Why do living things use enzymes instead of heat as a source of activation energy?


Adding heat would not give the reactants enough energy.


Adding heat does not affect how chemical reactions take place.


Adding sufficient heat would harm or kill a living thing.


Adding heat gives reactants the wrong kind of energy.


Answers

Answer 1
Adding sufficient heat would harm or kill a living thing.

Living things use enzymes instead of a heat source because they speed up chemical reactions as well as the metabolism in those living. Adding sufficient heat would harm or kill a living thing, also enzymes are far more efficient. A single enzyme can often carry out thousands of reactions per second. Living organisms use enzymes for activation energy because they speed up chemical reactions.


Related Questions

Given the decomposition reaction: 2so3(g) → 2so2 (g) + o2 (g) according to le châtelier's principle, which side of the reaction will be favored when more oxygen is added to the reaction chamber?

Answers

A)The products will be favored.

Virtually all chemical reactions are accompanied by the liberation or uptake of heat. If we regard heat as a "reactant" or "product" in an endothermic or exothermic reaction respectively, we can use the Le Châtelier principle to predict the direction in which an increase or decrease in temperature will shift the equilibrium state. Thus for the oxidation of nitrogen, an endothermic process, we can write

[heat] + N2(g) + O2(g) → 2 NO(g)

Suppose this reaction is at equilibrium at some temperature T1 and we raise the temperature to T2. The Le Châtelier principle tells us that a net reaction will occur in the direction that will partially counteract this change. Since the reaction is endothermic, a shift of the equilibrium to the right will take place.

Answer:

C. the reactants will be favored.

Explanation:

What is the hydronium ion concentration in a solution of HCl that has a pH of 4.65? × 10n M n = What is the hydroxide ion concentration in a solution of NH3 with a pOH of 4.65? × 10n M n =

Answers

Answer:What is the hydronium ion concentration in a solution of HCl that has a pH of 4.65? Round to the nearest hundredth.
 
2.24 × 10n Mn =  -5

What is the hydroxide ion concentration in a solution of NH3 with a pOH of 4.65?  Round to the nearest hundredth.

2.24 × 10n Mn =  -5

Explanation:

Calculate the amounts requested if 3.30 mol Fe2O3 completely react according to the following equation. Fe2O3 + 2Al --> 2Fe + Al2O3
a. moles of aluminum needed
b. moles of iron formed
c. moles of aluminum oxide formed

Answers

A. Moles of Aluminum needed;

Reaction is as follow,

                                Fe₂O₃ + 2 Al      →    2 Fe + Al₂O₃ 
According to eq,

                              1 mole Fe₂O₃ required  =  2 mole of Al
So,
                       3.30 mol Fe₂O₃ will require  =  X moles of Al

Solving for X,
                     X  =  (2 mol × 3.30 mol) ÷ 1 mol

                     X  =  6.6 mol of Al

B. Moles of Iron formed:

According to eq,

                              1 mole Fe₂O₃ produced  =  2 mole of Fe
So,
                       3.30 mol Fe₂O₃ will produce  =  X moles of Fe

Solving for X,
                     X  =  (2 mol × 3.30 mol) ÷ 1 mol

                     X  =  6.6 mol of Fe

C. Moles of Aluminum Oxide formed:

According to eq,

                              1 mole Fe₂O₃ produced  =  1 mole of Al₂O₃
So,
                       3.30 mol Fe₂O₃ will produce  =  X moles of Al₂O₃

Solving for X,
                     X  =  (1 mol × 3.30 mol) ÷ 1 mol

                     X  =  3.30 mol of Al₂O₃

The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.

Answers

CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

Final answer:

The solubility product constant (Ksp) of calcium carbonate is used to calculate the solubility of this compound in water. Considering the 1:1:1 molar ratio between CaCO3 and the ions it forms on dissolution, we derive the solubility as 0.0058 g/l.

Explanation:

The subject of your question is the solubility product constant (Ksp) of calcium carbonate (CaCO3). The Ksp is used to calculate the solubility of a compound, such as CaCO3, in a given solvent, which in this case is water. The Ksp is given as 3.36 × 10-9 M² and it is this value that we will use to determine the solubility.

As we know, for the dissolution of calcium carbonate into calcium and carbonate ions, the dissolution reaction can be written as: CaCO3(s) → Ca²+ + CO3²-. Here, it implies that there is a 1:1:1 molar ratio between CaCO3 and the ions it forms on dissolution. Thus, if 's' represents the molarity of CaCO3, then the Ksp expression can be written as Ksp = [Ca²+][CO3²-] = s².

Using the given Ksp value, we can solve the above equation for 's': s = sqrt(Ksp) = sqrt(3.36 × 10-9 M²) = 5.8 × 10-5 M. However, the question asks for the solubility in g/l. To convert molarity (M) to g/l, we multiply by the molecular weight of the compound. For CaCO3, the molecular weight is approximately 100 g/mol. Therefore, the solubility is 5.8 × 10-5 M x 100 g/mol = 0.0058 g/l.

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What causes a ball rolling across a rug to slow to a stop

Answers

The answer is friction. It oppose the ball's forward motion.  The cause for a ball rolling across a rug to slow to a stop is that friction resists the ball's forward motion.  Friction can cause a moving object, such as a ball, to slow down and eventually stop.

Answer:

Friction

Explanation:

Friction is a force that slows down moving objects. If you roll a ball across a shaggy rug, you can see that there are lumps and bumps in the rug that make the ball slow down. The rubbing, or friction, between the ball and the rug is what makes the ball stop rolling.

When oil and water are mixed vigorously, the oil is broken up into tiny droplets that are dispersed throughout the water. this dispersed mixture is a(n)?

Answers

Emulsion or heterogeneous mixture

What colors of visible light do green plant leave absorb the most

Answers

Chlorophyll in plant leaves absorb red and blue regions of the visible light spectrum.
The answer is Red and Blue light.
Red and blue. If red and blue are absorbed, the green would be reflected. This makes the plant appear to be green. If it absorbed green, plants would be (a) very different in color(s).

What is the chemical formula for the compound tetraphosphorus decasulfide?

Answers

P S
4 10

you just use the roots given in the molecular formula

The chemical formula for tetraphosphorus decasulfide is P4S10, consisting of four phosphorus atoms and ten sulfur atoms in the compound.

The chemical formula for the compound tetraphosphorus decasulfide is P4S10.

Phosphorus forms various compounds with different stoichiometries, and in this case, tetraphosphorus decasulfide consists of four phosphorus atoms bonded with ten sulfur atoms.

It is crucial to understand chemical formulas to identify elements and their quantities in compounds accurately.

Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole)

Answers

The  %  composition  by mass  of oxygen in litharge ( grams formula mass=223.2 g/mol) is  calculated as  below

%  composition is   percentage  by mass  of  each   element  in a  compound
which  is  calculated  as follows

%composition = molar mass  of element/molar  mass  of  compound  x100

The  molar mass of oxygen = 16 g/mol

therefore the % composition  = 16 g/mol/ 223.2 g/ mol  x100 = 7.17 %  of oxygen
Litharge is a yellow oxide of lead with a formula of PbO, which is formed by heating lead metal in air. 
The mass of one mole of PbO is 223.2 grams
1 mole of PbO contains 16 g of oxygen
Therefore; the percentage of oxygen will be;
     (16/223.2) × 100 = 7.168 %

Identify the element that has a ground state electronic configuration of [ar]4s23d104p 3 .

Answers

The element is arsenic.

Ka for hcn is 4.9 ⋅ 10-10. what is the ph of a 0.068 m aqueous solution of sodium cyanide? ka for hcn is 4.9 10-10. what is the ph of a 0.068 m aqueous solution of sodium cyanide? 0.74 7.00 2.96 13.24 11.07

Answers

Answer is: pH of solution of sodium cyanide is 11.07.
Chemical reaction 1: NaCN(aq) → CN⁻(aq) + Na⁺(aq).
Chemical reaction 2: CN⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻(aq).
c(NaCN) = c(CN⁻) = 0.068 M.
Ka(HCN) =  4.9·10⁻¹⁰.
Kb(CN⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵.
Kb = [HCN] · [OH⁻] / [CN⁻].
[HCN] · [OH⁻] = x.
[CN⁻] = 0.068 M - x..
2.04·10⁻⁵ = x² / (0.068 M - x).
Solve quadratic equation: x = [OH⁻] = 0.00116 M.
pOH = -log(0.00116 M) = 2.93.
pH = 14 - 2.93 = 11.07.

The pH of the sodium cyanide solution is 11.56.

Let the cyanide ion be X

We have to set up the ICE table for the problem as follows;

     X^-(aq) + H2O(l)  ⇄ HX(aq) + OH^-(aq)

I    0.068                            x                 x

C   -x                                 + x                +x      

E   0.068 - x                      x                   x

But Kb = Kw/Ka = 1 × 10^-14/4.9 × 10-10

Kb = 2 × 10^-4

So;

Kb = [HX] [OH^-]/[X^-]

2 × 10^-4 = x^2/ 0.068 - x  

2 × 10^-4(0.068 - x) = x^2

1.36 × 10^-5 - 2 × 10^-4x = x^2

x^2 + 2 × 10^-4x - 1.36 × 10^-5 = 0

x= 0.0036 M

Since x = [OH^-] = 0.0036 M

pOH = - log(0.0036 M)

pOH = 2.44

pH = 14 - 2.44 = 11.56

The pH of the sodium cyanide solution is 11.56.

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Gas stoichiometry: what volume of oxygen at 25 degrees celsius and 1.04 atm is needed for the complete combustion of 5.53 grams of propane?

Answers

Answer is: volume of oxygen is 14.7 liters.
Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
m(C₃H₈-propane) = 5.53 g.
n(C₃H₈) = m(C₃H₈) ÷ M(C₃H₈).
n(C₃H₈) = 5.53 g ÷ 44.1 g/mol.
n(C₃H₈) = 0.125 mol.
From chemical reaction: n(C₃H₈) : n(O₂) = 1 : 5.
n(O₂) = 0.625 mol.
T = 25° = 298.15K.
p = 1.04 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
V(O₂) = n·R·T / p.
V(O₂) = 0.625 mol · 0.08206 L·atm/mol·K · 298.15 K / 1.04 atm.
V(O₂) = 14.7 L.

Final answer:

To find the volume of oxygen needed to combust 5.53 grams of propane, calculate the moles of propane, use the stoichiometric relationship to find the moles of oxygen required, and then apply the ideal gas law to find the volume, resulting in 14.79 liters of oxygen needed.

Explanation:

Gas Stoichiometry of Propane Combustion

To determine the volume of oxygen at 25 degrees Celsius and 1.04 atm needed for the complete combustion of 5.53 grams of propane, we need to use stoichiometry and the ideal gas law. The balanced equation for the combustion of propane C3H8 is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

First, we convert the mass of propane into moles using its molar mass:

5.53 g C3H8 × (1 mol C3H8 / 44.11 g C3H8) = 0.1253 mol C3H8

According to the balanced equation, 1 mole of propane reacts with 5 moles of oxygen. Therefore, we need:

0.1253 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 0.6265 mol O2

Now, we use the ideal gas law, PV=nRT, to find the volume of oxygen. First, adjust R to match the pressure in atm and volume in liters:
1.04 atm × V = 0.6265 mol × 0.0821 L×atm/mol×K × 298.15 K

Solving for V gives us the volume of oxygen needed:

V = (0.6265 mol × 0.0821 L×atm/mol×K × 298.15 K) / 1.04 atm = 14.79 L

Therefore, 14.79 liters of oxygen at 25 degrees Celsius and 1.04 atm are required for the complete combustion of 5.53 grams of propane.

What volume, in milliliters, of 2.0 calcium chloride stock solution would you use to make 500 ml of 0.300 m of calcium chloride cacl2 solution?

Answers

we can use the following formula when making diluted solutions from more concentrated solutions.
c1v1 = c2v2 
where c1 is the concentration and v1 is the volume of the concentrated solution 
and c2 is concentration and v2 is volume of the diluted solution to be prepared 

substituting these values in the equation 
2.0 M x V = 0.300 M x 500 mL 
V = 75 mL

75 mL should be taken from the stock solution and diluted upto 500 mL to make the 0.300 M solution 

Which of the following best describes the changes involved in a fission reaction?

The nucleus of an atom splits into fragments, releasing a large amount of energy.
The nucleus of an atom splits into fragments, absorbing a large amount of energy.
The nuclei of two small atoms combine to form one larger nucleus, releasing a large amount of energy.
The nuclei of two small atoms combine to form one larger nucleus, absorbing a large amount of energy.

Answers

The correct answer is this: THE NUCLEUS OF AN ATOM SPLITS INTO FRAGMENTS, RELEASING A LARGE AMOUNT OF ENERGY.
Nuclear fission is the process in which the nucleus of a radioactive element split into two different nucleic of smaller sizes of different elements with a large release of energy. Nuclear fission process is usually used to provide energy for electricity generation. 

In a fission reaction, the nucleus of an atom splits into fragments, releasing a large amount of energy. Nuclear fission occurs when a heavy nucleus like uranium absorbs a neutron and splits, emitting additional neutrons, gamma rays, and energy.

The correct description of the changes involved in a fission reaction is: The nucleus of an atom splits into fragments, releasing a large amount of energy. Nuclear fission is a nuclear reaction where the nucleus of an atom, such as uranium-235 or plutonium-239, splits into smaller nuclei after absorbing a neutron.

This process produces additional free neutrons, gamma radiation, kinetic energy of fission fragments, and releases a significant amount of energy. The process is exothermic, and the energy released can be harnessed for electricity generation in nuclear reactors or can be used in nuclear weapons.

Nuclear fission differs from nuclear fusion, which is the combining of two smaller atomic nuclei to form a larger nucleus, also releasing energy. In both processes, large amounts of heat and radiation are emitted. However, for fission, a fissile material like uranium or plutonium is necessary to sustain the reaction, and it involves the breakup of a heavy nucleus into lighter elements.

A person moves a book from a 30-cm high coffee table to the top shelf of a bookshelf approximately 2.5 m high. Which statement correctly describes the gravitational potential energy of the book? It has more gravitational potential energy on the table than on the shelf, It has more gravitational potential energy on the shelf than on the table,Its gravitational potential energy is constant regardless of its position?

Answers

Correct statement is "It has more gravitational potential energy on the shelf than on the table".

GPE = mgh

Where, GPE is the gravitational potential (J), m is the mass of the object (kg), g is acceleration due to gravity (9.8 m s⁻²) and h is the height to the object from ground (m).

Hence, GPE is directly proportional to h means, when h increases, GPE also increases.

Adding salt to water when boiling vegetables or pasta makes the water boil at a higher temperature. How much would the boiling point of water be increased if 49.2 g of NaCl is added to 500 mL of water? (Remember that the density of water is 1 g/mL and kb for water is 0.51 oC/m)

Answers

Adding a non-volatile solute in solvent, increases the boiling point of solvent. This is referred as elevation in boiling point. The increase in boiling point is mathematically expressed as
ΔTb = Kb X m    ....... (1)
where, Kb = molal elevation constant =  0.51 oC/m
m = molality of solution = [tex] \frac{\text{weight of solute (g)}}{\text{Molecular weight X Weight of solvent (Kg)}} [/tex]

Given: weight of solute = 49.2 g
volume of solution = 500 ml
Density of water = 1 g/ml

∴  weight of solvent = 500 g = 0.5 kg

Also,we know that molecular weight of NaCl = 58.5

∴m = molality of solution = [tex] \frac{\text{49.2}}{\text{58.5 X 0.5}} [/tex]
                                        =  1.68 m

The molality of solution is 1.68 m      ......  (2)

Substituting 2 in 1 we get 
ΔTb = Kb X m = 0.51 x 1.68 = 0.8568 oC

Thus, increase in boiling point of water is 0.8568 oC
Final boiling point of solution = 100 + 0.8565 = 100.8568 oC

Which is the best description of a chain of custody?
A) A list of all personnel entering the crime scene.
B) A log of which family member has ownership of the evidence.
C) A log of which agency controls the evidence so the case stays in the correct jurisdiction.
D) A log of who has handled the evidence and when so the integrity of the evidence is upheld.

Answers

D) A log of who has handled the evidence and when so the integrity of the evidence is upheld.

Which aqueous solution has the lowest freezing point c6h12o6, c2h5oh, ch3cooh, or nacl?

Answers

Depression of a freezing point of the solutions depends on the number of particles of the solute in the solution.
1 mol of C6H12O6 after dissolving in water still be 1 mol, because C6H12O6 does no dissociate in water.
1 mol of C2H5OH after dissolving in water still be 1 mol, because C2H5OH does no dissociate in water.
1 mol of NaCl after dissolving in water gives 2 mol of particles (ions), because NaCl is a strong electrolyte(as salt) and completely dissociates in water.
NaCl ----->Na⁺ + Cl⁻
1 mol of CH3COOH after dissolving in water gives more than 1 mol but less than 2 moles, because CH3COOH is a weak electrolyte (weak acid) and dissociates  only partially. 

So, most particles of the solute is going to be in the solution of NaCl, 
so the lowest freezing point has the aqueous solution of NaCl.

Among C₆H₁₂O₆, C₂H₅OH, CH₃COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.

We have 4 aqueous solutions and we want to determine which has the lowest freezing point.

C₆H₁₂O₆C₂H₅OHCH₃COOHNaCl

What is the freezing point depression?

Freezing-point depression is a drop in the temperature at which a substance freezes, caused when a smaller amount of another, non-volatile substance is added.

We can calculate the freezing point depression (ΔT) using the following expression.

ΔT = Kf × b × i

where,

Kf is the cryoscopic constant for water.b is the molality of the solution.i is the Van't Hoff factor.

Assuming all the solutions have the same molality, the freezing point depression will be a function of the van't Hoff factor.

What is the van't Hoff factor?

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

For non-electrolytes, such as C₆H₁₂O₆ and C₂H₅OH, i = 1. Comparing NaCl and CH₃COOH, we can determine that i(NaCl) > i(CH₃COOH) because NaCl is a strong electrolyte and CH₃COOH a weak one.

Thus, NaCl, with the highest Van't Hoff factor, will have the lowest freezing point.

Among C₆H₁₂O₆, C₂H₅OH, CH₃COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.

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How many grams of solute are present in 615 ml of 0.630 m kbr?

Answers

molarity is the number of moles of solute in 1 L of solution
molarity of KBr solution is 0.630 M
this means that there there are 0.630 moles of KBr in 1 L solution 
then in 615 mL number of KBr moles are - 0.630 mol/L x 0.615 L = 0.387 mol
mass of KBr is - molar mass x number of moles 
KBr molar mass is 119 g/mol x 0.387 mol = 46.1 g
mass of KBr is 46.1 g

The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 mc030-1.jpg N2 + 3I2 The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Answers

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?


0.0136 

Answer:

0.0135 moles of iodine will be formed.

Explanation:

[tex]2NI_3\rightarrow N_2+3I_2[/tex]

Moles of nitrogen triiodide =[tex]\frac{3.58 g}{394.71 g/mol}=0.0090 mol[/tex]

According to reaction 2 moles of nitrogen triiodide gives 3 moles of iodione gas.

Then 0.0090 mol of nitrogen triiodide will give:

[tex]\frac{3}{2}\times 0.0090 mol=0.0135 mol[/tex]

0.0135 moles of iodine will be formed.

If 29.0 l of methane, ch4, undergoes complete combustion at 0.961 atm and 140c, how many liters of each product would be present at the same temperature and pressure

Answers

combustion of methane is as follows;
CH₄ + 2O₂ --> CO₂  + 2H₂O
at constant temperature and pressure, volume of gas is directly proportional to number of moles of gas. This is Avagadro's law.
since its the same temperature and pressure , molar ratio is equivalent to volume ratio.
for instance molar ratio of CH₄ to CO₂ is 1:1
since number of moles is directly proportional to volume of gas, then volume ratio of CH₄ to CO₂ is 1:1
volume of methane is 29.0 L
therefore volume of CO₂ formed is 29.0 L

volume ratio of CH₄ to H₂O is 1:2
then volume of H₂O formed is 29.0 x 2 = 58.0 L 
therefore volume of H₂O formed is 58.0 L

Decreasing the particle size of the reactants in a chemical reaction will increase the rate of reaction by
A) increasing the concentration of the reactants.
B) increasing the surface area of the reactants.
C) increasing the activation energy.
D) increasing the temperature.

Answers

Answer: B) increasing the surface area of the reactants.

Explanation:

Decreasing the particle size of the reactants in a chemical reaction will increase the rate of reaction by increasing the surface area of the reactants. Hence, option B is correct.

What is a chemical reaction?

A chemical reaction is a process that leads to the transformation of one set of chemical substances into another. It involves breaking and forming chemical bonds between atoms and molecules to form new substances.

In a chemical reaction, the reacting substances are called reactants, and the newly formed substances are called products.

Decreasing the particle size of the reactants in a chemical reaction will increase the rate of reaction by increasing the surface area of the reactants that are available for the reaction.

When the particle size is reduced, the total surface area of the reactant particles is increased, which makes it easier for the particles to collide and react with one another.

Thus, option B is correct.

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J. J. Thomson
A) Electrons are in orbital levels.

John Dalton
B) Atoms are the smallest unit of an element.

Ernest Rutherford
C) Electrons are scattered within the atom.

Niels Bohr
D) Protons are at the center of an atom.

Answers

John Dalton
B) Atoms are the smallest unit of an element.

J. J. Thomson
C) Electrons are scattered within the atom.

Ernest Rutherford
D) Protons are at the center of an atom.

Niels Bohr
A) Electrons are in orbital levels.

How is the energy divided up in the plant

Answers

When a crop of wheat grows, new organic matter is created by the process of photosynthesis, which converts light energy into energy stored in chemical bonds within plant tissue. ... New compounds and structures are synthesized, cells divide, and the plant grows in size over time
thanks
cbuck763

Explanation:

Plants veins provide energy to the rest of the plant and it also provides structure and support to the plant leaves and also transport water. When plants absorb water and nutrients through their roots, their vascular system come in use to move water and nutrients to the rest part of the plants. There are two types of tissue that make up the plants veins are xylem and phloem. Xylem moves water and minerals from the plants's roots and phloem moves food energy to all parts of plant where the plants need it.    

What volume of 6.00 m naoh solution is required to prepare 0.50 ml of 0.15 m naoh solution

a. 12.5 ml of naoh

b. 25 ml of naoh

c. 30 ml of naoh?

Answers

M1V1 = M2V2

Molarity of Solution 1 x Volume of Solution 1 = Molarity of Solution 2 x Volume of Solution 2

First of all, I think you mean .5 Liters?

(6M)(V) = (.15M)(.5L)

V = .0125 L x 1000 mL / Liter = a. 12.5 mL

Final answer:

To prepare 0.50 mL of a 0.15 M NaOH solution from a 6.00 M NaOH solution, you would need 12.5 μL of the concentrated solution according to the dilution formula, which is not listed among the provided answer options.

Explanation:

The volume of 6.00 M NaOH solution required to prepare 0.50 mL of 0.15 M NaOH solution can be found using the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution, respectively. Plugging the known values into the equation: (6.00 M)(V1) = (0.15 M)(0.50 mL) ⇒ V1 = (0.15 M)(0.50 mL) / (6.00 M) = 0.0125 mL or 12.5 μL.

Since none of the provided answer choices (a) 12.5 mL, (b) 25 mL, or (c) 30 mL match this result, it seems there might be a typo or a misprint in the question. To prepare 0.50 mL of a 0.15 M solution from a 6.00 M solution, you would need substantially less than 1 mL of the concentrated solution. The likely correct volume needed, based on the question's data, would be 12.5 μL, which is not listed as an option in the question.

Anyone good with chemistry? number five and six please?!

Answers

ask a teacher for help
5: it is True
6: it is False

When fracking liquid waste is left in pools on the surface, _ can evaporate into the air and contribute to pollution

Answers

When fracking liquid waste is left in pools on the surface, Toxic Waste or Toxic Chemicals can evaporate into the air and contribute to pollution. A new study shows that these spills have left surface waters in the area carrying radium, selenium, thallium, lead, and other toxic chemicals that can continue for years at unsafe levels. 

Volatile organic compounds (VOCs) can evaporate from fracking liquid waste pools, contributing to air pollution. These pools may also contain hazardous air pollutants and heavy metals, requiring careful handling to avoid environmental contamination.

When fracking liquid waste is left in pools on the surface, volatile organic compounds (VOCs) can evaporate into the air and contribute to pollution. These wastewater ponds can contain a variety of pollutants, including hazardous air pollutants such as benzene, toluene, ethylbenzene, and xylene. Moreover, fracking fluid, also known as flowback, can contain chemicals used in the drilling process, heavy metals, and radioactive materials. These substances pose a significant risk to both environmental and human health if they are not properly managed and treated.

The process of hydraulic fracturing or 'fracking' involves injecting high-pressure fluids to fracture shale deposits, which releases trapped gas and oil. The wastewater from this process may return to the water cycle, but the large volume of contaminated water requires careful handling to prevent land and water pollution. As a proactive measure, governments around the world have taken steps, in some cases banning the practice due to the severe risks associated with fracking.

The ph of lemon juice is approximately 2.40. at this ph, the hydronium ion concentration is closest to which concentration? 4.0 × 10¯3 m 0.38 m 5.6 × 10¯4 m 2.5 × 10¯12 m

Answers

pH = -log[H₃O⁺(aq)]

here the pH is given as 2.40.

Hence,
  2.40               = -log[H₃O⁺(aq)]
log[H₃O⁺(aq)]  = -2.40
[H₃O⁺(aq)]       = 3.98 x 10⁻³ M
                        = 4.0 x 10⁻³ M

Hence, the hydronium ion concentration in juice is 4.0 x 10⁻³ M.

Since, the pH is less than 7, the juice is acidic.

What is the final pressure of a system (atm) that has the volume increased from 0.75 l to 1.1 l with an initial pressure of 1.25 atm? 1.1 0.85 1.8 1.2 none of the above?

Answers

Boyle's law states that pressure is inversely proportional to volume of gas at constant temperature 
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting these values in the equation 
1.25 atm x 0.75 L = P x 1.1 L
P = 0.85 atm 
final pressure is B) 0.85 atm 

Final answer:

The final pressure of the system is 0.85 atm.

Explanation:

To determine the final pressure of the system, we can use the relationship between volume and pressure known as Boyle's Law. According to Boyle's Law, when the volume of a gas increases, the pressure decreases, and vice versa, at constant temperature and amount of gas.

In this case, the initial volume is 0.75 L and the final volume is 1.1 L. Since the volume increased, we can expect the pressure to decrease. The initial pressure is 1.25 atm. Using Boyle's Law, we can set up the equation:

P1 * V1 = P2 * V2

1.25 atm * 0.75 L = P2 * 1.1 L

Solving for P2, we get: P2 = 1.25 atm * 0.75 L / 1.1 L = 0.85 atm

Therefore, the final pressure of the system is 0.85 atm.

How many milliliters of .45m hcl will neutralize 25ml of 1m koh?

Answers

The  number of  Ml  of 0.45m HCl needed to neutralize  25 ml  of 1 ml KOH  is  calculated  as below

find the moles of KOH  used =  molarity  x volume

= 1  x25 = 25 moles
write the reacting  equation

KOH +HCL = KCl + H2O

by  use   of  mole ratio  between  KOH to HCl  which is 1:1 therefore the  moles of 25 moles

volume of HCl = moles/molarity

 25/0.45 = 55.6 ml  of HCL


the balanced equation for the reaction is as follows;
HCl + KOH ---> KCl + H₂O
stoichiometry of HCl to KOH is 1:1
number of KOH moles reacted - 1 mol/L x 0.025 L = 0.025 mol 
according to 1:1 molar ratio 
number of KOH moles reacted = number of HCl moles reacted 
therefore number of HCl moles reacted - 0.025 mol

molarity of HCl is 0.45 M
since 0.45 mol  are in 1000 mL 
therefore 0.025 mol are in a volume of 0.025 mol / 0.45 mol/L  = 55.5 mL 
55.6 mL of HCl is required to neutralise 
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