Write the elements of (a, b,c}-{a, b, d}) {c, d), where a, b, c, and d are distinct

Answers

Answer 1

Answer: If we have a set defined as the difference of two sets, this is

A = B - C, then A = B - B∩C

So this is defined as, if you subtract the set C to the set B, then you are subtracting the common elements between C and B, from the set B.

so if A = {a,b,c} - {a,b,d}, the common elements are a and b, so: A = {c}


Related Questions


Determine whether the relation describe c as a function of w.

The cost to mail a letter, c, is related to how much it weighs, w, in the following way: Letters that cost $0.49 to mail weigh up to 1 ounce, letters that cost $0.70 to mail weigh between 1 and 2 ounces, and letters that cost $0.91 to mail weigh between 2 and 3 ounces.

Question 3 options:

a)

Not a function

b)

Function

Answers

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

            = 0.70,  1 < w ≤ 2

            = 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

            = 0.70,  1 < w ≤ 2

            = 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

For a normal distribution with mean equal to - 30 and standard deviation equal to 9 What is the area under the curve that is between - 34.5 and - 39.

Answers

Answer: 0.1498 square units.

Step-by-step explanation:

Let x be any random variable that follows normal distribution.

Given : For a normal distribution with mean equal to - 30 and standard deviation equal to 9.

i.e.  [tex]\mu=-30[/tex] and [tex]\sigma=9[/tex]

Use formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex] to find the z-value corresponds to -34.5 will be

[tex]z=\dfrac{-34.5-(-30)}{9}=\dfrac{-34.5+30}{9}=\dfrac{-4.5}{9}=-0.5[/tex]

Similarly,  the z-value corresponds to -38 will be

[tex]z=\dfrac{-39-(-30)}{9}=\dfrac{-39+30}{9}=\dfrac{-9}{9}=-1[/tex]

By using the standard normal table for z-values , we have

The  area under the curve that is between - 34.5 and - 39. will be :-

[tex]P(-1<z<-0.5)=P(z<-0.5)-P(z<-1)\\\\=(1-P(z<0.5))-(1-P(z<1))\\\\=1-P(z<0.5)-1+P(z<1)\\\\=P(z<1)-P(z<0.5)\\\\=0.8413-0.6915=0.1498[/tex]

Hence, the area under the curve that is between - 34.5 and - 39 = 0.1498 square units.

Consider the Quadratic function f(x) = 4x^2 - 1. Its vertex is Preview The x value of its largest x-intercept is x = The y value of the y-intercept is y = Preview Preview Preview

Answers

Answer:

Vertex = (0,-1)

The x value of its largest x-intercept is [tex]x=\frac{1}{2}[/tex].

The y value of the y-intercept is y = -1.

Step-by-step explanation:

The given function is

[tex]f(x)=4x^2-1[/tex]           .... (1)

The vertex form of a parabola is

[tex]g(x)=a(x-h)^2+k[/tex]         ..... (2)

where, a is a constant, (h,k) is vertex of the parabola.

From (1) and (2) we get

[tex]a=4,h=0,k=-1[/tex]

So, the vertex of the parabola is (0,-1).

Substitute f(x)=0 in equation (1) to find x-intercepts.

[tex]0=4x^2-1[/tex]

Add 1 on both sides.

[tex]1=4x^2[/tex]

Divide both sides by 4.

[tex]\frac{1}{4}=x^2[/tex]

Taking square root both sides.

[tex]\pm \sqrt{\frac{1}{4}}=x[/tex]

[tex]\pm \frac{1}{2}=x[/tex]

The x-intercepts are [tex]-\frac{1}{2}[/tex] and [tex]\frac{1}{2}[/tex].

Therefore the x value of its largest x-intercept is [tex]x=\frac{1}{2}[/tex].

Substitute x=0 in equation (1) to find the y-intercept.

[tex]f(0)=4(0)^2-1=-1[/tex]

Therefore the y value of the y-intercept is y = -1.

Final answer:

The vertex of the quadratic function f(x) = 4x^2 - 1 is at (0, -1). The x-intercepts are x = 0.5 and x = -0.5. The y-intercept is at y = -1.

Explanation:

The quadratic function you provided is f(x) = 4x^2 - 1. This is indeed a second-order polynomial or more commonly referred to as a quadratic function.

The vertex of this quadratic function, which represents its maximum or minimum point, can be found using the formula -b/2a. Since this quadratic has no 'x' term, the vertex's x-value is 0. Plugging this into the function gives a y-value of -1. So, the vertex is at (0, -1).

The x-intercepts of the quadratic, i.e., the points where the function intersects the x-axis, can be found by setting f(x) = 0 and solving for x. Doing so gives two solutions: x = 0.5 and x = -0.5, with 0.5 being the larger of the two.

Finally, the y-intercept (the point where the function intersects the y-axis) is found by setting x = 0. Doing so gives a y-value of -1. So, the y-intercept is at y = -1.

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What is the answer to 9 - (-8) =

Answers

The answer to the math question is 17
distribute the negative so
9 + 8
17

Team A and team B play against each other repeatedly until one team wins two games in a row or a total of three games. 1) how many ways can the tourney be played? 2) what is the probability of 5 games being played? 3) what is the probability of a team winning two games in a row. Show work.

Answers

Answer:

1) The tournament can be played in 10 different ways

2) The probability of 5 games being played is 0.40

3) The probability of a team winning two games in a row is 0.80  

Step-by-step explanation:

a) From the tree diagram below we can observe that the tournament can be played in 10 different ways.

b)The probability of 5 games being played is

P= (number of possibilities where 5 games are being played) / (Total games)

P = 4 / 10

P= 0.40

c) The probability of a team winning two games in a row is

P = (number of possibilities where a team wins two games in a row) / Total games

P = 8 / 10

P = 0.80

A simple random sample of men over age 18 is taken to estimate the mean weight of all adult males.
Is this study
A. REPRESENTATIVE?
B. NON-REPRESENTATIVE?

Answers

Answer:

A. Representative

Step-by-step explanation:

The sample is a subset of the population. We take samples because it is easy to analyze samples as compared to population and it is less time taken. Further, Sample is said to be good if the sample is the representative of the population.

Simple Random Sampling is the sampling where samples are chosen randomly, where each unit has an equal chance of being selected in a sample.

Since, observer is taken the weight of men over age 18. Thus, it is good sample which represent whole population.

What weight of magnesium chloride (MgCl2, formula weight 95.3; Mg2, atomic weight = 243; Cl, atomic weight-35.5) is required to prepare 1,000 mL of a solution that contains 5.0 mEq of magnesium?

Answers

Answer:

238.25 mg

Step-by-step explanation:

Given:

Molar mass of MgCl₂ = 95.3

atomic weight of Mg₂ = 243

Atomic weight of Cl = 35.5

Volume of solution required = 5.0 mEq of magnesium

Now,

mEq = [tex]\frac{\textup{Weight in mg\timesValency}}{\textup{Atomic mass}}[/tex]

on substituting the values, we get

5 = [tex]\frac{\textup{Weight in mg\times2}}{\textup{95.3}}[/tex]

or

weight of magnesium chloride = 238.25 mg

Therefore,

the required mass of MgCl₂ is 238.25 mg

A survey of 1,107 tourists visiting Orlando was taken. Of those surveyed:

268 tourists had visited the Magic Kingdom

258 tourists had visited Universal Studios

68 tourists had visited both the Magic Kingdom and LEGOLAND

79 tourists had visited both the Magic Kingdom and Universal Studios

72 tourists had visited both LEGOLAND and Universal Studios

36 tourists had visited all three theme parks

58 tourists did not visit any of these theme parks

How many tourists only visited the LEGOLAND (of these three)?

Answers

Answer:

602 tourists visited only the LEGOLAND.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the tourists that visited LEGOLAND

-The set B represents the tourists that visited Universal Studios

-The set C represents the tourists that visited Magic Kingdown.

-The value d is the number of tourists that did not visit any of these parks, so: [tex]d = 58[/tex]

We have that:

[tex]A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)[/tex]

In which a is the number of tourists that only visited LEGOLAND, [tex]A \cap B[/tex] is the number of tourists that visited both LEGOLAND and Universal Studies, [tex]A \cap C[/tex] is the number of tourists that visited both LEGOLAND and the Magic Kingdom. and [tex]A \cap B \cap C[/tex] is the number of students that visited all these parks.

By the same logic, we have:

[tex]B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)[/tex]

[tex]C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)[/tex]

This diagram has the following subsets:

[tex]a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)[/tex]

There were 1,107 tourists suveyed. This means that:

[tex]a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107[/tex]

We start finding the values from the intersection of three sets.

The problem states that:

36 tourists had visited all three theme parks. So:

[tex](A \cap B \cap C) = 36[/tex]

72 tourists had visited both LEGOLAND and Universal Studios. So:

[tex](A \cap B) + (A \cap B \cap C) = 72[/tex]

[tex](A \cap B) = 72 - 36[/tex]

[tex](A \cap B) = 36[/tex]

79 tourists had visited both the Magic Kingdom and Universal Studios

[tex](B \cap C) + (A \cap B \cap C) = 79[/tex]

[tex](B \cap C) = 79 - 36[/tex]

[tex](B \cap C) = 43[/tex]

68 tourists had visited both the Magic Kingdom and LEGOLAND

[tex](A \cap C) + (A \cap B \cap C) = 68[/tex]

[tex](A \cap C) = 68 - 36[/tex]

[tex](A \cap C) = 32[/tex]

258 tourists had visited Universal Studios:

[tex]B = 258[/tex]

[tex]B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)[/tex]

[tex]258 = b + 43 + 36 + 36[/tex]

[tex]b = 143[/tex]

268 tourists had visited the Magic Kingdom:

[tex]C = 268[/tex]

[tex]C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)[/tex]

[tex]268 = c + 32 + 43 + 36[/tex]

[tex]c = 157[/tex]

How many tourists only visited the LEGOLAND (of these three)?

We have to find the value of a, and we can do this by the following equation:

[tex]a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 1,107[/tex]

[tex]a + 143 + 157 + 58 + 36 + 32 + 43 + 36 = 1,107[/tex]

[tex]a = 602[/tex]

602 tourists visited only the LEGOLAND.


I need this input into MATLAB. I'm so lost on how to code it.

Evaluate the integral sintcos tdt .

I have already solved and found the answer to be -cost 2cost cos t + C 5 9 7

I just need to prove my work with MATLAB

Answers

Answer:

>>syms t

>>f=sin(t)*cos(t);

>>int(f)

Step-by-step explanation:

It's actually pretty easy, just use symbolic variables.

First, create the symbolic variable t using this command:

syms t

Now define the function

f=sin(t)*cos(t)

Finally use the next command in order to calculate the indefinite integral:

int(f)

I attached a picture in which you can see the procedure and the result.

Final answer:

To evaluate the integral of sintcost tdt in MATLAB, use the symbolic math toolbox and the 'int' function.

Explanation:

To evaluate the integral sintcost tdt in MATLAB, you can use the symbolic math toolbox. First, define the extended variable t using 'syms t'. Then, determine the integrand using the symbolic expression 'f = sin(t) * cos(t)'. Finally, use the 'int' function to find the integral, 'int(f, t)'.

Here's the MATLAB code:

syms t
f = sin(t) * cos(t)
integral_value = int(f, t)

The resulting 'integral_value' will be the evaluated integral.

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(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard deviation of 3.2 hours. Find the 95% confidence interval, assuming the times are normally distributed.

(21.60, 28.00)

(22.12, 27.48)

(22.66, 26.94)

(24.10, 25.50)

Answers

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : [tex]\alpha: 1-0.95=0.05[/tex]

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: [tex]t_{n-1,\alpha/2}=t_{7,0.025}=2.365[/tex]

Sample mean : [tex]\overline{x}=24.8\text{ hours}[/tex]

Standard deviation : [tex]\sigma=3.2\text{ hours}[/tex]

The confidence interval for population means is given by :-

[tex]\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}[/tex]

i.e. [tex]24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}[/tex]

[tex]24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)[/tex]

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

The cost, in dollars, of making x items is given by the function C(C) = 250 + 300. Find C(1500), the cost of making 1500 items. a) $4050 Ob) $25,300 Oc) $30,300 Od) $37,800 O e) none

Answers

Answer:

$37,800.

Step-by-step explanation:

We have been given that the cost, in dollars, of making x items is given by the function [tex]C(x)=25x+300[/tex]. We are asked to find [tex]C(1500)[/tex].

To find [tex]C(1500)[/tex], we will substitute [tex]x=1500[/tex] in our given function as:

[tex]C(1500)=25(1500)+300[/tex]

[tex]C(1500)=37,500+300[/tex]

[tex]C(1500)=37,800[/tex]

Therefore, the cost of making 1500 items would be $37,800 and option D is the correct choice.

18. Naruto practices his harmonica 1 hour, spends hour working on
homework, and takes another hour to do chores every day. How much
longer does Naruto spend practicing his harmonica and doing his chores
than working on homework?

Answers

Answer:

If he uses 1 hour to practice harmonica, one our on homework, and another hour doing chores. He will be spending twice as much time practicing harmonica and doing homework than he would spend on chores.

Answer:

2

Step-by-step explanation:

UP

A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration of morphine sulfate on a mg/mL basis.

Answers

Answer:

20 mg/ml.

Step-by-step explanation:

We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.

[tex]\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}[/tex]

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.

1 gram equals 1000 milligrams.

[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}\times\frac{\text{1,000 mg}}{\text{1 g}}[/tex]

[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4\times\text{1,000 mg}}{\text{120 ml}}[/tex]

[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}[/tex]

[tex]\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}[/tex]

Therefore, the concentration of morphine sulfate would be 20 mg per ml.

Answer:

Step-by-step explanation:

Your 401(k) retirement account is currently worth $55,000. Assuming no more contributions, what will your account be worth in 20 years at an annual rate of 10.5%?

N= I/Y= PV= PMT= FV= P/Y=

Answers

Answer:

Your account is going to be worst $405,142.92

Step-by-step explanation:

This is a compound interest problem.

The compound interest formula is given by:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this problem:

We want to find A

[tex]P = 55,000[/tex]

[tex]n = 1[/tex]

[tex]r = 0.105[/tex]

[tex]t = 20[/tex]

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

[tex]A = 55000(1 + \frac{0.105}{1})^{20}[/tex]

[tex]A = 405,142.92[/tex]

Your account is going to be worst $405,142.92

Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

shock resistance
scratch resistance high low
high 70 9
low 16 5

Let A denote the event that a disk has high shock resistance, and let B denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Input your answers in the fractional form (do not simplify).

P(A)=86/100

P(B)=79/100

P(A')=7/50

P(A U B)=95/100

P(A' U B)= ???

Answers

Answer:

[tex]P(A'\cup B)=\frac{84}{100}[/tex]

Step-by-step explanation:

Let A and B represents the following events.

A denote the event that a disk has high shock resistance.

B denote the event that a disk has high scratch resistance.

Given probabilities:

[tex]P(A)=\frac{70+16}{100}=\frac{86}{100}[/tex]

[tex]P(B)=\frac{70+9}{100}=\frac{79}{100}[/tex]

[tex]P(A')=\frac{9+5}{100}=\frac{7}{50}[/tex]

[tex]P(A\cup B)=\frac{70+16+9}{100}=\frac{95}{100}[/tex]

The probability of intersection of A and B is,

[tex]P(A\cap B)=P(A)+P(B)-P(A\cup B)[/tex]

Substitute the above values.

[tex]P(A\cap B)=\frac{86}{100}+\frac{79}{100}-\frac{95}{100}=\frac{70}{100}[/tex]

The probability of union of A' and B is,

[tex]P(A'\cup B)=P(A')+P(A\cap B)[/tex]

Substitute the above values.

[tex]P(A'\cup B)=\frac{7}{50}+\frac{70}{100}[/tex]

[tex]P(A'\cup B)=\frac{14}{100}+\frac{70}{100}[/tex]

[tex]P(A'\cup B)=\frac{84}{100}[/tex]

Therefore, [tex]P(A'\cup B)=\frac{84}{100}[/tex].

Using Venn probabilities, it is found that the desired probability is given by:

[tex]P(A' \cup B) = \frac{21}{25}[/tex]

The or probability of Venn sets is given by:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

In this problem, we want:

[tex]P(A' \cup B) = P(A') + P(B) - P(A' \cap B)[/tex]

We have that:

[tex]P(A') = \frac{7}{50}[/tex]

[tex]P(B) = \frac{79}{100}[/tex]

[tex]P(A' \cap B)[/tex] is probability of A not happening and B happening, thus low shock resistance and high scratch resistance, thus [tex]P(A' \cap B) = \frac{9}{100}[/tex]

Then

[tex]P(A' \cup B) = P(A') + P(B) - P(A' \cap B)[/tex]

[tex]P(A' \cup B) = \frac{7}{50} + \frac{79}{100} - \frac{9}{100}[/tex]

[tex]P(A' \cup B) = \frac{14}{100} + \frac{70}{100}[/tex]

[tex]P(A' \cup B) = \frac{84}{100}[/tex]

[tex]P(A' \cup B) = \frac{21}{25}[/tex]

A similar problem is given at https://brainly.com/question/23508811

The length of the hypotenuse of an isosceles right triangle
is30 meters. Find the area of the triangle. Round to thenearest
tenth, if necessary.

Answers

Answer:  [tex]224.9\ m^2[/tex]

Step-by-step explanation:

An isosceles right triangle is a right triangle having two legs (other than hypotenuse ) of same length  .

Given : The length of the hypotenuse of an isosceles right triangle  is 30 meters.

Let x be the side length of the other two legs, then by using the Pythagoras theorem for right triangle , we have

[tex](30)^2=x^2+x^2\\\\\Rightarrow\ 900=2x^2\\\\\Rightarrow\ x^2=\dfrac{900}{2}\\\\\Rightarrow\ x^2=450\\\\\Rightarrow\ x=\sqrt{450}=\sqrt{9\times25\times2}=\sqrt{3^2\times5^2\times2}\\\Rightarrow\ x=3\times5\sqrt{2}=15(1.414)=21.21[/tex]

Thus, the other two legs have side length of 21.21 m each.

Now, the area of a right triangle is given by :-

[tex]A=\dfrac{1}{2}\times base\times height\\\\\Rightarrow\ A=\dfrac{1}{2}(21.21)\times(21.21)=224.93205\approx224.9\ m^2[/tex]

Hence, the area of the given isosceles right triangle= [tex]224.9\ m^2[/tex]


Mrs. Brown needs $5,000 in three years. If the interest rate on her investment account is 8.4% compounded monthly, how much should she put into her account at the end of each month to have $5,000 in three years?

Give answer in US dollars and cents rounded to the nearest cent. Do NOT enter "$" sign

Answers

Answer:

ohhh you have the right time and I am so glad to see it in a better time and if it was not to do you have no doubt

Step-by-step explanation:

your body has to have your body to have the best results you need for kids in a group that can help with a lot to learn about it as you do so much of the time it works out to you to get the job you need for the next few years or 8īijjhguu is not just the best person but the meaning and skills of a person is the meaning of life and the meaning is the only 3AM in a school that you need a lot of a job 3to to do with you need to get your mind off to get your job done with your mind and then you have to do it right now and.

Let A-10, 1, 2, 3, 4, 5,6), let B = 10, 1, 2, 3, 4, 5,6, 7,8), and let R be the relation from A to B given by "the greatest common divisor of a and b is 2." [Note: "greatest common divisor" is sometimes called "highest common factor"] List the elements of R.

Answers

Answer:

R = {(10,2), (10,4), (10,6), (10,8), (2,10), (2,2), (2,4), (2,6), (2,4), (4,10), (4,2), (4,6), (6,10), (6,2), (6,4), (6,8)}

Step-by-step explanation:

A = (10, 1, 2, 3, 4, 5, 6)

B = (10, 1, 2, 3, 4, 5, 6, 7, 8)

R is a relation and defined as

R: A→B

R: The greatest common divisor of a and b is 2

To find the elements of R we need to find pair from A and B respectively.

R = {(10,2), (10,4), (10,6), (10,8), (2,10), (2,2), (2,4), (2,6), (2,4), (4,10), (4,2), (4,6), (6,10), (6,2), (6,4), (6,8)}

Now, these pairs were found by picking one element from A and checking with elements of B if they have a gcd of 2. If yes, they fall under the defined relation.

The deep body temperature of a healthy person is 37°C. What is it in kelvins?

Answers

Answer:

The deep body temperature of a healthy person is 310.15 K

Step-by-step explanation:

The formula we are going to use is [tex]T_{K}=T_{C}+273.15[/tex]

We know that the deep body temperature is 37°C, putting this value into the formula we have that [tex]T_{K}=37+273.15 = 310.15 K[/tex]

use Gaussian elimination to write each system in triangular form

x+ y+z+ w= 1

x+y −w=−1

−x+ y+z+2w= 2

x+2y−z+ w= 0

Answers

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is [tex]x =  -\frac{1}{9}[/tex], [tex]y= -\frac{1}{9}[/tex], [tex]z= \frac{4}{9}[/tex] and [tex]w = \frac{7}{9}[/tex]

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

Swapping two rowsMultiplying a row by a nonzero numberAdding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

[tex]\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right][/tex]

For this matrix we need to perform the following row operations:

[tex]R_2 - 1 R_1 \rightarrow R_2[/tex] (multiply 1 row by 1 and subtract it from 2 row)[tex]R_3 + 1 R_1 \rightarrow R_3[/tex] (multiply 1 row by 1 and add it to 3 row)[tex]R_4 - 1 R_1 \rightarrow R_4[/tex] (multiply 1 row by 1 and subtract it from 4 row)[tex]R_2 \leftrightarrow R_3[/tex] (interchange the 2 and 3 rows)[tex]R_2 / 2 \rightarrow R_2[/tex] (divide the 2 row by 2)[tex]R_1 - 1 R_2 \rightarrow R_1[/tex] (multiply 2 row by 1 and subtract it from 1 row)[tex]R_4 - 1 R_2 \rightarrow R_4[/tex] (multiply 2 row by 1 and subtract it from 4 row)[tex]R_3 \cdot ( -1) \rightarrow R_3[/tex] (multiply the 3 row by -1)[tex]R_2 - 1 R_3 \rightarrow R_2[/tex] (multiply 3 row by 1 and subtract it from 2 row)[tex]R_4 + 3 R_3 \rightarrow R_4[/tex] (multiply 3 row by 3 and add it to 4 row)[tex]R_4 / 4.5 \rightarrow R_4[/tex] (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

[tex]\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right][/tex]

If you later perform the following operations you can find the solution to the system.

[tex]R_1 + 0.5 R_4 \rightarrow R_1[/tex] (multiply 4 row by 0.5 and add it to 1 row)[tex]R_2 + 0.5 R_4 \rightarrow R_2[/tex] (multiply 4 row by 0.5 and add it to 2 row)[tex]R_3 - 2 R_4 \rightarrow R_3[/tex](multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

[tex]\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right][/tex]

Thus, the solution is:

[tex]x =  -\frac{1}{9}[/tex], [tex]y= -\frac{1}{9}[/tex], [tex]z= \frac{4}{9}[/tex] and [tex]w = \frac{7}{9}[/tex]

find the focus of teh parabola that has vertex (-3,2), opens horizontally, and passes through the point (-10,1).

Answers

Answer:

[tex](-\frac{85}{28},2)[/tex]

Step-by-step explanation:

We are asked to find the focus of the parabola that has a vertex [tex](-3,2)[/tex] opens horizontally and passes through the point [tex](-10,1)[/tex].

We know that equation of a horizontal parabola is [tex](y-k)^2=4p(x-h)[/tex], where p is not equal to zero.

[tex](h,k)[/tex] = Vertex of parabola.

Focus: [tex](h+p,k)[/tex]

Upon substituting the coordinates of vertex and given point in equation of parabola, we will get:

[tex](1-2)^2=4p(-10-(-3))[/tex]

[tex](-1)^2=4p(-10+3)[/tex]

[tex]1=4p(-7)[/tex]

[tex]1=-28p[/tex]

[tex]\frac{1}{-28}=\frac{-28p}{-28}[/tex]

[tex]-\frac{1}{28}=p[/tex]

Focus: [tex](h+p,k)[/tex]

[tex](-3+(-\frac{1}{28}),2)[/tex]

[tex](-3-\frac{1}{28},2)[/tex]

[tex](\frac{-3*28}{28}-\frac{1}{28},2)[/tex]

[tex](\frac{-84}{28}-\frac{1}{28},2)[/tex]

[tex](\frac{-84-1}{28},2)[/tex]

[tex](\frac{-85}{28},2)[/tex]

[tex](-\frac{85}{28},2)[/tex]

Therefore, the focus of the parabola is at point [tex](-\frac{85}{28},2)[/tex].

Find the surface area of the part of the paraboloid z=5-3x^2-2y^2 located above the xy plane. (10 points) z

Answers

Answer:

Use the formula [tex]Area(S)=\iint_{S} 1 dS= \iint_{D} \lVert r_{u}\times r_{v} \rVert dudv[/tex]

Step-by-step explanation:

Let [tex]r(x,y)=(x,y,5-3x^2-2y^2)[/tex] be the explicit parametrization of the paraboid. The intersection of this paraboid with the xy plane is the ellipse given by

[tex]\dfrac{x^2}{\frac{5}{3}}+\dfrac{y^{2}}{\frac{5}{2}}=1[/tex]

The partial derivatives of the parametrization are:

[tex]\begin{array}{c}r_{x}=(1,0,-6x)\\r_{y}=(0,1,-4y)\end{array}[/tex]

and computing the cross product we have

[tex]r_{x}\times r_{y}=(6x,4y,1)[/tex]. Then

[tex]\lVert r_{x}\times r_{y}\rVert =\sqrt{1+36x^{2}+16y^{2}}[/tex]

Then,  if [tex]R[/tex] is the interior region of the ellipse the superficial area located above of the xy  is given by the double integral

[tex]\iint_{R}\sqrt{1+36x^2+16y^2}dxdy=\int_{-\sqrt{5/3}}^{\sqrt{5/3}}\int_{-\sqrt{5/2}\sqrt{1-\frac{x^2}{5/3}}}^{\sqrt{5/2}\sqrt{1-\frac{x^2}{5/3}}}\sqrt{1+36x^2+16y^2}dy dx=30.985[/tex]

The last integral is not easy to calculate because it is an elliptic integral, but with any software of mathematics you can obtain this value.

Help quickly D is Triangle EFH is congruent to triangle HFE by the Angle-Angle Theorem.

Answers

The correct answer is A, because the angles are proven same by the line of symmetry marked.

Answer:

A

explanation:

because the angles are proven same

How can this be proved to be a tautology using laws of logical equivalence?

((x ∨ y) ∧ (x → z) ∧ (¬z)) → y

Answers

Answer:

Step-by-step explanation:

If we assume that [tex][(x \vee y) \wedge (x \rightarrow z) \wedge (\neg z)][/tex] is true, then:

[tex](x \vee y)[/tex] is true

[tex](x \rightarrow z)[/tex] is true

[tex](\neg z)[/tex] is true

If [tex](\neg z)[/tex] is true, then [tex]z[/tex] is false.

[tex](x \rightarrow z) \equiv (\neg x \vee z)[/tex], since [tex](x \rightarrow z)[/tex] is true, then [tex](\neg x \vee z)[/tex] is true

If [tex]z[/tex] is false and [tex](\neg x \vee z)[/tex] is true, then [tex]\neg x[/tex] is true.

If [tex]\neg x[/tex] is true, then [tex]x[/tex] is false, as [tex](x \vee y)[/tex] is true and [tex]x[/tex] is false, then [tex]y[/tex] is true.

Conclusion [tex]y[/tex] it's true.

During the 2010 baseball​ season, the number of wins for three teams was three consecutive integers. Of these three​ teams, the first team had the most wins. The last team had the least wins. The total number of wins by these three teams was 228228. How many wins did each team have in the 2010​ season?

Answers

Answer:

76075, 76076, 76077

Step-by-step explanation:

There are 3 teams; Team A, Team B and Team C

Team A has most wins

Team C has least wins

Team B is in between

All these will be consecutive numbers.

Team B: x

Team A: x + 1 (most wins)

Team C: x - 1 (least wins)

Team A + Team B + Team C = Total number of wins

x + x + 1 + x - 1 = 228228

3x = 228228

x = 76076

Wins of Team B : x = 76076

Wins of Team A : x + 1 = 76076 + 1 = 76077

Wins of Team C : x - 1 = 76076 - 1 = 76075

Therefore, in the 2010 season, Team A had 76077 wins, Team B had 76076 wins and Team C had 76075 wins.

!!

Calculate how many Fluid ounces (fl oz) of water is needed if a recipe requires 2 cups of water.

Answers

Answer:

Is needed 16 fluid oz of water to fill in 2 cups of water

Step-by-step explanation:

1 cup have 8 fluid oz

2 cups = 2 * 8 fluid oz = 16 fluid oz

Final answer:

The recipe requires 2 cups of water, which is equivalent to 16 fluid ounces since there are 8 fluid ounces in one cup.

Explanation:

To calculate how many fluid ounces of water is needed if a recipe requires 2 cups of water, you need to understand the unit equivalence between cups and fluid ounces. One cup is equivalent to 8 fluid ounces. Since the recipe requires 2 cups, you will multiply the number of cups by the unit equivalence to find the total number of fluid ounces.

Here is the calculation:

2 cups × 8 fluid ounces/cup = 16 fluid ounces

Therefore, the recipe requires 16 fluid ounces of water.

The cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5ft length with diameter 2 inches costs $48.00, how much will a 17tf length with diameter 5in. cost?

Answers

Answer:

The cost for 17 ft length with diameter 5 in is $408.

Step-by-step explanation:

Consider the provided information.

It is given that the cost of stainless steel tubing varies jointly as the length and the diameter of the tubing. If a 5 foot length with a diameter 2 inches costs $48.00.

let [tex]C\propto L\cdot D[/tex]

[tex]C=k\cdot L\cdot D[/tex]

[tex]48=k\cdot 5\cdot 2[/tex]

[tex]\frac{48}{10}=k[/tex]

[tex]k=4.8[/tex]

For 17 ft length with diameter 5in the cost will be:

[tex]C=k\cdot L\cdot D[/tex]

Substitute the respective values in the above formula.

[tex]C=4.8\cdot 17\cdot 5[/tex]

[tex]C=408[/tex]

Cost = $408

Hence, the cost for 17 ft length with diameter 5in is $408.

A commercial package contains thirty-six 200-mg tablets of ibuprofen. How many kilograms of ibuprofen were

Answers

Final answer:

To find the total kilograms of ibuprofen, multiply 36 tablets by 200 mg each to get 7200 mg, and then divide by 1,000,000 to convert to kilograms, resulting in 0.0072 kg.

Explanation:

To calculate the total amount of ibuprofen in kilograms, you start by finding the total amount in milligrams. Multiply the number of tablets (36) by the amount of ibuprofen per tablet (200 mg).

36 tablets × 200 mg/tablet = 7200 mg

Now, since there are 1,000,000 milligrams in a kilogram, you'll need to divide the total milligrams by 1,000,000 to convert it to kilograms.

7200 mg ÷ 1,000,000 mg/kg = 0.0072 kg

Therefore, the package contains 0.0072 kilograms of ibuprofen.

The "Double-R-7" Ranch has a new owner. The 20 animals, all hummingbirds and mice, are dismayed, as they have heard that he is both foolish and inexperienced. Not being quite sure what he was looking for, however, he checked on the health of his animals by inspecting all their feet. There were 64 feet in all. How many hummingbirds and how many mice are on this ranch?
Please help immediately I'm so confused!!! :(

Answers

H+M=20
2H+4M=64 the 2 because hummingbirds have 2 feet and the 4 because mice have 4 feet

x=25.36+0.45(25.36)

LaTeX: x=

Answers

Answer:

[tex]x=36.772[/tex]  

Step-by-step explanation:

Given : Expression [tex]x=25.36+0.45(25.36)[/tex]

To find : Solve the expression ?

Solution :

Step 1 - Write the expression,

[tex]x=1(25.36)+0.45(25.36)[/tex]

Step 2 - Apply distributive, [tex]ab+ac=a(b+c)[/tex]

Here, a=25.36, b=1, c=0.45

[tex]x=25.36(1+0.45)[/tex]

Step 3 - Solve the expression,

[tex]x=25.36\times 1.45[/tex]

[tex]x=36.772[/tex]

Therefore, [tex]x=36.772[/tex]

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