You deposit $400 each month into an account earning 5% interest compounded monthly. a. How much will you have in the account in 30 years? b. How much total money will you put into the account? c. How much total interest will you earn?

Answers

Answer 1

a) After 30 years, the amount in the account will be approximately $499,355.18.

b) The total money deposited over 30 years will be $144,000.

c) The total interest earned over 30 years will be approximately $355355.18.

We have,

Given:

Monthly deposit: $400

Interest rate: 5% (expressed as a decimal, 0.05)

Time: 30 years (in months, 30 * 12 = 360 months)

a.

To calculate the amount in the account after 30 years, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = Amount in the account

P = Initial deposit (first deposit)

r = Annual interest rate

n = Number of times interest is compounded per year

t = Time in years

In this case:

P = $400 x 360 = $144000

r = 0.05

n = 12 (compounded monthly)

t = 30

Substituting the values into the formula:

A = 144000(1 + 0.05/12)^(12 * 30)

A ≈ $499,355.18

b.

The total money deposited can be calculated by multiplying the monthly deposit by the number of months:

Total Money Deposited = Monthly deposit * Number of months

Total Money Deposited = $400 * 360

Total Money Deposited = $144,000

c.

The total interest earned can be calculated by subtracting the total money deposited from the amount in the account:

Total Interest Earned = Amount in the account - Total Money Deposited

Total Interest Earned = $499,355.18 - $144,000

Total Interest Earned ≈ $355355.18

Therefore,

After 30 years, the amount in the account will be approximately $499,355.18.

The total money deposited over 30 years will be $144,000.

The total interest earned over 30 years will be approximately $355355.18.

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Answer 2
Final answer:

To find the future value of the account after 30 years, use the compound interest formula. Multiply the monthly deposit by the number of months to find the total money put into the account. The total interest earned is found by subtracting the total money put into the account from the future value.

Explanation:

To calculate the future value of the account, we can use the formula for compound interest: A = P(1 + r/n)^(nt), where A is the future value, P is the principal (initial deposit), r is the interest rate in decimal form, n is the number of times interest is compounded per year, and t is the number of years.

a. Plugging in the values, we have [tex]A = 400(1 + 0.05/12)^(12*30)[/tex]. Using a calculator, the future value after 30 years will be approximately $1000.40.

b. To find the total money put into the account, we multiply the monthly deposit by the number of months. In this case, it will be $[tex]400 * 12 * 30 = $144,000.[/tex]

c. The total interest earned can be found by subtracting the total money put into the account from the future value. In this case, it will be $[tex]1000.40 - $144,000 = -$143,999.60.[/tex]

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Related Questions

Write equations for the horizontal and vertical lines passing through the point (-8,6)

Answers

Answer:

So since your point is (-8,6), then your vertical line is x=-8 and horizontal line is y=6.

Step-by-step explanation:

Horizontal lines are in the form y=b.

Vertical lines are in the form x=a.

a and b are just constant numbers.

So anyways, in general:

The horizontal line going through (a,b) is y=b.

The vertical line going through (a,b) is x=a.

So since your point is (-8,6), then your vertical line is x=-8 and horizontal line is y=6.

the answer is

x=-8

y=6

good luck

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note: you don’t need to use the ratio test here because we know the radius of convergence of the series P∞ n=0 x n .) (b) Use part (a) to find a power series for f(x) = x ln(1 − x). (c) By putting x = 1 2 in your result from part (a), express ln 2 as the sum of an infinite series

Answers

a. Recall that

[tex]\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C[/tex]

For [tex]|x|<1[/tex], we have

[tex]\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n[/tex]

By integrating both sides, we get

[tex]\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}[/tex]

If [tex]x=0[/tex], then

[tex]\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0[/tex]

so that

[tex]\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}[/tex]

We can shift the index to simplify the sum slightly.

[tex]\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n[/tex]

b. The power series for [tex]x\ln(1-x)[/tex] can be obtained simply by multiplying both sides of the series above by [tex]x[/tex].

[tex]\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n[/tex]

c. We have

[tex]\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)[/tex]

[tex]\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}[/tex]

The power series of f(x) = ln(1 - x) is  [tex]\rm -\sum^{\infty}_{n=1}\dfrac{x^{n} }{n}[/tex], the power series of xln(1 - x) is  [tex]\rm -\sum^{\infty}_{n=1}\dfrac{x^{n+1} }{n}[/tex] and the value of ln(2) is [tex]\rm \sum^{\infty}_{n=0}\dfrac{1}{n2^n}[/tex].

Given :

f(x) = ln (1−x)

a) The integration of 1/(1 - x) is given by:

[tex]\rm \int \dfrac{1}{1-x}dx=-ln|1-x| + C[/tex]

When |x| >1 :

[tex]\dfrac{1}{1-x} = \sum^{\infty}_{n=0} x^n[/tex]

Now, integrate on both sides in the above equation.

[tex]\rm -ln(1-x) = C+\sum^{\infty}_{n=0}\dfrac{x^{n+1} }{n+1}[/tex]   --- (1)

Now, at (x = 0) the above expression becomes:

[tex]\rm -ln(1-0) = C+\sum^{\infty}_{n=0}\dfrac{0^{n+1} }{n+1}[/tex]

By simplifying the above expression in order to get the value of C.

C = 0

Now, substitute the value of C in expression (1).

[tex]\rm ln(1-x) =-\sum^{\infty}_{n=0}\dfrac{x^{n+1} }{n+1}[/tex]

Now, by shifting the index the above expression becomes:

[tex]\rm ln(1-x) =-\sum^{\infty}_{n=1}\dfrac{x^{n} }{n}[/tex]

b) Now, multiply by 'x' in the above expression in order to get the power series of (x ln(1 - x)).

[tex]\rm xln(1-x) =-\sum^{\infty}_{n=1}\dfrac{x^{n+1} }{n}[/tex]

c) Now, substitute the value x = 1/2 in the expression (1).

[tex]\rm ln2 = \sum^{\infty}_{n=0}\dfrac{1}{n2^n}[/tex]

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The sum of four consecutive natural numbers is 598. Identify any variables and write an equation to find the numbers. What are they?

Answers

Answer:

Equation is 4x + 6 = 598, where x represents smaller number.

Numbers are 148, 152, 156 and 160

Step-by-step explanation:

Let x be the smaller natural number,

So, the other consecutive natural numbers are x+1, x+2, x+3,

According to the question,

Sum of x, x+1, x+2 and x+3 is 598,

⇒ x + x + 1 + x + 2 + x + 3 = 598

⇒ 4x + 6 = 598

Which are the required equation,

Subtract 6 on both sides,

4x = 592

Divide both sides by 4,

x = 148

Hence, the numbers are 148, 152, 156 and 160

Final answer:

The equation to find four consecutive natural numbers with a sum of 598 is 4x + 6 = 598. Solving for x gives the first number as 148, which leads to the sequence: 148, 149, 150, and 151.

Explanation:

The student is tasked with finding four consecutive natural numbers whose sum is 598.

To solve this problem, we introduce a variable to represent the first number in the sequence, and then express the following three numbers in terms of this variable.

Let's denote the first number as x. Then the next three numbers will be x+1, x+2, and x+3, respectively. Our equation to find the numbers is:

x + (x+1) + (x+2) + (x+3) = 598

Combining like terms, we get:

4x + 6 = 598

We then solve for x:

4x = 598 - 6

4x = 592

x = 592 / 4

x = 148

So the four consecutive numbers are 148, 149, 150, and 151.

The cost (in hundreds of dollars) of tuition at the community college is given by T = 1.25c + 3, where c is the number of credits the student has registered for. If a student is planning to take out a loan to cover the cost of 13 credits, use the model to determine how much money he should borrow.

Answers

Answer:

The amount he should borrow is 19.25 hundreds dollars.

Step-by-step explanation:

Given : The cost (in hundreds of dollars) of tuition at the community college is given by [tex]T = 1.25c + 3[/tex], where c is the number of credits the student has registered for. If a student is planning to take out a loan to cover the cost of 13 credits.

To find : Use the model to determine how much money he should borrow?

Solution :

The model is given by [tex]T = 1.25c + 3[/tex]

Where,

c is the number of credits the student has registered.

T is the cost of tuition at the community college.

If a student is planning to take out a loan to cover the cost of 13 credits.

The amount he should borrow will get by putting the value of c in the model,

[tex]T = 1.25c + 3[/tex]

[tex]T = 1.25(13) + 3[/tex]

[tex]T = 16.25 + 3[/tex]

[tex]T =19.25[/tex]

Therefore, The amount he should borrow is 19.25 hundreds dollars.

Determine the value of g(4), g(3 / 2), g (2c) and g(c+3) then simplify as much as possible.

g(r) = 2 [tex]\pi[/tex] r h

Answers

Answer:

[tex]g(4) = 8 \pi h\\\\g(\frac{3}{2}) = 3 \pi h\\\\ g(2c) = 4 \pi ch\\\\g(c+3) = 2 \pi hc+6\pi h[/tex]

Step-by-step explanation:

You need to substitute [tex]r=4[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(4) = 2 \pi(4)h\\\\g(4) = 8 \pi h[/tex]

Substitute [tex]r=\frac{3}{2}[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(\frac{3}{2}) = 2 \pi(\frac{3}{2})h\\\\g(\frac{3}{2}) = 3 \pi h[/tex]

Substitute [tex]r=2c[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(2c) = 2 \pi(2c))h\\\\g(2c) = 4 \pi ch[/tex]

Substitute [tex]r=c+3[/tex] into [tex]g(r) = 2 \pi r h[/tex]. Then:

[tex]g(c+3) = 2 \pi (c+3)h\\\\g(c+3) = 2 \pi hc+6\pi h[/tex]

For this case we have the following function:

[tex]g (r) = 2 \pi * r * h[/tex]

We must evaluate the function for different values:

[tex]g (4) = 2 \pi * (4) * h = 8 \pi*h\\g (\frac {3} {2}) = 2 \pi * (\frac {3} {2}) * h = 3 \pi*h\\g (2c) = 2 \pi * (2c) * h = 4 \pi * c * h\\g (c + 3) = 2 \pi * (c + 3) * h = 2 \pi * c * h + 6 \pi * h[/tex]

Answer:

[tex]g (4) = 8 \pi*h\\g (\frac {3} {2}) =3 \pi*h\\g (2c) = 4 \pi * c * h\\g (c + 3) = 2 \pi * c * h + 6 \pi * h[/tex]

An item is discounted 20%; the sale price after the discount is $60. What was the original price? Round your answer to the nearest two decimal digits and express your answer without the $ sign (e.g., 1234.25, not $1234.25)

Answers

Answer:

75.

Step-by-step explanation:

Let x be the original price. 20% = 0.2. The price with the discount is 60, that is

x-x*0.2 = 60

x(1-0.2) = 60 using common factor,

x (0.8) = 60

x = 60/0.8

x = 75.

So, the original price is $75.

The original price of an item discounted 20% with a sale price after the discount of $60 is $75.

What is discounted price?

A discounted price is the marked-down price of an item.

The discounted price represents the selling price after reducing it with the discount.

Data and Calculations:

Discount rate = 20%

Discounted price = $60

Original price = $75 ($60/1-20%)

Thus, the original price of an item discounted 20% with a sale price after the discount of $60 is $75.

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Find the slope of the line passing through the points (-7,-7) and (-3, 6)

Answers

Answer:

13/4

Step-by-step explanation:

The slope of the line between 2 points is found by

m = (y2-y1)/(x2-x1)

   = (6--7)/(-3--7)

   = (6+7)/(-3+7)

   = 13/4

Answer:

The slope is 13/4.

Step-by-step explanation:

Slope formula:

[tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\displaystyle \frac{6-(-7)}{(-3)-(-7)}=\frac{13}{4}[/tex]

[tex]\huge\boxed{\frac{13}{4}}[/tex], which is our answer.

A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean score on the exam was 82 and the mean of the 9 readable scores is 84​, what is the value of the unreadable​ score?

Answers

Answer:

64

Step-by-step explanation:

[tex]mean=\frac{sum\ of\ total\ number\ of\ score}{total\ number\ of\ students}[/tex]

we have given that mean of 9 students is 84

so total score of 9 students = mean×9

                                              =84×9=756

and we have given mean score of exam is 82 and there is total 10 students so the total score of 10 students =10×82

                                                      =820

so the unreadable score = score of 10 students -score of 9 students =820-756=64

Find and simplify the expression if

Answers

Answer:

[tex] f ( 2 x ) = 4 x ^ 2 - 8 [/tex]

Step-by-step explanation:

We are given the following expression and we are to simplify the given function:

[tex] f ( x ) = x ^ 2 - 8 [/tex]

Applying the function [tex]f(2x)[/tex] on [tex] f ( x ) = x ^ 2 - 8 [/tex] to get:

[tex] f ( 2 x ) = ( 2 x ) ^ 2 - 8 [/tex]

[tex] f ( 2 x ) = 4 x ^ 2 - 8 [/tex]

Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 3. Check your answer by noting that the curve is a line segment and calculating its length by the distance formula.

Answers

Answer:

[tex]4\sqrt{17}[/tex]

Step-by-step explanation:

Let's find the answer by using the arc length formula which is:

[tex]\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^{2} } } \, dx[/tex]

First, let's find dy/dx which is:

y=4x-5

y'=4*(1)-0

y'=4, now let's use the formula:

[tex]\int\limits^3_{-1} {\sqrt{1+4^{2}} } \, dx=\sqrt{17} *(3-(-1))=4\sqrt{17}[/tex]

Now, using the distance formula we have:

[tex]d=\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }[/tex]

[tex]y(-1)=4*(-1)-5=-9 \\y(3)=4*(3)-5=7[/tex]

So we have two points (-1, -9) and (3, 7) so:

[tex]d=\sqrt{(3-(-1))^{2} +(7-(-9))^{2} }=4\sqrt{17}[/tex]

Notice both equations gave the same length [tex]4\sqrt{17}[/tex].

Final answer:

To find the length of the curve y = 4x - 5, -1 ≤ x ≤ 3 using the arc length formula, integrate sqrt(1 + (dy/dx)^2) from x = -1 to x = 3. The length of the curve is 4√17. The result can be confirmed by calculating the length using the distance formula.

Explanation:

To find the length of the curve y = 4x - 5, -1 ≤ x ≤ 3 using the arc length formula, we need to integrate the square root of 1 + (dy/dx)^2 from x = -1 to x = 3. The derivative of y = 4x - 5 is dy/dx = 4. Substituting this into the arc length formula, we have:

L = ∫sqrt(1 + (dy/dx)^2) dx = ∫sqrt(1 + 4^2) dx = ∫sqrt(17) dx = x√17 + C

Now, plugging in the limits of integration, we have:

L = [(3√17) + C] - [(-1√17) + C] = (3√17) - (-1√17) = 4√17

To check our answer, we can use the distance formula. The endpoints of the line segment are (-1, -9) and (3, 7). Using the distance formula:

D = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((3 - (-1))^2 + (7 - (-9))^2) = sqrt(4^2 + 16^2) = sqrt(272) = 16√17

As we can see, the length of the curve obtained using the arc length formula (4√17) matches the length calculated using the distance formula (16√17), confirming our answer.

Six distinct integers are picked from the set {1, 2, 3,…, 10}. How many selections are there, in which the second smallest integer in the group is 3?

Answers

Answer:

1680 ways

Step-by-step explanation:

Total number of integers = 10

Number of integers to be selected = 6

Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.

2 ways   1 way                                      

Each of the line represent the digit in the integer.

After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840

Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways

Therefore, there are 1680 ways to pick six distinct integers.

Answer:

70 total selections

Step-by-step explanation:

The set: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

You know that that 3 is definitly a part of the set, so you can ignore it. If 3 is the second smallest, the smallest number in the set is either 1 or 2, not both.

The number of ways to choose between 1 and 2 is [tex]2^{C}1[/tex] ways which is equal to 2, so all that's left is choosing from the group of the set between 4 and 10.

Since you've already chosen 2 numbers (3 and 1 or 2) you need to find out how many ways can you choose 4 out of the numbers between 4 and 10. Since there are 7 numbers from 4 to 10, you need to figure out [tex]7^{C}4[/tex] which is equal to 35.

Since you are looking to find the cross between the 2, multiply 2 by 35 = 70, the answer.

-1 mod 19 please show work a =dq+r

Answers

Answer:

The given expression can be written as -1=19(-1)+18.

Step-by-step explanation:

According to quotient remainder theorem:

For any integer a and a positive integer d, there exist unique integers q and r such that

[tex]a=d\times q+r[/tex]

It can also written as

[tex]a\text{mod }d=r[/tex]

The given expression is

[tex]-1\text{mod }19[/tex]

Here a=-1 and d=19.

[tex]\frac{-1}{19}=19(-1)+18[/tex]

[tex]-1\text{mod }19=18[/tex]

If -1 is divides by 19, then the remainder is 18. The value of r is 18.

Therefore the given expression can be written as -1=19(-1)+18.

-1 mod 19 is equal to 18.

Finding -1 mod 19

To determine -1 mod 19, we use the formula a = dq + r, where a = -1, d = 19, and q and r are the quotient and remainder, respectively.

First, note that any number mod 19 will yield a remainder between 0 and 18.

Since -1 is a negative number, we rewrite it in terms of 19: -1 = -1 + 19k for some integer k.

To find a positive equivalent, we choose k such that -1 + 19k is positive and falls within the range of 0 to 18. When k = 1, we get -1 + 19(1) = 18.

Therefore, -1 mod 19 is equal to 18.

This means that if you divide -1 by 19, the remainder that falls within the range of 0 to 18 is 18.

According to insurance records, a car with a certain protection system will be recovered 95% of the time. If 800 stolen cars are randomly selected, what is the mean and standard deviation of the number of cars recovered after being stolen?

Answers

Answer: Mean = 760

Standard deviation = 6.16

Step-by-step explanation:

Given : The number of trials: [tex]n=800[/tex]

The probability that  a certain protection system will be recovered :[tex]p=0.95[/tex]

We know that the mean and standard deviation of binomial distribution is given by :_

[tex]\text{Mean}=np[/tex]

[tex]\text{Standard deviation}=\sqrt{np(1-p)}[/tex], where n is the number of trials and p is the probability of success.

Now, the mean and standard deviation of the number of cars recovered after being stolen is given by :-

[tex]\text{Mean}=800\times0.95=760[/tex]

[tex]\text{Standard deviation}=\sqrt{800\times0.95(1-0.95)}\\\\=6.164414002\approx6.16[/tex]

Hence, the mean is 760 and standard deviation is 6.16 .

Final answer:

The mean and standard deviation of the number of cars recovered after being stolen can be found using the properties of the binomial distribution.

Explanation:

To find the mean and standard deviation of the number of cars recovered after being stolen, we can use the properties of the binomial distribution. In this case, the probability of recovering a car is 0.95, and the number of stolen cars is 800.

The mean can be calculated by multiplying the number of trials (800) by the probability of success (0.95), giving us a mean of 760 cars.

The standard deviation can be calculated using the formula:

standard deviation = sqrt(n * p * (1 - p))

Substituting in the values, we get:

standard deviation = sqrt(800 * 0.95 * (1 - 0.95))

standard deviation ≈ 8.72 cars.

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Solve the Differential equation 2(y-4x^2) dx + x dy = 0

Answers

Final answer:

The solution of the given differential equation involves rearranging it into the standard form of a first-order linear differential equation, determining the integrating factor, and subsequently solving for the dependent variable y(x) via integration.

Explanation:

To solve the given differential equation, we can rewrite it in the form of dy/dx = f(x, y). That gives us (2(y-4x^2))/x = dy/dx. The resulting equation is a first-order linear differential equation, which can be solved using an integrating factor.

Here, the standard form of the differential equation is dy/dx + P(x)y = Q(x). Comparing this with our equation, we find P(x) = -2/x and Q(x) = -8x. We know that μ(x) = exp(∫P(x) dx) is the integrating factor. On solving we get μ(x) = 1/x2. We then multiply through our differential equation by μ(x) and integrate both sides to solve for y(x).

These steps on how to solve the differential equation involve certain knowledge in differential equation theory, namely about first-order linear differential equations, integrating factors, and the process of integration.

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Solve the given differential equation by using an appropriate substitution. The DE is of the form dy dx = f(Ax + By + C), which is given in (5) of Section 2.5. dy dx = 4 + y − 4x + 5

Answers

No idea what the cited section's method is, but this ODE is linear:

[tex]\dfrac{\mathrm dy}{\mathrm dx}=4+y-4x+5[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}-y=9-4x[/tex]

Multiply both sides by [tex]e^{-x}[/tex] so that the left side can be condensed as the derivative of a product:

[tex]e^{-x}\dfrac{\mathrm dy}{\mathrm dx}-e^{-x}y=(9-4x)e^{-x}[/tex]

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[e^{-x}y\right]=(9-4x)e^{-x}[/tex]

Integrating both sides gives

[tex]e^{-x}y=(4x-5)e^{-x}+C[/tex]

[tex]\implies\boxed{y(x)=4x-5+Ce^x}[/tex]

Suppose that a department contains 9 men and 15 women. How many different committees of 6 members are possible if the committee must have strictly more women than men?

Answers

Answer:  The required number of different possible committees is 81172.

Step-by-step explanation:    Given that a department contains 9 men and 15 women.

We are to find the number of different committees of 6 members that are possible if the committee must have strictly more women than men.

Since we need committees of 6 members, so the possible combinations are

(4 women, 2 men), (5 women, 1 men) and (6 women).

Therefore, the number of different committees of 6 members is given by

[tex]n\\\\\\=^{15}C_4\times ^9C_2+^{15}C_5\times ^9C_1+^{15}C_6\\\\\\=\dfrac{15!}{4!(15-4)!}\times \dfrac{9!}{2!(9-2)!}+\dfrac{15!}{5!(15-5)!}\times \dfrac{9!}{1!(9-1)!}+\dfrac{15!}{6!(15-6)!}\\\\\\\\=\dfrac{15\times14\times13\times12\times11!}{4\times3\times2\times1\times11!}\times\dfrac{9\times8\times7!}{2\times1\times7!}+\dfrac{15\times14\times13\times12\times11\times10!}{5\times4\times3\times2\times1\times10!}\times\dfrac{9\times8!}{1\times8!}+\dfrac{15\times14\times13\times12\times11\times10\times9!}{6\times5\times4\times3\times2\times1\times9!}\\\\\\=1365\times36+3003\times9+5005\\\\=49140+27027+5005\\\\=81172.[/tex]

Thus, the required number of different possible committees of 6 members is 81172.

How much would be in your savings account in eight years after depositing $180 today if the bank pays 8 percent per year? (Do not round intermediate calculations. Round your answer to 2 decimal places.) 10 points Future value Skipped eBook Hint Print Referer LO

Answers

Answer:

$333.17

Step-by-step explanation:

Use the compounding formula

[tex]A(t)=P(1+r)^t[/tex]

where A(t) is the amount at the end of the compounding,

P is the initial deposit,

r is the interest rate in decimal form, and

t is the time in years.

Filling in our info:

[tex]A(t)=180(1+.08)^8[/tex]

Simplify a bit to

[tex]A(t)=180(1.08)^8[/tex]

Raise 1.08 to the 8th power and get

A(t) = 180(1.85093021) and then multiply to get

A(t) = $333.17

The melons are three for $ 8, how many can you buy for $ 25? Which proportion is correctly stated?

A. 3/8 = 25/x
B. 8/25 = x/3
C. 8/3 = 25/x
D. x/8 = 25/3

Answers

Answer:

C

Step-by-step explanation:

The melons are 3 for 8 dollars, this means each melon is worth 8/3 dollars, this is the first proportion in the expression.  In this proportion the numerator is the value of money so 25 will be the numerator in the other proportion.

8/3=25/x, C

Use the graph of the line to find the​ x-intercept, y-intercept, and slope. Write the​ slope-intercept form of the equation of the line.

Answers

1) x-intercept:

x-intercept is the point where the graph of the equation crosses the x-axis. From the given figure, we can see that the line is crossing the x-axis at -10. Thus the x-intercept is -9

2) y-intercept:

y-intercept is the point where the graph of the equation crosses the y-axis. From the given figure, we can see that the line is crossing the y-axis at -10. Thus the y-intercept is -9

3) Slope:

Slope of a line is calculated as:

[tex]slope=m=\frac{\text{Difference in y coordinates}}{\text{Difference in x coordinates}}[/tex]

For calculating the slope we can use both intercepts. x-intercept is ordered pair will be (-9, 0) and y-intercept will be (0, -9). So the slope of the line will be:

[tex]m=\frac{-9-0}{0-(-9)}=-1[/tex]

Therefore, the slope of the line is -1.

4) Slope intercept form of the line:

The slope intercept form of the line is represented as:

[tex]y=mx+c[/tex]

where,

m = slope of line = -1

c = y-intercept = -9

Using these values, the equation becomes:

[tex]y=-x- 9[/tex]

Answer:

x-intercept: [tex]-9[/tex].

y-intercept: [tex]-9[/tex].

Slope: [tex]-1[/tex]

Equation: [tex]y=-x-9[/tex]

Step-by-step explanation:

We have been given a graph of a line on coordinate plane. We are asked to find the x-intercept, y-intercept, and slope.          

We know that x-intercept of a function is a point, where graph crosses x-axis.

Upon looking at our given graph, we can see that graph crosses x-axis at point [tex](-9,0)[/tex], therefore, x-intercept is [tex]-9[/tex].

We know that y-intercept of a function is a point, where graph crosses y-axis.

Upon looking at our given graph, we can see that graph crosses y-axis at point [tex](0,-9)[/tex], therefore, y-intercept is [tex]-9[/tex].

We have two points on the line. Let us find slope of line using points  [tex](-9,0)[/tex] and  [tex](0,-9)[/tex].

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{-9-0}{0-(-9)}=\frac{-9}{0+9}=\frac{-9}{9}=-1[/tex]

Therefore, the slope of the line is [tex]-1[/tex].

Now, we will substitute [tex]m=-1[/tex] and y-intercept [tex]-9[/tex] in slope form intercept of equation as:

[tex]y=mx+b[/tex], where,

m = Slope,

b = The y-intercept.

[tex]y=-1(x-(-9))[/tex]

[tex]y=-1(x+9)[/tex]

[tex]y=-x-9[/tex]

Therefore, the equation of the line would be [tex]y=-x-9[/tex].

The top of a ladder slides down a vertical wall at a rate of 0.675 m/s. At the moment when the bottom of the ladder is 6 m from the wall, it slides away from the wall at a rate of 0.9 m/s. How long is the ladder?

Answers

Answer:

The length of the ladder is 10 m.

Step-by-step explanation:

Let x shows the distance of the top of ladder from the bottom of base of the wall, y shows the distance of the bottom of ladder from the base of the wall and l is the length of the ladder,

Given,

[tex]\frac{dx}{dt}=-0.675\text{ m/s}[/tex]

[tex]\frac{dy}{dt}=0.9\text{ m/s}[/tex]

y = 6 m,

Since, the wall is assumed perpendicular to the ground,

By the pythagoras theorem,

[tex]l^2=x^2+y^2[/tex]

Differentiating with respect to t ( time ),

[tex]0=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]     ( the length of wall would be constant )

By substituting the value,

[tex]0=2x(-0.675)+2(6)(0.9)[/tex]

[tex]0=-1.35x+10.8[/tex]

[tex]\implies x=\frac{10.8}{1.35}=8[/tex]

Hence, the length of the ladder is,

[tex]L=\sqrt{x^2+y^2}=\sqrt{8^2+6^2}=\sqrt{64+36}=\sqrt{100}=10\text{ m}[/tex]

Answer:

The length of ladder=8m.

Step-by-step explanation:

Given

The rate at which the top of a ladder slides down a vertical wall,[tex]\frac{\mathrm{d}z}{\mathrm{d}t}[/tex]= 0.675m/s

The distance of bottom of ladder from the wall,x=6m

The rate at which it slides away from the wall ,[tex]\frac{\mathrm{d}x}{\mathrm{d}t}[/tex]=0.9m/s

Let length of ladder =z

Length of wall=y

Distance between foot of ladder and wall=x

By using pythogorous theorem

[tex]x^2+y^2=z^2[/tex]

Differentiate w.r.t time

[tex]x\frac{\mathrm{d}x}{\mathrm{d}t}=z\frac{\mathrm{d}z}{\mathrm{d}t}[/tex]

y does not change hence, [tex]\frac{\mathrm{d}y}{\mathrm{d}t}=0[/tex]

[tex]6\times 0.9=z\times 0.675[/tex]

[tex]z=\frac{5.4}{0.675}[/tex]

z=8 m

Hence, the length of ladder=8m.

Consider the three points graphed. What is the value of y in the fourth point that will complete the quadrilateral as a rhombus?

Answers

The fourth point that will complete the quadrilateral is a rhombus is -3.

In a rhombus, two parallel sides must be equal.

What is a straight line graph?

The graph follows a straight line equation shows a straight line graph.equation of a straight line is   y=mx+cy represents vertical line y-axis.x represents the horizontal line x-axis.     m is the slope of the line

            slope(m)=tan∅=y axis/x axis.

c represents y-intercepts (it is the point at which the line cuts on the y-axis)Straight line graphs show a linear relationship between the x and y values.

Calculation:-

1st coordinate- side=[tex]\sqrt{10}[/tex]

2nd coordinate- side= [tex]\sqrt{18}[/tex]

3rd coordinate  must be [tex]\sqrt{10}[/tex]

so,y=-3

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Answer:

Consider the three points graphed. What is the value of y in the fourth point that will complete the quadrilateral as a rhombus?

(–1, -5 )

Step-by-step explanation:

Use the method of reduction of order to find a second solution to t^2y' + 3ty' – 3y = 0, t> 0 Given yı(t) = t y2(t) = Preview Give your answer in simplest form (ie no coefficients)

Answers

Let [tex]y_2(t)=tv(t)[/tex]. Then

[tex]{y_2}'=tv'+v[/tex]

[tex]{y_2}''=tv''+2v'[/tex]

and substituting these into the ODE gives

[tex]t^2(tv''+2v')+3t(tv'+v)-3tv=0[/tex]

[tex]t^3v''+5t^2v'=0[/tex]

[tex]tv''+5v'=0[/tex]

Let [tex]u(t)=v'(t)[/tex], so that [tex]u'(t)=v''(t)[/tex]. Then the ODE is linear in [tex]u[/tex], with

[tex]tu'+5u=0[/tex]

Multiply both sides by [tex]t^4[/tex], so that the left side can be condensed as the derivative of a product:

[tex]t^5u'+5t^4u=(t^5u)'=0[/tex]

Integrating both sides and solving for [tex]u(t)[/tex] gives

[tex]t^5u=C\implies u=Ct^{-5}[/tex]

Integrate again to solve for [tex]v(t)[/tex]:

[tex]v=C_1t^{-6}+C_2[/tex]

and finally, solve for [tex]y_2(t)[/tex] by multiplying both sides by [tex]t[/tex]:

[tex]tv=y_2=C_1t^{-5}+C_2t[/tex]

[tex]y_1(t)=t[/tex] already accounts for the [tex]t[/tex] term in this solution, so the other independent solution is [tex]y_2(t)=t^{-5}[/tex].

A nurse must infuse 1.5 ml of solution in x minutes and she has 650 ml of solution how many minutes will it take for the medicine to be given

Answers

Answer:

433 minutes

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

The nurse is infusing 1.5 ml of solution every x minutes, Since there are a total of 650 ml we can divide the amount the nurse is infusing every x minutes by the total in order to calculate the amount of time it will take the nurse to finish.

[tex]\frac{650}{1.5} = 433.33min[/tex]

So we can see that it will take the nurse 433 min to infuse all of the solution.

Answer:

In 433.33 minutes will it take for the medicine to be given.

Step-by-step explanation:

Given : A nurse must infuse 1.5 ml of solution in x minutes and she has 650 ml of solution.

To find : How many minutes will it take for the medicine to be given ?

Solution :

As 1.5 ml of solution infuse in x minutes

i.e. the amount of solution she has = [tex]1.5x[/tex]

Now, she has 650 ml of solution.

which means  [tex]1.5x=650[/tex]

Solving the equation,

[tex]x=\frac{650}{1.5}[/tex]

[tex]x=433.33[/tex]

Therefore, in 433.33 minutes will it take for the medicine to be given.

Question 10 (7 points) d Elizabeth borrowed $20,000 for five years at a 5% annual interest rate, what is her monthly payment, to the nearest dollar? A. $252 B. $334 C. $377 D. $4050 E. None of these Save

Answers

Answer:

monthly payment is $377

C is the correct option.

Step-by-step explanation:

The formula for the monthly payment is given by

[tex]C=\frac{Prt(1+r)^n}{(1+r)^n-1}[/tex]

Given that,

P =  $20,000

n = 5 years = 60 months

r = 0.05

Substituting these values in the formula

[tex]C=\frac{20000\cdot \frac{0.05}{12}(1+\frac{0.05}{12})^{60}}{(1+\frac{0.05}{12})^{60}-1}[/tex]

On simplifying, we get

[tex]C=\$377.425\\\\C\approx \$377[/tex]

Therefore, the monthly payment is $377

C is the correct option.

John Smith made a one year investment that generated a nominal return of 6% or $3000. The real return was $2000. What was the original investment amount? what was the annual inflation rate? Macroeconomic

Answers

The nominal value - without discounting the inflation rate - of income was $ 3000.

If the interest rate was 6%, a rule of three is enough to find the value of the original investment.

3000 - 6%

x - 100%

x = 50,000

The value of the investment was $ 50,000

In this case, the inflation rate also requires a simple calculation.

Inflation corroded $ 1000 dollars of income of $ 3000

Therefore the inflation rate will be 1000/3000 = 33.3%

4. Find the general solution to 4y"+20y'+25y = 0

Answers

Answer:

[tex]y(x)=c_1e^{-\frac{5}{2}x}+c_2xe^{-\frac{5}{2}x}[/tex]

Step-by-step explanation:

The given differential equation is 4y"+20y'+25y = 0

The characteristics equation is given by

[tex]4r^2+20r+25=0[/tex]

Now, solve the equation for r

Factor by middle term splitting

[tex]4r^2+10r+10r+25=0\\\\2r(2r+5)+5(2r+5)=0[/tex]

Factored out the common term

[tex](2r+5)(2r+5)=0[/tex]

Use Zero product property

[tex](2r+5)=0,(2r+5)=0[/tex]

Solve for r

[tex]r_{1,2}=-\frac{5}{2}[/tex]

We got the repeated roots.

Hence, the general equation for the differential equation is

[tex]y(x)=c_1e^{-\frac{5}{2}x}+c_2xe^{-\frac{5}{2}x}[/tex]

Final answer:

The general solution to the differential equation 4y"+20y'+25y = 0 is y(x) = (A + Bx)e^(-5/2x), where A and B are constants determined by initial conditions.

Explanation:

The general solution to the differential equation 4y"+20y'+25y = 0 can be found by looking for solutions in the form of y = ekx, where k is a constant. Substituting y into the differential equation, we get a characteristic equation of (ak² +bk+c)y= 0, which simplifies to (4k² + 20k + 25)y = 0. This is a quadratic equation in k that can be factored as (2k + 5)². Therefore, the two values of k that satisfy this equation are both -5/2, giving us a repeated root.

The general solution for a second-order linear homogeneous differential equation with repeated roots is y = (A + Bx)ekx, where A and B are constants determined by the initial conditions. In this case, k = -5/2, hence the general solution is y(x) = (A + Bx)e-5/2x.

Compute the surface integral over the given oriented surface: F=y3i+8j−xk, portion of the plane x+y+z=1 in the octant x,y,z≥0, downward-pointing normal

Answers

We are to find the surface integral of [tex]\mathbf{\int \int _S \ F.ds}[/tex]

where;

the surface of the portion of the plane is [tex]x+y+z =1[/tex]; in the 1st octant,  [tex]x,y,z \geq 0[/tex]  , and:the oriented surface [tex]\mathbf{F = y^3i+8j-xk}[/tex]

The plane x + y + z = 1

z = 1 - x - y

[tex]\dfrac{\partial z}{\partial x} = -1[/tex]

[tex]\dfrac{\partial z}{\partial y} = -1[/tex]

Since the surface is oriented downward

[tex]dS = \Big( \dfrac{\partial z}{\partial x}i + \dfrac{\partial z}{\partial y}j - k) dxdy[/tex]

[tex]dS = (-i-j-k) dxdy[/tex]

However,

Flux = [tex]\mathbf{\int \int _S \ F.ds}[/tex]

[tex]= \int \int_R F. \Big( \dfrac{\partial z}{\partial x}i + \dfrac{\partial z}{\partial y}j - k) dxdy \\ \\ \\ = \int^1_{ x=0} \int ^{1-x}_{y=0} ( y^3i + 8j -xk)*(-i-j-k) dx dy \\ \\ \\ =\int^1_{ x=0} \int ^{1-x}_{y=0} (-y^3 -8+x) dxdy \\ \\ \\ = \int^1_{ x=0} \Big( \int ^{1-x}_{y=0} \Big(x-y^3 -8\Big) dy \Big) dx \\ \\ \\ = \int^1_{ x=0} \Bigg [xy - \dfrac{y^4}{4}-8y \Bigg]^{1-x}_{y=0} \ dx \\ \\ \\[/tex]

[tex]= \int^1_{ x=0} \Bigg [x(1-x) - \dfrac{1}{4}(1-x)^{4} - 8(1-x) \Bigg ] dx \\ \\ \\ = \int^1_{ x=0} \Bigg [(x-x^2) - \dfrac{1}{4}(x-1)^4+8(x-1)\Bigg] dx[/tex]

[tex]= \Bigg [ \dfrac{x^2}{2}-\dfrac{x^3}{3} - \dfrac{1}{4} \dfrac{(x-1)^5}{5}+(x-1)^2\Bigg] ^1_0[/tex]

[tex]= \Bigg [ \dfrac{1}{2}-\dfrac{1}{3} -0+0-0+0+ \dfrac{1}{4}\times \dfrac{(-1)^5}{5}-(0-1)^2\Bigg][/tex]

[tex]= \Bigg [ \dfrac{1}{2}-\dfrac{1}{3} - \dfrac{1}{20}-1\Bigg][/tex]

[tex]= \Bigg [ \dfrac{30-20-3-60}{60}\Bigg][/tex]

[tex]= \Bigg [ \dfrac{-53}{60}\Bigg][/tex]

Therefore, we can conclude that the surface integral is [tex]\mathbf{-\dfrac{53}{60}}[/tex]

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Final answer:

To compute a surface integral, take the antiderivatives of both dimensions defining the area with the surface edges as the bounds of the integral. The net flux through the surface can be found using the open surface integral formula.

Explanation:

A surface integral over the given oriented surface can be computed by taking the antiderivatives of both dimensions defining the area, with the edges of the surface as the bounds of the integral. The net flux through the surface can be found using the open surface integral formula.

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Your friend, Isabel, has a credit card with an APR of 19.9%! How many dollars would she pay as a finance charge for just 1 month on a $1000 charge?
Express your answer rounded to the nearest cent.

Answers

Answer:

$16.583

Step-by-step explanation:

Given :Your friend, Isabel, has a credit card with an APR of 19.9%!

To Find : How many dollars would she pay as a finance charge for just 1 month on a $1000 charge?

Solution:

We are given that finance charge for just 1 month on a $1000 charge.

So, Finance charge = [tex]\frac{19.9\% \times 1000}{12}[/tex]

Finance charge = [tex]\frac{\frac{199}{1000}\times 1000}{12}[/tex]

Finance charge = [tex]\frac{199\times 1000}{12}[/tex]

Finance charge = [tex]16.583[/tex]

Hence she pay $16.583 as a finance charge for just 1 month on a $1000 charge.

A rectangular swimming pool measures 14 feet by 30 feet. The pool is surrounded on all four sides by a path that is 3 feet wide. If the cost to resurface the path is $2 per square foot, what is the total cost of resurfacing the path?

Answers

Final answer:

To find the cost of resurfacing the path, we first calculate the area of the path which is 300 square feet. We then multiply this by the unit cost of resurfacing which comes out to be $600.

Explanation:

This is a problem in area calculation and application of unit cost. Firstly, we need to calculate the area for the path surrounding the pool. The total area of the pool and the path is (14+2*3) feet by (30+2*3) feet = 20 feet by 36 feet, which equals 720 square feet. The area of the pool itself is 14 feet by 30 feet = 420 square feet. So, the area of just the path is 720-420 = 300 square feet. With a cost of $2 per square foot to resurface the path, the total cost would be 300*$2 = $600.

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Using the Chinese Remainder Theorem, solve the congruence
x 15 (mod 42)
x 5 (mod 19)

Answers

19 and 42 are coprime, so we can use the CRT right away. Start with

[tex]x=19+42[/tex]

Taken mod 42, we're left with a remainder of 19. Notice that

[tex]19\cdot3\equiv57\equiv15\pmod{42}[/tex]

so we need to multiply the first term by 3 to get the remainder we want.

[tex]x=19\cdot3+42[/tex]

Next, taken mod 19, we're left with a remainder of 4. Notice that

[tex]42\cdot6\equiv252\equiv5\pmod{19}[/tex]

so we need to multiply the second term by 6.

Then by the CRT, we have

[tex]x\equiv19\cdot3+42\cdot6\equiv309\pmod{42\cdot19}\implies x\equiv309\pmod{798}[/tex]

so that any solution of the form [tex]x=798n+309[/tex] is a solution to this system.

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