10 kg of saturated solution of a highly soluble component A at 80°C is cooled to 30°C Calculate the amount of an-hydrous crystals are coming out of the solution Solubility of A at 80*C is 0.8 kg of A 1 kg of water and at 30°C is 0.3 kg of A 1 kg of water a) 2.73 kg b) 5.73 kg c) 4.73 kg d) 3.73 kg

The concentration of the nickel(II) chloride solution is determined by dividing the amount of substance (in umol) by the volume of the solution (in liters). This results in a concentration of 306.5 umol/L.

The concentration of a solution is determined by the formula c = n/V, where 'c' is the concentration, 'n' is the amount of substance (in moles), and 'V' is the volume of the solution (in liters).

In this case, the chemist has used 61.3 umol of nickel(II) chloride (NiCl2), and the total volume of the solution is 200 ml. We need to convert this volume to liters, giving us 0.2 L. Now, using the formula, we calculate: c = 61.3 umol / 0.2 L, which equals 306.5 umol/L.

Make sure to always convert the units appropriately before you substitute the values into the formula.

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Answer:

The mass of  Fe₂O₃ in 0.500 g of mixture is 0.367 g.

Explanation:

First off, we know that 72% of the mass of the mixture is iron. The information also tells us that the remaining 28% of the mass is oxygen.

Now we calculate the total mass of iron and the total mass of oxygen in the mixture:

With the mass of each element we can calculate the number of moles of each atom, using the atomic weight:

0.360 g Fe * 1 mol / 55.845 g = 0.00645 moles of Fe

0.140 g O * 1 mol / 16 g = 0.00875 moles of O

The number of moles of Fe in the mixture is equal to the number of moles of FeO plus two times the number of moles of Fe₂O₃:

0.00645 = [tex]2*n_{Fe2O3} +n_{FeO}[/tex]             eq A

The number of moles of O in the mixture is equal to the number of moles of FeO plus three times the number of moles of Fe₂O₃:

0.00875 = [tex]3*n_{Fe2O3} +n_{FeO}[/tex]               eq B

So now we have a system of two equations and two unknowns, we solve for [tex]n_{Fe2O3}[/tex]:

From eq A:

[tex]n_{FeO3}=0.00645-2*n_{Fe2O3}[/tex]

Replacing in  eq B:

[tex]0.00875=3*n_{Fe2O3} + (0.00645-2*n_{Fe2O3})\\0.00230=n_{Fe2O3}[/tex]

Now we just need to convert moles of Fe₂O₃ into grams, using the molecular weight:

0.00230 moles * 159.66 g/mol = 0.367 g Fe₂O₃

Answer:

Hydrogen bond is a special type of dipole-dipole interaction between the hydrogen atom in a polar bond, such as N-H, O-H, or F-H, and electronegative O,N or F atom. The interaction is written:

                                        A-B . . . B        or           A-H . . . .A

A and B represent O,N or F; A-H is one molecule or part of a molecule and B is a part of another molecule, and the dotted represents the hydrogen bond. So, hydrogen bond is a type of intermolecular forces (attractive forces between molecules, NOT between atoms of the same molecule), and only a few elements can participate on hydrogen bond formation.

Note: dipole-dipole interactions are forces between polar molecules, that is, between molecules that possess dipole moments.  

Final answer:

A hydrogen bond is a weak intermolecular attraction where a partially positive hydrogen atom, bonded to an electronegative atom, is attracted to a lone pair of electrons on a nearby electronegative atom.

Explanation:

A hydrogen bond is a type of intermolecular or intramolecular attractive force. It occurs when a hydrogen atom, covalently bonded to a highly electronegative atom such as nitrogen, oxygen, or fluorine, develops a partial positive charge. This partially positive hydrogen atom is then attracted to the lone pair of electrons on a neighboring electronegative atom, often in a different molecule. This attraction is relatively weak compared to covalent bonds but is stronger than other dipole-dipole interactions. In water, hydrogen bonds are a crucial part of the molecule's properties, including its high boiling point and surface tension.

Answer:

molar volume of vapor ethanol is [tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]

mass of ethanol is 15430.22 g

Explanation:

By using ideal gas equation

PV = nRT

Where P is pressure , R is gas constant

so, volume is

[tex]V = \frac{RT}{P} = \frac{8.314\times (480+273)}{6000\times 10^3}[/tex]

[tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]

molar volume of vapor ethanol is

[tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]

b)

volume of vessel is given [tex]0.35 m^3[/tex]

therefore total moles of ethanol in given vessel will be

[tex]n =\frac{V_{vessel}}{V}[/tex]

[tex]n =\frac{0.35}{1.043\times10^{-3}}[/tex]

n = 335.44 mol

we know that

mole is given as [/tex]n = \frac{mass}{moleculae weight}[/tex]

weight of ethanol is 46 g/mol

n\times 46 = mass

[tex]335.44\times 46 = 15430.22 g[/tex]

mass of ethanol is 15430.22 g

Explanation:

The water is hard due to the presence of ions of Mg²⁺. Now in hard water soaps are ineffective . Since in hard water Mg²⁺ ion forms precipitate , which concludes less number of soap molecules are present in the solution and less amount of  froth  which disables the cleansing property of the soap .

Now the experiment , the very last step is the hard water test where some amount of MgCl₂ is added ,

Now this magnesium salt act as a source of Mg²⁺ ion and now the soap action can be determined , whether it is able to form froth or not .

MgCl2 is added to the soap solution during a soap testing experiment to simulate the conditions of hard water. This allows for assessment of the soap's effectiveness as a cleansing agent in hard water, as soaps often form insoluble precipitates when reacting with minerals like magnesium.

In a soap testing experiment, MgCl2 (magnesium chloride) is added to the soap solution as a way to simulate hard water conditions because hard water contains high levels of magnesium and other minerals. One property of soap is its ability to react with ions present in water. In hard water, soaps react with calcium or magnesium ions to form insoluble precipitates, which makes the soap less effective as a cleaning agent. This is notable because soaps form insoluble calcium and magnesium compounds in hard water, while detergents form water-soluble products.

The behavior of soap in this soap-magnesium chloride solution, therefore, would give an indication of its prospective behaviour in hard water conditions.

Learn more about Soap Testing here:

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Explanation:

We select the enthalpy of steam at state 1 at [tex]800^{o}C[/tex] and 8.0 MPa from the steam tables as follows.

                     [tex]h_{1}[/tex] = 3138 kJ/kg

Also, we select the enthalpy of steam at state 2 at 0.5 MPa from the steam tables as follows.

                     [tex]h_{2}[/tex] = 2748.6 kJ/kg

At state 3 also, from the steam tables at state 3 at 0.1 MPa.

                     [tex]h_{3}[/tex] = 2675.1 kJ/kg

Hence, calculate the mass flow rate at state 3 as follows.

                  [tex]m_{3} = m_{1} - m_{2}[/tex]

                              = 1000 kg/h - 300 kg/h

                              = 700 kg/h

Now, we will calculate the power output of the turbine as follows.

                 [tex]W_{r} = m_{1}(h_{1} - h_{2}) + m_{3}(h_{2} - h_{3})[/tex]

                             = 1000 kg/h (3138 kJ/kg - 2748.6 kJ/kg) + 700 kg/h (2784.6 kJ/kg - 2675.1 kJ/kg)

                            = 440850 kJ/h

It is known that 1 kJ/h = 0.000278 kW.

Therefore,        [tex]440850 kJ/h \times \frac{0.000278 kW}{1 kJ/hr}[/tex]    

                          = 122.56 kW

Thus, we can conclude that the power output of the turbine is 122.56 kW.

Answer:

Molarity of silver ion: 0.296 M

Explanation:

Reaction:

AgNO₃ + KCl → AgCl↓ + K⁺ + NO₃⁻

From the reaction, we know that the moles of AgCl produced will be the same as the moles of initial silver.

First, let´s calculate the number of moles of AgCl produced:

1.56 g AgCl was produced, that is, (1.56 g AgCl * 1 mol AgCl/143.3 g AgCl) 0.011 moles AgCl.

The moles of silver ion present in the original solution was 0.011 mol. Since this number of moles was present in a 37.1 ml solution, then, in 1000 ml:

moles of silver ion per liter = 1000 ml * 0.011 mol / 37.1 ml = 0.296 mol

Molarity of silver ion = 0.296 M

The molarity of silver ion in the original AgNO3 solution is 0.293 M.

To determine the molarity of silver ion in the original AgNO3 solution when 37.1 mL reacts to yield 1.56 g of AgCl, we first need to calculate the moles of AgCl produced using the molar mass of AgCl.

The molar mass of AgCl is 143.3 g/mol. So, the moles of AgCl formed are calculated as follows:

(1.56 g AgCl) / (143.3 g/mol) = 0.010878 mol AgCl

Since AgNO3 reacts with KCl in a 1:1 mole ratio to produce AgCl, the moles of AgNO3 that reacted is also 0.010878 mol. To find the molarity of AgNO3, we divide the moles by the volume of solution in liters:

(0.010878 mol AgNO3) / (0.0371 L) = 0.293 M

Answer:

The move from Level n=3 to Level n=2 has the long wavelength.

Explanation:

First, due to the selection rules, only transitions between adjacent levels are allowed, thus, only a transition between Level n=3 to Level n=2 or Level n=5 to Level n=4 are allowed. The two first options are wrong.

Second, analyzing the transition between Level n=3 to Level n=2 and the transition between Level n=5 to Level n=4 it is necessary to think in terms of the equation of the difference of energy for these type of transitions:

Δ[tex]E = \frac{h^{2}}{8.m.L}(n_{LUMO}^{2} -n_{HOMO}^{2} )[/tex] (1)

The difference in energy (ΔE) is directly proportional to the quadratic difference between the 'n' levels of transition. Therefore, If the transition occurs between smaller 'n' levels the difference of energy will be smaller too.

Also, the energy (ΔE) is inversely proportional to the wavelength (λ) so a smaller energy means a larger wavelength.

ΔE = c / λ (2)

Hence, the move from Level n=3 to Level n=2 has a long wavelength.

In order to calculate this wavelength is necessary to replace the data on equation (1) and (2).

To calculate the number of moles of solute particles in a solution, multiply the molarity by the volume of the solution. In this case, the result is 0.0070 mol. Taking the LOG (base 10) of the result gives -2.15.

To determine the number of moles of solute particles in a solution, you need to consider the molarity and volume of the solution. In this case, the molarity is 0.887 M and the volume is 7.94 mL. To calculate the number of moles, you can use the formula:

Moles = Molarity x Volume

Converting mL to L:

7.94 mL = 7.94/1000 L = 0.00794 L

Now, substitute the values into the formula:

Moles = 0.887 M x 0.00794 L = 0.0070 mol

Taking the LOG (base 10) of 0.0070, we get -2.15 (rounded to 2 decimal places).

Answer:

The value of the Prandlt number for this fluid is: 1656.04

Explanation:

As it is stated in the problem : Pr = Cp*mu/k

where:

cp: heat capacity of the fluid

mu: viscosity of the fluid

k: thermal conductivity of the fluid

Now for a given fluid we have

cp= 0.58 J/(g* deg C)

mu=1934 Ibm / (ft * h)

k = 0.28 W/(m * deg C)

If we put these values in the ecuation of the Prandlt number we have:

Pr = (0.58 J/(g* deg C)) × (1934 Ibm / (ft * h) / 0.28 W/(m * deg C)) =

As we can see we have to convert the units so we can operate all the values in the same units of measurement and then cancel them so as to obtain a dimensionless result.

Converting the value of: mu = 1934 Ibm / (ft * h)

1 ft= 0.3048 m

1 h= 3600 s

1 lbm= 453.59 g

mu= 1934 Ibm / (ft * h) × (453,59 g/ lbm) × (1h/3600 s) × (1 ft/0.3048 m) = 799.47 g/ (m *s).

Pr = (0.58 J/(g* deg C)) × (799.47 g/ (m *s) / 0.28 W/(m * deg C)) = 1656.04

Answer:

We could use fractional distillation, solvent extraction, partial crystallization, chromatography, and another.

Explanation:

The only information given is that the compounds have similar polarities, which means they form a homogeneous mixture, so, to separate them, we should use some of the processes of separation of a homogeneous mixture.

Without knowing any of the physical properties of A and B (physical state, density, boiling point, for example) it's impossible to determinate the better process of separation. However, we can describe some of the processes that are used to separate homogeneous mixtures: fractional distillation, solvent extraction, partial crystallization, and chromatography, for example.

Answer:

Sodium chloride has a crystalline face-centered  cubic structure whereas metallic sodium body-centered  cubic structure.

Explanation:

Hello, atomic arrangements provide the molecules different features and behaviors, since the sodium metal has a body-centered cubic structure (https://en.wikipedia.org/wiki/Cubic_crystal_system#/media/File:Cubic-body-centered.svg) the lack of inner atoms, allows the material to be soft and bendable. On the other hand the compacted sodium chloride's face-centered  cubic structure (https://en.wikipedia.org/wiki/Cubic_crystal_system#/media/File:Cubic-face-centered.svg), provides it a crystalline structure which is hard and brittle since the atoms are closer.

Best regards!

Answer:

Option c, Two atomic orbitals combine to form one molecular orbital

Explanation:

Molecular orbitals are formed by linear combination of atomic orbitals.

Some of the important facts of molecular orbital theories are as follows:

So, among given, option c which is 'atomic orbitals combine to form one molecular orbital' is incorrect.

All the statements provided are true with regards to Molecular Orbital Theory, except for 'Two atomic orbitals combine to form one molecular orbital.' In fact, two atomic orbitals combine to form two molecular orbitals, one being a lower-energy bonding molecular orbital and the other one being a higher-energy antibonding orbital.

In the context of Molecular Orbital Theory, three out of the four statements made in the question are correct. Namely, molecular orbitals are indeed formed by the combination of atomic orbitals, and they represent regions of a molecule where electrons are most likely to be found. Additionally, bonding molecular orbitals do have lower energy than the atomic orbitals from which they are formed.

However, the statement suggesting that 'Two atomic orbitals combine to form one molecular orbital' is not accurate. In reality, when two atomic orbitals combine, they form two molecular orbitals: one lower-energy (bonding) molecular orbital and one higher-energy (antibonding) orbital.

This nuanced concept is a cornerstone of MO theory and helps explain a range of phenomena, from the paramagnetism of the oxygen molecule to violations of the octet rule. Understanding this allows us to further appreciate the differences between bonding and antibonding orbitals and their roles in the structure and stability of molecules.

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Answer:

The answer is NaF.

Explanation:

Lattice energy:

It can be define as "the amount of energy released when ions combine to from the ionic solids or energy required to break the compound into its ions"

Example:

Consider the example of ionic solid NaCl. The sodium chloride is formed when ions like Na+ and Cl - are combine. During the formation of NaCl crystals the energy is released which is called lattice energy of sodium chloride.

Dependence of lattice energy:

Lattice energy depend upon following factors:

1. Charges of the ions

2. Sizes of the ions

As the charge of ion increase the lattice energy also increase. There is a direst relationship between them.

The size of the ions and lattice energy have inverse relation. As the size decreases, lattice energy increases. Therefor, the compound NaF consist of smallest cation (Na+) and the smallest anion (F-) have largest lattice energy.

                F= q1 × q2/ r²

As the size of ions decreases the distance between the oppositely charged ions in a ionic compound decreases. They will more tightly packed in a crystal and their center will more closer to each others hence increase the lattice energy.

Answer:

656,25 moles of CH3OH

Explanation:

If the mixture has 7% of weight in methanol (CH3OH), it means that for every 100 kg of the mixture there are 7 kg of methanol.

To solve the problem we just use this relation and convert the kilograms of methanol to gmoles of methanol using the molecuar weight of the methanol (32g/mol):

[tex]300 kgmixture*\frac{7kgCH3OH}{100kg}*\frac{1000g}{1kg}*\frac{1molCH3OH}{32g}=656,25molesCH3OH[/tex]

Answer:

12,000 units of heparin are received by patient in 24 hours.

Explanation:

10,000 units of heparin in 1000ml of D5W.

Units of heparin in 1 mL = [tex]\frac{10,000}{1000}=10 units[/tex]

Rate at heparin drip set at = 50 ml/hour

Units of heparin in 50 ml of solution = [tex]50\teimes 10 units =500 units[/tex]

500 units of heparin are received by patient in an every hour.So, in 24 hours patient will receive:

[tex]500units\times 24 = 12,000 units[/tex] of heparin

12,000 units of heparin are received by patient in 24 hours.

Answer:

The energy is 3.559 * 10⁻¹⁹ J

Explanation:

For this problem we need to use Planck's equation, this equation describes the relationship between energy radiated by light (a photon, to be precise) and its frequency. The equation is:

E = h * v

Where E is energy (in Joules), h is Planck's constant (6.626 * 10⁻³⁴ J·s), and v is the frequency (in s⁻¹).

Now we solve the equation, using the data given in the problem:

E = 6.626 * 10⁻³⁴ J·s * 5.371 * 10¹⁴ s⁻¹ = 3.559 * 10⁻⁴⁷ J

Thus the energy is 3.559 * 10⁻¹⁹ J

Answer:

1) 2.54 cm = 0.0254 m

2) 316 Ms = [tex]3.16\times 10^{8} s[/tex]

Explanation:

1) 2.54 cm

In 1 centimeter is there are 0.01 meters.

1 cm = 0.01 m

[tex]2.54 cm = 2.54\times 0.01 m = 0.0254 m[/tex]

2) 316 Ms

In 1 mega second  is there are 1 million seconds.

[tex]1 Ms = 10^{6} s[/tex]

[tex]316 Ms= 316\times 10^{6} s= 3.16\times 10^{8} s[/tex]

Answer:

Complete reaction

mole %: 0% N₂; 20% H₂; 80% NH₃

Gram %: 0% N₂; 2,9% H₂; 97,1% NH₃

75% reaction:

mole%: 8,3% N₂; 41,7% H₂; 50% NH₃

Gram: 20% N₂; 7,2% H₂; 72,8% NH₃

Explanation:

The global reaction in the reactor is:

N₂(g) + 3 H₂ (g) → 2 NH₃ (g)

For a complete reaction of 20 moles of N₂(g) you need:

20 moles N₂ ₓ [tex]\frac{3 mol H_2}{1 mol N_2}[/tex] = 60 moles of H₂(g)

So, 10 moles of H₂(g) will stay in the end.

The moles produced of NH₃ are:

20 moles N₂ ₓ [tex]\frac{2 mol NH_3}{1 mol N_2}[/tex] = 40 moles of NH₃(g)

Thus, the final composition in moles is:

0 moles N₂; 10 moles H₂; 40 moles of NH₃

The mole % is:

0% N₂; ¹⁰/₅₀ ₓ 100 = 20% H₂; ⁴⁰/₅₀ ₓ100 = 80% NH₃

In grams you have:

10 moles H₂ [tex]\frac{2,02 g}{1 mol}[/tex] = 20,2 g of H₂

40 moles NH₃ [tex]\frac{17,03 g}{1 mol}[/tex] = 681,2 g of NH₃

0% N₂; [tex]\frac{20,2 g}{701,4}[/tex] ₓ 100 = 2,9% H₂; [tex]\frac{681,2 g}{701,4}[/tex] ₓ100 = 97,1% NH₃

With a 75% of conversion you have that the moles produced of NH₃ are:

40 moles of NH₃(g) × 75% = 30 moles of NH₃

The necessary moles to produce these moles of NH₃ are:

30 moles NH₃ ₓ [tex]\frac{3 mol H_2}{2 mol NH_3}[/tex] = 45 moles of H₂(g)

So, 25 moles of H₂(g) will stay in the end.

30 moles NH₃ ₓ [tex]\frac{1 mol N_2}{2 mol NH_3}[/tex] = 15 moles of N₂(g)

So, 5 moles of H₂(g) will stay in the end.

Thus, the final composition in moles is:

5 moles N₂; 25 moles H₂; 30 moles of NH₃

The mole % is:

⁵/₆₀ ₓ 100 =8,3% N₂; ²⁵/₆₀ ₓ 100 = 41,7% H₂; ³⁰/₆₀ ₓ100 = 50% NH₃

In grams you have:

5 moles N₂ [tex]\frac{28 g}{1 mol}[/tex] = 140 g of N₂

25 moles H₂ [tex]\frac{2,02 g}{1 mol}[/tex] = 50,5 g of H₂

30 moles NH₃ [tex]\frac{17,03 g}{1 mol}[/tex] = 510,9 g of NH₃

[tex]\frac{140 g}{701,4}[/tex] ₓ 100 =20% N₂; [tex]\frac{ 50,5g}{701,4}[/tex] ₓ 100 = 7,2% H₂; [tex]\frac{510,9 g}{701,4}[/tex] ₓ100 = 72,8% NH₃

I hope it helps!

Answer:

The right answer is option A: The outlet temperature of the cold stream decreases and the outlet temperature of the hot stream increases.

Explanation:

In a heat exchanger, when the exchange area is reduced, and at the same condition for the rest of the variables, the amount of heat exchanged by the two fluids is reduced.

In the case of the hot fluid, it will rise at a higher temperature, compared to the temperature at which it would come out with a larger exchange area.

In the case of the hot fluid, it will come out at a lower temperature, compared to the temperature at which it would come out with a larger exchange area.

The correct answer is option A.

Answer:

a- The outlet temperature of the cold stream decreases and the outlet temperature of the hot stream increases.

Explanation:

Hello,

In heat transfer processes, specific units such as heat exchangers are useful to either heat up a cold stream with a hot one or vise-versa. However, the heat transfer efficiency increases as surface area increases, it means that the higher the surface area the higher the heat exchanger's efficiency, therefore, if the surface area is reduced, the efficiency is reduced as well, due to the lack of more space for the heat transfer.

In such a way, the outer temperature of the cold fluid will be lower (less heating up) and the outer one of the hot fluid will be higher (less cooling down), thus, the outlet temperature of the cold stream decreases and the outlet temperature of the hot stream increases (a option).

Best regards.

Answer: The given number in scientific notation is [tex]9.342\times 10^{-8}[/tex]

Explanation:

Scientific notation is the notation where a number is expressed in the decimal form. This means that the number is always written in the power of 10 form. The numerical digit lies between 0.1.... to 9.9.....

If the decimal is shifting to right side, the power of 10 is negative and if the decimal is shifting to left side, the power of 10 is positive.

We are given:

A number having value = 0.000000093425

Converting this into scientific notation, we get:

[tex]\Rightarrow 0.000000093425=9.342\times 10^{-8}[/tex]

Hence, the given number in scientific notation is [tex]9.342\times 10^{-8}[/tex]

Answer:

[tex]9.343\times 10^{-8}[/tex]

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10.

The given number:

0.000000093425 can be written as [tex]9.3425\times 10^{-8}[/tex]

Answer upto 4 significant digits = [tex]9.343\times 10^{-8}[/tex]

The ΔH value for the combustion of butane is given as 5315 kJ for the reaction as written, which is for 2 moles of butane. To find the enthalpy of combustion per mole, divide this number by 2, yielding -2658 kJ/mol.

The student asked to give the ΔH value for the combustion of butane as shown in the reaction 2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(g) + 5315 kJ. The ΔH value for the reaction is given as +5315 kJ, indicating the amount of energy released during the combustion of butane.

Now, the enthalpy of combustion is typically expressed on a per mole basis, referring to the amount of heat released when one mole of a substance is burned. Since the reaction above shows the combustion for 2 moles of butane, we can calculate the enthalpy of combustion per mole by dividing the total energy by 2. So, the enthalpy of combustion for one mole of butane would be 5315 kJ / 2 = 2657.5 kJ/mol, which is typically reported in kilojoules per mole (kJ/mol).

Expressed with four significant figures, the enthalpy of combustion per mole of butane would be -2658 kJ/mol (the negative sign indicates that energy is released).

Answer:

I hope you find these examples useful! good luck!

Answer: This world is rapidly moving towards to some serious enviornmental problems, the cause of this problems are mentioned below;

(1) The increase in average temperature of Earth.

(2) Deforestation

(3) Over Population

(4) Mining

Because of these reasons mentioned above there are many enviornmental issue occurring, and many problems we will face in future for example, water crisis, lack of resources.

Answer: The chemical formula of Iron (III) sulfate is [tex]Fe_2(SO_4)_3[/tex]

Explanation:

Iron is the 26th element of periodic table having electronic configuration of [tex][Ar]3d^64s^2[/tex].

To form [tex]Fe^{3+}[/tex] ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of [tex]SO_4^{2-}[/tex]

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is [tex]Fe_2(SO_4)_3[/tex]

Answer:

2 grams

Explanation:

The percentage in weight/weight is equivalent to the solute mass divided by the solution mass and multiplied by 100. For example, if you have 25g/100g then the percentage will be 25%. In this case you just need to multiply 8*25 and divided it by 100, so the answer is 2 grams of mupirocin per 25 g of the ointment.

Answer:

8.882 × 10^23

Explanation:

The molar mass of phosphorus is 30.97 g/mol. The moles of P corresponding to 45.67 g are:

45.67 g × (1 mol/30.97 g) = 1.475 mol

In 1 mole of P, there are 6.022 × 10²³ atoms of P (Avogadro's number). The number of atoms of P in 1.475 moles are:

1.475 mol × (6.022 × 10²³ atoms/1 mol) = 8.882 × 10²³ atoms

Answer: Thus rate of disappearance of [tex]H_2=2\times {\text {rate of disappearance of}O_2}[/tex]

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]

Given: Order with respect to [tex]H_2[/tex] = 2

Order with respect to [tex]O_2[/tex] = 1

Thus rate law is:

[tex]Rate=k[H_2]^2[O_2]^1[/tex]

k= rate constant

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

[tex]Rate=-\frac{1d[H_2]}{2dt}=-\frac{1d[O_2]}{dt}[/tex]

[tex]Rate=-\frac{1d[H_2]}{dt}=2\times -\frac{1d[O_2]}{dt}[/tex]

Thus rate of disappearance of [tex]H_2=2\times {\text {rate of disappearance of}O_2}[/tex]

Answer:

Option d, It is higher than the energy of both reactants and products.

Explanation:

When reactant molecules collide with each other during the course of the reaction, an intermediate state is reached before the formation of product. This intermediate state is also called activated complex.

Activated complex consist energy higher than that of both the reactants and products. Because of possessing higher energy, it is unstable and temporary.

Hence, among given, option d is correct.

Answer:

d. It is higher than the energy of both reactants and products.

Explanation:

The activated complex is a transient state, or intermediate phase, between reagents (weak or not), in which the final product has not yet been formed. This effective shock, like any chemical bond, needs energy. To form this transient state requires an activation energy, a minimum energy for this intermediate phase to occur.

Within this phenomenon, the activation energy must occur by some criteria, which characterizes a chemical bond in an activated complex:

Within these three rules, it is clearer to define this complex as the moment when a molecule of a given atom collides with another molecule of any other atom and breaks the bond established between them.

For it to happen, the energy needs to be high. When this potential energy is present at a high level during the reaction, it is also necessary to have a high energy charge to complete the complex and also the collision of the reactant molecules to form the binding products.