1. If the spring of a jack-in-the-box is compressed a distance of 8.00 cm from its relaxed length and then released, what is the speed of the toy head when the spring returns to its natural length? Assume the mass of the toy head is 50.0 g, the spring constant is 80.0 N/m and the toy head moves only in the vertical direction. Also disregard the mass of the spring. (Hint: Remember that there are two forms of potential energy in the problem.)

Answers

Answer 1
When the spring is compressed, the total energy of the jack-in-the-box system is elastic potential energy stored in the spring:
[tex]E_i= \frac{1}{2} kx^2 [/tex]
where [tex]k=80.0 N/m[/tex] is the spring's constant and [tex]x=-8 cm=-0.08 m[/tex] is the displacement of the spring with respect its rest position.

When the spring is released and it reaches its relaxed position, its elastic energy becomes zero (because x=0), and so the total energy of the system will be the kinetic energy of the toy's head:
[tex]E_f= \frac{1}{2} mv^2 [/tex]
where [tex]m=50 g=0.05 kg[/tex] is the mass of the head and v its velocity.

For the law of conservation of energy, [tex]E_i = E_f[/tex]. Rewriting both terms, we can find v:
[tex] \frac{1}{2}kx^2 = \frac{1}{2}mv^2 [/tex]
[tex]v= \sqrt{ \frac{kx^2}{m} }=3.2 m/s [/tex]
Answer 2
Final answer:

The speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s. This is found by equating the potential energy stored in the spring to the kinetic energy of the toy head and solving for the speed.

Explanation:

The question is regarding the use of the principles of conservation of energy and Hooke's Law in the context of a jack-in-the-box toy. Consider that energy is conserved, we can set the potential energy equal to the kinetic energy. The potential energy stored in the spring while it is compressed is given by the formula PE = 0.5*k*x², where k is the spring constant and x is the distance the spring is compressed. In this case, PE = 0.5*80N/m*(0.08m)² = 0.256 J.

When the spring is released and returns to its natural length, this energy is converted into kinetic energy for the toy head. The kinetic energy is given by KE = 0.5*m*v² where m represents mass and v stands for speed. Setting this equal to the potential energy from above and solving for v, we get v = sqrt((2*0.256J)/(0.05kg)) = sqrt(10.24) m/s = approximately 3.2 m/s.

Therefore, the speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s.

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Related Questions

______________ is a measure of the force of gravity pulling on an object of a given mass.

Answers

I think the answer is weight.

Which type of motor is shown below?

Answers

Answer: Option D, magnetic motor

Explanation: Plato/Edmentum

A magnetic motor has been shown in the picture.

What is a magnetic motor?

A magnet motor, also known as a magnetic motor, is a form of perpetual motion device designed to produce rotation using permanent magnets in the stator and rotor without the use of external energy. Both conceptually and physically, such a motor is not feasible.

Numerous amateurs have championed the concept of working magnetic motors. It is conceivable that it is parascience. The term "free energy" is frequently used.Magnet motors should not be confused with permanent magnet motors, which are more frequently used and are powered by an external electrical energy source.Permanent magnets are used in both the stator and rotor of a hypothetical magnet motor. A circular movement of the rotor is allegedly kept going forever by a specific configuration of the attracting and repelling poles.

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A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is disregarded, what is the mechanical energy of the system, and what is the speed of the fish when it hits the water?

Answers

1) What is the mechanical energy of the system?
(here I assume that "system" refers to the fish, because we don't know the mass of the bird).
The mechanical energy of the fish is conserved during the entire free fall, because there are no friction acting on it, therefore we can calculate it at the beginning of its free fall, when it is dropped by the bird. At this instant, the velocity of the fish is equal to the speed of the bird [tex](v_i=18 m/s)[/tex], and the distance from the ground is h=5.40 m. The mechanical energy is the sum of its kinetic energy and its potential energy:
[tex]E=K+U= \frac{1}{2}mv_i^2+mgh=[/tex]
[tex]= \frac{1}{2}(2 kg)(18 m/s)^2 +(2kg)(9.81 m/s^2)(5.40m)=430 J[/tex]

2) When the fish hits the water, its potential energy has become zero, because the height from the water is now zero: h=0. This means that the mechanical energy E (which is conserved) is now only kinetic energy. Therefore we can write:
[tex]E=K_f = \frac{1}{2}mv_f^2 [/tex]
And we can find the final speed:
[tex]v_f = \sqrt{ \frac{2E}{m} }= \sqrt{\frac{2\cdot 430 J}{2 kg}} = 20.7 m/s[/tex]

(a) The mechanical energy of the system is 429.84 J.

(b) The speed of the fish when it hits the water is 20.73 m/s.

Given data:

The speed of flying bird is, v = 18.0 m/s.

The mass of fish is, m = 2.00 kg.

The altitude of bird is, h = 5.40 m.

(a)

Since the fish is carried by the bird initially. So, considering them as a part of single system. The mechanical energy (ME) of system is given as,

[tex]\rm ME = \rm kinetic\;\rm energy + \rm potential \;\rm energy\\ME = \dfrac{1}{2}mv^{2} + mgh\\\\ME = \dfrac{1}{2} \times 2.00 \times 18.0^{2} + (2.00 \times 9.8 \times 54.0)\\\\ME= 429.84 \;\rm J[/tex]

Thus, the mechanical energy of the system is 429.84 J.

(b)

When the fish is dropped to water at ground, then entire mechanical energy is converted into the kinetic energy (or potential energy becomes zero). So,

mechanical energy = kinetic energy

[tex]ME = \dfrac{1}{2}mv^{2}[/tex]

Here, v is the speed of fish, with which it hits the water.

Solving as,

[tex]429.84 = \dfrac{1}{2} \times 2.00\times v^{2}\\v=\sqrt{429.84} \\v = 20.73 \;\rm m/s[/tex]

Thus, the speed of the fish when it hits the water is 20.73 m/s.

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A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude.

Answers

The amplitude of a wave corresponds to its maximum oscillation of the wave itself. 
In our problem, the equation of the wave is
[tex]y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])[/tex]
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,
[tex]y(x,t)=0.750 cm[/tex]
and therefore this value corresponds to the amplitude of the wave.

The amplitude of the given transverse wave in the rope is [tex]\boxed{0.750\,{\text{cm}}}[/tex].

Further Explanation:

The given expression of the wave developed in the rope is.

 [tex]y\left( {x,t} \right) = \left( {0.750\,{\text{cm}}} \right)\cos \left( {\pi \left[ {\left( {0.400\,{\text{cm}} - {\text{1}}} \right)x + \left( {250\,{\text{s}} - 1} \right)t} \right]} \right)[/tex]

The standard equation of the wave produced in a rope is given as.

[tex]\boxed{y\left( {x,t} \right) = A\cos \left( {kx + \omega t} \right)}[/tex]

Here, [tex]y[/tex] is the position of the wave, [tex]A[/tex] is the amplitude of the wave, [tex]k[/tex] is the wave number and [tex]\omega[/tex] is the angular frequency of the wave.

On comparing the above equation of the wave with the standard equation of the wave produced in a rope, the amplitude of the wave can be obtained as follows.

 [tex]A = 0.750\,{\text{cm}}[/tex]

Thus, the amplitude of the given transverse wave in the rope is [tex]\boxed{0.750\,{\text{cm}}}[/tex].

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Answer Details:

Grade: High School

Chapter: Waves

Subject: Physics

Keywords:  Transverse, wave, amplitude, angular frequency, stationary wave, rope, velocity, position, wave number.

As a moon follows its orbit around a planet, the maximum grav- itational force exerted on the moon by the planet exceeds the minimum gravitational force by 11%. find the ratio rmax/rmin, where rmax is the moon's maximum distance from the center of the planet and rmin is the minimum distance.

Answers

The gravitational force exerted on the moon by the planet when the moon is at maximum distance [tex]r_{max}[/tex] is
[tex]F_{min}=G \frac{Mm}{r_{max}^2} [/tex]
where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.

Similary, the gravitational force at minimum distance is
[tex]F_{max}=G \frac{Mm}{r_{min}^2}[/tex]
And this is the maximum force, since the distance between planet and moon is minimum.

The problem says that [tex]F_{max}[/tex] exceeds [tex]F_{min}[/tex] by 11%. We can rewrite this as
[tex]F_{max}=(1+0.11)F_{min}=1.11 F_{min}[/tex]

Substituing the formulas of Fmin and Fmax, this equation translates into
[tex] \frac{1}{r_{min}^2}=1.11 \frac{1}{r_{max}^2} [/tex]
and so, the ratio between the maximum and the minimum distance is
[tex] \frac{r_{max}}{r_{min}}= \sqrt{ 1.11 }=1.05 [/tex]

A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg, which initially is at rest as a result of the collision, 'A' is deflected and moves in a speed of 2.1m/s in a direction which is at an angle of 30 degree below the X-axis. 'B' is set in motion at an angle Φ above the X-axis. calculate the velocity of 'B' after the collision.

Answers

I already answered this question. 
Please refer to this link https://brainly.com/question/8743596.

Describe the image of an object that is 38 cm from a concave mirror that has a focal length of 10 cm.

Answers

Let's start by using the mirror equation:
[tex] \frac{1}{f}= \frac{1}{d}+ \frac{1}{q} [/tex]
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
[tex] \frac{1}{q}= \frac{1}{f}- \frac{1}{d} = \frac{1}{10 cm}- \frac{1}{38 cm} [/tex]
from which we find q=13.6 cm.

The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.

Then we can also find the size of the image with respect to the original object. The magnification is given by
[tex]M=- \frac{q}{d} =- \frac{13.6}{38}=-0.36 [/tex]
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.

Final answer:

A concave mirror with a focal length of 10 cm will form a virtual, upright image that is 11.43 cm away from the mirror. The magnification of the image will be -0.301.

Explanation:

A concave mirror with a focal length of 10 cm will form an image of an object that is 38 cm away. To determine the characteristics of the image, we can use the mirror equation: 1/f = 1/di + 1/do, where f is the focal length, di is the image distance, and do is the object distance. Rearranging the equation, we get di = 1 / (1/f - 1/do). Plugging in the given values, di = 1 / (1/10 - 1/38) = 11.43 cm.

The negative sign indicates that the image is virtual and upright. Furthermore, to determine the magnification of the image, we can use the formula: magnification = -di / do. Plugging in the values, magnification = -11.43 / 38 = -0.301.

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A bullet is fired at a speed of 2434 ft/s. what is this speed expressed in millimeters per minute?

Answers

44,512,992 mm/m. Hopefully...

Which arrow best represents the path of an object with projectile motion?

Answers

Answer:

C

Explanation:

Projectiles follow a parabolic path and I got it right on the quiz

Answer:

C

Explanation:

ball A has a mass of 5.0 kg. ball B has twice the mass of ball A. The Two balls collide and stick together in a perfectly inelastic collision. after the collision the combined balls are at rest. if the velocity of ball A before the collision was 13 m/s, what was the velocity of ball B before the collision?
A. 6.5
B. -6.5 m/s
C. 26 m/s
D. -13 m/s
E. 0.0 m/s

Answers

Ma.Va + Mb.Vb = (Ma+Mb)Vc
Vc=0
(5)(13) + (10)(Vb) = 0
65+10Vb = 0
Vb = -65/10
Vb = -6.5m/s

Answer = B

Using the conservation of momentum principle, the initial velocity of ball B before the collision is calculated to be -6.5 m/s given that the collision is perfectly inelastic and both balls come to rest after they stick together.

The problem describes a perfectly inelastic collision situation where ball A, with a mass of 5.0 kg and an initial velocity of 13 m/s, collides with ball B, which has twice the mass of ball A, and they stick together and come to rest. To find the initial velocity of ball B before the collision, we can use the conservation of momentum principle. The total momentum before the collision must equal the total momentum after the collision.

Let's denote the mass of ball A as mA and the mass of ball B as mB. The initial velocity of ball A is vA1 = 13 m/s, and let's denote the initial velocity of ball B as vB1. The mass of ball B is twice that of ball A, so mB = 2mA. Since the balls are at rest after the collision, their combined momentum is zero.

The momentum conservation equation can be written as:

mAvA1 + mBvB1 = 0

Substituting the given values and solving for vB1 we get:

(5.0 kg)(13 m/s) + (2 × 5.0 kg)vB1 = 0

65 kg×m/s + 10.0 kgvB1 = 0

vB1 = -(65 kg×m/s) / (10.0 kg)

vB1 = -6.5 m/s

Therefore, the initial velocity of ball B before the collision was -6.5 m/s, which corresponds to option B.

What is an important trait or skill a scientist must have

Answers

characteristics that lend themselves to carrying out the kind of work scientists do. These include strong observational skills, curiosity, logic, creativity, skepticism, and objectivity.

Assume the second cart moves in the negative direction. two carts with masses of 4.6 kg and 3.3 kg move toward each other on a frictionless track with speeds of 5.1 m/s and 4.9 m/s, respectively. the carts stick together after colliding head-on. find their final speed. answer in units of m/s.

Answers

The total momentum of the system (cart 1+ cart 2) is conserved after the collision. 
The initial momentum is
[tex]m_1 v_1 - m_2 v_2[/tex] (1)
where the negative sign in front of cart 2 momentum is due to the fact it goes in the opposite direction of cart 1.
The final momentum is
[tex](m_1 + m_2) v_f[/tex] (2)
because the two carts stick together, therefore their total mass is (m1+m2) moving at the new speed vf.

By requiring that (1) is equal to (2), we can solve to find the final speed vf:
[tex]m_1 v_1 - m_2 v_2 = (m_1 + m_2) v_f[/tex]
[tex]v_f = \frac{m_1 v_1 - m_2 v_2}{m_1+m_2}= \frac{(4.6 kg)(5.1 m/s)-(3.3 kg)(4.9 m/s)}{4.6 kg+3.3 kg} =0.9 m/s [/tex]
where the positive sign means the two carts are now going in the positive direction (i.e. the initial direction of cart 1)

Which of the following utilize electromagnetic induction to operate?
generators in power plants
telephones
turbines
masonry
fireplaces
solar ovens


it multiple choose

Answers

The correct answer is A. B. C. Hope this helps!!

The correct answer is option A and F, Generators in power plants and Solar ovens

Electromagnetic induction is the phenomena of generating electricity due to a changing magnetic field. In electric generators, a rotating coil (which acts as a conductor) is placed between the two magnets. As the coil rotates it induces electromotive force within the conductor. Like wise in case of solar oven , heating is caused due to the eddy currents produced with in the conductor placed with in a changing magnetic field.

Animals, including humans, need shelter, food, water, air, and space in order to survive. How do animals satisfy their basic needs?

Answers

if you come from study island then its all of them

Food, shelter and clothes are basic need of the humans. Animals like tiger hunt the animals in the jungle, some animals leaves on green grass which are abundantly present in the jungle. for shelter they live in the group at suitable place.

What is Animal ?

Animals belong to the biological kingdom Animalia and are multicellular, eukaryotic creatures. Animals generally ingest organic matter, breathe oxygen, can reproduce sexually, and form from a hollow ball of cells called a blastula during early development. There are an estimated 7.77 million animal species in existence as of 2022, but only 2.16 million of them have been described, including 1.05 million insects, over 36,000 fish, over 11,700 reptiles, over 11,100 birds, and 6,596 mammals. Animals can be as little as 8.5 micrometres (0.00033 in) or as large as 33.6 metres (110 ft). They construct extensive food webs through their complex interactions with one another and their surroundings. Zoology is the study of animals from a scientific perspective.

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every 24 hours, about how many hours are spent socializing and watching tv?

Answers

My guess would be about roughly 15, give or take a few. Including school, and it really depends how much TV you watch. Me personally spend about 5 hours watching TV or on the computer/ phone. So it really depends but 15 is my guess.

Answer:

16+ hours  

Explanation:

because they have a job and jobs are long so they would take as much time as they can get

Sam boards a ski lift, and rides up the mountain at 6 miles per hour. once at the top, sam immediately begins skiing down the mountain, averaging 54 miles per hour, and does not stop until reaching the entrance to the lift. the whole trip, up and down, takes 40 minutes. assuming the trips up and down cover the same distance, how many miles long is the trip down the

Answers

The general relationship between space S and time t for an uniform motion is
[tex]S=vt[/tex] 
with v being the velocity.
For the motion going up, we have [tex]v_{up}=6 mph[/tex], so we can write
[tex]S_{up} = 6 t_{up}[/tex]
While for the motion going down, we have [tex]v_{dn} = 54 mph[/tex], and so
[tex]S_{dn} = 54 t_{dn}[/tex]
The problem says that two distances covered up and down are the same, so we can write
[tex]6 t_{up} = 54 t_{dn}[/tex]
and so
[tex]t_{up} = 9 t_{dn}[/tex]

We also know that the total time of the motion (up+down) is 40 minutes, which corresponds to [tex] \frac{2}{3} [/tex] of hour. So we can write
[tex]t_{up} + t_{dn} = \frac{2}{3} [/tex]
Substituting [tex]t_{up} = 9 t_{dn}[/tex] as we found before, we can find the value of [tex]t_{dn}[/tex]:
[tex]9 t_{dn}+t_{dn} = \frac{2}{3} [/tex]
[tex]t_{dn} = \frac{1}{15} h [/tex]
And so we find also
[tex]t_{up}=9t_{dn}= \frac{3}{5}h [/tex]

And from [tex]t_{dn}[/tex], we can finally find how long is the trip going down:
[tex]S_{dn}=54 t_{dn}=54 \cdot \frac{1}{15} = 3.6 mil[/tex]
So, 3.6 miles.
Let us divide this problem into two parts:
1) Sam rides up the mountain.
2) Sam rides down the mountain.

1. 
Since speed is distance over time, as:
[tex]v = \frac{s}{t} [/tex]

Therefore, distance would be:
[tex]s_{up} = v_{up} * t_{up} [/tex]

Where s = distance,
v = speed,
t = time.

In the problem, Sam's speed while riding up is v = 6 miles/hour = (6 * 1609.34 / 60) = 160.934 meters/second(in SI Units). Plug this value in the above equation, you would get:

[tex]s_{up} = 160.934 * t_{up}[/tex] --- (A)

2. 
As Sam rides down the mountain, the speed given is:
[tex]v_{down} = 54 miles/h[/tex]

Convert it in SI units; the speed would be in SI unit:
v = 54 miles/hour = (54 * 1609.34 / 60) = 1448.406 meters/second(in SI Units). Plug this value in the distance equation, you would get:
[tex]s_{down} = 1448.406 * t_{down}[/tex]

Since the [tex]s_{up} = s_{down}[/tex], therefore,

[tex]160.934 * t_{up} = 1448.406 * t_{down}[/tex]

=> 
[tex] t_{up} = 9 t_{down}[/tex]

Now the condition is that the whole trip, up and down, takes 40 minutes(2400seconds), it means:
[tex]t_{up} + t_{down} = 2400[/tex]

Plug in the value of [tex]t_{up} [/tex] in the above equation, you would get:
[tex]t_{down} = 240[/tex]

Therefore,
[tex]s_{down} = 1448.406*240[/tex]
[tex]s_{down} = 347617.44[/tex] meters (in relation to seconds)

[tex]s_{down} = 5793.624[/tex] meters (in relation to hours)

Now the last step is to convert meters into miles, you would get:
[tex]s_{down} = 5793.624/1609.34 = 3.6miles[/tex]

So the answer is 3.6miles.

The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnels. (a) Determine its fundamental frequency of vibration. (b) What harmonic must be excited so that it resonates in the audio region at 20 Hz or greater?

Answers

For a cylinder that has both ends open resonant frequency is given by the following formula:
[tex]f= \frac{nv}{2L} [/tex]
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
[tex]f_0= \frac{v}{2L}=\frac{343}{2\cdot 2779}=0.062 Hz[/tex]
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
[tex]20= \frac{n343}{2\cdot 2779} =n\cdot f_0[/tex]
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
[tex]20=n\cdot f_0\\ n=\frac{20}{0.062}=322.58[/tex]
Since n has to be an integer, final answer would be 323.

Which of the following would most likely happen if water did not form hydrogen bonds? (2 points)

Answers

The answer choices for this question are:

A) Water would exist only as a solid.

B) Water would be able to dissolve all ionic compounds.

C) Water would not expand when it freezes.

D) Water would not exist on Earth.

The right answer is the option C) Water would not expand when if freezes.

Explanation:

Expansion of water when it freezes is an atypical behavior because substances contract when they freeze with the correpondant increase in density.

But when water forms the ice crystals, the strong hydrogen bonds do not permit an arrangement in which the molecules of water are closer and so they occupy more space (more volume). The length of the hydrogen bonds limits the distance between each water molecule. So, these bonds are the responsible of the expansion of water as it freezes.


Answer:

Water would not expand when it freezes

Explanation:

Which Of The Following Are Part Of The Ten Essentials List?

A. Extra Clothes And Rain Gear
B. Umbrella
C. Sunscreen And Hat
D. First Aid Kit
E. Water Purifier
F. Sleeping Pad

Answers

the are A,C,D   that is answer the don't forget to see more answer                                                            


Select the correct answer. What is tan for the given triangle? 0.60 1.67 1.33 5.00 0.20

Answers

the answer is 1.33 i hope this helps you
The correct answer should be 1.33

Compare the Carboniferous period to the Devonian period.

Answers

In the Devonian Period, forests and land plants evolved and vertebrates made their appearance. Four-legged vertebrates evolved during the Carboniferous Period, which caused an increase in the number of land-based organisms. Devonian Period, in geologic time, an interval of the Paleozoic Era that follows the Silurian Period and precedes the Carboniferous Period, spanning between about 419.2 million and 358.9 million years ago. The Devonian Period is sometimes called the “Age of Fishes” because of the diverse, abundant, and, in some cases, bizarre types of these creatures that swam Devonian seas. Forests and the coiled shell-bearing marine organisms known as ammonites first appeared early in the Devonian. Late in the period the first four-legged amphibians appeared, indicating the colonization of land by vertebrates. The Carboniferous Period lasted from about 359.2 to 299 million years ago* during the late Paleozoic Era. The term "Carboniferous" comes from England, in reference to the rich deposits of coal that occur there. These deposits of coal occur throughout northern Europe, Asia, and midwestern and eastern North America. The term "Carboniferous" is used throughout the world to describe this period, although in the United States it has been separated into the Mississippian (early Carboniferous) and the Pennsylvanian (late Carboniferous) Subsystems. This division was established to distinguish the coal-bearing layers of the Pennsylvanian from the mostly limestone Mississippian, and is a result of differing stratigraphy on the different continents. The Mississippian and Pennsylvanian, in turn, are subdivided into a number of internationally recognized stages based on evolutionary successions of fossil groups . These stages are (from early to late) Tournaisian, Visean, and Serpukhovian for the Mississippian — and Bashkirian, Moscovian, Kasimovian, and Gzhelian for the Pennsylvanian.

In geologic time, the Devonian Period is a period of the Paleozoic Era that follows the Silurian Period and precedes the Carboniferous Period, lasting between 419.2 million and 358.9 million years ago.

What is Devonian period?  

The Devonian, a Paleozoic era, is also known as the Age of Fishes because it produced a diverse range of fish.

The most fearsome were the armored placoderms, a group that first appeared during the Silurian period and had powerful jaws lined with bladelike plates that acted as teeth.

The Carboniferous period (about 360 million to 300 million years ago) was distinguished by dense and swampy forests that produced large deposits of peat.

Over time, peat bogs in Western Europe and North America transformed into rich coal reserves.

Thus, the above mentioned is the comparison between the two periods.

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it takes 1.0h to drive 20km through a city during rush hour your (Blank) speed is 20km/h

Answers

Your average speed is 20 km/h.

Final answer:

The question involves calculating average speed by dividing distance traveled by time of travel. In the example, for a 20 km drive taking 1.0 hour, the average speed is 20 km/h. Another scenario provided explains how to convert average speed to different units given a trip from school to home.

Explanation:

The question asks about calculating average speed during a trip, which can be determined by dividing the total distance traveled by the total time of travel. In the given scenario, the student has a 1.0 hour trip to cover 20 km, which correctly yields an average speed of 20 km/h. To calculate average speed, you simply use the formula:

Average speed = Total distance / Total time

For a more detailed example, if you drive 10.0 km from your school to home in 20.0 minutes, it's necessary to convert minutes to hours by dividing by 60. You would then calculate the average speed in kilometers per hour (km/h) and convert the result to meters per second (m/s), if needed, using the appropriate conversion factors (1 km = 1000 m and 1 hr = 3600 seconds).

At the end of a factory production line, boxes start from rest and slide down a 30 ∘ ramp 5.8 m long. part a if the slide is to take no more than 3.9 s , what's the maximum allowed frictional coefficient

Answers

We can solve the problem by analyzing the forces acting along the direction of the inclined plane. There are two forces: the first one is the component of the weight parallel to the inclined plane, which is
[tex]mg \sin \alpha[/tex]
where [tex]g=9.81 m/s^2[/tex] and [tex]\alpha=30^{\circ}[/tex]. This force points along the direction of the motion (down). The second one is the frictional force, acting against the motion, as well along the inclined plane:
[tex]-m g \mu_D[/tex]
where [tex]\mu_D[/tex] is the dynamic frictional coefficient, and we have to find the value of this. The negative sign means the force is acting against the direction of the motion.

Newton's second law states that the resultant of the forces acting on the object is equal to the product between the mass m and the acceleration a:
[tex]mg \sin \alpha - mg \mu_D = ma[/tex]
So we can write the acceleration as
[tex]a=g \sin \alpha - g \mu_D[/tex]

Now, we can use the law of motion along the direction of the inclined plane. For an uniformly accelerated motion, we have
[tex]S= \frac{1}{2} a t^2 [/tex]
Assuming the object is initially at rest. But S, in our problem, is exactly the lenght of the plane:
[tex]S=L=5.8 m[/tex]
So we can substitute a inside the formula and we get
[tex]L= \frac{1}{2} (g \sin \alpha - g \mu_D) t^2 [/tex]
From which we get
[tex]\mu_D = \sin \alpha - \frac{2L}{gt^2} [/tex]
and using the time given by the problem, [tex]t=3.9 s[/tex] and [tex]L=5.8 m[/tex], we find
[tex]\mu_D = 0.422[/tex] 
The component of weight(mg) that is responsible for the motion of boxes on ramp is:
[tex]m*g*sin \alpha [/tex]

Where m = mass of the boxes.
g = Acceleration due to gravity = 9.8[tex]m/s ^{2} [/tex]
[tex] \alpha [/tex] = The angle the ramp makes with the ground. In this case it is 30°.

Since the frictional force is:
[tex]F_{f} = [/tex]μ*N.

Where,
μ = Frictional Coefficient
N = Normal to the ramp = [tex] m*g*cos\alpha [/tex]

Therefore, the frictional force becomes = [tex]F_{f}[/tex] = μ*[tex]m*g* cos \alpha [/tex]

Apply Newton's second law we would get:
[tex]m*g*sin \alpha [/tex] -  μ*[tex]m*g* cos \alpha [/tex] = [tex]m*a[/tex]

=> [tex]a[/tex]=[tex]g*(sin \alpha - [/tex]μ [tex]cos \alpha )[/tex] -- (A)

Now according to equation of motion:
[tex]x = x_{o} + v_{o}*t + 1/2 * a * t^{2} [/tex]

Where x = 5.8m
[tex]x_{o}[/tex] = 0
[tex]v_{o}[/tex] = 0
[tex]t^{2}[/tex] = 10.24

Plug in the value in the above equation you would get:
[tex]a[/tex] = 1.1328[tex]m/s ^{2} [/tex]


Plug in [tex]a[/tex] in equation (A) and solve for μ, you would get,
μ = 0.4439   

What is the average speed of a human that runs a distance of 5 miles in 1 hour?

Answers

It would be 5 mph. Hope it helps! :)


One student did an experiment with two unknown minerals, Mineral 1 and Mineral 2. The hardness scale shown below was used for the experiment.


Mineral Talc Gypsum Calcite Fluorite Apatite Orthoclase
Hardness 1 2 3 4 5 6

Any mineral on the hardness scale would scratch minerals below it on the scale. The student tested Mineral 1 and observed that it could scratch only two other minerals on the hardness scale. It was observed that Mineral 2 could scratch only four other minerals on the hardness scale. Which of these is a correct conclusion the student can make about Mineral 1 and Mineral 2?
A) Mineral 1 can be used to scratch talc and Mineral 2 can be used to scratch orthoclase.
B) Mineral 1 can be used to scratch orthoclase and Mineral 2 can be used to scratch talc.
C) Mineral 1 can be used to scratch calcite and Mineral 2 can be used to scratch gypsum.
D) Mineral 1 can be used to scratch gypsum and Mineral 2 can be used to scratch calcite.

Answers

Scale: (soft 1-->6 hardest)
1=Talc 2=Gypsum 3=Calcite 4=Fluorite 5=Apatite 6=Orthoclase

Mineral #1 can only scratch two other minerals therefore it must have a hardness level of 2+1=3 which is Calcite. (scratches talc, gypsum)

Mineral #2 can scratch four other minerals therefore it must have a hardness level of 4+1=5 which is Apatite. (scratches all but Apatite, Orthoclase)

Looking through the possible conclusions.. It looks like answer is D.


Final answer:

Mineral 1 has a hardness equivalent to calcite, and Mineral 2 has a hardness equivalent to apatite. Therefore, Mineral 1 can scratch calcite and Mineral 2 can scratch gypsum.

Explanation:

The hardness scale in the question list minerals according to their hardness. Mineral 1 could only scratch two other minerals, which means that it should rank third on the scale, since it can only scratch minerals 1 and 2. The hardness of Mineral 1 is, therefore, equivalent to that of calcite. Similarly, Mineral 2 could scratch four other minerals, and thus should rank fifth on the scale, after minerals 1, 2, 3, and 4. This means that the hardness of Mineral 2 is equivalent to that of apatite. Therefore, the correct answer is option C) Mineral 1 can be used to scratch calcite and Mineral 2 can be used to scratch gypsum.

Learn more about Mineral Hardness here:

https://brainly.com/question/36383382

#SPJ2

Two mechanical waves intersect and produce the straight line seen here. What is the result of this intersection called?

A) summative interference
B) destructive interference
C) subtractive interference
D) constructive interference

Answers

B) destructive interference

Answer: The correct option is B.

Explanation:

In the given problem, two mechanical waves intersect and produce the straight line seen here. It means that the new wave having zero amplitude is formed.

Destructive interference is the interference of the wave in which the new wave will form with lower amplitude.

Constructive interference is the interference of the wave in which the new wave will form with lower amplitude.

Therefore, the correct answer is B.

Please help!! will mark brainiest and 60 pnts!!!

1) An items real value is
A) Equal to its price
B) Always greater than its perceived value
C) Equal to the cost of its production
D) An average of the price of competitor items

2) Bartering is an example of the exchange process at work.
A) True
B) False

3) The core of marketing is
A) Real value
B) Perceived value
C) Utility
D) Social media

4) Colligate football merchandise associated with colleges in the SEC (South Eastern Conference) are more popular in Alabama than in Oregon because of their
A) Time utility
B) Place utility
C) Form utility
D) Image utility

5) A consumer who is willing to pay more for a pre-assembled piece of furniture as opposed to a cheaper piece of furniture that has to be put together after purchase recognizes the item’s
A) Real value
B) Perceived value
C) Form utility
D) Possession utility

6) By marketing an item, sellers attempt to increase the real value of an item.
A) True
B) False

7) In modern-day society, the exchange process is primarily based on which of the following?
A) The bartering system
B) The honor system
C) The monetary system
D) The gold standard

8) All companies with a website use this online venue to directly sell their products to consumers.
A) True
B) False

9) In today’s society, some services and commodities can be successfully promoted via Internet marketing alone.
A) True
B) False

10) In marketing, an item’s utility refers to only how that product is used by the consumer.
A) True
B) False

Answers

In case you're in hurry, the correct answers are:
1) C
2) A
3) C
4) B
5) C
6) A
7) C
8) A
9) A
10) B

Detailed Explanation:
1)
In marketing, the real value of an item, in simple terms, is the cost to produce the product. Let us take an example of an Apple product(say iPhone). Its real value is the cost of making its whole design, electronics, certain components within that electronics, the casing etc. In the options given, the one that satisfies the definition of item's real value is: Option C) Equal to the cost of its production.

2) Bartering is an exchange process. An example would be helpful to explain the concept. Let us suppose that there are only three people in the world, say Tom, Marija and Hanna. Tom has apples, Marija has oranges, and Hanna has mangoes. Tom loves oranges; therefore, he would go to Marija and ask her to exchange orange for apples. If Marija wants apples, she would most likely exchange oranges for apples. What if Marija wants mangoes instead of apples? She might exchange one or two oranges with Tom, and rest she would exchange with Hanna for mangoes. The bottom line is that in bartering the "real" goods and services are being exchanged instead of any kind of money. The correct answer is: A) True. 

3) 
Marketing, according to American Marketing Association, is the set of activities and processes for creating, delivering and exchanging offerings that have value for customers. Customers always have a choice in the market, therefore, the core of marketing of any company/corporate is the benefit or the value a customer receives from the exchange in the market. The measure of that benefit and the value, in Marketing, is utility. The correct option is: C) Utility.

4) 
In Alabama more facilities are available. Stadiums there are much more bigger than that of in Oregon. Coaching facilities in Alabama are easily accessible to the consumers compared to that of in Oregon. Furthermore, the population of Alabama is more than that of Oregon. Therefore, place is the vital factor in the popularity of Colligate football merchandise. In marketing, Place Utility is the availability of a product or service in a location that is convenient and easily accessible to the customers. Hence, the correct option is: B) Place Utility.

5) 
Real value is the real cost of the production of an item. Perceived value is the worth of an item in the eyes of a consumer. Form Utility is the method of increasing the overall attractiveness of a product or making a product ready for consumption to a group of consumers by changing its physical appearance. Therefore, the correct option is: C) Form Utility.

6) 
Real value, as I explained above, is the cost to produce the product. In order to get much of the profit out of the product, sellers attempts to increase the real value. For example, if a company makes an item or product for $10, in order to get the profit out of it, it(company) advertises to increase its real value from $10 to $20. The correct option is: A) True

7) 
In modern-day society, the exchange process is primarily based on the monetary system. Individuals use money to buy items. States/countries uses money, almost all of the times, to sell and buy the services/goods. Therefore, the correct option is: C) The monetary system
Did you know(Information): Few countries prefer that bartering system along with the monetary system. Like China, Indonesia etc.

8) Indeed, the companies with a website use this online portal to directly sell their products to consumers. Apple, for instance, sell its products(iPad, iPhone, Macbooks, Apple TV, Watches etc.) online. Twitter and Facebook selling their services in terms of advertisements. There are hundreds and thousands of such examples.Therefore, the correct option is: A) True.

9) 
In present-day society, internet marketing is being used to promote and sell certain services and commodities. For example, on Facebook. Most of the businesses float their advertisements there for selling their products. Ebay and Amazon are the prime examples of selling the products online. The correct option is: A) True

10)  Item's utility in Marketing is the expected satisfaction that a consumer gets upon the consumption of that particular item or product. It is not how the product is used by the consumer. Therefore, the correct option is: B) False.

1) C  2) A  3) C  4) B  5) C  6) A  7) C  8) A  9) A  10) B Is the answer

Binary ionic compounds are: Check all that apply.

A.Compounds with very different electronegativities
B.Made from two metals
C.Compounds that share electrons
D.Metals and nonmetal ions

Answers

I believe the answer is the last one; they are made of metals and non metal ions. Binary ionic compounds are ionic compounds that contain only two elements, one is the cation and the other is the anion. They are neutrally charged compounds made up of bonded ions, a cation an an anion. For example sodium chloride; contains Na+ (a cation with a +1) combines with Cl- (an anion with a -1 charge) to make sodium chloride.

Compounds with very different electronegativities AND metals and non metals.

A long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? a long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? upward west north south downward east

Answers

Final answer:

The magnetic field is due east of a long, straight, vertical wire carrying a current upward points downward.

Explanation:

The magnetic field created by a long, straight, vertical wire carrying a current upward can be determined using the right-hand rule. According to the right-hand rule, if you point your right thumb in the direction of the current in the wire, your fingers will curl in the direction of the magnetic field.

Since the wire is carrying current upward, the magnetic field will point in the clockwise direction when viewed from above. Therefore, the magnetic field due east of the wire will point downward.

Because there is very little friction, the lever is an extremely efficient simple machine. using a 90.0% efficient lever, what input work is required to lift a(n) 19.0 kg mass through a distance of 45 cm? 3232 incorrect: your answer is incorrect. seenkey 93.2 j

Answers

more simply efficiency n=output work/input work =mgh/W(in)W(in) =18*9.81*0.5/0.90=98.1 Joule

Answer:

Input work: 93.2 J

Explanation:

The work efficiency formula is:

efficiency = output work/ input work

Solving for input work:

input work = output work/efficiency  

The work required to lift an object is computed as follows:

Output work = mass * gravity * height

Using mass in kg, gravity in m/(s^2) and height in m; then work is expressed in Joules. Combining the equations and replacing with data, we get (units are omitted):

input work = 19*9.81*0.45/0.9 = 93.2 J

Note that 45 cm is equivalent to 0.45 m

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