Write the equation for the dissolution of sr(no3)2 in water. how many moles of strontium ions and nitrate ions are produced by dissolving 0.5 mol of strontium nitrate?

Explanation:

When we are using spoon, beaker, stirring rod and graduated cylinder then they directly come in contact with the chemical we are using. Hence, if they are not washed thoroughly then chemicals remain deposited over them.

As a result, when successive test are performed using the same contaminated apparatuses then we do not get the desired results.

Whereas distilled water in a spray bottle if poured without touching or coming in contact with any kind of chemicals.

Hence, we can conclude that spoon, beaker, stirring rod and graduated cylinder are the tools that could have become cross-contaminated during the experiment if you had not cleaned them carefully between successive tests.

Answer:

A. Spoon, B. Beaker, C. Stirring Rod, D. Graduated Cylinder

Explanation:

Answer: The correct answer is [tex]1s^22s^22p^63s^1[/tex]

Explanation:

Electronic configuration is defined as the configuration in which total number of electrons are represented which are present in an element.

Number of electrons are determined by the atomic number of that element.

Atomic number of Sodium = 11

Electronic configuration of sodium element (Na) : [tex]1s^22s^22p^63s^1[/tex]

Hence, the correct answer is [tex]1s^22s^22p^63s^1[/tex]

Phosphorus has a +3 oxidation state in tetraphosphorus hexaoxide (P4O6) and phosphorous acid (H3PO3).

Phosphorus exhibits different oxidation states in various substances. When it comes to a +3 oxidation state, phosphorus(III) oxide, also known as tetraphosphorus hexaoxide (P4O6), is the substance where phosphorus has a +3 oxidation state. This compound can be formed when white phosphorus is carefully burned in limited oxygen. Additionally, another compound where phosphorus has a +3 oxidation state is phosphorous acid, H3PO3, which can be obtained by the slow dissolution of phosphorus(III) oxide in cold water.

Phosphorus also forms hydrides, such as diphosphorus tetrahydride (H2P-PH2) and tetraphosphorus trisulfide (P4S3), which exhibit phosphorus in atypical oxidation states including the +3 state.

The Brønsted base in the forward reaction HPO4²-(aq) + HNO3(aq) ⇀↽ NO3¯ (aq) + H2PO4¯ (aq) is HPO4²-(aq) because it accepts a proton in this reaction.

To identify the Brønsted base in the reaction HPO4²-(aq) + HNO3(aq) ⇀↽ NO3¯(aq) + H2PO4¯(aq), let's recognize the definitions of a Brønsted-Lowry base and acid.

A Brønsted base is a proton (H+) acceptor, whereas a Brønsted acid is a proton donor. In the forward reaction, HNO3 donates a proton; making it the Brønsted acid. The species that accepts the proton is HPO4²-. Therefore, HPO4²- is the Brønsted base in the forward reaction of this equilibrium.

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In the reaction, HPO₄²⁻ is the Brønsted base as it accepts a proton from HNO₃. HNO₃ acts as the Brønsted acid. Therefore, option 3: HPO₄²⁻ is correct.

In the forward reaction HPO₄²⁻ (aq) + HNO₃ (aq) ⇄ NO₃⁻ (aq) + H₂PO₄⁻ (aq), we need to identify the Brønsted base.

A Brønsted base is defined as a substance that can accept a proton (H⁺). In this reaction:

So, the correct answer is option 3: HPO₄²⁻.

Complete Question.

Identify the Brønsted base in the forward reaction HPO₄²⁻ (aq) + HNO₃(aq) ⇄ NO₃⁻ (aq) + H₂P0₄⁻ (aq).

1. NO₃⁻

2. H₂PO₄⁻ (aq)

3. HPO₄²⁻

4. HNO₃

Answer:

lightning

Explanation:

Natural fires are generally started by lightning, with a very small percentage started by spontaneous combustion of dry fuel such as sawdust and leaves. On the other hand, human-caused fires can be due to any number of reasons. Some classifications include smoking, recreation, equipment, and miscellaneous.

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Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, [tex] 0.5^{n} [/tex]

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

The empirical formula of nickel chloride, given the masses of nickel and chlorine, is c) NiCl₃

Determining the Empirical Formula of Nickel Chloride

To determine the empirical formula of nickel chloride from the given masses of nickel (0.587 g) and chlorine (1.065 g), follow these steps:

Convert the mass of each element to moles:

Nickel (Ni): 0.587 g ÷ 58.69 g/mol = 0.0100 mol

Chlorine (Cl): 1.065 g ÷ 35.45 g/mol = 0.0300 mol

Determine the simplest whole number ratio:

Nickel: 0.0100 mol ÷ 0.0100 mol = 1

Chlorine: 0.0300 mol ÷ 0.0100 mol = 3

Write the empirical formula: Hence, the simplest ratio of Nickel to Chlorine is 1:3, making the empirical formula NiCl₃

Answer:

6.31%

Explanation:

In order to solve this, you need to use the expression to calculate half life, which is the following:

C = Co e^-t λ  (1)

Where:

C: concentration after t has passed

Co: initial concentration

t: time that has passed

λ: lambda which relation half life time

λ this can be calculated with the following expression:

λ = ln2 / t(1/2)   (2)

So, let's calculate λ first and then, the concentration. In this case, we will assume that we begin with a concentration at 100%.

The value of lambda is:

λ = ln2 / 12.3

λ = 0.0564

Now, let's use (1) to calculate the concentration after 49 years:

C = 100 e^ (-49 * 0.0564)

C = 100 e^(-2.7636)

C = 6.31 %

And this will be the tritium remaining after 49 years

Answer:Explained

Explanation:

The following energy has been developed and improved by chemists

Anything which includes chemical reaction has been developed by chemists to utilize the hidden energy.For example Nuclear energy

If proper reactions and controlled environment is given then a huge amount of energy can be generated from Radioactive elements.

Final answer:

To determine the grams of aluminum chloride produced in the reaction, use the given balanced chemical equation and the molar masses of aluminum and aluminum chloride. Convert the given masses of aluminum and hydrochloric acid to moles and use the stoichiometric ratios to determine the moles of aluminum chloride produced. Finally, convert the moles of aluminum chloride to grams.

Explanation:

To determine the grams of aluminum chloride produced in the reaction, we need to use the given balanced chemical equation and the molar masses of aluminum (Al) and aluminum chloride (AlCl3). The molar mass of Al is approximately 26.98 g/mol, while the molar mass of AlCl3 is approximately 133.34 g/mol.

First, we convert the given masses of aluminum (72.0 g) and hydrochloric acid (252 g) to moles using their respective molar masses. Using the ratios from the balanced chemical equation, we can then determine the moles of aluminum chloride produced.

Starting with 72.0 g of Al:

72.0 g Al * (1 mol Al / 26.98 g Al) * (2 mol AlCl3 / 2 mol Al) * (133.34 g AlCl3 / 1 mol AlCl3) = 398.908 g AlCl3

Therefore, approximately 398.908 grams of aluminum chloride are produced.

Silver nitrate (AgNO₃) reacts with hydrochloric acid (HCl) to produce nitric acid (HNO₃) and silver chloride (AgCl). Increasing the concentration of HCl would increase the rate of reaction and the correct option is option A.

The rate of reaction or reaction rate is the speed at which reactants are converted into products. It is the measure of the change in concentration of the reactants or the change in concentration of the products per unit time. If a reaction has a low rate, that means the molecules combine at a slower speed than a reaction with a high rate.

Factors influencing the rate of reaction are:

1. surface area of a solid reactant

2. concentration and pressure of a reactant

3. temperature

4. nature of reactants

5. presence/absence of a catalyst

Thus, the ideal selection is option A.

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Answer:

19.9 psi

Explanation:

All the provided statements about 'yield' in chemistry are correct. The yield represents the amount of product from a chemical reaction. Percent yield is calculated using actual and theoretical yields, which can differ due to incomplete reactions or limiting reagents.

Regarding your question about which statement is not true about 'yield', all of the statements you listed are generally correct. Yield in chemistry refers to the amount of product obtained in a chemical reaction. The theoretical yield is the maximum possible amount of product that can be produced from a given amount of reactants. The actual yield is the amount of product actually produced when the chemical reaction is carried out in an experiment.

The percent yield is the ratio of the actual yield to the theoretical yield, expressed as a percentage (statement b). This value indeed requires knowledge of the actual yield (statement a). Both the actual and theoretical yield can differ due to incomplete reaction or inefficient use of limiting reagents (statement c and d).

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To neutralize 60.0 mL of 0.15 M HCl, 20.0 mL of 0.45 M LiOH is required. The neutralization reaction proceeds in a 1:1 molar ratio.

To calculate the volume of 0.45 M LiOH required to neutralize 60.0 mL of 0.15 M HCl, we use the neutralization reaction where LiOH reacts with HCl in a 1:1 molar ratio:

First, calculate the number of moles of HCl:

moles HCl = volume (L) × molarity (M) = 0.060 L × 0.15 M = 0.009 moles

Since the molar ratio is 1:1, 0.009 moles of LiOH will also be needed.

Then, calculate the volume of LiOH solution:

Volume LiOH = moles LiOH / molarity of LiOH = 0.009 moles / 0.45 M = 0.020 L or 20.0 mL

Therefore, 20.0 mL of 0.45 M LiOH is required to neutralize 60.0 mL of 0.15 M HCl.

Answer:

The answer is D.Apollo

Explanation:

The statement that describes the space missions involved the deployment of lunar rover is "Apollo."

What is a space mission?

A space mission is defined as the act of sending a space item to its designated location and then performing scientific or technological operations there. An examination of the reaches of the universe beyond Earth's atmosphere using crewed and uncrewed spacecraft, with the goal of increasing understanding of the cosmos and benefiting humanity.

The majority of the deployment occurred automatically as the rover was released from the bay.

The lunar rovers of Apollo 15, 16, and 17 anchored American automotive culture on the moon's surface while broadening the scientific scope of the missions' astronaut explorers.

Hence the correct option is Apollo.

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Final answer:

The molal concentration of the aqueous solution with a freezing point of -0.58°C is 0.312 mol/kg, calculated using the formula for freezing point depression and the molal freezing-point depression constant for water.

Explanation:

To determine the molal concentration of the solution based on the given freezing point depression, we use the formula ΔTf = Kf × m, where ΔTf is the change in freezing point, Kf is the molal freezing-point depression constant for water, and m is the molality of the solution.

For water, Kf is -1.86°C/m. The change in freezing point (ΔTf) can be calculated as the difference from water's normal freezing point, 0°C, to the solution's freezing point, which is -0.58°C. Thus, ΔTf = 0°C - (-0.58°C) = 0.58°C.

Plugging the values into the equation:

ΔTf = Kf × m
0.58°C = (-1.86°C/m) × m
m = 0.58°C / -1.86°C/m
m = 0.312 mol/kg

Therefore, the molal concentration of the solution is 0.312 mol/kg.

When the equilibrium of the decomposition of bromine dichloride is disturbed by increasing temperature, the reaction shifts towards the reactants according to Le Chatelier's principle.

If the temperature is increased for the decomposition of bromine dichloride, BrCl2, the reaction will shift towards the reactants. According to Le Chatelier's principle, if a chemical system at equilibrium experiences a change in concentration, temperature, volume, or pressure, then the equilibrium shifts to counteract the imposed change and re-establish equilibrium. In this endothermic reaction, heat is absorbed to convert BrCl2 into bromine, Br2, and chlorine, Cl2. Therefore, increasing the temperature adds heat to the system, which will shift the equilibrium towards the reactants (BrCl2) to absorb the excess heat.

To determine how many milliliters of a stock solution are needed to prepare a given volume of a diluted solution, one can use the dilution formula 'M1V1 = M2V2’. In this case, you'd need 50.0 ml of the stock solution to prepare 100.0 ml of a 1.00m MgSO4 solution.

To find out how many milliliters of a stock solution of 2.00m MgSO4 you would need to prepare 100.0 ml of 1.00m MgSO4, you can use the formula M1V1 = M2V2, where M1 is the molarity of the initial solution, V1 is the volume of the initial solution, M2 is the molarity of the final solution, and V2 is the volume of the final solution.

Firstly, we substitute the given values into the formula. M1 is our initial molarity (2.00m), V1 is what we're trying to find, M2 is our final molarity (1.00m) and V2 is our final volume (100.0 ml). By rearranging the formula, we get V1 = (M2 * V2) / M1.

The calculation step becomes: V1 = (1.00m * 100.0 ml) / 2.00m = 50.0 ml. Therefore, you would need 50.0 milliliters of the stock solution to prepare 100.0 ml of a 1.00m MgSO4 solution.

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Answer:

The reaction rate decreases.

Explanation: