Write the name of the following compound: H3PO4

Answers

Answer 1
Phosphoric acid, also known as orthophosphoric acid or phosphoric(V) acid, is a mineral acid with the chemical formula H3PO4
Answer 2

Explanation:

Since the given formula is [tex]H_{3}PO_{4}[/tex]. It consists of three hydrogen atoms, one phosphorous atom and four oxygen atoms.

[tex]H_{3}PO_{4}[/tex] is known as phosphoric acid. It is a weak acid and it dissociates to give hydrogen ions when dissolved in a solvent.

Phosphoric acid ([tex]H_{3}PO_{4}[/tex]) is also known as orthophosphoric acid.


Related Questions

What is the ph of a 0.015 m aqueous solution of hydrazoic acid (hn3) (ka = 1.9 x 10–5) at 25°c?

Answers

Answer is: pH value of aqueous solution of hydrazoic acid is 4,72.
Chemical reaction: N₃H + H₂O ⇄ N₃⁻ + H₃O⁺.
c(N₃H) = 0,015 M.
Ka(N₃H) = 1,9·10⁻⁵.
[N₃⁻] = [H₃O⁺] = x.
[N₃H)] = 0,015 M - x.
Ka = [N₃⁻] · [H₃O⁺] / [N₃H].
1,9·10⁻⁵= x² / 0,015 M -x.
Solve quadratic equation: x = [H₃O⁺] = 0,000019 M.
pH = -log [H₃O⁺] = 4,72.

What is the name of the species formed when a sodium atom loses an electron?

Answers

A sodium atom has one valence electron, since it is in Group 1 of the periodic table. If it loses this lone valence electron in its outermost shell, its electron configuration becomes similar to that of neon, which is just before it on the periodic table. If we remove one electron, the sodium atom will lose a negative charge, therefore giving it a positive net charge. Therefore, we call it an Na+ ion.
Final answer:

When a sodium atom loses an electron, it becomes a sodium ion (Na+).

Explanation:

When a sodium atom loses an electron, it becomes a sodium ion (Na+).

For example, a sodium atom has 11 protons and 10 electrons. By losing one electron, it now has an overall charge of +1. This positive charge is denoted by the superscripted plus sign (Na+).

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If the first half-life of a zero-order reaction is 200s, what will be the duration of the next half-life?

Answers

100s
Will be the answer to this.

A compound is found to contain 58.80 % xenon, 7.166 % oxygen, and 34.04 % fluorine by mass. what is the empirical formula for this compound?

Answers

To make it easier, assume that we have a total of 100 g of a compound. Hence, we have 58.80g of xenon, 7.166g of oxygen, and 34.04g of fluorine. 
Know we will convert each of these masses to moles by using the atomic masses:

58.8/131.3 = 0.45 mole of Xe
7.166/16 = 0.45 mole of O
34.04/19 = 1.79 mole of F

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:

Xe = 0.45/0.45 = 1
O = 045/0.45 = 1
F = 1.79/0.45 = 3.98 = 4

So, the empirical formula of the compound XeOF₄

Determine the melting point of an aqueous solution containing 101 mg of saccharin (c7h5o3ns) added to 1.00 ml of water (density of water = 1.00 g/ml, kf = 1.86°c/m).

Answers

Answer is:  the melting point of an aqueous solution is -1,023°C.
m(C₇H₅O₃NS) = 101 mg · 0,001 g/mg = 0,101 g.
V(H₂O) = 1,00 mL.
m(H₂O) = d(H₂O) · V(H₂O).
m(H₂O) = 1 g/mL · 1 mL = 1 g = 0,001 kg.
n(C₇H₅O₃NS) = 0,101 g ÷ 183,2 g/mol = 0,00055 mol.
b(C₇H₅O₃NS) = 0,00055 mol ÷ 0,001 kg = 0,55 mol/kg = 0,55 m.
ΔT = Kf · b(C₇H₅O₃NS).
ΔTsolution) = 1,86°C/m · 0,55 m = 1,023°C.

The freezing point of the solution is - 0.74 °c.

First, we have to determine the mass of the water as follows;

Density of water = mass/ volume

Mass = Density of water × volume

Mass = 1.00 g/ml × 1.00 ml = 1.00 g or 0.001 Kg

Number of moles of solute = 101 × 10^-3 g/183 g/mol = 0.0004 moles

Molality = 0.0004 moles/0.001 Kg = 0.4 m

ΔT = K m i

K = freezing constant

m = molality

i = Van't Hoff factor

ΔT = 1.86°c/m × 0.4 m × 1 = 0.74 °c

Freezing point = 0 °c - 0.74 °c = - 0.74 °c

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A nuclide of 64/29 Cu absorbs a position. Which is the resulting atom?

A) 65/29 Cu
B) 63/29 Cu
C) 64/28 Ni
D) 64/30 Zn

Answers

Final answer:

When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission and the resulting atom is 63/29 Cu.

Explanation:

When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission. During this process, one of the protons in the nucleus is transformed into a neutron, resulting in a new atom. The resulting atom will have the same number of protons as the original atom, but one less proton. Therefore, the resulting atom will be 63/29 Cu, which is option B.

Which of the following substances is considered to be a base? A. HCl B. HNO3 C. H2SO4 D. Ca(OH)2

Answers

Among all of the choices listed, the only option that is a base would be the last one. As it is unique, whereby Hydrogen is not present in the front of the compound.

Bases also possess OH in their molecular formula.

Among the options given, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.

What do you mean by a base?

A base in chemistry is defined as a type of chemical substance that can significantly accept hydrogen ions in water and can neutralize an acid. Bases feel soapy or slippery on the skin in texture and they have the ability to turn certain dyes blue.

According to the context of this question, H2SO4 or sulphuric acid is the strongest acid along with HNO3 (nitric acid) and HCl (hydrochloric acid). An example of a base is sodium hydroxide. Basicity is measured on a scale called the pH scale.

Therefore, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.

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How many grams of CO2 are in 4 mol of the compound?

Answers

Answer: 176.04 g

Explanation:

Data:

1) compound CO2
2) n = 4 mol
3) mass in grams = ?

Formula:

mass in grams = n * molar mass

Solution:

molar mass of CO2 = 1 * atomic mass of C + 2 * atomis mass of O

atomic mass of C = 12.01 g/mol
atomic mass of O = 16.00 g/mol

molar mass of CO2 = 1 * 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol

mass in grams = 4 mol * 44.01 g/mol = 176.04 g

Answer: 176.04 g

Which metal(s) can be oxidized with a sn2+ solution but not with an fe2+ solution? (hint: the reactions are occurring under standard conditions.)?

Answers

For this we have to consider the reactive series of metals in which metals are arranged according to their reactivity order.

Oxidation of a metal can be defined as ability to lose electrons to become positively charged metal and a metal will lose its electrons by reacting with a metal that is having low chemical reactivity as a higher reactive metal can lose its electrons to a low reactive metal. So here a metal should be one that is more reactive than tin so that it can lose its electrons to tin to become positively charged and less reactive than iron so that it will not give its electrons to iron to become positively charged. If we look into reactive series of metal than we will find that nickel is the example of a metal that is more reactive than tin and less reactive than iron.

Nickel and cadmium is the metal that can be oxidized with a sn2+ solution, but not with a fe2+ solution.

What is metal oxidization?

An ionic chemical reaction occurs on the surface of metal in the presence of oxygen.

Metals that can be oxidized in solution must have a weaker oxidizing agent or be less reactive than tin.

With solution, the same metals cannot be oxidized.

Thus, the correct option is Nickel and cadmium.

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Compare the viscosity of n-hexane, ch3ch2ch2ch2ch2ch3, to the viscosity of n-heptane, ch3ch2ch2ch2ch2ch2ch3.

Answers

Final answer:

n-Heptane has a higher viscosity than n-hexane due to its longer carbon chain and greater molecular weight, which leads to stronger dispersion forces and hence more resistance to flow.

Explanation:

The viscosity of a liquid is a measure of its resistance to deformation or flow. In comparing the viscosities of n-hexane (CH₃(CH₂)₄CH₃) and n-heptane (CH₃(CH₂)₅CH₃), we must consider their molecular weights and the strength of their intermolecular forces. Because n-heptane has a longer carbon chain and greater molecular weight than n-hexane, it also has stronger dispersion forces. These dispersion forces increase with the molecular surface area, so the larger n-heptane molecules experience more significant intermolecular attractions. As a result, n-heptane has a higher viscosity compared to n-hexane.

A 13.0 kg iron weightlifting plate has a volume of 1650 cm3 . What is the density of the iron plate in g/cm3?

Answers

11.0 kg = (11.0 kg)(1000 g/kg) = 11000 g
(11000 g)/(1400 cm3) = 7.857 g/cm3
Simplified = 7.86 g/cm3

Explanation:

It is known that density is the amount of mass divided by volume.

Mathematically,     Density = [tex]\frac{mass}{volume}[/tex]

It is given that mass is 13.0 kg or 13000 g (as 1 kg = 1000 g). And, volume is 1650 [tex]cm^{3}[/tex].

Therefore, calculate the density as follows.

                    Density = [tex]\frac{mass}{volume}[/tex]

                                 = [tex]\frac{13000 g}{1650 cm^{3}}[/tex]    

                                 = [tex]7.87 g/cm^{3}[/tex]

Thus, we can conclude that density of the given iron plate is [tex]7.87 g/cm^{3}[/tex].

If the calcium oxide were to be obtained by the heating of calcium hydroxide, how much hydroxide would be needed to obtain the 15.0 g?

Answers

Ca(OH)2 -------> CaO + H2O
ratio is 1 : 1
CaO Mr= 56g
15/56 = 0.268 mol (mols of CaO in 15g)
Ca(OH)2 Mr= 74g
0.268x74= 19.83g (required amount of Cash(OH)2)




how many grams of NaCl will be needed to form 600 ml of a saturated solution at 100 degrees celsius ?

Answers

The solubility of NaCl in water at 100 C is 40%, meaning that we can dissolve 40 g NaCl in 100 g water. Assuming that dissolving NaCl does not add any volume to the solution, 600 mL of water is approximately equal to 600 g of water. By ratio and proportion: 40 g NaCl/100 g H2O = x g NaCl/600 g H2O
x = 240 g NaCl
So 240 g of NaCl must be dissolved to form a saturated solution.

Which substance found in fossil fuels can form a harmful acid when the fuel is burned?

Answers

fossil fuels are mainly organic compounds.Combustion of fossil fuels also produces other air pollutants, such as nitrogen oxides, sulfur dioxide, volatile organic compounds and heavy metals.so,substances which contain sulphur cause to form harmful acids like sulphuric and sulphurus acids

Answer is: sulfur.

Fossil fuel combustion increases the acidity of rain because the sulfur dioxide is produced.  

Because of fuel combustion, sulfur dioxide goes up into the atmosphere as the hot gases rise, than it reacts with water and oxygen in the air and form sulfuric acid:  

Balanced chemical reaction: SO₂(g) + 2O₂(g) + 2H₂O → 2H₂SO₄.  

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

When pH is less than seven (pH<7), solution is acidic.

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reactants and products be explained?

Answers

Final answer:

The difference in masses of reactants and products in the reaction CaO + H2O → Ca(OH)2 could be due to measurement errors, presence of impurities, incomplete reactions, or factors such as the absorption of water if the product mass is greater than that of the reactants.

Explanation:

The 1:1 stoichiometry reaction you are referring to is CaO(s) + H2O(l) → Ca(OH)2(s). In this reaction, 56.08 g of CaO reacts with 36.04 g of H₂O to produce 74.10 g of Ca(OH)₂. The law of conservation of mass states that matter cannot be created or destroyed; hence the total mass of reactants should equal the mass of the products in a chemical reaction.

However, in realistic scenarios, there could be minor deviations due to aspects like measurement errors, the presence of impurities, or incomplete reactions. If the reaction goes to completion, and no gases are created (which may escape the reaction system), the masses should equal.

 

If the resulting mass of the product, Ca(OH)₂, is less than the combined mass of reactants, it suggests that there may be unreacted CaO or H₂O left. If the mass of Ca(OH)₂ is more than the reactants, it could suggest impurities, absorption of water, or some other factors at play.

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What mass of h2o will be produced if 9.5 g of h2 reacts with 1.2 g of o2?

Answers

Answer is: mass of water is 1,35 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(H₂) = 9,5 g.
n(H₂) = m(H₂) ÷ M(H₂).
n(H₂) = 9,5 g ÷ 2 g/mol.
n(H₂) = 4,75 mol.
m(O₂) = 1,2 g.
n(O₂) = 1,2 g ÷ 32 g/mol.
n(O₂) = 0,0375 mol; limiting reactant.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 0,0375 mol · 2 = 0,075 mol.
m(H₂O) = 0,075 mol · 18 g/mol.
m(H₂O) = 1,35 g.

The mass of H₂O produced from the reaction of 9.5 g of H₂ with 1.2 g of O₂ is 1.3515 g. The calculation is based on the molar mass of the substances and the balanced equation for the formation of water.

The question asks for the mass of H₂O produced from the reaction of hydrogen (H₂) with oxygen (O₂). According to the balanced chemical equation of the formation of water, which is 2H₂ + O₂
ightarrow 2H₂O, 2 moles of H₂ react with 1 mole of O₂ to produce 2 moles of H₂O. The molar masses are as follows: H₂ (2.02 g/mol) and O₂ (32.0 g/mol). Since 1 mole of water (H₂O) has a molar mass of 18.02 g, we can use this information to calculate the mass of water produced.

The mass of 9.5 g of H₂ corresponds to 9.5 g / 2.02 g/mol =4.7 moles of H₂, and the mass of 1.2 g of O₂ corresponds to 1.2 g / 32.0 g/mol = 0.0375 moles of O₂. Since oxygen is the limiting reagent here, it will determine how much water can be produced. From the stoichiometry of the reaction, 1 mole of O₂ will produce 2 moles of H₂O. Therefore, 0.0375 moles of O₂ would produce 0.0375 moles * 2 = 0.075 moles of H₂O. To find the mass: 0.075 moles * 18.02 g/mol = 1.3515 g of H₂O.

Therefore, the mass of H₂O produced is 1.3515 g.

Calculate the vapor pressure of a solution of 0.99 mol of cholesterol in 5.4 mol of toluene at 32°c. pure toluene has a vapor pressure of 41 torr at 32°c. (assume ideal behavior.)

Answers

Explanation:

No. of moles of cholesterol solute, [tex]n_{1}[/tex] = 0.99 mol

No. of moles of toulene solvent, [tex]n_{2}[/tex] = 5.4 mol

Hence, total number of moles of solution will be as follows.

                  n = [tex]n_{1} + n_{2}[/tex]

                     = 0.99 mol + 5.4 mol

                     = 6.39 mol

Therefore, mole fraction of cholestrol solute ([tex]\chi_{1}[/tex]) is as follows.

                = [tex]\frac{\text{no. of moles of chloesterol}}{\text{Total number of moles of solution (n)}}[/tex]  

     [tex]\chi_{1}[/tex] = [tex]\frac{0.99 mol}{6.39 mol}[/tex]

                      = 0.154

Vapor pressure of pure toulene solvent ([tex]p^{o}[/tex]) = 41 torr

Vapor pressure of solution = P

Hence, formula to calculate relative lowering of vapor pressure is as follows.

     Relative lowering of vapor pressure = [tex]\frac{p^{o} - P}{p^{o}}[/tex]

As per relative lowering of vapor pressure colligative property, the relative lowering of vapor pressure is equal to the mole fraction of solute.

Hence,     [tex]\frac{p^{o} - P}{p^{o}}[/tex] = [tex]\chi_{1}[/tex]

               [tex]\frac{41 torr - P}{41 torr}[/tex] = 0.154

                         41 torr - P = 6.314

                                      P = 34.686 torr

or,                                      = 35 torr

Therefore, we can conclude that vapor pressure of the solution is 35 torr.

Final answer:

To calculate the vapor pressure of a cholesterol-toluene solution, we use Raoult's Law, which gives a vapor pressure of approximately 34.65 torr at 32°C after calculating the mole fraction of toluene and applying the formula.

Explanation:

To calculate the vapor pressure of a solution containing 0.99 mol of cholesterol in 5.4 mol of toluene at 32°C, where pure toluene has a vapor pressure of 41 torr, we use Raoult's Law. This law states that the vapor pressure of a solution (Psolution) is equal to the mole fraction of the solvent (Xsolvent) times the vapor pressure of the pure solvent (Psolvent).

First, calculate the mole fraction of toluene, which is given by the number of moles of toluene divided by the total number of moles in the solution: Xtoluene = moles of toluene / (moles of toluene + moles of solute) = 5.4 / (5.4 + 0.99) = 5.4 / 6.39.

Next, apply Raoult's Law: Psolution = Xtoluene × Ptoluene = (5.4 / 6.39) × 41 torr. By calculating, we find Xtoluene is approximately 0.845, and thus Psolution = 0.845 × 41 torr = 34.645 torr. So, the vapor pressure of the solution is approximately 34.65 torr at 32°C.

Codeine (c18h21no3) is a weak organic base. a 5.0 x 10-3 m solution of codeine has a ph of 9.95. what is the pkb for this base

Answers

Answer is: pKb for codeine is 5,8.
Chemical reaction:  C₁₈H₂₁NO₃ + H₂O ⇄ C₁₈H₂₁NO₃H⁺ + OH⁻.
c(C₁₈H₂₁NO₃) = 5·10⁻³ M = 0,005 mol/L.
pH = 9,95.
pOH = 14 - 9,95 = 4,05.
[OH⁻] = 10∧(-4,05) = 0,000089 mol/L.
[OH⁻] = [C₁₈H₂₁NO₃H⁺] = 8,9·10⁻⁵ mol/L.
[C₁₈H₂₁NO₃] = 0,005 mol/L - 0,000089 mol/L = 0,004911 mol/L.
Kb = [OH⁻] · [C₁₈H₂₁NO₃H⁺] / [C₁₈H₂₁NO₃].
Kb = (0,000089 mol/L)² / 0,004911 mol/L = 1,613·10⁻⁶.
pKb = -log(1,613·10⁻⁶) = 5,8.

What is the molecular formula of the molecule that has an empirical formula of C2H2O and a molar mass of 252.22 g/mol?

Answers

Ok I got it wrong I think but I'm too lazy to delete all my hard work soooo.... merry Christmas?
Molar masses of
C = 12.0107
H = 2.016
O = 15.999
Now what we gots tuh do is take the masses and add them together, but we have to add 2 carbons and 2 oxygens because we are trying to find the molar mass of the empirical formula. So...
2(12.0107)+2(2.016)+15.999
24.0214+4.032+15.999 = 44.0524
Now that we have the molar mass of the empirical formula, we divide the 252.22 by it.
252.22/44.0524 = 5.7254
72.0642+12.096+95.994

Empirical formula is the simplest whole number ratio of elements in a compound. Molecular formula is n times the empirical formula, where n is integers 1,2,...  Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].

What is empirical formula?

Empirical formula gives the proportion of the element that is present in a compound. It does not give information about the actual number or the arrangements of the atoms.

n= molecular formula÷ empirical formula

Molar masses of  C[tex]_2[/tex]H[tex]_2[/tex]O

C = 12.0107

H = 2.016

O = 15.999

Molar masses of  C[tex]_2[/tex]H[tex]_2[/tex]O =2(12.0107)+2(2.016)+15.999

                                         =24.0214+4.032+15.999

                                         = 44.0524

252.22/44.0524 = 5

C[tex]_2[/tex]H[tex]_2[/tex]O ×5=C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]

The molecular formula is C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]

Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].

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Sodium chloride comprises 97%-99% of table salt. Given their location on the periodic table, identify the ionic charge for each element and predict the chemical formula of the compound formed. A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s). B) Sodium, Na, is an alkaline earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl2(s). C) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a noble gas and is in Group VIA with a charge of -2. These will form Na2Cl2(s). D) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a diatomic gas and is in Group VIA with a charge of -2. These will form Na2Cl(s).

Answers

The answer is A) Sodium is an Alkali metal and is in group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in group VIIA with a charge of -1. These will form NaCl(s).

Answer is: A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s).

Table salt is sodium chloride mixed with small amount of potassium iodide (KI), sodium iodide (NaI) or sodium iodate (NaIO₃).

Atomic level - sodium chloride (NaCl) has crystal cubic structure (lattice-type arrangement) with ionic bonds. Sodium is cation with charge 1+ and chlorine is an anion with charge 1-.

Macroscopic level - table salt is colorless crystal, soluble in water with high melting and boiling temperature.

Ionic compounds are good good electricity and heat conductors, because ionic compounds have mobile ions (cations and anions) that are able to transfer electrical charge.

n the balanced equation 4Fe + 3O2à 2Fe2O3 , how many atoms of iron (Fe) are reacting with every three molecules of oxygen (O2)?

Answers

Answer is: four iron atoms are reacting with every three molecules of oxygen.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
From chemical reaction: n(Fe) : n(O₂) = 4 : 3.
Ratios of atoms of iron and molecules of oxygen is 4 : 3..
There is four atoms of iron and six atoms of oxygen on both side of reaction.

Final answer:

Four atoms of iron (Fe) are reacting with every three molecules of oxygen (O₂) in the balanced chemical equation 4Fe + 3O₂ → 2Fe₂O₃.

Explanation:

In the balanced chemical equation 4Fe + 3O₂ → 2Fe₂O₃, for every three molecules of oxygen (O₂) that reacts, there are four atoms of iron (Fe) involved in that reaction. This is because the coefficients in the equation represent the stoichiometric ratios of the reactants and products. Hence, according to the coefficient in front of Fe, four atoms of iron react with three diatomic oxygen molecules to form two molecules of iron (III) oxide (Fe₂O₃).

2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio? CO2:H2O = 14:6 CO2:H2O = 6:14 CO2:H2O = 1:1 O2:H2O = 15:6

Answers

The products of the reaction are the molecules on the right, thus water and carbon dioxide, hence we eliminate choice 4. Every time the reaction takes place, 14 molecules of CO2 are created and 6 molecules of H2O by the stoicheiometry of the reaction. This ratio will remain throughout the whole reaction, however many reactants are used up. Hence, the correct ratio is CO2:H2O=14:6, answer a).

Answer:

The Answer is a) CO2:H2O = 14:6

Explanation:

Hydrogen peroxide, h2o2(aq), decomposes into water and oxygen. adding a small amount of fecl3(aq) increases the rate of gas evolution in this reaction. what is the best description of the role of fecl3?

Answers

I would call ferric trichloride a catalyst here. It increases the rate of the rxn.

Answer:

fecl₃ acting as catalyst-

iron (III) chloride is acts as the catalyst for the reaction which takes place in the transformation of hydrogen peroxide, H₂O₂(aq) into the two main products mainly water,H₂O and oxygen,O₂.

The reaction is as follow:H₂O₂(aq)⇒ H₂O + O₂.

Explanation:

Catalysts-

A catalyst provide the best route or the easy path to start or initiate the reaction or the chemical transformation which leads to the speeding up the reactions.

A ball-and-stick model of a molecule provides much the same information as a

Answers

A ball-and-stick model of a molecule provides much the same information as a structure of a hydrocarbonates

Both the ball-and-stick and space-filling models are 3D molecular representations, with the former displaying the bonds and the latter showing the relative atom sizes and general shape.

A ball-and-stick model of a molecule provides much the same information as a space-filling model. Both are used to represent the three-dimensional structure of a molecule in different ways. The ball-and-stick model shows atoms as spheres and bonds as sticks, highlighting the bond angles and lengths between atoms.

In contrast, the space-filling model represents atoms by spheres that are sized proportionally to the atoms' radii, depicting the actual volume occupied by the atoms without showing the bonds explicitly.

While the ball-and-stick model may exaggerate the space between the atoms, it is beneficial for understanding the geometry of the chemical bonds. The space-filling model, however, allows for visualization of the molecule's general shape and the relative sizes of the atoms. Both models are simplifications and do not fully capture subtle variations in bond lengths and angles.

One form of transportation that uses nuclear power for energy is the
A) airplane.
B) automobile.
C) motorcycle.
D) submarine.

Answers

Submarines use a nuclear reactor.

One form of transportation that uses nuclear power for energy is the  submarine. Therefore, option D is correct.

What do you mean by nuclear energy ?

The term nuclear energy is defined as the energy in the nucleus, of an atom. Atoms are small units that formed all matter in the universe, and energy is what binds the nucleus together. There is a huge amount of energy in an atom's dense nucleus.

Nuclear submarines and aircraft carriers are powered by onboard nuclear reactors. Atoms in the nuclear reactor break, which passes  energy as heat. This heat is used to create high-pressured steam.

U.S. submarines rely on nuclear power for both propulsion and life support. The nuclear reactor heats water to produce steam that drives a turbine to transfer the propeller.

Thus, option D is correct.

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An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre of the Ba(No3)2 solution?

Answers

Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.

which molecular formula is also an empirical formula?
1)C6h6
2)h2o2
3) n2h4
4) n2o5

Answers

The answer is number 4, N2O5.

Because it can't be divided any further since 2 and 5 do not have a common divisor.

The molecular formula which is also an empirical formula is Choice 4: N2O5

The molecular formula of a compound is always a multiple of the empirical formula.

The choices are analysed as follows;

For Choice 1;

The subscripts can further be divided. As such, C6H6 is a molecular formula but not an empirical formula.

For Choice 2;

The subscripts can further be divided. As such, H2O2 is a molecular formula but not an empirical formula.

For Choice 3;

The subscripts can further be divided. As such, N2H4 is a molecular formula but not an empirical formula

However; For Choice 3;

The subscripts can not be further divided. As such, N2O5 is a molecular formula and also an empirical formula.

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A diels–alder reaction of 2,5-dimethylfuran and maleic anhydride gives a compound a that undergoes acid-catalyzed dehydration to give 3,6-dimethylphthalic anhydride.

Answers

The Diels-Alder reaction between 2,5-dimethylfuran and maleic anhydride produces a compound that can be dehydrated to form 3,6-dimethylphthalic anhydride. Maleic anhydride's electron-withdrawing groups and the s-cis configuration of the diene aid the reaction's efficiency and dictate the stereochemistry of the product.

The Diels-Alder reaction between 2,5-dimethylfuran and maleic anhydride is a classic example of a cycloaddition reaction in organic chemistry. This reaction forms a compound that, upon dehydration, can yield 3,6-dimethylphthalic anhydride. Maleic anhydride serves as an excellent dienophile due to the electron-withdrawing effect of the carbonyl groups making the alkene carbons electron-poor and thus more reactive. The s-cis configuration of the diene, as in the case with cyclopentadiene, enhances the reaction's efficiency.

The stereochemistry of the Diels-Alder reaction dictates that the product will generally prefer the endo position, and models can help visualize these reactions and their outcomes. Acid-catalyzed dehydration is commonly used in organic synthesis to generate -unsaturated carbonyl compounds, which can lead to structural rearrangements depending on the nature of the starting materials and reaction conditions.

100 POINTS Which energy source produces electricity at a hydroelectric dam? A. solar panels B. wind turning turbines C. falling water D. pressure from water on the dam

100 POINTS

Answers

The answer is C falling water hope this helps

Electricity at a hydroelectric dam is produced by falling water, which turns turbines to generate electricity. The ultimate source of this energy is solar energy that drives the hydrological cycle.

The energy source that produces electricity at a hydroelectric dam is C. falling water. This process involves the conversion of potential energy stored in the water behind the dam into kinetic energy as the water flows down. The kinetic energy turns the blades of turbines, which then drive a generator to produce electricity. The ultimate source of the electrical energy produced by a hydroelectric plant is solar energy, which drives the hydrological cycle that lifts water to high elevations through evaporation and precipitation.

Be sure to answer all parts. identify and label the species in each reaction. (a) nh4+(aq) + h2o(l) ⇌ nh3(aq) + h3o+(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base (b) cn−(aq) + h2o(l) ⇌ hcn(aq) + oh−(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base

Answers

a)

NH⁴⁺(aq) + H₂O(l) ⇌ NH₃(aq) + H₃0⁺(aq)

- acid a species that able to donate (H+): NH⁴⁺
- base a species that is able to accept a proton (H+): H₂O
- conjugate base a species formed when acid donates a proton (H+): NH₃
- conjugate acid a species formed by a base accepts a proton (H+): H₃0⁺

b)

CN⁻(aq) + H₂O(l) ⇌ HCN(aq) + OH⁻(aq)

base a species that is able to accept a proton (H+): CN⁻
acid a species that able to donate (H+): H₂O
conjugate acid a species formed by a base accepts a proton (H+): HCN
conjugate base a species formed when acid donates a proton (H+): OH⁻

Final answer:

In the given reaction, label the species as acid, base, conjugate acid, and conjugate base. (a) Acid: NH4+, Base: H2O, Conjugate Acid: H3O+, Conjugate Base: NH3. (b) Acid: CN-, Base: H2O, Conjugate Acid: HCN, Conjugate Base: OH-

Explanation:

(a) In the reaction: NH4+(aq) + H2O(l) ⇌ NH3(aq) + H3O+(aq), we have NH4+ as the acid and H2O as the base. After the reaction, NH3 becomes the conjugate base and H3O+ becomes the conjugate acid.

(b) In the reaction: CN-(aq) + H2O(l) ⇌ HCN(aq) + OH-(aq), we have CN- as the acid and H2O as the base. After the reaction, HCN becomes the conjugate acid and OH- becomes the conjugate base.

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