Answer:
It is given that number of electrons is 11.
It is known that when an atom is neutral then the number of protons equals number of electrons. Also, atomic number means number of protons an atom holds.
Whereas mass number equals number of protons + number of neutrons. Thus, mass number of given atom is 11 + 13 = 24.
The symbol for this element will be as follows 24/11x . This atom sodium has atomic number 11 and mass number 24.
Therefore, symbol of this radioactive nuclide is as follows . A)Superscript 24 subscript 11 upper N a.
Answer:
Answer Is A
Explanation:
24/11 NA: This answer was correct
Match each type of asexual reproduction with its description.
Budding
A new organism grows from the body of the
parent
Fragmentation
The parent cell divides to produce a
genetically identical cell
Binary fission
The parent breaks into parts that may
regenerate into offspring
Answer:
Budding- A new organism growing from the body of the parent
Fragmentation- The parent breaks into parts that may regenerate into offspring
Binary Fission- The parent cell divides to produce a genetically identical cell
Answer: A new organism growing from the body of the parent
Fragmentation- The parent breaks into parts that may regenerate into offspring
Binary Fission- The parent cell divides to produce a genetically identical cell
Which aqueous solution will theoretically have the lowest freezing point? A) 0.001 M NaCl B) 0.001 M C6H12O6 C) 0.001 M CaCl2 D) 0.001 M AlCl3
Answer:
D) 0.001 M AlCl3
Explanation:
The solution with the lowest freezing point would be 0.001 M AlCl3 because it produces the most particles when fully ionized in water, therefore lowering the freezing point the most.
Theoretically, the aqueous solution that will have the lowest freezing point is D) 0.001 M AlCl3. This is based on the principle of colligative properties, which states that the freezing point of a solution is lowered when solutes are added. The extent of this lowering depends on the number of solute particles present. In this case, AlCl3, when fully ionized in water, produces 4 particles (1 Al3+ and 3 Cl-), contributing to the greatest decrease in freezing point.
Learn more about Freezing Point Depression here:
https://brainly.com/question/34610084
#SPJ6
Can someone pls help me!
Answer:
the third one
Explanation:
they change overtime
In which compound have electrons been transferred to an oxygen atom
a NO2
b N2O
c Na2O
d CO2
Answer:
Na2O
Explanation:
This is because a bond between a metal and a non-metal has occured.
Final answer:
In Na₂O, two sodium atoms transfer one electron each to the oxygen atom, forming a neutral ionic compound with a ratio of two sodium ions to one oxide ion.
Explanation:
Among the options given, the compound in which electrons have been transferred to an oxygen atom is Na₂O. In Na₂O, two sodium (Na) atoms each donate one electron to the oxygen (O) atom. This transfer of electrons is what forms the ionic bond in Na₂O. Each sodium atom becomes positively charged (Na+), and the oxygen atom gains two electrons to become negatively charged (O₂-). This results in the formation of a neutral ionic compound with a ratio of two sodium ions to one oxide ion.
Can anyone help with this question?
Answer:
b
Explanation:
Determine the solution of the following system of equations: *
Captionless Image
No solution
(3, 1)
( 1 , -3 )
Infinite Solutions
Answer: N/A
Explanation: You have to write down the equation otherwise we are unable to help you.
Which of these salts is most likely to be soluble? Potassium nitrate OR Iron carbonate OR Copper oxide
Final answer:
Potassium nitrate is the most likely to be soluble among the options given because all nitrates are known to be soluble in water, while Iron carbonate and Copper oxide are typically insoluble.
Explanation:
Among the given options of salts—Potassium nitrate, Iron carbonate, and Copper oxide—the one most likely to be soluble is Potassium nitrate. This is due to the general solubility rule that all nitrates are soluble in water. Salts containing the large, singly charged NO₃⁻ ion, such as Potassium nitrate, tend to form highly soluble compounds, while carbonates (like Iron carbonate) and oxides (like Copper oxide) are often less soluble or insoluble except in the presence of certain cations like potassium, sodium, and ammonium.
Iron carbonate and Copper oxide are generally insoluble in water. For instance, iron(II) carbonate is not soluble except when combined with cations like potassium, sodium, or ammonium. Similarly, Copper oxide's solubility is very low in water. On the contrary, even though Copper sulfate is not provided as an option, it is worth mentioning that many sulfates, unlike carbonates and oxides, are generally soluble, with few exceptions.
What basic equation is used to calculate the ph of a solution
Answer: You can calculate the pH of an acid or base solution given the hydronium ion concentration by using the formula pH = -log [H3O+] or if given the hydroxide ion concentration by the formula [H3O+] = Kw / [OH-], then using the pH = -log [H3O+] formula.
The pH of a solution is calculated using the equation pH = -log[H3O+], which represents the negative logarithm of the hydrogen ion concentration. A pH less than 7 indicates an acidic solution, while a pH greater than 7 denotes a basic solution.
The basic equation used to calculate the pH of a solution is the negative, base-10 logarithm of the hydrogen ion (H+) concentration of the solution. This can be formally written as pH = -log[H3O+]. Using this equation, we can determine the acidity or alkalinity of a solution on a scale from 0 to 14.
A solution with a pH of 7 is considered neutral, with those pH less than 7 being acidic and those pH greater than 7 being basic or alkaline. For example, a solution with a pH 4 is ten times more acidic than a solution with a pH 5 since each pH unit represents a tenfold difference in H+ ion concentration.
Learn more about pH here:
https://brainly.com/question/36153729
#SPJ12
If the absolute temperature of a gas is doubled, what happens to the root‑mean‑square speed of the molecules? Nothing happens to the rms speed. The new rms speed is 4 times the original rms speed. The new rms speed is 2 times the original rms speed. The new rms speed is 1.414 times the original rms speed. The new rms speed is 1/2 the original rms speed.
Answer:
The new rms speed is 1.414 times the original rms speed
Explanation:
The rms speed (root-mean-square speed) of the molecules in a gas can be found by using the formula:
[tex]v=\sqrt{\frac{3RT}{M}}[/tex]
where
R is the gas constant
T is the absoolute temperature (in Kelvin) of the gas
M is the molar mass of the gas (the amount of mass per unit mole)
We can rewrite the equation as
[tex]v\propto \sqrt{T}[/tex] (1)
which means that the rms speed is proportional to the square root of the temperature.
In this problem, we are told that the absolute temperature of the gas is doubled, so the new temperature is
[tex]T'=2T[/tex]
Therefore, according to eq(1), we find that the new rms speed will be:
[tex]v\propto \sqrt{T'} = \sqrt{2T}=\sqrt{2} \sqrt{T}=\sqrt{2}v=1.414v[/tex]
So,
The new rms speed is 1.414 times the original rms speed
If the absolute temperature of a gas is doubled ; ( D ) The new rms speed is 1.414 times the original rms speed
The r.m.s speed of molecules in a gas can be calculated using the formula below ;
[tex]v = \sqrt{\frac{3RT}{M} }[/tex]
T = absolute temperature
R = gas constant
M = molar mass
Also ; The rms speed of gas molecules is directly proportional to [tex]\sqrt{T}[/tex]
i.e. v ∝ √T ----- ( 1 )
Given that the absolute temperature ( T ) is doubled the new value of T = 2T
Back to equation ( 1 )
v = √2T = √2 * √T
= 1.414
Hence we can conclude that If the absolute temperature of a gas is doubled The new rms speed is 1.414 times the original rms speed.
Learn more : https://brainly.com/question/24355842
this is 6th grade question 25 POINTS PLEASE HELP A waste company has been dumping untreated sewage into the river next to the house. They have recently been found guilty because of the effect the pollution has had on the plants and animals living there. What effect has the raw sewage had on the animals that live in the river?
A) Animals blend in better in the darker water.
B) More animals now live in the river than ever before.
C) Many animals have become sick or have been found dead.
D) Animals that have lived in the water now live on land.
Final answer:
Untreated sewage dumped into a river causes significant harm to aquatic life, leading to sickness and fatalities among animals, degradation of water quality, and the creation of dead zones. These pollutants also pose a risk to human health as they can travel up the food chain.
Explanation:
The effect of untreated sewage being dumped into a river on the animals living therein is typically devastating. The correct answer to the question, 'What effect has the raw sewage had on the animals that live in the river?' is C) Many animals have become sick or have been found dead.
Water pollution from untreated sewage includes harmful bacteria and chemicals that can cause disease and death in river ecosystems. Pollutants like nitrogen and phosphorus can lead to eutrophication, which depletes the oxygen in the water, creating dead zones where fish and other aquatic life cannot survive. Additionally, contaminated water can carry diseases and toxins up the food chain, posing health risks to animals and humans alike.
Industrial waste and agricultural runoff also contribute to the degradation of water quality, affecting not only the immediate area but also environments downstream. This contamination has a cascading effect on ecosystems, harming countless plants, animals, and humans who depend on these water sources.
What volume is occupied by 21.0 g of methane (CH4) at 27 degrees Celsius and 1 atm?
Answer:
The volume is occupies by 21,0g of methane is 32, 3 L.
Explanation:
We use the formula PV=nRT. We convert the unit temperature Celsiud into Kelvin: 0°C=273 K---> 27°C= 27+273= 300K. We calculate the weight of 1 mol of CH4:
Weight 1 mol CH4= Weight C+ (Weight H)x4= 12 g+ 1g x4= 16 g
16 g---1 mol CH4
21g---x= (21g x 1 mol CH4)/16g= 1, 31 mol CH4
PV=nRT ----> V= (nRT)/P
V= (1, 31 mol x 0,082 l atm/K mol x 300 K)/ 1 atm
V= 32, 3875 L
The volume occupied by 21.0 g of methane (CH4) at 27 degree celsius and 1 atm is 32.3L
IDEAL GAS LAW:The volume occupied by a gas can be calculated by using the ideal gas law equation as follows:PV = nRT
Where;
P = pressure (atm)V = volume (L)n = number of moles (mol)R = gas law constant (0.0821 Latm/molK)According to this question;n = 21g ÷ 16g/mol = 1.3125molV = ?P = 1 atmT = 27°C + 273 = 300K1 × V = 1.3125 × 0.0821 × 300V = 32.32LTherefore, volume occupied by 21.0 g of methane (CH4) at 27 degree celsius and 1 atm is 32.3L.Learn more about ideal gas law at: https://brainly.com/question/4147359?referrer=searchResults
A gas has pressure of 50.0 mmHG at a temperature of 540K. What will be the temperature if the pressure goes down to 3 mmHG
Answer:
32.4 K
Explanation:
From the given parameters;
Initial pressure P1= 50.0 mmHg
Initial temperature T1= 540K
Final Temperature T2 = ?????
Final pressure P2=3 mmHg
Now using this relationship;
P1/T1 = P2/T2
We have; P1T2= P2T1
Hence;
T2= P2T1/P1
T2= 3 ×540/50.0
T2= 32.4 K
How many moles are in 6.99 x 1020 formula units of magnesium bromide (MgBr2)? Round your answer to 2 decimal places and, if needed, enter scientific notation like this 6.02e23 (would mean 6.02 x 1023.)
Answer:
1.16x10^–3 mole
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.
Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,
Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e
Xmol of MgBr2 = 6.99x10^20/6.02x10^23
Xmol of MgBr2 = 1.16x10^–3 mole
CH3 + HCl <=> CH3Cl + H2O
Kp = 4.7 x 10^3 at 400K.
CH3Cl and HCl combine in 10.00L at 400K. The pressure of CH3OH is 0.250 atm and the pressure of HCl is 0.600 atm (I might have wrote this down wrong).
Does the pressure increase, decrease, or stay the same if equilibrium approaches?
Using Kp, calculate the final partial pressure of HCl at equilibrium.
A student claims the final partial pressure is small but not zero. Justify or argue against this claim and explain why.
Answer:
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Explanation:
Step 1: Data given
Kp = 4.7 x 10^3 at 400K
Pressure of CH3OH = 0.250 atm
Pressure of HCl = 0.600 atm
Volume = 10.00 L
Step 2: The balanced equation
CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)
Step 3: The initial pressure
p(CH3OH) = 0.250atm
p(HCl) = 0.600 atm
p(CH3Cl)= 0 atm
p(H2O) = 0 atm
Step 3: Calculate the pressure at the equilibrium
p(CH3OH) = 0.250 - X atm
p(HCl) = 0.600 - X atm
p(CH3Cl)= X atm
p(H2O) = X atm
Step 4: Calculate Kp
Kp = (pHO * pCH3Cl) / (pCH3* pHCl)
4.7 * 10³ = X² /(0.250-X)(0.600-X)
X = 0.249962
p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm
p(HCl) = 0.600 - 0.249962 = 0.350038 atm
p(CH3Cl)= 0.249962 atm
p(H2O) = 0.249962 atm
Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)
Kp = 4.7 *10³
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
I have 20 electrons and 4 energy levels. *
Answer:
Ca, also known as Calcium
Explanation:
Get a periodic table. In the top left hand corner are of each element's box is a number. This is how many protons are present. Protons are equal to electrons, therefore calcium has 20 electrons. It is in group 2A period 4 if that helps.
When the pressure of a gas doubt, does the volume:
A. Doubles
B.triples
C. Halves
D. Quarters
E. Remains constant
Answer:
it will halves
Explanation:
if the volume is doubled then the pressure is halves.
A solution has a pH of 11.8. What is the pOH?
Answer:
pOH is 2.2
Explanation:
The pH scale goes from 0 to 14. As such, the pH and the pOH add up to 14. Subtract your pH from 14 to get your answer.
14 - 11.8 = 2.2
Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).
C6H12O6⟶2CH3CH2OH+2CO2
The molar mass of glucose is 180.15 g/mol,180.15 g/mol, the molar mass of ethanol is 46.08 g/mol,46.08 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.
a) What is the theoretical yield (in grams) of ethanol from the fermentation of 97.5 g of glucose?
b) If the reaction produced 23.4 g of ethanol, what was the percent yield?
Answer: a) 49.8 gram
b) 47.0 %
Explanation:
First we have to calculate the moles of glucose
[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles[/tex]
The balanced chemical reaction will be,
[tex]C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2[/tex]
From the balanced reaction, we conclude that
As,1 mole of glucose produce = 2 moles of ethanol
So, 0.54 moles of glucose will produce = [tex]\frac{2}{1}\times 0.54=1.08[/tex] mole of ethanol
Now we have to calculate the mass of ethanol produced
[tex]\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}[/tex]
[tex]\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g[/tex]
Now we have to calculate the percent yield of ethanol
[tex]\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%[/tex]
Therefore, the percent yield is 47.0 %
Final answer:
The theoretical yield of ethanol from the fermentation of 97.5 g of glucose is 49.3 g. The percent yield is 47.4% if the actual yield of ethanol is 23.4 g.
Explanation:
To determine the theoretical yield of ethanol, we need to calculate the molar ratio between glucose and ethanol. According to the balanced equation, for every mole of glucose, two moles of ethanol are produced. Therefore, we can set up a proportion and solve for the theoretical yield:
(97.5 g glucose / 180.15 g/mol) x (2 mol ethanol / 1 mol glucose) x (46.08 g/mol) = 49.3 g ethanol
For the percent yield, we can divide the actual yield (23.4 g) by the theoretical yield (49.3 g) and multiply by 100:
(23.4 g / 49.3 g) x 100 = 47.4%
There are three groups that contain carbon but are not organic compounds:
•carbon chlorides
•carbon oxides
•carbon iodides
•carbides
•carbonates
Answer:
Carbonates, Carbides, Carbon oxides
Explanation: Its the answer I promise!!
Most first aid "cold packs" are based on the dissociation of ammonium nitrate (NH4NO3) in water. When the cold pack is activated, the ammonium nitrate (NH4NO3) dissolves in water, producing ammonium (NH4+) and nitrate (NO3-) ions. The "cold pack" then feels cold to touch. What conclusion can be drawn about the bond energy of products and reactants?
A) More energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds.
B) Less energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
D) Less energy was absorbed in the formation of chemical bonds than released in the breaking of chemical bonds.
Answer:C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.
Explanation:
Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is the percent abundance of each isotope? Show all calculations and report to the correct number of sig figs.
Answer : The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
[tex]\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex] .....(1)
Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'
For Li isotope-1 :
Mass of Li isotope-1 = 6.01512 amu
Fractional abundance of Li isotope-1 = x
For Li isotope-2 :
Mass of Li isotope-2 = 7.01600 amu
Fractional abundance of Li isotope-2 = 100-x
Average atomic mass of Li = 6.941 amu
Putting values in equation 1, we get:
[tex]6.941=[(6.01512\times x)+(7.01600\times (100-x))][/tex]
By solving the term 'x', we get:
[tex]x=694.048[/tex]
Percent abundance of Li isotope-1 = [tex]\frac{694.048}{100}=6.94\%[/tex]
Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %
The relative abundance of the isotopes are 7.5% and 92.5%.
The relative atomic mass of an atom is the sum of the products of the relative atomic masses of its isotopes and their respective percentage abundance. We have been told in the question that the relative atomic mass of Li is 6.941 amu. Let the percentage abundance be x and 1-x
6.941 = 6.01512x + 7.01600(1 - x)
6.941 = 6.01512x + 7.01600 - 7.01600x
6.941 - 7.01600 = -1.00088x
-0.075 = -1.00088x
x = -0.075/-1.00088
x = 0.075
Hence, the other isotope is 1 - 0.075 = 0.925
Therefore, the relative abundance of the isotopes is 7.5% and 92.5%
Learn more: https://brainly.com/question/16243729
Sodium Sulfide chemical formula
Answer:
Na2S
Explanation:Just took the test
The chemical formula for the compound formed between sodium and sulfide is Na2S. Sodium has a positive charge and sulfide has a negative charge, which balance when combined in the proportions indicated by the formula.
Explanation:The chemical formula for the ionic compound formed between the sodium cation, Na+, and the sulfide anion, S²-, is Na2S. This is derived from the fact that sodium (Na) has a positive charge and sulfide (S) has a negative charge.
To balance these charges and form a neutral compound, you need two sodium ions for every sulfide ion. Hence the '2' in Na2S.
This indicates there are two sodium ions in the compound.
Learn more about Chemical formula here:https://brainly.com/question/35157423
#SPJ12
Find Number 6. After Titration, Calculate and Enter Molarity of Base
To calculate the molarity of your base, you will first need to write out the balanced equation for the reaction between your acid and base . You will then use the Molarity of Acid , Volume of Acid, and Volume of Base Used to determine the Molarity of the Base. Your sig figs should match with the sig figs used in the Molarity of the Acid.
I’ll give Brainliest
Answer:
where in the book is it
Explanation:
Question 1
1
What happens when a beam of light hits an object?
The light passes through it.
O All the light is absorbed
O A shadow forms.
O All the light is reflected.
Question 2
Final answer:
The correct answer when a beam of light hits an object is that the light can be reflected, absorbed, or transmitted, depending on the material's properties. It is not exclusive to one single outcome.
Explanation:
When a beam of light hits an object, several outcomes are possible depending on the properties of the material: it can be reflected, absorbed, or transmitted. Reflection occurs when light waves bounce off an object, like seeing your reflection in a glass window. Absorbance happens when a material takes in the energy of a light wave, which may later be re-emitted in some cases, such as with phosphorescence. Lastly, transmission is when light passes through a material, like sunlight through a clear glass. So, when a beam of light hits an object, the correct answer is that all the light is not necessarily absorbed, reflected, or transmitted exclusively; it can be a combination of these interactions.
How are today's field galaxies different than distant ones?
Answer:
we cant see them since they are delayed by light years
Explanation:
Answer: The reason why galaxies appear so different between our local universe and the distant one is because we are observing galaxies at different stages of their evolution as we look out in space. Telescopes are time machines, albeit ones that run only in reverse, and so the farther out we look with them, the progressively younger universe we see. Furthermore, we do not observe the universe from any special vantage point. So if we make the reasonable assumption that the physical laws we measure in the local cosmos are universal, we can conclude that the galaxies we observe in the early universe are analogous to the predecessors of the local galaxies. Thus, the differences we see between the different populations of galaxies provide direct insights into the nature of galaxy evolutio
At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? in kelvin
Answer:
T₂ = 251.6 K
Explanation:
Given data:
Initial temperature = 41°C
Initial volume = 4.87 L
Final volume = 6.08 L
Final temperature = ?
Solution:
Initial temperature = 41°C (41+273.15 = 314.15 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 4.87 L × 314.15 K / 6.08 L
T₂ = 1529.9 L.K / 6.08 L
T₂ = 251.6 K
The pressure of 9.0 L of an ideal gas in a flexible container is decreased to one-eighth of its original pressure, and its absolute temperature is decreased to one-ninth of the original. What is the final volume of the gas
Answer:
8L will be the new volume
Explanation:
Let's use the Ideal Gases Law to determine the answer of this question:
Pressure . volume = number of moles . R . T
P . V = n . R . T
We can propose the two situation for the gas:
P₁ . V₁ = n₁ . R . T₁
P₂ . V₂ = n₁ . R . T₂
Notice that R is a constant and n₁ (moles of gas), is not modified with the changes, so we can cancel them.
For the second situation: P₂ = P₁/8 and T₂ = T₁/9
(P₁ . 9L) / T₁ = (P₁/8 . V₂) / T₁/9
(P₁ . 9L) / T₁ . T₁/9 = (P₁/8 . V₂)
P₁ . 1L = P₁/8 . V₂
P₁ . 1L . 8/P₁ = V₂ → 8L
You can also see it, if you put numbers, for example
1 mol of the gas at 1 atm, let's find out the temperature:
1 atm . 9L = 1 mol . 0.082 . T
9/ 0.082 = 110 K
Second situation: 1/8 atm . V = 1 mol . 0.082 . 110/9 K
V = (1 mol . 0.082 . 110/9 K) . 8 atm → 8.02 L ≅ 8L
25 POINTS HELP (6th grade question)
Which landform change due to destructive processes is most easily controlled by human intervention?
A) coastal erosion
B) erosion by glaciers
C) volcanic deposition of lava
D) surface movement in earthquakes
Answer:
A
Explanation:
I did the test
The coastal erosion landform change due to destructive processes is most easily controlled by human intervention. Therefore, option A is correct.
What is coastal erosion ?The term coastal erosion is defined as the process by which local sea level increase, strong wave action, and coastal flooding wear down or carry away rocks, soils, and sands along the coast.
Coastal erosion is caused by hydraulic action, abrasion, impact and corrosion by wind and water, and other forces, natural or unnatural. The softer areas filled with sediment eroded from hard areas, and rock formations are eroded away.
Human activity can rise rates of coastal recession by interrupting the operation of the sediment cell. The construction of major dams of rivers can detain river sediment behind the dam wall.
Thus, option A is correct.
To learn more about the coastal erosion, follow the link;
https://brainly.com/question/20087178
#SPJ6
One liter of 1 M NaOH will completely neutralize one liter of
a
1.0 M H2SO4
b
2.0 M H2SO4
c
1.5 M H2SO4
d
0.50 M H2SO4
Final answer:
One liter of 1 M NaOH can completely neutralize one liter of 0.50 M H2SO4 because 1 mole of NaOH is needed to neutralize 0.5 mole of H2SO4, according to the stoichiometric relationship in the balanced chemical equation. So the correct option is d.
Explanation:
To determine which molarity of H2SO4 will be completely neutralized by one liter of 1 M NaOH, we need to look at the stoichiometry of the reaction. Sulfuric acid is a diprotic acid, meaning it can donate two protons (H+). The balanced chemical equation for its reaction with sodium hydroxide (NaOH), which is a monoprotic base, is:
H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l)
From this equation, we can see that it takes two moles of NaOH to neutralize one mole of H2SO4. Therefore, one liter of 1 M NaOH contains one mole of NaOH, and it can completely neutralize 0.5 mol of H2SO4. If we have one liter of H2SO4, the molarity that would supply 0.5 mol would be 0.50 M, because 0.50 mol/L × 1 L = 0.5 mol. The correct answer is option d - 0.50 M H2SO4.
Give the characteristic of a second order reaction having only one reactant. Group of answer choices The rate of the reaction is proportional to the natural logarithm of the concentration of the reactant. The rate of the reaction is not proportional to the concentration of the reactant. The rate of the reaction is proportional to the square of the concentration of the reactant. The rate of the reaction is proportional to the square root of the concentration of the reactant. The rate of the reaction is directly proportional to the concentration of the reactant.
Answer:
The rate of the reaction is proportional to the square of the concentration of the reactant.
Explanation:
Let us assume a hypothetical reaction in which the rate determining step is the elementary reaction;
2A------> A2
The rate of reaction will be given by:
Rate= k[A]^2
Hence for a second order reaction having only one reactant, the rate of reaction is proportional to the square of the concentration of the reactant. The proportionality constant k, is known as the rate constant of the reaction.