Answer:
The electromagnetic wave that travels the fastest through space is gamma ray
Explanation:
Electromagnetic wave is a type of wave which does not require material medium for its propagation. Examples of electromagnetic waves according to increasing frequency of the waves are gamma ray, x-ray, ultra violet ray, infra red, visible light, micro wave and radio waves.
Frequency of a wave is inversely proportional to period of oscillation of the wave. The higher the frequency of a wave, the shorter the period of oscillation. Gamma ray has the highest wave frequency in electromagnetic spectrum and shorter period of oscillation, thereby causing it to have the highest penetration power.
Urgent! Based on the diagram below, what color will each pigmented paper appear to be to an observer?
Examples A and B will both appear blue.
Examples A and B will both appear green.
Example A will appear greenish-blue, while Example B will appear green.
Example A will appear green, while Example B will appear greenish-blue.
Answer:
Example A will appear green, while Example B will appear greenish-blue.
Explanation:
The color of an object depend on which part of the visible light it reflects towards the observer. Visible light is made up of seven colors: Violet, Indigo, Blue, Green, Yellow, Orange, and Red (VIBGYOR). If all the colors will be reflected object will appear white. If all the colors are absorbed the object appears black. In example A, only green color is being reflected so it will appear Green.
In example B, green and blue are being reflected so the object will appear a mix of green and blue. This color is cyan (greenish blue).
_______ or radioactive substance have a half life.
Radioactive substances have a half-life.
Radioactive substances are characterized by their unstable atomic nuclei. These nuclei undergo a process called radioactive decay over time, transforming into more stable nuclei by emitting particles and energy. This process occurs randomly at the level of individual atoms, making it impossible to predict exactly when a particular atom will decay.
The concept of a "half-life" is crucial in understanding the behavior of radioactive substances. The half-life is the time it takes for half of the radioactive nuclei in a sample to decay. It's a fundamental property of each radioactive isotope and varies widely from one isotope to another. Some isotopes have very short half-lives, measured in fractions of a second, while others have half-lives measured in millions of years.
The half-life allows scientists to quantitatively describe the rate of radioactive decay. It provides a useful tool for various applications, including dating geological samples (e.g., carbon-14 dating for archaeological purposes), understanding the behavior of radioactive materials in nuclear reactors, and determining the safety and handling of radioactive substances in medical and industrial settings.
In summary, radioactive substances are characterized by their propensity to undergo radioactive decay, and the concept of half-life is a fundamental aspect of their behavior. It quantifies the rate of decay and is essential for a wide range of scientific and practical applications.
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The half-life of a radioactive substance is the time it takes for half of it to decay. The remaining amount of substance can be calculated by dividing the initial amount by two for each half-life that elapses.
Define Half-Life
The half-life of a radioactive substance is the length of time required for half of the radioactive nuclei in a sample to undergo decay. This is a characteristic property of each radioactive isotope. After one half-life, the amount of the original substance is reduced by half. Thus, after an integer number (n) of half-lives, the amount remaining can be found by dividing the initial amount by 2n.
Determine the Amount of Radioactive Substance Remaining
For example, if you start with 5 grams of a radioactive isotope and one half-life passes, you would have 2.5 grams remaining. If another half-life passes, you divide that amount by two again, leaving you with 1.25 grams, and so on for each subsequent half-life.
Considering the example provided in the prompt, if substance A has a half-life of 4.2 days and your initial amount is 5 grams, after one half-life (4.2 days), you would have 2.5 grams remaining. Similarly, substance B with a half-life of 310 days would still be 5 grams after the same period, as the number of elapsed half-lives would be much less than one.
rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind tunnel. The freestream velocity is 40 m/s. The density of the air is 1.2250 kg/m3, and the absolute viscosity is 1.7894 x 10-5 kg/m s. Plot (not sketch) the velocity profiles at x = 0.0 m, x = 0.05 m, x = 0.10 m, and x = 0.20 m. Calculate the chordwise distribution of the skin friction coefficient and the displacement thickness. What is the drag coefficient for the plate? Be sure to account for both sides of the plate. Ans.: CD = 3.587 x 10
Answer:
See explaination for the details of the answer.
Explanation:
Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density An object with little matter in the same amount of volume has a low density. Density is found by dividing the mass of an object by its volume.
The Calculate of the chordwise distribution of the skin friction coefficient and the displacement thickness is done and represented in the attachment.
Please kindly check attachment for the step by step answer.
What percentage of a radioactive substance remains after 7.00 half-lives have elapsed?
Answer:
Explanation:
We want to know the percentage of the radio active element after 7half life
Let assume the original mass or quantity of the radioactive element is No
After first half life it remains No/2
Second half life No/4
Third half life No/8
Fourth half life No/16
Fifth half life No/32
Sixth half life No/64
Seventh half life No/128
So after the seventh half life the radioactive element has decay to No/128
Then, the that remain is
The remaining amount / Original amount × 100
%remain = (No/128 / No) × 100
No cancel No
%remain = 100/128
%remain = 0.78%
Person a pushes a box on wheeled to the left with a force of 10,000 Newton's .Person b and friction from the floor exerts a net force of 9,990n force to the right how does the box move and why
The box will be pushed by Person A and so the box will move with magnitude of 10 N force and in left direction.
Explanation:
So in the present problem, three forces are acting on the box. The force exerted by Person A on the box is represented as F₁ and it is given as 10000 N. Similarly, the net force exerted by Person B and friction on the box is given as 9990 N and it is represented as F₂. Since, F₁ is acting toward left side and F₂ is acting toward right side, both the force will be acting opposite to each other. Then the net force of all the three force acting on it will be the difference between F₁ and F₂ and the box will move towards the direction of maximum force.
[tex]Net force = 10000-9990 = 10 N[/tex]
Thus, the magnitude of the net force acting on the box will be 10 N and as the force exerted by Person A on the box is greater than the combined force of Person B and friction, the box will move towards left side as exerted by Person A.
So the box will be pushed by Person A and so the box will move with magnitude of 10 N force and in left direction.
You illuminate a slit with a width of 0.0537 mm with a light of wavelength 719 nm and observe the resulting diffraction pattern on a screen that is situated 2.77 m from the slit. What is the width, in centimeters, of the pattern's central maximum?
Answer:
Width of central maximum will be [tex]7.423\times 10^{-12}m[/tex]
Explanation:
We have given width of the slit [tex]D =0.0537mm=5.37\times 10^{-5}m[/tex]
Wavelength of light [tex]\lambda =719nm=719\times 10^{-9}m[/tex]
Distance of screen from slit D = 2.77 m
Angle to first minimum [tex]sin\Theta =\frac{\lambda }{d}=\frac{719\times 10^{-19}}{0.0537\times 10^{-3}}=1.34\times 10^{-12}[/tex]
So width of the central maximum
w= [tex]2y=2\times Dsin\Theta =2\times 2.77\times 1.34\times 10^{-12}=7.423\times 10^{-12}m[/tex]
So width of central maximum will be [tex]7.423\times 10^{-12}m[/tex]
2. El sonido de una ballena es en especial de frecuencia baja, pero existe una especie de ballena la Whalien cuya frecuencia es de 52 Hz, si la velocidad de propagación de la onda es de 1400m/s ¿Cuál será su periodo en el agua y el aire? Y ¿Cuál será la longitud de onda en cada medio? Recuerda que la velocidad de propagación en el aire es 340m/s
Answer:
The sound of a whale is especially low frequency, but there is a species of whale the Whalien whose frequency is 52 Hz, if the propagation speed of the wave is 1400m / s What will be its period in the water and the air? And what will be the wavelength in each medium? Remember that the propagation speed in air is 340m / s
Explanation:
From wave equation, the speed, wavelength and frequency is related using
V = fλ
Where
V is the speed
f is the frequency
And λ is the wavelength
So,
The frequency of the whale is
f = 52Hz
The speed in water is V_w = 1400m/s
The speed in air is V_a = 340m/s
We want to find the period in each medium, the period is related to the frequency and since the frequency is constant.
Then, period in equal in both medium
T = 1 / f
T_w = T_a = 1 / f
T = 1 / 52
T = 0.0192 seconds
We want to find the wavelength in each medium
For water,
V = fλ
V_w = f × λ_w
Then,
λ_w = V_w / f.
λ_w = 1400 / 52 = 26.92 m
The wavelength in water is 26.92m
Now, in air
V = fλ
V_a = f × λ_a
Then,
λ_a = V_a / f.
λ_a = 340 / 52 = 6.54 m
The wavelength in air is 6.54 m
In Spanish
De la ecuación de onda, la velocidad, la longitud de onda y la frecuencia se relacionan usando
V = fλ
Dónde
V es la velocidad
f es la frecuencia
Y λ es la longitud de onda
Entonces,
La frecuencia de la ballena es
f = 52Hz
La velocidad en el agua es V_w = 1400m / s
La velocidad en el aire es V_a = 340m / s
Queremos encontrar el período en cada medio, el período está relacionado con la frecuencia y dado que la frecuencia es constante.
Luego, período igual en ambos medios
T = 1 / f
T_w = T_a = 1 / f
T = 1/52
T = 0.0192 segundos
Queremos encontrar la longitud de onda en cada medio
Para agua,
V = fλ
V_w = f × λ_w
Entonces,
λ_w = V_w / f.
λ_w = 1400/52 = 26,92 m
La longitud de onda en el agua es de 26,92 m.
Ahora en el aire
V = fλ
V_a = f × λ_a
Entonces,
λ_a = V_a / f.
λ_a = 340/52 = 6,54 m
La longitud de onda en el aire es de 6.54 m.
Which of the following statements about energy is true?
1 Kinetic energy cannot be transformed into another type of energy.
II. Kinetic energy can be transformed into potential energy.
III. Potential energy can be transformed into kinetic energy
IV. Potential energy cannot be transformed into another type of energy
Answer:ll. Kinetic energy can be transformed into Potential energy.
And, lll. Potential energy can be transformed into Kinetic energy
Final answer:
Statements II and III are true as they describe the mutual transformation between kinetic and potential energy. Kinetic energy can be converted to potential energy and vice versa, which is a fundamental concept in physics describing energy dynamics.
Explanation:
When discussing energy, it's important to distinguish between kinetic energy and potential energy. Kinetic energy is the energy of motion, exemplified by a rolling ball or flowing water. Potential energy, on the other hand, is the energy stored due to an object's position, such as a book on a shelf or water behind a dam.
Contrary to statement I, kinetic energy can indeed be transformed into other types of energy. An easy-to-understand example is a pendulum. As it swings, its kinetic energy at the lowest point is transformed into potential energy as it rises. When it stops at the highest point, all the kinetic energy has been converted into potential energy. This validates statement II that kinetic energy can be transformed into potential energy.
Similarly, statement III is true: potential energy can be transformed into kinetic energy. This is seen when the pendulum begins its swing downward, with the potential energy converting back into kinetic energy due to gravity's pull.
Finally, statement IV is false because potential energy can be transformed into other types of energy. The potential energy of water behind a dam can be transformed into kinetic energy as the water falls and then into electrical energy through a generator.
Therefore, statements II and III accurately describe the transformation of energy, illustrating that energy is not static and can be converted from one form to another, including potential and kinetic energy.
Choose the statement that is a misconception about a system in chemical equilibrium.
The rate of the forward reaction is equal to the rate of the backward reaction.
The concentrations of the products and reactants don't change.
There are equal parts reactants and products.
Reactions continue to happen in both directions.
Answer:
There are equal parts reactants and products.
Explanation:
When a system is in a chemical equilibrium, the rate at which the forward reaction occur is the same as the rate at which the reverse reaction occurs. This system is said to undergo a reversible reaction. The concentration of the reactants and products do not change, i.e are constant.
In a chemical equilibrium, the reaction continues in both directions but at the same rate.
Therefore the statement that is a misconception about a system in chemical equilibrium is 'There are equal parts reactants and products'.
Answer:
C
Explanation:
i just took the quiz and went over my answers its C
The heat that builds up in the greenhouse effect initially enters the atmosphere as
Answer:
Solar radiation
Explanation:
Gases such as methane , ozone, and Carbon dioxide are known as the greenhouse gases. When the gases are heated up they usually build up in the greenhouse effect and after a while they enter the atmosphere as solar radiation.
It is important to note that the release of the gases is usually the first(initial) release of the gases into the atmosphere.
Answer:
infrared radiation within the sun's radiation.
Explanation:
The solar radiation that gets to earth contains about 3 electromagnetic waves which includes visible rays, infrared rays, ultraviolet rays. Infrared rays carries heat through space and is the part of the solar radiation that carries heat into the earth's atmosphere.
An object is placed at a known distance in front of a mirror whose focal length is also known. You apply the mirror equation and find that the image distance is a negative number. This result tells you that __________
Answer:
the image is behind the mirror, so the image is virtual and upright.
Explanation:
If the speed of an object doubles, its kinetic energy
What is occurring when two waves traveling along the same medium meet and cancel each other out?
Answer:
Destructive interference
Explanation:
Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.
Answer:
Destructive interference
Explanation:
Destructive interference occurs when waves come together in such a way that they completely cancel each other out. When two waves interfere destructively, they must have the same amplitude in opposite directions.
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What physical improvements might result from his training?
Answer:
He may experience increased metabolism, better weight management, and increased muscle strength and mass.
Explanation:
A 2.50 kg fireworks shell is fired straight up from a mortar and reaches a height of 110.0 m. a) Neglecting air resistance (a poor assumption, but we will make it for this example), calculate the shell’s velocity when it leaves the mortar. b) The mortar itself is a tube 0.450 m long. Calculate the average acceleration of the shell in the tube as it goes from zero to the velocity found in a). c) What is the average force on the shell in the mortar? Express your answer in newtons and as a ratio to the weight of the shell.
Answer:
A) 46.43 m/s
B) Acceleration = 2395.27 m/s²
C) Average force in Newton's = 5988.18 N
Ratio of this force to weight = 244.14
Explanation:
We are given that;
Mass; m = 2.5 kg
Height reached by firework; y = 110m
Length of tube;L = 0.45m
A) According to kinematic equation;
v² = u² + 2gs
In this case, v = 0 and because gravity is acting against motion. Thus,
0 = u² - 2gy
u² = 2gy
u = √2gy
Plugging in the relevant values ;
u = √(2 x 9.8 x 110)
u = √2156
u = 46.43 m/s
B) we want to find the acceleration with u = 0 m/s and v = 46.43 m/s in the tube. The tube length is 0.45m
Thus,
v² = u² + 2aL
46.43² = 0 + (2•a•0.45)
2155.7449 = 0.9a
acceleration, a = 2155.7449/0.9 = 2395.27 m/s²
C) From Newton's law of motion,
Average Force; F = ma
Thus, F = 2.5 x 2395.27 = 5988.18 N
We are told to express it as a ratio to the weight of the shell.
Thus, ratio = F/W
Weight = mg and force = ma
Thus, F/W = ma/mg = a/g = 2395.27/9.8 = 244.42
Answer:
a) the initial velocity ot the firework shell is 46.5m/s
b) the average acceleration of the shell in the tube is 2.4 × 10³m/s²
c) the average force on the shell in the tube is 2.4 × 10³m/s²
the ratio of the average force acting on the shell to the weight of the shell is 244.65 : 1
Explanation:
Given that;
Mass, m = 2.5 kg
Height, h = 110m
Length , L = 0.45m
The expression of the relationship between velocity and distance kinematic law of motion
[tex]v^2 = u^2 - 2gh[/tex]
[tex]u = \sqrt{v^2+2gh}[/tex]
At maximum height the velocity of the firework shell is zero
That is why the final velocity of the firework shell is zero
[tex]u = \sqrt{2gh}[/tex]
[tex]u = \sqrt{2\times 9.81 \times 110} \\\\u = 46.5m/s[/tex]
Hence, the initial velocity ot the firework shell is 46.5m/s
b)
[tex]v^2 = u^2 + 2as[/tex]
[tex]a = \frac{v^2 - u^2}{2s}[/tex]
The initial velocity of the shell in the tube is zero
[tex]a = \frac{v^2}{2s} \\[/tex]
substitute 46.5m/s for v and 0.450 for s
[tex]a = \frac{46.5^2}{2\times 0.450} \\\\a = 2.4 \times 10 ^3m/s^2[/tex]
Hence , the average acceleration of the shell in the tube is 2.4 × 10³m/s²
c)
From Newton's law of motion,
Average Force, F = ma
substitute 2.50kg for m and 2.4 × 10³m/s² for a
F = ( 2.50kg )(2.4 × 10³m/s²)
F = 6 × 10³N
Hence, the average force on the shell in the tube is 2.4 × 10³m/s²
Calculate the weight of the shell
W = mg
substitute 2.50kg for m and 9.81m/s² for g
W = (2.50kg)( 9.81m/s²)
W = 24.525N
Calculate the ratio of the average force acting on the shell in the tube to the weight of the shell
[tex]Ratio = \frac{F}{W}[/tex]
substitute 24.525N for W and 6 × 10³N for F
[tex]Ratio = \frac{6 \times 10^3N}{24.525N} \\\\= 244.65[/tex]
Hence , the ratio of the average force acting on the shell to the weight of the shell is 244.65 : 1
The internal energy of a system is always increased by ________.
Answer:
The options are
A) adding heat to the system
B) having the system do work on the surroundings
C) withdrawing heat from the system
D) adding heat to the system and having the system do work on the surroundings
E) a volume compression
The answer is
A) adding heat to the system
Explanation:
It is important to note that increase in temperature will result in the collision of more particles thereby resulting in a corresponding increase in the internal energy of the system.
The relationship between temperature and internal energy is a direct one. As temperature increases, internal energy also increases and vice versa.
Answer:
Doing thermodynamic work on the system
Explanation:
The internal energy of a system can be increased by introduction of matter, by heat, or by doing thermodynamic work on the system. ... If the containing walls pass neither matter nor energy, the system is said to be isolated and its internal energy cannot change.
Internal energy is NOT all the energy in the system, it is the kinetic and potential energy associated with the random motion of the molecules of an object. If you heat an object, you will increase its internal energy. As the object cools, its internal energy will decrease.
The internal energy can be changed by changing the temperature or volume of the object without changing the amount of particles in the object. Temperature: If the temperature of a system rises, the molecules will travel quicker, therefore have more kinetic energy and so the Internal Energy will increase.
Select to show the energy of pendulum 1. Be sure that friction is set to none. Drag the pendulum to an angle (with respect to the vertical) of 30∘, and then release it. When the pendulum is at −30∘, what form(s) of energy does it have? Check all that apply. Check all that apply. Potential energy Kinetic energy Thermal energy
Answer:
The pendulum only has potential energy.
Explanation:
A pendulum is a weight that is tied to a rope and is also suspended with a pivot and that can swing freely. Said pendulum moves at an angle of 30 degrees. Then he is released. The pendulum moves with a constant amplitude. In this way, it reaches the maximum amplitude when its angle is 30 degrees. The angles mentioned in the exercise are the extremes. At each point, the total energy is conserved. Total energy is defined as the sum of the kinetic energies plus the potential energy. The kinetic energy of the pendulum is equal to zero in the extreme positions, therefore, only the total energy is equal to the potential energy.
Final answer:
At −30°, a pendulum has both potential and kinetic energy, with energy conversion governed by the conservation of mechanical energy.
Explanation:
When a pendulum is at an angle of −30°, it possesses both potential energy and kinetic energy. Potential energy is due to its height above the lowest point of the swing and kinetic energy due to its motion. In the absence of friction, no thermal energy is produced.
Using conservation of mechanical energy, we know that as the pendulum swings towards −30°, some of the potential energy is converted into kinetic energy. At the highest points in its swing (±30°), the pendulum has maximum potential energy and zero kinetic energy. When it passes through the vertical, it has maximum kinetic energy and minimum potential energy. At −30°, the pendulum is on its upward swing, thus it starts regaining potential energy and losing kinetic energy.
As the solar nebula contracts during the formation of the solar system, it Group of answer choices forms a black hole. flattens out into the ecliptic plane and spins faster due to conservation of angular momentum. reverses its direction of rotation. loses angular momentum.
During the formation of the solar system, the solar nebula contracts, spins faster due to conservation of angular momentum and flattens out into the ecliptic plane. This process doesn't result in a black hole formation or loss of angular momentum.
Explanation:In the formation of the solar system, the solar nebula contracts and, due to the conservation of angular momentum, it starts to spin faster. As it continues to contract, it begins to flatten out into what we call the ecliptic plane, an imaginary plane that passes through all the planets orbits.
This movement and transformation do not lead to the formation of a black hole or necessarily result in the loss of angular momentum. Rather, the nebula maintains its angular momentum, as per the law of conservation, and this aids in speeding up the rotation as the nebula gets smaller. This is very similar to what happens when a figure skater pulls their arms in while spinning, they go faster but their angular momentum remains constant.
These processes—gravity-induced contraction, increase in rotation speed, and flattening into the ecliptic plane—are integral steps in our understanding of how our solar system came into existence.
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During the formation of the solar system, the solar nebula contracts, flattens into the ecliptic plane and spins faster. This is due to the conservation of angular momentum. The material is concentrated in the center, forming a star, with the remaining materials eventually becoming planets and moons.
Explanation:As the solar nebula contracts during the formation of the solar system, it flattens out into the ecliptic plane and spins faster due to conservation of angular momentum. This process starts when a large cloud of gas and dust, which originally had rotational energy, begins to contract under its own gravity. The natural motion and turbulence of the material lead to an initial spinning motion.
As the nebula shrinks, the rotation causes it to flatten into a disk-like shape. This can be compared to a figure skater spinning more rapidly by bringing her arms in closer to her body, which minimizes her rotational radius and conserves angular momentum. Similarly, as the nebula contracts and its rotational radius decreases, it spins faster.
A majority of the matter becomes concentrated in the hot center, eventually leading to the formation of a star. The remainder of the material, consisting of solid particles which condense as the nebula cools, forms the planetesimals - the building blocks of the planets and moons.
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Which statement correctly compares sound and Electromagnetic waves?
A. Both EM and sound waves need matter to carry energy from one place to another.
B. Neither EM nor sound waves need matter to carry energy from one place to another.
C. EM waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it
D. Sound waves carry energy parallel to the motion of the wave, while EM waves carry energy perpendicular to it.
Answer: D
D. Sound waves carry energy parallel to the motion of the wave, while EM waves carry energy perpendicular to it.
Explanation:
Sound is a longitudinal wave in which the displacement of the medium is in the same direction as, or the opposite direction to, the direction of propagation of the wave
While electromagnetic wave are transverse wave. A moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation. So the correct answer is D. Sound waves carry energy parallel to the motion of the wave, while EM waves carry energy perpendicular to it
A block of mass 500 g is attached to a horizontal spring, whose force constant is 25.0 N/m . The block is undergoing simple harmonic motion with an amplitude of 6.00 cm . At t=0 the block is 4.00 cm to the left of its equilibrium position and is moving to the right. At what time t1 will it first reach the limit of its motion to the right?
Answer:
t = 0.325343 sec
Explanation:
given
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
we know simple harmonic motion equation as
y = A sin (ωt + Φ)
where Φ = [tex]sin^{-1} (-4/6)[/tex]
so we get
Φ = - 0.729727656 rad
and we know
[tex]\omega = \sqrt{\frac{k}{m}[/tex]
[tex]y = A sin (t\sqrt\frac{k}{m} - 0.729727656)[/tex]
now substitute the values we get as
y = 0.06 m
[tex]0.06 = 0.06 sin (t\sqrt(\frac{25}{0.5}) - 0.729727656)[/tex]
[tex](t\frac{25}{0.5} - 0.729727656) = \frac{\pi}{2}[/tex]
on solving these equation we get
t = 0.325343 sec
The time where t1 will it first reach the limit of its motion to the right is 0.325343 sec.
Calculation of the time taken:Since
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
Here we apply the harmonic motion equation i.e.
y = A sin (ωt + Φ)
where Φ = sin^-(-4/6)
Φ = - 0.729727656 rad
Now
w = √k/m
y = Asin (t√k/m - 0.729727656)
y = 0.06m
Now
(t2.5/0.5 - 0.729727656) = π/2
t = 0.325343 sec
Hence, The time where t1 will it first reach the limit of its motion to the right is 0.325343 sec.
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A ball is pushed from a stop and rolls 6 m in 2 s. Student A says the average speed of the ball is 3 m/s. Student B says the average speed of the ball is 1.5 m/s2. Which student is correct? Explain your answer.
Answer:
Student A is correct
Explanation:
This is because by student A's recording, we get the average speed = total distance/total time = 6 m/2 s = 3 m/s. Student B recorded an average speed of 1.5 m/s². This cannot be correct because it is in the unit of acceleration.
Student A is correct; the average speed of the ball is 3 m/s. Student B's 1.5 m/s² refers to acceleration, not speed.
The average speed of an object is calculated by dividing the total distance traveled by the total time taken.
In this case, the ball rolls 6 meters in 2 seconds.
Average Speed Calculation
Total distance traveled: 6 metersTotal time taken: 2 secondsAverage speed = Total distance / Total time = 6 meters / 2 seconds = 3 m/sStudent A is correct. The average speed of the ball is 3 m/s. Student B's statement about 1.5 m/s² is incorrect because it refers to acceleration, not speed.
Have you ever ridden the swing ride at an amusement park? If so you know that the swings are attached to a circular mount in 2-3 rows. As the ride begins the swings rise up and swing outward. What would decrease the speed of the swing's circular motion?
Final answer:
The speed of a swing's circular motion in an amusement ride can be decreased by increasing air resistance, reducing the propelling force, altering the angle of the swing's support, or increasing the swing's mass without an increase in force.
Explanation:
The speed of a swing's circular motion in an amusement park ride can be decreased through various means. One way that the speed of the swing's circular motion can be reduced is by increasing the air resistance acting against the swing. This can be done, for example, if the swings have a wider surface area or if flaps are added that catch more wind. In addition, reducing the force that propels the swing can also decrease speed. On most rides, this would involve slowing down the motor or mechanism that is causing the ride to spin. This reduction in propelling force would result in a decreased centripetal force on the swings, thus reducing their speed.
Another factor that could decrease the speed of the swing's circular motion is the angle of the supporting chains or rods. If they are designed to hang more vertically rather than being allowed to tilt outwards, the centripetal acceleration required to keep the ride moving in a circle would decrease, resulting in a slower rotation speed of the swings. Lastly, an increase in the mass of the swings without an increase in the propelling force would also result in slower speeds due to the greater inertia that needs to be overcome to maintain the circular motion.
What is referred to as reflectivity of surfaces?
Answer:
Reflectance of the surface of a material is its effectiveness in reflecting radiant energy.
Explanation:
It is the fraction of incident electromagnetic power that is reflected at an interface. The reflectance spectrum or spectral reflectance curve is the plot of the reflectance as a function of wavelength.
What force would be required to accelerate a 1,100kg car to 0.5 m/s2
Answer:
the force required to accelerate a 1,100kg car is 550N
What happens to a light wave when it travels from air into glass?
Describe how the solar radiation that arrives at the equator is redistributed around the earth through atmospheric circulation.
The energy that reaches the Earth's equator is redistributed through air currents and ocean currents.
Atmospheric circulation is a term used in geography to refer to the movement of air on a large scale that serves as the distribution of solar heat on the surface of the Earth.
As a result of the latitudinal circulation, the solar radiation (that affects the low equatorial latitudes) uses air currents, differences in atmospheric pressure and water currents to distribute itself throughout the Earth's atmosphere.
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Solar radiation at the Earth's equator is converted into thermal radiation that is redistributed by the atmosphere and oceans, in a process known as atmospheric circulation. This energy transfer is facilitated by convection currents within the atmosphere and is influenced by Earth's rotation. Some of this reradiated heat is trapped by greenhouse gases, contributing to the greenhouse effect.
Explanation:The solar radiation arriving at the Earth's equator is redistributed around the globe through a process known as atmospheric circulation. This circulation is crucial for weather patterns and global climate phenomena. Here's a step-by-step breakdown:
Solar Radiations: The Earth receives almost all its energy from the Sun's radiation, which is more intense at the equator due to the direct incidence of sunlight. Heat Redistribution: These solar radiations are converted into thermal radiation on Earth's surface, some of which is reradiated back into the atmosphere. The atmosphere and oceans play a crucial role in redistributing this heat from warmer to cooler areas. They essentially transport heat energy from the equator towards the poles, maintaining a balance. Atmospheric Circulation: Within the atmosphere, deep convection currents of rising hot air (near the equator) and falling cooler air (closer to the poles) help circulate this energy. Such motions are influenced by Earth's rotation, leading to patterns of atmospheric circulation. Greenhouse Effect: Some of the infrared or heat radiation emitted from Earth's surface gets trapped by greenhouse gases (e.g., water vapor, methane, and CO2) in the atmosphere, leading to a warmer planet. This is known as the greenhouse effect.Learn more about Atmospheric Circulation here:
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A ray diagram is shown.
Which letter represents the location of the image produced by the lens?
W
X
Y
Z
Answer:
Z
Explanation:
The purple and yellow rays from the same point on the object are shown converging at point Z, where the image will be.
Answer:
Z
Explanation:
got it right on edge
The graph shows the accumulation of stable atoms during the decay of a radioactive substance. Why does the graph approach the horizontal line y = 100?
Answer:
The decay process started with 100 radioactive atoms.Eventually all 100 atoms will decay to a stable form. The graph approaches 100 because that is the maximum number of stable atoms that can form
Explanation:
Edge
The graph approach the horizontal line y = 100. Because the maximum number of the stable atoms is equal to 100.
What is radioactivity?The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.
Radiation is being employed to assist humanity in medical, academia, and industry, as well as to generate power.
From the graph, it is observed that the as the stable atom is increasing, the half life is increasing. But at a point of time the at the value of the half life equal to 6 the no of stable atoms reached to 100.
The graph approach the horizontal line y = 100. Because the maximum number of the stable atoms is equal to 100.
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Calculate the mechanical advantage of a lever that has an input force of 15 N and an output force of 60 N. *
Answer:
4
Explanation:
Mechanical Advantage is given as a ratio of the force a machines gives out to the force that it receives.
Simply put, it is the ratio of output force to input force:
[tex]MA = \frac{OF}{IF}[/tex]
We are given that:
OF = 60 N
IF = 15 N
Hence, the Mechanical Advantage of the lever is:
[tex]MA = \frac{60}{15} \\\\\\MA = 4[/tex]
It is a ratio so it has no unit.
Answer:
Explanation:
Given that, .
Input effort is 15N
Fi = 15N
Output effort is 60N
Fo = 60N
Then,
Mechanical advantage(M•A) is the ratio of two forces, and it is also referred to has force ratio.
M•A = Output Force / Input Force
M•A = Fo / Fi
M•A = 60 / 15
M•A = 4
The mechanical advantage is 4
Why are the arms of spiral galaxies typically blue in color?
Answer:
Stars are forming in the spiral arms so there are high mass, hot, blue stars in the arms.
Explanation: