You are going to movies friday night (not a matinee). which of the theaters will cost the least, if you intend to have soda and popcorn? theater a theater b theater c adults $6.25 $7.25 $5.25 children $3.50 $3.75 $4.25 soda $2.00 $2.00 $2.50 popcorn $2.50 $2.00 $2.50

Answer:

Just took the K12 quiz, and like killdrone said in the comments, the correct answer is 9.8 m

Step-by-step explanation:

The height at which both basketballs are at the same height is approximately 16.3 meters.

To find the moment when the basketballs are at the same height, we need to find the common height value for both functions.

Setting the functions equal to each other, we get: -4.9x^2 + 12x + 2.5 = -4.9x^2 + 14x

Simplifying the equation, we get 2x = 2.5, which means x = 1.25.

Substituting this value back into the original function for Eli, we get f(1.25) = -4.9(1.25)^2 + 12(1.25) + 2.5 = 16.325

Therefore, the height at which both basketballs are at the same height is approximately 16.3 meters.

To find the revenue per minute of the movie, divide the total revenue ( [tex]\$1.1 \times 10^9[/tex]) by the length of the movie ( [tex]9.1 * 10^1[/tex]). The trick is to divide the numerical portions and the power of ten portions separately. The answer is approximately [tex]\$1.20879 \times 10^7[/tex] per minute.

The subject of this question is mathematics and it involves a concept called division in scientific notation. To find the revenue per minute for this movie, we'll divide the total earnings ($1.1 * 109) by the length of the movie in minutes (9.1 * 101).

Step 1: Place the two values with scientific notation over each other, akin to a typical division problem. This means $1.1 * 109 / 9.1 * 101.

Step 2: Divide the two numerical portions separately from the power of ten portions. This is dividing 1.1 by 9.1 and 109 by 101.

Step 3: The former (from step 2) gives you approximately 0.120879 and the latter simplifies to 108 (because when you divide with the same base, you subtract the exponents).

So the earnings per minute of this movie were approximately $0.120879 * 108, or $1.20879 * 107.

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To be the least expensive babysitter, Karel should charge less than $2.00. If she wants her hourly rate to be higher than half the babysitters but lower than the other half, she could charge slightly less than $2.75. Beyond these rates, Karel should consider factors like her own experience, the specific tasks she'll perform, and the hours she'll work.

To determine how much Karel should charge for her babysitting services, we need to consider the other babysitting rates and find the midpoint. The other students charge the following amounts: Stephanie-$2.75, Jessica-$2.00, Michael-$3.00, Raoul -$2.50, Rolanda-$2.75, Harry -$2.25, Samuel-$2.25, Anita-$2.75.

To be the least expensive, Karel should charge less than the lowest rate, which is $2.00 charged by Jessica. So, Karel could charge $1.75, for example.

Now, suppose Karel wants to have an hourly rate higher than half the babysitters but lower than the other half. We need to organize the rates in ascending order, and then find the median value. If we do this, we find that the middle value (the median) is $2.75. Therefore, Karel could charge slightly less than this, for example, $2.70.

Lastly, Karel should also consider other factors when setting her rates. These might include her experience and skills as a babysitter, the average babysitting rates in her neighborhood or city, the specific tasks she'll be expected to perform, and the hours she'll be working.

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divide number of apples by how many fit I a basket:

285 / 37 = 7.70

 so he will need 8 baskets

Answer:

B. 2 points

Step-by-step explanation:

1 point is a dot in space, 2 can make a line

Answer:

54 sq. ft.

Step-by-step explanation:

LA=ph or in other words Lateral Area= base perimeter * height

The perimeter of the base is 9 because 3+3+3=9.

The height is 6. So 6 * 9 = 54

Answer:  The answer is below i am in k12 just took the test

Circle Q is a dilation of circle P with a scale factor of 7. "

Circle Q is a translation of circle P, 6 units up.

Step-by-step explanation:

The dimensions of a rectangle with an area of 221 cm² and a perimeter of 60 cm are found by solving a system of equations derived from the definitions of area and perimeter. The dimensions are 13 cm by 17 cm, or equivalently, 17 cm by 13 cm.

To find the dimensions of a rectangle with an area of 221 cm2 and a perimeter of 60 cm, we will let the length be x and the width be y. The area of a rectangle is found by multiplying the length and width, so we have the equation x * y = 221. The perimeter is twice the sum of the length and width, so we have 2x + 2y = 60, which simplifies to x + y = 30.

To solve these equations, divide the perimeter equation by 2 to find y = 30 - x. Substituting this into the area equation gives x(30 - x) = 221. Expanding this and bringing all terms to one side provides a quadratic equation: x2 - 30x + 221 = 0. Solving this quadratic equation by factoring or using the quadratic formula gives the dimensions of the rectangle.

The solutions to the quadratic equation are x = 13 and x = 17. Since x and y are interchangeable as length and width, the two sets of possible dimensions for the rectangle are 13 cm by 17 cm and 17 cm by 13 cm.

The dimensions of the rectangle are [tex]17\ cm , 13\ cm[/tex]

To find the dimensions [tex]\( l \)[/tex] (length) and [tex]\( w \)[/tex] (width) of the rectangle given its area and perimeter, we start with the following equations:

1. Area equation:

[tex]\[l \times w = 221\][/tex]

2. Perimeter equation:

[tex]\[ 2l + 2w = 60 \][/tex]

Step-by-Step Solution:

The dimensions of the rectangle are [tex]{{17, 13} \) cm.[/tex]

From the perimeter equation, divide everything by [tex]2[/tex] to simplify:

[tex]\[l + w = 30\][/tex]

Now we have a system of equations:

[tex]\[\begincases}l \times w = 221 \\l + w = 30\end{cases}\][/tex]

Let's solve this system using substitution or elimination:

From [tex]\( l + w = 30 \)[/tex], we can express [tex]\( w \)[/tex] in terms of [tex]\( l \)[/tex]

[tex]\[w = 30 - l\][/tex]

Substitute [tex]\( w = 30 - l \)[/tex] into the area equation:

[tex]\[l \times (30 - l) = 221\][/tex]

[tex]\[30l - l^2 = 221\][/tex]

Rearrange this equation to form a quadratic equation:

[tex]\[l^2 - 30l + 221 = 0\][/tex]

Now, solve this quadratic equation using the quadratic formula [tex]\( l = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = -30 \), and \( c = 221 \)[/tex]

[tex]\[l = \frac{-(-30) \pm \sqrt{(-30)^2 - 4 \times 1 \times 221}}{2 \times 1}\][/tex]

[tex]\[l = \frac{30 \pm \sqrt{900 - 884}}{2}\][/tex]

[tex]\[l = \frac{30 \pm \sqrt{16}}{2}\][/tex]

[tex]\[l = \frac{30 \pm 4}{2}\][/tex]

Calculate both possible values of [tex]\( l \)[/tex]

[tex]\[l = \frac{30 + 4}{2} = 17 \quad \text{or} \quad l = \frac{30 - 4}{2} = 13\][/tex]

Corresponding values of \( w \)

[tex]If\ \( l = 17 \), then \( w = 30 - 17 = 13 \)[/tex]

[tex]If\ \( l = 13 \), then \( w = 30 - 13 = 17 \)[/tex]

Therefore, the dimensions of the rectangle are [tex]\( 17 \) cm[/tex] by [tex]\( 13 \) cm.[/tex]

Verification:

[tex]Area: \( 17 \times 13 = 221 \) cm\(^2\)[/tex]

[tex]Perimeter: \( 2 \times (17 + 13) = 2 \times 30 = 60 \) cm[/tex]

Both conditions match the given area and perimeter, confirming that the dimensions are correct.

When both the base and height of a shape are multiplied by x, the area increases by a factor of x^2. Therefore, the area of Sail B is x^2 times greater than that of Sail A.

The area of a shape with a base and height is commonly found using the formula Area = 1/2 * Base * Height. If the base and the height of Sail B are x times greater than those of Sail A, then both the base and height of Sail B are multiplied by x, resulting in an area that is x^2 (x squared) times greater. This is because, in the formula, base and height are multiplied together, so if both are multiplied by x, the overall multiplication is by x*x, or x^2. Therefore, the area of Sail B is x^2 times greater than the area of Sail A.

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L=2+4W
W=L/2
f=3d

hope this is the right question????

To evaluate (f - g)(0), find f(0) and g(0) for the functions f(x) = x + 3 and g(x) = x^2 - 2, and then subtract the latter from the former. For f(0) we have 3, and for g(0) we have -2. Subtracting, we get (f - g)(0) = 5.

To evaluate the expression (f - g)(0), it means we need to find the value of the function f at x = 0, subtract the value of the function g at x = 0, and combine them. Given the functions f(x) = x + 3 and g(x) = x^2 − 2, let's calculate their values at x = 0:

Now, let's subtract g(0) from f(0):

(f - g)(0) = f(0) - g(0) = 3 - (-2) = 3 + 2 = 5

Therefore, the value of (f - g)(0) is 5.

Answer:

[tex]\left \{ {{n+q=28} \atop {n(0.05)+q(0.25)=4}} \right.[/tex]

And the pair [tex](n,q)=(15,13)[/tex] is the solution.

Step-by-step explanation:

We know that Yolanda paid for her movie ticket using 28 coins. She only paid with nickels and quarters.

We also know that the ticket cost $4.

We need to form a linear equation system that solves this problem.

We have the following variables :

n : number of nickels

q : number of quarters

We know that she used 28 coins ⇒ the number of nickels plus the number of quarters must be equal to 28.

We have our first equation :

[tex]n+q=28[/tex] (I)

For the second equation we need to use the ticket price information.

We know that the ticket cost $4 and she only paid with nickels and quarters.

Therefore we can write the following equation that relates the variable ''n'' and the variable ''q'' :

[tex]n(0.05)+q(0.25)=4[/tex] (II)

This equation represents that the number of nickels ''n'' per its value plus the number of quarters ''q'' per its value is equal to $4 that it is the value of the movie ticket.

With (I) and (II) we form the linear equation system :

[tex]\left \{ {{n+q=28} \atop {n(0.05)+q(0.25)=4}} \right.[/tex]

This linear equation system can be used to find the value of ''n'' and ''q''.

For example, in equation (I)

[tex]n+q=28[/tex]

we can solve it in terms of ''n'' :

[tex]n=28-q[/tex] (III)

If we use (III) in (II) :

[tex](28-q)(0.05)+q(0.25)=4[/tex]

[tex]1.4-(0.05)q+(0.25)q=4[/tex]

[tex]q(0.2)=2.6[/tex]

[tex]q=\frac{2.6}{0.2}=13[/tex]

[tex]q=13[/tex]

Now replacing this value of q in (III) :

[tex]n=28-13=15[/tex]

[tex]n=15[/tex]

We find that Yoland used 15 nickels and 13 quarters to paid the movie ticket .

Answer:

Step-by-step explanation:

The GCF is found by listing the factors of all the numbers and picking the largest one that occurs in each.  The factors of your numbers are as follows:

32:  1, 2, 4, 8, 16, 32

48:  1, 2, 3, 4, 6, 8, 12, 16, 24, 48

80:  1, 2, 4, 5, 8, 10, 16, 20, 40, 80

Looking at those factors you can pick out anything you'd like:  all the common factors, the greatest common factors, whatever you need.

Final answer:

The number 16 is a common factor of 32, 48, and 80, as it is the only number among the options given that divides evenly into all three numbers.

Explanation:

To find a common factor of 32, 48, and 80, we need to identify a number that divides evenly into all three numbers. A systematic way to do this is to list out the factors of each number and see which ones they have in common.

Factors of 32: 1, 2, 4, 8, 16, 32

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Factors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

From these lists, we see that the numbers 1, 2, 4, 8, and 16 are common factors of all three numbers. However, among the options provided (3, 9, 10, 16), 16 is the only number that appears in all lists and is therefore a common factor of 32, 48, and 80.