1. What is the variable on the X-axis of a solubility curve?
A.Temperature
B.Time
2. _________ grams of sugar will dissolve in 100 g of solution at 90° C.
A.80.61
B.91.76
3. The units of solubility in this video are grams of _________/grams of solution.
A. Water
B. Sugar
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Answer:

0.09 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

From the question, expression for acceleration is given as

F' = ma  

Using Pythagoras Theory,

√(F₁²+F₂²) = ma................... Equation 1

Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.

make a the subject of the equation

a = √(F₁²+F₂²) /m................ Equation 2

Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,

Substitute into equation 2

a = [√(64²+38²)]/825

a = {√(5540)}/825

a = 74.43/825

a = 0.09 m/s²

The magnitude of the acceleration of the boulder, with a mass of 825 kg being pushed with forces of 64 N northward and 38 N westward, is approximately 0.09 m/s² assuming negligible friction.

To predict the magnitude of the acceleration of the boulder, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass (a = F/m). Since the forces are applied in perpendicular directions (north and west), we can treat them as components of a resultant force vector and calculate the resultant force using Pythagoras' theorem: Fr = sqrt(Fn² + Fw²), where Fn is the northward force and Fw is the westward force.

By plugging the given values into the equation, we get Fr = √((64 N)² + (38 N)²) = √(4096 + 1444) = √(5540) N  ≈ 74.43 N. We then divide this resultant force by the mass of the boulder to find the acceleration: a = Fr / m = 74.43 N / 825 kg ≈ 0.09 m/s².

The magnitude of the acceleration of the boulder, assuming negligible friction, is approximately 0.09 m/s².

Answer:

Their number should increase

Explanation:

The photoelectric effect is a phenomenon that causes the ejection of electrons from that metal as light shined onto a metal surface. Only certain frequencies of light can cause the ejection of electrons. However, if the frequency of the incident light is too low then no electrons were ejected even if the intensity of the light was very high. If the frequency of the light was higher then electrons were able to be ejected from the metal surface even if the intensity of the light was very low.

According to the accepted wave theory, light of any frequency will cause electrons to be emitted. Kinetic energy emitted by the electrons depends upon the intensity of light.

According to the accepted wave theory, number of electrons being ejected by the metal should increase

The correct option is Their number should increase. According to classical wave theory, an increase in light intensity should increase the number of ejected electrons in the photoelectric effect. However, experiments show that the kinetic energy depends on the light's frequency, not intensity.

The phenomenon being described here is known as the photoelectric effect, which is a key piece of evidence for the particle nature of light. The classical wave theory of light predicted that the kinetic energy of ejected electrons should increase with the intensity of the light.

However, experiments have shown that the kinetic energy of the ejected electrons depends on the frequency of the light, not its intensity, and no electrons are ejected below a certain threshold frequency, regardless of the light's intensity.

Given the choices in the question, none exactly match the expectations from classical wave theory. However, based on the wave theory, one might erroneously expect that as the intensity of light increased, the number of ejected electrons (if any) would increase, which is the closest option provided.

Answer:

See explanation

Explanation:

Acceleration is defined as the change in velocity. In other words, if your velocity changes, then you are accelerating. And since velocity is a vector of both speed and direction, you don't have to be speeding up to be accelerating, you could also just be turning. Hope this helps!

Acceleration is the change in velocity of an object, can involve speed or direction, and is measured as a vector quantity. It is notably expressed in physics by Newton's Second Law, F = ma, and experienced through everyday examples like using a car's accelerator.

In physics, acceleration is defined as the rate at which the velocity of an object changes over time. This can include changes in speed, direction, or both. It is a vector quantity, which means it has both magnitude and direction. Acceleration occurs when a force is applied to a mass, described by Newtons Second Law, with the equation F = ma, indicating that force (F) is the product of mass (m) and acceleration (a). The SI unit for measuring acceleration is meter per second squared (m/s²).

In casual conversation, to 'accelerate' often means simply to speed up. An example of this is using the accelerator pedal in a car, which increases the vehicle's speed. This effect of acceleration, the increase in velocity, conforms to the physical definition, though in a broader sense, acceleration encompasses any change in velocity, not just speeding up.

We usually experience acceleration in daily life through the steady increase in speed due to gravity when an object falls, known in physics as gravitational acceleration. However, acceleration in a technical sense involves any alteration in uniform motion, whether it's a change in speed or a change in direction.

Summary: Acceleration, a change in velocity, signifies a change in either the speed or the direction of an object, veering from its original motion path due to the application of an external force.

Answer:

(a) orbit the galactic center just as fast as stars closer to the center.

Explanation:

The orbital speed is defined as:

[tex]v = \sqrt{\frac{G M}{r}}[/tex]  

Where v is the orbital speed, G is the gravitational constant, M is the mass of the supermassive black hole, and r is the orbital radius.

If the distance increase the orbital speed decreases (inversely proportional).

However, the results of the measurements of the orbital speed of the star in the outskirts of the Milky way show that in fact, they orbit the galactic center as fast as the star closer to the center.  

Dark matter in the other hand was born to explain why stars that were farther from the supermassive black hole in the center of the Milky Way galaxy didn't decrease its orbital speed as it was expected since the contribution of more matter in that region is the only explanation to that weird behavior.

Answer:

the answer is in the question 80 km in an hour

Explanation

The average speed of a train that travels 80 km in 1 hour, 200 km in 2 hours, and 420 km in 4 hours is 100 km/h, calculated by dividing the total distance (700 km) by the total time (7 hours).

The student is asking about how to calculate the average speed of a train that covers different distances over different time intervals. To find the average speed, we need to combine the total distance traveled with the total time taken.

First, we add up all the distances: 80 km + 200 km + 420 km = 700 km.
Then, we add up all the time intervals: 1 h + 2 h + 4 h = 7 h.
Finally, we divide the total distance by the total time to get the average speed:

Average speed = Total distance / Total time = 700 km / 7 h = 100 km/h.

The average speed of the train over the entire journey is 100 km/h.

Answer:

Technician B is actually correct

The automobile Ignition systems have two circuits that result in a spark being fired at the end of a spark plug. The primary circuit is between the battery and the ignition coil. The secondary circuit is between the ignition coil and the spark plug.

Explanation:

1. The primary circuit carries low voltage. This circuit operates only on battery current and is controlled by the breaker points and the ignition switch. When the ignition key is turned on, a low voltage current from the battery flows through the primary windings of the ignition coil, through the breaker points and back to the battery. This current flow causes a magnetic field to form around the coil.

2. The secondary circuit consists of the secondary windings in the coil, the high tension lead between the distributor and the coil on external coil distributors, the distributor cap, the distributor rotor, the spark plug leads and the spark plugs. As the engine rotates, the distributor shaft cam turns until the high point on the cam causes the breaker points to separate suddenly. Instantaneously, when the points open (separate) current flow stops through the primary windings of the ignition coil. This causes the magnetic field to collapse around the coil. The condenser absorbs the energy and prevents arcing between the points each time they open. This condenser also aids in the rapid collapse of the magnetic field.

Answer:

Because of unstable membrane potentials

Explanation:

Autorhythmic cells are specialized cardiac muscle cells in the heart from which electrical impulses called action potentials originate. These cells can generate electrical impulses without any external simulations by the nerve cells. I.e. they are self – excitable.

Autorhythmic cells spontaneously create action potentials because they have an unstable resting or membrane potentials that continuously depolarizes, drifting slowly toward threshold. As sodium ions enter the cell, the inner surface of the plasma membrane gradually becomes less negative, generating the pacemaker potential.

Though their is an influx of sodium ions into the cell, the basic reason for the spontaneous generation of action potentials solely because of unstable membrane potentials. and not majorly due to the influx of sodium ion.

Autorhythmic cells can generate action potentials spontaneously due to the presence of L-type Ca2+ channels.

Autorhythmic cells are a type of specialized cells found in the heart. Unlike regular cardiac muscle cells, autorhythmic cells can generate action potentials spontaneously without external stimuli. This is due to the presence of L-type Ca2+ channels.

These channels allow the entry of calcium ions, which triggers the depolarization phase of the action potential. The influx of calcium ions leads to the opening of voltage-gated potassium channels and closure of calcium channels, helping restore the resting membrane potential.

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Answer:

B.) Y,W,Z,X

Explanation:

Edge 2021

Assuming letters represent current strengths in descending order, the correct answer for the list ordered from most bright to least bright is option (b) YWZX.

The relationship between the brightness of a light bulb and the current that powers it is such that a brighter bulb corresponds to a greater current when other factors such as voltage and bulb type are held constant.

To order the currents from greatest to least based on brightness, we would start with the highest current and move to the lowest. Since the question does not provide specific current values for W, X, Y, and Z, the best we can do is rely on the principle that higher current leads to greater brightness.

Given this, and assuming that W > X > Y > Z or some similar relationship, the order from most bright to least bright would be from the letter associated with the highest current to the lowest.

So if 'Y' represents the largest current and 'W', 'Z', and 'X' follow in decreasing order, the correct answer would be: (b) YWZX

Answer:

3688 km/h

Explanation:

Given:-

- The speed of vehicle relative to earth, vs_e = 3760 km/h

- The relative speed of command and motor, v_c/m = 90 km/h

- The mass of command = m

- The mass of motor = 4m

Find:-

What is the speed of the command module relative to Earth just after the separation?

Solution:-

- Consider the space vehicle as a system that detaches itself into two parts ( command and motor ). We will assume that the gravitational pull due to Earth on the space vehicle is negligible. With that assumption we have our system in isolation. We will apply the principle of conservation of linear momentum on the system as follows:

             Initial momentum = Final momentum

                                       Pi = Pf

                  M*vs_e = m*vc_e + 4m*vm_e

Where,

                  M = m + 4m = 5m

                  vc_e = Velocity of command relative to earth

                  vm_e = Velocity of motor relative to earth  

- We will develop a relation of velocities of command and motor in the frame of earth as follows:

                  vm_e =  v_c/m + vc_e        

- Substituting (vm_e) from Equation 2 into Equation 1, we have:

                  5m*vs_e = m*vc_e + 4m*(v_c/m + vc_e)

                  5m*vs_e = 5m*vc_e + 4m*(v_c/m)

- Solve for vc_e:

                  5m*vs_e -  4m*(v_c/m) = 5m*vc_e

                   vs_e - 0.8*(v_c/m) = vc_e

- Plug in values and evaluate vc_e:

                  vc_e = 3760 - 0.8*(90)

                  vc_e = 3,688 km/h

Answer:

The command module is traveling at 3832 km/h after the separation.

Explanation:

Let's call the mass of the module M, and the mass of the motor is 4M. The total mass of the vehicle, then, is M + 4M = 5M.

Now, momentum = force x distance.

Thus, momentum of the vehicle before separation 3760 x 5M = 18800M kg-km/h.

Let's call the velocity of the motor v. So the velocity of the module must be v + 93.

Now, after the separation, the momentum of the motor will be 4Mv, and the momentum of the module is M(v + 90) = Mv + 90M. The total momentum is 4MV + Mv + 90M = 5Mv + 90M.

From conservation of momentum that says initial momentum equals final momentum, we have;

18800M = 5Mv + 90M

Divide both sides by M to get;

18800 = 5v + 90

18800 - 90 = 5v

18710 = 5v

v = 18710/5

v = 3742 km/h

But v is the velocity of the motor, so we have to add 90 to get the velocity of the module, thus, velocity of module = 3742 + 90 = 3832

So the command module is traveling at 3832 km/h after the separation.

Final answer:

Using the equations of projectile motion and accounting for the initial height of 3.5 m, we find that the soccer ball is approximately 2.4 m above the ground at 0.32 seconds after being kicked horizontally from the roof.

Explanation:

To determine how far above the ground the soccer ball is at 0.32 seconds after being kicked horizontally from a height of 3.5 m, we can use the equations for projectile motion. Specifically, we only need to consider the vertical motion because the horizontal velocity does not affect the height at which the ball is above the ground.

The vertical position of the ball (y) at any time (t) can be given by:

y = y0 + (v0y · t) + (½ · g · t²)

Where:

y0 = initial vertical position

v0y = initial vertical velocity (0 m/s for horizontal launch)

g = acceleration due to gravity (approximately -9.8 m/s²)

t = time (0.32 s in this case)

Given that the ball is launched from the roof horizontally, the initial vertical velocity (v0y) is 0 m/s, and the initial height (y0) is 3.5 m. Plugging in the values:

y = 3.5 m + (0 m/s · 0.32 s) - (½ · 9.8 m/s² · (0.32 s)²)

Upon simplifying, we find that the ball is approximately 2.4 m above the ground at 0.32 seconds.

Answer:

a) The speed is 61.42 m/s

b) The drag force is 10.32 N

Explanation:

a) The Reynold´s number for the model and prototype is:

[tex]Re_{m} =\frac{p_{m}V_{m}L_{m} }{u_{m} }[/tex]

[tex]Re_{p} =\frac{p_{p}V_{p}L_{p} }{u_{p} }[/tex]

Equaling both Reynold's number:

[tex]\frac{p_{p}V_{p}L_{p} }{u_{p} }=\frac{p_{m}V_{m}L_{m} }{u_{m} }[/tex]

Clearing Vm:

[tex]V_{m} =\frac{p_{p}V_{p}L_{p} u_{m} }{u_{p} p_{m} L_{m} }=\frac{999.1*0.56*8*1.849x10^{-5} }{1.138x10^{-3}*1.184*1 } =61.42m/s[/tex]

b) The drag force is:

[tex]\frac{F_{Dm} }{p_{m}V_{m}^{2}L_{m}^{2} } =\frac{F_{Dp} }{p_{p}V_{p}^{2}L_{p}^{2} } \\F_{Dp} =\frac{F_{Dp}p_{p}V_{p}^{2}L_{p}^{2} }{p_{m}V_{m}^{2}L_{m}^{2} } \\F_{Dp}=\frac{2.3*999.1*0.56^{2} *8^{2} }{1.184*61.42^{2}*1^{2} } =10.32N[/tex]

Answer:

1. The air speed at which wind tunnel should be ran in order to achieve similarity = 61.423 m/s

2. The drag force on the prototype submarine at the conditions given above = 10.325 N.

Explanation:

1. Here we have

Density of water at 15 °C = 999.1 kg/m³

Density of air at 25 °C = 1.184 kg/m³

[tex]\mu_{Water}[/tex] at 15 °C = 1.138 × 10⁻³ kg/(m·s)

[tex]\mu_{Air}[/tex] at 25 °C = 1.849 × 10⁻⁵ kg/(m·s)    

The formula is

[tex]\frac{V_m\times \rho_m \times L_m}{\mu_m} = \frac{V_p\times \rho_p \times L_p}{\mu_p}[/tex]

Where:

[tex]V_m[/tex] = Velocity of the model =

[tex]\rho_m[/tex] = Density of the model medium at the medium temperature = 1.184 kg/m³

[tex]L_m[/tex] = Length of the model = 1/8 × [tex]L_p[/tex] = 0.28 m

[tex]\mu_m[/tex] = Dynamic viscosity of model medium at the model medium temperature = 1.849 × 10⁻⁵ kg/(m·s)

[tex]V_p[/tex] = Velocity of the prototype = 0.560 m/s

[tex]\rho_p[/tex] = Density of the prototype medium at the medium temperature = 999.1 kg/m³

[tex]L_p[/tex] = Length of the prototype = 2.24 m

[tex]\mu_p[/tex] = Dynamic viscosity of prototype medium at the prototype medium temperature 1.138 × 10⁻³ kg/(m·s)

Therefore

[tex]{V_m}{} = \frac{V_p\times \rho_p \times L_p \times \mu_m}{\mu_p\times \rho_m \times L_m}[/tex]

[tex]{V_m}{} = \frac{0.560\times 999.1 \times 2.24 \times 1.849 \times 10^{-5}}{1.138 \times 10^{-3}\times 1.184 \times 0.28}[/tex] =  61.423 m/s

The air speed at which wind tunnel should be ran in order to achieve similarity = 61.423 m/s

2. The drag force on the prototype is given by    

[tex]F_{D.p} = F_{D.m}(\frac{\rho_p}{\rho_m} )( \frac{V_p}{V_m})^2 ( \frac{L_p}{L_m})^2\\[/tex]

Where:

[tex]F_{D.p}[/tex] = Drag force of the prototype

[tex]F_{D.m}[/tex] = Drag force of the model

[tex]F_{D.p} =2.3(\frac{999.1 }{1.184} )( \frac{0.560 }{61.423 })^2 ( \frac{2.24 }{0.28})^2\\[/tex] =   10.325 N

The drag force on the prototype submarine at the conditions given above = 10.325 N.

Answer:

The  answer is electromagnetic waves can travel through a region void of matter and mechanical waves cannot (option C)

Explanation:

To begin with, electromagnetic waves are waves that are created due to vibrations between a magnetic and electric field. On the other hand, mechanical waves are waves that are created due to vibration in matter or energy transfer through a material medium.

Electromagnetic waves are quite distinct from mechanical waves because the latter requires a material medium to transport energy while the former does not. In fact, electromagnetic waves can carry out transportation of energy through the vacuum of outer space.

Answer:

Net Force= -7.8N

Explanation:

fist start by solving the weight of the ball, this means the force pushing the ball down and the mass of the ball combined. we know that the force acting on the ball is gravity. the force of gravity is equivalent to 9.8m/s^2

weight formula w=mg. w= weight m= mass g= gravity

w=1kg(9.8m/^2)

w=9.8kg.m/s^2

w=9.8N

Simply add the two forces together to get the net force. The weight 9.8N is negative since it is directed downwards, while the air resistance 2N is positive since it is directed upwards.

Fnet= -9.8N+2N

Fnet= -7.8N

A 1-kg ball falling to the earth experiences a gravitational force of 9.8 N. With air resistance of 2 N, the net force acting on the body is 7.8 N.

The net force acting on a 1-kg ball falling due to gravity can be calculated by using Newton's second law. The gravitational force (weight) is equal to the mass times the gravity acceleration on Earth's surface. Thus, it is 1 kg times 9.8 m/s^2, which equals 9.8 N. However, the object encounters air resistance of 2 N, therefore, the net force on the object would be the gravitational force minus the air resistance: 9.8 N - 2 N = 7.8 N.

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The solution with 10 grams of sugar per liter is hypertonic to the one with 5 grams of sugar per liter. Comparatively, the solution with 45 grams of sugar in 100 mL of water is much more hypertonic than both. The cup with more sugar has less water compared to the cup with less sugar due to the displacement of water by sugar.

When comparing two sugar solutions with different amounts of sugar but the same volume of water, the solution with more sugar is considered hypertonic, and the one with less sugar is hypotonic. In the given scenario, a student created two solutions by dissolving different amounts of sugar in equal volumes of water. The first solution with 5 grams of sugar is hypotonic compared to the second solution, which has 10 grams of sugar in the same volume of water (1 liter), making the second solution hypertonic to the first.

To further illustrate this with a different example, if you have 100 mL of water and add 45 grams of sugar, you will have a more concentrated (hypertonic) solution compared to a solution where you add a lesser amount of sugar to the same volume of water. This is because the hypertonic solution has a greater solute concentration. Comparatively, the solution with lesser sugar concentration, in this case, 5 grams per liter, would be hypotonic to the one with higher sugar concentration, which is 10 grams per liter or even more substantially to the one with 45 grams in 100 mL.

Therefore, when the volume is the same, the cup with the larger amount of sugar has less water due to the space taken by the sugar, and vice versa. This scenario is another way to understand the concept of hypertonic and hypotonic solutions based on solute concentration and the displacement of the solvent (water) by the solute (sugar).

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

Answer:

Final temperature = 23.4 °C

Explanation:

The idea here is that the heat lost by the metal will be equal to the heat gained by the water.

In order to be able to calculate the final temperature of the iron + water system, we need to know the specific heats of water and iron which are;

C_water = 4.18 J/g°C

C_iron = 0.45 J/g°C

The formula to determine the determine the amount of heat lost or gained is given by;

q = m•c•ΔT

q = heat lost or gained

m = the mass of the sample

c = specific heat of the substance

ΔT = the change in temperature, defined as final temperature minus initial temperature

Now, -q_water = q_iron

The negative sign is used here because heat lost carries a negative sign. Let's say that the final temperature of the iron + water system will be T_f

Thus, we can say that the changes in temperature for the iron and for the water will be;

ΔT_iron = T_f − 550 °C

and ΔT_water = T_f − 20 °C

This means that we will now have;

−m_iron•c_iron•ΔT_iron = m_water•c_water•ΔT_water

This now gives us ;

−m_iron•c_iron•(T_f − 550°C) = m_water•c_water•(T_f − 20°C) - - - - (eq1)

Notice that the specific heats for these two substances is given per gram. This means that you will have to

Mass of iron = 1.5 kg = 1500g

Mass of water = 25 kg = 25000 g

Plugging the relevant values into eq(1),we have;

−(1500g)•(0.45 J/g°C)•(T_f − 550°C) = (25000 g)•(4.18 J/g°C)•(T_f − 20°C)

Multiplying out to get;

-675(T_f − 550) = 104,500(T_f − 20)

-675T_f + 371,250 = 104,500T_f - 2090000

371,250 + 2090000 = 104,500T_f + 675T_f

2461250 = 105175T_f

T_f = 2461250/105175 = 23.4 °C

Answer: one brain... humans have one brain

Explanation: humans have many parts of the brain but they only have one brain there are left brain right brain people. Right brain tends to me more creative and left brain is more logical but its is all still the same brain you just use different parts of the brain at one time

Answer:

Net filtration pressure

Explanation:

The net filtration pressure is the outward pressure minus the inward pressure. Figure of a glomerular capsule with glomerular hydrostatic pressure, blood colloid osmotic pressure, and capsular hydrostatic pressure.

The sum of all of the influences, both osmotic and hydrostatic, results in a net filtration pressure (NFP) of about 10 mm Hg. A proper concentration of solutes in the blood is important in maintaining osmotic pressure both in the glomerulus and systemically.

the soccer player maintains contact with the ball for approximately 0.0121 seconds.

We can use the impulse-momentum theorem to solve this problem. The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. Impulse [tex](\( J \))[/tex] is the product of force[tex](\( F \)) and time (\( \Delta t \)).[/tex]

[tex]\[ J = F \times \Delta t \][/tex]

Given:

- Change in momentum[tex](\( \Delta p \))[/tex]= 11 kg·m/s

- Net force[tex](\( F \))[/tex] = 910 N

Using the formula for impulse, we can rearrange it to solve for time[tex](\( \Delta t \)):[/tex]

[tex]\[ \Delta t = \frac{\Delta p}{F} \][/tex]

Substitute the given values:

[tex]\[ \Delta t = \frac{11 \, \text{kg·m/s}}{910 \, \text{N}} \]\[ \Delta t = \frac{11}{910} \, \text{s} \]\[ \Delta t \approx 0.0121 \, \text{s} \][/tex]

Therefore, the soccer player maintains contact with the ball for approximately 0.0121 seconds.

Answer:

A

Explanation:

ED GU NU IT Y PE OP LE

The mass defect of a carbon-14 nucleus is (6mp + 8mn) – mc – 14.

To find the correct option among all the options, we need to know about the mass defect.

Mathematically, mass defect is given as

∆m = mass of all nucleons - mass of nucleus

= Mass of protons + mass of neutrons - mass of nucleus

Thus, we can conclude that the option (a) is correct.

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Answer:

C. 441 N

Explanation:

Gravitational force between two objects can by calculated by the formula

= G m₁m₂ / r² , m₁ and m₂ are masses at distance r

= ( 6.67 x 10⁻¹¹ x 45 x 5.98 x 10²⁴) / ( 6.38 x 10⁶ )²

= 44.09 x 10

= 440.9 N

= 441 N .  

Answer:

B.It is a satellite that collects data about rain and snow

C.Its orbit covers 90 percent of Earth’s surface

F.The sensors measure microwaves

Answer: B, C, F

Explanation:

I got it right

Answer:

The torque applied to the nut is 34.6 N-m.

Explanation:

Given that,

Length of the wrench, l = 0.5 m

Force applied by the wrench, F = 80 N

The force must be exerted upward and at an angle of 60.0 degrees, with respect to a line from the bolt through the end of the wrench.

Torque applied to the nut is given by :

[tex]\tau=Fr\ \sin\theta\\\tau=80\times 0.5\ \sin(60)\\\tau=34.6\ N.m[/tex]

So, the torque applied to the nut is 34.6 N-m.

Answer:

variations in great horned owl body size due to food supply can be acted on by natural selection.

Explanation:

Natural selection can help select great horned owl with smaller body size since it's an advantage in a place with smaller available food sources, compared to a bigger body size that will need more food. At first, birds with smaller body survive while those bigger ones die out, and the smaller birds pass on this genes to their offspring.

Answer:

variation in body size due to inherited traits can be acted on by natural selection

Explanation :

Variations in body size in body size due to inherited trait can be acted upon by natural selection by favoring the size that is best suited for the survival of the species. Those with these genes survive and pass it on to their offspring, while those with the unfavorable body size are wiped out.

Variations in body size of the Great Horned Owl can be acted on by natural selection, both due to food supply and inherited traits.

Variations in body size of the Great Horned Owl due to food supply can be acted on by natural selection. When there is a shortage of food, smaller individuals with less energy requirements may be favored, while in times of plenty, larger owls with higher energy needs may have an advantage. On the other hand, variation in body size due to inherited traits can also be acted on by natural selection.

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Answer:

Magnetize: place in magnet field, rub on permanent magnet, pass electricity through

Demagnetize: heat, strike, place in opposite polarity

Explanation:

Final answer:

Ferromagnetic materials can be magnetized by aligning their magnetic domains with an external magnetic field, which may become permanent, making them permanent magnets. Demagnetization occurs when these domains are misaligned due to heat, physical disturbance, or an opposing magnetic field.

Explanation:

Ferromagnetic materials such as iron, cobalt, nickel, and gadolinium exhibit strong magnetic effects. These materials can become magnetized in the presence of an external magnetic field due to the alignment of their magnetic domains. Magnetization occurs when the domains within the ferromagnetic material align with the magnetic field lines, and this alignment can become permanent, turning the material into a permanent magnet. Conversely, demagnetization can occur when these domains lose their alignment, often due to factors such as heat, hammering, or an opposing magnetic field.

Demagnetization typically happens when the material is heated to its Curie temperature, at which point the ferromagnetism disappears. Alternatively, demagnetization can occur when the material is exposed to an external magnetic field in a direction opposite to the magnet's existing fields, or through physical disturbance such as dropping or hammering.

Answer:

Velocity of the teen = 5m/s

Mass of the truck = 100kg

Explanation:

Momentum can be found with the equation

P = m * v

Where P is momentum in kg*m/s, v is velocity in m/s and m is mass in kg.

Substitute in our values and solve for the unknowns

1.) P = m * v

250 = 50 * v

Divide both sides of the equals by 50 to solve for v

250/50 = v * 50/50

v = 5m/s

2.) P = m * v

20500 = m * 205

Divide both sides of the equals by 205 to solve for m

20500/205 = m * 205/205

m = 100kg

Answer:

The correct option is A (TRUE)

Explanation:

International Electrotechnical Commission (IEC) which was first formed in 1906 is the predominant organization for developing and publishing international standards for technologies related to electrical and electronic devices and processes. The standards developed by this association are widely used in scientific fields such as power generation, semiconductors, fibre optics, batteries, solar energy, nanotechnology and marine energy. They also proposed the International System of Units( SI unit) used in many fields of study today.

A coefficient called the Avogadro's number is used to calculate the number of atoms in each molecule.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number.

Learn more about Avogadro's number,here:

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Answer:

The unknown frequency is either 438 Hz or 442 Hz.

Explanation:

The frequency of a beat heard when two sounds with frequencies f₁ and f₂, are played simultaneously, is simply the difference between two frequencies.

b = |f₁ - f₂|

b = 2 Hz

f₁ = 440 Hz

f₂ = ?

440 - f₂ = 2 or 440 - f₂ = -2

f₂ = 438 Hz or 442 Hz

The unknown frequency is either 438 Hz or 442 Hz.

Hope this Helps!!!

1) [tex]-9.3rad/s^2[/tex]

2) 3.0 s

Explanation:

1)

The angular acceleration of a rigid body in rotation can be  found by using the equivalent of Newton's second law for rotational motions:

[tex]\tau = I\alpha[/tex] (1)

where

[tex]\tau[/tex] is the torque on the object

I is the moment of inertia of the object

[tex]\alpha[/tex] is the angular acceleration

Here we have:

[tex]I=\frac{2}{5}MR^2[/tex] is the moment of inertia of a solid sphere about its central axis, where

M = 240 g = 0.240 kg is the mass of the sphere

R = 4.50 cm /2= 2.25 cm = 0.0225 m is the radius of the sphere

[tex]\tau = F r[/tex] is the torque exerted by the frictional force, where

[tex]F=-0.0200 N[/tex] is the force of friction (negative because the direction is opposite to the motion)

r = R = 0.0225 m is the distance of the point of application of the force from the centre

Substituting into eq(1) we find

[tex]FR=\frac{2}{5}MR^2 \alpha[/tex]

And solving for [tex]\alpha[/tex], we find the angular acceleration:

[tex]\alpha = \frac{5F}{2MR}=\frac{5(-0.0200)}{2(0.240)(0.0225)}=-9.3rad/s^2[/tex]

2)

Here we know that the motion of the sphere is an angular accelerated motion.

Therefore, we can use the equivalent of suvat equations for rotational motion:

[tex]\omega_f = \omega_i +\alpha t[/tex]

where

[tex]\omega_f[/tex] is the final angular velocity

[tex]\omega_i[/tex] is the initial angular velocity

[tex]\alpha[/tex] is the angular acceleration

t is the time

In this problem, we know that

[tex]\omega_f-\omega_i = -28.0 rad/s[/tex], since we are told that the rotational speed decreases by 28.0 rad/s

[tex]\alpha=-9.3 rad/s^2[/tex] is the angular acceleration of the sphere

Solving for t, we find how long it takes for the sphere to decelerate by 28.0 rad/s:

[tex]t=\frac{\omega_f - \omega_i}{\alpha}=\frac{-28.0}{-9.3}=3.0 s[/tex]