You walk into an elevator, step onto a scale, and push the "up" button. you recall that your normal weight is 639 n . when the elevator has an upward acceleration of magnitude 2.90 m/s2 , what does the scale read?

This question deals with the concepts of the actual weight and apparent weight.

The apparent weight of the person is "827.9 N".

The apparent weight of an object is the reaction of the elevator floor on the person while the elevator is in accelerated motion. It is not the actual weight but the weight felt by the person for that time. In this case the elevator is moving up. Hence the apparent weight will be:

[tex]W_a=m(g+a)=mg+ma\\W_a=W+ma[/tex]

where,

Therefore,

[tex]W_a=639\ N + (65.14\ kg)(2.9\ m/s^s)[/tex]

[tex]W_a=827.9\ N[/tex]

Learn more about apparent weight here:

https://brainly.com/question/26393265

The scale reading in an elevator accelerating upwards will display an increased weight due to the additional force of acceleration. When an elevator accelerates with a magnitude of 2.90 m/s^2, the scale will show a higher value than the normal weight, calculated by the sum of gravitational force and force of acceleration.

When you step onto a scale in an elevator that is accelerating upwards with a magnitude of 2.90 m/s2, the scale reading will be higher than your normal weight due to the additional force required to accelerate you upwards. Given that your normal weight is 639 N, we can calculate the new scale reading by incorporating the effects of the elevator's acceleration using Newton's second law of motion.

To find the new scale reading, we first determine the apparent weight. The apparent weight is the sum of the true weight (gravitational force) and the force of acceleration (ma).

Apparent weight = True weight (W) + Force of acceleration (ma)

Where the true weight W = mg (mass times gravity), and a is the acceleration of the elevator.

Assuming Earth's gravity to be 9.81 m/s2, we can calculate the apparent weight as follows:

Apparent weight = mg + ma

Now, we need to find the mass (m) from the given weight (639 N), which is m = W/g = 639 N / 9.81 m/s2.

Then plug the mass and the given acceleration into the equation for apparent weight.

The scale reading in an accelerating elevator is directly proportional to the acceleration; it increases as the elevator accelerates upwards. However, once the elevator reaches a constant velocity, the scale reading will return to your normal weight, 639 N, because there will be no additional force from acceleration (a = 0).

Without inertia, how would an object that is experiencing a centripetal force behave?

It would move in a line away from the circle’s center.
It would move in a line toward the circle’s center.
It would move in a curved, circular path.
It would move in a line tangent to the circular path.