12. In cell I9, create a formula without using a function that first adds the selected boxed set’s net weight (cell I8) to the packing weight (cell F5), and then divides the value by 16 to show the shipping weight in pounds.

Answer:

#include <iostream>

#include <climits>

#include<fstream>

using namespace std;

int main ()

{

fstream filein;

ofstream fileout;

string inputfilename, outputfilename;

// ASk user to enter filenames of input and output file

cout<<"Enter file input name: ";

cin>>inputfilename;

cout<<"Enter file output name: ";

cin>>outputfilename;

// Open both file

filein.open(inputfilename);

fileout.open(outputfilename);

// Check if file exists [Output file will automatically be created if not exists]

if(!filein)

{

cout<<"File cannot be opened"<<endl;

return 0;

}

int min = INT_MAX;

int max = INT_MIN; //(Can't use 0 or any other value in case input file has negative numbers)

int count = 0; // To keep track of number of integers read from file

double average = 0;

int number;

// Read number from file

while(filein>>number)

{

// If min > number, set min = number

if (min>number)

{

min = number;

}

// If max < number. set max = number

if(max<number)

{

max = number;

}

// add number to average

average = average+number;

// add 1 to count

count+=1;

// If count reaches 10, break the loop

if(count==10)

{

break;

}

}

// Calculate average

average = average/count;

// Write result in output file

fileout<<"Max: "<<max<<"\nMin: "<<min<<"\nAverage: "<<average;

// Close both files

filein.close();

fileout.close();

return 0;

}

Answer:

Check the explanation

Explanation:

(1.) The functional dependencies based on assumptions are as follows:-

Trip determines which staff was there in the trip, the car used for the trip, the quantity of fuel used in the trip, the fill up time and the total paid of the trip.

Service station refers to its address

Car details consist of the details of license plate, odometer reading and the fuel type used in the car

fuel type and the fill up time will help to determine the cost of the fuel at that time

cost of the fuel and the quantity of fuel used will determine the total paid

From the above assumptions the functional dependencies are as follows:-

Trip ID -> Staff Name, Car Details, Service Station, Quantity, Fill Up Time, Total Paid

Service Station -> Station Address,

Car Details -> License Plate, Odometer reading, Fuel Type

Fuel Type, Fill up Time -> Cost per litre

Cost per Litre, Quantity -> Total Paid

(2.) Initially the relation is as follows:-

R (Trip ID, Staff Name, Car Details, License Plate, Odometer Reading, Service Station, Station Address, Fill up Time, Fuel type, Quantity, Cost per Litre, Total Paid)

For 1 NF there should not be composite attributes,in the above relation Staff Name and Station Address are composite attributes therefore it will be decomposed as follows:-

R (Trip ID, Staff First Name,Staff Last Name, Car Details, License Plate, Odometer Reading, Service Station, Street, City, State, Zip Code, Fill up Time, Fuel type, Quantity, Cost per Litre, Total Paid)

For 2 NF there should not be partial dependency that is non prime attribute should not dependent upon any 1 prime attribute of candidate key, since in the given relation there is only 1 candidate key which is only Trip ID, therefore the relation is already in 2 NF.

For 3 NF there should not be transitive dependency that is non prime attribute should not dependent upon the other non prime attribute, if it is present then the relation will be decomposed into sub relations, the given relation is not in 3 NF therefore it will be decomposed as follows:-

R1 (Trip ID, Staff First Name, Staff Last Name, Car Details, Service Station, Quantity, Fill up time, Total paid)

R2 (Service Station, Street, City, State, Zip Code)

R3 (Car Details, License Plate, Odometer reading, Fuel Type)

R4 (Fuel Type, Fill up Time, Cost per litre)

R5 (Cost per Litre, Quantity, Total Paid)

(3.) After the 3 NF we add the primary and foreign key constraints as follows:-

R1 (Trip ID, Staff First Name, Staff Last Name, Car Details, Service Station, Quantity, Fill up time, Total paid)

R2 (Service Station, Street, City, State, Zip Code)

R3 (Car Details, License Plate, Odometer reading, Fuel Type)

R4 (Fuel Type, Fill up Time, Cost per litre)

R5 (Cost per Litre, Quantity, Total Paid)

In the above relational schema the primary keys are represented with bold and foreign keys by italic

(4.) The ER diagram of the above relational schema using crow's foot notation are as shown in the attached image below:-

Answer:

See explaination

Explanation:

class Seat {

private boolean available;

private int tier;

public Seat(boolean isAvail, int tierNum)

{ available = isAvail;

tier = tierNum; }

public boolean isAvailable() { return available; }

public int getTier() { return tier; }

public void setAvailability(boolean isAvail) { available = isAvail; } }

//The Theater class represents a theater of seats. The number of seats per row and the number of tier 1 and tier 2 rows are

//determined by the parameters of the Theater constructor.

//Row 0 of the theaterSeats array represents the row closest to the stage.

public class Theater {

private Seat[][] theaterSeats; /** Constructs a Theater object, as described in part (a). * Precondition: seatsPerRow > 0; tier1Rows > 0; tier2Rows >= 0 */

public Theater(int seatsPerRow, int tier1Rows, int tier2Rows) {

theaterSeats= new Seat[tier1Rows+tier2Rows][seatsPerRow];

}

public boolean reassignSeat(int fromRow, int fromCol, int toRow, int toCol) {

if(theaterSeats[toRow][toCol].isAvailable()) {

int tierDestination =theaterSeats[toRow][toCol].getTier();

int tierSource =theaterSeats[fromRow][fromCol].getTier();

if(tierDestination<=tierSource) {

if(tierDestination==tierSource) {

if(fromRow<toRow) {

return false;

}else {

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}

}

theaterSeats[toRow][toCol].setAvailability(false);

theaterSeats[fromRow][fromCol].setAvailability(true);

return true;

}else {

return false;

}

}else {

return false;

}

}

public static void main(String[] args) {

//Lets understand it with simple example

Theater t1 = new Theater(3,1,2);

//Our threater has 3 seat in each row and we have one tier 1 row and 1 tier 2 row

//total no of seat will be 9.

//Lets create our seat

t1.theaterSeats[0][0] = new Seat(true,1);

t1.theaterSeats[0][1] = new Seat(false,1);

t1.theaterSeats[0][2] = new Seat(true,1);

t1.theaterSeats[1][0] = new Seat(true,2);

t1.theaterSeats[1][1] = new Seat(true,2);

t1.theaterSeats[1][2] = new Seat(true,2);

t1.theaterSeats[2][0] = new Seat(false,2);

t1.theaterSeats[2][1] = new Seat(false,2);

t1.theaterSeats[2][2] = new Seat(true,2);

//Lets print out theater and see which seat is available or which is not

System.out.println("Theater===>");

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

System.out.println("(2,1) want to change seat to (0,0)");

System.out.println("["+2+"]"+"["+1+"]"+"===>"+"["+0+"]"+"["+0+"]");

t1.reassignSeat(2, 1, 0, 0);

for(int i=0;i<3;i++) {

for(int j=0;j<3;j++) {

System.out.print("["+i+"]"+"["+j+"] : "+t1.theaterSeats[i][j].isAvailable()+" ");

}

System.out.println();

}

}

}

Answer:

See explaination for the details of the answer.

Explanation:

#include <iostream>

#include <stack>

using namespace std;

int main(){

string str;

cout<<"Enter a String: ";

std::getline (std::cin,str);

bool flag=true;

stack<char> st;

for(int i=0;i<str.size();i++){

if( (str.at(i)>='0' && str.at(i)<='9') || str.at(i)=='+' || str.at(i)=='-' || str.at(i)=='/'|| str.at(i)=='*' || str.at(i)==' ' ){

// cout<<str.at(i) <<"came"<<endl;

continue;

}

if( str.at(i)=='{' || str.at(i)=='(' ){

st.push(str.at(i));

}

else if(!st.empty() &&((st.top() == '{' && str.at(i) == '}') || (st.top() == '(' && str.at(i) == ')')))

st.pop();

else{

flag=false;

break;

}

}

if(!st.empty()){

cout<<"Does not match"<<"\n";

}else{

if(flag)

cout<<"Match"<<"\n";

else

cout<<"Does not match"<<"\n";

}

return 0;

}

See attachment for the output.

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class GtldValidation {

public static void main (String [ ] args) {

Scanner scnr = new Scanner(System.in);

// Define the list of valid core gTLDs

String [ ] validCoreGtld = { ".com", ".net", ".org", ".info" };

// FIXME: Define an array named validRestrictedGtld that has the names

// of the restricted domains, .biz, .name, and .pro

String [] validRestrictedGtld={".biz",".name",".pro"};

String inputName = "";

String searchName = "";

String theGtld = "";

boolean isValidDomainName = false;

boolean isCoreGtld = false;

boolean isRestrictedGtld = false;

int periodCounter = 0;

int periodPosition = 0;

int i = 0;

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

while (inputName.length() > 0) {

searchName = inputName.toLowerCase();

isValidDomainName = false;

isCoreGtld = false;

isRestrictedGtld = false;

// Count the number of periods in the domain name

periodCounter = 0;

for (i = 0; i < searchName.length(); ++i) {

if (searchName.charAt(i) == '.') {

++periodCounter;

periodPosition = i;

}

}

// If there is exactly one period that is not at the start

// or end of searchName, check if the TLD is a core gTLD or a restricted gTLD

if ((periodCounter == 1) &&

(searchName.charAt(0) != '.') &&

(searchName.charAt(searchName.length() - 1) != '.')) {

isValidDomainName = true;

}

if (isValidDomainName) {

// Extract the Top-level Domain name starting at the period's position. Ex:

// If searchName = "example.com", the next statement extracts ".com"

theGtld = searchName.substring(periodPosition);

i = 0;

while ((i < validCoreGtld.length) && (!isCoreGtld)) {

if(theGtld.equals(validCoreGtld[i])) {

isCoreGtld = true;

}

else {

++i;

}

}

// FIXME: Check to see if the gTLD is not a core gTLD. If it is not,

// check to see whether the gTLD is a valid restricted gTLD.

// If it is, set isRestrictedGtld to true

}

System.out.print("\"" + inputName + "\" ");

if (isValidDomainName) {

System.out.print("is a valid domain name and ");

if (isCoreGtld) {

System.out.println("has a core gTLD of \"" + theGtld + "\".");

}

else if (isRestrictedGtld) {

System.out.println("has a restricted gTLD of \"" + theGtld + "\".");

}

else {

System.out.println("does not have a core gTLD."); // FIXME update message

}

}

else {

System.out.println("is not a valid domain name.");

}

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

}

return;

}

}

Answer:

celsius = float(input("Enter the celcius value: "))

f = 1.8 * celsius + 32

print(str(celsius) + " C = "+ str(f) + " F")

Explanation:

The code is in Python.

Ask the user for the input, celsius value

Convert the celsius value to fahrenheit using the given formula

Print the result as in shown in the example output

Answer:

See explaination

Explanation:

#include<iostream>

#include<iomanip>

using namespace std;

int main(){

double tempF, tempC;

cout<<"Enter a degree in Celsius: ";

cin>>tempC;

tempF = tempC*(9/5.0)+32;

cout<<setprecision(1)<<fixed;

cout<<tempC<<" C = "<<tempF<<" F"<<endl;

return 0;

}

Answer:

see explaination

Explanation:

a)

amount = 5000

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

###### function ######

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

b)

amount <- enter amount

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

###### function ######

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

c)

#include <iostream>

using namespace std;

// function defination

double calculateInterest(double amount, double rate, int year);

int main(){

double amount, rate;

int year = 1;

cout<<"Enter amount: ";

cin>>amount;

cout<<"Enter rate: ";

cin>>rate;

// calling method

double interest = calculateInterest(amount, rate, year);

cout<<"Amount after 1 year: "<<(amount+interest)<<endl;

return 0;

}

// function calculation

double calculateInterest(double amount, double rate, int year){

return (amount*rate*year)/100.0;

}

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is

a)amount = 5000

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

b)amount <- enter amount

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

c)#include <iostream>

using namespace std;

double calculateInterest(double amount, double rate, int year);

int main(){

double amount, rate;

int year = 1;

cout<<"Enter amount: ";

cin>>amount;

cout<<"Enter rate: ";

cin>>rate;

double interest = calculateInterest(amount, rate, year);

cout<<"Amount after 1 year: "<<(amount+interest)<<endl;

return 0;

}

double calculateInterest(double amount, double rate, int year){

return (amount*rate*year)/100.0;

}

See more about python at brainly.com/question/18502436

Answer:

numBuckets = 47

def create():

global numBuckets

hSet = []

for i in range(numBuckets):

hSet.append([])

# print "[XYZ]: create() hSet: ", hSet, " type(hSet): ",type(hSet)

return hSet

def hashElem(e):

global numBuckets

return e % numBuckets

def insert(hSet,i):

hSet[hashElem(i)].append(i)

# print "[XYZ]: insert() hSet: ", hSet, " type(hSet): ",type(hSet)

def remove(hSet,i):

newBucket = []

for j in hSet[hashElem(i)]:

if j != i:

newBucket.append(j)

hSet[hashElem(i)] = newBucket

print "[XYZ]: remove() i: ", i," hashElem[i]: ", hashElem(i), " hSet[hashElem(i): ", hSet[hashElem(i)]

def member(hSet,i):

return i in hSet[hashElem(i)]

def testOne():

s = create()

for i in range(40):

insert(s,i)

print "[XYZ]: S: ", s

insert(s,325)

insert(s,325)

insert(s,9898900067)

print "[XYZ]: S: ", s

print "[XYZ]: ,member(s,325): ",member(s,325)

remove(s,325)

print "[XYZ]: After Remove, member(s,325): ",member(s,325)

print "[XYZ]: member(s,9898900067)",member(s,9898900067)

testOne()

Answer:

Professional implications refers  to when a number of folders in a laptop/machine goes higher,how to manage information becomes a problem, resulting into informational retrieval and storage issues.

Personal Implications refers to sharing of information on different websites, which might result in information theft or fraud once it gets into the hands of wrong people.

Business should be allowed to have access as much they want because, by having a standard procedures such as terms and conditions, this will enable them to protect their information, before allowing individuals to sign up on their sites, in terms of agreement of what the user wants to do with the contents.

Individuals should be allowed to have share more content on the internet, so that at any given time, if they can cancel the read access mode of any content they are accessing on the internet.

Explanation:

Just as the population increases, the need to store more  information by the population as goes higher.

When an any information is to be stored, it needs disk allocation or storage.  Now, we may be required to store address, Names of individuals, profile photos or phone numbers and so on. there are various path or method of achieving this.

The implications of storing this information are stated below

Professional Implications: As the number of files and folders in an office laptop/machines increases, this can lead to two vital issues which van either be information retrieval or storage issues.

Personal implications: This refers to sharing many personal data to different sites on the web in a way of an  electronic format this may result in  threat referred to  as'Data stealing or Theft.  

In a more understanding way, the information that is shared by us to a particular site on the web is given out to another third party website for some  benefit that are monetary.with this out information is at risk and can be used for negative purposes such as internet fraud or theft.

Business should be permitted to retrieve the data that they need unless there is standard  defined Terms and Conditions before permitting a user to have  access to their site on the web, so long as the  information they collect are used  for better and meaning purposes.

Users should be given full control to the contents that they like to share on various  website/apps. At any given time, they can cancel the read access mode from any of their contents present in internet.

Answer:

import java.util.*;

public class Dates {

   public static void main(String[] args) {

       String January,February, March, April, May, June, July,  

       August, September,October, November, December, month;

       January = February = March = April = May = June = July =  

               August = September = October = November = December = month = null;

       Scanner myScanner = new Scanner(System.in);  

       System.out.print("Enter date in the format mm/dd/yyyy: ");

       String input = myScanner.next();

       String months = input.substring(0,1);

       int monthInt = Integer.parseInt(months);

       if (monthInt == 01){

           month = January;

       }

       else if (monthInt == 02){

           month = February;

       }

       else if (monthInt == 03){

           month = March;

       }

       else if (monthInt == 04){

           month = April;

       }

       else if (monthInt == 05){

           month = May;

       }

       else if (monthInt == 06){

           month = June;

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

Answer:

#include <iostream>

using namespace std;

struct Course

{

int courseNumber;

int courseStartDate;

int courseHours;

int lecturerId;

};

struct Lecturer

{

int lecturerId;

int officeHours;

Course courseTeaching[2];

};

struct Student

{

int studentId;

Course coursesTaken[2];

};

int main()

{

Course courseObj1, courseObj2, courseObj3;

courseObj1.courseNumber = 1000;

courseObj1.courseStartDate = 20200107;

courseObj1.courseHours = 2;

courseObj1.lecturerId = 100;

courseObj2.courseNumber = 1100;  

courseObj2.courseStartDate = 20200113;

courseObj2.courseHours = 4;

courseObj2.lecturerId = 200;

courseObj3.courseNumber = 1200;

courseObj3.courseStartDate = 20200203;

courseObj3.courseHours = 4;

courseObj3.lecturerId = 100;

Lecturer lecturerObj1, lecturerObj2;

lecturerObj1.lecturerId = 100;

lecturerObj1.officeHours = 2;

lecturerObj1.courseTeaching[0] = courseObj1;

lecturerObj1.courseTeaching[1] = courseObj3;

lecturerObj2.lecturerId = 200;

lecturerObj2.officeHours = 2;

lecturerObj2.courseTeaching[0] = courseObj2;

Student student;

student.studentId = 2000;

student.coursesTaken[0] = courseObj1;

student.coursesTaken[1] = courseObj3;

cout << "1. Lecturer ID: " << lecturerObj1.lecturerId << "\tOffice Hours: " << lecturerObj1.officeHours << endl;

for(int i = 0; i < 2; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj1.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj1.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj1.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj1.courseTeaching[i].lecturerId << endl;

cout << "\n2. Lecturer ID: " << lecturerObj2.lecturerId << "\tOffice Hours: " << lecturerObj2.officeHours << endl;

for(int i = 0; i < 1; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj2.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj2.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj2.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj2.courseTeaching[i].lecturerId << endl;

int courseNumber;

cout << "\n Enter the course number: ";

cin >> courseNumber;

int index = -1;

int len = sizeof(student.coursesTaken) / sizeof(student.coursesTaken[0]);

int totalHours = 0;

for(int i = 0; i < len; i++)

{

if(student.coursesTaken[i].courseNumber == courseNumber)

{

totalHours += student.coursesTaken[i].courseHours;

}

}

if(totalHours == 0)

cout << "\n Student is not registered to this course!\n";

else

cout << "\nStudent " << student.studentId << " needs " << totalHours << " hours per week of this course.\n";

return 0;

}

Explanation:

Answer:particular layer N, a PDU is a complete message that implements the protocol at that layer. However, when this “layer N PDU” is passed down to layer N-1, it becomes the data that the layer N-1 protocol is supposed to service. Thus, the layer N protocol data unit (PDU) is called the layer N-1 service data unit (SDU). The job of layer N-1 is to transport this SDU, which it does in turn by placing the layer N SDU into its own PDU format, preceding the SDU with its own headers and appending footers as necessary. This process is called data encapsulation, because the entire contents of the higher-layer message are encapsulated as the data payload of the message at the lower layer.

What does layer N-1 do with its PDU? It of course passes it down to the next lower layer, where it is treated as a layer N-2 SDU. Layer N-2 creates a layer N-2 PDU containing the layer N-1 SDU and layer N-2’s headers and footers. And the so the process continues, all the way down to the physical layer. In the theoretical model, what you end up with is a message at layer 1 that consists of application-layer data that is encapsulated with headers and/or footers from each of layers 7 through

Explanation:

Answer:

An example  of poor work ethic which I encountered recently was the observation of poor hygiene by an employee of a fast-food outlet of a renowned company.

Explanation:

Some patties suddenly slipped out of his hands and fell on the ground. He did not discard them and simply put them into burg adversely. ers. The fall must have soiled and contaminated them, which would affect the health of consumers. Such incidents can be avoided by the company by training the staff in such possibilities and suggesting corrective actions. Monitoring and taking action against offenders will also help. IT professionals should have good analytical and interpersonal skills besides cross-cultural sensitivity to do good in their roles.

You should apologize for his mistake for reaching the wrong place. The message should be through an electronic message ( sms ) or another instant messaging service, followed by a telephone call. The content of the message should comprise of an apology for not being able to reach in time, the reason for the misunderstanding, your current location and the approximate time it will take to reach the venue. It will be better if you share your location with the client through a GPS enabled application, so that it will be convenient to coordinate.

The tow more skills that are good for IT professionals the the skill off After sale services, and to establish a good relationship with clients.

Answer:

The answer to this question can be defined as below:

Explanation:

The three uses of the spreadsheet can be described as follows:

In Business:

In Auditing:

In nursing:

Answer:

Invoice_Date and Salesman Id

Explanation:

As the WHERE clause looking at the Invoice_Date and Salesman Id columns so they should be indexed for the following reasons.

Answer:

import java.util.*;

public class num2 {

   public static void main(String[] args) {

       //Set the Value of the argument

       int val = 5;

       //Call the method

       int returnedNum = testInteger(val);

       //Use a While to continously call the method as long as the returned value is not 0

       while(returnedNum != 0){

           int rt = testInteger(val);

           //Break out of loop when the user enters correct value and the return is 0

           if(rt == 0){

               break;

           }

       }

   }

   //The Method definition

   public static int testInteger(int val){

       //Prompt and receive user input

       System.out.println("Enter a number");

       Scanner in = new Scanner(System.in);

       int userNum = in.nextInt();

       //Check different values using if and else statements

       if(userNum > val){

           System.out.println("Too High");

           return 1;

       }

       else if(userNum < val){

           System.out.println("Too Low");

           return -1;

       }

       else{

           System.out.println("Got it");

         return 0;

       }

   }

}

Explanation:

This is solved with Java Programing Language

Pay close attention to the comments provided in the code

The logic is using a while loop to countinually prompt the user to enter a new number as long as the number entered by the user is not equal to the value of the argument already set to 5.

Answer:

def high_low(val):

   number = int(input("Enter a number: "))

   if number > val:

       print("Too high")

       return 1

   elif number < val:

       print("Too low")

       return -1

   elif number == val:

       print("Got it!")

       return 0

val = 7

while True:

   if high_low(val) == 0:

       break

Explanation:

The code is in Python.

Create a function called high_low that takes one parameter, var

Ask the user for a number. Check the number. If the number is greater than 1, smaller than 1 or equal to 1. Depending on the number, print the required output and return the value.

Set the value to a number. Create a while loop iterates until the user enters the correct number, when the return value of the function is equal to 0, that means the user entered the correct number. Otherwise, it keeps asking the number and prints the appropriate message.

Answer:

public static ArrayList manyStrings(ArrayList<String> list, int n){

    ArrayList<String> newList = new ArrayList<String>();

    for (int i=0; i<list.size(); i++) {

        for (int j=0; j<n; j++) {

            newList.add(list.get(i));

        }

    }

    return newList;

}

Explanation:

Create a method called manyStrings that takes two parameters, list and n

Create a new ArrayList that will hold new values

Create a nested for loop. The outer loop iterates through the list. The inner loop adds the elements, n of this element, to the newList.

When the loops are done, return the newList

Answer:

Compare the predictions in terms of the predictors that were used, the magnitude of the difference between the two predictions, and the advantages and disadvantages of the two methods.

Our predictions for the two models were very simmilar. A difference of $32.78 (less than 1% of the total price of the car) is statistically insignificant in this case. Our binned model returned a whole number while the full model returned a more “accurate” price, but ultimately it is a wash. Both models had comparable accuracy, but the full regression seemed to be better trained. If we wanted to use the binned model I would suggest creating smaller bin ranges to prevent underfitting the model. However, when considering the the overall accuracy range and the car sale market both models would be

Explanation:

Answer:

SELECT country.Name, city.Name

FROM country

JOIN countrylanguage ON country.Code = countrylanguage.CountryCode

JOIN city ON country.Capital = city.ID

WHERE countrylanguage.Language = 'English'

AND countrylanguage.Percentage < 30;

Explanation:

SELECT is used to query the database and get back the specified fields.

City.Name is an attribute of city table.

country.Name is an attribute of country table.

FROM is used to query the database and get back the preferred information by specifying the table name.

country , countrylanguage and city are the table names.

country and countrylanguage are joined based ON country.Code = countrylanguage.CountryCode

countrylanguage and city are joined based ON country.Capital = city.ID

WHERE is used to specify a condition based on which the data is to be retrieved. The conditions are as follows:

countrylanguage.Language = 'English'

countrylanguage.Percentage < 30;

‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎   ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎ .‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎  ‏‏‎

Final answer:

The provided response includes a Java implementation of the radixSort algorithm that sorts an array of integers with only even digits and aborts if odd digits are found. The running time complexity is O(nk) but is effectively O(n) due to the fixed set of digits.

Explanation:

The student has asked to implement the radixSort algorithm in Java, which sorts an array of integers containing only even digits (0, 2, 4, 6, and 8). Moreover, the program should abort if odd digits are present in the keys. Here's an example implementation:

import java.util.ArrayList;

class RadixSortExample {
   public void radixSort(int[] arr) {
       final int RADIX = 10;

       // Find the maximum number to know the number of digits
       int max = arr[0];
       for (int i = 1; i < arr.length; i++) {
           if (arr[i] > max) max = arr[i];
       }

       // Abort if odd digits found
       for (int num : arr) {
           if (containsOddDigit(num)) {
               throw new IllegalArgumentException("Array contains odd digits, which is not allowed.");
           }
       }

       // Perform sorting
       for (int exp = 1; max / exp > 0; exp *= RADIX) {
           countSort(arr, exp);
       }
   }

   private void countSort(int[] arr, int exp) {
       ArrayList<ArrayList<Integer>> bucketList = new ArrayList<>(10);
       for (int i = 0; i < 10; i++) {
           bucketList.add(new ArrayList<>());
       }

       // Distribute the numbers based on the digit at the given exponent
       for (int num : arr) {
           int bucketIndex = (num / exp) % 10;
           bucketList.get(bucketIndex).add(num);
       }

       // Merge the buckets
       int index = 0;
       for (int i = 0; i < 10; i++) {
           for (int num : bucketList.get(i)) {
               arr[index++] = num;
           }
       }
   }

   private boolean containsOddDigit(int num) {
       while (num > 0) {
           if ((num % 10) % 2 != 0) return true;
           num /= 10;
       }
       return false;
   }
}

As for the running time complexity of the radixSort method, it is O(nk), where n is the number of keys and k is the number of digits in the maximum key. The algorithm runs digit by digit, but since we're dealing with a fixed set of digits (even digits only), the k value is bounded and the complexity can also be seen as O(n) for practical considerations, especially when the range of the input is restricted.

Answer:

An Epic is a container for a Solution development initiative large enough to require analysis, the definition of a Minimum Viable Product (MVP), and financial approval prior to implementation. Implementation occurs over multiple Program Increments (PIs) and follows the Lean startup 'build-measure-learn' cycle.

Explanation:

Hope this is what your looking for

The purpose of a Program Epic is to represent business capabilities that address various user needs.

What is Program Epic ?

An Epic is a holder for a Solution improvement drive sufficiently enormous to require examination, the meaning of a Minimum Viable Product (MVP), and monetary endorsement preceding execution. Execution happens over numerous Program Increments (PIs) and follows the Lean startup 'assemble measure-learn' cycle.

A program epic obliged to a solitary delivery train, conveyed by different groups, and crossing numerous PI emphases. Program Epics can address business abilities that address different client needs. Include: Functionality that meets explicit partner needs.

Thus, the purpose is explained.

Learn more about Program Epic

https://brainly.com/question/15450565

#SPJ2

Answer:

Public Class Form1

   Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click

       Dim sum, product, num1, num2 As Integer

       num1 = Val(TextBox1.Text)

       num2 = Val(TextBox2.Text)

       sum = num1 + num2

       product = num1 * num2

       TextBox3.Text = sum

       TextBox4.Text = product

   End Sub

End Class

Answer:

program:

#your name

print("{:10} {:10} {:10}".format("Number","Square","Cube"))

print("{:<10} {:<10} {:<10}".format(0,0,0))

print("{:<10} {:<10} {:<10}".format(1,1,1))

print("{:<10} {:<10} {:<10}".format(2,2**2,2**3))

print("{:<10} {:<10} {:<10}".format(3,3**2,3**3))

print("{:<10} {:<10} {:<10}".format(4,4**2,4**3))

print("{:<10} {:<10} {:<10}".format(5,5**2,5**3))

print("{:<10} {:<10} {:<10}".format(6,6**2,6**3))

print("{:<10} {:<10} {:<10}".format(7,7**2,7**3))

print("{:<10} {:<10} {:<10}".format(8,8**2,8**3))

print("{:<10} {:<10} {:<10}".format(9,9**2,9**3))

print("{:<10} {:<10} {:<10}".format(10,10**2,10**3))

output:

Number Square Cube

0 0 0

1 1 1

2 4 8

3 9 27

4 16 64

5 25 125

6 36 216

7 49 343

8 64 512

9 81 729

10 100 1000

The program reads whitespace-delimited strings and an integer frequency, then outputs strings with the specified frequency in a case-insensitive manner using a frequency counting approach.

In this programming task, the goal is to create a program that reads whitespace-delimited strings and an integer frequency (freq). The program should then output the strings from the input that have a frequency equal to the specified freq in a case-insensitive manner.

To achieve this, the program needs to:

1. Read input: Use an input mechanism to read whitespace-delimited strings and the integer frequency.

2. Count frequency: Maintain a data structure, such as a dictionary or a hashmap, to store the frequency of each string. While reading the input strings, update the frequency count accordingly.

3. Filter strings: Iterate through the stored strings and output only those with a frequency equal to the specified freq. Ensure case-insensitivity by converting all strings to lowercase during comparison.

Here's a Python example:

```python

def find_strings_with_frequency(words, freq):

   word_count = {}    

   # Count the frequency of each word

   for word in words:

       word_lower = word.lower()

       word_count[word_lower] = word_count.get(word_lower, 0) + 1    

   # Output strings with the specified frequency

   result = [word for word, count in word_count.items() if count == freq]    

   return result

# Example usage

input_words = input("Enter whitespace-delimited strings: ").split()

input_freq = int(input("Enter frequency: "))

output_strings = find_strings_with_frequency(input_words, input_freq)

print("Strings with frequency {}: {}".format(input_freq, output_strings))

```

This program takes user input for whitespace-delimited strings and an integer frequency, processes the input, and outputs strings with the specified frequency in a case-insensitive manner.

Answer:

Check the explanation

Explanation:

weights = [2,3,4,5,9] #assign the weights here

value = [3,4,8,8,10] #assign the values here

#recursive function to get the maximum weight for a given knapsack

def getMaxWeight(weights,value,W,n):

#check if any elements are there or check if the knapsack can hold any more weights

if(n==0 or W==0):

return 0

elif(weights[n]>W):

#if the current value of the weight is greater than what a knapsack can hold then discard that

return getMaxWeight(weights,value,W,n-1)

else:

#either choose the current weight or do not choose based on the maximum values

return max(value[n]+getMaxWeight(weights,value,W-weights[n],n-1),getMaxWeight(weights,value,W,n-1))

if __name__ == '__main__':

W=20

n=len(weights)-1

print("Weights are:",weights)

print("Values are:",value)

print("Maximum value for given knapsack is:",getMaxWeight(weights,value,W,n))

Kindly check the attached output images below.

Answer:

void showSeatingChart(const string [][COLS], int);

Explanation:

void showSeatingChart(const string [][COLS], int);

The above function showSeatingChart() will display the 2D array of seating chart.

The return type of this function is void because it does not need to retun anything.

The parameter of the function is a 2D array which is seatingChart[ROWS][COLS].

The type of this 2D array is string that means it is a 2D array of string. It will contain string elements.

To declare a prototype of a function, there should be a semi-colon (;) at the end of declaration.

The definition of the function should be given outside main() function and declaration of the function should be above the main() function or at the beginning of the program with declaration of constant variables.

Input the three numbers. A first method must be called and used to develop logic to find the smallest of the three numbers. A second method must be used to print out that smallest number found.

Explanation:

import java.util.Scanner;

public class Exercise1 {

public static void main(String[] args)

   {

       Scanner in = new Scanner(System.in);

       System.out.print("Input the first number: ");

       double x = in.nextDouble();

       System.out.print("Input the Second number: ");

       double y = in.nextDouble();

       System.out.print("Input the third number: ");

       double z = in.nextDouble();

       System.out.print("The smallest value is " + smallest(x, y, z)+"\n" );

   }

  public static double smallest(double x, double y, double z)

   {

       return Math.min(Math.min(x, y), z);

   }

}

Answer:

1. Python is called as interpreted language. However as a programming language it is not fully compiled nor interpreted language. Python program runs from direct source code which makes it byte code interpreted.

An Interpreter is the one which takes the code and performs the actions specified in the code. It turns the code into intermediate language which is again translated to machine language understood by the processor. Interpreted or compiled are the property of the implementation and not of the language.

2. Array : It is a collection of same data type elements stored at contagious memory location. It is handled in python with module array. All the elements of array must be of same data type. In order to manipulate same data types arrays are used.

Ex: array1 = a.array ('i', [10, 20, 30]) this is a array of integer type.

Lists : Python lists are ordered data structure and are like non homogeneous dynamic sized arrays. It may contain integers, strings, boolean, or objects.

Ex: List1 = [70, 89, 98] , List2 = ["Rose", "Lilly", "Jasmine"]

List3 = [1, 10, 100, 'Test', 'Test1']

Tuple : It is a collection of objects separated by commas and they are immutable. It is static which makes them faster.

Ex: tupule1 = ('element1', 'element2')

List and Tuple in Python are the class of data structure. The list is dynamic, whereas tuple has static characteristics.

Lists are mutable but tuples are not.

tuples are mainly used to access the elements where as lists are used in operations like insertion and deletion.

Iterations are time consuming in list where as it is faster in tuples.

tuples don't have inbuilt methods but list has many builtin methods.

tuples takes slightly less memory that lists in Python

Records: Records data structure will have fixed number of fields and each field may have a name and different type. Immutable records are implemented using named tuple.

3. Syntax of slice in python is list[<start>:<stop>:<step>] and it can be used on tuples and lists.

so X [::-1] means that it will start from the end towards the first element by taking each of the elements.

for ex: X = '9876'

X [::-1] will result in '6789'.

Means it will reverse all the elements in the array.

4. Items of list can be shuffled with the random.shuffle() function of a random module.

Syntax is : random.shuffle(x, random)

x- It is a sequence to shuffle and can be list or tuple.

random- it is a optional argument which returns random float number between 0.1 to 1.0.

5. range() – Range function returns a range object which is a type of iterable object.

xrange() – xrange function returns the generator object that can be used to display numbers only by looping. Only particular range is displayed on demand and hence called “lazy evaluation“.

• Return type of range () is range object whereas that of xrange() is xrange object.

• Variable to store the range using range () takes more memory but xrange takes comparative less memory.

• Range returns the list but xrange returns the xrange object. Hence operations on list can be applied for range but not on xrange.

• Xrange is faster to implement than range as xrange evaluates only generator objects.

• Xrange is depreciated in Python 3 and above.

For ex :

x = range (10, 100)

y= xrange (10, 100)

#To know the return type we can print it

print ( return type of range () is : “)

print (type (x))

print ( return type of xrange () is : “)

print (type (y))

Output will be list and xrange respectively.

6. NumPy's arrays are more compact than Python lists

reading and writing items is also faster with NumPy.

Memory taken by python lists are way higher than NumPy arrays.

Python lists don’t support vectorized operation.

Since lists can contain objects of different types its type information must be stored and executed every time operation is performed on it.

Memory taken by python lists are a lot higher than that of NumPy Arrays.

Reading and writing of elements in NumPy arrays are faster than lists.

NumPy arrays are compact and accumulate lesser storage.

Numpy is convenient and efficient.

For ex :

Metrics operations are easy in NumPy.

Checkerboard pattern can be done using NumPy.

7. Attached as Image

8. split() method returns a list of strings after breaking the given string by the specified separator. It is splitting of string into list with each word is a list item.

Syntax : str.split ( separator, maxsplit)

Separator : its is delimiter used and by default whitespace is used as separator.

Maxsplit : Maximum number of times to split the string. By default it has no limit.

For ex:

text = 'apples and oranges are different '

print(text.split())

output will be : ['apples', 'and', 'oranges', 'are', 'different' ]

Explanation:

Answer:

It Is C to shorten it The answer is C

Explanation:

Answer:

See explaination

Explanation:

format RAT

Number=input('Enter the no. of resistors:');

R=ParallelR(Number)

function Req=ParallelR(N)

R=0;

for i=1:N

r=input('Enter Resistor Value:');

R=R+1/r;

end

Req=(1/R);

end