#1: What is the charge on an electrically neutral atom of hydrogen?

A. 1

B. 0

C. +1

D. +2
**My answer: B. 0

I believe the answer is C, hydrogen bonds. A water molecule consist of two hydrogen atoms bonded to an oxygen atom, and a bent overall structure. Water molecules can only form hydrogen bonds between the partially positively charged hydrogen atoms in water molecules and a partially negatively charged atom in another molecules say oxygen in another water molecule.

At STP, 1 mol = 22.4

1 mol = 6.022 X 10^ 23

so your answer is right it is B 6.022 X 10^ 23

They use a pH meter. The scale is called pH scale, any value below 7 is acidic

covalent  bond  is  a  bond  between  two  non  metal   and   it  involve  sharing   of  electrons  between  the  non    metals.  in  the  compounds  above  the one  which  are  covalent  include  the   following
B2H6,  HCl,  NH3, NO2  and  S2F4  since  their  bond  involve  between  two  non  metals

Answers:

B2H6

HCl

Sn(SO4)

NH3

Al(OH)3

NO2

S2F4

I did the quiz, it's correct.

by using this formula of vapor pressure:
Pv(solu)= n Pv(water) 
when we have Pv(solu)=231.16 torr & Pv(water)= 233.7 torr
from this formula, we can get n (mole fraction of water) by substitution:
231.16 = n * 233.7
∴ n(mole fraction of water) = 0.99
so mole fraction of solution = 1 - 0.99 = 0.01
when no.of moles of water = mass weight / molar weight
                                             = 365g / 18g/mol = 20 moles
Total moles in solution =  moles of water / mole fraction of water
                                      = 20 / 0.99 =20.2
no. of moles of the solution= total moles in solution- moles of water
                                              = 20.2 - 20 = 0.2 moles
when we assumed the mass weight of the solution = 16 g (missing in your question should be given)
∴ molar mass = mass weight of solute / no. of moles of solute
                        = 16 g / 0.2 mol = 80 g/mol
 

The answer is A) Aluminum Bromide 
hope this helps :)

Answer:

Aluminium bromide

Explanation:

Thinking process:

The aluminium bromide has the following structure:

[tex]AlBr_{3}[/tex]

The compound is a Lewis acid.

Aluminium bromide has a vacant p-orbital so it accepts a lone pair of electrons and acts as a Lewis acid.

Sodium bromide, on the other hand, donates electrons and acts as a Lewis base like this:

[tex]AlBr_{3} + Br^{-} = AlBr^{-} _{4}[/tex]

Thus, clearly the bromide ion is a base, and it donates electrons.

Answer: Molarity of solution is 0.751 M. 

Reason:
Given: weight of solute (LiF) = 17.8 g, volume of solution = 915 ml = 0.915 l

We know that,
Molarity = [tex] \frac{\text{weight of solute (g)}}{\text{Molecular weight X Volume of solution(l)}} [/tex]

Molecular Weight of LiF = 25.9 g/mol. 

∴, Molarity = [tex] \frac{17.8}{25.9X0.915} [/tex]
                 = 0.751 M

Answer:

0.751 M

Explanation:

Given:

Mass of LiF (solute), m = 17.8 g

Volume of water (solvent), V = 915 ml = 0.915 L

Formula:

Molar mass of LiF = 25.9 g/mol

[tex]Molarity = \frac{moles of solute}{Volume of solution}[/tex]

[tex]Moles LiF= \frac{Mass}{Molar Mass} = \frac{17.8 g}{25.9 g/mol} = 0.6873 moles[/tex]

[tex]Molarity = \frac{0.6873 moles}{0.915 L} = 0.751 moles/L[/tex]

Boron is 5th element in periodic table. It has the electronic configuration 1s², 2s² 2p¹. Where, the last three electrons are called valence electrons.

What is boron?

Boron is 5th element in periodic table. It is classified in 13th group of p-block in periodic table. Boron is known as metalloid based on its properties.

Metalloids are  elements showing properties intermediate to that of gases and metals. Other metalloids are silicon, arsenic etc.

The electronic configuration of en elements representing the filling of two electrons from lower energy levels to higher energy levels. each element have characteristic electronic configuration.

Boron have total 5 electrons in which 2 are inner electrons and three electrons are filled in the outermost shell hence its electronic configuration is written as 1s², 2s² 2p¹.

To find more on boron, refer here:

https://brainly.com/question/2790945

#SPJ6

The colors are separated into the rainbow colors of red, orange, yellow, green, blue, indigo and violet (I always remember ROY G BIV to remember the colors).

Hope this helps! :)

b)The number of protons.
c) their atomic masses are different.

Final answer:

The Calvin cycle is a process of carbon fixation in plants, where CO₂ is turned into organic molecules using RuBisCO. C3 plants experience photorespiration under high O₂ conditions due to closed stomata in dry weather, while C4 and CAM plants have adaptations to more efficiently fix CO₂.

Explanation:Calvin Cycle and Carbon Fixation in Plants

In plants, the Calvin cycle is significant for carbon fixation during photosynthesis. During this cycle, CO₂ is incorporated into organic molecules in the chloroplast's stroma through three main stages: fixation, reduction, and regeneration. The enzyme RuBisCO catalyzes the first major step of the Calvin cycle, where CO₂ and RuBP combine to form a six-carbon compound that quickly splits into two molecules of 3-phosphoglyceric acid (3-PGA), a three-carbon compound.

During hot and dry conditions, some plants (C3 plants) close their stomata to conserve water, leading to a rise in O₂ compared to CO₂ inside the leaf. This causes RuBisCO to add O₂ to RuBP instead, leading to a process called photorespiration, in which a two-carbon molecule is produced, is broken down to CO₂, and ATP is used without generating sugar—considered a wasteful process by some. Alternatively, C4 plants fix CO₂ into a four-carbon compound in a separate compartment to overcome low CO₂ concentrations and shuttle this compound to bundle-sheath cells, where it releases CO₂ for fixation by RuBisCO.

Additionally, cam plants open stomata at night to fix CO₂ into a four-carbon compound, storing it until daylight when it releases CO₂ for the Calvin cycle, adapting to arid conditions. All three types of plants ultimately depend on RuBisCO to incorporate CO₂ into the Calvin cycle to produce sugars needed for growth and energy storage.

In photosynthesis, the Calvin Cycle initiates carbon fixation, producing the three-carbon compound 3-phosphoglycerate (3-PGA). On hot, dry days, plants close stomata to conserve water, leading to the buildup of oxygen and the wasteful process of photorespiration. Some plants adopt C4 or CAM pathways to optimize carbon fixation and minimize water loss. In the C4 pathway, CO2 is first fixed into a four-carbon compound, while in CAM plants, this occurs at night. Despite these adaptations, all plant types rely on the enzyme RuBisCO to bring CO2 into the Calvin Cycle, driving the synthesis of organic molecules essential for plant growth.

1. In the Calvin Cycle, the first product of carbon fixation is the three-carbon compound 3-phosphoglycerate (3-PGA). This process occurs in the stroma of chloroplasts during photosynthesis.

2. When plants close their stomata on hot, dry days to conserve water, oxygen (O2) builds up in the leaf and is added to ribulose-1,5-bisphosphate (RuBP) in place of carbon dioxide (CO2). This process is called photorespiration. A two-carbon product, glycolate, is formed and later broken down to CO2, consuming ATP and generating no sugar.

3. The apparently wasteful process described in sentence 2 is called photorespiration. While it consumes energy and does not contribute to sugar production, it is considered wasteful because it counteracts the efficiency of the Calvin Cycle in fixing carbon.

4. In certain plants, CO2 is first fixed into a four-carbon compound, oxaloacetate, through the C4 pathway. This compound moves into bundle-sheath cells, where it releases CO2 to the Calvin Cycle. This adaptation enhances the efficiency of carbon fixation, especially in conditions with high temperatures and intense sunlight.

5. In CAM (Crassulacean Acid Metabolism) plants, stomata are open at night, and CO2 is first fixed into a four-carbon compound, malate. This compound releases CO2 to the Calvin Cycle during the day, allowing plants to reduce water loss by opening stomata during cooler nighttime hours.

6. In all three types of plants (C3, C4, and CAM), the enzyme ribulose-1,5-bisphosphate carboxylase/oxygenase (RuBisCO) brings CO2 into the Calvin Cycle. RuBisCO catalyzes the initial step of carbon fixation by incorporating CO2 into RuBP, initiating the synthesis of organic molecules in the Calvin Cycle.

. Life exists only on Earth because water exists as a gas on earth

Hello!

Water exists on other planets in the solar system. Life exists only on Earth because water exists as a liquid on Earth.

Why?

The boiling point of water is 100 °C and the freezing point is 0 °C. A normal temperature on Earth is 25 °C, meaning that water is generally found in the liquid state on Earth.

Liquid water is essential for life because it is at the same time an essential molecule for photosynthesis (the basis of all energy processes needed for life), and a medium where nutrients and waste circulate in living beings.

Have a nice day!

Answer is: volume of carbon dioxide is 1,84·10⁸ l.
Chemical reaction: C + O₂ → CO₂.
m(C) = 100 t · 1000 kg/t = 100000 kg 
m(C) = 100000 kg · 1000 g/kg = 10⁸ g.
n(C) = m(C) ÷ M(C).
n(C) = 10⁸ g ÷ 12 g/mol.
n(C) = 8,33·10⁶ mol.
From chemical reaction: n(C) . n(CO₂) = 1 : 1.
n(CO₂) = 8,33·10⁶ mol.
m(CO₂) = 8,33·10⁶ mol · 44 g/mol.
m(CO₂)  = 3,66·10⁸ = 3,66·10⁵ kg.
V(CO₂) = 3,66·10⁵ kg ÷ 1,98 kg/m³ = 1,84·10⁵ m³.
V(CO₂) = 1,84·10⁵ m³ · 1000 l/m³ = 1,84·10⁸ l.

The patient received 2839.059mL.

Answer : The volume of plasma given to the patient were, [tex]2.8\times 10^{3}ml[/tex]

Explanation :

As we are given that a patient receives 6.0 pints of plasma. Now we have to calculate the volume in milliliters.

As we know that, 1 pints is equal to 473.176 milliliters.

As, 1 pints = 473.176 milliliters

So, 6.0 pints = [tex]\frac{473.176milliliters}{1pint}\times 6.0pints=2839.056milliliter[/tex]

The volume in milliliters to two significant figures is, [tex]2.8\times 10^{3}ml[/tex]

Therefore, the volume of plasma given to the patient were, [tex]2.8\times 10^{3}ml[/tex]

1. An allotrope of carbon that is soft and can be used as a lubricant is d. graphite.
Graphite is the most stable allotrope of carbon under standard conditions (pressure and temperature). In graphite carbon atoms have sp2 hybridization, because of that graphite has ability to conduct electricity and heat.

2. The process by which a solid changes directly to a gas without first becoming a liquid is called c. sublimation.
Sublimation is an endothermic process. For example dry ice (carbon(IV) oxide in solid state) is used because of sublimation in nightclubs, fog machines, at theaters, haunted house attractions.

3. In the gaseous state d. halogens form diatomic covalent molecules.
Halogen diatomic molecules (17 group in the periodic table, halogen means "salt producing) in the gaseous state in room temperature are fluorine (F₂) and chlorine (Cl₂). Both molecules have single covalent bond and they are very reactive.

4. When hydrogen reacts with the active metals, it b. gains one electron.
Active metals are I group of Periodic table of elements (alkaline metals). Alkaline metals are lithium, sodium, rubidium, potassium, cesium. They have low ionization energy and lose one electron very easy. Compounds with hydrogen with this metals are called hydrides.

5. Different forms of the same element that have different properties because of different atom arrangements are called a. allotropes.
Carbon has many allotropes, but two most important are graphite and diamomd. Graphite has sp2 and diamond has sp3 hybridization of carbon atoms, because of that graphite conduct electricity and diamond not.

6. At room temperature, most metals are b. solids.
Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.
They also form crystal lattice and because of that has high melting points.

7. An allotrope of carbon that is hard and is often used in jewelry is b. diamond.
In diamond carbon atoms are arranged in the face centered cubic crystal structure called a diamond lattice.
Diamond has very strong covalent bonds between carbon atoms and because of that it has the highest hardness and thermal conductivity of any bulk substance. 

8. Metals can be used as wire because they are a. ductile.
Ductility is a measure of a material's (in this example metal) ability to undergo deformation before rupture. For example gold is very ductile and can be drawn into a monoatomic wire.
Malleability is a material's ability to deform under compressive stress.

9. The d. transition elements often occur in nature as uncombined elements.
Uncombined elements are in elemental form and do not attache with other elements. Several transition elements (metals) like gold, silver, rhodium, palladium and platinum are unreactive and are resistant to oxidation and corrosion.

Answer: Nothing; the reaction will stay at equilibrium

There is no change in concentration at equilibrium because the rate of product formed is equal to the rate of product breakdown. When an enzyme is added, the rate of product formed and breaks will be increased. This will not shift the equilibrium because the rate of reaction is increased in both ways.