Why do elements in groups share more chemical properties than elements in a period

The business practice of hiring workers in another country is known as outsourcing.

Outsourcing is a business practice of hiring worker from outside country. This practice is done with the aim getting cheap labour force, or getting efficient labour force.

This business practice (outsourcing) can also be seen as transferring of employees and assets from one firm to another.

Thus, the business practice of hiring workers in another country is known as outsourcing.

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The business practice of hiring workers in another country is known as outsourcing. Hence, option D is correct.

Outsourcing is the business practice of hiring a party to perform services and goods. It results in the globalization of markets and it drives maximum profits.

It is also defined as a company hiring a third party or a company to perform their task and to provide service for the company. Examples of outsourcing are advertising, website development, etc.

Outsourcing can help to reduce labor costs and enable them to work for less money. It helps the company to focus on the core aspects of the business. The outsourcing process leads to running a successful business model.

Outsourcing has the biggest advantage in time and money savings. Adapting outsourcing helps in gaining profit, increasing efficiency, and can control costs.

Hence, the business practice of hiring workers in another country is known as outsourcing. Thus, the correct option is D.

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Final answer:

Copper has the lowest resistance among the given materials.

Explanation:

Copper has the lowest resistance among the given materials: copper, wood, and plastic.

In a series circuit, the total resistance is the sum of individual resistances. The circuit element with the lowest resistance would contribute the least to the overall resistance.

In a parallel circuit, the total resistance is less than the smallest individual resistance due to the combined effect of multiple paths for current flow.

It's important to note that resistance in most materials increases with temperature. So, achieving the lowest possible resistance often involves using superconducting materials at extremely low temperatures or selecting materials with inherently low resistance characteristics for specific applications.

Answer:

It has only 1 electron in its valence shell and if that electron is removed it will acquire noble gas configuration

Explanation:

Sodium forms an ion of charge +1 as in its ionic state it has inert gas configuration

It forms an ion of charge +1 when the valence shell electron is removed to gain the noble gas configuration and the electrons can be removed mostly from its valence shell because inner shell electrons will be tightly bounded to the nucleus of the atom and it requires high energy to remove the electron present in the inner shell when compared to the valence shell (outermost shell)

Answer:

True. The sun and stars look like they are moving because the earth rotates.

Answer:

The coefficient of friction between the log and the ground is, μₓ = 0.3630

Explanation:

Given data,

The skidder dragging the mass, m = 520 kg

The acceleration of the mass, a = 3.5 m/s

The force applied by the skidder, Fₓ = 1850 N

The kinetic frictional force is given by,

                       Fₓ = μₓ η

                      μₓ = Fₓ / η

Where  μₓ - the coefficient of the kinetic friction  

            η is the normal force acting on the mass due to gravitational force.

                          η = mg

                              = 520 x 9.8

                               = 5096 N

Substituting the values in the above equation,

                           μₓ = 1850 N / 5096 N

                                = 0.3630

Hence, the coefficient of friction between the log and the ground is, μₓ = 0.3630

Answer:

Newton proposed the "law of Universal Gravitation". He said that gravity is universal in nature and it affects all the objects. Gravity is present between you and every object having mass around you. The "Strength of the gravity" between two objects with mass is depends on the product of masses and distance between the objects.

The "Gravitational force" increases with the increase in mass of the objects and decreases with the increase in distance between the objects. The gravity exerts a force on every object. The direction of force of gravity is towards the centre of the Earth.  

Answer:

The correct answer to this question is D) Density

EXPLANATION:

From Newton's second laws of motion, we know that the external force acting on a body is equal to the product of mass with the acceleration of the body.

Mathematically Force F = m × a

Here, m is the  mass of the body.

         a is the acceleration of the body.

Hence, it is the force which is responsible for creating acceleration in an object.

In the given question, we have four factors i.e wind, friction, gravity and density.

Out of the four options, wind, friction and gravity can exert force on an object and can create acceleration in it.

The density of a body is defined as the mass of that body per unit volume.

Mathematically it is written as -

                           Density d = \frac{m}{v} where v is the volume occupied by the body.

Hence, density will not be responsible for the acceleration of the body.

Answer: Your answer is option D: density

the wind can move objects depending on how strong it is and how small the object is.

Gravity pulls things towards the earth which will move it.

you needs movement to cause friction and friction causes heat which causes movement

but density has to do with the object itself not with movement.

Explanation:

When two mechanical waves that have positive displacements from the equilibrium position meet and coincide, a constructive interference occurs.

Option A

Considering the principle of superposition of waves; the resultant amplitude of an output wave due to interference of two or more waves at any point is given by individual addition of their amplitudes at that point. Two waves with positive displacements refer to the fact that crest of the both the waves are on the same side of displacement axis, either both are positive or both are negative, similarly with their troughs.

If such two waves with their crest on crest meet at any point, by superposition principle. their individual amplitude gets added up and hence the resultant wave after interference is greater in amplitude that both the individual waves. This is termed as a constructive interference. Destructive interference on the other hand is a condition when one of the two waves has a positive displacement and other has a negative displacement (a condition of one’s crest on other’s trough); resulting in amplitude subtraction.

The only scalar quantity is a. 35 m

Explanation:

In physics, there are two types of quantities:

- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:

Speed

Energy

Distance

Time

- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:

Velocity

Force

Acceleration

Displacement

Let's now analyze each given option, to evaluate if it is a scalar or a vector:

a. 35m  --> it is only a unit (no direction), so it is a scalar

b. 20 m to the right  --> it has a direction, so it is a vector

c. 30 m to the North --> it has a direction, so it is a vector

So, the only correct option is a).

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Answer:

6.7 m/s @ 116.6°

Explanation:

Use Pythagorean theorem to find the magnitude:

v² = vx² + vy²

v² = (-3 m/s)² + (6 m/s)²

v = √45 m/s

v ≈ 6.7 m/s

Use trigonometry to find the direction:

θ = atan(vy / vx)

θ = atan(6 m/s / -3 m/s)

θ = atan(-2)

θ ≈ 116.6° from the +x axis, or 63.4° north of west.

Answer:

E before = 0 J Work = 735.75 J E after= 735.75 J

Explanation:

The work that was done on the object is calculated as follows:

W = m*g*h

where m refers to the mass of the object, g to gravitational acceleration (9.81 m/(s^2)) and h to the hight that the object was raised up. Replacing with data into the equation (units are ommited):

W = 5*9.81*15

W = 735.75 J

Taking the ground as heigth = 0 m, then both potential and kinetic energy of the object before the lift was zero (notice that it was resting). Conservation energy equation states that the change of energy of an object is equal to the work applied on the object (like this case) or done by the object. That is:

ΔE = W

where ΔE = Energy after - Energy before

Therefore:

Energy after = W = 735.75 J

The potential energy after the lift is also calculated as m*g*h, so the energy after the lift is all potential energy gained by the object due to the work applied on it.

Answer:

The force on the 2.00-uC charge is [tex]36 \times 10^{10} \mathrm{N}[/tex]

Explanation:

We know that force between two charges is given by Coulomb’s law,

[tex]\mathrm{F}=\mathrm{k} \frac{q 1 q 2}{r * r}[/tex]

Where k = Coulomb’s constant =

[tex]9.0 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}[/tex]

And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges

And r = distance between the charges = 20 cm = 0.2 m  

Substituting the given values in the formula we get force applied on [tex]2.00\ \mu C[/tex] charge,

F =  [tex]36 \times 10^{10} \mathrm{N}[/tex] attractive force which is the required answer.

The force on the 2.00-uC charge is 1.8N towards the right.

Let us assume Q = -4.00μC and charge q = 2.00μC. Distance between them is r = 0cm = 0.2m

According to Coulomb's law, the electrostatic force between two charges Q and q separated by a distance r is given by:

[tex]F=k\frac{Qq}{r^2}[/tex]

where k is Coulomb's constant

[tex]F=\frac{9\times10^9\times4\times10^{-6}\times2\times10^{-6}}{0.20\times0.20} N\\\\F=1.8N[/tex]

Since we are calculating the force on the q which is positive, due to Q which is negative. The direction of the force will be towards the right since the electric field for the negative charge will be directed towards the charge, which is towards the right.

So the net force is 1.8N towards right.

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1) Angular velocity: D) 73.3 rev/s

2) Centripetal acceleration: D) [tex]5053 m/s^2[/tex]

3) Net force on the car: E) [tex]2.19\cdot 10^4 N[/tex]

4) Orbital speed: D) [tex](\frac{GM}{r})^{\frac{1}{2}}[/tex]

5) Total mechanical energy: E) [tex]-\frac{GMm}{2r}[/tex]

6) Gravitational force: C) [tex]1.32\cdot 10^{-10}N[/tex]

7) Upward force: C) 188 N

8) Total upward force at B: C) 122 N

Explanation:

1)

The relationship between centripetal acceleration and angular velocity is given by

[tex]a_c = \omega^2 r[/tex]

where:

[tex]a_c[/tex] is the centripetal acceleration

[tex]\omega[/tex] is the angular velocity

r is the radius of the circular path

In this problem,

[tex]a_c = 1950 g = 1950(9.8)=19,110 m/s^2[/tex]

r = 9 cm = 0.09 m

Solving for [tex]\omega[/tex],

[tex]\omega=\sqrt{\frac{a_c}{r}}=\sqrt{\frac{19,110}{0.09}}=460.8 rad/s[/tex]

And keeping in mind that [tex]1 rev = 2 \pi rad[/tex], we can convert into rev/s:

[tex]\omega=460.8 rad/s \cdot \frac{1}{2\pi rad/rev}=73.3 rev/s[/tex]

2)

Again, the centripetal acceleration is given by

[tex]a_c = \omega^2 r[/tex]

where in this problem we have:

[tex]\omega=16 rev/s \cdot 2\pi (rad/rev) = 100.5 rad/s[/tex] is the angular velocity of the piece of dust

r = 0.50 m is the distance of the piece of dust from the axis of rotation

And substituting into the equation, we find the centripetal acceleration of the piece of dust:

[tex]a_c = (100.53)^2(0.5)=5053 m/s^2[/tex]

3)

Since the car is moving in circular motion, the net force is equal to the centripetal force, so it is given by:

[tex]F=m\frac{v^2}{r}[/tex]

where

m = 732 kg is the mass of the car

v = 20.0 m/s is the linear speed of the car

r = 13.0 m is the radius of curvature of the loop-the-loop

Here we have

m = 732 kg

v = 20.0 m/s

r = 13.0 m

Substituting into the equation, we find:

[tex]F=(732)\frac{20.0^2}{13.0}=2.25\cdot 10^4 N[/tex]

The closest option is E) [tex]2.19\cdot 10^4 N[/tex]

4)

The gravitational force between the satellite and the Earth provides the centripetal force that keeps the satellite in circular motion, therefore we can write:

[tex]m\frac{v^2}{r}=G\frac{Mm}{r^2}[/tex]

where the term on the left is the centripetal force while the term on the right is the gravitational force, and where

m is the mass of the satellite

v is its speed

r is the orbital radius

G is the gravitational constant

M is the Earth's mass

Solving for v,

[tex]v=\sqrt{\frac{GM}{r}} = (\frac{GM}{r})^{\frac{1}{2}}[/tex]

5)

The kinetic energy of the satellite is given by

[tex]K=\frac{1}{2}mv^2[/tex]

And substituting its speed, [tex]v=\sqrt{\frac{GM}{r}}[/tex], we get

[tex]K=\frac{GMm}{2r}[/tex]

The potential energy of the satellite is equal to the work that must be done against gravity to bring the satellite from r to infinite, and it is

[tex]U=-\frac{GMm}{r}[/tex]

The total mechanical energy is equal to the sum of kinetic and potential energy:

[tex]E=K+U=\frac{GMm}{2r}+(-\frac{GMm}{r})=-\frac{GMm}{2r}[/tex]

6)

The gravitational force between two objects is given by

[tex]F=G\frac{m_1 m_2}{r^2}[/tex]

where

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

Here we have:

[tex]m_1 = 12 kg\\m_2 = 14 kg[/tex]

and

r = 9.22 m

Substituting,

[tex]F=(6.67\cdot 10^{-11})\frac{(12)(14)}{(9.22)^2}=1.32\cdot 10^{-10}N[/tex]

7)

To solve the problem, we can apply the equation of the equilibrium of momenta about point B:

[tex]Wx_W - F_A x_A=0[/tex]

where:

W = 300 N is the weight of the plank

[tex]x_W = 5 m[/tex] is the distance of the point of application of the weight from B (half the length of the plank)

[tex]F_A[/tex] is the upward force applied at A

[tex]x_A = 10 - 2 = 8 m[/tex] is the distance of the point of application of [tex]F_A[/tex] from B

Solving for [tex]F_A[/tex],

[tex]F_A = \frac{W x_W}{x_A}=\frac{(300)(5)}{8}=188 N[/tex]

8)

We can solve this part instead by applying the equation of equilibrium of moments around point A:

[tex]-Wx_W - W_B x_B + F_B x_{F_B} = 0[/tex]

where

W = 300 N is the weight of the plank

[tex]x_W = 5 - 2 = 3 m[/tex] is the distance of the point of application of the weight from A

[tex]W_B = 9.0 N[/tex] is the weight of the can of paint at B

[tex]x_B = 10 - 2 = 8 m[/tex] is the distance of the can of paint from A

[tex]F_B[/tex] is the upward force exerted by block B

[tex]x_{F_B}= 10 -2 = 8 m[/tex] is the distance of the point of application of [tex]F_B[/tex] from A

Solving for [tex]F_B[/tex],

[tex]F_B = \frac{W_B x_B + W x_A}{x_{F_B}}=\frac{(9)(8)+(300)(3)}{8}=122 N[/tex]

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Answer:

150 inches (12.5 ft)

Explanation:

The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.

The following is the equation one needs to solve:

[tex]10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\[/tex]

therefore solving for the distance "x" gives as the answer (in inches):

[tex]10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in[/tex]

which can also be given in feet as: 12.5 ft

Answer:

150 in"

Explanation:

Answer:

Force of attraction is 2,46*10^-8N[tex]F= G*(m1*m2/r^2)\\where \\\\G=6,67*10^-11 (N*m^2/kg^2)\\m1=42kg\\m2=55kg\\r=2,5m\\therefore\\F=6,67*10^-11*(42*55/2.5^2)\\

F=2,46*10^-8 N[/tex]

Explanation:

Using the Law of Universal Gravitation, proposed by Newton.

Answer: solenoid

Explanation: solenoid: increase strength around electromagnetic fields

Answer:

Yes, the amount of Iron can affect the growth of plant.

Explanation:

Iron is essential micro-nutrient for the growth of plant but it is required only in small amount. Iron is required when plant produces chlorophyll and this gives plants oxygen and healthy green color but if a plant is suffering from iron deficiency then the plant's growth becomes stunted and leaves color changes to yellow. For plants requirement of iron is just 1 to 1.5 lb per acre whereas, requirement of nitrogen is 75 to 200 lb per acre.

The amount of iron in the water affects plant growth, with both deficiency and excess having potential negative impacts. A testable hypothesis using the 'if...then' structure could predict improved growth at optimal iron levels, or decreased health at excessive levels, with measurable outcomes such as plant height and foliage health.

The amount of iron in the water does indeed affect plant growth. Iron is a crucial nutrient for plants, involved in the creation of chlorophyll and essential for some enzymes and cellular functions. However, iron levels must be balanced because both deficiency and excess can lead to plant health issues. Iron deficiency can cause chlorosis, a condition where leaves become pale or yellow because they don't have enough chlorophyll. On the other hand, excess iron, particularly in the ferrous state (Fe2+), can become toxic to plants, especially in waterlogged, anaerobic soil conditions.

To frame a hypothesis regarding the effect of iron on plant growth, using an 'if...then' format, one might say: "If the amount of iron in the water available to plants is increased to optimal levels, then the plants will show improved growth and healthier foliage compared to those receiving suboptimal levels." Conversely, if investigating the negative aspects: "If the amount of iron in the water exceeds optimal levels, then the plants may show signs of toxicity and decreased health."

It is important for the hypothesis to be testable and include measurable variables. For example, plant height, leaf color, and biomass could be measured to determine the impact of iron in water on plant growth.

The beginning momentum of the object is zero

Explanation:

The momentum of an object is given by:

[tex]p=mv[/tex]

where

m is the mass of the object

v is its velocity

For the object in this problem, we have:

m = 3.0 kg is its mass

v = 0, because it is initially at rest, so its initial velocity is zero

Therefore, the initial momentum of the object is

[tex]p=(3.0)(0)=0[/tex]

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Answer:

The length of the resultant vector is 50 inches

Explanation:

Use the Pythagorean theorem to find the answer, since the addition of these two perpendicular vectors will have a magnitude (length) equal to the hypotenuse of the right angle triangle formed by the two:

[tex]|Resultant|\,=\,\sqrt{x^2+y^2} \\|Resultant|\,=\,\sqrt{48^2+14^2}\\|Resultant|\,=\,\sqrt{2304+196}\\|Resultant|\,=\,\sqrt{2500}\\|Resultant|\,=\,50\,in[/tex]  

The length of the resultant vector is 50 inches

Answer:

50 inches Edge 2021

Explanation:

417 K is the “final temperature” of the gas.

Explanation:

According to “Charles law” the change in “volume” of a given mass of gas expanded is “directly proportional” to the “temperature” of the given gas expanded. When we keep “pressure” of the gas as constant. Mathematically,

[tex]v \alpha T[/tex]

[tex]\frac{v}{T}=\text { constant }[/tex]

If gas is expanded from initial volume to final volume and initial temperature to final temperature then,

[tex]\frac{v_{1}}{T_{1}}=\frac{v_{2}}{T_{2}}[/tex]

[tex]\begin{array}{l}{\text { Where, } v_{1} \text { and } v_{2} \text { are the initial and final volumes of the gas expanded recpectively,}} \\ {T_{1} \text { and } T_{2} \text { are the initial and final temperatures of the gas expanded recpectively }}\end{array}[/tex]

Given that,

Initial volume is 1.0L

Final volume is 1.5L

[tex]\text { Initial temperatureis } 5.0^{\circ} \mathrm{C}=5+273=278 \mathrm{K}[/tex]

To find final temperature of the gas

Substitute the given values,

[tex]\frac{1}{278}=\frac{1.5}{T_{2}}[/tex]

[tex]T_{2}=1.5 \times 278[/tex]

[tex]T_{2}=417 K[/tex]

Therefore, final temperature of the gas after expanding is 417 K.

To calculate the final temperature of an expanding gas, you can use Charles's Law, which relates volume and temperature. By substituting the given values into the Charles's Law equation and solving for the final temperature in Kelvin, and then converting it to Celsius, you can find the final temperature of the gas.

To find the final temperature of a gas that has expanded, we can use Charles's Law. This law states that at constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its temperature (in Kelvin) increases or decreases. The formula is: V1/T1 = V2/T2, where V is volume and T is temperature (in Kelvin).

The initial volume (V1) is 1.0L, and the final volume (V2) is 1.5L. The initial temperature (T1) is 5.0°C, which is 278.15K. To find the final temperature in Kelvin (T2), rearrange the formula to get T2 = V2*T1/V1. Substituting in the values gives T2 = (1.5L * 278.15K) / 1.0L. Calculating this gives us a value for T2. To convert T2 back to Celsius, subtract 273.15 from the Kelvin temperature.

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

[tex]a=\frac{v^2}{r}[/tex]

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

[tex]a=1.1 g[/tex]

where [tex]g=9.8 m/s^2[/tex] is the acceleration of gravity. Substituting,

[tex]a=(1.1)(9.8)=10.8 m/s^2[/tex]

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

[tex]v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s[/tex]

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Final answer:

To find the maximum speed that a ride can go without exceeding 1.1g's with a turn radius of 10m, the centripetal acceleration formula is used, and the calculation results in a maximum speed of approximately 10.44 m/s.

Explanation:

To calculate the maximum speed at which a ride can go without exceeding 1.1g's of acceleration, we use the formula for centripetal acceleration a = v^2 / r, where a is the centripetal acceleration, v is the speed, and r is the radius of the turn, which is given as 10m.

We want to keep the acceleration a at no more than 1.1 times the gravitational acceleration g (9.8 m/s^2). Thus, we have: 1.1g = v^2 / r. Plugging in the numbers, we get 1.1 × 9.8 m/s^2 = v^2 / 10 m. To find the maximum speed v, we solve for v, which gives us v = √(1.1 × 9.8 m/s^2 × 10 m). After calculating, we find the maximum speed to be approximately 10.44 m/s.

1. Equinox

2. Greatest

3. Gravity

4. Penumbra

5. Solar

6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.

Answer:

1. Equinox

2. Greatest

3. Gravity

4. Penumbra

5. Solar

6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.

Answer:

The acceleration of the car, a = 60 m/s²

Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

The final velocity of the car, v = 30 m/s

The displacement of the car, s = 0.25 km

Using the III equations of motion

                    v² = u² + 2as

                     a = (v² - u²) / 2s

                        = 30 / 2 x 0.25

                        = 60 m/s²

Hence, the acceleration of the car, a = 60 m/s²

Answer:

Fingers

Explanation:

The index finger shows the moving charge, while your middle finger shows the magnetic field line.

Answer: Palm

Explanation: When you have a wire, you must point your thumb in the direction in which the electricity is going, and now you close your palm, in the direction in which you closed your hand is in the direction in which points the magnetic field.

Then the correct option is the first one, the palm points in the direction of the magnetic field.

Answer:

Yes, a force is require to set an object in motion.

Explanation:

Answer:

D- clay block

Explanation:

Answer:

The correct answer is D.

Explanation:

The clay block provides the force of resistance in the photo, since the weight it exerts on the right end of the ruler on which it is supported makes the system stay in balance. The weight of the spring balance (object A) is transferred to its point of support on the ruler, while the wood and clay cube only exerts one point of support, but does not exert any force on the ruler. The weight exerted by the clay block downward counteracts the weight of the spring balance.

Have a nice day!

Answer:

as far as the car can withstand

Explanation:

When two carts collide and hook together, their momenta combine according to the law of conservation of momentum.

The subject of this question is Physics and the grade level is High School.

In this scenario, we have two carts of different masses approaching each other with the same speed. When the carts collide, they hook together and move as a single system. The total momentum before the collision is equal to the total momentum after the collision, according to the law of conservation of momentum.

The equation for conservation of momentum in this case would be: (2m * v) + (m * (-v)) = (3m * v'), where v' is the final velocity of the hooked carts.

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v' = 0. The combined cart comes to a complete rest.

Let's analyze the scenario of two carts colliding and hooking together:

Initial Conditions:

Cart 1 (mass 2m) has velocity v to the right (positive momentum)

Cart 2 (mass m) has velocity v to the left (negative momentum)

Collision and Resulting Motion:

Upon collision, the carts hook together, forming a single system with a combined mass of 3m. The carts will then move together with a common velocity, v'.

Since the collision is inelastic, kinetic energy is not conserved. Some of the kinetic energy is converted into other forms, such as heat or sound.

Conservation of Momentum:

Despite the loss of kinetic energy, momentum is conserved in an isolated system. The total momentum before the collision must equal the total momentum after the collision.

Initial momentum = (2m * v) + (-m * v) = 0

Final momentum = (3m * v')

Therefore, v' = 0. The combined cart comes to a complete rest.

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Answer:

(B) A pot being heated by an electric burner

(D) A radiator that emits warm air and draws in cool air

(E) A hot air balloon rising and falling in the atmosphere​

These are some of the examples of the convection currents.

Explanation:

Earlier, electrons were believed to have positive charges and then electric current were discovered. But later after the invention of electric current and current which is termed to be the flow of electrons and is usually flows from negative to positive terminal. But its convention is not discarded in which current moves from positive terminal to negative and it is called convention current. The direction of current shown in the circuit is said to be the convention current.

Hence, the following are the examples of convention current.

1.  Boiling water - The energy travels into the pot from the burner, boiling down the water. Then this warm water is accumulating on the top and colder one is heading down to absorb it, triggering a circular motion.

2. Radiator - Place hot air at the peak and pull cool air at the bottom.

3. Hot air balloon - The air is warmed up by a heating element within the balloon, so the air jumps upwards. This induces the balloon to increase in size due to the inside trapping of the warm air. He removes a few of the warm air when the pilot commences to dive, and cold air takes place, enabling the parachute to drop.

Your answer is.

(B) a pot being heated by an electric burner

(D) a radiator that emits warm air and draws in cool air

(E) a hot air balloon rising and falling in the atmosphere

Hope this helps you and you pass your test good luck my friend!

Answer:

The speed of the car is 32.4m/s

Explanation:

1mi = 1600m

152mi = 243 200m

2hr 5min = 7200s + 300s

= 7500s

speed = distance/time

= 243200/7500

= 32.4m/s (3s.f)