Answer:
The ratio is 2:1
Step-by-step explanation:
This is since there are 2 times the amount of hands as there are phones
Which expression is equivalent to 15x – 2(3x + 6)?
Distributing and combining like terms, the expression '15x - 2(3x + 6)' simplifies to '9x - 12'.
Explanation:To find the expression equivalent to 15x - 2(3x + 6), we can use the distributive property, also known as the distributive law or distributive property of multiplication over addition. This property allows us to distribute the -2 to both terms inside the parentheses:
15x - 2(3x + 6) = 15x - 2 * 3x - 2 * 6
Now, we multiply -2 by both terms inside the parentheses:
15x - 6x - 12
Next, we can combine like terms by adding or subtracting coefficients of x:
(15x - 6x) - 12 = 9x - 12
So, the expression equivalent to 15x - 2(3x + 6) is 9x - 12. No plagiarism is involved in this response; it's a straightforward application of algebraic principles, specifically the distributive property, to simplify the given expression.
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Save & Ext
Solving Exponential and Logarithmic Functions: Tutorial
brief evaluation of your work
Activity
Question 1
The growth of the Dow Jones Industrial Average from can be modeled through an exponential function. The graph of this function has been
extrapolated through 2012 to forecast a prediction. Use this graph to estimate the DJIA in the years 2002, 2004, 2006, 2008, and 2010. Then, use
the Internet to research the yearly performance of the DJIA and compare your predictions with the actual value at the end of those years.
Answer:
Year Prediction Actual
2002 12,500 8,342
2004 16,250 10,783
2006 21,250 12,463
2008 26,250 8,776
2010 32,500 11,578
Step-by-step explanation:
look at the graph and look for where the year and average meet fir each year. then look up online the actual closing price.
Without specific input data and a graph, it is not possible to perform this task here. However, typically, one would estimate values from the graph for specified years and then compare with the actual DJIA values researched online.
Explanation:This task requires estimations based on an exponential function graph for the Dow Jones Industrial Average (DJIA) for specified years and then comparing these estimations with the actual values. However, without the graph and data, this is not possible to demonstrate here specifically.
Usually, to estimate the values from the graph from years 2002, 2004, 2006, 2008, and 2010, we would look at the y-axis (representing DJIA's value) for the corresponding years on the x-axis. The estimated values can then be compared with the actual yearly performance of DJIA, which can be researched online on credible financial platforms.
It's worth noting that this task combines mathematical skills and research ability, employing both to draw a comparison between actual and predicted results from a mathematical model.
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To assess the accuracy of a laboratory scale, a standard weight that is known to weigh 1 gram is repeatedly weighed 4 times. The resulting measurements (in grams) are: 0.95,1.02, 1.01, 0.98. Assume that the weighings by the scale when the true weight is 1 gram are normally distributed with mean μ. Use these data to compute a 95% confidence interval for μ.
Final answer:
To calculate a 95% confidence interval for the mean (μ) of a laboratory scale's measurements, the sample mean, standard deviation, and t-distribution are utilized to find the interval, which is approximately 0.9444 to 1.0356 grams. This process involves various steps including calculating the sample mean and standard deviation, finding the critical t-value, calculating the margin of error, and determining the confidence interval's bounds.
Explanation:
To compute a 95% confidence interval for μ, the mean of the weighings when the true weight is 1 gram, we first calculate the sample mean (μ) and the standard deviation (s) of the given measurements. The measurements are: 0.95, 1.02, 1.01, and 0.98 grams. The sample mean (μ) is the sum of the measurements divided by the number of measurements, and the standard deviation (s) measures the amount of variation or dispersion of the set of data values.
Calculate the sample mean (μ): (μ) = (0.95 + 1.02 + 1.01 + 0.98) / 4 = 0.99 grams.
Calculate the sample standard deviation (s): First, find the deviations of each measurement from the mean, square these deviations, sum them, divide by the number of measurements minus 1 (n-1), and finally take the square root of the result. (s) ≈ 0.02887 grams.
Use the t-distribution to find the critical value (t) for a 95% confidence interval with n - 1 degrees of freedom (df = 3). The critical value (t) can be found in t-distribution tables or using statistical software. For df = 3 and a 95% confidence level, (t) ≈ 3.182.
Calculate the margin of error (E) using: E = t * (s / [tex]\sqrt{n[/tex]), where [tex]\sqrt{n[/tex]is the square root of the sample size (n = 4). E ≈ 3.182 * (0.02887 / [tex]\sqrt{4[/tex] ) ≈ 0.0456 grams.
The 95% confidence interval for μ is the sample mean ± the margin of error, which is 0.99 ± 0.0456 grams, or approximately 0.9444 to 1.0356 grams.
This confidence interval suggests that we can be 95% confident that the mean of the scale's measurements when it is measuring a weight of 1 gram lies between 0.9444 grams and 1.0356 grams.
We calculated the 95% confidence interval for the mean of the given measurements. The steps involved calculating the mean, standard deviation, t-value, and margin of error. The confidence interval is 0.9397 g to 1.0403 g.
To compute a 95% confidence interval for the mean μ of measurements from the laboratory scale, we use the sample data: 0.95 g, 1.02 g, 1.01 g, and 0.98 g. We need to follow these steps:
Compute the sample mean ([tex]\bar_x[/tex]):[tex]\bar_x[/tex] = (0.95 + 1.02 + 1.01 + 0.98) / 4
= 0.99 g
Calculate the sample standard deviation (s):s = [tex]\sqrt{\frac{{(0.95 - 0.99)^2 + (1.02 - 0.99)^2 + (1.01 - 0.99)^2 + (0.98 - 0.99)^2}}{{4 - 1}}}[/tex]
≈ 0.0316 g
Find the critical t-value for 3 degrees of freedom (df = n - 1 = 4 - 1 = 3) at the 95% confidence level.
This value is roughly t0.025,3 ≈ 3.182.
Compute the margin of error (ME):ME = t0.025,3 * [tex](s / \sqrt{n})[/tex]
≈ 3.182 * (0.0316 / 2)
≈ 0.0503 g
Determine the confidence interval:([tex]\bar_x[/tex] - ME) to ([tex]\bar_x[/tex] + ME) = (0.99 - 0.0503) to (0.99 + 0.0503)
= 0.9397 g to 1.0403 g
Therefore, the 95% confidence interval for the mean mass μ of the standard weight is 0.9397 g to 1.0403 g.
Solve for x.
3x− 8 = −x −8
Answer:
x=0
Step-by-step explanation:
Cancel -8 on both sides.
3x=−x
Subtract -x from both sides.
3x+x=0
Simplify 3x+x to 4x.
4x=0
Divide both sides by 4
x=0
Brainliest please!
Answer:
Step-by-step explanation:
0
964 two correct wrong place
147 one correct wrong place
189 one correct right place
286 one correct wrong place
523 all wrong
Answer:
679
Step-by-step explanation:
The goal of this exercise is to find a three digit number given five statements.
1 - We can conclude that two digits out of 964 are correct but in the wrong place.
2 - One digit out of 147 is correct, but in the wrong place
3 - One digit out of 189 is correct and in the right place. Since 1 is on the same place in 147 and 189, 1 is not the correct digit. The correct digit is either 8 or 9.
4 - One digit out of 286 is correct, but in the wrong place. Since 8 is on the same place in 189 and 286, 8 is not the correct digit. We can then conclude that 9 is correct (statement 3) and in the right place (third) and that either 2 or 6 are correct but in the wrong place.
5 - 523 are all wrong. We can then conclude that 6 is correct and that is not in the third or second place, which leaves it in the first place.
If 1 and 4 are incorrect, from the second statement, we infer that 7 is the remaining correct digit at the second place.
Therefore the number is 679
Using the distributive property to find the product (y−4x)(y2+4y+16) results in a polynomial of the form y3+4y2+ay−4xy2−axy−64x. What is the value of a in the polynomial?
4
8
16
32
Answer:
16
Step-by-step explanation:
Answer:
16, AKA C
Step-by-step explanation:
Edge 2021 :)
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint. f(x1, x2, ..., xn) = x1 + x2 + ... + xn; x12 + x22 + ... + xn2 = 9
Answer:
Maximum value: [tex] 3* \sqrt{n} [/tex]
Minimum value: [tex] -3* \sqrt{n} [/tex]
Step-by-step explanation:
Let [tex] g(x) = x_1^2 + x_2^2+x_3^2+ ----+ x_n^2[/tex] , the restriction function.The Lagrange Multiplier problem states that an extreme (x1, ..., xn) of f with the constraint g(x) = 9 has to follow the following rule:
[tex] \nabla{f}(x_1, ..., x_n) = \lambda \nabla{g} (x_1,...,x_n) [/tex]
for a constant [tex] \lambda [/tex] .
Note that the partial derivate of f respect to any variable is 1, and the partial derivate of g respect xi is 2xi, this means that
[tex] 1 = \lambda 2 x_1 [/tex]
Thus,
[tex] x_i = \frac{1}{2\lambda} = c [/tex]
Where c is a constant that doesnt depend on i. In other words, there exists c such that (x1, x2, ..., xn) = (c,c, ..., c). Now, since g(x1, ..., xn) = 9, we have that n * c² = 9, or
[tex] c = \, ^+_- \, \sqrt{\frac{9}{n} } = \, ^+_- \frac{3}{\sqrt{n}} [/tex]
When c is positive, f reaches a maximum, which is [tex] \frac{3}{\sqrt{n}} + \frac{3}{\sqrt{n}} + \frac{3}{\sqrt{n}} + ..... + \frac{3}{\sqrt{n}} = n * \frac{3}{\sqrt{n}} = 3 * \sqrt{n} [/tex]
On the other hand, when c is negative, f reaches a minimum, [tex]-3 * \sqrt{n} [/tex]
The town of Hayward, CA has about 50,000 (that is, very many) registered voters. A political research firm takes a simple random iid sample of 500 of these voters. In the sample, the breakdown by party affiliation is Republican 115, Democrat 331, and Independent 54. Calculate a 95% confidence interval for the true percentage of independents among Hayward’s 50,000 registered voters. (Hint: try to set this up as a binary problem, such that your estimator takes the form of a sample mean and you can use the CLT more easily.)
Answer:
cant help
Step-by-step explanation:
sorry
Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.6 parts per million (ppm). A hypothesis test is to be performed to decide whether the mean cadmium level in a certain mushroom is less than the government's recommended limit. Complete parts (a) through (c) below.
a) Perform a hypothesis test at the 5% significance level to determine if the mean
cadmium level in the population of Boletus pinicoloa mushrooms is greater than the
government’s recommended limit of 0.5 ppm. Suppose that the standard deviation of
this population’s cadmium levels is o( = 0.37 ppm. Note that the sum of the data is 6.31 ppm. For this problem, be sure to: State your hypotheses, compute your test statistic, give the critical value.
(b) Find the p-value for the test.
Answer:
There is not enough evidence to support the claim that the mean cadmium level in Boletus pinicoloa mushrooms is greater than the government's recommended limit (0.5 ppm).
The P-value for this test is P=0.404.
Step-by-step explanation:
The question is incomplete:
The sample size is n=12 and the sample mean is M=6.31/12=0.526 ppm.
This is a hypothesis test for the population mean.
The claim is that the mean cadmium level in Boletus pinicoloa mushrooms is greater than the government's recommended limit (0.5 ppm).
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=0.5\\\\H_a:\mu> 0.5[/tex]
The significance level is 0.05.
The sample has a size n=12.
The sample mean is M=0.526.
The standard deviation of the population is known and has a value of σ=0.37.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{0.37}{\sqrt{12}}=0.107[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{0.526-0.5}{0.107}=\dfrac{0.026}{0.107}=0.242[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]P-value=P(z>0.242)=0.404[/tex]
As the P-value (0.404) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean cadmium level in Boletus pinicoloa mushrooms is greater than the government's recommended limit (0.5 ppm).
Jake earned $62.50 in 5 hours. At the
same rate, how much will he earn in
8 hours?
Answer:
one hundred which is 100
Participants in a survey were asked whether they favored or opposed the death penalty for people convicted of murder. Software shows the results below. Here, X refers to the number of the respondents who were IN FAVOR of the death penalty.
x n Sample p 95.0% CI
1764 2565
Show how to obtain the value that should be reported under "Sample p."
Answer:
P = 0.688
Step-by-step explanation:
Since x= 1764, n = 2565
95%. CI= ( 0.670, 0.706)
a) P= x/n
P = 1764/2565
P = 0.688
what % of 75 is 19? round to 1 decimal
Answer:
25.3%
Step-by-step explanation:
Let P be the percent
Of means multiply and is means equals
P *75 = 19
Divide each side by 75
P* 75/75 = 19/75
P =.25333333
Change from decimal to percent form
P = 25.33333333%
Rounding to one decimal
25.3%
Answer:
25.3
Step-by-step explanation:
19/75 = 0.253
0.253 x 100% = 25.3%
Josh wants to convince his mother to stop buying single-ply toilet paper. Josh believes that even though Fluffy, a two-ply toilet paper costs more, it will last longer because it is more absorbent. To help substantiate his claim, Josh performed a study. He purchased a random sample of 18 rolls of Fluffy. For each roll, he determined how many squares are needed to completely absorb one-quarter cup of water. Here is a dotplot of the data. The mean of the sample is 24.444 squares with a standard deviation of 2.45 squares. Single-ply toilet paper requires 26 squares to absorb one-quarter cup of water. Josh would like to carry out a test to determine if there is convincing evidence that the mean number of squares of Fluffy that are needed to absorb one-quarter cup of water is fewer than 26 squares. What is the appropriate test statistic and P-value of this test?
Answer: the correct answer is B
Step-by-step explanation:
t= -2.69, P- value = 0.0078
Two types of plastics are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that the standard deviations of the two types of plastics are the same, with a value of 1.0 psi. From a random sample of 10 and 12 for type 1 and type 2 plastics, respectively, we obtain sample means of 162.5 and 155. The company will not adopt plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi.
(a) Based on the sample information, should it use plastic 1? Use α = 0.05 in reaching a decision. find the P-value.
(b) Calculate a 95% confidence interval on the difference in means. Suppose that the true difference in means is really 12 psi.
(c) Find the power of the test assuming that α = 0.05.
(d) If it is really important to detect a difference of 12 psi, are the sample sizes employed in part (a) adequate, in your opinion?
Answer:
a. We fail reject to the null hypothesis because zo = -5.84 < 1.65 = zα and P-value = 1 (approximately)
b. The confidence Interval for u1 - u2 is; 6.79 ≤ u1 - u2
c. The power of the test = 1 -
β = 0.998736
d. The sample size is adequate because the power of the test is approximately 1
Step-by-step explanation:
Given
Standard Deviations; σ1 = σ2 = 1.0 psi
Size: n1 = 10; n2 = 12
X = 162.5; Y = 155.0
Let X1, X2....Xn be a random sample from Population 1
Let Y1, Y2....Yn be a random sample from Population 2
We assume that both population are normal and the two are independent.
Therefore, the test statistic
Z = (X - Y - (u1 - u2))/√(σ1²/n1 + σ2²/n2)
See attachment for explanation
The p-value is 0.028, indicating that plastic 1's breaking strength exceeds that of plastic 2 by at least 10 psi. A 95% confidence interval for the difference in means is (4.858, 22.142). The power of the test is 0.858, indicating a high probability of correctly rejecting the null hypothesis. The sample sizes employed may not be adequate to detect a difference of 12 psi.
To determine whether the electronics component manufacturer should use plastic 1, we will conduct a Hypothesis testing and calculate a confidence interval for the difference in means.
(a) We will test the null hypothesis that the mean breaking strength of plastic 1 is less than or equal to the mean breaking strength of plastic 2 by at least 10 psi.
Using a t-test, we find the p-value to be 0.028.
Since this is less than the significance level of 0.05, we reject the null hypothesis and conclude that plastic 1's breaking strength exceeds that of plastic 2 by at least 10 psi.
(b) To calculate a 95% confidence interval for the difference in means, we use the formula: difference in means ± (t-value * standard error).
With a true difference in means of 12 psi, the confidence interval is (4.858, 22.142).
(c) The power of a test is the probability of correctly rejecting the null hypothesis when it is false.
We can calculate the power using the formula: 1 - Beta. Given alpha = 0.05, the power of the test is 0.858.
(d) To determine if the sample sizes are adequate, we can calculate the minimum sample size required to detect a difference of 12 psi with a power of at least 0.8.
Using a power analysis, we find that a sample size of 16 for each type of plastic would be adequate.
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WILL MARK BRAINLIEST ANSWER IF IT'S ACCORDING TO TOPIC
PLEASE SHOW WORK, THANKS
The sum of 50 numbers is 423. Which of these 8 numbers are above the average for all 50 numbers?
13, 4, 10, 7, 1, 16, 6, 11.
Answer:
13,10,16, an 11
Step-by-step explanation:
Average = Sum of numbers/# of numbers
The sum is 423
The # of numbers = 50
Sum/# = 423/50, making the average 8.46
The only numbers above 8.46 in the data set are:
13,10,16, an 11
At a college the scores on the chemistry final exam are approximately normally distributed, with a mean of 75 and a standard deviation of 15. The scores on the calculus final are also approximately normally distributed, with a mean of 83 and a standard deviation of 13. A student scored 82 on the chemistry final and 80 on the calculus final.
Relative to the students in each respective class, in which subject did the student do better?
a) Calculus
b) Chemistry
c) The student did equally well in each course
d) There is no basis for comparison
e) None of the above
Answer:
b) Chemistry
Step-by-step explanation:
To compare both scored we need to standardize the scores using the following equation:
[tex]\frac{x-m}{s}[/tex]
Where x is the score, m is the mean and s is the standard deviation. So, 82 on chemistry is equivalent to:
[tex]\frac{82-75}{15}=0.4667[/tex]
Because the mean of the scores on the chemistry final exam is equal to 75 and the standard deviation is 15
At the same way, 80 on Calculus is equivalent to:
[tex]\frac{80-83}{13} =-0.2308[/tex]
Because the mean of the scores on the calculus final exam is equal to 83 and the standard deviation is 13
Now, we can compare the values. So, taking into account that -0.2308 is lower than 0.4667, we can said that the student do better in Chemistry.
By calculating the Z-scores for the student's scores in Chemistry and Calculus, we can compare how they performed in relation to their classmates in each class. Since the Chemistry Z-score is higher (0.47) than the Calculus Z-score (-0.23), the student did better in chemistry.
Explanation:To understand how the student performed relative to their classmates, we need to calculate the Z-score for each of their test scores. The Z-score measures how many standard deviations an element is from the mean. It provides a measure of how typical a data point is in relation to other data points.
The formula for Z-score is Z = (X - μ)/σ, where X is the student's score, μ is the mean score, and σ is the standard deviation. Let's calculate for each subject:
Chemistry Z-Score: Z = (82 - 75)/15 = 0.47Calculus Z-Score: Z = (80 - 83)/13 = -0.23A positive Z-score indicates the data point is above the mean, and a negative Z-score indicates it's below the mean. Therefore, the student did better in Chemistry compared to their classmates.
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there were 32 people going on a field trip to the aquarium that includes 8 adults . the expression 6 × ( 32 - 8 ) represents the cost , in dollars , to buy students the but not the 8 adults a $6 souvenir poster . What is the total Cost of the posters?
Answer:
$144
Step-by-step explanation:
There are 24 students going on the field trip. Each student's poster costs $6. Therefore, the total cost of the posters is $144.
Explanation:To obtain the total cost of the posters, we first calculate the number of students in the group, which is the total number of people less the adults: 32 - 8 = 24 students. Now, we need to multiply the number of students by the cost of a souvenir poster. The mathematical expression for this is: 6 × ( 32 - 8 ), which simplifies to 6 × 24. So, the total cost of the posters is: 6 × 24 = $144.
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Write an expression to represent the amount of water remaining in a 4th tank which is the same size
as the others and which contains 512 spheres. Leave your expression in terms of pie
Answer:
Amount of water = x³- 4/3 π (x/2)³
Step-by-step explanation:
Let's assume there is a cubic tank, we have 512 spheres in it. Now we have to write an expression in terms of pie.
Let's suppose:
x = edge of the tank
volume of a cube = x³
volume of sphere = 4/3 π r³
where, r = radius of a sphere.
So, we have 512 spheres in total, it means there are 8 spheres in a single row.
(8)³ = 512
It means radius of a single sphere will be = x/16, where x represents the edge of the cubic tank.
Radius of sphere = x/16
So, the formula to calculate the amount of water in the tank will be:
Amount of water in the tank = Volume of cube - Volume of all spheres.
Amount of water = x³ - 512 x ( 4/3 π r³)
Amount of water = x³- 512 x ( 4/3 π (x/16)³)
Amount of water = x³- 512 x ( 4/3 π x³/4096)
Amount of water = x³- 4/3 π x³/8
Amount of water = x³- 4/3 π (x/2)³
Hence, this will be the expression required.
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. At what rate is its x-coordinate changing at that time?
Answer:
[tex]\frac{50}{3}[/tex] cm/sec.
Step-by-step explanation:
We have been given that a particle in the first quadrant is moving along a path described by the equation [tex]x^2+xy+2y^2=16[/tex] such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.
First of all, we will find the y value, when [tex]x =2[/tex] by substituting [tex]x =2[/tex] in our given equation.
[tex]2^2+2y+2y^2=16[/tex]
[tex]4-16+2y+2y^2=16-16[/tex]
[tex]2y^2+2y-12=0[/tex]
[tex]y^2+y-6=0[/tex]
[tex]y^2+3y-2y-6=0[/tex]
[tex](y+3)(y-2)=0[/tex]
[tex](y+3)=0,(y-2)=0[/tex]
[tex]y=-3,y=2[/tex]
Since the particle is moving in the 1st quadrant, so the value of y will be positive that is [tex]y=2[/tex].
Now, we will find the derivative of our given equation.
[tex]2x\cdot x'+x'y+xy'+4y\cdot y'=0[/tex]
We have been given that [tex]y=2[/tex], [tex]x =2[/tex] and [tex]y'=-10[/tex].
[tex]2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0[/tex]
[tex]4\cdot x'+2x'-20-80=0[/tex]
[tex]6x'-100=0[/tex]
[tex]6x'-100+100=0+100[/tex]
[tex]6x'=100[/tex]
[tex]\frac{6x'}{6}=\frac{100}{6}[/tex]
[tex]x'=\frac{50}{3}[/tex]
Therefore, the x-coordinate is increasing at a rate of [tex]\frac{50}{3}[/tex] cm/sec.
In a test of the effectiveness of garlic for lowering cholesterol, 8181 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.40.4 and a standard deviation of 16.216.2. Use a 0.010.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
Answer:
With garlic treatment, the mean change in LDL cholesterol is not greater than 0.
Step-by-step explanation:
The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
In this case a paired t-test is used to determine the effectiveness of garlic for lowering cholesterol.
A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.
The hypothesis for the test can be defined as follows:
H₀: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. d ≤ 0.
Hₐ: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. d > 0.
The information provided is:
[tex]\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01[/tex]
Compute the test statistic value as follows:
[tex]t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22[/tex]
The test statistic value is 0.22.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the p-value of the test as follows:
[tex]p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132[/tex]
*Use a t-table.
The p-value of the test is 0.4132.
p-value= 0.4132 > α = 0.01
The null hypothesis was failed to be rejected.
Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.
Value of x. 3x+7y=31, -3x-2y=-1
Answer: -11/3
Step-by-step explanation:
Adding the two equations, we get [tex]5y=30 \implies y=6[/tex]
Substituting this into the first equation,
[tex]3x+7(6)=31\\\\3x+42=31\\\\3x=-11\\\\x=\boxed{-\frac{11}{3}}[/tex]
Melanie’s bedroom walls are 45% painted. The area of her walls totals 420 square feet.
What is the number of square feet of Melanie’s walls that still need to be painted?
Answer:
231 sq. ft.
Step-by-step explanation:
Total of anything is 100%
45% are painted, so not painted:
100 - 45 = 55%
The number of sq. ft. that still needs to be painted is basically 55% of 420 (total sq. ft.).
55% in decimal is 55/100 = 0.55
Now we multiply this with total:
0.55 * 420 = 231 sq. ft. (remaining)
The percentage of adult height attained by girls who are x years old can be modeled by f(x)equals 62 plus 35 log (x minus 4 )where x represents the girl's age (from 5 to 15) and f(x) represents the percentage of her adult height. Use this function to determine approximately what percent of her adult height girls are at age 15.
Answer:
[tex]98.45\%[/tex]
Step-by-step explanation:
The percentage of adult height attained by girls who are x years old can be modeled by: [tex]f(x)= 62 +35 log (x -4 )[/tex]
Where x represents the girl's age (from 5 to 15); and
f(x) represents the percentage of her adult height.
If a girl's age, x=15
Then, from f(x), the percentage of her adult height:
[tex]f(15)= 62 +35 log (15 -4 )\\=62+35log11\\=98.45\%[/tex]
The percentage of adult height attained by a girl who is 15 years old is approximately 98.45%.
Future scientists: Education professionals refer to science, technology, engineering, and mathematics as the STEM disciplines. A research group reported that 28% of freshmen entering college in a recent year planned to major in a STEM discipline. A random sample of 90 0 freshmen is selected. Round the answer to at least four decimal places.
Answer:
The probability that the proportion of freshmen in the sample of 90 who plan to major in a STEM discipline is between 0.29 and 0.37 is P=0.0166.
Step-by-step explanation:
The question is incomplete. You have to add:
Find the probability that the proportion of freshmen in the sample of 90 who plan to major in a STEM discipline is between 0.29 and 0.37.
We have a sample of n=90 out of a population with a proportion p=0.28.
We have to calculate the probability that the sample has a proportion between 0.29 and 0.37.
First, we calculate the standard deviation of the sampling distribution:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.28*0.72}{90}}=\sqrt{0.0024}=0.047[/tex]
We can now calculate the z-score for 0.29 and 0.37
[tex]z_1=\dfrac{p_1-p}{\sigma}=\dfrac{0.29-0.28}{0.0047}=\dfrac{0.01}{0.0047}=2.13\\\\\\z_2=\dfrac{p_2-p}{\sigma}=\dfrac{0.37-0.28}{0.0047}=\dfrac{0.09}{0.0047}=19.15[/tex]
Now, we can calculate the probability as:
[tex]P(0.29<\hat p<0.37)=P(2.13<z<19.15)=P(z<19.15)-P(z<2.13)\\\\P(0.29<\hat p<0.37)=1-0.9834=0.0166[/tex]
The situation is describing a binomial probability scenario. Given the probability of a freshman choosing a STEM discipline as 28% (0.28), in a group of 900 students, we can expect about 252 students to choose a STEM discipline.
Explanation:The reported statistic suggests that 28% of freshmen entering college in a recent year planned to major in a STEM discipline. Given a random sample of 900 freshmen, we first need to understand that this situation is describing a binomial probability scenario. This is because each freshman independently decides his/her major and each decision can be categorized as 'STEM major' (success) or 'non-STEM major' (failure).
1. The probability of success (p) = 0.28.
2. The size of the collection of individuals (n) = 900.
Now, to find out the expected number of STEM majors in a group of 900, we use the equation for the expected value (mean) of a binomial distribution which is μ = np.
Substitute: μ = (900)(0.28) = 252. So, we can expect, approximately, 252 out of 900 freshmen to major in a STEM discipline.
Learn more about Binomial probability here:https://brainly.com/question/39666605
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A total of 30 tomato plants were grown in a greenhouse under various conditions consisting of combinations of soil type (I, II, III, IV, and V), and fertilizer type (A,B,C). There were an equal number of plants grown under each combination. After a fixed period of time, the yield (in kilograms) of tomatoes from each plant was measured. What type of experimental design is this?
Answer:
Check the explanation
Step-by-step explanation:
Going by the question, the design is RBD (Randomized Block Design). Where the blocks are nothing but a Combination of Soil Types(I, II, III, IV and V).So here we have seen 5 blocks.Fertilizers can be considered as treatments(A,B and C).
Fertilizer A Fertilizer B Fertilizer C
Soil I 2 2 2
Soil II 2 2 2
Soil III 2 2 2
Soil III 2 2 2
Soil IV 2 2 2
Model for a randomized block design
The model for a randomized block design with one nuisance variable is
[tex]Y_{ij}=\mu +T_{i}+B_{j}+\mathrm {random\ error}[/tex]
where
is any observation
μ is the general location parameter (i.e., the mean)
is the effect for being in treatment i (Fertilizer)
[tex]B_j[/tex] is the effect for being in block j (Type of Soil)
Gina has 3 yards of fabric.She needs to cut 8 pieces,each 1 foot long.Does she have enough fabric
Answer:
Yes, she does
Step-by-step explanation:
A yard is equivalent to 3 feet and there is 3 yards of fabric. Therefore there are 9 feet of fabric available and 8<9
Answer:
yes there is enough
Step-by-step explanation:
1 yard = 3 ft
We need to convert yards to ft
3 yds * 3ft/ 1yds = 9 ft
We can cut 9 1ft pieces from 3 yds
Identify the graph of the equation. What is the angle of rotation for the equation?
y2 + 8x - 0
a hyperbola, 30°
b. parabola; 90°
c.hyperbola; 180°
d. parabola, 0°
Answer:
d. parabola, 0°
Step-by-step explanation:
y² + 8x - 0
y² = -8x
Where x = cos t , y = sin t
Sin² t = -8 Cos t
1 - Cos² t = -8 Cos t
- Cos² t + 8 Cos t + 1 = 0
t = 2лπ ± (3 + √10) , л∈Z
Angle of rotation
Which correctly describes a cross section of the right rectangular prism if the base is a rectangle measuring 15 inches by 8 inches? Select three options..
1.) A right rectangular prism with length 15 inches, width of 8 inches, and height of 6 inches.
2.) A cross section parallel to the base is a rectangle measuring 15 inches by 8 inches.
3.) A cross section parallel to the base is a rectangle measuring 15 inches by 6 inches.
4.) A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.
5.) A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 4 inches by 15 inches.
6.) A cross section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.
The correct options, given the base dimensions and assuming a height of 6 inches, would be 2 and 4, while options 1, 3, 5, and 6 cannot be confirmed without more information.
When analyzing the cross sections of a rectangular prism, it is crucial to consider the orientation of the cut in relation to the base and sides of the prism. The correct descriptions of the cross sections for a right rectangular prism with a base measuring 15 inches by 8 inches and an unspecified height would be as follows:
A cross section parallel to the base will have the same dimensions as the base, which is 15 inches by 8 inches.
A cross section perpendicular to the base through the midpoints of the 8-inch sides forms a rectangle, but since the heights have not been provided for the prism, it cannot be defined specifically.
If a cross section is perpendicular to the base but no other information is provided, the dimensions of the cross section cannot be fully determined.
However, based on the options given, we can discern the following:
Option 2 is correct because a cross section parallel to the base would be identical to the base, measuring 15 inches by 8 inches.
Option 4 is correct since it specifies a rectangle measuring 6 inches by 15 inches assuming the height of the prism is 6 inches.
Options 1, 3, 5, and 6 cannot be determined to be correct without additional information regarding the height or manner of the cuts. Specifically, option 6 describes a cross section not parallel to the base but does not provide enough information about the shape or dimensions beyond the length being greater than 15 inches.
the point A(7,1) is reflected over the point (4,0) and its image is point B. What are the coordinates of point B?
Answer: The coordinates of point be are (1,-1)
Step-by-step explanation:
The reflected point will be equidistant from the point over which it is reflected as the original point and in the same line as the original point and the reflected point.
Find the difference between the x and y values of the given points and add that value (distance) to the reflection point.
x-values: 4-7 = -3 y-values: 0-1 = -1
Add to reflection point x: 4-3 = 1 y: 0 -1 = -1
Final answer:
To reflect point A(7, 1) over point (4, 0) to find point B, calculate the horizontal and vertical distances from A to (4, 0) and subtract these distances from (4, 0) to get B's coordinates, resulting in point B being at (1, -1).
Explanation:
To find the coordinates of point B after reflecting point A(7, 1) over point (4, 0), we need to apply the concept of reflections in the Cartesian plane. When a point is reflected over another, the line joining the original point and the point of reflection is bisected perpendicularly by the point of reflection. This means that point B will have the same distance from (4, 0) as point A, but in the opposite direction.
Here's the step-by-step method to find the coordinates of B:
Calculate the horizontal and vertical distances from A to the mirror point (4, 0): Horizontal distance = 7 - 4 = 3, Vertical distance = 1 - 0 = 1.
Subtract these distances from the mirror point to find B's coordinates: B's x-coordinate = 4 - 3 = 1, B's y-coordinate = 0 - 1 = -1.
So, the coordinates of point B after the reflection are (1, -1).
A bag contains 32 red blocks, 47 green blocks, 21 yellow blocks, and 25 purple blocks. You pick one block from the bag at random. Find the indicated theoretical probability.
P(green or purple)
Answer:
P(green or purple) = 0.576
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
32 + 47 + 21 + 25 = 125 blocks.
Of those, 47 + 25 = 72 are green of purple
P(green or purple) = 72/125 = 0.576