WILL MARK BRAINLIEST! PLEASE HELP
In triangle PQR, mP= 43, PQ=7.5 and PR= 8.4. What is mR to the nearest degree?
A. 64
B. 52
C. 41
D. 60

In triangle ABC mA=43, mB=62 and BC=22 in. What is AB to the nearest tenth of an inch?
A. 28.5
B. 15.6
C. 14.1
D.31.2

thank you.

Answers

Answer 1
Part 1) In triangle PQR, mP= 43, PQ=7.5 and PR= 8.4. What is mR to the nearest degree?

we know that
the law of cosines establishes that
c²=a²+b²-2*a*b*cos C

in this problem

c=QR
a=PQ=7.5
b=PR=8.4
C=angle P=43°
c²=a²+b²-2*a*b*cos C----> c²=7.5²+8.4²-2*7.5*8.4*cos 43°
c²=34.66--------> c=5.89
QR=5.9 

applying the law of sines
7.5/sin R=5.9/sin 43-----> 7.5*sin 43=5.9*sin R---> sin R=7.5*sin 43/5.9
sin R=0.8669---------> R=arc sin (0.8669)----> R=60.11°----> R=60°

the answer Part 1) is the option
D. 60

Part 2) In triangle ABC mA=43, mB=62 and BC=22 in. What is AB to the nearest tenth of an inch?

we know that 
∠C=180-(62+43)-----> ∠C=75°

Applying the law of sines
22/sin 43=AB/sin 75------> AB=22*sin 75/ sin 43-----> AB=31.16 in
AB=31.2 in

the answer Part 2) is
D.31.2

Related Questions

T (2,10) is the midpoint of CD. The coordinates of D are (2,13). What are the coordinates of C?

A. (2, 16)

B. (2, 20)

C. (2, 11.5)

D. (2, 7)

Answers

Your answer should be D because 13-10=3 and 10-3=7 (2, 7)!

What is 3X times 1/6X

Answers

Multiplying an integer by a fraction can be treated as the following operation:

[tex] \frac{3x}{1} * \frac{1}{6x} = \frac{3x}{6x} [/tex]

The x's cancel out, since they're both on the numerator and denominator, so you'll be left with this fraction:

[tex] \frac{3}{6} [/tex]

The fraction can be further simplified by dividing both the numerator and denominator by 3:

[tex]\frac{3}{6} \div \frac{3}{3} = \frac{1}{2}[/tex]

The answer is 1/2.
1/2 x^2

multiply 1/3 and 6

The vertex angle of an isosceles triangle is 20° less than the sum of the base angles. Which system of equations can be used to find the measure of the vertex and base angles?

A)
v + 2b = 180; 2b - 20 = v


B)
v + 2b = 180; 2b + 20 = v


C)
v - 2b = 180; v + 2b = -20


D)
v - 2b = 180; -2b - 20 = v

Answers

The answer to the above question can be explained as under -

We know that, the sum of angles of triangle is 180°.

So, vertex angle plus base angles are equal are equal to 180°.

Let the vertex angle be represented by "v" and base angles be represented by "b".

Thus,  v + b + b = 180°

So,  v + 2b = 180°

Next, the question says, the vertex angle is 20° less than the sum of base angles.

Thus, 2b - 20° = v

Thus, we can conclude that the correct option is A) v + 2b = 180°, 2b - 20° = v

The correct system of equations for an isosceles triangle where the vertex angle is 20 degrees less than the sum of the base angles is v + 2b = 180 for the sum of the angles, and 2b - 20 = v for the relationship between the base angles and the vertex angle. Option A is correct.

The correct system of equations to find the measure of the vertex and base angles of an isosceles triangle, where the vertex angle is 20° less than the sum of the base angles, is given by option A. The two equations can be described as follows:

The sum of the angles in a triangle is 180°, leading to the equation: v + 2b = 180.The vertex angle v is 20° less than the sum of the base angles, giving us the equation: 2b - 20 = v.

To solve for the angles, you would substitute the expression for v from the second equation into the first and then solve for b, which represents the measure of each base angle. Once you have b, you can find v by substituting b back into the second equation.

Is my work correct?

Given: ABCD is an inscribed polygon.

Prove: ∠A and​ ∠C ​ are supplementary angles.

Answers

Solution:

Given: A B CD is an inscribed polygon.

To Prove: ∠A and​ ∠C ​ are supplementary angles.

Proof: Join AC and B D.

Angle in the same segment of a circle are equal.

∠ACB=∠ADB→→AB is a segment.

Also, ∠A B D=∠A CD→→AD is a Segment.

In Δ ABD

∠A+∠ABD+∠ADB=180°→→Angle sum property of triangle.

∠A+∠A CD+ ∠ACB=180°

∠A+∠C=180°

Hence proved, that is, ∠A and​ ∠C ​ are supplementary angles.

The method Adopted by you

∠1=2 ∠A----(1)

and, ∠2=2 ∠C-------(2)

The theorem which has been used to prove 1 and 2, Angle subtended by an arc at the center is twice the angle subtended by it any point on the circle.→(Inscribed angle theorem)

Also, angle in a complete circle measures 360°.→→Chord arc theorem

∠1+∠2=360°→→Addition Property of Equality

2∠A+2∠C=360°→→[Using 1 and 2, Called Substitution Property]

Dividing both sides by 2→→Division Property of Equality

2∠A+2∠C=360°→→[Using 1 and 2]

∠A+∠C=180°

→→Correct work.

A two-column proof to prove that angles A and​ C ​ are supplementary angles should be completed as follows;

Statement                                                  Reason______________

ABCD is an inscribed polygon                   Given

mBCD = 2(m∠A)                                      Inscribed Angle Theorem

mDAB = 2(m∠C)                                      Inscribed Angle Theorem

mBCD + mDAB = 360°               The sum of arcs that make a circle is 360°

2(m∠A) + 2(m∠C) = 360°                        Substitution Property

m∠A + m∠C = 180°                                  Division Property of Equality

∠A and∠C are supplementary angles   Defintion of supplementary angles.

In Mathematics and Euclidean Geometry, the inscribed angle theorem states that the measure of an inscribed angle is one-half the measure of the intercepted arc in a circle or the inscribed angle of a circle is equal to half of the central angle of a circle.

Generally speaking, a supplementary angle refers to two angles or arc whose sum is equal to 180 degrees.

Based on the defintion of supplementary angles, we can logically deduce that angle A and angle C are supplementary angles.

A cube has a side length of 120 cm, what is its volume in cubic meters? (100 cm = 1 m)

Answers

the volume is V=a^3
a=120 cm and a=1.2m
V=120^3=1,728,000 cm^3
V=1,728 m^3

The value of volume of cube is,

⇒ V = 1.728 meter³

What is mean by Cuboid?

A cuboid is the solid shape or three-dimensional shape. A convex polyhedron which is bounded by six rectangular faces with eight vertices and twelve edges is called cuboid.

Given that;

A cube has a side length of 120 cm.

Since, We know that;

1 m = 100 cm

Hence,

120 cm = 120 / 100 m

            = 1.2 m

So, Volume of cube is,

⇒ V = side³

⇒ V = 1.2³

⇒ V = 1.728 meter³

Thus,  volume of cube is,

⇒ V = 1.728 meter³

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A briefcase lock has 3 roating cylinders, each containing 10 digits. How many numerical codes are possible?

Answers

Since there are 10 digits, and 3 cylinders we can find the possible amount of numerical codes by multiplying 10, 3 times

10*10*10=1000

There would be 1000 possible numerical codes

I hope this helps.. sorry if it’s confusing or anything

Step-by-step explanation:

If the numbers can be repeated, we have such numeric codes:

10 · 10 · 10 = 1,000

If the numbers can not be repeated, then we have such numeric codes:

10 · 9 · 8 = 720

Simplify the rational expression. state any excluded values. 4x - 4/ x - 1

Answers

We need to simplify this expression:

[tex] \frac{4x-4}{x-1} [/tex]

So, we will call this expression as:
[tex] f(x) = \frac{4x-4}{x-1} [/tex]

We can write this equation like this:

[tex]f(x) = \frac{4(x-1)}{(x-1)} [/tex]

So, if we simplify it, this can be written like this:

f(x) = 4 but given that the denominator can't be zero, then:
[tex] x-1 \neq 0 [/tex] ∴ [tex]x \neq 1[/tex] 

Therefore:
f(x) = 4 if and only if [tex]x \neq 1[/tex] 

Answer:

1 and 4 i believe

Step-by-step explanation:

David, Egil and Frances share money in the ratio 2:7:9. David gets £25. Work out how much Egil and Frances get.

Please help. Needed for tomorrow.

Answers

Money is shared among David, Egil and Frances in the ratio 2:7:9 and David gets £25, thus Egil and Frances will get:
Egil:
(ratio of Egil to David)×(Amount David gets)
7/2×25
=£87.5

Frances:
(ratio of Frances to David)×(Amount David gets)
9/2×25
=£112.5

The base edge of the regular triangular pyramid is b=10 cm and altitude of the base hb ≈ 8.66 cm. The slant height of the pyramid is k=8 cm. Find:
Lateral area and Surface area of the pyramid

Answers

Answer:

Step-by-step explanation:

It is given that the base edge of the regular triangular pyramid is b=10 cm and altitude of the base h =8.66 cm. The slant height of the pyramid is k=8 cm.

Now, the lateral surface area of the pyramid is given as:

[tex]LSA={\frac{3}{2}}(b)(k)[/tex]

Substituting the given values, we have

[tex]LSA=\frac{3}{2}(10)(8)[/tex]

[tex]LSA=120cm^2[/tex]

Thus, the Lateral surface area of the pyramid is [tex]120cm^2[/tex].

Now, the surface area is given as:

[tex]SA=\frac{1}{2}bh+LSA[/tex]

[tex]SA=\frac{1}{2}bh+120[/tex]

[tex]SA=\frac{1}{2}(10)(8.66)+120[/tex]

[tex]SA=43.3+120[/tex]

[tex]SA=163.3cm^2[/tex]

Thus, the surface area of the pyramid will be [tex]163.3cm^2[/tex].

The Lateral area is 120 cubic cm, and the Surface area of the pyramid is 163.3 cubic cm.

What is a pyramid?

A polyhedron that has a polygonal base and triangles for sides, is a pyramid.

The lateral area of the pyramid is equal to the area of its three triangular lateral faces is;

[tex]\rm Lateral \ Area=3 \times \dfrac{1}{2}\times b \times k\\\\ Lateral \ Area=3 \times \dfrac{1}{2}\times 10 \times 8\\\\ Lateral \ Area=120[/tex]

The surface area of the pyramid is;

[tex]\rm Surface \ area=\dfrac{1}{2}bh + Lateral \ area\\\\Surface \ area=\dfrac{1}{2}\times 10 \times 8.66 +120\\\\Surface \ area=43.3+120\\\\Surface \ area=163.3 \ cm^3[/tex]

Hence, the Lateral area is 120 cubic cm, and the Surface area of the pyramid is 163.3 cubic cm.

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If you buy a computer directly from the manufacturer for $ 2,469 and agree to repay it in 48 equal installments at 2.1 % interest per month on the unpaid​ balance, how much are your monthly​ payments? How much total interest will be​ paid?

Answers

Final answer:

The monthly payments would be approximately $61.02 and the total interest paid would be approximately -$764.04.

Explanation:

To calculate the monthly payments, you can use the formula for the monthly payment on a loan:

P = (r * PV) / (1 - (1 + r)^-n)

Where:

P is the monthly paymentr is the monthly interest ratePV is the present value or the loan amountn is the total number of payments

Using the given values, we can calculate:

P = (0.021 * 2469) / (1 - (1 + 0.021)^-48)

P ≈ $61.02

Therefore, the monthly payments would be approximately $61.02.

To calculate the total interest paid, you can multiply the monthly payment by the total number of payments and subtract the loan amount:

Total Interest = (P * n) - PV

Total Interest ≈ ($61.02 * 48) - $2469

Total Interest ≈ $1704.96 - $2469

Total Interest ≈ -$764.04

Therefore, the total interest paid would be approximately -$764.04. This negative value indicates that you will pay back less than the initial loan amount.

In football, a field goal is worth 3 points, and the extra point after a touchdown is worth 1 point. During the 2006 season, John Kasay, of the Carolina Panthers scored a total of 100 points for his team by making a total of 52 field goals and extra points combined. How many 3 point field goals did he make?


Answers

24 field goals and 28 extra points. 

You can get this by setting up the system of equations:

x + y = 52 (total number of kicks)
3x + y = 100 (points)

Jack runs 3 miles in 27 minutes. at this constant rate how long will it take him to run 10 miles answer

Answers

Let x = the unknown amount of time it takes to run 10 miles. We are going to use this to set up a proportion and then crossmultiply.

[tex] \frac{3 miles}{27 min} = \frac{10 miles}{x min} [/tex]

Now we cross-multiply

3x = 27(10)
3x = 270
x = 90

It will take Jack 90 minutes to run 10 miles.

Apologies for the delayed answer. I'm surprised no one saw this before. 

You hold $25 in a savings account and you deposit an equal amount into your account each week after 5 weeks the account holds $170 write an equation that represents the amount y in dollars of money in the account after x weeks

Answers

First find amount you deposit each week.
25+5w=170
5w=145
w=29

You deposit $29 each week, so after x weeks:
25+29x=y

Use the x-intercept method to find all real solutions of the equation. x^3-9x^2+23x-15=0

Answers

hey user


the answer to this is going to be


hope it helped 

if u need more help plz let me know


thanks have a good day boi

see u 

if u need more help plz let me know 

thanks 

-im out
For this case we have the following function:
 x ^ 3-9x ^ 2 + 23x-15 = 0
 Rewriting we have:
 (x-5) * (x-3) * (x-1) = 0
 Therefore, the solutions are given by:
 Solution 1:
 x-5 = 0
 x = 5
 Solution 2:
 x-3 = 0
 x = 3
 Solution 3:
 x-1 = 0
 x = 1
 Answer:
 
x = 5
 
x = 3
 
x = 1

On average, Carson spends $2 of his $20 monthly allowance on library fines. What percent of his allowance is spent on library fines?

Answers

20 x 5 = 100
2 x 5 = 10
10/100 = .1
he spends 10%
10% of twenty because twenty goes into one hundred Five-0 times and 2 x 5= 10

For parametric equations x= a cos t and y= b sin t, describe how the values of a and b determine which conic section will be traced

Answers

In mathematics, a conic section is a curve obtained as the intersection of the surface of a cone with a plane. The four types of conic section are the hyperbola, the parabola, the circumference and the ellipse.

For the problem we have this parametric equation:

(1) [tex]\left\{{{x=acost}\atop{y=bsint}}\right[/tex]

From geometry, we know that we can express a circumference in terms of parameters like this:

(2) [tex]\left \{ {{x=rcost} \atop {y=rsint}}\right[/tex]

being r the radius of the circumference.

On the other hands, we know that a ellipse can be expressed in terms of parameters like this:

(3) [tex]\left \{ {{x=acost} \atop {y=bsint}}\right[/tex]

Therefore, we will have three answers that are the cases for the values a and b, namely.

Case 1: Circumference

To the case of a circumference, the more simple ordinary equation is given by:

(4) [tex]x^{2} + y^{2} = r^{2}[/tex]

Substituting (1) into (4):

[tex]a^{2}cos^{2}t+b^{2}cos^{2}t=r^{2}[/tex]

But because of the equation (2), necessarily:

[tex]a = b = r[/tex]

Case 2: Ellipse (focal axis matches the x-axis) 

In this case, the simple ordinary equation is given by:

(5) [tex]\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1[/tex]


being a and b semi-major axis and semi-minor axis respectively. 

Given that a an b are variables of the parametrization, and a and b are variables of the ellipse as well, to avoid confusion we will modify the equation (5) like this:

(6) [tex]\frac{x^{2}}{a'^{2}}+\frac{y^{2}}{b'^{2}}=1[/tex]

So, substituting (2) into (6):

[tex]\frac{a^{2}cos^{2}t}{a'^{2}}+\frac{b^{2}cos^{2}t}{b'^{2}}=1[/tex]

Necessarily:

[tex]a=a'[/tex]  and  [tex]b=b'[/tex] 

and given that the focal axis matches the x-axis, then:

[tex]a>b[/tex] 


Case 3: Ellipse (focal axis matches the y-axis) 

In this case, applying the same previous reasoning, the simple ordinary equation is given by:

(7) [tex]\frac{x^{2} }{b'^{2}}+\frac{y^{2}}{a'^{2}}=1[/tex]

being a' and b' semi-major axis and semi-minor axis respectively. 

So, substituting (2) into (7):

[tex]\frac{a^{2}cos^{2}t}{b'^{2}}+\frac{b^{2}cos^{2}t}{a'^{2}}=1[/tex]

Necessarily:

[tex]a = b'[/tex]  and  [tex]b = a'[/tex] 

and given that the focal axis matches the y-axis, then:

[tex]a<b[/tex] 

Finally, the conclusions are:

1. If [tex]a = b[/tex] then a circumference will be traced. (See Figure 1)

2. If [tex]a>b[/tex] then a ellipse will be traced with focal axis matching the x-axis. (See Figure 2)

3. If [tex]a<b[/tex] then a ellipse will be traced with focal axis matching the y-axis. (See Figure 3)

How the values of a and b determine which conic section will be traced was discussed thoroughly.

What is a conic section?

A conic section is a curve obtained as the intersection of the surface of a cone with a plane.

The given parametric equations are:

[tex]x=acos t[/tex]

[tex]\frac{x}{a} =cost[/tex]....(1)

[tex]y=bsint[/tex]

[tex]\frac{y}{b} =sint[/tex]....(2)

Adding the squares of (1) and (2)

[tex](\frac{x}{a} )^2+(\frac{y}{b} )^2=cos^{2} t + sin^{2} t[/tex]

We know [tex]cos^{2} t + sin^{2} t=1[/tex]

So, [tex]\frac{x^{2} }{a^{2} } +\frac{y^2}{b^2} =1[/tex]........(3)

If [tex]a=b[/tex], (3) will be reduced into:

[tex]x^{2} +y^{2} =a^{2}[/tex] representing a circle.

If [tex]a > b[/tex], (3) will represent an ellipse with the length of the major axis > length of the minor axis.

if [tex]a < b,[/tex] (3) will represent an ellipse with the length of the major axis < length of the minor axis.

Thus, How the values of a and b determine which conic section will be traced was discussed thoroughly.

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A solid oblique pyramid has a square base with an edge length of 2 cm. Angle BAC measures 45°.What is the volume of the pyramid?2.4 cm33.6 cm34.8 cm37.2 cm3

Answers

Answer:4.8cm^3

Step-by-step explanation:I got it right on edge.

On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if each grid unit equals one centimeter?

Answers

Let
A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and 
AB and AD are perpendicular 
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure


Find the surface area 4cm 5cm 6cm 13cm

Answers

[tex]A_\Delta=\dfrac{1}{2}\cdot6\cdot4=12\ cm^2\\\\A_{[]_1}=6\cdot13=78\ cm^2\\\\A_{[]_2}=5\cdot13=65\ cm^2\\\\A=2A_\Delta+A_{[]_1}+2A_{[]_2}\\\\A=2\cdot12+78+2\cdot65=24+78+130=232\ cm^2[/tex]

What is the volume of a pyramid with slant height 17 feet and square base with edges of 16 feet?

Answers

check the picture below.

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ ------\\ B=\stackrel{16\times 16}{256}\\ h=15 \end{cases}\implies V=\cfrac{1}{3}(256)(15)\implies V=1280[/tex]

The volume of the pyramid is 1280 cubic feet.

To find the volume of a pyramid, we can use the formula:

Volume = (1/3) * Base Area * Height

Given that the pyramid has a square base with edges of 16 feet, the base area (A) is calculated as:

[tex]Base Area (A) = side^2\\A = 16^2 = 256 square feet[/tex]

The height of the pyramid can be found using the Pythagorean theorem. The height, slant height, and half the length of a side form a right triangle. The half length of a side is 16/2 = 8 feet. The slant height is 17 feet. So, using the Pythagorean theorem:

[tex]Height^2 + (Half side length)^2 = Slant height^2\\Height^2 + 8^2 = 17^2\\Height^2 + 64 = 289\\Height^2 = 289 - 64\\Height^2 = 225\\Height = \sqrt{225}\\Height = 15 feet\\[/tex]

Now that we have the base area (A = 256 square feet) and the height (h = 15 feet), we can find the volume:

Volume = (1/3) * 256 * 15

Volume = (1/3) * 3840

Volume = 1280 cubic feet

Therefore, the volume of the pyramid is 1280 cubic feet.

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Let f(x)=-4x+7 and g(x)=10x-6. Find f(g(x))

Answers

[tex]\bf \begin{cases} f(x)=-4x+7\\ g(x)=10x-6 \end{cases}\qquad \qquad f(~~g(x)~~)=-4[g(x)]+7 \\\\\\ f(~~g(x)~~)=-4[10x-6]+7\implies f(~~g(x)~~)=-40x+24+7 \\\\\\ f(~~g(x)~~)=-40x+31[/tex]

The diagram below shows triangle MNR with ray NM.
-
What is the measure of MRN?

Answers

Answer:

The answer is 18

Step-by-step explanation:

Subtract 115 from 180

Add 65 and 97

Subtract 162 from 180

The measure of ∠MRN  is 18°

What is sum of angles of a triangle?

The sum of angles of a triangle equals the straight angle which is 180°.

According to ques

∠RNM= 97°

∠RMA = 115°

∠RMA +∠RMN = 180° ( sum of angles on straight line )

115° + ∠RMN = 180°

∠RMN = 180° - 115°

∠RMN = 65°

∠RMN + ∠MRN + ∠RNM = 180° ( Sum of angles of triangle )

65° + ∠MRN + 97° = 180°

162° + ∠MRN  = 180°

∠MRN = 180° - 162°

∠MRN = 18°

Hence ,  measure of ∠MRN is 180°

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A number is chosen at random from 1 to 10. find the probabilty of not selecting a multiple of 3

Answers

How many numbers from 1 to 10 are not a multiple of 3? 1, 2, 4, 5, 7, 8, 10 means there are 7 
So the probability is 7/10 = .7 = 70%

the height h of the equilateral triangle below is given by y= 5 cot theta where theta = 30 degrees
A) 2.9
B)4.3
C)7.1
D)8.7

Answers

To solve this we can take two different approaches:

1. We can substitute theta by 30° and evaluate our expression using a calculator: 
[tex]y=5cot( \alpha )[/tex]
[tex]y=5cot(30)[/tex]
[tex]y=8.7[/tex]

2. We can use the unitary circle and the fact that [tex]cot \alpha = \frac{cos( \alpha }{sin( \alpha )} [/tex], so we can rewrite our expression as follows:
[tex]y=5cot( \alpha )[/tex]
[tex]y=5 \frac{cos( \alpha )}{sin( \alpha )} [/tex]
[tex]y= \frac{cos(30)}{sin(30)} [/tex]
From our unitary circle we can check that [tex]cos(30)= \frac{ \sqrt{3} }{2} [/tex] and [tex]sin(30)= \frac{1}{2} [/tex]. 
Lets replace those values in our expression and simplify:
[tex]y= \frac{ 5(\frac{ \sqrt{3} }{2})}{ \frac{1}{2} }[/tex]
[tex]y=5 \sqrt{3} [/tex]
[tex]y=8.7[/tex]

Either way we can conclude that the correct answer is: D)8.7

In a 3-4-5 right triangle which expression would provide the measure of the smallest acute angle

Answers

The possible expressions for the measure of the smallest acute angle

     [tex]sin\:\theta =\frac{3}{5}\:or\:\theta =sin^{-1}\left(\frac{3}{5}\right)[/tex]

     [tex]cos\:\theta =\frac{4}{5}\:or\:\theta =cos^{-1}\left(\frac{4}{5}\right)[/tex]

     [tex]tan\:\theta =\frac{3}{4}\:or\:\theta =tan^{-1}\left(\frac{3}{4}\right)[/tex]

These three expressions are the possible measure of the smallest acute angle. 

PLZZZZZZ HELPPPP MEEEE!!!!!!!!

Determine the number of real solutions for each system of equations.

Answers

To solve this we are going to graph each one of the system of equations. The points in which the graphs of the tow equations intercepts will be the real solutions of the system of equations.

System A. Since the graph of the equations intercepts two times, we can conclude that the system has 2 real solutions. 

System B. Since the graph of the equation don't intercept, we can conclude that the system has 0 real solutions.

System C. Since the graph of the equations intercepts two times, we can conclude that the system has 2 real solutions.

Answer:

First box is 2, second box is 0, and the third box is 1.

Step-by-step explanation:

Find the difference sqrt 20- sqrt 80

Answers

First you need to reduce each square root.  In each case, find the largest perfect square factor under the radical.  

in the case of sqrt(20), that boils down to 4*5, so sqrt(20)=sqrt(4)*sqrt(5), or 2sqrt(5).

sqrt(80) = sqrt(16)*sqrt(5) = 4sqrt(5).

Final answer:  subtract 4 sqrt(5) from 2 sqrt(5).  Can you do this?

Final answer:

The difference between sqrt(20) and sqrt(80) is -2sqrt(5).

Explanation:

To find the difference sqrt(20) - sqrt(80), we can simplify each square root by factoring out perfect squares.

The number 20 can be factored into 4×5, and 80 can be factored into 16×5. Since 4 and 16 are perfect squares, they can be taken out of the square root as 2 and 4, respectively.

Therefore, the expressions simplify to:

sqrt(20) = sqrt(4×5) = sqrt(4) × sqrt(5) = 2sqrt(5)

sqrt(80) = sqrt(16×5) = sqrt(16) × sqrt(5) = 4sqrt(5)

Now we can find the difference:

2sqrt(5) - 4sqrt(5) = -2sqrt(5)

So the difference between sqrt(20) and sqrt(80) is -2sqrt(5).

Geometry Problem (PIC)

Answers

Look at the picture.


[tex]\Delta ADC\ and\ \Delta CDB\ are\ similar\ therefore\\\\\dfrac{y}{4}=\dfrac{9}{y}\ \ \ \ |cross\ multiply\\\\y\cdot y=4\cdot9\\\\y^2=36\to y=\sqrt{36}\to y=6[/tex]

HELP PLS!! FIND THE AREA!!!

Answers

the figure is really just 3 triangles and 1 rectangle, as you see in the picture below.

notice the blue triangle has a base of 3 and a height of 2,

the green triangle has a base of 6 and a height of 1,

the yellow triangle has a base of 2 and a height of 6,

and the rectangle is a 7x6 rectangle.

we can simply get the area of each and sum them up, that's the area of the figure.

[tex]\bf \stackrel{\textit{blue triangle}}{\frac{1}{2}(3)(2)}~~~~+~~~~\stackrel{\textit{green triangle}}{\frac{1}{2}(6)(1)}~~~~+~~~~\stackrel{\textit{yellow triangle}}{\frac{1}{2}(2)(6)}~~~~+~~~~\stackrel{\textit{rectangle}}{7\cdot 6}[/tex]

how many terms are in the arithmetic sequence shown below?
15, 7, -1, -9...,-225

Answers

Final answer:

To determine the number of terms in the given arithmetic sequence, we calculate the common difference and apply the formula for the nth term. With a common difference of -8 and an nth term of -225, we find that there are 31 terms in the sequence.

Explanation:

To find out how many terms are in the arithmetic sequence 15, 7, -1, -9,..., -225, we need to determine the common difference and use the formula for the nth term of an arithmetic sequence, which is an = a1 + (n - 1)d, where an is the nth term, a1 is the first term, n is the number of terms, and d is the common difference.

In this sequence, the common difference d is 7 - 15 = -8. Now we use the formula with an = -225, a1 = 15, and d = -8 to find n.

Plugging these values into the formula, we get:
-225 = 15 + (n - 1)(-8)
-225 = 15 - 8n + 8
-225 = 23 - 8n
-248 = -8n
n = 31

Therefore, there are 31 terms in the arithmetic sequence.

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