The question is incomplete. The complete question is as follows.
Juan, Carlos and Maria went to the museum. The entrance ticket cost $5 per person, but, as they are students, there is a discount of $1 per ticket. After, they bought: 3 combos of chicken and fries costing $4 each; 3 bottles of water costing $1 each; 3 vanilla cookies costing $1 each; How much money each student paid if they divided the costs in equal amount?
Answer: $10
Step-by-step explanation: As each students split the bill in equal parts, to find how much they spent, we can calculate how much one of the three spent.
For ticket: 5 - 1 (because of the students discount) = $4
Each combo of chicken and fries cost $4, so: combo = $4
Each bottle of water costs $1, so: water = $1
and each vanilla cookie costs $1: cookie = $1
Total spent is:
T = 4+4+1+1
T = 10
Each student spent a total of $10 for this outing.
Zoe made 6 3/4 cups of fruit salad for a picnic at the picnic they ate 1/3 of the fruit salad how much fruit salad did they eat
6 3/4 = 27/4
27/4 * 1/3 = 27/12
27/12 = 9/4
Answer: 9/4 cups
To find out how much fruit salad was eaten, convert the mixed number to an improper fraction and multiply by the fraction representing the amount eaten.
Explanation:To calculate how much fruit salad was eaten, we need to find 1/3 of 6 3/4 cups. First, we convert the mixed number 6 3/4 to an improper fraction by multiplying the whole part (6) by the denominator (4) and adding the numerator (3) to it. This gives us 27/4 cups. Next, we multiply 27/4 by 1/3, which can be simplified to 9/4. So, they ate 9/4 cups of fruit salad.
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The number of cell phone accounts in a certain country has increased exponentially for the last decade. The number of cell phone accounts (in millions) in this country can be approximated by the following function. Estimate the number of cell phone accounts in 2003.
f(x)= 114.8e.125x (0
What was the approximate number of cell phone accounts in 2003?
Answer:
See Below
Step-by-step explanation:
The equation estimating the number of cellphones in the country is:
[tex]f(x)=114.8 e^{0.125x}[/tex]
Where x = 0 corresponds to year 2000
thus,
x = 1 is year 2001
x = 2 is year 2002
x = 3 is year 2003
and so on...
We want approx. number of cellphones in the country in 2003. This corresponds to x = 3. So substituting in the equation we get:
[tex]f(x)=114.8 e^{0.125x}\\f(3)=114.8 e^{0.125(3)}\\f(3)= 167.03[/tex]
So, approximately there were 167.03 million cellphones in the country in 2003
Find the volume of a sphere with a diameter of 20 inches
Answer:
V≈4188.79in³
Step-by-step explanation:
4.188.79in3
BeanPod Groceries will deliver. The delivery fee is $9.95 for a minimum order of $60, which drops to $6.95 for orders of $100 or more. Your order comes to $99.48. If you add a last-minute item costing $1.99 what will your final bill be?
Answer:
$99.44 + $1.99 = $101.47
Delivery fee: $6.95
Final bill: $101.47 + 6.95 = $108.42
The final bill will be either $109.43 or $108.42, depending on whether the last-minute item is included in the order.
Explanation:To calculate the final bill, we need to consider two scenarios: the order without the last-minute item and the order with the last-minute item. First, let's calculate the delivery fee for an order without the last-minute item. Since the order total is $99.48, which is less than $100, the delivery fee will be $9.95. Now, let's calculate the final bill by adding the delivery fee to the order total: $99.48 + $9.95 = $109.43.
Next, let's calculate the delivery fee for an order with the last-minute item. Since the order total will be $101.47 ($99.48 + $1.99), which is more than $100, the delivery fee will be $6.95. To calculate the final bill, we need to add the delivery fee to the updated order total: $101.47 + $6.95 = $108.42.
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A carousel has eight evenly spaced seats shaped like animals. During each ride, the carousel makes between 8 and 9 clockwise revolutions. At the end of one ride, the carousel stops so that the lion is in the position where the zebra was when the ride started. Through how many degrees did the carousel rotate on this ride
Answer:
2931 + 51.4n/7 degrees where n is the number of animal from the lion to the zebra in the clockwise direction.
Step-by-step explanation:
We don't have details on the positions of the lion and the zebra prior to revolution but suppose the zebra is n animal away from the lion where n could be in the range of 0 to 6 in the clockwise direction. If n = 0, the zebra is next to the lion in line, and if n = 6, the zebra is right behind the lion.
In angular term, since all 8 animals are evenly spaced, there are 7 space in between them, each of them would span an angle of 360/7 degrees
Then the angular distance between the zebra and the lion is (n+1)360/7 degrees
If the carousel makes between 8 and 9 revolutions then the total angular distance is 8*360 + (n+1)360/7 = 2931 + 51.4n/7 degrees
Answer:
-2970, -3320
Step-by-step explanation:
The carousel makes between 8 and 9 clockwise revolutions
the position of the lion rotated to that of the zebra is two steps
now,
1 revolution = 360 degrees accomplished in 8 steps
1 step = 360/8 = 45 deg
=> position of lion rotated to zebra = 2 × 45 = 90 deg
if 1 revolution = 360 accomplished in 9 steps
then
1 step = 360/9 = 40 deg
=> position of lion rotated to zebra = 2 × 40 = 80 deg
since the rotation is in clockwise direction, a negative sign is required
FOR 8 Revolutions
in total the carousel rotates
-[8(360) + 90] degrees
= -2970 degrees
FOR 9 revolution
in total the carousel rotates
-[9(360) + 80] degrees
= -3320 degrees
Determine the center of the following data set by finding
the median.
Test Scores
47,50,43, 42, 42, 38, 49, 47, 42, 50
Answer:
The median of this set is 45.
Step-by-step explanation:
Maximum height___feet
Answer:
you are not aloud to cheat on tests please don't do that sorry can't answer to a cheater
Step-by-step explanation:
Make x the subject of m =n+x/p
Answer:
[tex]x = p( m - n)[/tex]
Step-by-step explanation:
[tex]m = n + \frac{x}{p} \\ m - n = \frac{x}{p} \\ p(m - n) = \frac{x}{p} \times p \\ \\ x = p(m - n)[/tex]
(06.01)
A class has 21 girls and 12 boys. What is the probability that a boy's name is drawn at random? (5 points)
Answer:
In my opinion I think the answer is C.12/33
Step-by-step explanation:
this would be the answer because...
1. First, add up the amount of boys and girls
21 girls+ 12 boys= 33 total
2. Next, since its asking for the probability for a boys name to de drawn at random, your going to divide 12 by 33
12/33Answer:
it is c i took test good luck
Step-by-step explanation:
sike i lied your a is mine lol
Find the theoretical probability of the event when rolling a standard number cube. P(6)
The theoretical probability of rolling a 6 on a standard number cube is 1/6 or approximately 0.1667.
Explanation:The theoretical probability of rolling a 6 on a standard number cube is 1/6 or approximately 0.1667.
To find the probability, we divide the number of successful outcomes (rolling a 6) by the total number of possible outcomes (numbers 1 to 6), which is 6.
So the probability is 1/6 or 0.1667.
Since a standard number cube has equal chances of landing on any number from 1 to 6, each outcome has the same probability of occurring, which is 1/6.
Thus, the theoretical probability of the event when rolling a standard number cube is found to be 1/6 or approximately 0.1667.
Final answer:
The theoretical probability of rolling a six on a standard six-sided die is 1 in 6, or P(6) = 1/6.
Explanation:
The student has asked about finding the theoretical probability of rolling a six, P(6), with a standard six-sided die. In a fair six-sided die, the outcomes are equally likely, meaning the probabilities for each number 1 through 6 are the same. Given that there are six possible outcomes, the probability of rolling any one specific number, for example 6, is 1 out of the 6 total possible outcomes. Therefore, P(6) = 1/6. This probability reflects that, theoretically, if we were to roll the die many times, we'd expect to roll a 6 in approximately one-sixth of all the rolls.
Refer to speeds at which cars pass through a checkpoint on the highway. Assume the speeds are normally distributed with a population mean of 61 miles per hour and a population standard deviation of 4 miles per hour. Calculate the probability that the next car passing will be travelling more than 66 miles per hour.
Answer:
Probability that the next car passing will be travelling more than 66 miles per hour is 0.10565.
Step-by-step explanation:
We are given that the the speeds are normally distributed with a population mean of 61 miles per hour and a population standard deviation of 4 miles per hour.
Let X = speed of car
The z-score probability distribution for normal distribution is given by;
Z = [tex]\frac{ X-\mu}{\sigma}} }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean speed = 61 miles per hour
[tex]\sigma[/tex] = standard deviation = 4 miles per hour
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the next car passing will be travelling more than 66 miles per hour is given by = P(X > 66 miles per hour)
P(X > 66) = P( [tex]\frac{ X-\mu}{\sigma}} }[/tex] > [tex]\frac{ 66-61}{4}} }[/tex] ) = P(Z > 1.25) = 1 - P(Z [tex]\leq[/tex] 1.25)
= 1 - 0.89435 = 0.10565
So, in the z table the P(Z [tex]\leq[/tex] x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.25 in the z table which has an area of 0.89435.
Hence, the probability that the next car passing will be travelling more than 66 miles per hour is 0.10565.
Final answer:
The probability that the next car passing will be traveling more than 66 miles per hour, given a mean speed of 61 mph and standard deviation of 4 mph, is approximately 10.56%.
Explanation:
To calculate the probability that the next car passing will be traveling more than 66 miles per hour, given the speeds are normally distributed with a mean of 61 miles per hour and a standard deviation of 4 miles per hour, we use the Z-score formula.
The Z-score formula is: Z = (X - μ) / σ, where μ is the mean, σ is the standard deviation, and X is the value we're interested in.
Substitute the given values into the formula to find the Z-score for 66 miles per hour.
Z = (66 - 61) / 4 = 5 / 4 = 1.25.
Next, we look up the Z-score of 1.25 on the standard normal distribution table or use a calculator to find the area to the left of Z. The area to the left of Z=1.25 is approximately 0.8944. To find the probability of a car traveling more than 66 miles per hour, we subtract this value from 1.
Probability = 1 - 0.8944 = 0.1056.
Therefore, the probability that the next car passing will be traveling more than 66 miles per hour is approximately 10.56%.
Match the number to the value of its 7
Answer:
The first one is matched with 700,000
The second one is matched with 7
The third one is matched with 70
The fourth one is matched with 70,000
Step-by-step explanation:
Look at where the 7 is in the number, and replace all the digits to the right of it with 0's. Get rid of the digits to the left of the 7, if any
Answer:
1-->1
2-->3
3-->2
4-->4
Step-by-step explanation:
In the first number the 7 is in the the hundred thousands place. In the second the 7 is in the ones place. In the third the 7 is in the tens place. In the fourth the 7 is in the ten thousands place.
How many black cherry trees have a height of 80 or more feet?
(Group of answer choices)
A) 7
B) 5
C) 10
D) 17
Which would you use to solve the equation? Check all that apply.
12.7 = j – 3.4
Subtract 3.4 from both sides of the equation.
Add 3.4 to both sides of the equation.
12.7 + 3.4 = 16.1, so j = 16.1.
12.7 – 3.4 = 9.3, so j = 9.3.
Substitute 9.3 for j to check the solution.
Substitute 16.1 for j to check the solution.
Answer:
the answer is B,C,F
Step-by-step explanation:
The correct options are,
1. Add 3.4 to both sides of the equation.
2. 12.7 + 3.4 = 16.1, so j = 16.1.
3. Substitute 16.1 for j to check the solution.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
The steps to solve the equation: 12.7 = j - 3.4 are as follows,
Add 3.4 to both sides of the equation,
12.7 + 3.4 = j
Solve for j,
16.1 = j
So the solution is j = 16.1
To check the solution, you would substitute 16.1 for j in the original equation and see if both sides are equal.
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According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1 comma 100 Americans results in 121 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.
Answer:
Event is not unusual(p>0.05).
Step-by-step explanation:
Given that :
[tex]p=0.10\\\\n=1100\\\\x=121[/tex]
#The sample proportion is calculated as:
[tex]\hat p=\frac{x}{n}\\\\=\frac{121}{1100}\\\\=0.1100[/tex]
#Mathematically, the z-value is the value decreased by the mean then divided the standard deviation :
[tex]z=\frac{\hat p- p}{\sqrt{\frac{p(1-p)}{n}}}\\\\\\\\=\frac{0.11-0.10}{\sqrt{\frac{0.10(1-0.10)}{1100}}}\\\\\\=1.1055[/tex]
#We use the normal probability table to determine the corresponding probability;
[tex]P(X\geq 121)=P(Z>1.1055)\\\\=0.1314[/tex]
Hence, the probaility is more than 0.05, thus the event not unusual and thus this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.
The mean weekly earnings of a sample of 30 construction workers was $759, with a standard deviation of $73, and the mean weekly earnings of a sample of 28 manufacturing workers was $658, with a standard deviation of $65. Construct a 85% confidence interval for the difference between the mean weekly earnings for construction workers and the mean weekly earnings for manufacturing workers. Round to the second decimal place.
Answer:
[tex] (759-658) -1.46 \sqrt{\frac{73^2}{30} +\frac{65^2}{28}}= 74.54[/tex]
[tex] (759-658) +1.46 \sqrt{\frac{73^2}{30} +\frac{65^2}{28}}= 127.46[/tex]
And the confidence interval for the difference of the two means is given by (74.54, 127.46)
Step-by-step explanation:
Information given:
[tex]\bar X_1 = 759[/tex] the sample mean for construction workers
[tex] s_1 =73[/tex] the sample standard deviation for construction workers
[tex]n_1 =30[/tex] sample size of construction workers
[tex]\bar X_2 = 658[/tex] the sample mean for manufacturing workers
[tex] s_2 =65[/tex] the sample standard deviation for manufacturing workers
[tex]n_2 =28[/tex] sample size of construction workers
Confidence interval
The confidence interval for the difference of means are given by:
[tex] (\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}[/tex]
We need to find the degrees of freedom given by:
[tex] df = n_1 +n_2 -2= 30+28-2=56[/tex]
The confidence is 0.85 and the significance level would be [tex]1-0.85=0.15[/tex] and [tex]\alpha/2 = 0.075[/tex]. We need to find a critical value in the t distribution who accumulates 0.075 of the area on each tail and we got:
[tex] t_{\alpha/2}= \pm 1.46[/tex]
And then we can replace and we got:
[tex] (759-658) -1.46 \sqrt{\frac{73^2}{30} +\frac{65^2}{28}}= 74.54[/tex]
[tex] (759-658) +1.46 \sqrt{\frac{73^2}{30} +\frac{65^2}{28}}= 127.46[/tex]
And the confidence interval for the difference of the two means is given by (74.54, 127.46)
Part (a): The 80% confidence interval for the earnings difference is $77.51 to $124.49.
Part (b): The interval suggests 80% confidence in the true earnings difference falling within $77.51 to $124.49.
Part (c): Since zero isn't in the interval, there's a significant pay difference between construction and manufacturing workers.
Part (a): Construct an 80% confidence interval for the difference between the mean weekly earnings
Step 1: Identify the given data
- Construction workers:
- Mean [tex](\(\bar{X_1}\)) = \$759[/tex]
- Standard deviation [tex](\(s_1\)) = \$73[/tex]
- Sample size [tex](\(n_1\))[/tex] = 30
- Manufacturing workers:
- Mean [tex](\(\bar{X_2}\)) = \$658[/tex]
- Standard deviation [tex](\(s_2\)) = \$65[/tex]
- Sample size [tex](\(n_2\)) = 28[/tex]
Step 2: Determine the formula for the confidence interval
We use the formula for the confidence interval of the difference between two independent means:
[tex]\[ (\bar{X_1} - \bar{X_2}) \pm t_{\alpha/2} \cdot \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} \][/tex]
Step 3: Calculate the standard error (SE) of the difference
[tex]\[ SE = \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} \][/tex]
[tex]\[ SE = \sqrt{\frac{73^2}{30} + \frac{65^2}{28}} \][/tex]
[tex]\[ SE = \sqrt{\frac{5329}{30} + \frac{4225}{28}} \][/tex]
[tex]\[ SE = \sqrt{177.63 + 150.89} \][/tex]
[tex]\[ SE = \sqrt{328.52} \approx 18.12 \][/tex]
Step 4: Determine the degrees of freedom (df) using the Welch-Satterthwaite equation
[tex]\[ df = \frac{\left(\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}\right)^2}{\frac{\left(\frac{s_1^2}{n_1}\right)^2}{n_1-1} + \frac{\left(\frac{s_2^2}{n_2}\right)^2}{n_2-1}} \][/tex]
[tex]\[ df \approx \frac{328.52^2}{\frac{(177.63)^2}{29} + \frac{(150.89)^2}{27}} \][/tex]
[tex]\[ df \approx \frac{107,922.4}{1090.15 + 843.48} \][/tex]
[tex]\[ df \approx \frac{107,922.4}{1933.63} \approx 55.83 \approx 56 \][/tex]
Step 5: Find the t-value for an 80% confidence interval
For df ≈ 56 and [tex]\(\alpha/2 = 0.10\),[/tex] the t-value [tex](\(t_{0.10}\))[/tex] is approximately 1.296.
Step 6: Construct the confidence interval
[tex]\[ (\bar{X_1} - \bar{X_2}) \pm t_{\alpha/2} \cdot SE \][/tex]
[tex]\[ (759 - 658) \pm 1.296 \cdot 18.12 \][/tex]
[tex]\[ 101 \pm 23.49 \][/tex]
[tex]\[ (77.51, 124.49) \][/tex]
So, the 80% confidence interval for the difference between the mean weekly earnings is [tex]\((77.51, 124.49)\).[/tex]
Part (b): Explanation of the Confidence Interval
The 80% confidence interval [tex]\((77.51, 124.49)\)[/tex] means that we are 80% confident that the true difference between the mean weekly earnings of construction workers and manufacturing workers lies between [tex]\$77.51[/tex] and [tex]\$124.49[/tex]. In other words, if we were to take many samples and compute the confidence interval for each, about 80% of those intervals would contain the true difference in mean earnings.
Part (c): Is there a significant difference in pay?
To determine if there is a significant difference in pay, we look at whether the confidence interval includes zero. Since the 80% confidence interval for the difference in mean earnings (\(77.51, 124.49\)) does not include zero, we can conclude that there is a statistically significant difference in pay between construction workers and manufacturing workers at the 80% confidence level.
Complete Question:
A mechanic finds that 30% of his customers own foreign cars, and that 40% own dogs. Assuming that these events are independent, what percent of the customers have neither a foreign car nor a dog
Answer:
42%
Step-by-step explanation:
Answer:
Since the events are independent, 30% of his customers have neither a foreign car nor a dog.
Step-by-step explanation:
Let the total number of his customers = 100.
Since the events are independent,
customers with foreign cars + customers that own dogs + customers that have neither a foreign car nor a dog = 100.
But,
Customers with foreign cars = 30% = 30
Customers that own dogs = 40% = 40
Customers with neither foreign car nor dog = x%
So that,
30 + 40 + x = 100
70 + x = 100
x = 100 - 70
x = 30
Customers with neither foreign car nor dog = 30.
Converting this value to percentage,
= [tex]\frac{30}{100}[/tex] × 100
= 30%.
Therefore, 30% of his customers have neither a foreign car nor a dog.
A manager recorded how many hours each of 11 cashiers worked in a week. Which interval contains the median number of hours worked?
Answer:
Step-by-step explanation:
Hello!
In descriptive statistics, the median is a measurement of center position. It separates the sample in halves. (bottom 50% from upper 50%)
The manager took a sample of 11 cashiers and recorded the worked hours in a week
To identify the median you have to calculate it's position:
The position is calculated as
PosMe= (n+1)/2= (11+1)/2= 6 cashier
This means that the Median of hours worked is a week observed corresponds to the 6th cashier (after ordering the data from lowest to highest)
If you observe the histogram, the x-axis corresponds to worked hours and the y-axis shows the number of workers.
The workers were already arranged from least hours worked to most hours worked.
The first interval corresponds to 0-10 worked hours and two workers recorded these working times.
The second interval corresponds to 10-20 worked hours and three workers recorded these working times.
In the third interval of 20-30 hours, no workers recorded these working times.
The fourth interval corresponds to 30 - 40 worked hours and 5 workers recorded these working times.
The fifth interval corresponds to 40 - 50 worked hours and only one worker recorded these working hours.
The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"
I hope this helps!
The interval that contains the median number of hours worked is "30 - 40 hours"
The manager took a sample of 11 cashiers and recorded the worked hours in a week
To identify the median you have to calculate it's position:
The position is calculated as
PosMe= (n+1)/2= (11+1)/2= 6 cashier
The fourth interval corresponds to 30 - 40 worked hours and 5 workers recorded these working times.
The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"
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What is the surface area of a square pyramid with a slant height of 6cm and the length of one side of the square base is 5cm
Answer:
S = 85cm^2
Step-by-step explanation:
The surface area of a square pyramid is given by the following formula:
[tex]S=2hb+b^2[/tex]
where it has taken into account the sum of the area of a square and four triangles:
[tex]4(\frac{hb}{2})+b*b=2bh+b^2[/tex]
h: slant height = 6cm
b: base = 5cm
By replacing in the formula you obtain:
[tex]S=2(5cm)(6cm)+(5cm)^2=85cm^2[/tex]
hence, the surface area is 85cm^2
Solve the equation for x, and enter your answer below.
7 x -5= 65
x=10
Step-by-step explanation:
7x - 5=65
+5 +5 so the 5's cancel so add 5 to 65
7x =70 because you add 5 to 65 to get 70
7x 7
7 x cancels out so you answer will be
x=10
Answer:
x = 10Step-by-step explanation:
7 x -5 = 65
7 times what? (x) - 5 equals 65
Well we know that x has to be less than 65 and more than 7 and -5.
So 7 must be multiplied by numbers 8, and up.
7 * 8 -5 = 51, NOT 65.
7 * 9 -5 = 58, NOT 65.
7 * 10 -5 = Does equal 65.
Therefore, x is equivalent to 10.
Simplify: 1/4(-12+4/3)
According to this site, if you know the coordinates of two points on a line, what form would you use to write the equation of the
line? Explain the process for writing the equation. (Site 1)
You would use the POINT SLOPE FORMULA and the Slope Formula
which is as follows ...
slope formula : [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
point slope formula: [tex]y - y_{1} = m(x - x_{1} )[/tex]
Determine the slope of the line which contains the following points.
(-3,5) and (2,-6)
Answer:
I like it when im high marks a lil by and he say he fly but he dono ha ta fly OoOoooOoOoOOoO
Step-by-step explanation:
A simple random sample of 5 months of sales data provided the following information: Month:12345 Units Sold:9480859492 (a)Develop a point estimate of the population mean number of units sold per month. x
Answer:
89 units
Step-by-step explanation:
-The population's mean point estimate is equivalent to the sample mean.
Given the 5 month units sold is 94,80,85,94 and 92
-Mean is the average of the units sold over the 5 month period:
[tex]\bar X=\frac{\sum {x_i}}{n}\\\\=\frac{94+80+85+84+92}{5}\\\\=89[/tex]
Hence, the point estimate for the population mean is 89 units
HELP! will give brainliest if given right answers
7. tails, odd, 4
P(tails) = 1/2
P(odd) = 3/6 = 1/2
P(4) = 1/6
P(tails then odd then 4) = (1/2)×(1/2)×(1/6) = 1/24 ≈ 0.041666
Answer: 1/24, 4.2%
8. tails, 6 or 1, 3
P(6 or 1) = 2/6 = 1/3
P(3) = 1/6
P( tails, 6 or 1, 3) = (1/2)(1/3)(1/6) = 1/36 ≈ 0.027777
Answer: 1/36, 2.8%
9. heads, not 2, even
P(heads) = 1/2
P(not 2) = 5/6
P(even) = 1/2
P(heads, not 2, even) = (1/2)(5/6)(1/2) = 5/24 ≈ 0.208333
Answer: 5/24, 20.8%
Answer:
7. 1/24 = 4.2%
8. 1/36 = 2.8%
9. 1/6 = 16.67%
All percentages are rounded
What is the slope of the line that passes through the points (-8, -6) and (-18, 6)
Answer:
Step-by-step explanation:
Al find a new supplier. He can buy raw peanuts for $.30 for a pound. If he sells the peanuts in a .2-pound bags for $2.50 a bag, How much profit is made on each bag
Answer:
$1.9
Step-by-step explanation:
2 pound bag (when he bought) =.30×2=$0.6
when he sells, price is $2.50.
Profit for each bag= $2.5-$0.6=$1.9
A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts.
About 15.4% of the mixed nuts in a batch are pecans.
If a batch contains 77 pounds of pecans, how many pounds of mixed nuts are in a batch altogether?
Step-by-step explanation:
15.4% of the nuts are pecans.
0.154x = 77
x = 500
There are 500 pounds of mixed nuts in the batch.
George works for a shipping company, loading packages into a truck. How much work does George do on a 2-kg package when he lifts it to a height of 1.8 m?
Answer:
Work done by george = 35.28J
Step-by-step explanation:
We are given;
Mass; m = 2 kg
Height;h = 1.8 m
Now, we want to find how much work does George do on a 2-kg package at the height of 1.8m.
This is a potential energy problem.
The formula for work done is therefore;
W = mgh
Where;
m is mass
g is acceleration due to gravity which has a constant value of 9.8 m/s²
h is height
Thus, plugging in relevant values;
W = 2 x 9.8 x 1.8
W = 35.28 J
Final answer:
The work done by George on the 2-kg package when he lifts it to a height of 1.8 meters is calculated using the equation W = mgh, which results in 35.28 joules.
Explanation:
The question How much work does George do on a 2-kg package when he lifts it to a height of 1.8 m? requires the calculation of the work done against the force of gravity. To find the work done, the equation W = mgh is used, where W is the work done in joules, m is the mass in kilograms, g is the acceleration due to gravity (9.8 m/s2), and h is the height in meters.
To solve for the work done in this case: W = (2 kg)(9.8 m/s2)(1.8 m).
When you calculate this, it gives you the work done by George as W = 35.28 J (joules).
In March, April, and June it rained 2 inches. In February, May, and September it rained 1 inch In August and
October, it rained 3 inches. And in January it only rained 4 inches. Which line plot represents the data?
x
x
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X
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X
X
X
1
2
3
4
5
✓ Done
Intro
Answer:
d
Step-by-step explanation: