You must keep track of some data. Your options are: (1) A linked-list maintained in sorted order. (2) A linked-list of unsorted records. (3) A binary search tree. (4) An array-based list maintained in sorted order. (5) An array-based list of unsorted records

Answer:

See explaination

Explanation:

Critical path method (CPM) is a step-by-step process by which critical and non-critical tasks are defined so that time-frame problems and process bottlenecks are prevented.

please see attachment for the step by step solution of the given problem.

Answer:

Option B - Enhanced Checking Account

Explanation:

Enhanced Checking Account as this class overrides the get interest Rate

Answer:

See Explaination

Explanation:

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

float input1, input2, input3;

float sum=0.0, avg, l;

cout<<"enter the value for input1: ";

cin>>input1;

cout<<"enter the value for input2: ";

cin>>input2;

cout<<"enter the value for input3: ";

cin>>input3;

sum=input1+input2+input3;

cout<<"sum of three numbers: "<<sum<<endl;

avg=sum/3;

cout<<"average of three numbers: "<<avg<<endl;

l=log2(input1);

cout<<"log2 value of input1 number: "<<l;

return 0;

}

output:

enter the value for input1: 4

enter the value for input2: 5

enter the value for input3: 6

sum of three numbers: 15

average of three numbers: 5

log2 value of input1 number: 2

Answer:

// Scanner class is imported

import java.util.Scanner;

// InputExample class to hold the program

public class InputExample {

// main method to begin program execution

public static void main(String args[]) {

// Scanner object scnr is created

Scanner scnr = new Scanner(System.in);

// variable birthMonth is declared

int birthMonth;

// variable birthYear is declared

int birthYear;

// birthMonth is initialized to 1

birthMonth = 1;

// birthYear is initialized to 2000

birthYear = 2000;

// birthday is displayed

System.out.println("1/2000");

// prompt is displayed asking user to enter birthMonth

System.out.println("Enter birthMonth:");

// birthMonth is received using Scanner object

birthMonth = scnr.nextInt();

// prompt is displayed asking user to enter birthYear

System.out.println("Enter birthYear:");

// birthYear is received using Scanner object

birthYear = scnr.nextInt();

// the birthday format is displayed

System.out.println(birthMonth + "/" + birthYear);

}

}

Explanation:

The program is written in Java as required and it is well commented.

An image depicting the full question is attached.

Answer:

def sumSquares(num):

   if (num == 0):

       return 0

   else:

       return num*num + sumSquares(num-1)

print(sumSquares(7))

Explanation:

* The code is in Python

The function takes one parameter num. If the num is equal to 0, that means function checked all the numbers up until num, and stops.

If the num is not equal to 0, the function will calculate the square of the number. It multiplies the num with num, adds this multiplication to result of the   same function with a parameter that is decreased by 1.

For example, if num is equal to 3 initially, following will happen:

first iteration: sumSquares(3) =  3x3 + sumSquares(2)  

second iteration: sumSquares(2) =  2x2 + sumSquares(1)

third iteration: sumSquares(1) =  1x1   + sumSquares(0)

forth iteration : sumSquares(0) = 0

If you go from bottom to top,

We know that sumSquares(0) is equal to 0, that means the result of the third iteration is 1, 1 + 0

We know that sumSquares(1) is equal to 1, that means the result of the third iteration is 5, 4 + 1

We know that sumSquares(2) is equal to 5, that means the result of the third iteration is 14, 9 + 5

Answer:

Acknowledgement number

Explanation:

The Acknowledgement number field provides the next expected segment.

TCP packets can contain an acknowledgement, which is the sequence number of the next byte the sender expects to receive this also is an acknowledgement of receiving all bytes prior to that.

Answer:

3

Explanation:

= 1 + (int) (4*(63 - 51)/(71-51)))

= 1 + (int) (4*12/20)

= 1 + (int) (48/20)

= 1 + (int)2.4

= 1 + 2

= 3

Answer:

Duty cycle of a signal measures the fraction of a  time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.

Duty cycle = 15 %

frequency =  13.3Mhz = 13.3 x 10^3 hz = I/T = F

T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s

Duty cycle = pulse duration/ period

15 % = PD/7.5188 x 10 ^-5 s

PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s

INTERPRETATION OF RESULTS

With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver

Explanation:

Duty cycle of a signal measures the fraction of a  time of a given transmitter is transmitting that signal. This fraction of a time determines the overall or total power transmitted or delivered by that signal.

Duty cycle = 15 %

frequency =  13.3Mhz = 13.3 x 10^3 hz = I/T = F

T = period = 1 / F = 1/13.3 x 10^3 hz= 7.5188 x 10 ^-5 s

Duty cycle = pulse duration/ period

15 % = PD/7.5188 x 10 ^-5 s

PD = 15/100 X 7.5188 x 10 ^-5 s = 1.12782 x 10^ -5 s

INTERPRETATION OF RESULTS

With a duty of 15 % and pulse duration of 1.12782 x 10^ -5 s, the strength is low , short signal and less reliable and needs more efficient receiver

Answer:

(a) Q = (M-(1-n)S)/n

(b)    

When M = 450,

       Q = 82

       % CPU time wasted = 8.889%

When M = 90,

       Q = 10

       % CPU time wasted = 44.44%

When M = 50,

       Q = 2

       % CPU time wasted = 80%

Explanation:

Given  Data:

n = process

T = ms time

Context switch time overhead = S

and M is total overhead

See attached file for the calculation.

Final answer:

To determine the appropriate quantum size Q in a CPU time-sharing system with n processes and context-switching overhead S, one must calculate Q in relation to the maximum allowed gap M between quanta. This will enable scheduling that satisfies the gap constraint and maximizes CPU efficiency. The waste percentage of CPU time due to context switching can then be calculated.

Explanation:

The question involves calculating the appropriate quantum size for CPU time-sharing and the related context switching overhead. Given are the number of processes (n), context switching overhead (S), and the maximum allowed gap (M) between quanta. The quantum size (Q) must be chosen to ensure that a process resumes its next quantum within the specified maximum allowed gap after its last quantum ends, considering the context switching overhead.

For part (a), a general formula must be determined that takes into account S and M to calculate Q. For part (b), the formula will be applied with fixed values of n = 5, S = 10 ms, and varying values for M. Having M = 450, 90, 50 ms, the respective Qs will be calculated. Then, the percentage of CPU time wasted on context switching will be determined using the formula:

Percent CPU time wasted = (
( n * S ) / ( n * ( Q + S ) )
) * 100%

Lastly, the results will highlight how the quantum size influences the efficiency of the system by reducing the relative amount of time spent on context switching.

Answer:

The answer is "True"

Explanation:

In the given question some information is missing, that is an option "true or false", which can be described as follows:

It displays the format string properties, which helps them build and update equations. In the second here are examples of what Linux Excel's equation bars, in this two-button, are used, which can be described as follows:

Answer: A. It’s a robust way to find information

Explanation:

Hope this help.

Answer:

A. It is a robust way to find information

Explanation:

eh

Answer:

a. Clock Speed of Processor = 0.5 GHz

b. Cycles per Instruction (CPI) = 1 Clock per Instruction

c. Throughput = 1 billion Instruction per Second

Explanation

Given Data

Time Take to complete the single Cycle = 2000ps = 2000 x 10⁻¹²

To Find

a. Clock Speed of Processor = ?

b. Cycles per Instruction (CPI) = ?

c. Throughput = ?

Solution:

a. Clock Speed of Processor = ?

Clock Speed = 1/Time to complete the cycle

                      = 1/2000 x 10⁻¹²  Hz

                      =  0.0005 x 10¹²  Hz

                      =  0.5 x 10⁹  Hz                             as   10⁹ = 1 Giga   so,

                      = 0.5 GHz

b. Cycles per Instruction (CPI) = ?

It is mentioned that, each instruction should start at the start of the new cycle and completely processed at the end of that cycle so, we can say that Cycles per Instruction (CPI) = 1

for above mentioned processor.

c. Throughput = ?

Throughput = CPI x Clock Speed

where

CPI = 1 cycle per instruction

Clock Speed = 1 billion Instructions per Second

as

Clock Speed = 1 billion Cycles per Second

Throughput = 1 cycle per instruction x 1 billion Cycles per Second

Throughput = 1 billion Instruction per Second

Answer:

Packets

Explanation:

Answer:

The answer is "180,000, 6, and  90"

Explanation:

The answer to this question can be described as follows:

[tex]\ force = 12,000 \ lb \\\\\ distance = 15 \ ft \\\\ \ Formula : \\\\ \ total \ work = force \times distance \\\\ \ IMA = \frac{load}{effort} \\\\\ OR \\\\ \ IMA = \frac{\ distance \ move \ by \ load }{\ distance \ moved \ by \ efforts}[/tex]

[tex]a ) \\\\\ total \ work = 12,000 \times 15 \\\\\ total \ work = 180,000 ft \cdot lbf[/tex]

[tex]b) \\\\IMA = \frac{12000}{2000} = 6 \\\\ c) \\\\IMA = \frac{Y}{15} \\\\6= \frac{Y}{15}\\\\Y= 90\\\\X = \sqrt{8100-225}\\\\X = \sqrt{90^2-15^2} \\\\X= \sqrt{7875} \\\\X =88.74 ft\\\\[/tex]

by comparing the length of the ramp is 90 ft.

Answer:

See explaination for the details of the answer.

Explanation:

A class is a structured diagram that describes the structure of the system.

It consists of class name, attributes, methods and responsibilities.

A mailbox and an email message has some certain attributes such as, compose, reply, draft, inbox, etc.

See attachment for the Model object classes that might be used in the system implementation to represent a mailbox and an email message.

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class sort {

static void lowestToHighest(float arr[][])

{

float temp;

for(int i=0;i<11;i++)

for(int j=0;j<12-i-1;j++) //Using bubble sort to sort

{

if(arr[j][0]>arr[j+1][0])

{

temp = arr[j][0];

arr[j][0] = arr[j+1][0];

arr[j+1][0] = temp;

}

}

for(int i=0;i<11;i++) //Using bubble sort to sort

{

for(int j=0;j<12-i-1;j++)

if(arr[j][1]>arr[j+1][1])

{

temp = arr[j][1];

arr[j][1] = arr[j+1][1];

arr[j+1][1] = temp;

}

}

System.out.println("Data in the array after sorting lowest to highest: ");

for(int i=0;i<12;i++)

System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");

}

static void highestToLowest(float arr[][])

{

float temp;

for(int i=0;i<11;i++)

for(int j=0;j<12-i-1;j++) //Using bubble sort to sort

{

if(arr[j][0]<arr[j+1][0])

{

temp = arr[j][0];

arr[j][0] = arr[j+1][0];

arr[j+1][0] = temp;

}

}

for(int i=0;i<11;i++) //Using bubble sort to sort

{

for(int j=0;j<12-i-1;j++)

if(arr[j][1]<arr[j+1][1])

{

temp = arr[j][1];

arr[j][1] = arr[j+1][1];

arr[j+1][1] = temp;

}

}

System.out.println("Data in the array after sorting highest to lowest: ");

for(int i=0;i<12;i++)

System.out.printf(arr[i][0]+" "+arr[i][1]+"\n");

}

public static void main(String[] args){

float temperature[][]=new float[12][2];

Scanner input = new Scanner(System.in);

System.out.println("Enter 12 months of highest and lowest temperatures for each month of the year: ");

for(int i=0;i<12;i++)

for(int j=0;j<2;j++)

temperature[i][j]=input.nextFloat();

System.out.println("Data in the array: ");

for(int i=0;i<12;i++)

System.out.printf(temperature[i][0]+" "+temperature[i][1]+"\n");

lowestToHighest(temperature);

highestToLowest(temperature);

}

}

Answer:

Check the explanation

Explanation:

Car.java

//class Car

public class Car {

  //private variable declarations

  private int year;

  private double price;

  //getYear method

  public int getYear() {

      return year;

  }

  //setYear method

  public void setYear(int year) throws CarException {

      //check for the year is in the given range

      if(year>=1970&&year<=2011)

          this.year = year;

      //else throw an exception of type CarException

      else

          throw new CarException("Invalid Year");

  }

  //getPrice method

  public double getPrice() {

      return price;

  }

  //setPrice method

  public void setPrice(double price) throws CarException {

      //check for the price is in the given range

      if(price>=0&&price<=100000)

          this.price = price;

      //else throw an exception of type CarException

      else

          throw new CarException("Invalid Price");

  }

  //default constructor to set default values

  public Car(){

      this.year=1970;

      this.price=0;

  }

  //overloaded constructor

  public Car(int year, double price) {

      //check for the year is in the given range

      if(year>=1970&&year<=2011)

          this.year = year;

      //else initialize with default value

      else

          this.year=1970;

      //check for the price is in the given range

      if(price>=0&&price<=100000)

          this.price = price;

      //else initialize with default value

      else

          this.price=0;

  }

  //copy constructor

  public Car(Car c){

      this.year=c.year;

      this.price=c.price;

  }

  //toString method in the given format

  public String toString() {

      return "[Year:" + year + ",Price:" + (int)price + "]";

  }

  //finalize method

  public void finalize(){

      System.out.println("The finalize method called.");

  }

  public static void main(String args[]) throws CarException{

      Car a=new Car();

      System.out.println(a.toString());

      Car b=new Car(1986,25000.98);

      System.out.println(b.toString());

      Car c=new Car();

      c.setYear(1900);

      c.setPrice(23000);

      System.out.println(c.toString());

      Car d=new Car();

      d.setYear(2000);

      d.setPrice(320000);

      System.out.println(d.toString());

  }

}

CarException.java

//exception class declaration

public class CarException extends Exception{

  //private variable declaration

  private String message;

  //constructor

  public CarException(String message) {

      super();

      this.message = message;

  }

  //return error message

  public String getMessage(){

      return message;

  }

}

BookLibrary, that creates a library (array) of up to 10 books. If the user selects the add option, issue an error message if the library is full.If the book with that title exists, issue an error message

Explanation:

import java.util.Scanner;

import java.util.Arrays;

public class Derro_BooksLibrary {

public static void main(String[] args) {

 Derro_Books[] Library = new Derro_Books[10];

 Scanner scan = new Scanner(System.in);

 Derro_Books book1 = new Derro_Books("", 20);

 Derro_Books book2 = new Derro_Books("hi", 10);

 Library[0] = book1;

 Library[1] = book2;

 System.out.println("Enter 1 for add, 2 for delete, 3 for change, 4 to stop application: ");

 int answer = scan.nextInt();

 int counter = 0;

 int z = 0;

 while (true) {

  if (answer == 1) {

   for (Derro_Books book : Library) {

    counter = counter + 1;

   }

   if (counter == 10) {

    System.out.println("Library full");

   }

   System.out.println("Enter Title: ");

   String title = scan.nextLine();

   for (int i = 0; i < Library.length; i++) {

    if (title == Library[i].getTitle()) {

     System.out.println("No Duplicated Books Titles Are Allowed");

     break;

    }

    else {

     z++;

    }

   }

   if (z < Library.length) {

   System.out.println("Enter number of pages: ");

   int pages = scan.nextInt();

   Library[z + 1] = new Derro_Books(title, pages);

  }

  if (answer == 2){

   if (Library.length == 0) {

    System.out.println("Library is empty");

   }

   System.out.println("Enter title of book: ");

   String title2 = scan.nextLine();

   for (int d = 0; d < Library.length; d++) {

    if (title2 == Library[d].getTitle())

     // Delete book

     System.out.println("Deleted book: " + title2);

    else

     System.out.println("Book does not exist");

   }

  }

  if (answer == 3) {

   if (Library.length == 0) {

    System.out.println("Library is empty.");

   } else {

    System.out.println("Enter book title: ");

    String title3 = scan.nextLine();

    for (int y = 0; y < Library.length; y++) {

     if (title3 != Library[y].getTitle())

      continue;

     else {

      System.out.println("Enter number of pages: ");

      int pages = scan.nextInt();

      Library[y] = new Derro_Books(title3, pages);

     }

    }

   }

  }

  String[] StringList = new String[10];

  for (int y = 0; y < Library.length; y++) {

   StringList[y] = Library[y].getTitle();

  }

  Arrays.sort(StringList);

  for (String bookt : StringList) {

   System.out.println(bookt + Library);

  }

 }

}

}

}

Answer:

c) it will always return with an answer of 7 or fewer comparisons of data.

Explanation:

As maximum number of comparison in worst case for sorted binary search is log₂n, here n = 100, so maximum search is at least 6.6 which is approximately 7.

Explanation:

The program that merges two lists or two arrays is written below;

Code :

void main void

{

char [] arr1= {'1','2','3'};

char [] arr2= {'a','b','c','d','e'};

int l1= arr1.length;

int l2=arr2.length;

int l3=l1+l2;

char [] arr3=new char[l1+l2];

int i=0;

int j=0;

int k=0;

int m=0;

int r=0;

if(l1<l2)

   r=l1;

else

   r=l2;

while(m<r)

{

   arr3[k++]=arr1[i++];

   arr3[k++]=arr2[j++];

   m++;

}

while(k<l3)

{

   if(l1<l2)

       arr3[k++]=arr2[j++];

   else

       arr3[k++]=arr1[i++];

}

for(int n=0;n<l3;n++)

{

   System.out.print(arr3[n]+" ");

}

}

Answer:

See explaination for the details.

Explanation:

% Matlab file calculateMirrorMatrix.m

% Matlab function to return a matrix which should be input matrix mirrored

% on the vertical axis

% input is a matrix

% output is a matrix of same size as input matrix

function [mirrorMatrix] = calculateMirrorMatrix(inputMatrix)

mirrorMatrix = zeros(size(inputMatrix)); % create output matrix mirrorMatrix of same size as inputMatrix

fprintf('\n Input Matrix :\n');

disp(inputMatrix); % display the input matrix

[row,col] = size(inputMatrix); % row, col contains number of rows and columns of the inputMatrix

% loop to find the matrix which should be input matrix mirrored

for i = 1:row

mirrorIndex =1;

for j = col:-1:1

mirrorMatrix(i,mirrorIndex)=inputMatrix(i,j);

mirrorIndex=mirrorIndex + 1;

end

end

end

% end of matlab function

Please kindly check attachment for its output.

The function 'mirror_matrix' takes a matrix and returns a new matrix where the columns are reversed. It handles matrices with both odd and even numbers of columns. This solution ensures accurate vertical mirroring of the input matrix.

Mirroring a Matrix on the Vertical Axis

To solve the problem of mirroring a matrix on the vertical axis, we need to create a function that takes an input matrix and outputs a matrix of the same size where the columns are reversed.

Here's a step-by-step explanation:

Here's a sample Python function to achieve this:

For example, an input matrix:

would result in:

This solution ensures that the output matrix is mirrored correctly on the vertical axis.

Answer:

Check the explanation

Explanation:

Coach Kyle is havaing the following data.

Alice 3:15, 2:45, 3:30, 2:27, 3:42

Bob 2:25, 3:15, 3:20, 2:57, 2:42, 3:27

Charlie 2:45, 3:25, 3:50, 2:27, 2:52, 3:12

David 2:15, 3:35, 3:10, 2:47

let us name it as Athlete. txt

now

1. Use a function to read the data from the file.

To read a file, we can use different methods.

file.read( )

If you want to return a string containing all characters in the file, you can

use file. read().

file = open('Athlete. txt', 'r')

print file. read()

Output:

Alice 3:15, 2:45, 3:30, 2:27, 3:42

Bob 2:25, 3:15, 3:20, 2:57, 2:42, 3:27

Charlie 2:45, 3:25, 3:50, 2:27, 2:52, 3:12

David 2:15, 3:35, 3:10, 2:47  

We can also specify how many characters the string should return, by using

file.read(n), where "n" determines number of characters.

This reads the first 5 characters of data and returns it as a string.

file = open('Athlete .txt', 'r')

print file.read(5)

Output:

alice  

file. readline( )  

The readline() function will read from a file line by line (rather than pulling  

the entire file in at once).  

Use readline() when you want to get the first line of the file, subsequent calls  

to readline() will return successive lines.  

Basically, it will read a single line from the file and return a string  

containing characters up to .  

file = open('athlete .txt', 'r')  

print file. readline():  

2.Implement the logic using Dictionary, List, and String:  

One way to create a dictionary is to start with the empty dictionary and add key-value pairs. The empty dictionary is denoted with a pair of curly braces, {}:  

Dictionary operations:  

The del statement removes a key-value pair from a dictionary. For example, the following dictionary contains the names of various fruits and the number of each fruit in stock:  

>>> inventory = {'apples': 430, 'bananas': 312, 'oranges': 525, 'pears': 217}  

>>> print(inventory)  

{'oranges': 525, 'apples': 430, 'pears': 217, 'bananas': 312}  

If someone buys all of the pears, we can remove the entry from the dictionary:  

>>> del inventory['pears']  

>>> print(inventory)  

{'oranges': 525, 'apples': 430, 'bananas': 312}  

Or if we’re expecting more pears soon, we might just change the value associated with pears:  

>>> inventory['pears'] = 0  

>>> print(inventory)  

{'oranges': 525, 'apples': 430, 'pears': 0, 'bananas': 312}  

The len function also works on dictionaries; it returns the number of key-value pairs:  

>>> len(inventory)  

4  

The in operator returns True if the key appears in the dictionary and False otherwise:  

>>> 'pears' in inventory  

True  

>>> 'blueberries' in inventory  

False  

This operator can be very useful, since looking up a non-existant key in a dictionary causes a runtime error:  

>>> inventory['blueberries']  

Traceback (most recent call last):  

File "", line 1, in <module>  

KeyError: 'blueberries'  

>>>  

3. Use maketrans and translate functions to replace commas with spaces  

text = text. translate(string. maketrans("",""), string. punctuation)  

4. Use split function to split the timings into individual elements of a list  

>>> Athlete. split(",")  

split reverses by splitting a string into a multi-element list. Note that the delimiter (“,”) is stripped out completely; it does not appear in any of the elements of the returned list.  

5. Perform necessary calculations to display min, max, and avg timings of each athlete  

_min = None  

_max = None  

_sum = 0  

_len = 0  

with open('Athlete .txt') as  ff:  

for line in ff:  

val = int(line. strip())  

if _min is None or val < _min:  

_min = val  

if _max is None or val > _max:  

_max = val  

_sum += val  

_len += 1  

_avg = float(_sum) / _len  

# Print output  

print("Min: %s" % _min)  

print("Max: %s" % _max)  

print("Avg: %s" % _avg)  

for index, row in enumerate(rows):  

print "In row %s, Avg = %s, Min = %s" % (index, Avg(row), min(row))  

for index, column in enumerate(columns):  

print "In column %s, Avg = %s, Min = %s" % (index, Avg(column), min(column))  

Answer:

minimum number of cores required = 6

Explanation:

Time take by parallelizable code = 24 mins

Reduced time of parallelizable code = 4 mins

Speed gained = 24/4 = 6 times

Therefore minimum number of cores required = 6

Answer:

It really depends - in general every data structure has its use.

Explanation:

Furthermore, traversing the list will be inefficient because the data items are not contiguous in memory, forcing the CPU to jump all over the RAM memory causing further slowdown.

Answer:

JAVA program is given below.

import java.util.Scanner;

public class Main

{

   //static variables declared and initialized as required

   static float deposit1 = 0.10f;

   static float deposit2 = 0.25f;

   static float refund1;

   static float refund2;

   static int num_one_lit;

   static int num_more;

public static void main(String[] args){

    Scanner sc = new Scanner(System.in);

 System.out.print("Enter the number of containers of 1 liter or less: ");

 num_one_lit = sc.nextInt();

 System.out.print("Enter the number of containers of more than 1 liter: ");

 num_more = sc.nextInt();

 //refund computed based on user input

 refund1 = num_one_lit*deposit1;

 refund2 = num_more*deposit2;

 //displaying refund

 System.out.printf("Total refund amount for containers of 1 liter or less is $%.2f %n", refund1);

 System.out.printf("Total refund amount for containers of more than 1 liter is $%.2f %n", refund2);

}

}

OUTPUT

Enter the number of containers of 1 liter or less: 5

Enter the number of containers of more than 1 liter: 2

Total refund amount for containers of 1 liter or less is $0.50  

Total refund amount for containers of more than 1 liter is $0.50

Explanation:

1. Variables are declared at class level hence declared as static.

2. Variables holding deposit also initialized with the given values.

3. User input is taken for the number of containers in both categories.

4. The total value of refund is computed using the given values and user entered values.

5. The total refund is displayed to the user for both categories.

6. To display two decimal places always, variables to hold deposit and refund are declared as float.

7. The keywords used for decimals are %.2f %n. The %.2f keyword indicates two decimal places to be displayed in float variable, %n indicates a numeric value is to be displayed.

8. The printf() method is used to display the formatted output for refund amount.

9. The keywords used to display the formatted output is derived from C language.

10. All the code is written inside class and execution begins from the main() method.

Answer:

The correct answer to the following question will be "Worms".

Explanation:

Worms represent malicious programs that repeatedly render variations of themselves on a shared drive, networking shares respectively. The worm's aim is to replicate itself over and over again.

Answer:

Following are the program to this question:

import java.util.*; //import package

public class Main //defining class

{

 public static void main(String[] args) //defining main method

 {

   int testedEmployee; //defining integer variable

   for(int i = 1;i<=52;i++) //defining loop that counts from 1 to 52  

   {

     testedEmployee = 1 + (int) (Math.random() * 30); //using random method that calculate and hold value

     System.out.print(testedEmployee+"\t"); //print value

     if(i%4 == 0)//defining codition thats checks value is divisiable by 4  

     {

       System.out.println(); //print space

     }

   }

 }

}

Output:

please find the attachment.

Explanation:

In the given java program, a class Main is declared, inside the class, the main method is declared, in which an integer variable "testedEmployee", is declared, in the next line, the loop is declared, that can be described as follows:

Answer:

public class Lab10

{

//Constants

private final static String NAME = "John Terry"; // replace YOUR NAME with your name

private final static int STUID = 123456789;

private final static double GPA1 = 4.00;

private final static double GPA2 = 2.34;

//main method

public static void main (String[] args)

{

Student stu1;

stu1 = new Student(NAME, STUID, GPA1);

System.out.println("\nName: " + stu1.getName());

System.out.println("Id Number: " + stu1.getIdNum());

System.out.println("GPA : " + stu1.getGPA());

stu1.setGPA(GPA2);

System.out.println(stu1 + "\n");

// Create a second student object

// With a name of Trine Thunder, a

// gpa of 4.00, and a student Id of

// 000000001

// You do not need to declare these at final constants,

// but you can if you want to.

System.out.println("\nName: Trine Thunder" );

System.out.println("Id Number: 000000001");

System.out.println("GPA : 4.00");

Student stu2 = new Student("Trine Thunder",000000001, 4.00 );

// [Add code here]

// Print out this student similar to above.

// You do not need to reset the gpa of this student.

System.out.println(stu2 + "\n");

// [Add code here]

// Check if both objects are same using == and .equals() methods.

// Print the message in both cases, whether same or not as shown in sample output.

System.out.println("Using ==");

if(stu1 == stu2){

System.out.println("Both are same");

}

else{

System.out.println("Both are different");

}

stu1.equals(stu2);

// [Add code here]

} // end of main

} // end of class Lab10

// Name:

// Section:

// Lab 10

// CS1113

// Fall 2016

// Class : Student.java

public class Student

{

//class variables

private String name;

private int idNum;

private double gpa;

// Constructor

public Student(String namePar, int idNumPar, double gpaPar)

{

// Save namePar to class variable name

name = namePar;

// [Add code here]

idNum = idNumPar;

// Save idNumPar to class variable idNum

gpa = gpaPar ;

// [Add code here]

// Save gpaPar to class variable gpa

// [Add code here]

}

// Accessor: returns name of student

public String getName()

{

// Return the name of the student

return name;

// [Add code here]

}

// Accessor: returns GPA of student

public double getGPA()

{

// Return the gpa of the student

return gpa;

// [Add code here]

}

// Accessor: returns idNum of student

public int getIdNum()

{

// Return the idnum of the Student

return idNum;

// [Add code here]

}

// Mutator: Changes the GPA of the student

public void setGPA(double g)

{

// Set the class variable gpa equal to g

gpa = g;

// [Add code here]

}

// toString method: Returns a formatted string

// of student information.

// As shown in sample output.

public String toString()

{

// declare a String variable to store the string value

// then return the formatted String.

String s ="";

s = s + "Student Name: "+name+"\n";

s =s + "Student Id num: "+idNum+"\n";

s =s + "Student GPA: "+gpa+"\n";

return s;

// [Add code here]

}

// implement .equals() method which returns a boolean value

// of student information. When you call this method,

// it should print message as shown in sample output.

public boolean equals(Student s)

{

//[Add code here]

System.out.println("Using .equals() method");

if(this.equals(s.idNum == this.idNum)){

System.out.println("Both are same");

return true;

}

else{

System.out.println("Both are different");

return false;

}

}

} // end of class Student

Explanation:

Output:

Name: John Terry

Id Number: 123456789

GPA : 4.0

Student Name: John Terry

Student Id num: 123456789

Student GPA: 2.34

Name: Trine Thunder

Id Number: 000000001

GPA : 4.00

Student Name: Trine Thunder

Student Id num: 1

Student GPA: 4.0

Using ==

Both are different

Using .equals() method

Both are different

Answer:

Check the explanation

Explanation:

use `my_guitar_shop`;

#delete the procedure test if it exists.

DROP PROCEDURE IF EXISTS test;

DELIMITER //

CREATE PROCEDURE test ()

BEGIN

   #declare variable sqlerr to store if there is an sql exception

  declare sqlerr tinyint default false;

   #declare variable handler to flag when duplicate value is inserted

  declare continue handler for 1062 set sqlerr = TRUE;

   #start transaction

   start transaction;

  delete from order_items where order_id in

      (select order_id from orders where customer_id=6);

  delete from orders where customer_id=6;

  delete from addresses where customer_id=6;

  delete from customers where customer_id=6;

   if sqlerr=FALSE then

      commit;

        select 'Transaction Committed' as msg;

  else

       rollback;

       select 'Transaction rollbacked' as msg;

   end if;

end //

delimiter ;

call test();