Write how you would use numbers to investigate each object

Mass of the dummy m = 75 kg

Net Force on the dummy [tex]F_{net}  = -825 N[/tex] since it is given that the force is towards the backside of the car.

Acceleration of the dummy a = ?

Using Newton's 2nd law of motion, we have

[tex]F_{net}  = ma[/tex]

-825 = (75)a

Hence, [tex]a =  \frac{-825}{75}[/tex]

Acceleration of the dummy is -11 [tex]m/s^{2}[/tex]

The negative sign indicates that the dummy is slowing at a rate of 11 [tex]m/s^{2}[/tex]

Answer:

        Acceleration towards rear = 11 [tex]m/s^2[/tex]

        Acceleration towards direction of movement of dummy  = -11 [tex]m/s^2[/tex]

Explanation:

  Mass of dummy = 75 kg

   Force acted towards rear of the car = 825 N

   We have Force acting on a body = Mass of body * Acceleration of body

   Substituting the given values in the above equation we will get

        825  = 75 * a

         a = 11 [tex]m/s^2[/tex]

        So acceleration towards rear = 11 [tex]m/s^2[/tex]

        Acceleration towards direction of movement of dummy  = -11 [tex]m/s^2[/tex]

Bohr’s model showed that electron orbits had distinct radii.

Answer:

bohr developed a model of the atom that predicts how it will behave

Explanation:  

a p e x :)

here two cars are placed on an aluminium track

so there is no friction on two carts during their motion and hence there is no external force on them

now if there is no external force so momentum is conserved

[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f][/tex]

here

[tex]m_1 = m_2 = 0.4 kg[/tex]

[tex]v_{1i} = 1.5 m/s[/tex]

[tex]v_{2i} = 0[/tex]

now plug in all values in it

[tex]0.4 * 1.5 + 0 = 0.4* v_{1f} + 0.4*v_{2f}[/tex]

divide whole equation by mass 0.4

[tex]v_{1f} + v_{2f} = 1.5[/tex]

also be the equation of coefficient of restitution

[tex]e = 1 = \frac{v_{2f} - v_{1f}}{v_{1i} - v_{2i}}[/tex]

now we have

[tex]v_{2f} - v_{1f} = 1.5[/tex]

now by solving above equations we will have

[tex]v_{2f} = 1.5 m/s[/tex]

[tex]v_{1f} = 0[/tex]

so after collision speed of two carts is 0 m/s and 1.5 m/s after collision

Area is the scalar quantity,

Answer:

The correct answer is option B.

Explanation:

Scalar quantity are those which only have magnitude and no direction.

For example:  mass, time, distance etc.

Vector quantity are those which have  both magnitude and direction.

For example:  displacement , velocity etc.

From the given options, the quantity which is scalar is are a because it only has magnitude but no directions.

Where acceleration, velocity, displacement  and force all are vector quantities.

Hence, the correct answer is option B.

The Sun is a star around which our planet Earth and other planets and satellites of our solar system revolve along specific orbits. Sun appears to be spherical in shape and consists of glowing hot gases. It contains mostly hydrogen and helium gases. The temperature of the gas mixture is extremely high.

Therefore, the Sun mostly composed of hydrogen and helium gases.

(Answer) B. Composition mostly hydrogen and helium gas, Mass 1.989 x 10^30 Kg

Answer:

Third displacement = 2.81 m which is 61.70° north of east.

Explanation:

   Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

  She sails 2 km east, displacement = 2 i

  Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis

  Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j

  Let third displacement be x i + y j

  We have final displacement = 5.80 km east = 5.80 i

  From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j

                                                                           = (4.47+x) i + (y - 2.47) j

  Comparing both , we have 4.47+x = 5.80

                                                        x = 1.33

                                                 y-2.47=0

                                                         y = 2.47 j

  So third displacement = 1.33 i + 2.47 j

  Magnitude of third displacement = [tex]\sqrt{1.33^2+2.47^2} =2.81m[/tex]

  θ = tan⁻¹(2.47/1.33) = 61.70°

  So third displacement = 2.81 m which is 61.70° north of east.

In the absence of air resistance , object fall with  same acceleration .

In the absence of air resistance, objects fall at constant acceleration.

Object falling in absence of air resistance is tantamount to object falling in a vacuum. The experiment was performed in Italy by a Physicist known as Galilio Galilian. He dropped two different objects of different masses in the absence of air and discovered that they both landed at the same time.

The objects falling in the absence of air resistance will experience a free fall. And the formula for free fall are :

Non of the above formula depends on the mass of the object but the acceleration due to gravity and the height at which they are falling.

And since the acceleration due to gravity is constant, therefore, In the absence of air resistance, objects fall at constant acceleration due to gravity.

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Newton's 2nd law of motion:

F = ma

F is force, m is mass, and a is acceleration.

In an attempt to reduce our dependence on non-renewable resources, and cut down on the harm to the environment, we could burn biomass to produce electricity.

Speed of the cannon is 95 m/s

now we will find its two components

speed in horizontal direction is

[tex]v_x = 95 cos15[/tex]

[tex]v_x = 91.76 m/s[/tex]

speed in vertical direction is

[tex]v_y = 95 sin(-15)[/tex]

[tex]v_y = -24.6 m/s[/tex]

now the time taken by the cannon to reach the water surface will be find out by using kinematics

[tex]\Delta y = v_y * t + \frac{1}{2} at^2[/tex]

[tex]-3 = -24.6 * t - \frac{1}{2}9.8 * t^2[/tex]

[tex]4.9t^2 + 24.6 t - 3 = 0[/tex]

By solving above quadratic equation

[tex]t = 0.12 s[/tex]

now in the same time the horizontal distance moved by the cannon

[tex]d_x = v_x * t[/tex]

[tex]d_x = 91.76 * 0.12[/tex]

[tex]d_x = 10.93 m[/tex]

Since the distance of crewmen is 20 m so it will definitely safe as cannon will hit at distance 10.93 m

Complete solution is given below in attachment

A. Lowering the temperature.

The anser is going to be A.Lowering the temperature.

I HOPE THIS HELPS YOU OUT ALLOT

Answer:

Bohr atomic model

Explanation:

Bohr's atomic model:

Bohr's atomic model was proposed by Neil Bohr in 1913. In this atomic model  Neil Bohr's modified the Rutherford Model and show how electrons in an atoms moves around the nucleus in stable orbits. According to Rutherford model electron's in atoms are filled in orbits and these electron moves around the nucleus in these orbits like planets moves around the sun in fixed orbit but Rutherford's model was unable to show the stability of orbits. To solve this problem, Bohr proposed a new model b. According to this model electrons move around the nucleus in fixed size orbits which have fixed energy and the electron with low energy is filled in smaller size orbit. Radiation are emitted from atoms only when transition of electron from higher energy orbit to lower energy orbit takes place.

(a) the horizontal force is 11.3 N

(b) The tension in the thread is 22.6 N

Draw a free body diagram for the suspended metal ball as shown in the figure. The tension T acts along the length of the thread, the force F is the horizontal force and its weight is mg, which acts vertically down wards.

Resolve the tension into two components- T cos 30 along the vertical and T sin30 along the horizontal as shown in the figure.

Apply the condition for equilibrium along the horizontal direction.

[tex]F=Tsin30........(1)[/tex]

Apply the condition for equilibrium along the vertical direction.

[tex]mg=Tcos30.......(2)[/tex]

Divide equation (1) by equation (2) and write an expression for F.

[tex]\frac{F}{mg} = tan30\\ F=mgtan30[/tex]

Substitute 2 kg for m and 9.81 m/s² for g.

[tex]F=mgtan30\\ =(2kg)(9.81m/s^2)(tan30^o)\\ =11.3N[/tex]

The horizontal force required to keep the ball taut is 11.3 N

From equation (2),

[tex]T=\frac{mg}{sin30} \\ =\frac{(2kg)(9.81m/s^2)}{sin30^o} \\ =22.6N[/tex]

Thus, the tension in the thread is 22.6 N

The mass of strawberries after freeze-drying would be significantly less than their original mass, given that most of the water content is removed during the process. For 100 kg of fresh strawberries, the approximate mass after freeze-drying would be about 8.4 kg, assuming 91.6% water content.

The approximate mass of strawberries after freeze-drying can be calculated by considering the water content in the fresh strawberries. Fresh strawberries consist of about 91.6% water. During the freeze-drying process, most of this water is removed, hence reducing the mass significantly.

To estimate this change in mass, we can subtract the mass of water (91.6% of the original mass) from the total mass of the fresh strawberries (100 kg). Thus, the dried strawberries would approximately be 8.4% of their original mass, since the mass of fructose and other non-water components remain. This is an estimation and the actual number can be slightly higher or lower depending on the exact freeze-drying process and the specifics of the strawberries.

Therefore, after freeze-drying 100 kg of fresh strawberries, which originally consist of 91.6% water, the approximate mass of the strawberries would be about 8.4 kg.

Answer:

1) time t = 9 s

2) velocity v  = 26.4 m/s 2.17° east of north

Explanation:

1

Given

velocity of sea lion [tex]v_s = 40.0 kmph[/tex]

velocity of the fish [tex]v-f = 16 kmph[/tex]

Distance  between the fish and sea lion d = 60 m

Solution

Relative velocity of the sea lion with respect to the fish

[tex]v = v_s - v_f\\\\v = 40 - 16\\\\v = 24.kmph\\\\v = 24 \times \frac{1000}{60 \times 60}  m/s\\\\v = 6.67 m/s[/tex]

Time

[tex]t = \frac{d}{v} \\\\t = \frac{60}{6.67} \\\\t = 9 s[/tex]

2

Given

velocity of the truck [tex]v_t = 25 m/s[/tex]

velocity of the dog [tex]v_d = 1.75 m/s[/tex]

Angle [tex]\theta = 35.0^o[/tex]

Solution

Dog moves in north east so

Component of velocity in East

[tex]v_{d,E} = v_dsin\theta\\\\v_{d,E} = 1.75 \times sin35\\\\v_{d,E} = 1.004 m/s[/tex]

Component of velocity in North

[tex]v_{d,N} = v_dcos\theta\\\\v_{d,N} = 1.75 \times cos35\\\\v_{d,N} = 1.434 m/s[/tex]

The velocity of Dog relative to the road = velocity of the dog relative to truck + velocity of the truck relative to the road

Y component

[tex]v_y = v_t + v_{d,N}\\\\v_y = 25 + 1.434\\\\v_y = 26.434 m/s[/tex]

X component

[tex]v_x = v_{d,E}\\\\V_x = 1.004 m/s[/tex]

Velocity

[tex]v = \sqrt{v_x^{2} +v_y^{2} } \\\\v = \sqrt{1.004^2 + 26.434^2} \\\\v = 26.4 m/s[/tex]

Direction

[tex]\phi = tan^{-1}\frac{v_x}{v_y} \\\\\phi = tan^{-1}\frac{1.004}{26.434} \\\\\phi = 2.17^o east of north[/tex]

For the time and velocity:

The sea lion will catch the fish in 0.42 seconds.

The velocity of the dog relative to the road is 26.41 m/s north.

Question 1: Formula:

Relative velocity = vA - vB

The sea lion is moving at a relative velocity of 40.0 - 16.0 = 24.0 km/h faster than the fish.

The distance between the sea lion and the fish is 60.0 m, which is 0.160 km.

The time it takes the sea lion to catch the fish is:

time = distance / relative velocity

= 0.160 km / 24.0 km/h

= 0.007 h

= 0.42 seconds

Therefore, it would take the sea lion 0.42 seconds to catch the fish.

Question 2: Formula:

Relative velocity = vA + vB

The velocity of the dog relative to the road can be found by adding the velocity of the truck and the velocity of the dog.

The velocity of the truck is 25.0 m/s north.

The velocity of the dog can be broken down into two components: a northward component of 1.75 × cos(35.0°) = 1.41 m/s and an eastward component of 1.75 × sin(35.0°) = 1.18 m/s.

Therefore, the velocity of the dog relative to the road is 25.0 + 1.41 = 26.41 m/s north.

The direction of the velocity of the dog relative to the road is north.

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force of friction on the cart is given as

[tex]F_f = 280 N[/tex]

here we also know the reaction force due to surface

[tex]R = 766 N[/tex]

so we can say reaction force is given as

[tex]R = \sqrt{F_n^2 + F_f^2}[/tex]

[tex]766 = \sqrt{F_n^2 + 280^2}[/tex]

[tex]F_n^2 = 766^2 - 280^2[/tex]

[tex]F_n = 713 N[/tex]

now by force balance we will say

[tex]F_y + F_n = mg[/tex]

[tex]F_y = mg - F_n[/tex]

[tex]F_x = F_f[/tex]

also we know that

[tex]F_f = \mu * F_n[/tex]

[tex]280 = \mu * 713[/tex]

[tex]\mu = 0.39[/tex]

now minimum force required to set this into motion

[tex]F_{min} = \frac{\mu mg}{\sqrt{1 + \mu^2}}[/tex]

here we know that

[tex]mg = F_n = 713 N[/tex]

[tex]F_{min} = \frac{0.39* 713}{\sqrt{1 + 0.39^2}}[/tex]

[tex]F_{min} = 259 N[/tex]

So it will require 259 N minimum force to move it

The internal pressure increases as the gas is heated

Answer:

could someone at least give one answer instead of a choice between two cause that is a 50/50 chance to get it correct on a test!!

Explanation:

when heat energy is added to a system, change in system can be:

If they're dropped from the same height at the same time and there's no air resistance, the the lighter ball and the heavier ball, as well as a feather, a hammer, a bowling ball, a speck of dust, a school bus, and a battle ship, will all fall side-by-side and hit the ground at the same time.  

We've known this for about 400 years, since Galileo.  And we've known WHY for about 300 years, since Newton.

Thallium (Tl) is a solid at room temperature. It has a melting point of 304 degrees Celsius and a boiling point of 1,473 degrees Celsius.

Thallium (Tl) is a chemical element that is classified as a metal. At standard temperature and pressure conditions, thallium exists in a solid state. This means that it maintains a fixed shape and volume.

The state of matter of an element or compound is determined by its melting and boiling points.

However, at room temperature (around 25 degrees Celsius), thallium remains in its solid state. It has a metallic appearance and is relatively soft and malleable.

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The arrow in a chemical reaction can be translated as the following:

A. yields

C. react to form

The arrrow in a chemical reaction is translated to mean a reactant combines to yield or react to form a product: Option A and C are correct.

Arrows in a chemical reaction are very important to differentiate between the reactants and the product.

They are used in chemical reactions to show that the reaction yields a particular product.

For instance, hydrogen reacts with oxygen to yield water as shown;

[tex]2H_2 + O_2 \rightarrow 2H_2O[/tex]

We can see that the arrow in the reaction shows that the reaction of hydrogen and oxygen element yields or react to form water.

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C.  

carbon and hydrogen are elements and methane is a compound.

Answer:

C. carbon and hydrogen are elements and methane is a compound.

Explanation:

Elements are substances which have one type of atoms. Compounds are substances which have different types of atoms. Since, Carbon and Methane have only one type of atoms and thus, these are pure substances. Methane  contains atoms of Carbon and Hydrogen chemically combined together. Thus, methane is a compound.

Answer:

Option D is quantities described by both magnitude and direction is the correct answer.

Explanation:

A scalar is quantity with magnitude only. It does not have direction. Examples of scalar are distance, speed, time etc.

A vector is quantity with both magnitude and direction. Some examples for vectors are displacement, velocity, acceleration, force, moment, electric field, magnetic field etc.

Here option A, quantities described by both force and gravity is not correct.

Option B is quantities described by both speed and movement is also not correct.

Option C is quantities described by both velocity and acceleration is also not correct.

Option D is quantities described by both magnitude and direction is the correct answer.

The planet stay in orbit due to gravity. because the gravity of the sun  keeps  the planets in their orbits,

The chemical equation of a chemical must be balanced to obey the law of conservation of mass. Therefore, option (D) is correct.

The equation in which the number of atoms of each element of reactants is equal to the number of atoms of each element of products is called a balanced chemical equation.

The law of conservation of mass obeys by a balancing of a chemical equation for a chemical reaction. According to this law, the mass of matter can neither be created nor be destroyed in a chemical reaction.

By following this law, the total mass of the elements on the reactant side should be equal to the total mass of elements on the product side in a balanced chemical equation.

An example of the balanced chemical equation is the formation of water:

2H₂ + O₂  →  2H₂O

On both sides of the arrow in the equation, the number of hydrogen and oxygen atoms is equal and so are their masses. Therefore this chemical equation obeys the law of conservation of mass.

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Hello  Undeadman12

All objects in motion would have kinetic energy

:)

Hi there.

Your Question: All objects in motion have what energy ?

Kinetic Energy is the answer,  (I took this part from google) Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position).

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