Write three numbers that are greater than 12,000 but less than 13,000

Hey there!!

Equation given :

2x² - 4x  = 0

Taking the common terms

2x ( x - 2 ) = 0

Divide by 2x on both sides

x - 2 = 0

Adding 2 on both sides ...

x = 2

And another answer would be zero as the whole equation is zero,

Hence the answer : ( 0 , 2 )

Hope it helps@+!!

The value x for equation 2x² - 4x = 0 is 2.

Given equation:

2x² - 4x = 0

Add 4x on both side,

2x² = 4x

Divide x on both side

2x = 4

Divide 2 on both side,

x = 2.

Therefore, the value x for equation 2x² - 4x = 0 is 2.

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The formula is

T=4B+10C

To do a two-column proof, you must know the definitions of the terms that are being used. Also, you must know the postulates and theorems you have learned so far. You look at the given information, and using the definitions, postulates, and theorems, you reason in your mind how to go from the given to the conclusion, step by step. You write each step and the accompanying reason that allows you to conclude each step.

up (+)        123             187

down (-)            -154            -175

(123 + 187) - (154 + 175)

=    310        -      329

=                 -19

Answer: 19 feet below ground

A,C,D those were the answers i put and they were correct.

Answer:

A. h(m) = 27 – m3

C. f(a) = a3 – 4a2 + a + 6

D. f(x) = 2x3 – 5x2 – 9

Step-by-step explanation:

did review on edg2020

Every time you divide something by something else, you already have a fraction. A fraction is simply a different way to visualize a division. So, the following writings express the same concept:

[tex] 72\div 24 = \dfrac{72}{24} [/tex]

There's no conceptual difference between the two expressions, so you're not actuall "turning" 72 divided by 24 "into" a fraction, you're just writing it in another way.

Replace [tex]a_{n}[/tex] with 27, solve for [tex]a_{n-1}[/tex], and see if the result is a whole number.

27 = 2a   ⇒ [tex]\frac{27}{2}[/tex] = a not a whole number  NO

27 = 2a + 1  ⇒  26 = 2a  ⇒  13 = a  13 is a whole number  YES

27 = 3a  ⇒  9 = a   9 is a whole number  YES

27 = 3a + 6   ⇒   21 = 3a   ⇒   7 = a   7 is a whole number  YES

27 = 3a + 1   ⇒   26 = 3a   ⇒   [tex]\frac{26}{3}[/tex] = a not a whole number  NO

Answer: B, C, D

[tex]n!=1\cdot2\cdot3\cdot...\cdot n\\\\6!=1\cdot2\cdot3\cdot4\cdot5\cdot6=720\\\\Answer:\ \boxed{D.\ 720}[/tex]

Answer:  D.  

720

Step-by-step explanation:

We know that the value of  n factorial or n! is given by :-

[tex]n!=n\times(n-1)\times(n-2)\times(n-3)\times...........................\times1[/tex]

We are given to find the value of 6! (or 6 factorial )

Using the above formula , the value of 6! is given by :-

[tex]6!=6\times(6-1)\times(6-2)\times(6-3)\times\times(6-4)\times(6-5)\\\\\Rightarrow\ 6!=6\times5\times4\times3\times2\times1\\\\\Rightarrow\ 6!=720[/tex]

Therefore , the value of 6! = 720

Answer:

They will need 197 canoes.

Step-by-step explanation:

The first step is to find the ''3-people canoes'' that they filled.

Given that 273 people filled a certain number ''a'' of canoes that each hold 3 people, we know that is we multiply the number of canoes ''a'' by the number of people that can each canoe hold, we will obtain the number of people who

will take the canoe trip in the ''3-people canoes''. We write :

[tex]3a=273[/tex] ⇒

[tex]a=\frac{273}{3}=91[/tex]

We find that [tex]a=91[/tex] canoes. This means that 91 ''3-people canoes'' were filled each one with 3 people in order to hold 273 people in total.

The second step is to find the remaining people that won't take the ''3-people canoes''. We do this by subtracting 273 people to the total 485 people.

[tex]485-273=212[/tex]

We know that 212 people will travel in the ''2-people canoes''. Using a similar reasoning and defining as ''b'' to the total number of ''2-people canoes'' we write :

[tex]2b=212\\b=\frac{212}{2}=106\\ b=106[/tex]

We find that [tex]b=106[/tex] canoes is the total number of ''2-people canoes'' that we need If we want them to be filled up with 212 people.

The total number of canoes that the group will need is the sum of ''3-people canoes'' and ''2-people canoes'' :

[tex]Total=a+b=91+106=197[/tex]

The group of 485 people will need 197 canoes.

Answer:

A linear graph will be plotted to show the relation between ages of Mike and Dan.

Step-by-step explanation:

As the age of Mike increase, the age of Dan will also increase. There is a relation of direct proportionality and a linear graph line will be plotted. When x=3, y=0, therefore the line will be at a distance of 3 x-intercept from origin.

ANSWER=  +/- 5i sqrt2

sqrt=square root sign to solve you subtract 50 so x^2=-50 then get the square root on both sides and you're left with x=5isqrt 2 the i comes from the negative sign inside the square root

 +/- 5i sqrt2  is the solution

Answer:

the answer is point N

Step-by-step explanation:

i dont have a graph to explain

The midpoint of a line segment is calculated using the formula Midpoint = ((x1 + x2)/2 , (y1 + y2)/2), which finds the average of the x-coordinates and y-coordinates of the two points. Unfortunately, without specific points, we can't provide a concrete midpoint.

Unfortunately, your question is slightly unclear as we need more detail to accurately determine the midpoint of the segment. Generally, if you want to find the midpoint of a segment, you need two defined points. Knowing these two points, you can calculate the midpoint using the formula: Midpoint = ((x1 + x2)/2 , (y1 + y2)/2). This formula calculates the average of the x-coordinates and y-coordinates of the two points, which gives you the coordinates of the midpoint.

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Final answer:

The car travels approximately 210 kilometers in 2 hours and 20 minutes by multiplying its speed of 90km/h by the time duration converted to hours (2.333 hours).

Explanation:

The student's question involves calculating the distance a car travels at a constant speed over a given period of time. In this case, the car drives at a speed of 90km/h for 2 hours and 20 mins. To find the distance, you can use the formula: distance = speed × time. First, convert 2 hours and 20 mins into hours, which is 2 hours + 20/60 hours = 2.333 hours.

Next, multiply the speed by the time to get the distance:

Distance = 90km/h × 2.333 hours = 209.97 km

So, the car travels approximately 210 kilometers in 2 hours and 20 minutes.

First take not of the total sales and the cost of each ticket.

1,824 and 16

Now setup the equation

16x=1824

To solve this divide 1824 by 16 getting

X=144

x is the total tickets sold

Each ticket (t) costs $16. The band made a total of $1,824 from ticket sales, meaning that 16t=1,824, because the total amount of 16 dollar tickets sold is equal to the total made from ticket sales.

The equation is:

16t=1,824.

You are trying to find the amount of tickets sold by solving the equation.

t stands for the total amount of tickets sold.

Solving the equation:

16t=1,824

Divide both sides by 16.

t=114

114 tickets were sold. 114*16=1,824. This means that when 114 $16 tickets were sold, the band did make $1,824, which shows that 114 is the correct answer.

I hope this helps :)

Answer:

[tex]a_{26}=-20[/tex]

Step-by-step explanation:

The formula of a nth term of an arithmetic sequence:

[tex]a_n=a_1+(n-1)d[/tex]

We have:

[tex]a_1=30,\ d=-2,\ n=26[/tex]

Substitute:

[tex]a_{26}=30+(26-1)(-2)=30+(25)(-2)=30-50=-20[/tex]

There are two ways you can approach this:

1) Factor [tex]\frac{5(x-1)(x+3)}{x+5}[/tex] this equals to [tex]\frac{5x^2+10x-15}{x+5}[/tex]

2) or divide which equals to 5x+35+[tex]\frac{160}{x+5}[/tex]

[tex]f(x)=\dfrac{5x+7}{7x-5},\ g(x)=\dfrac{8x}{7x-5}\\\\(f+g)(x)=f(x)+g(x)=\dfrac{5x+7}{7x-5}+\dfrac{8x}{7x-5}=\dfrac{5x+7+8x}{7x-5}=\dfrac{13x+7}{7x-5}\\\\(f-g)(x)=f(x)-g(x)=\dfrac{5x+7}{7x-5}-\dfrac{8x}{7x-5}=\dfrac{5x+7-8x}{7x-5}=\dfrac{-3x+7}{7x-5}\\\\(f\cdot g)(x)=f(x)\cdot g(x)=\dfrac{5x+7}{7x-5}\cdot\dfrac{8x}{7x-5}=\dfrac{(5x+7)(8x)}{(7x-5)(7x-5)}\\\\=\dfrac{40x^2+56x}{(7x)(7x)+(7x)(-5)+(-5)(7x)+(-5)(-5)}=\dfrac{40x^2+56x}{49x^2-70x+25}[/tex]

[tex](f+g)(x)=4x^2+\frac{3}{2}x-7[/tex]

Answer:

[tex]h(x)=4x^2+\dfrac{3}{2}x-7[/tex]

Step-by-step explanation:

Given:  

[tex]f(x)=\dfrac{x}{2}-3[/tex]

[tex]g(x)=4x^2+x-4[/tex]

To find: (f+g)(x)

It is a composite function. Sum of f and g function.

[tex]h(x)=f(x)+g(x)[/tex]

[tex]h(x)=\dfrac{x}{2}-3+4x^2+x-4[/tex]

Combine the like term

[tex]h(x)=4x^2+\dfrac{3}{2}x-7[/tex]

Hence, The sum of f(x) and g(x) would be [tex]h(x)=4x^2+\dfrac{3}{2}x-7[/tex]

Answer:

your answers C

Step-by-step explanation:

The factored form of the expression [tex]27x^3+y^6[/tex] is [tex](3x+y^2)(9x2-3xy^2+y^4)[/tex]. The correct answer of the factored expression is option A

Given the expression;

[tex]27x^3+y^6[/tex]

This can be expressed as the sum of cubes

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)[/tex]

The given expression can also be written as the sum of cubes as shown:

[tex]27x^3+y^6 = (3x)^3+(y^2)^3[/tex]

We can see that:

a = 3x

b = y²

Substituting the given parameters into the formula above;

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)\\(3x)^3+(y^2)^3=(3x+y^2)((3x)^2-3xy^2+(y^2)^2)\\(3x)^3+(y^2)^3=(3x+y^2)(9x2-3xy^2+y^4)\\[/tex]

Hence the factored form of the expression is [tex](3x+y^2)(9x2-3xy^2+y^4)[/tex]

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2. Linear Pair Postulate

4. 60° + m∠ACB = 180°

5. m∠ACB = 120°

6. definition of obtuse angle

Answer:

B- False

Step-by-step explanation:

that is very false bc the units mean alot

Answer:

D. It is $13 less than the gross pay.

Step-by-step explanation:

To find the net pay, you have to look at the table h

We are given that table.

Step 1: Biweekly gross salary is $840 and the number of claimed is 5.

Step 2: Look for claimed number to the corresponding wage $840. It is 13, which is rounded by blue circle in the given table.

Thank you.

Answer:

D. It is $13 less than the gross pay.

Step-by-step explanation:

To find the net pay, you have to look at the table h

We are given that table.

Step 1: Biweekly gross salary is $840 and the number of claimed is 5.

Step 2: Look for claimed number to the corresponding wage $840. It is 13, which is rounded by blue circle in the given table.

Thank you.

i copied the other dued lol

The average total cost of manufacturing scented candles is given by the formula A(b) = C(b)/b = (250 + 3b)/b, where b is the number of candles manufactured.

The concept of average total cost is key in the calculation. Given the function for total cost of the candles, C(b) = 250 + 3b, the average cost, A, can be calculated by dividing the total cost by the number of candles, b. Therefore, the function representing the average cost, A, in terms of b is given by A(b) = C(b)/b = (250 + 3b)/b. It's important to note that this function also signifies the 'economies of scale', stating as output number increases, the average cost falls.

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B and D are both wrong. B has +4 outside the brackets. It is - 4

D is wrong because there is no 4 of any kind outside the brackets.

A is incorrectly represented inside the brackets as 16. That's not right

That only leaves  C. <<<< Answer

Graphs

Notice that the red parabola and the green one are the same thing.

Red: y = -4x^2 - 16x - 14

Green: y = -4(x + 2)^2 + 2

Answer:

He sees 16 cats that day

Step-by-step explanation:

If the veterinarian sees 5 dogs a day then he also sees 2 cats.

If he sees 40 dogs a day then,

⇒[tex]\frac{2}{5} *40[/tex]

=[tex]16[/tex] Cats

He sees 16 cats that day.

The correct option is C.

Approximately 29 dogs were seen by the vet in one day.

To solve this problem, we first need to find the fraction of dogs among the total animals seen by the vet.

Given that the ratio of cats to dogs is 2 to 5, the total parts in this ratio is 2 + 5 = 7.

Now, to find the fraction representing dogs, we divide the number of parts representing dogs (5) by the total parts (7). This gives us 5/7.

Next, to find out how many of the 40 animals were dogs, we multiply the total number of animals seen (40) by the fraction representing dogs:

40 animals × (5/7) = (40 × 5) / 7 = 200/7 ≈ 28.57

Since we're looking for an approximation, we round this to the nearest whole number, which is 29.

So, approximately 29 of the animals seen were dogs, which corresponds to option C.

The complete question is here:

The ratio of cats to dogs seen by a vet in a day is about 2 to 5. If a vet saw 40 animals in one day, about how many were dogs?

A. 5

B. 12

C. 29

D. 40

answer is TT->T or a

Answer:

A)

Step-by-step explanation: