You have 40 g of a radioisotope. If the half-life of this radioisotope is 4 days, how many grams will remain after 12 days?

Answers

Answer 1
 the number of grams  of radioisotope that have remained after 12 days if the  half life if 4 days is calculated as below

calculate the number of half lives involved

12/4 = 3 half live are involved

40 after one half life = 40/2 = 20 g
20g after the second half life = 20/2 = 10g
10g after the third half life = 10/2 = 5 g

therefore 5 g will be remaining


Related Questions



HELP! 30 POINTS!! 

2. Which of the following statements are true about a strong base and a weak base at a pH of 11?

HCl will not bring the pH of either solution to pH 7.

Both bases require the same amount of HCl to reach pH 7 because they are both
at the same initial pH.

The weak base will require less HCl to bring the pH to 7 than the strong base. The strong base will require less HCl to bring the pH to 7 than the weak base.

Answers

The answer is "The weak base will require less HCl to bring the pH to 7 than the strong base." Using titration curves, both bases will require the same amount of HCl to reach equivalence point but they will have different pH values. A strong acid like HCl will react with a strong base to form a solution with pH equal to 7 while HCl will react with a weak base to form a solution with pH less than 7. Hence, the weak base will require lesser HCl to bring the pH to 7.

the answer is definatly A

The​ half-life of the radioactive element unobtanium dash 53 is 20 seconds. if 32 grams of unobtanium dash 53 are initially​ present, how many grams are present after 20 ​seconds? 40 ​seconds? 60 ​seconds? 80 ​seconds? 100 ​seconds?

Answers

Answer: After 20 seconds, 16 grams of unobtanium will be present, after 40 seconds, 8 grams of unobtanium will be present after 60 seconds, 4 grams of unobtanium will be present, after 80 seconds, 2 grams of unobtanium will be present and after 100 seconds, 1 grams of unobtanium will be present.

Explanation: Half life is the time in which half of the reaction is completed. Thus the half of the substance will be decomposed and half of it will remain.

Amount of the substance left after n half lives will be=[tex]\frac{A}{2^n}[/tex]

where A= initial amount of substance

n=no of half lives=[tex]\frac{\text{given time}}{\text{half life}}[/tex]

a) t= 20 seconds

no of half lives=[tex]\frac{20}{20}=1[/tex]

amount of the substance left after 1 half life will be=[tex]\frac{32}{2^1}[/tex]=16 g.

b)  t= 40 seconds

no of half lives=[tex]\frac{40}{20}=2[/tex]

amount of the substance left after 2 half lives will be=[tex]\frac{32}{2^2}[/tex]=8g.

c) t= 60 seconds

no of half lives=[tex]\frac{60}{20}=3[/tex]

amount of the substance left after 3 half lives will be=[tex]\frac{32}{2^3}=4g[/tex]

d) t= 80 seconds

no of half lives=[tex]\frac{80}{20}=4[/tex]

amount of the substance left after 4 half lives will be=[tex]\frac{32}{2^4}=2g[/tex]

e) t= 100 seconds

no of half lives=[tex]\frac{100}{20}=5[/tex]

amount of the substance left after 5 half lives will be=[tex]\frac{32}{2^5}=1g.[/tex]




The half-life of a radioactive element is defined as the time required by the specific isotope to decrease by half of its original value. The unobtanium after given time will be present as:

After 20 secs, 16 gramsAfter 40 secs, 8 gramsAfter 60 secs, 4 gramsAfter 80 secs, 2 gramsAfter 100 secs, 1 gram

Half-life is the time required by the unobtanium is the half of the reaction is completed. Half of the substance will be decomposed, such that:

Amount of substance left n half-lives = [tex]\dfrac{\text A}{{2}^{\text n}}[/tex]

where A= initial amount of substance

Now,

n = number of half-lives = given time /half-life

Given,

1. Time = t = 20 seconds

Number of half-lives = [tex]\dfrac{20}{20}[/tex] = 1Amount of the substance left after 1 half life =  [tex]\dfrac{\text 32}{{2}^{\text 1}}[/tex] = 16 grams.

2.Time = t = 40 seconds

Number of half-lives = [tex]\dfrac{40}{20}[/tex] = 1Amount of the substance left after 1 half life =  [tex]\dfrac{\text 32}{{2}^{\text 2}}[/tex] = 8 grams.

3.Time = t = 60 seconds

Number of half-lives = [tex]\dfrac{60}{20}[/tex] = 1Amount of the substance left after 1 half life =  [tex]\dfrac{\text 32}{{2}^{\text 3}}[/tex] = 4 grams.

4.Time = t = 80 seconds

Number of half-lives = [tex]\dfrac{80}{20}[/tex] = 1Amount of the substance left after 1 half life =  [tex]\dfrac{\text 32}{{2}^{\text 4}}[/tex] = 2 grams.

5.Time = t = 100 seconds

Number of half-lives = [tex]\dfrac{100}{20}[/tex] = 1Amount of the substance left after 1 half life =  [tex]\dfrac{\text 32}{{2}^{\text 5}}[/tex] = 1 grams.

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How many nitrogen molecules are in a 8.86 L container of nitrogen gas at a pressure of 112.1 kPa and a temperature of 30.8 oC?

Answers

we can first find the number of moles of nitrogen gas in the container using th ideal gas law equation 
PV = nRT
where P - pressure - 112 100 Pa
V - volume - 8.86 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 30.8 °C + 273.15 = 303.95 K
substituting these values in the equation 
112 100 Pa x 8.86 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 303.95 K
n = 0.393 mol 
number of N₂ moles are 0.393 mol

In 1 mol of N₂ there are 6.022 x 10²³ molecules of N₂
therefore in 0.393 mol - 6.022 x 10²³ mol⁻¹ x 0.393 mol = 2.37 x 10²³ 
there are 2.37 x 10²³ molecules of N₂
We will use this law PV = nRT
we have to convert pressure from kPa to atm
1 atm = 101.325 kPa
? atm = 112.1 kPa
P = 1.11 atm
T = 30.8 °C + 273.15 = 303.95 K
V = 8.86 L
R = 0.088205 atm. L / mol . Kelvin
n = [tex] \frac{PV}{RT} = \frac{1.11 * 8.86}{0.08205 * 303.95} [/tex] = 0.39 mol
number of N₂ molecules = number of moles * Avogadro's number
                                        = 0.39 * (6.022 * 10²³) = 2.37 x 10²³ molecules 

What is the theoretical yield in liters of hydrogen at STP if 20.1g of calcium are completely reacted

Answers

Calcium reacts with water to produce Calcium Hydroxide and Hydrogen gas;

                            Ca  +  2 H₂O    →    Ca(OH)₂  +  H₂

According to balance equation,

                 40 g (1 mole) Ca reacts to form  =  22.4 L (1 mole) H₂
So,
                           20.1 g of Ca will produce  =  X L of H₂

Solving for X,,
                                        X  =  (22.4 L × 20.1 g) ÷ 40 g

                                        X  =  11.25 L

Result:
          Theoretical Yield of H₂ at STP  =  11.25 Liter

Rubbing alcohol is 70.% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container? 330 ml 680 ml 0.15 ml 70. ml 470 ml

Answers

move the decimal to the left 2 spaces then mult that by the number of mls.
0.70 times 473 = 331ml

Why do covalent compounds tend to have lower melting points than ionic compounds?

Answers

Simple molecular substances consist of molecules in which the atoms are joined by strong covalent bonds. Their molecules are held together by weak forces, so these substances have low melting and boiling points. ... They have high melting and boiling points.

The forces of attraction in covalent compounds are weaker than those in ionic compounds as they are formed by sharing of electrons.

What are covalent compounds?

Covalent compound is defined as a compound which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.

Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.

Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.

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The pair of elements that forms a bond with the least ionic character is

A. Na and Cl
B. K and Cl
C. O and Cl
D. Mg and Cl

Answers

As we know the electronegativity difference between two atoms in ionic compounds is greater than 1.7. So, greater the difference in electronegativity above 1.7 greater will be the ionic character and vice versa.

For Na and Cl;

                                    E.N of Chlorine   =  3.16
 
                                    E.N of Sodium    =  0.93
                                                                 ------------
                                    Difference               2.23

For K and Cl;

                                    E.N of Chlorine       =  3.16
 
                                    E.N of Potassium    =  0.82
                                                                     ------------
                                    Difference                    2.34

For O and Cl;

                                    E.N of Oxygen     =  3.44
 
                                    E.N of Chlorine    =  3.16
                                                                  ------------
                                    Difference                0.28

For Mg and Cl;

                                    E.N of Chlorine         =  3.16
 
                                    E.N of Magnesium    =  0.93
                                                                       ------------
                                    Difference                     1.31

Result:
           
As calculated above,the least electronegativity difference is found between Oxygen and Chlorine which is less than 1.7. Hence, it is not ionic compound or it has least Ionic character.

The pair of O and Cl elements forms a bond with the least ionic character.

The ionic character of the bond depends on the electronegativity difference. The bonds having an electronegativity difference of greater than 1.7 have more ionic character.

(A) In bond between Na and Cl, the electronegativity difference =

Electronegativity of Cl - electronegativity of Na

= 3.16 - 0.93

= 2.23

(B) In bond between K and Cl

= electronegativity of Cl - electronegativity of K

= 3.16 - 0.82

= 2.34

(C) In bond between O and Cl:

= electronegativity of O - electronegativity of Cl

= 3.44 - 3.16

= 0.17

(D) In bond between Mg and Cl:

= electronegativity of Cl - electronegativity of Mg

= 3.16 - 1.31

= 1.85

Since the bond between O and Cl has the least electronegativity difference, thus have the least ionic character.

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Which best describes the tyndall effect? the scattering of light by solutes in a mixture the scattering of light by solvent in a solution the scattering of light by solutes in a solution the scattering of light by particles in a mixt?

Answers

the scattering of light by particles in a mixture

Answer:The correct answer is option:'the scattering of light by particles in a mixture'.

Explanation:

Tyndall effect is defined as scattering of the light by the particles present in the mixture. A beam of the light passing through these mixture are visible to the human eyes. Generally colloidal mixture displays this type of effect. The name of his effect is named after the physicist named John Tyndall.

Hence, the correct answer is option:'the scattering of light by particles in a mixture'.

How many moles of KNO3 are needed to make 600 ml of a 1.3M solution?

Answers

Final answer:

To make a 1.3M solution with a volume of 600 ml, you would need 0.78 moles of KNO3.

Explanation:

To calculate the number of moles of KNO3 needed to make a 1.3M solution, we can use the equation:

Molarity (M) = moles of solute / liters of solution

Rearranging the equation, we can solve for moles of solute:

Moles of solute = Molarity x liters of solution

In this case, the molarity is 1.3M and the volume is 600 ml (which is equivalent to 0.6 L). Substituting these values into the equation:

Moles of KNO3 = 1.3M x 0.6 L = 0.78 moles

Potassium-40 has a half-life of 1.3 billion years. as the potassium-40 isotope decays, it becomes argon. if a rock was formed with 12 g of potassium-40, approximately how long would it take for 75% of the potassium-40 to be replaced by argon?
a. 1.3 billion years
b. 2.6 billion years
c. 5.2 billion years
d. 650 million years

Answers

Final answer:

It takes two half-lives, or 2.6 billion years, for 75% of Potassium-40 to decay to Argon, making (b) 2.6 billion years the correct option.

Explanation:

The decay of Potassium-40 (K-40) to Argon (Ar-40) follows the principles of radioactive decay and the concept of half-lives. The half-life is the time it takes for half of the original quantity of a radioactive isotope to decay. In this case, K-40 has a half-life of approximately 1.3 billion years. After one half-life, there would be 6 grams of K-40 and 6 grams of Ar-40. After two half-lives, which is 2.6 billion years, there would be 3 grams of K-40 and 9 grams of Ar-40. Since the question asks for the time it would take for 75% of the potassium-40 to be replaced by argon, we are looking for the time it takes to have only 25% of the original K-40 remaining.

Starting with 12 grams of K-40, after the first half-life, we would be left with 6 grams of K-40, which is 50%. After the second half-life, we would be left with 3 grams of K-40, which is 25% of the original amount. Therefore, it would take two half-lives for 75% of the potassium-40 to decay to argon, which equates to 2.6 billion years. The correct option is therefore (b) 2.6 billion years.

Sedimentary rocks formed from the remains of once-living things are

Answers

The correct option is D. This type of rock is called biologic sedimentary rock. It is formed from accumulation of dead living things which have been compressed and cemented together to form a rock.

Please advise if this is your complete question entirely? If yes, then your correct answer is provided above.

Sedimentary rocks formed from the remains of once-living things are ____.
a. metamorphic
c. organic
b. detrital
d. none of the above

The correct option is D. This type of rock is called biologic sedimentary rock. It is formed from accumulation of dead living things which have been compressed and cemented together to form a rock.


Please advise if this is your complete question entirely? If yes, then your correct answer is provided above.


Sedimentary rocks formed from the remains of once-living things are ____.

a. metamorphic

c. organic

b. detrital

d. none of the above


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How many sites on this antibody molecule have potential to bind to a non-self molecule?

Answers

There are two sites on the antibody molecule that have a potential to bind to a non-self molecule. The Fab of an antibody is the region of the antibody that binds to an antigen. It consist of one constant and one variable domain from each heavy and light chain of the antibody. During immune reaction, an antigen-antibody reaction occurs between the antibodies made by the B cells and the antigens.

What kind of reaction occurs when the entropy change of an endothermic reaction is negative?

Answers

Answer is: reaction is nonspontaneous under standard conditions at all temperatures.

Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).


Answer:

reaction is nonspontaneous under standard conditions at all temperatures.

Explanation:

took the test.

Which of the following energy yields is most likely to have come from a fission or a fusion reaction?

Answers

The correct option is D.
Fusion and fission reactions involve the generation of energy either by the coming together of atomic nuclei or by splitting apart of atomic nuclei. The amount of energy that is generated during fusion and fission process is very high and is in the range of kiloelectron volts (10^3 eV), megaelectron volts (10^6 eV) and gigaelectron volts (10^9 eV) per atom or particle. 

Answer:

D. 2.0 x 10^11 kJ/mol

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J. J. Thomson’s experiment disproved the theory that an atom is divisible. is indivisible. contains protons. contains electrons.

Answers

J. J. Thomson’s experiment disproved the theory that an atom is indivisible.

J.J. Thomson's experiment did not disprove the theory that atoms are indivisible. Instead, his experiment demonstrated the presence of subatomic particles, specifically electrons, within atoms.

The atom's indivisibleness was not refuted by J. J. Thomson's experiment. Instead, his research demonstrated that electrons, a type of subatomic particle, are present in atoms. The "plum pudding" model of the atom was created as a result of Thomson's research from the late 19th and early 20th centuries, which advanced knowledge of atomic structure.

Thomson studied the behavior of electrically charged particles (electrons) inside a vacuum tube in his well-known cathode ray tube experiment. A stream of negatively charged particles (electrons) traveled from the cathode (negative electrode) to the anode (positive electrode) when a voltage was applied across the tube. Thomson came to the conclusion that these particles were the basic building blocks of atoms.

The old belief that atoms were indestructible was refuted by Thomson's discovery of electrons within them, which also supported the notion of subatomic particles inside the atom. His "plum pudding" concept proposed that atoms had a neutral overall charge because electrons were contained within a positively charged "pudding" or matrix.

Later investigations, like those by Ernest Rutherford, helped to clarify our understanding of atomic structure and revealed the existence of a positively charged nucleus that contains protons as well as neutral particles known as neutrons. The existence of indivisible atoms was therefore not refuted by Thomson's experiment, but it did introduce the idea of subatomic particles within atoms, particularly electrons.

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Which of the following is an example of chemical weathering? a. waves washing over rocks on the beach b. acid rain falling on sidewalks c. ice forming in the cracks of rocks d. wind blowing against rocks

Answers

B. acid rain falling on sidewalks

Answer:

b. Acid rain falling on sidewalks

Explanation:

Hello,

Acid rain contains majorly carbonic acid [tex]H_2CO_3[/tex] which could react with the concrete that is used to make sidewalks. This chemical reaction, although varies based on the concrete's composition, usually gives off carbon dioxide owing to the acid's instability and leads to the weathering since the sidewalks start to wear out and subsequently break down.

Best regards.

How are genes related to DNA?


A-Genes are sections of DNA that program the amino acid sequences of proteins.

B-Genes are monomers that are joined by dehydration synthesis to make DNA.

C-Genes are proteins that bind molecules of DNA together to make amino acids.

D-Genes are monomers that are joined by hydrolysis to make DNA.


Answers

the answer to your question would be A. hope this helps...
B-Genes are monomers that are joined by dehydration synthesis to make DNA.

As the moisture-rich air approaches the mountain, it rises and cools, and water molecules in the air combine to form small drops. the process where water vapor becomes a liquid is called ____________

Answers

As the moisture-rich air approaches the mountain, it rises and cools, and water molecules in the air combine to form small drops. The process where water vapor becomes a liquid is called condensation

What is the standard cell notation for an electrolytic cell with aluminum and gold electrodes?

Answers

Answer:

Au3+

Explanation:

The standard cell notation for an electrolytic cell with aluminum and gold electrodes  Au(s)| Au³⁺  ||   Al³⁺| Al (s)

What is an Electrolytic Cell ?

A device in which electrical energy is converted into chemical energy or chemical energy is converted into electric energy is called an Electrolytic cell

The electrolytic cell consists of two metallic electrodes and an electrolyte.

In this cell nomenclature, the electrode to the left of the salt bridge is always assumed to be the anode, and the accompanying half-equation is always stated as an oxidation , while right side is cathode and the half equation is Reduction.

Reaction at Anode: Au(s) → Au³⁺(aq) + 3e⁻  ..........(oxidation)

Reaction at Cathode: Au³⁺(aq) + 3e⁻ →Au(s) ..............(reduction)

The standard cell notation for an electrolytic cell with aluminum and gold electrodes

                         Au(s)| Au³⁺  ||   Al³⁺| Al (s)

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In the formation of a solution how does the solvent differ from the solute

Answers

Solute is a substance that dissolves in a solvent in order to form a solution. Solutes can be in liquid, gaseous or solid phase. Normally, in a solution, solutes are in a lesser amount than the solvents. When a solution has the maximum amount of solutes it can dissolve, then the solution is said to be saturated.

Why can 6-aminohexanoic acid undergo a polymerization reaction with itself?

Answers

The amino group on one molecule can react with the carboxyl group on another molecule.

Answer:  Functional groups can lead to intra molecular condensation.

Explanation:  6 -aminohexanoic acid is a molecule which have 2 functional groups - one is amine group (-NH2) and the other one is carboxylic group (-COOH).

The non bonding electrons or lone pairs present on the amine group being nucleophillic in nature will attack on the electrophillic carbon of carboxylic group to form the amide bond, the structure of which is hereby attached.

Thus due to the presence of 2 active functional groups, polymerization with itself can take place easily.

Calculate the theoretical yield if 100.0 g p4o10 react with 200.0 g h2o

Answers

The reaction of Phosphorous Pentaoxide with water yield Phosphoric Acid as shown below,

                             P₄O₁₀  +  6 H₂O   →    4 H₃PO₄

According to balance equation,

           283.88 g (1 mole) P₄O₁₀ requires  =  108 g (6 mole) of H₂O
So,
                          100 g P₄O₁₀ will require  =  X g of H₂O

Solving for X,

                        X  =  (100 g × 108 g) ÷ 283.88 g

                        X  =  38.04 g of H₂O

So, 100 g P₄O₁₀ requires 38.04 g of H₂O, while we are provided with 200 g of H₂O which means that water is in excess and P₄O₁₀ is limiting reagent. Therefore, P₄O₁₀ will control the yield of H₃PO₄. So,
As,
           283.88 g (1 mole) P₄O₁₀ produced  =  391.96 g (4 mole) of H₃PO₄
So,
                          100 g P₄O₁₀ will produce  =  X g of H₃PO₄

Solving for X,
                             X  =  (100 g × 391.96 g) ÷ 283.88 g

                             X  =  138.07 g of H₃PO₄

Result:
           
Theoretical Yield of this reaction is 138.07 g.

A gas sample has a volume of 150 ml at 0.00 ∘c. the temperature is raised (at constant pressure) until the volume is 218 ml. what is the temperature of the gas sample in ∘c at this volume?

Answers

Charles law gives the relationship between volume and temperature of a gas. 
It states that at constant pressure, volume is directly proportional to temperature of gas. 
V/ T = k
where V -volume , T - temperature and k - constant 
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
parameters for the first instance are given on the left side and parameters for the second instance are given on the right side of the equation 
T1 - temperature in kelvin 0.0 °C + 273 = 273 K
substituting the values in the equation 
[tex] \frac{150 mL}{273 K} = \frac{218 mL}{T} [/tex]
T = 397 K 
temperature in celcius - 397 K - 273 = 124 °C
new temperature is 124 °C

A 94.7-g sample of silver (s = 0.237 j/(g · °c)), initially at 348.25°c, is added to an insulated vessel containing 143.6 g of water (s = 4.18 j/(g · °c)), initially at 13.97°c. at equilibrium, the final temperature of the metal–water mixture is 22.63°c. how much heat was absorbed by the water? the heat capacity of the vessel is 0.244 kj/°c.

Answers

Q = m*C*dT

m = mass

C = specific heat capacity

dT = Temperature change

Q = heat evolved

Heat lost by metal is equal to the sum of heat taken up by water and vessel. Since water is taken in the vessel so

the initial and final temperatures would be same for vessel and water...

Q = 94.7 *0.237 *(22.63 - 348.25) = 7308.18 Joules = 7.3 KJ

Heat lost by silver = 7.3 KJ

Heat absorbed by water = 143.6*4.18*(22.63 - 13.97) = 5.2 KJ

Describe two negative effects that water pollution can have on the environment. Explain one way water pollution can be reduced.

Answers

water pollution affects the fish, and then we eat the fish so the fish affects us.  im not sure about the first part.Do not  dispose of household cleaning  down the toilet.

Answer:

1) Adverse effect on aquatic life also increase in biological oxygen demand.

2) Biomagnification of pollutants

Explanation:

Water pollution is caused by unwanted addition of waste, animal debris, industrial effluents etc in a water body.

Water pollution may cause many direct and indirect harmful effects on environment. To name a few:

a) Decrease in level of oxygen leading to death of aquatic organism like fish.

Increase in biological oxygen demand.

b) Biomagnification: a pollutant may enter food chain from water and some pollutant may enter food chain contaminating other members of food chain.

How much is 2.50 g of CuCl2 in moles ?

Answers

The molar mass of CuCl2 is 134.45 g/mol; therefore, you divide 2.5 g of CuCl2 by 134.45 g of CuCl2 leaving you with 0.019 moles. 
I hope this works.
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How does nh3 and ca(OH)2 form OH- ions in water?

Answers

Ca(OH)2 dissociates in water.
NH3 makes NH4 and OH via acid base equilibrium

The formula for the illegal drug cocaine is c17h21no4 (303.39 g/mol). what is the percentage of hydrogen in the compound? 21.09% 4.618% 67.30% 6.991% 3.959%

Answers

molar mass is the sum of the products of molar masses of individual elements by the number of atoms of the element in the compound.
molar mass of H - 1.01 g
number of H atoms - 21 H atoms 
therefore mass of H in 1 mol of compound - 1.01 g x 21 = 21.21 g
the molar mass of the compound - 303.39 g/mol 
H composition percentage = [tex] \frac{mass of H in 1 mol}{molar mass of compound} *100%[/tex]
            composition percentage = 21.21 g/mol /303.39 g/mol x 100%
H composition percentage = 6.991 %

therefore answer is 6.99 %

Write out the balanced equation for the reaction that occurs when Mg(OH)2 and HCl react together.

Answers

Mg(OH)2 + HCl —> H2O + MgCl2

Answer:

The balanced equation for the reaction that occurs when Mg(OH)2 and HCl react together is:

Mg(OH)2+2HCl -------->MgCl2+2H20

How many moles of gas occupy 98 l at a pressure of 2.8 atmospheres and a temperature of 292 k?

Answers

From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n =[tex] \frac{PV}{RT} [/tex] = [tex] \frac{2.8 X 98}{0.082 X 292} [/tex] = 11.46

"11.46" moles of gas occupy 98 L at 2.8 atm pressure.

Ideal gas equation:

The equation characterizing the stages of hypothetical gasses stated mathematically involving combinations of empirical as well as physiological constants, is considered as Ideal gas equation.

According to the question,

Volume occupied, V = 98

Temperature, T = 292 k

Pressure, P = 2.8 atm

By using ideal gas equation, we get

→ PV = nRT

or,

→ n = [tex]\frac{PV}{RT}[/tex]

By substituting the above values, we get

      = [tex]\frac{2.8\times 98}{0.082\times 292}[/tex]

      = [tex]\frac{274.4}{23.944}[/tex]

      = [tex]11.46[/tex]

Thus the above answer is appropriate.

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https://brainly.com/question/12873752

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