for the set of data shown? 26,34,38,49,65,75,81
Answers
Answer: 49
Step-by-step explanation:
We need to remember that the median of a set of data is the middle value in the set.
To find the median of a set of data the first step is to arrange the data in order from least to greatest, but, in this case, the set of data given is already arranged from least to greatest:
26,34,38,49,65,75,81
Therefore, you can oberve that the middle value in the set is the following:
26,34,38,49,65,75,81
Then, the median for this set of data is: 49
The answer is provided in the image attached.
what is the quotient of 1 over (1 plus the square root of 3)?
Answers
[tex]\dfrac{1}{1+\sqrt{3}}=\dfrac{1}{1+\sqrt{3}}\cdot \dfrac{1-\sqrt{3}}{1-\sqrt{3}}\\\\=\dfrac{1-\sqrt{3}}{1^{2}-(\sqrt{3})^{2}}=\dfrac{1-\sqrt{3}}{1-3}\\\\=\dfrac{\sqrt{3}-1}{2}[/tex]
This eqvaluates to approximately 0.3660254037844386.
−13 and a number 18 units to the right of −13"
tell me the equation?
Answers
If it is a regular equation then it will look like, : -13 + [(-13) + 18].
I hope this helps!
3 times as much as the sum of 3/4 and 2/6
Answers
The result of 3 times as much as the sum of 3/4 and 2/6 is; 13/4
Fraction and ArithmeticsFirst, we must evaluate the sum of 3/4 and 2/6; we have;
3/4 + 2/6Using the lowest common multiple; 12
We have; (9 +4)/12 = 13/12.
Therefore, 3 times 13/12 = 39/12 = 13/4
Read more on fraction addition;
https://brainly.com/question/11562149
What percentage of the rectangular sheets of cardboard will be wasted because it is not part of the box and will be discarded when the net is cut out?
PLEASE HELP
Dimension : 18 x 24 x 12 in
Answers
30% I believe because we still have those to rectangles on the side
Hope this helps :)
When the square sheet of cardboard is cut and folded to create a rectangular box with a lid, the maximum possible volume is achieved when x = 20 inches. All other values will result in a smaller volume for the box.
Here, we have,
1. Calculate the side lengths of the box and lid:
Box: 40 inches - 2x = 40 - 2x
Lid: 2x
2. Calculate the volume of the box with a lid when x = 20 inches:
Box Volume:
(40 - 2x) x (40 - 2x) x (40 - 2x) = (40 - 2*20) x (40 - 2*20) x (40 - 2*20) = (20) x (20) x (20)
= 8000 in^3
Lid Volume: 2x x 2x x 2x = 2*20 x 2*20 x 2*20
= 8000 in^3
Total Volume: 8000 in^3 + 8000 in^3 = 16000 in^3
3. Calculate the volume of the box with a lid when x = 20/3 inches:
Box Volume: (40 - 2x) x (40 - 2x) x (40 - 2x) = (40 - 2*20/3) x (40 - 2*20/3) x (40 - 2*20/3) = (33 1/3) x (33 1/3) x (33 1/3)
= 7157.7 in^3
Lid Volume: 2x x 2x x 2x = 2*20/3 x 2*20/3 x 2*20/3
= 1365.3 in^3
Total Volume: 7157.7 in^3 + 1365.3 in^3
= 8523 in^3
4. Comparison:
When x = 20 inches, the box has a minimum possible volume of 16000 in^3, while when x = 20/3 inches, the box has a volume of 8523 in^3. Therefore, the statement is true.
Learn more about volume here
brainly.com/question/16134180
#SPJ2
Complete question:
The figure above represents a square sheet of cardboard with side length 40 inches. The sheet is cut and pieces are discarded. When the cardboard is folded, it becomes a rectangular box with a lid. The pattern for the rectangular box with a lid is shaded in the figure. Four squares with side length xx and two rectangular regions are discarded from the cardboard. Which of the following statements is true? (The volume V of a rectangular box is given by V=lwh).
A. When x = 20 inches, the box has a minimum possible volume.
B. When x = 20 inches, the box has a maximum possible volume.
C. When x = 20/3 inches, the box has a minimum possible volume.
D. When x = 20/3 inches, the box has a maximum possible volume.
solve for x 19-24. find the measure of the angle indicated in bold for 25-28.
Answers
angle (21x+6) is equal angle 90°-----> by alternate exterior angles
so
21x+6=90--------> 21x=84----------> x=4°
the answer N 19) is 4 degrees
N 20)
angle 75 is equal angle 11x-2-----> by corresponding angles
so
11x-2=75-----> 11x=77--------> x=7°
the answer N 20) is x=7 degrees
N 21)
angle 60 is equal angle (8x-4)------> by alternate interior angles
so
8x-4=60-----> 8x=64--------> x=64/8-----> x=8°
the answer N 21) is x=8 degrees
N 22)
angle (x+139) is equal to angle 132-----> by alternate interior angles
so
x+139=132-------> x=132-139--------> x=-7 °
the answer N 22) is x=-7 degrees
N 23)
angle (-1+14x) is equal to angle (12x+17)----> by alternate exterior angles
so
-1+14x=12x+17------> 14x-12x=17+1----> 2x=18----> x=9
the answer N 23) is x=9 degrees
N 24)
angle (23x-5) is equal to angle (21x+5)----> by corresponding angles
so
23x-5=21x+5-----> 23x-21x=5+5-----> 2x=10-----> x=5
the answer N 24) is x=5 degrees
N 25)
angle (x+96) and angle (x+96)-------> are supplementary angles
so
x+96+x+96=180--------->2x+192=180------> x=-6°
the angle indicated in bold is (-6+96)=90°
N 26)
angle (20x+5) and angle (24x-1)-------> are supplementary angles
so
20x+5+24x-1=180------> 44x=176-----> x=4°
the angle indicated in bold is (20*4+5)=85°
N 27)
angle (6x) is equal to angle (5x+10)--------> by corresponding angles
so
6x=5x+10------> 6x-5x=10------> x=10
the angle indicated in bold is (6*10)=60°
N 28)
angle (x+109) and angle (x+89) are supplementary angles
so
x+109+x+89=180----> 2x=-18-------> x=-9
the angle indicated in bold is (x+89)----> -9+89=80°
To solve for x in 19-24, x = -5. For the angle measurement in question for 25-28, more information is needed.
Explanation:To solve for x in 19-24, we subtract 24 from 19, which gives us x = -5.
Regarding the measurement of the angle indicated in bold for 25-28, the provided options (a, b, c) seem to be unrelated to this question. Could you please provide more information or clarify your query?
the largest doll is 12 inches tall. The height of each of the other dolls is 7/10 the height of the next larger doll. Write an expression for the height of the smallest doll. What is the height of the smallest doll?
Answers
Final answer:
The height of the smallest doll in a sequence is 4.116 inches found using the formula based on geometric progression, with each smaller doll having a height of 7/10 the height of the next larger one, starting from the largest at 12 inches.
Explanation:
To find the height of the smallest doll, we use a geometric sequence formula height of smallest doll = height of largest doll × (7/10)^n, with 'n' being the number of dolls smaller than the largest one.
To solve for a specific number of dolls, we'd need the value of 'n'. However, without knowing the total number of dolls in the sequence, we use the given formula to understand the pattern of the dolls' heights.
For illustrative purposes, if there were 3 dolls smaller than the largest, the height of the smallest doll would be 12 × (7/10)^3 = 12 × 0.343 = 4.116 inches. The exact height for the smallest doll would vary based on the total number of dolls in the set.
PLEASE HELP ***What is the length of AC??? Please help me understand how to find this
Answers
AC and CE have the same ratio as BA and DE. So you can get the answer by getting their proportions.
84 = 7
156-x x
Cross multiply, transpose, and simplify to get the variable x.
84x = 1092-7x
84x + 7x = 1092
91x = 1092
x = 12
To get AC, substitute.
AC = 156 - x
AC = 156 - 12
AC = 144
Determine whether the given equation has one solution, no solution, or infinitely many solutions. x+4/4=x+3/3
A. one solution
B. no solution
C. infinitely many solutions
D. cannot be determined
Please explain what you did to get the answer (it'll help me learn better)
Answers
Check the attachment.
Hope it helps you :)
Answer:
There can be only one solution
Step-by-step explanation:
The only soution is zero, because anything else is unequal.