Answer:
Decrease
Explanation:
If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :
"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."
Final answer:
When moving toward the edge of a spinning turntable, the rate of rotation decreases due to the principle of conservation of angular momentum, which necessitates a decrease in angular velocity to compensate for an increased moment of inertia.
Explanation:
When you crawl toward the edge of a large turntable at an amusement park while it is spinning, the rate of the rotation decreases. This phenomenon is explained by the principle of conservation of angular momentum, which states that if no external torque acts on a system, the total angular momentum of the system remains constant.
Angular momentum is given by the product of the moment of inertia (I) and the angular velocity (ω), represented by the equation L = Iω. As you move away from the axis of rotation, your moment of inertia increases because the moment of inertia is directly proportional to the square of the distance from the axis of rotation. In order to conserve angular momentum, if the moment of inertia increases, the angular velocity must decrease accordingly.
Which of these statements explains the difference between nuclear binding energy and the strong nuclear force? Check all that apply.
A) Nuclear binding energy holds the nuclear particles together
B) Nuclear binding energy is the energy needed to separate nuclear particles.
C) The strong nuclear force holds an atom’s protons and neutrons together.
D) The strong nuclear force is the energy released during radioactive decay processes.
E) The strong nuclear force is directly responsible for radioactive decay.
F) Nuclear binding energy can be calculated using E = mc^2.
Answer:
B, C, F
Explanation:
Final answer:
Nuclear binding energy is the energy required to separate the particles of a nucleus, while the strong nuclear force is the force that keeps protons and neutrons together within the nucleus. The binding energy can be calculated using E = mc², and the strong nuclear force operates over extremely short distances within an atomic nucleus.
Explanation:
The difference between nuclear binding energy and the strong nuclear force has to do with their functions and properties within an atom. Nuclear binding energy is the energy needed to separate nuclear particles. To calculate this energy, we can use Einstein's famous equation E = mc², where E represents the energy, m represents the mass defect, and c represents the speed of light. This energy is what holds the nucleus together and, when released, often accompanies nuclear reactions such as fusion or fission.
On the other hand, the strong nuclear force is an attractive force that keeps protons and neutrons in the nucleus bound together. This force operates over very short distances, only effective within the realm of the atomic nucleus. It is not the energy itself but the force that counteracts the highly repulsive Coulomb force between protons, ensuring that the nucleus remains stable.
Thus, the correct statements explaining the difference between nuclear binding energy and the strong nuclear force are:
B) Nuclear binding energy is the energy needed to separate nuclear particles.C) The strong nuclear force holds an atom's protons and neutrons together.F) Nuclear binding energy can be calculated using E = mc².A mass of 230 g, hanging on a spring, vertically oscillates with a period of 1 sec (the spring itself has no mass). After adding a mass, m, to the 230 g, we find that the period of oscillation of this mass-spring system becomes 2 sec. The value of m is equal to________.
Answer:
The added mass m= 0.7kg
Explanation:
This problem bothers on the simple harmonic motion of a spiral spring
We know that the period of a simple harmonic motion of a spring is given as
T=2π√m/k
We need to solve first for the spring constant k
Given data
Mass m =230g - - - - - kg
=230/1000= 0.230kg
Period T = 1sec
Substituting we have
1= 2*3.142√0.230/k
1=6.284√0.230/k
1/6.284=√0.230/k
Square both sides
(0.159)²=0.230/k
0.025=0.230/k
k=0.230/0.025
k= 9.2N/m
Now we find that the period of oscillation is 2 after adding mass m to 230g.. Let's solve for the new mass
Using the formula for the period T=2π√m/k
2=2*3.142√m/9.2
2=6.284√m/9.2
2/6.284=√m/9.2
Square both sides
(0.318)²=m/9.2
0.10=m/9.2
m= 0.930kg
Therefore the added mass is
0.930kg-0.230kg
The added mass m= 0.7kg
A person produces two sound waves with a flute one immediately after the other. Both sound waves have the same pitch, but the second one is louder. Which of the following properties is greater for the second sound wave?
A) Frequency
B) Amplitude
C) Wavelength
D) Speed in air
Answer:
Option B is the right choice.
Explanation:
Given:
Two sounds waves lets say [tex]S_1[/tex] and [tex]S_2[/tex] having same pitch but
We have to find the property which from the options and identify which one is greater for [tex]S_2[/tex] .
Lets take one and one analysis of the terms.
a.
Frequency :
It is how fast the sound wave is oscillating. Frequency is [tex]f=\frac{1}{T}[/tex] hertz. The faster the sound wave oscillates the higher pitch it will have.According to the question the pitch is same so the frequency will be same for both the waves.
b.
Amplitude :
The loudness of the sound increases with an increase in the amplitude of sound waves.It is the maximum amount of displacement of a particle on the medium from its rest position.c.
Wavelength :
Distance between two consecutive crest (high) or trough (low) is called wavelength.Shorter wavelength will have higher frequency.Here the frequency is same so the wavelength for [tex]S_1,S_2[/tex] will be same.
d.
Speed in air:
Speed of sound in a same medium is usually same.Speed of sound in air is 343 m/s.So,
Amplitude of [tex]S_2 > S_1[/tex] .
Here the amplitude of the louder sound wave will be greater .
You and your family are driving to your grandparents’ house, which is 185 km away. If you drive at an average speed of 95 km/h, how long will it take you to get there?
Answer:
Why don't you search for the formula, this one is really basic. The answer is below
Explanation: The formula t= d/s or d= st or s= d/t in this problem we use:
t = d/s
t is time
d is distance and s is speed
so just plug in the data which are given in the question,
185 km is the distance,d
95 km/h is the speed, s
It tell you to calculate how long means t= 185/95 ≈ 1.947 or 2 hours
Final answer:
To calculate the time it will take to drive 185 km at an average speed of 95 km/h, you divide the distance by the speed to get approximately 1 hour and 57 minutes.
Explanation:
The question asks us to calculate the time it will take to travel to your grandparents' house at a constant speed. This is a classic speed, distance, and time problem that can be solved using the formula: time = distance \/ average speed. To find the time it will take to reach the grandparents' house, we divide the distance by the average speed.
Step-by-Step Calculation:
Distance to grandparents' house = 185 km.
Average speed = 95 km/h.
Time = Distance \/ Average Speed = 185 km \/ 95 km/h.
Time = 1.9474 hours.
To convert hours to minutes, we multiply by 60 (since each hour has 60 minutes).
Time = 1.9474 hours × 60 minutes/hour = 116.842 minutes, which is approximately 1 hour and 57 minutes.
Therefore, it will take nearly 1 hour and 57 minutes to get to your grandparents' house if you drive at an average speed of 95 km/h.
It requires energy to bring two identical positive charges together. As these charges are brought closer together, the electrical potential energy will
Answer:
it increases
Explanation:
It requires energy to bring two identical, similar positive charges together. As the charges come closer, the electrical potential energy will increase.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship among different components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the floor as opposed to falling to the ground, it has more potential energy. It is capable of carrying out additional work when raised.
Potential energy is a feature of systems rather than of particular bodies or particles; for instance, the system created up of Earth and the elevated ball has more energy stored as they become further apart.
Potential energy develops in systems components whose configurations, or spatial arrangement, determine the amount of the forces they apply to one another.
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Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, (d) 2.00 s, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 14.0 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70.0 m above the water.
Answer:
a) 8.25 m and 19 m/s
b) 19 m and 24 m/s
c) 32.25 m and 29 m/s
d) 48 m and 34 m/s
e) 66.25 m and 39 m/s
Explanation:
Let gravitational constant g = 10m/s2
Formula for displacement: [tex]s = v_0t + gt^2/2 = 14t + 10t^2/2 = 14t + 5t^2[/tex]
Formula for velocity: v = v_0 + gt = 14 + 10t
a) at t = 0.5s
[tex]s = 14*0.5 + 5*0.5^2 = 7 + 1.25 = 8.25 m[/tex]
v = 14 + 10*0.5 = 14 + 5 = 19 m/s[/tex]
b) at t = 1s
[tex]s = 14*1 + 5*1^2 = 19 m[/tex]
v = 14 + 10*1 = 24 m/s
c) at t = 1.5 s
[tex]s = 14*1.5 + 5*1.5^2 = 21 + 11.25 = 32.25 m[/tex]
v = 14 + 10*1.5 = 29 m/s
d) at t = 2s
[tex]s = 14*2 + 5*2^2 = 28 + 20 = 48 m[/tex]
v = 14 + 10*2 = 34 m/s
e) at t = 2.5s
[tex]s = 14*2.5 + 5*2.5^2 = 35 + 31.25 = 66.25 m[/tex]
v = 14 + 10*2.5 = 39 m/s
Complete the following sentence: The operation of a hydraulic jack is an application of a) Archimedesâ principle. b) Bernoulli's principle. c) Pascal's principle. d) the continuity equation. e) irrotational flow.
Answer:
a) archimedes principle
The operation of a hydraulic jack is an application of Pascal's principle. Hence, option (c) is correct.
What is Pascal's principle?Pascal's principle in fluid mechanics asserts that a pressure change in one component of a fluid at rest in a closed container is transferred without loss to every portion of the fluid and to the container walls.
The force multiplied by the surface area on which it acts produces pressure. Pascal's principle states that a pressure rise on one piston in a hydraulic system causes an equivalent increase in pressure on another piston in the system.
Even though the pressure on the second piston is the same as that on the first piston, the force acting on it is 10 times more if its area is 10 times greater than the first piston's.
The hydraulic press, which is based on Pascal's concept and is employed in systems like hydraulic jacks , is a good example of this effect.
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As a wave moves through a medium at a speed v, the particles of the medium move in simple harmonic motion about their undisturbed positions. The maximum speed of the simple harmonic motion is vmax. When the amplitude of the wave doubles, __________________
Answer:
1) The velocity remain the same
2) the frequency remains the same
3) the energy increases by four times.
A light year is approximately 9.5 million km long. 'Barnard's Star' is 6 light years away from Earth. Calculate how many millions of kilometres this is.
Final answer:
Barnard's Star is approximately 56.76 trillion kilometers away from Earth, which is calculated by multiplying the distance of one light-year (9.46 × 10¹² kilometers) by 6 light-years.
Explanation:
To calculate the distance from Earth to Barnard's Star in millions of kilometers, we need to multiply the distance of one light-year in kilometers by the number of light-years Barnard's Star is from Earth. One light-year is equal to approximately 9.46 × 10¹² kilometers. Since Barnard's Star is 6 light years away, we multiply 9.46 × 10¹² kilometers by 6 to get the distance.
9.46 × 10¹² kilometers/light-year × 6 light-years = 56.76 × 10¹² kilometers
Therefore, Barnard's Star is approximately 56.76 trillion kilometers away from Earth, which can also be written as 56,760 million kilometers.
Other things being equal, which would be easier? a. To drive at high speed around an unbanked horizontal curve on the moon. b. To drive at high speed around an unbanked horizontal curve on the earth. c. Neither would be easier because there's no difference.
Answer:
To drive at high speed around an unbanked horizontal curve on the earth.
Explanation:
Garvitational pull on on eart is 6 times more than on the moon. On. Earth, the vehicle will have more grip on the surface due to its weight. This grip will reduce its tendency to skid off the horizontal curve when compared to driving in the same unbanked horizontal curve on the moon.
Final answer:
Driving at high speed around an unbanked horizontal curve would be easier on Earth compared to the moon, because Earth's greater gravity provides a higher force of static friction, reducing the risk of slipping at high speeds.
Explanation:
When deciding whether it would be easier to drive at high speed around an unbanked horizontal curve on the moon or the earth, with other things being equal, we need to consider the force of static friction and the acceleration required to maintain uniform circular motion. The acceleration in question is given by the equation |a| = |v|²/r, where |a| is the magnitude of acceleration, |v| is the speed of the car, and r is the radius of the circular path.
On the moon, due to its lower gravity, the force of static friction is less than it is on earth. Despite that, it would be more challenging to drive at high speed on the moon because a lower force of static friction means a lower threshold for slipping. On earth, the higher gravity increases the maximum force of static friction, allowing for a presumably safer high-speed turn, assuming no additional adverse conditions like rain or mud. Therefore, b. To drive at high speed around an unbanked horizontal curve on the earth would be easier for the given scenario.
Calculate the force of a particle with a net charge of 170 coulombs traveling at a speed of 135 meters/second perpendicular to the magnetic field of 5.0 × 10-5 tesla. The magnetic field runs from south to north (as shown below), and the particle is moving from east to west: ↑B ← +q
Answer:
F=1.14N j
Explanation:
The magnitude of the magnetic force over a charge in a constant magnetic field is given by the formula:
[tex]|\vec{F}|=|q\vec{v} \ X\ \vec{B}|=qvsin\theta[/tex] (|)
In this case v and B vectors are perpendicular between them. Furthermore the direction of the magnetic force is:
-i X k = +j
Finally, by replacing in (1) we obtain:
[tex]\vec{F}=(170C)(135\frac{m}{s})(5.0*10^{-5}T)=1.14N\ \hat{j}[/tex]
hope this helps!
Answer:
The force on the particle, F = 1.15 N
Explanation:
Charge, q = 170 Coulombs
speed of the particle, v = 135 m/s
Magnetic field, B = 5 * 10⁻⁵ T
The force is perpendicular to the magnetic field, θ = 90°
The force of the particle is given by the formula,
F = qvBsinθ
F = 170 * 135 * 5 * 10⁻⁵ * sin90°
F =1.15 N
A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a distance d1= 0.850 m to the left of sawhorse B. When the cat is a distance d2= 1.11 m to the right of sawhorse B, the plank just begins to tip.If the cat has a mass of 3.6 kg, how far to the right of sawhorse B can it walk before the plank begins to tip?
In the Physics topic of static equilibrium, this problem finds the distance the cat can walk right from sawhorse B before the plank tips. The calculated distance, 0.56m, is found by setting the torques exerted by the cat and plank equal to each other and solving for the unknown distance.
Explanation:The category of this problem belongs to Physics, specifically in the topic of static equilibrium. In this problem, we want to find out how far right the cat can walk from sawhorse B before the plank begins to tip.
First, realize the plank will begin to tip once the center of mass of the system (plank plus cat) is directly above sawhorse B.
To maintain equilibrium, the torque exerted by the cat must be equal to the torque exerted by the plank, given by Torque = Force x Distance (or) m1d1 = m2d2. The force is the weight of the object.
So we have, M*d1 = (M+m)*d2, here M is the mass of the plank, m is the mass of the cat. By substituting the known values (M=7kg, d1=0.85m, m=3.6kg) and solving for d2:
7*0.85 = (7 + 3.6)*d2, we get d2 = 0.85*7/10.6 ≈ 0.56m (rounded).
So, the cat can walk about 0.56m to the right of sawhorse B before the plank starts to tip.
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The value of 1.65 meters is the maximum distance the cat can walk to the right of sawhorse B before the plank tips.
We need to set up the conditions for static equilibrium and rotational equilibrium.
The plank has mass M = 7.00 kg and its center of mass is located at d₁ = 0.850 m to the left of sawhorse B.
The cat has a mass of 3.6 kg and is initially at a distance d₂ = 1.11 m to the right of sawhorse B where the plank starts to tip.
To find the tipping point, we need the sum of moments about sawhorse B to equate to zero upon tipping.
Rotational equilibrium condition:
Στ = 0 = (M * g * d₁) - ([tex]m_{cat[/tex] * g * d₂)
Where g is the acceleration due to gravity.
Substituting back in the appropriate values, we have:
(7.00 kg * 9.8 m/s² * 0.850 m) = (3.6 kg * 9.8 m/s² * d₂)
Simplifying, (7 * 0.850) = (3.6 * d₂)
Thus,
d2 = (7 * 0.850 / 3.6) = 1.65 m
Therefore, the cat can walk a maximum distance of 1.65 m to the right of sawhorse B before the plank tips.
What happens to the resistance of a filament if it is replaced by a shorter
wire?
Answer:the resistance decrease
Explanation:
How do the values of δg∘ calculated this way compare to those calculated from δh∘ and δs∘? how do the values of calculated this way compare to those calculated from and ? all of the values are compararable. some of the values are compararable. none of the values are compararable?
Answer: all of the values are comparable.
Explanation:
Values calculated by the two methods are comparable. The method using ΔH∘ and ΔS∘ is longer, but it can be used to determine how ΔG∘ changes with temperature.
How many resonance structures does aniline have after the first step of electrophilic aromatic substitution?
Final answer:
After the first step of electrophilic aromatic substitution, aniline has several resonance structures representing the delocalization of the positive charge developed during the reaction. The number of possible structures depends on the attacking electrophile and its position on the ring.
Explanation:
Number of Resonance Structures in Aniline After Electrophilic Aromatic Substitution
After the first step of electrophilic aromatic substitution, aniline, which is a benzene ring with an amino (NH₂) group, can have several resonance structures. This reaction involves the attack of the nucleophilic π-bond of aniline on a cation electrophile (E+), resulting in a very unstable non-aromatic intermediate. This intermediate can be represented by multiple resonance structures, all of which help to delocalize the positive charge that develops on the benzene ring. However, the exact number of resonance structures after the first step varies depending on the electrophile involved and the position it attacks on the benzene ring. Typically, there are fewer resonance structures available for the intermediate compared to the original benzene ring, because the substitution disrupts the complete delocalization of electrons.
How does the gas exchange system in fishes work?
Answer:
Gas exchange in fish is by counter current exchange
Explanation:
The gills located at the pharynx of a fish is a very important respiratory organ.Oxygen and carbon dioxide are the substance of exchange in fishes during respiration.During exchange a fish takes in a needed volume of water through the mouth,then moves it through the gills which aids in repleting oxgen poor water out through various opening and also helps in replenishing the blood capillaries flowing in the opposite direction with oxygen
Answer:
By using countercurrent flow principle of water and blood to exchange oxygen.
Explanation:
Fish use a specialized organ called gills to carry out gas exchange.
Gills have a lot of folds, maximizing their surface area and maximising the efficiency of gas exchange. The gill filaments have protrusions called gill lamellae.
One of the ways in which gas exchange is carried out efficiently is by the countercurrent flow principle, which simply means that water and blood are flowing in different directions. The water that passes over the gill lamellae flows in the opposite direction to the blood within the gill lamellae.
The tropic of cancer is to the tropic of capricorn as the arctic circle is to the
Answer:
Antarctic Circle
Explanation:
The Tropic of Cancer, which is also referred to as the Northern Tropic, is the most northerly circle of latitude on Earth at which the Sun can be directly overhead. This occurs on the June solstice, when the Northern Hemisphere is tilted toward the Sun to its maximum extent.
Tropic of Capricorn Is it Southern Hemisphere counterpart, marking the most southerly position at which the Sun can be directly overhead.
What do the single electrons in nitrogen do for a triple bond?
Nitrogen could form 3 bonds based on octet rule, because it has 5 valence electrons. That means it needs 3 bonds.
Explanation:
A nitrogen atom can fill its octet by sharing three electrons with another nitrogen atom, forming three covalent bonds, a so-called triple bond. A triple bond isn't quite three times as strong as a single bond, but it's a very strong bond.Every covalent bond is a sharing of two electrons between two atoms. A double bond is 4 electrons being shared (2x2). Therefore a triple bond is 6 electrons being shared (2x3)Triple bonds are stronger than double bonds due to the the presence of two pi bonds rather than one. Each carbon has two sp hybrid orbitals, and one of them overlaps with its corresponding one from the other carbon atom to form an sp-sp sigma bond.A single lone pair can be found with atoms in the nitrogen such as nitrogen in ammonia , two lone pairs can be found with atoms in the chalogen group such as oxygen in water and the halogen can carry three lone pairs such as in hydrogen chloride. Nitrogen has 2 lone pairs.Supongamos que Lisa necesita una panaderia más cercana porqye necesita nejorar su tiempo a 80s. A que distancia deberia estar ka panaderia si se mueve a una rapidez de 0.5m/s?
Answer:
40 m
Explanation:
English Translation for the question
Suppose Lisa needs to find a nearby bakery because she needs to improve her time to 80s. How far should the bakery be if she moves at a speed of 0.5m/s?
Speed = (Distance/time)
Speed = 0.5 m/s
Distance = how far away the bakery should be = d = ?
Time = 80 s
0.5 = (d/80)
d = 0.5×80 = 40 m
Hope this Helps!!!
In this Calculating Distance question, Para determinar la distancia a la que debe estar la panadería, podemos utilizar la fórmula de velocidad promedio. Reemplazando los valores conocidos, la panadería debe estar a una distancia de 40 metros.
Para calcular la distancia a la que debería estar la panadería, podemos utilizar la fórmula de velocidad promedio:
Velocidad promedio = Distancia / Tiempo
En este caso, la velocidad es de 0.5 m/s y queremos calcular la distancia. Dado que el tiempo es de 80 segundos (el cual debe convertirse a minutos), podemos reorganizar la fórmula para despejar la distancia:
Distancia = Velocidad promedio x Tiempo
Reemplazando los valores conocidos, tenemos:
Distancia = 0.5 m/s x 80 s = 40 metros
Por lo tanto, la panadería debe estar a una distancia de 40 metros para que Lisa mejore su tiempo a 80s.
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You pull straight up on the string of a yo-yo with a force 0.35 N, and while your hand is moving up a distance 0.16 m, the yo-yo moves down a distance 0.32 m. The mass of the yo-yo is 0.062 kg, and it was initially moving downward with speed 2.9 m/s.(a) What is the increase in the translational kinetic energy of the yo-yo?(b) What is the new speed of the yo-yo?(c) What is the increase in the rotational kinetic energy of the yo-yo?
To solve this problem, we need to analyze the forces and energies involved. The force of 0.35 N applied to the string by your hand is equal to the tension in the string.
Explanation:To solve this problem, we need to analyze the forces and energies involved. The force of 0.35 N applied to the string by your hand is equal to the tension in the string. The work done by this force is given by the formula W = Fd, where W is the work done, F is the force applied, and d is the distance moved in the direction of the force.
Since the yo-yo moves down a distance of 0.32 m while your hand moves up a distance of 0.16 m, the yo-yo has a greater displacement in the direction of the force. Therefore, the work done by your hand on the yo-yo is positive.
The work done on an object is equal to the change in its translational kinetic energy. The increase in translational kinetic energy of the yo-yo can be calculated using the formula ΔKE = W. To find the new speed of the yo-yo, we can use the principle of conservation of energy, which states that the total mechanical energy of a system remains constant. The increase in the rotational kinetic energy of the yo-yo can be calculated using the formula ΔKE_rot = ΔKE - ΔKE_trans.
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A puddle of water has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavelength of light incident on the film is 560 nm and the indices of refraction of gasoline and water are 1.40 and 1.33, respectively, what must be the minimum thickness of the film to see a bright reflection? 100 nm 200 nm 300 nm 400 nm 500 nm
Answer:
option A
Explanation:
Given,
wavelength of light,[tex] \lambda = 560\ nm[/tex]
refractive index of gasoline, n₁ = 1.40
Refractive index of water, n₂ = 1.33
thickness of the film, t = ?
Condition of constructive interference is given by
[tex]2 n t = (m+\dfrac{1}{2})\lambda[/tex]
For minimum thickness of the film m = 0
From the question we can clearly observe that phase change from gasoline to air
so, n = 1.4
[tex]2 \times 1.4 \times t = \dfrac{560}{2}[/tex]
[tex] t = 100\ nm[/tex]
Hence, the correct answer is option A
A spherical mirror has a radius of curvature of -14 cm. What type of mirror could it be?
Answer:
Convex mirror
Explanation:
Using the mirror formula
1/V+1/U=1/F
Were F=r/2
F=-14/2=-7
So 1/V=-1/7-1/U
Since v=image distance
U= object distance
F= local length
It is only convex mirror that have both local length and image distance negative
The center of gravity is defined as: a. The part of the skeleton composed of the bones of the vertebral column, ribs, and skull b. A plane the passes through the midpoint of the body c. State of an object as a result of forces pushing on it d. Imaginary point through which the resultant force of gravity acts on an object
Answer:
the corect answer it b and c
Explanation:
b. the density of lines shows the strength of the force.
c. the arrows on the lines of force show which way a posative object will move.
youre welcome
What is the difference between systolic and diastolic pressure?
Answer:
The difference between the systolic and the diastolic pressure is the pulse
Explanation:
Systolic blood pressure is the top number of the maximum pressure your heart exerts while beating (systolic pressure),
and the bottom number is the amount of pressure in your arteries between beats (diastolic pressure).
The numeric difference between your systolic and diastolic blood pressure is called your pulse pressure.
Hence systolic - diastolic = pulse
Answer:
Pulse pressure
Explanation:
Blood pressure readings are given in two numbers, upper and lower limit.
- The upper limit is the maximum pressure your heart exerts while beating, also called systolic pressure.
- The lower is the amount of pressure in your arteries between beats, also called diastolic pressure.
- The numerical difference between systolic and diastolic pressure is called the pulse pressure.
- For example, if your resting blood pressure is 120/80 millimeters of mercury (mm Hg).
systolic pressure = 120 mm Hg
diastolic pressure = 80 mm Hg
Pulse pressure = 120 - 80 = 40 mm Hg
A coil 4.20 cm radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10−2 T/s )t+( 2.60×10−5 T/s4 )t4. The coil is connected to a 640-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
a)Find the magnitude of the induced emf in the coil as a function of time.
Explanation:
Given that,
Radius of the coil, r = 4.2 cm
Number of turns in the coil, N = 500
The magnetic field as a function of time is given by :
[tex]B=1.2\times 10^{-2}t+2.6\times 10^{-5}t^4[/tex]
Resistance of the coil, R = 640 ohms
We need to find the magnitude of induced emf in the coil as a function of time. It is given by :
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=N\pi r^2\dfrac{-dB}{dt}\\\\\epsilon=N\pi r^2\times \dfrac{-d(1.2\times 10^{-2}t+2.6\times 10^{-5}t^4)}{dt}\\\\\epsilon=N\pi r^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=500\pi \times (4.2\times 10^{-2})^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=2.77(1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\ V[/tex]
Hence, this is the required solution.
Answer:
Explanation:
Radius of the coil, r = 4.2 cm
number of turns, N = 500
resistance in the circuit, R = 640 ohm
The magnetic field is given by
[tex]B=1.2\times 10^{-2}t+2.6\times 10^{-5}t^{4}[/tex]
(a) According to the Faraday's law of electromagnetic induction, the magnitude of induced emf is given by
[tex]e = \frac{d\phi}{dt}[/tex]
magnetic flux, Ф = N x B x A x Cos 0
Ф = N A B
Differentiate both sides
[tex]\frac{d\phi}{dt}=NA\frac{dB}{dt}[/tex]
[tex]\frac{d\phi}{dt}=500\times 3.14 \times 0.042\times 0.042\times \left ( 1.2\times 10^{-2}+4 \times 2.6\times 10^{-5}t^{3}\right )[/tex]
So, the magnitude of induced emf is given by
[tex]e =3.324\times 10^{-2}+28.8 \times 10^{-5}t^{3} V[/tex]
This is the magnitude of induced emf as the function of time.
A 2 kg, frictionless block is attached to a horizontal, ideal spring with spring constant 300 N/m. At t = 0 the spring is neither stretched nor compressed and the block is moving in the negative direction at 12 m/s. (a) Find the amplitude of this oscillation.
Answer:
Explanation:
Given that,
Mass of block
M = 2kg
Spring constant k = 300N/m
Velocity v = 12m/s
At t = 0, the spring is neither stretched nor compressed. Then, it amplitude is zero at t=0
xo = 0
It velocity is 12m/s at t=0
Then, it initial velocity is
Vo = 12m/s
Then, amplitude is given as
A = √[xo + (Vo²/ω²)]
Where
xo is the initial amplitude =0
Vo is the initial velocity =12m/s
ω is the angular frequency and it can be determine using
ω = √(k/m)
Where
k is spring constant = 300N/m
m is the mass of object = 2kg
Then,
ω = √300/2 = √150
ω = 12.25 rad/s²
Then,
A = √[xo + (Vo²/ω²)]
A = √[0 + (12²/12.5²)]
A = √[0 + 0.96]
A = √0.96
A = 0.98m
Now let’s apply the work–energy theorem to a more complex, multistep problem. In a pile driver, a steel hammerhead with mass 200 kg is lifted 3.00 m above the top of a vertical I-beam that is to be driven into the ground (Figure 1) . The hammer is then dropped, driving the I-beam 7.40 cm farther into the ground. The vertical rails that guide the hammerhead exert a constant 60.0 N friction force on it. Use the work–energy theorem to find
(a) the speed of the hammerhead just as it hits the I-beam and
(b) the average force the hammerhead exerts on the I-beam.
The question applies work-energy theorem to find the speed of the hammerhead and the average force. For the speed, we calculate the work done by gravitational and frictional forces. For the average force, we use the work done on the I-beam and the fall distance.
Explanation:To solve this question, we can apply the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.
Let's start with part (a), the speed of the hammerhead just as it hits the I-beam:
To calculate the speed, we need to find the work done on the hammerhead. The work done involves the gravitational force and the frictional force. The work done by the gravitational force is mgh, where m is the mass (200 kg), g is gravity (9.8 m/s^2), and h is the fall height (3.00 m). The work done by the frictional force is -fd, where f is frictional force (60.0 N) and d is the fall distance (3.00 m). By solving these and equating them to change in kinetic energy (1/2 mv^2), we can find the speed v.
For part (b), the average force the hammerhead exerts on the I-beam:
The average force can be dropped by using the work done on the I-beam and the fall distance. Work done on the I-beam can be calculated by the difference in kinetic energy before and after hitting the I-beam. This work done is equal to force times distance (fd). By solving this, we get the average force on the I-beam.
Learn more about Work-Energy Theorem here:https://brainly.com/question/32184004
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A 0.250 kg block on a vertical spring with a spring constant of 5.00 x 103 N/m is pushed downward compressing the spring 0.100 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above its point of release
Answer:
The height at point of release is 10.20 m
Explanation:
Given:
Spring constant [tex]k = 5 \times 10^{3} \frac{N}{m}[/tex]
Compression [tex]x = 0.10[/tex] m
Mass of block [tex]m = 0.250[/tex] kg
Here spring potential energy converted into potential energy,
[tex]mgh = \frac{1}{2} kx^{2}[/tex]
For finding at what height it rise,
[tex]0.250 \times 9.8 \times h = \frac{1}{2} \times 5 \times 10^{3} \times (0.10) ^{2}[/tex] ( ∵ [tex]g = 9.8 \frac{m}{s^{2} }[/tex] )
[tex]h = 10.20[/tex] m
Therefore, the height at point of release is 10.20 m
This question involves the concepts of the law of conservation of energy, elastic potential energy, and gravitational potential energy.
The block will rise "10.2 m" high above the point of its release.
According to the law of conservation of energy, the elastic potential energy stored by spring must be equal to the gravitational potential energy acquired by the block.
[tex]mgh = \frac{1}{2}kx^2[/tex]
where,
m = mass = 0.25 kg
g = acceleration due to gravity = 9.81 m/s²
h = heoght = ?
k = spring constant = 5000 N/m
x = compression = 0.1 m
Therefore,
[tex]h=\frac{(5000\ N/m)(0.1\ m)^2}{2(0.25\ kg)(9.81\ m/s^2)}[/tex]
h = 10.2 m
Learn more about the law of conservation of energy here:
brainly.com/question/20971995?referrer=searchResults
The attached picture explains the law of conservation of energy.
With current technologies and solar collectors on the ground, the best we can hope for is that solar cells will generate an average (day and night) power of about 230 watts/m2watts/m2 . What total area would we need to cover with solar cells to supply all the power needed for the United States
Answer:
The question is missing
The total annual U.S. energy consumption is about 2 × 10^20 J
Explanation:
So, if the annual Energy is
2 × 10^20J
Let find the power usage of this energy
We know that
Power = Energy / Time
Now, the time is one year, so we have to convert one year to seconds
1year = 365days
365days = 365 × 24hours
365 × 24 hours = 365 × 24 × 3600 seconds
Then,
1year = 31,536,000seconds
Then,
P = E / T
P = 2 × 10^20 / 31,536,000
P = 6.342 × 10^12 Watts
The power intensity is given as
I = P/A
Then,
A = P / I
Where,
P is power, I is intensity and A is area
Given that, I = 230 W/m²
A = 6.342 × 10^12 / 230
A = 2.757 × 10^10 m²
To meet the United States' energy needs using solar cells generating 230 watts/m², an area of approximately 14,500 km² is required.
To determine the total area of solar cells needed to supply all the power needed for the United States, we start with the given average power generation of 230 watts/m².
The energy needs for the United States per year is given as 1.05 × 10²⁰ Joules.
Convert Energy to Power:
First, we need to convert this annual energy requirement into average power, knowing that there are 31,536,000 seconds in a year (365 days × 24 hours/day × 3600 seconds/hour).
Average Power Required = [tex]\frac{Total Energy}{Time}[/tex] = (1.05 × 10²⁰J) ÷ {31,536,000 s} ≈ 3.33 × 10¹² watts
Calculate the Area Required:
If each square meter generates an average power of 230 watts, we can find the total area (A) by dividing the total power required by the power generated per square meter.
Required Area = [tex]\frac{Total Power Required}{Power Generated per unit area}[/tex] = 3.33 × 10¹² watts ÷ 230 watts/m² ≈ 1.45 × 10¹⁰ m²
To find the area in square kilometers, we convert square meters to square kilometers knowing that 1 km² = 1,000,000 m².
Total Area in km² = (1.45 × 10¹⁰ m²) ÷ (1,000,000 m²/km²) = 14,500 km²
Thus, approximately 14,500 km² of solar cells would be needed to generate enough power to meet the United States' energy needs.
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