Answer:
Any of the set of metallic elements occupying a central block (Groups IVB–VIII, IB, and IIB, or 4–12) in the periodic table, e.g., iron, manganese, chromium, and copper. Chemically they show variable valence and a strong tendency to form coordination compounds, and many of their compounds are colored.
Step-by-step explanation:
linear combination
Answer:
linear combination is an expression constructed from a set of terms by multiplying each term by a constant and adding the results (e.g. a linear combination of x and y would be any expression of the form ax + by, where a and b are constants)
Step-by-step explanation:
A rectangle has the width of r+3 and a length of 2r+9. What is the perimeter of the rectangle
Answer:
6r+24
Step-by-step explanation:
2(r+3)=2r+6
2(2r+9)=4r+18
(2r+6)+(4r+18)=6r+24
Which expression is equivalent to −13(6x+15)−3
The expression is equivalent to −78x − 198.
To simplify the expression −13(6x + 15) − 3, you can start by distributing the −13 across the terms inside the parentheses:
−13 * 6x = −78x
−13 * 15 = −195
So, the expression becomes:
−78x − 195 − 3
Next, combine the constant terms:
−195 − 3 = −198
The simplified expression is now:
−78x − 198
This expression is equivalent to the original expression −13(6x + 15) − 3. It cannot be further simplified as the terms are not like terms and cannot be combined further. So, the answer is −78x − 198.
The expression represents a linear equation where x is the variable. It can be used to find the value of the expression for specific values of x.
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Quadrilateral PQRS has vertices P(2, 10), Q(6, 8), R(6, 3), and K(2, 3).
What are the coordinates of S’ after a dilation of quadrilateral PQRS by a factor of 2 centered at the origin?
Answer:
[tex]S'(4,6)[/tex]
Step-by-step explanation:
Dilation rules :
For a pre-image point [tex](x,y)[/tex] which is dilated by a scalar factor of [tex]k[/tex] about the origin, the corresponding point of the image can be given by [tex](kx,ky)[/tex]
Pre-image point [tex](x,y)\rightarrow (kx,ky)[/tex] Image point
Given points of quadrilateral PQRS.
P(2,10)
Q(6,8)
R(6,3)
S(2,3)
The quadrilateral is dilated about the origin by a scalar factor of 2.
The co-ordinates of point S' after dilation can be given by:
[tex]S(2,3)\rightarrow S'((2\times2),(2\times3))[/tex]
Thus [tex]S'(4,6)[/tex] (Answer)
Answer:
As jitumahi456 states B).(4, 6) is the correct answer.
Step-by-step explanation:
I took the test on edg.
the sum of 2fifteens and 10 fifteens
Answer:4/5
Step-by-step explanation:
2/15 + 10/15=12/15=4/5
easy right?
-k - (-8k) combining like terms with negative coefficients
Answer:
7k
Step-by-step explanation:
Note that - (- 8k) = + 8k
Given
- k - (- 8k)
= - k + 8k
= 7k
What is the area of the triangle ADE in the following figure ?
Answer:
Step-by-step explanation:
Hello
Area triangle DCE :
10 x (8/2) / 2 = 10 x 4 / 2 = 20 cm^2
Area triangle ABE = Area triangle DCE
Area ABCD :
10 x 8 = 80 cm^2
Area triangle AED :
Area ABCD - 2 area DCE
= 80 - 2 x 20
= 80 - 40
= 40 cm^2
find a positive real number such that its square is equal to 15 times the number increased by 286
Answer:
The positive real number is 26
Step-by-step explanation:
Let
x ----> the number
we know that
The algebraic expression that represent this problem is
[tex]x^{2} =15x+286[/tex]
so
[tex]x^{2}-15x-286=0[/tex]
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]x^{2}-15x-286=0[/tex]
so
[tex]a=1\\b=-15\\c=-286[/tex]
substitute in the formula
[tex]x=\frac{-(-15)(+/-)\sqrt{-15^{2}-4(1)(-286)}} {2(1)}[/tex]
[tex]x=\frac{15(+/-)\sqrt{1,369}} {2}[/tex]
[tex]x=\frac{15(+/-)37}{2}[/tex]
[tex]x_1=\frac{15(+)37}{2}=26[/tex]
[tex]x_2=\frac{15(-)37}{2}=-11[/tex] ---> the solution cannot be negative
therefore
The positive real number is 26
Identify the transformation on the figure shown.
A) reflection over the x-axis
B) reflection over the y-axis
C) rotation about the x-axis
D) rotation about the y-axis
The transformation on the figure is a reflection over the y-axis.
How to identify the transformation?In the image, we can see that we have an original figure in the left side of the y-axis, and then it is reflected over it.
We can see that it is a reflection and not a translation, because the orientation of the figure changes (you can see that in both figures, the 90° is in the side farthest away from the axis).
So the correct option is B, reflection over the y-axis.
If you want to learn more about reflections, you can read:
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Whats the slope of (-5,9) (7,3)
Answer:
-1/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-9)/(7-(-5))
m=-6/(7+5)
m=-6/12
m=-1/2
Which graph represents the function f(x)=2⋅4x ?
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
[tex]f(x)=2(4^x)[/tex]
This is a exponential function of the form
[tex]f(x)=a(b^x)[/tex]
where
a is the initial value
b is the base
r is the rate
b=(1+r)
In this problem we have
[tex]a=2\\b=4\\r=b-1=4-1=3=300\%[/tex]
For x=0
[tex]f(0)=2(4^0)[/tex] -----> [tex]f(0)=2[/tex] ---> y-intercept or initial value
For x=1
[tex]f(1)=2(4^1)[/tex] -----> [tex]f(1)=8[/tex]
Identify the graph
using a graphing tool
The graph in the attached figure
Five times the difference of twice a number and seven is negative twenty-five. Find the number.
The number is 1
Step-by-step explanation:
Let x be the required number
Then according to given statement
Five times the difference of twice a number and seven is negative twenty-five.
[tex]5(2x-7) = -25[/tex]
Simplifying
[tex]10x-35 = -25\\[/tex]
Adding 35 on both sides
[tex]10x-35+35 = -25+35\\10x = 10[/tex]
Dividing both sides by 10
[tex]\frac{10x}{10} = \frac{10}{10}\\x = 1[/tex]
Verification:
[tex]5[2(1)-7] = -25\\5(2-7) = -25\\5(-5) = -25\\-25=-25[/tex]
Hence,
1 is the number
Keywords: Linear equation
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what is the value of x ?
Answer:
the value of x is 7cm.
Step-by-step explanation:
i looked it up on the Internet next u could try n do tht
Answer:
x=65 degrees
Step-by-step explanation:
in a triangle all angles will have to add up to 180 adding the two given you can find the third one.
Which of the following is the greatest number?
A. 1.3 * 105
B. 9.8 * 102
C. 9.6 * 104
D. 4.6 * 10-5
Answer:
The greatest number is A. 1.3 * 10⁵
Step-by-step explanation:
Let's find the greatest number:
Option A : 1.3 * 10⁵ = 1.3 * 100,000 = 130,000
Option B : 9.8 * 10² = 9.8 * 100 = 980
Option C : 9.6 * 10⁴ = 9.6 * 10,000 = 96,000
Option D : 4.6 * 10⁻⁵ = 4.6 * 0.00001 = 0.000046
130,000 > 96,000 > 980 > 0.000046
The greatest number is A. 1.3 * 10⁵
please help me with these, oh sweet jesus
Answer:
77. [tex]\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x[/tex]Proved
78. [tex]\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ][/tex] Proved
79. [tex]\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x[/tex] Proved.
80. [tex]\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x[/tex] Proved.
Step-by-step explanation:
77. Left hand side
= [tex]\cot^{6} x[/tex]
= [tex]\cot^{4} x \times \cot^{2} x[/tex]
= [tex]\cot^{4}x [\csc^{2}x - 1][/tex]
{Since we know, [tex]\csc^{2} x - \cot^{2}x = 1[/tex]}
= [tex]\cot^{4} x \csc^{2}x - \cot^{4} x[/tex]
= Right hand side (Proved)
78. Left hand side
= [tex]\sec^{4}x \tan^{2} x[/tex]
= [tex]\sec^{2} x [1 + \tan^{2}x] \tan^{2} x[/tex]
{Since [tex]\sec^{2}x - \tan^{2}x = 1[/tex]}
= [tex]\sec^{2}x [\tan^{2}x + \tan^{4}x ][/tex]
= Right hand side (Proved)
79. Left hand side
= [tex]\cos^{3} x\sin^{2} x[/tex]
= [tex]\cos x[1 - \sin^{2} x] \sin^{2} x[/tex]
{Since [tex]\sin^{2}x + \cos^{2} x = 1[/tex]}
= [tex][\sin^{2}x - \sin^{4}x] \cos x[/tex]
= Right hand side
80. Left hand side
= [tex]\sin^{4}x - \cos^{4}x[/tex]
= [tex][\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x[/tex]
{Since [tex]\sin^{2}x + \cos^{2} x = 1[/tex]}
= [tex]1 - 2\cos^{2} x[1 - \cos^{2}x ][/tex]
= [tex]1 - 2\cos^{2}x + 2 \cos^{4} x[/tex]
= Right hand side. (Proved)
A golf ball, thrown upwards, rises at a speed of v metres per second.
The ball reaches a maximum height of h metres.
h is proportional to the square of v.
When v = 20, h = 8
Work out the maximum height reached by the golf ball when v = 35
Answer:24.5
Step-by-step explanation:
Formula:
H=KV²
8=K×20²(400)
=8/400
=0.02
H=0.02×35²
=24.5
Answer:
The maximum height reached by the golf ball when v = 35 is 24.5 meters.
Step-by-step explanation:
Given : A golf ball, thrown upwards, rises at a speed of v metres per second. The ball reaches a maximum height of h metres. h is proportional to the square of v. When v = 20, h = 8.
To find : Work out the maximum height reached by the golf ball when v = 35 ?
Solution :
h is proportional to the square of v i.e. [tex]h\propto v^2[/tex]
[tex]h=kv^2[/tex]
Where, k is the constant of proportionality
When v = 20, h = 8,
[tex]8=k(20)^2[/tex]
[tex]8=400k[/tex]
[tex]k=\frac{8}{400}[/tex]
[tex]k=0.02[/tex]
The equation became [tex]h=0.02v^2[/tex].
Now, when v = 35 the value of h is
[tex]h=0.02(35)^2[/tex]
[tex]h=0.02\times 1225[/tex]
[tex]h=24.5[/tex]
Therefore, the maximum height reached by the golf ball when v = 35 is 24.5 meters.
Citizens less than 18 years old are not allowed to vote define a variable and write an inequality for the ages of citizens who are not allowed to vote
Answer:
[tex]x < 18[/tex]
Step-by-step explanation:
We are given the following information in the question:
"Citizens less than 18 years old are not allowed to vote"
We define a variable x such that x represents the age of citizens.
We have to write a relationship with the help of an inequality for the ages of citizens who are not allowed to vote.
Citizens less than 18 are not allowed to vote.
So x should be less than 18.
This can be written as:
[tex]x < 18[/tex]
is the required inequality for the ages of citizens who are not allowed to vote.
Differentiate from first principle
1. y= x^2 + 3x
2. y= x^2 + 3x + 8
Answer:
Differentiation of both the term is [tex]2x+3[/tex]
Step-by-step explanation:
As we have to use first principle of derivatives lets recall the formula.
[tex]f(x)= \lim_{h\to 0}\frac{(x+h)-f(x)}{h}[/tex]
Solving our eqaution.
[tex]y=x^2+3x[/tex]
We will work with [tex]f(x+h)[/tex] then [tex]-f(x)[/tex] separately then put in the above formula.
1.
[tex]f(x+h)=(x+h)^2+3(x+h)[/tex]
[tex](x^2+h^2+2hx+3x+3h)[/tex]
Now [tex]-f(x)[/tex]
[tex]-f(x)=-x^2-3x[/tex]
Plugging the values of both.
[tex]f(x)= \lim_{h\to 0}\frac{(x+h)-f(x)}{h}[/tex]
[tex]f(x)= \lim_{h\to 0}\frac{(x^2+h^2+2hx+3h+3x)- x^2-3x}{h}=\frac{h^2+2hx+3h}{h}[/tex]
Taking [tex]h[/tex] as common.
[tex]f(x)= \lim_{h\to 0}\frac{h^2+2hx+3h}{h}=h+2x+3[/tex]
Putting [tex]h=0[/tex]
Then
[tex]f(x)=2x+3[/tex] is the final derivative.
This will be same for [tex]y= x^2 + 3x + 8[/tex] as we have to put [tex]8[/tex] only.
2.
[tex]f(x+h)=(x+h)^2+3(x+h)+8[/tex]
[tex](x^2+h^2+2hx+3x+3h)[/tex]
Then [tex]-f(x)=-x^2-3x-8[/tex]
Plugging the values of both.
[tex]f(x)= \lim_{h\to 0}\frac{(x+h)-f(x)}{h}[/tex]
[tex]f(x)= \lim_{h\to 0}\frac{(x^2+h^2+2hx+3h+3x+8)- x^2-3x-8}{h}=\frac{h^2+2hx+3h}{h}[/tex]
Taking [tex]h[/tex] as common.
[tex]f(x)= \lim_{h\to 0}\frac{h^2+2hx+3h}{h}=h+2x+3[/tex]
Putting [tex]h=0[/tex]
Then
[tex]f(x)=2x+3[/tex] is the final derivative.
So both the derivatives are same.
Eric jogged for 47 minutes, ending at 3:35 p.m. When did Eric start his jog?
A) 2:48 p.m.
B) 2:30 p.m.
C) 2:58 p.m.
D) 4:22 p.m.
plz help ASAP TwT
Answer:
im pretty sure its c
Step-by-step explanation:
A pool holds 33500 gallons of water. The pool is filled at a constant rate of 485 gallons every 6.5 minutes. Select whether each statement is true or false.
________ The unit rate for filling the pool is 74 gallons per minute
________ It will take 4 hours and 15 minutes to fill the pool to 85% of its capacity.
________ The difference between the pool being 64% full and 48% full is 3600 gallons.
________ A slow leak has left the pool with only 19800 gallons, a 12% decrease.
________ The pool can be completely filled in less than 5 hours.
1. It's True. Since it's 485 gallons every 6.5 minutes, then to find 1 minute you would do 485/6.5 which is approximately 74 gallons.
2. It's False. 85% of 33500 is 28475 gallons. If you divide that by 74, since that's the number of gallons per minute, you get approximately around 384 minutes. Since you want the time in hours, you divide 384 by 60, and you get the decimal 6.4. Since 6 hours is greater than 4 hours, it's false.
3. It's False. 64% of 33500 is 21440 gallons. 48% of 33500 is 16080 gallons. 21440-16080 is 5360 gallons, not 3360 gallons.
4. It's False. To find the percent of change, you first need to subtract 19800 from 33500, which gives you a result of 13700. Then you divide 13700/33500, which gives you a quotient of approximately 0.41. You multiply that by 100 to find the percent, which is 41%. 41% is not equal to 12%.
5. It's False. Since the unit rate is 74 gallons per minute, you divide 33500 by 74 to see how many minutes it takes. That gives you a quotient of approximately 453 minutes. You divide that by 60 since you want the time in hours, and the quotient of that is 7.55. 7 hours is greater than 5, so it's false.
I'm not too sure about some of them, so you might want to check my math. :)
Can the sides of a triangle have lengths 3, 3, and 10?
Answer:
No
Step-by-step explanation:
According to the property of the triangle ,
sum of any two sides should we greater then third side of the triangle.
Here, Measurement of three sides are given as 3,3,5 .
So, sum of the measurement of first two sides is 6.
And third side equals 10.
Clearly 6 is less than 10. So . it violates the property sum of any two sides should we greater then third side of the triangle.
Thus , Sides of a triangle can't be 3,3,10.
Answer:
Yes
Step-by-step explanation:
As long as there are three sides and it forms a triangle, the answer is yes.
Find the solution for 72 < 7x − 5.
1 x < -11
2 x > 11
3 x > 21
4 x < 11
Answer:
Option 2. [tex]x > 11[/tex]
Step-by-step explanation:
we have
[tex]72 < 7x-5[/tex]
Solve the inequality for x
Adds 5 both sides
[tex]72+5 < 7x-5+5[/tex]
[tex]77 < 7x[/tex]
Divide by 7 both sides
[tex]77/7 < 7x/7[/tex]
[tex]11 < x[/tex]
Rewrite
[tex]x > 11[/tex]
if I add .002 ounces of coloring to 3 lbs of product what is the percentage of coloring I used to product. I need to increase the amount of product but maintain the correct percentage of coloring. thank you
Answer:
0.0042%
Step-by-step explanation:
We know that 1 pound is equivalent to 16 ounces.
So, 3 pounds of a product is equivalent to (16 × 3) = 48 ounces of the product.
Now, it is given that I add 0.002 ounces of coloring to 3 lbs of product.
So, the required percentage of coloring I used to product is [tex]\frac{0.002 \times 100}{48 + 0.002} = 0.0042[/tex]% (Answer)
PLEASEEEE HELPPPP
What is the y-coordinate?
The x-coordinate of the intersection point of BD and CE IS
2(a+c)
l.y=[*2]x-( 206 )
2.y=[22] 260701)-(2014
3. y = (a 2Jl 2(4+0) )-(2 626)
4. y = 2b(Q+c) -6bc
3(-20)
5, y = 2ab +2bc-6bc
3(2-2)
Answer: 2b/3 (second answer choice)
======================================
Explanation:
The work shown on the screenshot basically shows plugging x = 2(a+c)/3 into the y(x) function and then simplifying. Step 5 isnt fully simplified, so let's combine like terms, factor, and then divide out a pair of (a-2c) terms to get the following:
y = (2ab+2bc-6bc)/(3(a-2c))
y = (2ab-4bc)/(3(a-2c))
y = (2b*a-2b*2c)/(3(a-2c))
y = 2b(a-2c)/(3(a-2c))
y = 2b/3
Jackson has let out 50 meter of kite string when he observes that his kite is directly above a point on the ground 30 meters away from him, how high is the kite?
The height of the observer can be taken negligible in case of big measurements. The height of the kite from the ground is 40 meters approximately.
What is Pythagoras Theorem?If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
Referring to the figure attached below, we have the vertical distance of the kite from the ground as the length of the side BC.
(assume that the height of the observer flying kite is negligible and that kite's string is straight, and some more basic assumptions)
Using the Pythagoras theorem as the triangle ABC is a right angled triangle as vertical distance means line perpendicular to the ground, we get the length of the line segment BC as:
[tex]|AC|^2 = |AB|^2 + |BC|^2\\\\|BC|^2 = |AC|^2 - |AB|^2\\\\|BC| = \sqrt{|AC|^2 - |AB|^2}\\[/tex]
(positive root since length is a non-negative quantity).
We have |AC| = length of the kite's string = 50 meters
|AB| = distance of the observer from the point directly above which the kite is flying = 30 meters
Thus, we get the height of the kite from the ground as:
[tex]|BC| = \sqrt{|AC|^2 - |AB|^2}\\|BC| = \sqrt{50^2 - 30^2} = \sqrt{1600} = 40\: \rm \text{(in meters)}[/tex]
Thus, the height of the kite from the ground is 40 meters approximately.
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a.3/8
b.1/2
c.5/8
d.7/8
Answer:
3/8
Step-by-step explanation:
You'd first want to count all the triangles (possibilities) which is 8 total numbers
Then find the even numbers. There is 2, 2, and 4 which is a total of 3 even numbers
The fraction would be 3/8 and it can't be simplified any further
Answer:
3/8
Step-by-step explanation:
This is because, out of 8 results, only 3 of them are even numbers. That is the biggest chance you have at getting an even number.
Multiply. Use the greatest common factor to write each answer in
simplest form
3/4 • 2/3
Four runners formed a relay team at Jan’s high school. The team completed the relay in 3.86 minutes. Each runner ran exactly the Same time. What was each runners time?
Answer: All four runners ran .96 seconds
Step-by-step explanation: The total time of the four runners, divided by the amount of runners.
3.86/4= .965
Circle O is shown. Secant A C intersects tangent C D at point C outside of the circle. Secant A C intersects circle O at point B and tangent C D intersects circle O at point D. Point E is on arc A D. Angle A C D is 57 degrees. Aaron is standing at point C, watching his friends on a Ferris wheel. He knows that he is looking up at a 57° angle and the measure of arc BD is 80°. What is the measure of arc AED?
Answer:
the answer is 194
Step-by-step explanation:
bob bought bill an item that cost 193. bill gave him 200. bob then took 100 out of the 200 to buy bill an item for 93. how much does bill owe Bob totally?
Answer:Bob Owes $186 to the store he purchased an item at
Step-by-step explanation: