The chef would need to add approximately 555.2 moles of salt NaCl to 1.0 kg of water to raise its boiling point to 105°C.
To determine how many moles of salt NaCl are needed to raise the boiling point of 1.0 kg of water to 105°C, we can use the concept of boiling point elevation and the colligative property of solutions.
Given data.
- Mass of water, [tex]\( m = 1.0 \) kg = \( 1000 \) g\\[/tex]
- Desired boiling point of water,[tex]\( T_{\text{new}} = 105 \)°C[/tex]
- Boiling point constant for water,[tex]\( K_b = 0.25 \) °C/m[/tex]
- Van't Hoff factor for NaCl [tex]\( i \) = 2 since NaCl dissociates completely into Na+ and Cl- ions in water[/tex]
First, calculate the change in boiling point [tex]\( \Delta T_b \)[/tex] using the formula for boiling point elevation
[tex]\[ \Delta T_b = i \cdot K_b \cdot m_{\text{salt}} \][/tex]
where.
- [tex]\( i \)[/tex] is the Van't Hoff factor,
- [tex]\( K_b \)[/tex] is the boiling point elevation constant,
- [tex]\( m_{\text{salt}} \)[/tex] is the molality of the salt in the solution.
To find [tex]\( m_{\text{salt}} \)[/tex], rearrange the equation:
[tex]\[ m_{\text{salt}} = \frac{\Delta T_b}{i \cdot K_b} \][/tex]
Calculate [tex]\( \Delta T_b \):[/tex]
[tex]\[ \Delta T_b = T_{\text{new}} - T_{\text{normal}} = 105 \text{°C} - 100 \text{°C} = 5 \text{°C} \][/tex]
Substitute the values into the equation.
[tex]\[ m_{\text{salt}} = \frac{5 \text{ °C}}{2 \cdot 0.25 \text{ °C/m}} \][/tex]
[tex]\[ m_{\text{salt}} = \frac{5}{0.5} \][/tex]
[tex]\[ m_{\text{salt}} = 10 \text{ mol/kg} \][/tex]
This molality [tex]10 mol/kg[/tex] represents the number of moles of salt per kilogram of solvent water.
To find the moles of salt [tex]\( n_{\text{salt}} \)[/tex] needed.
[tex]\[ n_{\text{salt}} = m_{\text{salt}} \cdot \frac{m_{\text{water}}}{M_{\text{water}}} \][/tex]
where.
[tex]- \( m_{\text{water}} \) is the mass of water[/tex],
[tex]- \( M_{\text{water}} \) is the molar mass of water.[/tex]
Calculate [tex]\( M_{\text{water}} \)[/tex].
[tex]\[ M_{\text{water}} = 18.015 \text{ g/mol} \][/tex]
Convert [tex]\( m_{\text{water}} \) to grams[/tex].
[tex]\[ m_{\text{water}} = 1000 \text{ g} \][/tex]
calculate [tex]\( n_{\text{salt}} \)[/tex].
[tex]\[ n_{\text{salt}} = 10 \text{ mol/kg} \cdot \frac{1000 \text{ g}}{18.015 \text{ g/mol}} \]\\[/tex]
[tex]\[ n_{\text{salt}} = 10 \cdot \frac{1000}{18.015} \text{ mol} \][/tex]
[tex]\[ n_{\text{salt}} \approx 555.2 \text{ mol} \][/tex]
If 355 mL of 1.50 M aluminum nitrate is added to an excess of sodium sulfate, how many grams of aluminum sulfate will be produced?
How many grams of copper Cu, 63.54 g/mol are in 3.42 moles copper
Question 6 the chemical formula ch2o can be classified as: empirical only. molecular only. empirical, possibly molecular. not enough information none of the above
When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? when 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? 0.880 mol 0.440 mol 0.330 mol 0.220 mol 0.110 mol?
When 0.440 mol of aluminum react with excess chlorine gas, 0.440 mol of aluminum chloride are produced according to the 1:1 stoichiometric ratio in the balanced chemical equation.
Explanation:When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas (Cl2), to determine how many moles of aluminum chloride (AlCl3) are produced, we look at the stoichiometry of the balanced equation:
2 Al (s) + 3 Cl2 (g) → 2 AlCl3 (s)
This reaction shows that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride. Given the stoichiometry is a 1:1 ratio between aluminum and aluminum chloride, if you start with 0.440 mol of aluminum, you would end up producing 0.440 mol of aluminum chloride as well, provided chlorine is in excess.
Which property of gases allows you to smell popcorn when you walk into a movie theater? compressibility of gas particles diffusion definite shape effusion
How many kilojoules of heat are needed to completely vaporize 42.8 grams of c4h10o at its boiling point given that c4h10o has a heat of vaporization (δhvap) of +26.5 kj/mol and a molar mass of 74.12 g/mol?
A cube of iron (Cp = 0.450 J/g•°C) with a mass of 55.8 g is heated from 25.0°C to 49.0°C. How much heat is required for this process?
A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temperature of 38.6°C. What was the mass of the cadmium sample?
In the word equation, sodium oxide water sodium hydroxide, the formula for sodium hydroxide is represented by
The correct formula for sodium hydroxide in the given word equation is NaOH.
The word equation provided is:
[tex]\[ \text{sodium oxide} + \text{water} \rightarrow \text{sodium hydroxide} \][/tex]
To represent this equation with chemical formulas, we need to know the formulas for each compound:
- Sodium oxide (Na2O) is an ionic compound composed of sodium ions (Na+) and oxide ions (O2-).
- Water (H2O) is a molecular compound composed of two hydrogen atoms and one oxygen atom.
- Sodium hydroxide (NaOH) is an ionic compound composed of sodium ions (Na+) and hydroxide ions (OH-).
The balanced chemical equation for the reaction is:
[tex]\[ \text{Na}_2\text{O} + \text{H}_2\text{O} \rightarrow 2\text{NaOH} \][/tex]
This equation shows that sodium oxide reacts with water to form sodium hydroxide. The formula for sodium hydroxide is NaOH, which consists of one sodium ion (Na+) and one hydroxide ion (OH-). The coefficient 2 in front of NaOH indicates that two moles of sodium hydroxide are produced for every mole of sodium oxide and water that react.
Calculate the mass of sodium chloride produced when 5.50 moles of sodium reacts in excess chlorine gas
4. The diagram shows an electrochemical cell with a gold strip (left) and aluminum glasses (right). In your response, do the following: • Label all parts. • Label the cathode and the anode, including the charge on each. • Show the flow of electrons. • Describe what type of electrochemical cell is pictured and what its use is. • Explain how the cell works. Include the oxidation and reduction half-reactions in your explanation.
The electrochemical cell in the diagram is an electrolytic cell used for gold plating. Electroplating is an electrolytic process used to coat metal objects with a more expensive and less reactive metal. The metal to be plated is used as the anode and the electrolyte solution contains the ions of the metal to be plated.
In the diagram, the gold strip on the left is connected to the positive terminal of the battery and is anode. The aluminum glasses on the right is connected to negative terminal of the battery and is cathode. Anode is positive electrode and cathode is negative.
When the power is switched on, the electrolyte solution splits into ions. Positively charged Au³⁺ ions are attracted to the negatively charged cathode, aluminum glasses and slowly deposit on it. The negatively charged ions are attracted to positively charged anode, the gold strip and release electrons. The electrons move through battery towards the cathode.
Au goes into the solution at the anode and get reduced at the cathode, and is thus plated. A constant concentration of Au³⁺ is maintained in the electrolyte solution surrounding the electrodes.
Anode: Au(s) → Au³⁺(aq) + 3e- ............(oxidation)
Cathode: Au³⁺(aq) + 3e- → Au(s) .........(reduction)
If the number of moles of a gas initially contained in a 2.10 l vessel is doubled, what is the final volume of the gas in liters? (assume the pressure and temperature remain constant.) none of the above 8.40 4.20 1.05 6.30
an aqueous solution of NaOh is used as a drain cleaner.If the concentration of OH^- ions in this solution is 1×10^-5,the concentration of H^+ ions in it would be?
Which of these formulas is the expanded structural formula for an alkane with three carbon atoms? which of these formulas is the expanded structural formula for an alkane with three carbon atoms? c– c– c ch3–ch2–ch3 c3h6 c3h8?
The expanded structural formula for a three-carbon alkane is CH3-CH2-CH3, which represents propane (C3H8) following the general alkane formula CnH2n+2.
Explanation:The expanded structural formula for an alkane with three carbon atoms is CH3-CH2-CH3. In the alkanes series, each molecule follows the general formula CnH2n+2, indicating that for three carbon atoms, the molecular formula is C3H8. Thus, the correct choice from the options provided is CH3-CH2-CH3, which is the condensed structural formula for propane.
what is ½O2 ? pls help me!!!
How much energy is needed to convert 64.0 grams of ice at 0.00?
Approximately 21.4 kJ of energy is needed to convert 64.0 grams of ice at 0.00°C to liquid water at the same temperature. This is calculated using the concept of 'enthalpy of fusion', which is the energy required to convert a substance from solid to liquid without changing its temperature.
Explanation:To find out how much energy is needed to convert 64.0 grams of ice at 0.00°C to water at the same temperature, we should first understand that the melting of ice is an endothermic process, meaning it requires energy. The energy required to convert a substance from solid to liquid state without changing its temperature is termed the enthalpy of fusion.
For water, the enthalpy of fusion is 334 kJ/kg. However, our given mass is in grams, so we need to convert it to kilograms, thus we have 0.064 kg of ice. Using the formula Q=mLf (where Q is energy, m is mass, and Lf is the enthalpy of fusion), we can calculate the necessary energy: Q = (0.064 kg)(334 kJ/kg) = 21.376 kJ.
So, approximatley 21.4 kJ of energy is required to convert 64.0 grams of ice at 0.00°C into water at the same temperature.
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What is a functional group? A-a group of organs in the body that work together to perform a certain function B-a group of living things that are made up of organic compounds C-a group of atoms bonded to carbon that determines how the molecule will react D-a group of organic molecules that work together to speed up reactions
The answer to your question is C.
The mass percent of oxygen in pure glucose, c6h12o6 is 53.3 percent. a chemist analyzes a sample of glucose that contains impurities and determines that the mass percent of oxygen is 49.7 percent. which of the follow impurities could account for the low mass percent of oxygen in the sample?
Methanol is the most plausible candidate among these potential contaminants because its oxygen content is closest to the reported mass percent of oxygen in the sample (49.7%).
The proportional amount of a certain component (typically a substance or element) in a combination, compound, or solution is expressed as mass percent (also known as weight percent or weightage). It is a percentage that represents the component's mass in relation to the overall mass of the combination, compound, or solution multiplied by 100.
molecular formula mass of [tex]\rm C_6H_{12}O_6[/tex] = 180.18 g/mol
mass percent of oxygen is
(96.00 g/mol / 180.18 g/mol) × 100%
≈ 53.3%
In water, the mass percent of oxygen is:
(16.00 g/mol / 18.02 g/mol) × 100%
≈ 88.9%
In formaldehyde, the mass percent of oxygen is:
(16.00 g/mol / 30.03 g/mol) × 100%
≈ 53.3%
In methanol, the mass percent of oxygen is:
(16.00 g/mol / 32.04 g/mol) × 100%
≈ 50.0%
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which has not been a major source of CFCs
Answer : Any natural sources of CFC's are not known only the major sources like aerosols, propellants, refrigerants,etc are known. So, if any natural sources are given then it cannot be called as a major source for emitting CFC into environment.
Answer:
• televisions
An equilibrium mixture of so2, o2, and so3 gases is determined to consist of 2 mol/l so2, 1 mol/l o2, and 4 mol/l so3. what is the equilibrium constant for the system at this temperature? the balanced equation for this reaction is
The all substances that participate in the
reaction are in gaseous phase and the given data are the concentrations when
the reaction at equilibrium. Hence, we can use that given concentrations directly to find out the equilibrium constant, Kc.
The balanced equation for the equilibrium is,
2SO₂(g) + O₂(g) ⇄ 2SO₃(g)
Kc = [SO₃(g)]² / [SO₂(g)]² [O₂(g)]
Kc = (4 mol/L)² / (2 mol/L)² (1 mol/L)
Kc = 4 mol⁻¹ L
Hence, the equilibrium constant is 4 mol⁻¹ L
How much heat energy would be released if 78.1 g of water at 0.00 °c were converted to ice at −57.1 °c. give your answer as a positive number in kilojoules (kj)?
Question 10 unsaved in a chemical reaction, the mass of the products question 10 options: has no relationship to the mass of the reactants. is less than the mass of the reactants. is greater than the mass of the reactants. is equal to the mass of the reactants.
The radioactive element carbon-14 has a half-life of 5750 years. a scientist determined that the bones from a mastodon had lost 78.5% of their carbon-14. how old were the bones at the time they were discovered?
A 4.305-g sample of a nonelectrolyte is dissolved in 105 g of water. the solution freezes at -1.23c. calculate the molar mass of the solute. kf for water = 1.86c/m.
The molar mass of the solute is calculated by first finding the molality of the solution using the freezing point depression, then using this to find the number of moles of solute, and finally dividing the mass of the solute by the number of moles. The computed molar mass of the solute is 62.15 g/mol.
Explanation:To calculate the molar mass of the solute, we first need to calculate the molality of the solution using the freezing point depression formula, ΔTf = iKfm, where i is the van't Hoff factor (which is 1 for a non-electrolyte), Kf is the freezing point depression constant for water (1.86°C/m), and m is molality. We know that ΔTf = -1.23°C. So, molality can be determined as follows: m = ΔTf / (i x Kf) = -1.23°C / (1 x 1.86°C/m) = -0.66mol/kg.
Molality is defined as moles of solute per kilogram of solvent. Therefore, if we multiply the molality by the mass of the solvent (105g or 0.105kg), we get the moles of solute. Moles of solute = m x mass of solvent = -0.66mol/kg x 0.105kg = -0.0693mol.
Finally, to determine the molar mass of the solute, we divide the mass of the solute by the number of moles. Molar mass = mass of solute / moles of solute = 4.305g / -0.0693mol = -62.15g/mol. The negative sign indicates a freezing point depression, but the molar mass of a substance cannot be negative. Therefore, the molar mass of the solute is 62.15g/mol.
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What is the value of n when the empirical formula is c3h5 and the molecular mass is 205.4?
What test or tests do you use to find NaCl
Answer:
Sodium chloride, regular table salt, is also known as the mineral halite. The diagram to the right shows how sodium and chlorine atoms pack tightly together to form cube-like units of the compound NaCl
Explanation:
What is the melting point of a solution in which 3.5 grams of sodium chloride is added to 230 mL of water?
Answer:
0.952 °C
Explanation:
The change in melting point is computed as:
ΔT = k*m*i
where ΔT is the difference between the melting point of water and of solution, k is a constant (1.86 °C*kg/mol for water), i is the van't Hoff factor (equal to 2 for sodium chloride because 2 ions are obtained after its dissolution), and m is the molality of the solution.
Molar mass of sodium chloride: 58.44 g/mol
Moles of of sodium chloride: mass / molar mass 3.5/58.44 = 0.059 mol
Density of water 1 kg/L
230 mL of water are equivalent to 0.23 L
mass of water: density * volume = 1*0.23 = 0.23 kg
Molality of the solution: m = moles of solute/ kg of solvent = 0.059/0.23 = 0.256
Finally:
ΔT = 1.86*0.256*2 = 0.952 °C
Water melting point: 0 °C
So, the solution melting point is: 0 - 0.952 = 0.952 °C
The process in which sediment is dropped and comes to rest is called
Answer : The process in which sediment is dropped and comes to rest is called, Deposition.
Explanation:
Deposition : It is a type of process in which the molecules are settle down at the bottom of the container. In this process, there is no intermolecular space present between the atoms of molecule.
This process results in the formation of the sedimentary rocks which are made out of ice, wind and water flows which carry particles in the suspension.
Hence, the process in which sediment is dropped and comes to rest is called, Deposition.
Ac sample of octane that has a mass of 0.750 g is burned in a bone calorimeter. As a result, the temperature if the calorimeter increases from 21.0 °C to 41°C . The specific heatv of the calorimeter is 1.50 J/(g*°C), and it's nass is 1.0 kg. How much heat is released during the combustion
If sodium loses 1 electron, it will have the same number of valence electrons as which noble gas?